someone help please!

Answer:

pOH is 2.2

Explanation:

The pH scale goes from 0 to 14. As such, the pH and the pOH add up to 14. Subtract your pH from 14 to get your answer.

14 - 11.8 = 2.2

Answer:

D) 0.001 M AlCl3

Explanation:

The solution with the lowest freezing point would be 0.001 M AlCl3 because it produces the most particles when fully ionized in water, therefore lowering the freezing point the most.

Theoretically, the aqueous solution that will have the lowest freezing point is D) 0.001 M AlCl3. This is based on the principle of colligative properties, which states that the freezing point of a solution is lowered when solutes are added. The extent of this lowering depends on the number of solute particles present. In this case, AlCl3, when fully ionized in water, produces 4 particles (1 Al3+ and 3 Cl-), contributing to the greatest decrease in freezing point.

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Answer:

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Explanation:

Step 1: Data given

Kp = 4.7 x 10^3 at 400K

Pressure of CH3OH = 0.250 atm

Pressure of HCl = 0.600 atm

Volume = 10.00 L

Step 2: The balanced equation

CH3OH(g) + HCl(g) <=> CH3Cl(g) + H2O(g)

Step 3: The initial pressure

p(CH3OH) = 0.250atm

p(HCl) = 0.600 atm

p(CH3Cl)= 0 atm

p(H2O) = 0 atm

Step 3: Calculate the pressure at the equilibrium

p(CH3OH) = 0.250 - X atm

p(HCl) = 0.600 - X atm

p(CH3Cl)= X atm

p(H2O) = X atm

Step 4: Calculate Kp

Kp = (pHO * pCH3Cl) / (pCH3* pHCl)

4.7 * 10³ =  X² /(0.250-X)(0.600-X)

X = 0.249962

p(CH3OH) = 0.250 - 0.249962 = 0.000038 atm

p(HCl) = 0.600 - 0.249962 = 0.350038 atm

p(CH3Cl)= 0.249962 atm

p(H2O) = 0.249962 atm

Kp = (0.249962 * 0.249962) / (0.000038 * 0.350038)

Kp = 4.7 *10³

The pressure of CH3OH and HCl will decrease.

The final partial pressure of HCl is 0.350038 atm

Final answer:

One liter of 1 M NaOH can completely neutralize one liter of 0.50 M H2SO4 because 1 mole of NaOH is needed to neutralize 0.5 mole of H2SO4, according to the stoichiometric relationship in the balanced chemical equation. So the correct option is d.

Explanation:

To determine which molarity of H2SO4 will be completely neutralized by one liter of 1 M NaOH, we need to look at the stoichiometry of the reaction. Sulfuric acid is a diprotic acid, meaning it can donate two protons (H+). The balanced chemical equation for its reaction with sodium hydroxide (NaOH), which is a monoprotic base, is:

       H2SO4(aq) + 2NaOH(aq) → Na2SO4(aq) + 2H2O(l)

From this equation, we can see that it takes two moles of NaOH to neutralize one mole of H2SO4. Therefore, one liter of 1 M NaOH contains one mole of NaOH, and it can completely neutralize 0.5 mol of H2SO4. If we have one liter of H2SO4, the molarity that would supply 0.5 mol would be 0.50 M, because 0.50 mol/L × 1 L = 0.5 mol. The correct answer is option d - 0.50 M H2SO4.

Answer:

where in the book is it

Explanation:

Answer : [tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.

Explanation :

As we know that when strontium hydroxide, [tex]Sn(OH)_2[/tex] dissociates then it gives strontium ion, [tex]Sr^{2+}[/tex] and hydroxide ion, [tex]OH^-[/tex].

The dissociation reaction will be:

[tex]Sr(OH)_2\rightarrow Sr^{2+}+2OH^-[/tex]

[tex]Sn(OH)_2[/tex] will dissociate into strontium ion, [tex]Sr^{2+}[/tex] with a (+2) charge and hydroxide ion, [tex]OH^-[/tex] with a (-1) charge.

Strontium hydroxide, Sr(OH)2, dissociates into one Sr2+ ion and two OH- ions when it dissolves in water.

When Sr(OH)2 (strontium hydroxide) dissociates in water, it separates into ions with specific charges. The chemical equation representing this dissociation is:

Sr(OH)₂ → Sr²⁺ (aq) + 2OH⁻(aq)

This means that one molecule of strontium hydroxide will produce one Sr²⁺ ion and two OH⁻ ions. The Sr²⁺ ion has a plus two charge and each of the OH⁻ ions has a negative one charge.

Answer:

C

Explanation:

A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.

Density is the degree of how closely the mass of matter is compacted. The more compacted the mass is in relation to the amount of volume the matter occupies, the higher its density will be. Conversely, matter that has a low density, has a smaller ratio of mass per amount of volume the matter occupies.

To determine the density of a solid that has regular side lengths, it is first needed to calculate the volume of the solid using the equation volume = length x width x height.

The density of a material depends on the molecular packing.

Therefore, A small, jagged particle with a density of 1.2 g/cm³ deposits on the ground before a large, round particle with a density of 0.82 g/cm³. The one that is most likely influences the rate of deposition of the jagged particle is high density and the correct option is option 3.

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Answer: a) 49.8 gram

b) 47.0 %

Explanation:

First we have to calculate the moles of glucose

[tex]\text{Moles of glucose}=\frac{\text{Mass of glucose}}{\text{Molar mass of glucose}}=\frac{97.5g}{180.15g/mole}=0.54moles[/tex]

The balanced chemical reaction will be,

[tex]C_6H_{12}O_6\rightarrow 2CH_3CH_2OH+2CO_2[/tex]

From the balanced reaction, we conclude that

As,1 mole of glucose produce = 2 moles of ethanol

So, 0.54 moles of glucose will produce =  [tex]\frac{2}{1}\times 0.54=1.08[/tex] mole of ethanol

Now we have to calculate the mass of ethanol produced

[tex]\text{Mass of ethanol}=\text{Moles of ethanol}\times \text{Molar mass of ethanol}[/tex]

[tex]\text{Mass of ethanol}=(1.08mole)\times (46.08g/mole)=49.8g[/tex]

Now we have to calculate the percent yield of ethanol

[tex]\%\text{ yield of ethanol}=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{23.4g}{49.8g}\times 100=47.0\%[/tex]

Therefore, the percent yield is 47.0 %

Final answer:

The theoretical yield of ethanol from the fermentation of 97.5 g of glucose is 49.3 g. The percent yield is 47.4% if the actual yield of ethanol is 23.4 g.

Explanation:

To determine the theoretical yield of ethanol, we need to calculate the molar ratio between glucose and ethanol. According to the balanced equation, for every mole of glucose, two moles of ethanol are produced. Therefore, we can set up a proportion and solve for the theoretical yield:

(97.5 g glucose / 180.15 g/mol) x (2 mol ethanol / 1 mol glucose) x (46.08 g/mol) = 49.3 g ethanol

For the percent yield, we can divide the actual yield (23.4 g) by the theoretical yield (49.3 g) and multiply by 100:

(23.4 g / 49.3 g) x 100 = 47.4%

Answer:

Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.

Cloudy nights can be warmer than clear nights because clouds trap heat absorbed by Earth during daylight hours.

In thermodynamics, heat is defined as the form of energy crossing the boundary of a thermodynamic system by virtue of a temperature difference across the boundary.[1] A thermodynamic system does not contain heat. Nevertheless, the term is also often used to refer to the thermal energy contained in a system as a component of its internal energy and that is reflected in the temperature of the system. For both uses of the term, heat is a form of energy.

Another example of informal usage is the term heat content, used despite the fact that physics defines heat as energy transfer. More accurately, it is thermal energy that is contained in the system or body, as it is stored in the microscopic degrees of freedom of the modes of vibration.

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Answer:

Na2S

Explanation:Just took the test

The chemical formula for the compound formed between sodium and sulfide is Na2S. Sodium has a positive charge and sulfide has a negative charge, which balance when combined in the proportions indicated by the formula.

The chemical formula for the ionic compound formed between the sodium cation, Na+, and the sulfide anion, S²-, is Na2S. This is derived from the fact that sodium (Na) has a positive charge and sulfide (S) has a negative charge.

To balance these charges and form a neutral compound, you need two sodium ions for every sulfide ion. Hence the '2' in Na2S.

This indicates there are two sodium ions in the compound.

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Answer:

Carbonates, Carbides, Carbon oxides

Explanation: Its the answer I promise!!

Answer:

1.16x10^–3 mole

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 formula units. This implies that 1 mole of MgBr2 also contains 6.02x10^23 formula units.

Now, if 1 mole of MgBr2 contains 6.02x10^23 formula units,

Then Xmol of MgBr2 will contain 6.99x10^20 formula units i.e

Xmol of MgBr2 = 6.99x10^20/6.02x10^23

Xmol of MgBr2 = 1.16x10^–3 mole

Answer: N/A

Explanation: You have to write down the equation otherwise we are unable to help you.

Answer :  The percent abundance of Li isotope-1 and Li isotope-2 is, 6.94 % and 93.1 % respectively.

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

[tex]\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i[/tex]   .....(1)

Let the fractional abundance of Li isotope-1 be 'x' and the fractional abundance of Li isotope-2 will be '100-x'

For Li isotope-1 :

Mass of Li isotope-1 = 6.01512 amu

Fractional abundance of Li isotope-1 = x

For Li isotope-2 :

Mass of Li isotope-2 = 7.01600 amu

Fractional abundance of Li isotope-2 = 100-x

Average atomic mass of Li = 6.941 amu

Putting values in equation 1, we get:

[tex]6.941=[(6.01512\times x)+(7.01600\times (100-x))][/tex]

By solving the term 'x', we get:

[tex]x=694.048[/tex]

Percent abundance of Li isotope-1 = [tex]\frac{694.048}{100}=6.94\%[/tex]

Percent abundance of Li isotope-2 = 100 - x = 100-6.94 = 93.1 %

The relative abundance of the isotopes are   7.5% and 92.5%.

The relative atomic mass of an atom is the sum of the products of the relative atomic masses of its isotopes and their respective percentage abundance. We have been told in the question that the relative atomic  mass of Li is 6.941 amu. Let the percentage abundance be x and 1-x

6.941 =  6.01512x +  7.01600(1 - x)

6.941 =  6.01512x +  7.01600 - 7.01600x

6.941 -  7.01600 = -1.00088x

-0.075 = -1.00088x

x = -0.075/-1.00088

x = 0.075

Hence, the other isotope is 1 -  0.075 = 0.925

Therefore, the relative abundance of the isotopes is 7.5% and 92.5%

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Answer:

Budding- A new organism growing from the body of the parent

Fragmentation- The parent breaks into parts that may regenerate into offspring

Binary Fission- The parent cell divides to produce a genetically identical cell

Answer: A new organism growing from the body of the parent

Fragmentation- The parent breaks into parts that may regenerate into offspring

Binary Fission- The parent cell divides to produce a genetically identical cell

Answer:

the wet bulb will get warmer because their will be a smaller difference between the the dry/wet bulb temps.

Explanation:

At any given ambient temperature, less relative humidity results in a greater difference between the dry-bulb and wet-bulb temperatures; the wet-bulb is colder.

For your problem, this is opposite, therefore it will get warmer.

Answer:

Na2O

Explanation:

This is because a bond between a metal and a non-metal has occured.

Final answer:

In Na₂O, two sodium atoms transfer one electron each to the oxygen atom, forming a neutral ionic compound with a ratio of two sodium ions to one oxide ion.

Explanation:

Among the options given, the compound in which electrons have been transferred to an oxygen atom is Na₂O. In Na₂O, two sodium (Na) atoms each donate one electron to the oxygen (O) atom. This transfer of electrons is what forms the ionic bond in Na₂O. Each sodium atom becomes positively charged (Na+), and the oxygen atom gains two electrons to become negatively charged (O₂-). This results in the formation of a neutral ionic compound with a ratio of two sodium ions to one oxide ion.

Answer:

The volume is occupies by 21,0g of methane is 32, 3 L.

Explanation:

We use the formula PV=nRT. We convert the unit temperature Celsiud into Kelvin: 0°C=273 K---> 27°C= 27+273= 300K. We calculate the weight of 1 mol of CH4:

Weight 1 mol CH4= Weight C+ (Weight H)x4= 12 g+ 1g x4= 16 g

16 g---1 mol CH4

21g---x= (21g x 1 mol CH4)/16g= 1, 31 mol CH4

PV=nRT    ----> V= (nRT)/P

V= (1, 31 mol x 0,082 l atm/K mol x 300 K)/ 1 atm

V= 32, 3875 L

The volume occupied by 21.0 g of methane (CH4) at 27 degree celsius and 1 atm is 32.3L

PV = nRT

Where;

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Final answer:

Untreated sewage dumped into a river causes significant harm to aquatic life, leading to sickness and fatalities among animals, degradation of water quality, and the creation of dead zones. These pollutants also pose a risk to human health as they can travel up the food chain.

Explanation:

The effect of untreated sewage being dumped into a river on the animals living therein is typically devastating. The correct answer to the question, 'What effect has the raw sewage had on the animals that live in the river?' is C) Many animals have become sick or have been found dead.

Water pollution from untreated sewage includes harmful bacteria and chemicals that can cause disease and death in river ecosystems. Pollutants like nitrogen and phosphorus can lead to eutrophication, which depletes the oxygen in the water, creating dead zones where fish and other aquatic life cannot survive. Additionally, contaminated water can carry diseases and toxins up the food chain, posing health risks to animals and humans alike.

Industrial waste and agricultural runoff also contribute to the degradation of water quality, affecting not only the immediate area but also environments downstream. This contamination has a cascading effect on ecosystems, harming countless plants, animals, and humans who depend on these water sources.

Answer:

It is given that number of electrons is 11.

It is known that when an atom is neutral then the number of protons equals number of electrons. Also, atomic number means number of protons an atom holds.

Whereas mass number equals number of protons + number of neutrons. Thus, mass number of given atom is 11 + 13 = 24.

The symbol for this element will be as follows 24/11x  . This atom sodium has atomic number 11 and mass number 24.

Therefore, symbol of this radioactive nuclide is as follows . A)Superscript 24 subscript 11 upper N a.

Answer:

Answer Is A

Explanation:

24/11 NA: This answer was correct

Final answer:

Potassium nitrate is the most likely to be soluble among the options given because all nitrates are known to be soluble in water, while Iron carbonate and Copper oxide are typically insoluble.

Explanation:

Among the given options of salts—Potassium nitrate, Iron carbonate, and Copper oxide—the one most likely to be soluble is Potassium nitrate. This is due to the general solubility rule that all nitrates are soluble in water. Salts containing the large, singly charged NO₃⁻ ion, such as Potassium nitrate, tend to form highly soluble compounds, while carbonates (like Iron carbonate) and oxides (like Copper oxide) are often less soluble or insoluble except in the presence of certain cations like potassium, sodium, and ammonium.

Iron carbonate and Copper oxide are generally insoluble in water. For instance, iron(II) carbonate is not soluble except when combined with cations like potassium, sodium, or ammonium. Similarly, Copper oxide's solubility is very low in water. On the contrary, even though Copper sulfate is not provided as an option, it is worth mentioning that many sulfates, unlike carbonates and oxides, are generally soluble, with few exceptions.

The step which best describes asexual rather than sexual reproduction is that "in some organisms, a piece of the parent may bud off to produce offspring." Thus, the correct option for this question is C.

Asexual reproduction may be defined as a mode of reproduction in which a new offspring is significantly produced or constructed by a single parent itself. This mode of reproduction does not involve the fusion of gametes or a change in the number of chromosomes.

The new individuals produced through asexual reproduction are genetically and physically identical to each other along with their parents, i.e., they are the clones of their parents. This type of reproduction is mediated via mitosis.

Therefore, the correct option for this question is C.

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Answer:C) More energy was absorbed in the breaking of chemical bonds than released in the formation of chemical bonds.

Explanation:

Answer:

The rate of the reaction is proportional to the square of the concentration of the reactant.

Explanation:

Let us assume a hypothetical reaction in which the rate determining step is the elementary reaction;

2A------> A2

The rate of reaction will be given by:

Rate= k[A]^2

Hence for a second order reaction having only one reactant, the rate of reaction is proportional to the square of the concentration of the reactant. The proportionality constant k, is known as the rate constant of the reaction.

Answer:

The gas will occupy a volume of 4000L

Explanation:

V1 = 2000L

T1 = 100K

P1 = 100kPa = 100*10³Pa

T2 = 400k

P2 = 200kPa = 200*10³kPa

V2 = ?

To solve this question, we need to use combined gas equation

[(P₁ * V₁) / T₁] = [(P₂ * V₂) / T₂]

V₂ = (P₁ * V₁ * T₂) / (P₂ * T₁)

V₂ = (100*10³ * 2000 * 400) / (200*10³ * 100)

V₂ = 8.0*10¹⁰ / 2.0*10⁷

V₂ = 4000L

The new volume of the gas is 4000L

Answer:

The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa is 4000. L

Explanation:

Here we are required to utilize the combined gas equation as follows;

[tex]\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}[/tex]

Where:

P₁ = Initial pressure of the gas = 100.0 kPa

V₁ =  Initial volume of the gas = 2000. L

T₁ =  Initial temperature of the gas = 100.0 K

P₂ = Final pressure of the gas = 200.0 kPa

V₂ =  Final volume of the gas = Required

T₂ =  Final temperature of the gas = 400.0 K

Making V₂ the formula subject of the combined gas equation, we have;

[tex]V_{2}}{} = \frac{P_{1}\times V_{1}\times T_{2} }{T_{1}\times P_{2}}[/tex]

Therefore, by plugging the values, we have;

[tex]V_{2}}{} = \frac{100.0\times 2000\times 400.0 }{100.0 \times 200.0 } = 4000. \, L[/tex]

The volume that the gas will occupy when the temperature is increased to 400.0 K and the pressure is increased to 200. kPa = 4000. L.

Answer:

killer whale

Explanation:

Answer:

c

Explanation:

im taking the test right now

Answer:

8L will be the new volume

Explanation:

Let's use the Ideal Gases Law to determine the answer of this question:

Pressure . volume = number of moles . R . T

P . V = n . R . T

We can propose the two situation for the gas:

P₁ . V₁ = n₁ . R . T₁

P₂ . V₂ = n₁ . R . T₂

Notice that R is a constant and n₁ (moles of gas), is not modified with the changes, so we can cancel them.

For the second situation: P₂ = P₁/8 and T₂ = T₁/9

(P₁ . 9L) / T₁ = (P₁/8 . V₂) / T₁/9

(P₁ . 9L) / T₁ . T₁/9 = (P₁/8 . V₂)

P₁ . 1L = P₁/8 . V₂

P₁ . 1L . 8/P₁ = V₂ → 8L

You can also see it, if you put numbers, for example

1 mol of the gas at 1 atm, let's find out the temperature:

1 atm . 9L = 1 mol . 0.082 . T

9/ 0.082 = 110 K

Second situation: 1/8 atm . V = 1 mol . 0.082 . 110/9 K

V = (1 mol . 0.082 . 110/9 K) . 8 atm → 8.02 L ≅ 8L

Answer:

it will halves

Explanation:

if the volume is doubled then the pressure is halves.

Answer:

3.4g of Al

Explanation:

you would need to start with 3.4 g of Al

Answer:

A

Explanation:

N2(g) + 3H2(g) -> 2NH3(g)

According to Le Chatelier's principle, and since H2(g) is on the left side and a reactant, if it's concentration is increased, the equilibrium shifts to the right and the forward reaction is favoured, leading to the production of more NH3(g). The rate of the forward reaction increases.

As the concentration of H2(g) is increased, the concentration of the other reactant, N2(g) decreases as more of it is used up to react with the excess H2(g)

The forward reaction would increase to start reducing the concentration of N2.

Explanation: