Solve the system of equations

y=3x+30
y=8x
_______________________

x= ??

y= ??

Answers

Answer 1
x=6, y=48

Since both equations are set equal to y, set 3x+30=8x. Subtract 3x from each side, getting 5x=30. Divide by 5, so x=6. Then, just plug in 6 for x in any of the two equations, so y=48.
Answer 2
Lets get started :)


y = 3x + 30
y = 8x

Since y = both the equations, we can equate them

8x = 3x + 30   {Take 3x by subtracting to the other side in order to find the value of the variable)
We do minus, when we see plus

8x - 3x = 3x - 3x + 30
3x and -3x cancels out in the right hand side

5x = 30

Divide by 5 on either side to isolate x
We do division, when we see multiplication

[tex] \frac{5x}{5} = \frac{30}{5} [/tex]
5 and 5 cancels out

x = 6

Now, we need to substitute x by 6 in order to find y
We can substitute in either equation, we will still get the same value

y = 8(6)
   = 48

y = 3(6) + 30
   = 18 + 30
   = 48

x = 6 , y = 48



Related Questions

Some people say that more babies are born in september than in any other month. to test this claim, you take a simple random sample of 150 students at your school and find that 21 of them were born in september. you are interested in whether the proportion born in september is higher than 1/12—what you would expect if september was no different from any other month.

Answers

Final answer:

To test whether the proportion of babies born in September is higher than the expected proportion of 1/12, we can use hypothesis testing. Given a sample of 150 students, with 21 of them born in September, we calculate the test statistic, compare it to the critical value, and make a decision.

Explanation:

To test whether the proportion of babies born in September is higher than the expected proportion of 1/12, we can use hypothesis testing. Let's set up the hypotheses:

Null Hypothesis (H0): The proportion of babies born in September is equal to 1/12.

Alternative Hypothesis (Ha): The proportion of babies born in September is greater than 1/12.

We can use a one-sample proportion test to test these hypotheses. Given that we have a simple random sample of 150 students at your school and 21 of them were born in September, we can calculate the sample proportion: 21/150 = 0.14.

Next, we calculate the test statistic using the formula: test statistic = (sample proportion - null proportion) / standard error. The null proportion is 1/12 = 0.0833, and the standard error is √[(null proportion * (1 - null proportion)) / sample size]. Calculating the test statistic gives us: test statistic = (0.14 - 0.0833) / √[(0.0833 * (1 - 0.0833)) / 150] = 2.92 (rounded to two decimal places).

Finally, we compare the test statistic to the critical value(s) at a chosen significance level to make a decision. The critical value(s) depend on the significance level and the direction of the alternative hypothesis. If the test statistic falls in the rejection region (i.e., it is greater than the critical value), we reject the null hypothesis and conclude that the proportion of babies born in September is higher than 1/12.

The difference of two numbers is 3 and their quotinet is 2 what are the 2 numbers

Answers

The two numbers are 6 and 3

You are working at the register at a grocery store during the busiest time of the day. A customer buys a mud of cheese for 4.62 and a box of crackers for 1.29. She hands you $6.00, and the register says she still owes $0.54. Since you were in a hurry, you made a mistake by typing the numbers in the wrong order. What mistake did you make?

Answers

the mistake is that instead of typing 1.29 you typed 1.92
4.62+1.92=6.54
she gave you 6 and looks like she still own 0.54 cents 

1. which function is shown on the graph?
f(x)=1/2cosx
f(x)=−1/2sinx
f(x)=−1/2cosx
f(x)=1/2sinx

2. (picture)


3.(picture)


4.(which equation represents the function on the graph?

5. what is the period of the funtion f(x)=cos2x?

Answers

Problem 1

Answer: choice C) f(x) = (-1/2)cos(x)

We can rule out anything with sine in it since the graph does not go through the origin. We can rule out choice A as well since plugging x = 0 into f(x) leads to a positive result, when instead we want a negative value. So the only thing left is choice C

======================================================
Problem 2

See the attached image

Point A is approximately (1.57, 0) which is exactly (pi/2, 0)
Point B is approximately (3.14, -2) which is exactly (pi, -2)

======================================================
Problem 3

Answer: 1/pi

Period = pi since the graph repeats itself every pi units
Frequency = 1/Period 
Frequency = 1/pi 

======================================================
Problem 4

Answer: Choice A) f(x) = cos(2x)

This is a cosine function as it doesn't go through the origin. The period is T = pi, so b = 2pi/T = 2pi/pi = 2 is the coefficient of the inner x term. Therefore the function is f(x) = cos(2x)

======================================================

Name the type of symmetry for the figure.
reflectional
rotational
rotational and reflectional
no symmetry
DOES ANYONE HAVE THE WHOLE QUIZ????

Answers

Answer:

Rotational

Step-by-step explanation:

Reflectional symmetry is when a figure can be folded in half through some given line and half each half congruent to the other.  There is no line through which to fold this figure, so there is no reflectional symmetry.

Rotational symmetry is when a figure can be turned some degree and be congruent to itself; This figure can be rotated 180°, so this has rotational symmetry.

Final answer:

Without the figure, it's impossible to determine the type of symmetry it has. Symmetry in mathematics can be reflectional, rotational, both, or none at all depending on the characteristics of the given figure.

Explanation:

To answer your question, we need the figure in order to determine the type of symmetry. In mathematics, symmetry can be classified as reflectional, rotational, both reflectional and rotational, or it can have no symmetry at all. Reflectional symmetry is when one half is the mirror image of the other half. Rotational symmetry is when the figure can be rotated to some degrees and still appears the same. The term doesn't have a specific figure attached, so without more information, a direct answer cannot be given.

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Maria has three children. there is two years age difference between each child. the total ages of all three children is 36 years. tina is the youngest child. how old is tina? let t = the age of tina. which formula will calculate tina's age?

Answers

t= Tina's age
t+2= second child
t+4= third child
36= age of all children

Add the ages of all children equal to 36 years. Add 2 to each age because there is 2 years age difference between each child.

t + (t+2) + (t+4)= 36
combine like terms
3t + 6= 36
subtract 6 from both sides
3t= 30
divide both sides by 3
t= 10 Tina's age

t+2= 12
(10)+2= 12 age of second child

t+4= 14
(10)+4= 14 age of third child

ANSWER: The formula that will calculate Tina's age is t + (t+2) + (t+4)= 36.

Hope this helps! :)

t= Tina's age

t+2= second child

t+4= third child

36= age of all children

Add the ages of all children equal to 36 years. Add 2 to each age because there is 2 years age difference between each child.

t + (t+2) + (t+4)= 36

combine like terms

3t + 6= 36

subtract 6 from both sides

3t= 30

divide both sides by 3

t= 10 Tina's age

t+2= 12

(10)+2= 12 age of second child

t+4= 14

(10)+4= 14 age of third child

ANSWER: The formula that will calculate Tina's age is t + (t+2) + (t+4)= 36.

Hope this helps! :)

Edna says that when (x - 2)2 = 9, that x - 2 = 3. Use complete sentences to explain whether Edna is correct. Use specific details in your explanation.

Answers

Assuming the given equation is (x-2)^2 = 9, Edna is partially correct. Saying x-2 = 3 is halfway there in terms of getting the ful solution. She forgot about the minus form of the plus minus. If (x-2)^2 = 9, then applying the square root to both sides leads to these two equations: x-2 = 3 or x-2 = -3. So we have a plus 3 and then a minus 3.

Answer:x=5,-1

Step-by-step explanation:

Edna says that when \left ( x-2\right )^2=9[/tex]

then x-2=3

such that x=5

but this is not true as when we put the value of x in equation then it will not satisfy the equation.

It can be solved by taking the terms either on LHS or RHS

[tex]\left ( x-2\right )^2-9=0[/tex]

[tex]x-2=\pm 3[/tex]

x=5

x=-1

The Polynomial Remainder Theorem

Answers

1. 7
2. 77
3. 8
4. (-2,2)
5. (-4,46)
Final answer:

The Polynomial Remainder Theorem in mathematics states that the remainder of dividing a polynomial P(x) by (x - a) is P(a). This theorem is linked to the Binomial theorem for series expansions and is useful in graphing and solving polynomials and quadratic equations.

Explanation:

The Polynomial Remainder Theorem is a concept in mathematics associated with series expansions and equation graphing. This theorem states for a given polynomial P(x) and a number a, when P(x) is divided by the binomial (x - a), the remainder is P(a). This is a crucial concept when graphing polynomials, as understanding the remainder can assist in predicting the behavior of the polynomial curve. The theorem is tied to the Binomial theorem which provides a series expansion for expressing powers of a sum of terms (a + b)^n in terms of a and b.

To solve quadratic equations, which are second-order polynomials, the Polynomial Remainder Theorem can also be utilized. It can further clarify the solutions of quadratic functions when they are graphed. Furthermore, in the realm of function graphing, the theorem aids in visualizing how different terms contribute to the shape of the polynomial curve.

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10 POINTS!!! FULL ANSWER WITH FULL STEP BY STEP SOLUTION PLEASE. DO BOTH PARTS OF 3 AND ALL OF 4.

Answers

see the attached picture for the answers:

3. Recognize that log(x) = ln(x)/ln(10)

3a) (d/dx)(ln(x)/(ln(x)/ln(10)) = (d/dx)(ln(10)) = 0

3b) (d/dx)(ln(log(x)) = (d/dx)(ln(ln(x)/ln(10))) = (d/dx)(ln(ln(x)) -ln(1/ln(10)))
.. = (d/dx)(ln(ln(x))) . . . . . . . . simplified form
.. = (1/ln(x))*(d/dx)(ln(x))
.. = 1/(x*ln(x))


4. y' = 1/x
.. y'' = -1/x^2
.. y''' = 2/x^3
.. yⁿ = -(n-1)!*(-1/x)ⁿ

A new car is purchased for 20300 dollars. The value of the car depreciates at 9.5% per year. What will the value of the car be, to the nearest cent, after 11 years?

Answers

Answer:

6670.65

Step-by-step explanation:

Final answer:

After 11 years, the value of the car will be $1,913.50.

Explanation:

To find the value of the car after 11 years, we need to calculate the depreciation of the car each year.

The value of the car depreciates at a rate of 9.5% per year, meaning that each year the value of the car will decrease by 9.5% of its current value.

Let's calculate the value of the car after 11 years:

Step 1: Find the depreciation of the car each year.

Depreciation = 9.5% of $20,300 = $1,928.50

Step 2: Calculate the value of the car after 11 years.

Value after 11 years = $20,300 - (11 * $1,928.50)

Value after 11 years = $20,300 - $21,213.50

Value after 11 years = $1,913.50

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How many positive integers less than 1000 are divisible by exactly one of 7 and 11?

Answers

994/7(number of multiples of 7 smaller than 1000) + 990(number of multiples of 11 smaller than 1000) - 924/(lcm of 7 and 11) (number of multiples of 77 smaller than 1000) = 142+90-12
                   = 220

hope i helped :)

p[x]=5b exponent x what do the a and b in exponential function represent

Answers

P(x) = 5·b^x

You have a = 5, the initial value, the value of P(0).
"b" represents the growth factor, the multiplier corresponding to each unit of x.

Which is a true statement about any two congruent chords in a circle? A.They are parallel. B.They are perpendicular. C.They form an angle. D.They are equidistant from the center of the circle.

Answers

They are equidistant from the center of the circle because two congruent chords have the same length, angles, and radii meaning the answer would be D.

Please vote Brainliest, thanks.

The statement (D) "They are equidistant from the center of the circle" is correct.

What is a circle?

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have a statement:

Which is a true statement about any two congruent chords in a circle?

As we know, due to the similar length, angles, and radii of two congruent chords, they are equally spaced from the circle's center.

Thus, the statement (D) "They are equidistant from the center of the circle" is correct.

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Will mark brainliest and give 20 points! In what ways can vertical, horizontal, and oblique asymptotes be identified? Please use your own example to identify.

Answers

Vertical asymptote:
When you have a rational expression in which the denominator is zero, you have a vertical asymptote. So to find vertical asymptotes, just set the denominator of your rational expression equal to zero, and then, solve for [tex]x[/tex]:
[tex] \frac{x-1}{x-3} [/tex]
Set the denominator equal to zero:
[tex]x-3=0[/tex]
Solve for [tex]x[/tex]:
[tex]x=3[/tex] is the vertical asymptote of our rational expression.

Horizontal asymptote:
Here we have two scenarios.
1) Is the degree of the denominator is higher than the degree of the numerator, you will have a horizontal asymptote at [tex]y=0[/tex]:
[tex]y= \frac{x-1}{x^{2}+3} [/tex]
Since the degree of the denominator is higher of the degree of the numerator, our rational expression will have an asymptote at [tex]y=0[/tex]
2) If the degree of both denominator and numerator is the same, the rational expression will have an horizontal asymptote at the ratio of the leading coefficients:
[tex] \frac{3x^{2}+5}{2x^2-3x+1} [/tex]
Leading coefficients: 3 and 2
Ratio of leading coefficients:
[tex] \frac{3}{2} [/tex]. Our rational expression will have an horizontal asymptote at [tex]y= \frac{3}{2} [/tex]

Oblique asymptote:
If the degree of the numerator is higher than the degree of the numerator, you will have an oblique asymptote. To find it, we are going to perform long division; the quotient (without the remainder) will be the equation of the oblique asymptote line:
[tex] \frac{x^2+5x+2}{x+1} [/tex]
The quotient of the long division is [tex]x-1[/tex] with a remainder of 2; therefore, the equation of the oblique asymptote line will be:
[tex]y=x+4[/tex]

Eighty percent of a roof, or 2800 square feet of the roof, has been re-shingled. What is the total area of the roof? a. 22,400 sq ft b. 2240 sq ft c. 3500 sq ft d. 35000 sq ft

Answers

Given that "80% of the roof" is same as "2800 square feet of the roof".

Let's consider total area of roof = X square feet.

Then "80 percent of X" = "2800 square feet".

[tex] 80\% \;of X = 2800 \;square \;feet \\\\\frac{80}{100} *X = 2800 \;square \;feet \\\\\frac{4}{5} *X = 2800 \;square \;feet \\\\X = \frac{5}{4}* 2800 \;square \;feet \\\\X = \frac{14000}{4} \;square \;feet \\\\X = 3500 \;square \;feet \\\\ [/tex]

So total area of the roof would be 3500 square feet.

Hence, option C is correct i.e. 3500 square feet.




A) 90°

B) 180°

C). 6°

D). 86°

Answers

The sum of the angles in a triangle is 180°, then:
68°+26°+x°=180°
Solve it as an equation:
68+26+x=180
x=180-68-26
x=86°
The answer is D) 86 degrees

In a candy factory, the nutty chocolate bars contain 19.0 % pecans by mass. if 5.0 kg of pecans were used for candy last tuesday, how many pounds of nutty chocolate bars were made?

Answers

26.32 pounds of nutty chocolate were made.

Using the parameters given;

percentage of pecans per chocolate = 19%Mass of pecans used = 5kg

The amount of pounds of chocolate made ;

Mass of pecans used / Percentage of pecans 0er chocolate

Now we have ;

5/0.19 = 26.315

Hence, 26.32 pounds of nutty chocolate were made.

Which sentence is an example of the distributive property

Answers

The distributive property of multiplication is a very useful property that lets you simplify expressions in which you are multiplying a number by a sum or difference. The property states that the product of a sum or difference, such as 6(5 – 2), is equal to the sum or difference of the products – in this case, 6(5) – 6(2).

 

Remember that there are several ways to write multiplication. 3 x 6 = 3(6) = 3 • 6.

3 • (2 + 4) = 3 • 6 = 18.

 

Distributive Property of Multiplication over Addition

 

The distributive property of multiplication over addition can be used when you multiply a number by a sum. For example, suppose you want to multiply 3 by the sum of 10 + 2.

 

3(10 + 2) = ?

 

According to this property, you can add the numbers and then multiply by 3.

3(10 + 2) = 3(12) = 36. Or, you can first multiply each addend by the 3. (This is called distributing the 3.) Then, you can add the products.

The multiplication of 3(10) and 3(2) will each be done before you add.

3(10) + 3(2) = 30 + 6 = 36. Note that the answer is the same as before.

 

You probably use this property without knowing that you are using it. When a group (let’s say 5 of you) order food, and order the same thing (let’s say you each order a hamburger for $3 each and a coke for $1 each), you can compute the bill (without tax) in two ways. You can figure out how much each of you needs to pay and multiply the sum times the number of you. So, you each pay (3 + 1) and then multiply times 5. That’s 5(3 + 1) = 5(4) = 20. Or, you can figure out how much the 5 hamburgers will cost and the 5 cokes and then find the total. That’s 5(3) + 5(1) = 15 + 5 = 20. Either way, the answer is the same, $20.

 

The two methods are represented by the equations below. On the left side, we add 10 and 2, and then multiply by 3. The expression is rewritten using the distributive property on the right side, where we distribute the 3, then multiply each by 3 and add the results. Notice that the result is the same in each case.

 

HEY THERE

please help me in math>>>

Answers

The answer is C. Reason- It makes the most sense.
The answer is D. The total number of road accidents per year.

A four sided sandbox has exactly two right angles side lengths 5ft and two side lengths 6ft what shape best describes the shape of the sandbox

Answers

The sandbox is most likely in the shape of a kite. As it has only two right angles, it cannot be a square or other form of rectangle. It also cannot be a parallelogram, which has no right angles, nor is it a rhombus- all four sides are not of the same length.

A kite, however, has two pairs of equal-length sides that are adjacent to each other. It also has two sets of equal-measure angles, one of which can be 90° if it is a cyclic kite.

The sandbox has two right angles and two side lengths of 5ft and two side lengths of 6ft. This shape is consistent with a rectangle. Therefore, the shape of the sandbox is best described as a rectangle.

The sandbox described possesses two right angles and two pairs of opposite sides with equal lengths. Specifically, it has two sides of 5ft and two sides of 6ft. These characteristics are indicative of a rectangle.

Rectangles are quadrilaterals with four right angles, meaning each corner of the shape forms a 90-degree angle. Additionally, opposite sides of a rectangle are equal in length, which is evident in this sandbox with its 5ft and 6ft sides. The presence of two right angles further reinforces the shape's rectilinear nature.

Moreover, rectangles have parallel opposite sides, which allows for uniformity in the sandbox's shape. This geometric feature is crucial for ensuring a consistent and stable structure.

By definition, squares are also rectangles, but not all rectangles are squares. Given that the sides of the sandbox are not all of equal length (i.e., not a square), it is more appropriate to classify it as a rectangle.

Therefore, considering the sandbox's right angles, equal opposite sides, and parallel sides, it aligns most closely with the characteristics of a rectangle.

PLEASE MATH HELP WILL GIVEBRAINLIEST AND 20 POINTS!!!

1.What is the area of a regular hexagon with a side length of 12 cm?

Enter your answer in the box.

Round only your final answer to the nearest hundredth.

2.In a 30-60-90 triangle, what is the length of the hypotenuse when the shorter leg is 5 cm?

3.
What is the exact value of sin 30° ?

Enter your answer, as a simplified fraction, in the box.

Answers

 Question 1:
 
 By definition, the area of ​​a regular hexagon, depending on its sides, is given by:
 [tex]A = \frac{3 \sqrt{3}L^2}{2} [/tex]
 Where,
 L: side of the regular hexagon.
 Substituting values ​​we have:
 [tex]A = \frac{3 \sqrt{3}12^2}{2} [/tex]
 [tex]A = 374.1229744 [/tex]
 Rounding to the nearest hundredth we have:
 [tex]A = 374.12 cm ^ 2 [/tex] Answer:
 The area of ​​a regular hexagon with a side length of 12 cm is:
 [tex]A = 374.12 cm ^ 2 [/tex]

 Question 2:

 By definition, sides of a triangle 30-60-90 are given by:
 Largest side:[tex] \sqrt{3}x[/tex]
 Smallest side: x
 hypotenuse: 2x
 Therefore, since the smallest side length measures 5 cm, then the hypotenuse is:
 [tex]2x = 2 * 5 = 10 cm [/tex]
 Answer:
 
the length of the hypotenuse when the shorter leg is 5 cm is:
 
10 cm

 
Question 3:

 The first thing you should know for this case, is that angle 30, is a notable angle.
 Therefore, the values ​​of the sine are defined for notables angles.
 The notable angles are:
 0, 30, 45, 60, 90
 Therefore, the value of sine (30) is given by:
 sine (30) = 1/2
 Answer:
 
the exact value of sin 30 ° is:
 
sine (30) = 1/2

4(x − 3) − 5(x + 1) = 3 Which of the following algebraic properties is not needed to solve this equation?

Answers

Hi there!

To solve this problem, you need to use the distributive property. You distribute the 4 inside the parenthesis as well as the 5.

Hope this helps!

Which of the following fractions is in simplest form?
9/16
8/14
6/20
15/35

Answers

9/16
thats the correct answer bro

The correct fraction in simplest form is 9/16. Hence option 1 is true.

Used the concept of the fraction that states,

A fraction is a part of the whole number and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called a fraction.

Ask about the simplest form of a fraction.

When a fraction is in the simplest form then the GCD of numerators and denominators would be 1.

From (i);

9/16

Clearly, GCD (9, 16) = 1

Hence this shows the simplest form of a fraction.

Therefore, option 1 is true.

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What transformations change the graph of f(x) to the graph of g(x)? f(x)=x^2 g(x)=(x+3)^2-7
The graph of g is the graph of f translated to the right 3 units and up 7 units
The graph of g is the graph of f translated to the left 3 units and down 7 units
The graph of g is the graph of f translated up 3 units and to the left 7 units
The graph of g is the graph of f translated down 3 units and to the right 7 units

Answers

The graph of g is the graph of f translated to the left 3 units and down 7 units .

Answer:

The graph of g is the graph of f translated to the left 3 units and down 7 units

Step-by-step explanation:

As you can see, the F(X) graph has its origin on (0,0) since when X is equal to 0, Y will be equal as 0 as well, so having both quadratic graphs, we just have to see how the graph is translated, in this case you just have to make x=0, when X is equal to 0 on g(x) Y=-7, so the graph will be translated 7 units down, the only option you have that has the graph tranlated 7 units down is option 2:"The graph of g is the graph of f translated to the left 3 units and down 7 units"

And that is your correct answer.

Describe how to transform -------- into an expression with a rational exponent.
(a index of 3, square root of x^4) raised to the 5th power

Answers

The answer is :x^20/3

Solution:
Simplify. ( cube root of x to the power of 4 )from the given :(a index of 3, square root of x^4) raised to the 5th power.
=x to the power of 4/3
multiply it by five will give you the answer of x to the power of 20/3

kat had 2 3/5 bags of carrots.she gave 3/4 of a bag of carrots To her sister which shows how many bags of carrots kat had left

Answers

1 17/20 of a bag of carrots

Sam is walking to Joe’s house at a rate of 2 miles per hour. Joe left his house at the same time and is walking at a rate of 1.5 miles per hour. If Sam and Joe live 7 miles apart, how long will it take for Sam and Joe to meet?

Answers

In order to answer this questions, let's suppose,

The time it takes for Sam and Joe to meet in hours= t
Joe's speed = 1.5miles/hour 
Sam's speed = 2 miles/hour
Distance between Joe and Sam = 7 miles
When they meet Joe covers a distance of J miles and Sam covers S miles
Now,
J+S=7
J=1.5 miles/hour *t
S= 2 miles/hour * t
1.5t + 2t =7
3.5 t = 7
t=2 hours
It will take 2 hours for Sam and Joe to meet

1. Use the above figure to answer the following questions.

a. What is the intersection of plane P and plane R?

b. Name three points that are collinear

c. Name plane R in two more ways

d. Name four coplanar points

e. Name a point that lies on both plane P and plane R

Answers

a. Plane R and plane P intersect at AB. 
Planes are when 3 points that are not on the same line can be used to describe a plane. Plane P is horizontal and Plane R is vertical and these 2 planes intersect at line AB. Intersecting is where these 2 planes meet, therefore line AB is common to both planes.

b. 3 points that are collinear are A, D and B. As the word collinear implies, this is when three points or more are all aligned in a single straight line. 

c. Planes can be named indicating three points that are on the same plane yet not on the same line. In other words these points are not collinear. Plane R can be written as DBG or FAD.

d.Coplanar points are three or more points that lie on the same plane. planes are usually flat surfaces, therefore any three or more points lying on this flat surface be used as coplanar points. 4 coplanar points are ACDE, these lie on plane P.

e. A point that lies on both plane P and plane R is point D, as its on the line of intersection, hence its common to both planes.

what ones are relatively prime?

A) 11 & 121
B) 35 & 125
C) 39 & 75
D) 34 & 49

Answers

A) 11 & 121 should be your answer

because you can divide 11 (a prime number) from both numbers, and they both give you prime numbers (1 and 11)

hope this helps

Answer:

it is 34 and 49

Step-by-step explanation:

because i'm big smart

Whole numbers are written on cards and then placed in a bag. Pilar selects a single card, writes down the number, and then places it back in the bag. She repeats this 46 times.

Pilar calculates the relative frequency of each number card.

Outcome 1 2 3 4 5
Relative Frequency 0.05 0.35 0.26 0.13 0.21
Which statement about Pilar's experiment is true?


The outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment.

The outcomes appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment.

The outcomes do not appear to be equally likely, so a uniform probability model is a good model to represent probabilities in Pilar's experiment.

The outcomes appear to be equally likely, so a uniform probability model is a good model to represent probabilities in Pilar's experiment.

Answers

Answer:

Option 1  

The outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment.

Step-by-step explanation:

Given :

The outcomes are :             1         2         3        4        5

The Relative Frequency : 0.05   0.35   0.26   0.13    0.21

To find : Which statement about Pilar's experiment is true?

Solution :

We can see the outcomes do not appear to be equally likely.

Since 0.05 and 1 are not close in number range along with the other options.

So, The outcomes do not appear to be equally likely.

Uniform probability model - A model in which every outcome has equal probability.

But in given case, Probabilities in Pilar's experiment does not support a uniform probability model.

So, A uniform probability model is not a good model to represent probabilities in Pilar's experiment.

Therefore, Option 1 is correct.

The correct statement about Pilar's experiment is: A) The outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment.

To determine whether a uniform probability model is appropriate, we need to assess if each outcome has the same likelihood of occurring. In a uniform probability model, if there are 'n' possible outcomes, each outcome has a probability of 1/n.

In Pilar's experiment, she selects a card 46 times, and we are given the relative frequencies of the outcomes 1 through 5. If the outcomes were equally likely, we would expect each number to have a relative frequency of approximately 1/5, since there are 5 different numbers.

Let's calculate the expected relative frequency for each number if the outcomes were equally likely:

Expected relative frequency for each number = 1/5 = 0.2.

Now, let's compare this with the given relative frequencies:

Number 1 has a relative frequency of 0.05 Number 2 has a relative frequency of 0.35 Number 3 has a relative frequency of 0.26 Number 4 has a relative frequency of 0.13 Number 5 has a relative frequency of 0.21

These relative frequencies are not close to the expected relative frequency of 0.20 for a uniform distribution. Since the relative frequencies vary significantly from one another, the outcomes do not appear to be equally likely. Therefore, a uniform probability model, which assumes equal likelihood for all outcomes, would not be a good fit for Pilar's experiment.

Hence, the correct conclusion is that the outcomes do not appear to be equally likely, and thus a uniform probability model is not suitable for representing the probabilities in Pilar's experiment.

The complete question is Whole numbers are written on cards and then placed in a bag. Pilar selects a single card, writes down the number, and then places it back in the bag. She repeats this 46 times.

Pilar calculates the relative frequency of each number card.

Outcome 1 2 3 4 5

Relative Frequency 0.05 0.35 0.26 0.13 0.21

Which statement about Pilar's experiment is true?

A) The outcomes do not appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment.

B) The outcomes appear to be equally likely, so a uniform probability model is not a good model to represent probabilities in Pilar's experiment.

C) The outcomes do not appear to be equally likely, so a uniform probability model is a good model to represent probabilities in Pilar's experiment.

D) The outcomes appear to be equally likely, so a uniform probability model is a good model to represent probabilities in Pilar's experiment.

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