solve the inequality:-3x-4/7 >5

Answers

Answer 1

x < -  [tex]\frac{13}{7}[/tex]

add [tex]\frac{4}{7}[/tex] to both sides

- 3x > [tex]\frac{4}{7}[/tex] + [tex]\frac{35}{7}[/tex]

- 3x > [tex]\frac{39}{7}[/tex] ( divide both sides by - 3 )

note that when we divide/ multiply by a negative quantity we must reverse the inequality symbol

x < - [tex]\frac{13}{7}[/tex]




Related Questions

will give brainliest plz hep!!!!!
Which line is a graph of the equation: 2x + 5y = 10?
Number graph ranging from negative five to five on the x axis and negative six to two on the y axis. Four lines are drawn in blue on the graph. Lines a and c have a positive slope and are parallel to each other. Lines b and d have a negative slope and are parallel to each other. Lines a and b intersect at (zero, two), and lines c and d intersect at (zero, negative two).
A. line a B. line b C. line c D. line d

Answers

Answer: The equation is of line "b"


Step-by-step explanation:


First we find the slope of the given line by using slope intercept form.


Converting the equation into slope intercept form


[tex] 5y=-2x+10 [/tex]


Divide both side by 5 we get


[tex] y= \frac{-2}{5} x+ 2 [/tex]


On comparing with


[tex] y =mx+c [/tex]


We get slope [tex] m=\frac{-2}{5} [/tex]


as the slope of line is negative therefore the line will be either line "b" or line "d"


As line "b" pass from (0,2)


On putting point [tex] x=0 &y=2[/tex] in given equation we get


[tex] 2(0)+5(2)=0+10=10 [/tex]



Which is equal to RHS of the line


Therefore the given equation is of line "b"


Now putting point (0,-2)


We get [tex] 2(0)+5(-2)=-10 [/tex]


Which is not equal to RHS and therefore line "d" is not the required line



Therefore the given equation is of line "b"


Which of the graphs below would result if you made the leading term of the following function negative?

Answers

We are given function F(x) = x^3 +3x^2.

Leading term is the term that has highest power of a variable.

For the given function we have highest power 3 of x.

Therefore, leading term is x^3. We don't have any sign in front of x^3. Therefore, it's a positive leading term.

And degree of the is highest power, that is 3.

Therefore, degree is an odd number.

According to problem,  we need to make the leading term as a negative number.

So, we need to find a rule for end behaviour of the graph with:

Leading coefficent = Negative.

Degree : Odd.

Please note the rule, when leading coefficent a negative number and degree is odd.

x--> + ∞   f(x) ---> - ∞

x--> - ∞   f(x) ---> + ∞

We can see option D has  f(x) ---> - ∞ for x--> + ∞ and  f(x) ---> + ∞ for x--> - ∞.

Therefore, correct option is D.

Answer: graph D

Step-by-step explanation: just took the test

What is the value of x?

6+8x/ 2 =5x

Answers

HEY THERE!!

We have to find the value of (6+8x)/ 2 =5x

so let's start
=6 + 8x)/2=5x

multiplying with 2 on both sides

=> 6 +8x= 10x
Subtracting 8x on both sides
=> x = 3

HOPE IT HELPED YOU.



Which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21 ?

Select each correct answer.

(−3, 3)
(−1, −6)
(7, 0)
(11, 3)

Answers

Answer:

(-1,-6) , (7,0) and (11,3)

Step-by-step explanation:

3x - 4y = 21

4y = 3x - 21

y = 3/4x - 21/4 , the slope(m) of this line is 3/4

The x and y intercepts are (0,-5.25) and (7,0)

Taking a point (-3,3):

Slope(m) = change in y ÷ change in x

Slope = (3 - 0) ÷ (-3 - 7) = -0.3

Since the slope here is not 3/4 then point (-3,3) is not on the line.

Taking a point (-1,-6)

Slope = (-6 - 0 ) ÷ (-1 - 7) = -6/-8 = 3/4

The point (-1,-6) is on the line.

Taking a point (7,0):

This point is the x - intercept and so its on the line.

Taking a point (11,3):

Slope = (3 - 0) ÷ (11 - 7) = 3/4

Therefore the point (11,3) is on the line.


Answer:

wut that dude said is correct i verified it

Step-by-step explanation:

Point C ∈ AB, AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.

Answers

We are given that

point C lies on AB

Let's assume AC=x

we know that

CB=AB-AC

[tex]CB=30-x[/tex]

Point C is 1.5 times farther from point A than from point B

so, we get

[tex]\frac{AC}{CB} =1.5[/tex]

now, we can plug values

[tex]\frac{x}{30-x} =1.5[/tex]

now, we can solve for x

[tex]x=1.5\left(30-x\right)[/tex]

[tex]x=18[/tex]

so, we get

[tex]AC=18[/tex]

now, we can find CB

[tex]CB=30-18[/tex]

[tex]CB=12[/tex]

so, we get

[tex]AC=18[/tex]

[tex]CB=12[/tex]...............Answer

Use net to find the lateral area of the prism.

Answers

The lateral area of the prism is the area of the three rectangles in the middle of the net. (The two triangles are the bases of the prism, which don't count toward lateral area.) The total length of the three rectangular prism faces is (8 +15 +17) cm = 40 cm. The width of those rectangles is 11 cm. The lateral area will be the product of this length and width:

... lateral area = (40 cm)(11 cm) = 440 cm²

I need geometry help
I don't know what is the correct classification for ∠BEC?

I can't tell if it's straight, acute, obtuse, or a right angle.

Answers

Angle BEC is the unmarked angle in the middle of the figure. Its value is the difference between straight angle AED (180°) and the two marked angles, 57° and 33°. That difference is ...

... 180° - 57° -33° = 90°

∠BEC is a right angle.

Answer:

Right angle

Step-by-step explanation:

We are given that

Angle AEB=[tex]57^{\circ}[/tex]

Angle CED=[tex]33^{\circ}[/tex]

We have to find  the classification of angle BEC

We know linear sum =[tex]180^{\circ][/tex]

Angle AEB +Angle BEC+Angle CED=180

Substitute the values then we get

[tex]57+33+\angle BEC=180^{\circ}[/tex]

[tex]90+\angle BEC=180[/tex]

[tex]\angle BEC=180-90[/tex]

[tex]\angle BEC=90^{\circ}[/tex]

Hence, the angle BEC is right angle

which is the slope of the like represented by the equation 2x+3y=-12

Answers

slope = - [tex]\frac{2}{3}[/tex]

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + 3y = - 12 into this form

subtract 2x from both sides

3y = - 2x - 12 ( divide all terms by 3 )

y = - [tex]\frac{2}{3}[/tex] x - 4 ← in slope- intercept form

with slope m = - [tex]\frac{2}{3}[/tex]


[tex]\text{The slope-intercept form:}\ y=mx+b\\m-slope,\ b-y-intercept\\\\2x+3y=-12\qquad|\text{subtract 2x from both sides}\\\\3y=-2x-12\qquad|\text{divide both sides by 3}\\\\y=-\dfrac{2}{3}x-4\\\\Answer:\ \boxed{m=-\dfrac{2}{3}}[/tex]

Please help me on this!

Answers

How does the $100 gift card affect the measure of center of the data?

It increases the mean value of the prizes.

It decreases the mean value of the prizes.

It increases the median value of the prizes.

It decreases the median value of the prizes.

A ferryboat makes four trips to an island each day.The ferry can hold 88 people.If the ferry is full on each trip,how many passengers are carried by the ferry each day?

Answers

That would be four times 88 passengers:  352 passengers per day.

Answer: 352

Step-by-step explanation:

88x4

How does sin 30degrees compare to sin -30degrees?

Answers

The sine function is an odd function, so the sine of -30° is the opposite of the sine of 30°.

sin(30°) = 1/2

sin(-30°) = -1/2

The sine of 30° is greater than the sine of -30°.

The table below shows the number of shoppers at Jacob's store over a period of five months:
Month 1 2 3 4 5
Shoppers 50 250 1,250 6,250 31,250
Did the number of people at Jacob's store increase linearly or exponentially? A.Linearly, because the table shows an equal increase in number of shoppers for an equal increase in months
B. Exponentially, because the table shows an equal increase in number of shoppers for an equal increase in months
C.Linearly, because the table shows the number of shoppers increases by an equal factor for an equal increase in months
D.Exponentially, because the table shows the number of shoppers increases by an equal factor for an equal increase in months

Answers

We are given table

Month :         1     2        3         4         5

Shoppers:   50  250   1250   6250  3250

so, we have

first term =50

[tex]a_1=50[/tex]

Second term =250

[tex]a_2=250[/tex]

Third term =1250

[tex]a_3=1250[/tex]

[tex]a_4=6250[/tex]

[tex]a_5=31250[/tex]

now, we can find ratios

[tex]\frac{a_2}{a_1} =\frac{a_3}{a_2}=\frac{a_4}{a_3}=\frac{a_5}{a_4}=5[/tex]

we can see that all ratios are same and 5

so, this is exponential

so, option-D..........Answer



The table below shows the number of shoppers at Jacob's store over a period of five months:  

Month 1 2 3 4 5  

Shoppers 50 250 1,250 6,250 31,250  

Did the number of people at Jacob's store increase linearly or exponentially?

Answer:

D.Exponentially, because the table shows the number of shoppers increases by an equal factor for an equal increase in months

Solve the inequality |x| < 5. {x|-5 < x < 5} {x|x < -5 ∪ x > 5} {x|x -5 ∪ x < 5}

Answers

ANSWER

The correct answer is A

{[tex]x|-5<\:x<\:5[/tex]}


EXPLANATION

[tex]|x|<5[/tex]


This implies that

[tex]x<5\:or\:-x<5[/tex]


We solve the compound inequality to obtain,


[tex]x<5\:or\:x>-5[/tex]

Remember that, dividing through by negative 1 reverses the inequality sign

The solution set is

{[tex]x|-5<\:x<\:5[/tex]}


Jo flips a coin {H, T}; then rolls a 6-sided die {1, 2, 3, 4, 5, 6}.

How many possible outcomes are in the sample space of this experiment?

A. 4

B. 8

C. 12

D. 36

Answers

Answer:

Option C

Step-by-step explanation:

A coin has two outcomes Head (H) and tail (T).

So, the number of outcomes when a coin is tossed = 2

A coin has six outcomes [tex]\left \{ 1,2,3,4,5,6 \right \}[/tex]

So, the number of outcomes when a coin is tossed = 6

Therefore, possible outcomes when Jo flips a coin and then rolls a 6-sided die are [tex]\left \{ H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6 \right \}[/tex]

So, the number of possible outcomes = 12

Option C. is correct.

Using the concept of sample space, it is found that the number of possible outcomes in the experiment is given by:

C. 12

The sample space of an experiment is the set that contains all possible outcomes.

In this problem:

For the coin, there are 2 outcomes.For the dice, there are 6 outcomes.

The coin and the dice are independent, thus, there are 2 x 6 = 12 possible outcomes, which means that the correct option is:

C. 12

A similar problem is given at https://brainly.com/question/15006554

Choose the equations that are not linear equations. - x - y = 2, x^2 + y = 4, x/2 - y^3 = 1, x = 5

Answers

Answer:

x^2 + y = 4x/2 - y^3 = 1

Step-by-step explanation:

Any equation with a product of variables, or with a variable in an exponent or denominator, is not a linear equation. Here, "product of variables" includes powers and roots—any expression with an exponent other than 1, or a total of exponents other than 1.

The equations x^2 + y = 4 and x/2 - y^3 = 1 are not linear equations because they contain terms with variables raised to powers other than one, whereas - x - y = 2 and x = 5 are linear.

The question involves identifying which equations from the given list are not linear equations. Linear equations are of the form y = mx + b, where m and b are constants. Non-linear equations can include terms with variables raised to powers other than one, variables in the denominator, or variables under a radical.

The given equations are - x - y = 2, x^2 + y = 4, x/2 - y^3 = 1, and x = 5. The second equation, x^2 + y = 4, is not linear because it has a term x squared. The third equation, x/2 - y^3 = 1, is also not linear due to the term y cubed. Both of these equations contain expressions that disqualify them from being linear, as linear equations cannot have variables with exponents other than one. Therefore, these two are examples of a non-linear system of equations.

On the other hand, the first equation - x-y = 2 and the fourth equation, x = 5 are both linear. The first is in the standard linear form after being rearranged, and the fourth represents a vertical line in the xy-plane, which is a special case of a linear equation.

Explain how (13 + 10) + 5 is solved differently from 13 + (10 + 5). A) For (13 + 10) + 5, you add 13 + 5 first, then add 10. For 13 + (10 + 5), you add the 10 + 13 first, then add 5. Eliminate B) For (13 + 10) + 5, you add 13 + 10 first, then add 5. For 13 + (10 + 5), you add the 10 + 5 first, then add 13. C) For (13 + 10) + 5, you add 13 - 10 first, then add 5. For 13 + (10 + 5), you add the 10 - 5 first, then add 13. D) For (13 + 10) + 5, you add 13 + 10 first, then subtract 5. For 13 + (10 + 5), you add the 10 + 5 first, then subtract 13.

Answers

Answer:

The answer is B

Step-by-step explanation:

Simple use P.E.M.D.A.S

Parentheses are always first, you add 13+10 then evaluate everything else.

Have a great day.

what is the answer for 300/2 by changing the number from mixed to improper and simplify at the end if needed

Answers

Simplify. Divide the number

300/2 = 150

150 is your answer (it is a whole number, no need to change to improper, unless you want 150/1)

hope this helps

find the sum (2x−6)+4(x−3)

Answers

The sum of the given expressions will be 6x-18.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression is (2x−6)+4(x−3). The summation will be calculated as

Sum = (2x-6)+4(x-3)

Sum = (2x-6)+4x-12

Then we combine like terms.

Sum = (2x-6)+4x-12

Sum = 6x-6-12

Sum = 6x-18

Therefore, the sum of the given expressions will be 6x-18.

To know more about an expression follow

https://brainly.com/question/18356625

#SPJ2

[Precalculus] Find the value of sin(x/2):

Answers

Put your number into the half-angle formula and simplify.

[tex]\displaystyle\sin{\frac{\theta}{2}}=\pm\sqrt{\frac{1-\cos{\theta}}{2}}=\sqrt{\frac{1-\frac{1}{3}}{2}}\\\\=\sqrt{\frac{1}{3}}=\sqrt{\frac{3}{9}}\\\\=\frac{\sqrt{3}}{3}[/tex]

The appropriate selection is ...

[tex]A)\quad\dfrac{\sqrt{3}}{3}[/tex]

Write the unknown number for n. 5.28-3.4=n

Answers

n = 28

to evaluate the expression, perform the multiplications before subtraction

( 5 × 28 ) - ( 3 × 4 ) = 140 - 12 = 128


Write the equation of the line perpendicular to the given line and passing through the given point: y=3x−2 through (3,4)

Answers

The equation of the given line, y = 3x - 2, is written in slope-intercept form:

... y = mx + b

where m represents the slope and b is the y-intercept.

Matching the form to the given equation, you see m = 3, and b = -2. The slope of the given line is 3.

The slope of a line perpendicular to it will be the negative reciprocal of this value

... slope of perpendicular line = -1/m = -1/3

For some new value of b, the equation of the perpendicular line can be written

... y = (-1/3)x + b

Filling in the values of the point coordinates, we can find the appropriate value of b.

... 4 = (-1/3)(3) +b

... 4 = -1 + b . . . . . . . simplify

... 5 = b . . . . . . . . . . add 1

Then the equation you want is ...

... y = (-1/3)x + 5

More Literal Expressions, please include the way you worked out.

Answers

A=h/2(a+b) solver for h

2A=h(a+b)

2A/(a+b)=h   (Solution)

Solve the system of equations below by graphing.
x^2-2x+y-3=0
x^2+y=0

What is the solution rounded to the nearest hundredth?
(–2.25, –1.5)
(–1.5, –2.25)
(–0.82, –0.68)
(–0.68, –0.82)

Answers

ANSWER


The correct answer is B

EXPLANATION

The first function is


[tex]x^2-2x+y-3=0[/tex]


We make y the subject to obtain;


[tex]y=-x^2+2x+3[/tex]


Let us quickly write this in the vertex form.


[tex]y=-(x^2-2x)+3[/tex]


[tex]y=-(x^2-2x+(-1)^2)+3+(-1)^2[/tex]


[tex]y=-(x-1)^2+4[/tex]


Since the [tex]a[/tex] is negative, the graph opens up.


The vertex is at [tex](1,4)[/tex]


The y-intercept is [tex]-3[/tex]


The x-intercept is found by equating the function to zero.


[tex]-(x-1)^2+4=0[/tex]


[tex]\Rightarrow (x-1)^2=4[/tex]


[tex]\Rightarrow (x-1)=\pm 2[/tex]


[tex]\Rightarrow x=1 \pm2[/tex]

[tex]\Rightarrow x=-1,3[/tex]


With these information we can quickly sketch the graph as shown in the attachment(the red graph).


For the second function,


[tex]x^2+y=0[/tex]


we again make y the subject to obtain,


[tex]y=-x^2[/tex]


This is a basic quadratic function that can be graphed easily. Note that it is also a maximum graph.


From the graph the solution to the two functions is


[tex](-1.5,-2.25)[/tex]





Answer:

B.(–1.5, –2.25)

Step-by-step explanation:

At most, Keith can spend $90 on sandwiches and chips for a company lunch. He already bought chips for $15 and will buy sandwiches that cost $6 each. The inequality 15 + 6s ≤ 90 represents the described cost, where s is the maximum number of sandwiches that could be bought. What is the maximum number of sandwiches Keith can buy? A) 12 sandwiches B) 13 sandwiches C) 17 sandwiches D) 18 sandwiches

Answers

A. 12 sandwiches. He can buy 12 because 6*12=72. He already has the chips at 15.00. So 72+15=87. Close to the amount of $90.00


Help asap! Will mark brainlyst

Answers

1 and a half is the correct answer (1 1/2) for the first one, for the second one it is D, and for the third one it is A.

Let's add both of the fractions together. They at 2 slices of pumpkin pie, and 3 slices of pecan pie. The fractions of these is 2/8 and 3/8. Added together, this is 5/8, so I believe this is your answer.

For this one, we can simply multiply the total acres by the cost per acre. 1240*52 is 64,480, so your land is worth a total of $64,480.

For this question, all we need to do is multiply the number of gallons Shelly's car can hold by the price per gallon. 14*3.56 is 49.84, so she'll be spending $49.84 to fill up her tank.

I just need help on number 14. Thank you very much.

Answers

I believe you only need to know one angle.

For example, if you know angle 1, you can calculate angle 3. Angle 2 = angle 3 and angle 4 = angle 1.

Also, Angle 5= angle 1 and so on...

please show work

1. y = -2x
y = -4x + 10


2. y = 3 x
y = zx - 7


3. y = 6x + 22
y = -8

Answers

(1)

since both equations express y in terms of x, equate the right sides

- 2x = - 4x + 10 ( subtract 4x from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

substitute x = 5 into y = - 2x → y = - 10

solution is : (x, y ) → (5, - 10 )

(2)

equate the right sides of both equations

3x = 2x - 7 ( subtract 2x from both sides )

x = - 7

substitute x = - 7 into y = 3x → y = - 21

solution is : (x, y) → (- 7, - 21)

(3)

substitute y = - 8 into the other equation

- 8 = 6x + 22 ( subtract 22 from both sides )

- 30 = 6x ( divide both sides by 6 )

x = - 5

solution is : (x, y ) → (- 5, - 8 )



Which ordered pairs are on the line ​ 2x−3y=8 ​? Select each correct answer. ​ (12,−73) ​ ​ (−2,4) ​ ​ (2,−43) ​ ​ (−5,−6) ​

Answers

The answer is (-5,-6)

Answer:

Option D is correct.

(-5, -6)

Step-by-step explanation:

Ordered pair states that a pair of number that is locate a point on a coordinate plane i.,e (x, y)

Given the line: [tex]2x-3y = 8[/tex]              .....[1]

Option A:

(12, -73)

Substitute the value of x = 12 and y = -73 in [1] we have;

2(12) - 3(-73) = 8

24 + 219 = 8

243 = 8        False.

Similarly for;

Option B

(-2, 4)

2(-2) - 3(4) = 8

-4 -12 = 8

-20 = 8        False.

Option C

(2, 43)

2(2) - 3(43) = 8

4-129= 8

-125= 8        False.

Option D

(-5, -6)

2(-5) - 3(-6) = 8

-10 +18 = 8

8 = 8      True.

Therefore, only (-5, -6) ordered pair is on the line 2x-3y = 8



A number and its absolute value are equal. If you subtract two from the number, the new number and its absolute value are not equal. What do you know about the number?

Answers

A number and its absolute value are not equal when the number is less than zero. Since subtracting 2 makes the number less than zero, we know ...

... the number is a non-negative number less than 2. (0 ≤ n < 2)

Tom is putting cartons of ice-cream in one of the freezers. There are 13 boxes and each box contains 24 cartons. How many cartons of ice-cream are there in total?

Answers


24x13=312


There are a total of 312 total ice cream cartons.

There are a total of 312 cartons or ice cream in total.

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