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Two angels re supplementary. The larger angle is 48 degrees more than the 10 times the smaller angle. Find the measure of each angle.
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STEP 1:
find the value of x
x= smaller angle
10x + 48= larger angle
Add the two angles above to equal 180.
x + (10x + 48)= 180
combine like terms
11x + 48= 180
subtract 48 from both sides
11x= 132
divide both sides by 11
x= 12° smaller angle
STEP 2:
find the value of the second angle
=10x + 48
=10(12) + 48
=120 + 48
=168° larger angle
CHECK:
12° + 168°= 180°
180°= 180°
ANSWER: The smaller angle is 12° and the larger angle is 168°.
Hope this helps! :)
Need help ASAP ! Please !!
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Hope this helps.
If 5 balls are placed randomly into 3 bins, what is the expected number of balls in each bin?
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Jordan travels 3/4 of a mile longer to school each day than harisson does. combined, they have traveled 5 1/4 miles to school. how far does each trave;?
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let harissom travel Y mile
given
X=Y plus 3/4 of y =1.75Y (3/4=0.75)
X+Y = 5.25(1/4=0.25)
now we can just put thevalue of X and we get
X+Y=5.25
1.75Y + Y= 5.25
Y=1.909
x= 1.75 × 1.909= 3.341
A rectangular storage box is 12in. wide,15. long,and 9 in. high.how many square inches of colored paper are needed to cover the surface of the box?
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(I had a question just like this)
Given that ABCD is a rhombus, find the value of x (x-10)
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To start, a rhombus will have perpendicular bisectors.
With that, we know that the section where these bisectors cross will create 90 degree angles.
So now we have angles: x, (x-10), and 90.
A triangle will total 180 degrees in total. So if we add up all of these angles, it will total to exactly 180.
In other words: 90+x+(x-10)=180.
So, in this situation, we want to isolate the variables, and find the value of x.
This is the easy part:
Here's that equation again
90+x+(x-10)=180
Subtract 90 from both sides
90-90+x+(x-10)=180-90
x+(x-10)=90
Add 10 to both sides
x+x-10+10=90+10
x+x=100
2x=100
Divide by 2 on both sides
2x/2=100/2
x=50
There's your x value.
Please help. Web making by spiders is an example of which of the following
A. Innate behavior
B. Courtship
C.defensive behavior
D.reproducing
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C. It's not defensive. It's meant to trap food. Spiders are carnivores and they eat what they catch. Webs are sticky and their pray can't get away.
A. Webs are constructed out of different types of silk, depending on what the web is for. The only thing you can eliminate is C. The silk itself is attractive to the opposite sex so courtship is a possibility. After the spider reproduces, the egg can be placed in a very dense covering of silk.
A is the all encompassing answer to the 11 things webs their silk are used for by spiders.
A <<<< answer.
Find the measure of an angle with measure between 0° and 360° that is coterminal with an angle measuring –800°. °
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-800+360=-440
-440+360=-80
-80+360=280
So the angle is 280 degrees.
Answer:
280
Step-by-step explanation:
I need the answer I need help with this question
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The origin is the midpoint between each vertex and its image.
Negate every coordinate value, for example, J(-5, -3) gets rotated to J'(5, 3).
Find an explicit rule for the nth term of the sequence. 9, 36, 144, 576, ...
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The answer is an = 9 • 4n - 1
The explicit rule for the [tex]nth[/tex] term of the given sequence is [tex]a_n=9(4)^{n-1}[/tex].
Given:
The given sequence is [tex]9,36,144,576[/tex].
To find:
The explicit rule for the [tex]nth[/tex] term of the given sequence.
Explanation:
the first term of the sequence is [tex]9[/tex].
The ratios of two consecutive terms are:
[tex]\dfrac{36}{9}=4[/tex]
[tex]\dfrac{144}{36}=4[/tex]
[tex]\dfrac{576}{144}=4[/tex]
The given sequence is a geometric sequence because the sequence has a common ratio [tex]4[/tex].
The explicit formula for the [tex]nth[/tex] term is:
[tex]a_n=ar^{n-1}[/tex]
Where, [tex]a[/tex] is the first term and [tex]r[/tex] is the common ratio.
Substituting [tex]a=9,r=4[/tex], we get
[tex]a_n=9(4)^{n-1}[/tex]
Therefore, the explicit rule for the [tex]nth[/tex] term of the given sequence is [tex]a_n=9(4)^{n-1}[/tex].
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What is (4a)^2 without exponents?
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need help for question one in polynomials
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Answer:
a) monomial
b) constant
c) binomial
d) trinomial
e) binomial
f) constant
g) monomial
Step-by-step explanation:
Let's start by defining the terms in the question:
A monomial is an expression with a single term, regardless of how many variables are in the term.
A binomial is an expression with two different terms, which cannot be combined into a single term due to their variables not matching.
A trinomial is an expression with three different terms, which cannot be combined into a binomial or monomial because their variables do not match.
A constant is an integer that lacks a variable attached to it. An integer with a variable attached to it would be a monomial, and the integer itself would be called a coefficient.
Now, we can get into the parts of the question:
a) 8a²b is two variables however it is still a single term so this is a monomial.
b) -39 is an integer with no variables attached. Therefore, it is a constant.
c) x + y is two variables and two different terms that cannot be combined into one single term. It is a binomial.
d) -12xy + 5y - x² showcases three different variables and three different terms that cannot be consolidated. Thus, it is a trinomial.
e) 2x² + 2y² demonstrates two different variables and two different terms that are not alike. As such, we have a binomial.
f) 3/4 is an integer with no variables in sight. We have here a constant.
g) -32m²n² has two variables but is only a single term on its own. This is a monomial.
What are the coordinates of the center of a circle whose equation is (x + 7)2 + (y – 5)2 = 16?
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The standard form of the equation of a circle is the following:
[tex](x - a) {}^{2} + (y - b) {}^{2} = r {}^{2} [/tex]
In this equation r represents the radius of the circle and the point (a, b) is its centre.
Therefore, the centre of the circle
[tex](x + 7) {}^{2} + (y - 5) {}^{2} = 16[/tex]
is the point ( - 7, 5).
the frequency of the musical note E3 is about 164.81 Hz.
what is the frequency of the note a perfect fifth above E3.
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Therefore, we can set the proportion:
164.81 : x = 2 : 3
which gives:
x = 164.81 × 3 ÷ 2
= 247.21
Hence, the perfect fifth above E₃ will have a frequency of 247.21Hz which corresponds to a B₃.
Answer: 247.215 Hz
Step-by-step explanation:
We know that in music theory, a perfect fifth is a musical interval having inverse perfect fourth that corresponds a pair of pitches with a frequency ratio of 3:2.
Let the frequency of the note a perfect fifth above [tex]E_3[/tex] be x, then we have the following proportion.
[tex]x:164.81::3:2\\\\\Rightarrow x=\dfrac{3\times164.81}{2}=247.215[/tex]
Hence, the frequency of the note a perfect fifth above [tex]E_3[/tex] is 247.215 Hz.
One hose can fill a pool in 12 hours. another hose can fill the same pool in 8 h
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Explanation:
One hose can fill a pool in 12 hours.
The other house can fill the same pool in 8 hours.
If they fill the pool together,
[tex]\text {Time Needed } = \cfrac{12 \times 8}{12 + 8} = 4.8 hours [/tex]
HELP ME PLS BBRAINLIESST AND 10 POINTS
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Look on the row for "not like pink". Your probability is the number under "not like black" divided by the total for "not like pink".
A card is drawn from a well shuffled deck of 52 cards. find the probability of drawing a club or a diamond
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[tex] |\Omega|=52\\
|A|=26\\\\
P(A)=\dfrac{26}{52}=\dfrac{1}{2}=50\% [/tex]
In bridge each player is dealt a hand of 13 cards from a deck of 52 cards. there are 4 aces in the entire deck. what are the expected number of aces in a single hand of cards?
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Expected number of aces in a single hand of cards = 1/13 x 13 = 1
Answer: 1 ace card
you deposit $400 in a saving account with an annual rate of 4%. At this rate how much money will you have after 10 years?
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A = original amount
r = rate of interest
t = time
Plug in the numbers: y = 400(1.04)^10
y = $592.10
Maria is playing a game where she is trying to draw a spade from a standard deck of cards. if she doesn't get a spade, she replaces the card, shuffles the deck, and tries again. if she draws a card 3 times and doesn't get a spade, she loses. what is the probability that maria loses the game?
A.17.8%
B.23.7%
C.42.2%
D.31.6%
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Answer:
The correct answer is C. 42.2%
Step-by-step explanation:
Total number of cards in the deck of playing cards = 52
Number of spades in the deck of playing cards = 13
Number of cards other than spade = 52 - 13
= 39
If she draws a card 3 times and doesn't get a spade, she loses.
So, She loses only if he gets all the three cards other than spade
[tex]\text{Probability that she does not get a spade in first draw = }\frac{39}{52}[/tex]
Now, The card is replaced if she does not get a spade.
[tex]\text{So, Probability that she does not get a spade in second draw = }\frac{39}{52}[/tex]
[tex]\text{Similarly, Probability that she does not get a spade in third draw = }\frac{39}{52}[/tex]
[tex]\text{Thus, Probability that she will lose the game = }\frac{39^3}{52^3}=0.422[/tex]
[tex]\text{Also, The percentage of Probability that she will lose the game = }0.422\times 100=42.2\%[/tex]
Hence, The correct answer is C. 42.2%
I would appreciate it if someone could take a look at my work on this calculus question and let me know if my work is correct!
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_____
The second blue line in part A should identify the point on the curve as (-1, 1).
You can stop at any point in the development of the equation for a line, as the problem only asks for "an equation", not one in any specific form.
Mark runs 3/4 of a mile each day for 5 days. What is the total distance that Mark has run after 5 days? A.3 3/4 B.4 1/4 C.5 3/4 D.6 2/3
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Your answer is A.
Final answer:
To find the total distance Mark has run after 5 days, multiply his daily distance of 3/4 mile by 5 days, resulting in A.3 3/4 miles.
Explanation:
The question asks us to find the total distance that Mark runs over 5 days, given that he runs 3/4 of a mile each day. To find the total distance, we simply multiply the daily distance by the number of days.
Multiply the daily distance (3/4 mile) by the number of days (5 days):
(3/4) × 5 = 15/4
Convert the improper fraction to a mixed number:
15/4 is equivalent to 3 whole miles and 3/4 of a mile, which can be written as 3 3/4 miles.
Therefore, after 5 days, Mark has run a total distance of A.3 3/4 miles.
Volume of pyramids and cones day 1
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and the volume of the pyramid is = V= l w h/3
Hope this helps!
can I get a brainleist
List the following stocks and bonds in order from lowest default risk to highest default risk:
Bond in a stable foreign government
Preferred stock
Common stock
A. foreign government bond, common stock, preferred stock
B. foreign government bond, preferred stock, common stock
C. common stock, preferred stock, foreign government bond
D. preferred stock, common stock, foreign government bond
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Common and preferred stock both represent the ownership of a corporation, but preferred stockholders are paid before common stockholders, both in good and bad times.
Therefore, from least to highest default risk we have a bond in a stable foreign government, preferred stock and then, common stock.
Hence, the correct answer is B. foreign government bond, preferred stock, common stock.
The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square kilometers, find the dimensions of the rectangle.
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2x - 6 = the width as given in the description.
Area of a rectangle is length * width. Now we plug in.
108 = x(2x - 6)
108 = 2x² - 6x
We are going to get all terms on the same side and factor.
2x² - 6x - 108 = 0
Factor out and divide each term by a GCF of 2 to get:
x² - 3x - 54 = 0
x² + 6x - 9x - 54 = 0
x(x + 6) - 9(x + 6) = 0
Your factors are (x + 6)(x - 9) = 0. Now we set each binomial equal to zero. This gives us x = - 6 and x = 9. Distance cannot be measure in negative numbers so we know to use x = 9 to find our measurements.
The length (x) is 9 kilometers. The width (2x - 6) is 12 kilometers when you plug in 9 where the x is.
The dimensions of the rectangle are [tex]\( \boxed{9 \text{ km} \times 12 \text{ km}} \)[/tex].
Let's denote the length of the rectangle as [tex]\( l \)[/tex] kilometers, and its width as [tex]\( w \)[/tex] kilometers.
From the problem statement, we have two pieces of information:
1. The width is 6 kilometers less than twice the length:
[tex]\[ w = 2l - 6 \][/tex]
2. The area of the rectangle is 108 square kilometers:
[tex]\[ lw = 108 \][/tex]
Now we can substitute the expression for \( w \) from the first equation into the second equation:
[tex]\[l(2l - 6) = 108\][/tex]
Expand and simplify the equation:
[tex]\[2l^2 - 6l = 108\][/tex]
Subtract 108 from both sides to set the equation to zero:
[tex]\[2l^2 - 6l - 108 = 0\][/tex]
Divide every term by 2 to simplify:
[tex]\[l^2 - 3l - 54 = 0\][/tex]
Now, we'll solve this quadratic equation using the quadratic formula, [tex]\( l = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)[/tex], where [tex]\( a = 1 \)[/tex], [tex]\( b = -3 \)[/tex], and [tex]\( c = -54 \)[/tex]:
[tex]\[l = \frac{-(-3) \pm \sqrt{(-3)^2 - 4 \cdot 1 \cdot (-54)}}{2 \cdot 1}\][/tex]
[tex]\[l = \frac{3 \pm \sqrt{9 + 216}}{2}\][/tex]
[tex]\[l = \frac{3 \pm \sqrt{225}}{2}\][/tex]
[tex]\[l = \frac{3 \pm 15}{2}\][/tex]
This gives us two possible solutions for [tex]\( l \)[/tex]:
[tex]\[l = \frac{18}{2} = 9 \quad \text{or} \quad l = \frac{-12}{2} = -6\][/tex]
Since length cannot be negative, we take [tex]\( l = 9 \)[/tex] kilometers.
Now, substitute [tex]\( l = 9 \)[/tex] back into the expression for [tex]\( w \)[/tex]:
[tex]\[w = 2l - 6 = 2 \cdot 9 - 6 = 18 - 6 = 12\][/tex]
Therefore, the dimensions of the rectangle are:
- Length [tex]\( l = 9 \)[/tex] kilometers
- Width [tex]\( w = 12 \)[/tex] kilometers
To verify, calculate the area:
[tex]\[l \times w = 9 \times 12 = 108 \text{ square kilometers}\][/tex]
Since this matches the given area, the dimensions [tex]\( l = 9 \)[/tex] kilometers and [tex]\( w = 12 \)[/tex] kilometers are correct.
Thus, the dimensions of the rectangle are [tex]\( \boxed{9 \text{ kilometers} \times 12 \text{ kilometers}} \)[/tex].
1.)Simplify the expression: 4 times Start Root 18 End Root plus 5 times Start Root 32 End Root
2.)Simplify the expression: 7 times Start Root 5 End Root minus 3 times Start Root 80 End Root
3.)Simplify the expression: Start Root 21 End Root times Left Parenthesis Start Root 3 End Root plus Start Root 14 End Root Right Parenthesis.
4.)Simplify by rationalizing the denominator: Start Fraction 4 over Start Root 10 End Root minus Start Root 6 End Root End Fraction
I WILL MAKE YOU THE BRAINIEST! PLEASE HELP
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2.) -5 start root 5 end root
3.) 3 start root 7 end root + 7 start root 6 end root
4.) start root 10 end root + start root 6 end root
hope this helped :)
Answer:
I agree with Sydneyjones :D i very much agree
1.) 32 start root 2 end root
2.) -5 start root 5 end root
3.) 3 start root 7 end root + 7 start root 6 end root
4.) start root 10 end root + start root 6 end root
The length of a rectangle is increasing at a rate of 3 cm/s and its width is increasing at a rate of 5 cm/s. when the length is 14 cm and the width is 9 cm, how fast is the area of the rectangle increasing?
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Differentiate with respect to time:
dA
----- = L*(dW/dt) + W*(dL/dt)
dt
Here,
dA
----- = (14 cm)*(5 cm/sec) + (9 cm)*(3 cm/sec)
dt
Finish the indicated multiplication and addition to obtain your final answer.
The area of the rectangle at L = 14 cm and B = 9 cm is increasing at 97 cm²/s.
What is the area of rectangle?
The area of a rectangle is given by -
A[R] = L x B
Given is the length of a rectangle is increasing at a rate of 3 cm/s and its width is increasing at a rate of 5 cm/s.
Now, we can write -
dL/dt = 3 cm/s
dB/dt = 5 cm/s
We know, that the area is -
A = LB
differentiating both sides with respect to [t], we get -
dA/dt = L dB/dt + B dL/dt
dA/dt = 5L + 3B
At L = 14 cm and B = 9 cm.
(dA/dt) [14, 9] = 5 x 14 + 3 x 9 = 70 + 27 = 97 cm²/s
Therefore, the area of the rectangle at L = 14 cm and B = 9 cm is increasing at 97 cm²/s.
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HELP, MARKING BRAINLIEST
How many compass settings are required to complete the construction?
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Hint: if you don't know the answer you can count the number of arcs
What is the approximate difference in the growth rate of the two populations? The approximate difference in the growth rate is 10 percent. The approximate difference in the growth rate is 40 percent.
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Answer:
B
Step-by-step explanation:
The approximate difference in the growth rate is 40 percent.
a bag contains 30 lottery balls numbered 1-30 a ball is selected replaced then another is drawn find each probability
p ( and even,then odd )
p ( 7, then a number greater than 16)
p ( a multiple of 5, then a prime number )
p ( two even number )
Answers
Answer:
Given : A bag contains 30 lottery balls numbered 1-30 a ball is selected replaced then another is drawn.
To find : Each probability
1) p ( and even,then odd )
2) p ( 7, then a number greater than 16)
3) p ( a multiple of 5, then a prime number )
4) p ( two even number )
Solution :
[tex]\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}[/tex]
1) There are 15 even numbers and 15 odd numbers.
Probability of getting even first then odd is
[tex]\text{P(even,then odd)}=\frac{15}{30}\times\frac{15}{30}[/tex]
[tex]\text{P(even,then odd)}=\frac{225}{900}=\frac{1}{4}[/tex]
2) Number greater than 16 out of 30 are 14.
Probability of getting 7 first then a number greater than 16 is
[tex]\text{P(7, then a number greater than 16)}=\frac{1}{30}\times\frac{14}{30}[/tex]
[tex]\text{P(7, then a number greater than 16)}=\frac{14}{900}=\frac{7}{450}[/tex]
3) Multiple of 5 - 5,10,15,20,25,30=6
Prime numbers - 2,3,7,9,11,13,17,19,23,29=10
Probability of getting a multiple of 5, then a prime number is
[tex]\text{P(a multiple of 5, then a prime number )}=\frac{6}{30}\times\frac{10}{30}[/tex]
[tex]\text{P(a multiple of 5, then a prime number )}=\frac{60}{900}=\frac{1}{15}[/tex]
4) There are 15 even numbers.
Probability of getting two even number is
[tex]\text{P( two even number)}=\frac{15}{30}\times\frac{15}{30}[/tex]
[tex]\text{P( two even number)}=\frac{225}{900}=\frac{1}{4}[/tex]