1. Acceleration: [tex]0.375 m/s^2[/tex]
Newton's second law states that the net force on an object is equal to the product between the object's mass and its acceleration:
F = ma
where
F is the net force
m is the mass
a is the acceleration
For the crate in this problem we have
F = 60 N
m = 160 kg
Re-arranging the equation, we can find the acceleration of the crate:
[tex]a=\frac{F}{m}=\frac{60 N}{160 kg}=0.375 m/s^2[/tex]
2. Distance: 3 m
For this problem we can use the following SUVAT equation:
[tex]S=ut+\frac{1}{2}at^2[/tex]
where
S is the distance travelled by the crate
u = 0 is the initial velocity, since it starts from rest
t = 4 s is the time elapsed
[tex]a=0.375 m/s^2[/tex] is the acceleration
Substituting all numbers into the equation,
[tex]S=0+\frac{1}{2}(0.375)(4)^2=3 m[/tex]
3. Work done: 180 J
The work done by a force, assuming that the force is parallel to the displacement of the object, is given by
W = F d
where
W is the work done
F is the magnitude of the force
d is the displacement
Here we have
F = 60 N
d = 3 m
So the work done is
[tex]W=(60 N)(3 m)=180 J[/tex]
4. Final velocity: 1.5 m/s
The final velocity of the crate can be found by using the following SUVAT equation:
[tex]v^2 = u^2 +2ad[/tex]
where here
u = 0 is the initial velocity
[tex]a=0.375 m/s^2[/tex] is the acceleration
d = 3 m is the distance covered
Substituting all the numbers that we have, we found:
[tex]v=\sqrt{u^2 +2ad}=\sqrt{0^2+2(0.375)(3)}=1.5 m/s[/tex]
5. Kinetic energy: 180 J
The kinetic energy of an object is given by
[tex]K=\frac{1}{2}mv^2[/tex]
where
m is the mass of the object
v is the velocity
Here we have
m = 160 kg is the mass of the crate
v = 1.5 m/s is its final velocity
So the kinetic energy of the crate is
[tex]K=\frac{1}{2}(160)(1.5)^2=180 J[/tex]
A famous physics tale is about a rich man who was found dead. He was
stuck in the middle of a frozen lake where the ice was completely
frictionless, making it impossible to walk. The man was found clutching a
heavy bag of money, with which he could have saved himself had he not
been so miserly.
How could the rich man have saved himself using Newton's third law?
A)He could have thrown the money upwards, creating a vertical
reaction force on himself.
B)He could have dropped the bag of money, creating a horizontal
reaction force on himself.
C)He could have thrown the bag of money sideways, creating a
horizontal reaction force on himself.
D)He could have thrown the money upwards, creating a horizontal
Explanation:
According to Newton's third law of motion, when two bodies interact between them, appear equal forces and opposite senses in each of them.
To understand it better:
Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude and direction but in the opposite direction on the first.
So, if the rich man had pushed the bag of money horizontally opposite of where he was, he could have saved himself.
Four identical light bulbs (B1, B2, B3, and B4) and
six voltmeters are connected as shown in the figure.
Assuming that V is as its original reading when all bulbs
are working and V' is as its reading when B2 is caught
on fire. If B2 were to be caught on fire, the reading of V
is ...
Answer:
(D) V > V' > 1/2 V
Explanation:
When B₂ is in the circuit, the equivalent resistance is:
Req = R + (1/R + 1/2R)^-1
Req = R + 2/3 R
Req = 5/3 R
So the current in B₁ is:
I = V/R
I = V₀ / (5/3 R)
I = 3/5 V₀/R
Therefore, the reading of V₁ is:
V = IR
V₁ = (3/5 V₀/R) R
V₁ = 3/5 V₀
V₁ = 0.6 V₀
After B₂ is removed, the equivalent resistance is:
Req = 3 R
So the current in B₁ is:
I = V/R
I = V₀ / (3 R)
I = 1/3 V₀/R
Therefore, the new reading V₁' is:
V = IR
V₁' = (1/3 V₀/R) R
V₁' = 1/3 V₀
V₁' = 0.333 V₀
The new voltage is less than the original voltage, but more than half the original voltage. The answer is D.
A runner has an initial velocity of 4 meters per second. After 20 seconds, the runner's velocity is 6 meters per second. Which is the runner's acceleration?
A.
1 meter/second/second in the same direction of travel
B.
0.1 meters/second/second in the same direction of travel
C.
–1 meter/second/second in the same direction of travel
Answer:
B. 0.1 meters/second/second in the same direction of travel.
Explanation:
Acceleration is the rate of change of velocity. Acceleration is a vector quantity.
a=Δv/Δt
=(v₂-v₁)/(t₂-t₁)
v₁=4 m/s
v₂=6 m/s
t₁=0 s
t₂=20 s
a=(6m/s-4m/s)/(20s-0)
= 0.1 m/s² in the same direction of travel.
Therefore acceleration =0.1 meters/second/second in the same direction of travel.
The acceleration of runner is [tex]\bold{0.1 \ m / s^{2}}[/tex] if his initial velocity is 4 m⁄s and after 20 seconds the runner's velocity is 6 m⁄s.
Option: B
Explanation:From given we came to know that the runner starts his initial velocity is 4 , and in 20 s speeds up to 6 m⁄s, to find acceleration of runner, we know that acceleration is ratio of change in velocity to change in time.
The acceleration is given by the formula:
[tex]\text { Acceleration }=\frac{\text { Change in velocity }}{\text { Change in time }}[/tex]
We know that change in velocity as 4 m/s to 6 m/s and change time as 20 s.
[tex]\Rightarrow \text { Acceleration }=\frac{6-4}{20}[/tex]
[tex]\therefore \text { Acceleration }=0.1 \ \mathrm{m} / \mathrm{s}^{2}[/tex]
Therefore, acceleration of runner will be [tex]0.1 \ m / s^{2}[/tex]
What is Scientific Notation?
A. It is a way to abbreviate very large or very small numbers.
O
B. It is a special way of writing that looks scientific.
O
C. It is writing scientific summaries in a journal.
D. It is a way of making numbers scientific.
Answer:
A. It is a way to abbreviate very large or very small numbers.
Explanation:
Scientific Notation is a way to abbreviate very large or very small numbers.
A ball is moving at a speed of 5 mi/h along a frictionless surface. It will continue moving at this speed as long as (Select all that apply)
A) something keeps pushing it because it requires a force to continue its motion
B) balanced forces act up on it because an unbalanced force will change its motion
C) something keeps pulling it because it requires a force to continue its motion
D) no forces act upon it because it’s inertia will allow it to continue moving at a constant velocity
The ball will continue moving at this same speed as long as no external forces act upon it because it’s inertia will allow it to continue moving at a constant velocity. So, option D is correct.
What is meant by inertia ?Inertia of an object is defined as the tendency of the object to continue its state of rest or uniform motion.
Here,
The ball is moving along a frictionless surface with a speed of 5 m/h.
This motion of the ball will be continued as long as no external force acts on it. This is because,
According to Newton's first law, a moving body will continue its state of uniform motion unless it is acted upon by an external force. So, an external force like a push or pull is required to change the speed of the ball as well as to change the direction of motion of the ball. Therefore the ball will continue its motion with the same speed and direction due to its property of inertia of motion.
Hence,
The ball will continue moving at this same speed as long as no external forces act upon it because it’s inertia will allow it to continue moving at a constant velocity.
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Final answer:
A ball on a frictionless surface will maintain its speed of 5 mi/h due to inertia and balanced forces, meaning no additional force is required to keep it in motion. Statements B and D accurately describe this scenario according to Newton's laws of motion.
Explanation:
A ball moving at a speed of 5 mi/h along a frictionless surface will continue moving at this speed if certain conditions are met. According to physics principles, particularly Newton's laws of motion, an object in motion will stay in motion at a constant speed in a straight line unless acted upon by a net force. Therefore, the correct answers are:
(B) Balanced forces act upon it because an unbalanced force will change its motion.(D) No forces act upon it because its inertia will allow it to continue moving at a constant velocity.Both statements B and D are true because in the absence of external forces, such as friction, the ball's inertia will keep it moving indefinitely at the same speed and in the same direction. No additional force is needed to maintain its motion; on the contrary, it requires a force to change its state of motion as stipulated by the law of inertia.
Matthew drops a ball and watches it bounce back up from the ground he draws a force diagram that shows the forces when the ball collides with the grand Which diagram correctly shows the forces involved
Answer: i think that the third option is correct
the force of the ball goes to the floor making it go down and up reflecting a little lower force back to the ball and sending the ball back up
hope this helps
brainliest if possible
Answer:
Option (c)
Explanation:
In this question it is given that, Matthew drops a ball and watches it bounce back up from the ground. The force diagram is given which shows when the ball collides with the ground.
The force acting on the ball are gravitational force and drag force. According to Newton's third law of motion, the force acting on the ball are equal in magnitude but the direction is opposite.
So, diagram (c) shows the correct scenario as per third law of motion. Hence, the correct option is (c).
A body initially at rest explodes into two masses M1 and M2 that moves apart with speeds v1 and v2 respectively. what is the ratio v1/v2?
a)-M2/M1
b)M2/M1
Answer:
a)-M2/M1
Explanation:
Momentum is conserved:
M₁ v₁ + M₂ v₂ = 0
M₁ v₁ = -M₂ v₂
v₁ / v₂ = -M₂ / M₁
In the given physical scenario, by adhering to the conservation of momentum, you can find the ratio of the speeds v1/v2 which is represented by -M2/M1.
Explanation:From the conservation of momentum, we might deduce that the total momentum of a system of particles is constant if there is no resultant external force. Before the explosion, the body was at rest, indicating that its total momentum was zero. After the explosion, the total momentum should still be zero. Hence, the momentum of M1 moving at speed v1 should be equal but opposite to the momentum of M2 moving at speed v2. This is represented mathematically as M1*v1 = M2*v2. By rearranging this equation, we can find the ratio v1/v2 which equals -M2/M1.
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Which of the following factors could you change in a system and not change its induced EMF?
A.
magnetic field
B.
type of wire
C.
velocity of the wire
D.
length of the wire in the field
Answer:
The type of wire
Explanation:
E=Blv
Answer:
The type of wire
Explanation:
The EMF is induced in the closed conducting loop whenever there is a change in the magnetic flux linked with it. Mathematically, it is given by :
[tex]\epsilon=\dfrac{-d\phi}{dt}[/tex]
Where
[tex]\phi[/tex] is the magnetic flux
[tex]\phi=B.A[/tex]
[tex]\epsilon=\dfrac{-d(BA)}{dt}[/tex]
For n number of coils,
[tex]\epsilon=\dfrac{-d(NBA)}{dt}[/tex]
Where
B is the magnetic field
A is the area of the coil
If the coil is moved with the speed of v in the magnetic field, then induced EMF is given by :
[tex]\epsilon=Blv[/tex]
l is the length of the coil
So, the induced EMF depends on the following factors:
magnetic fieldvelocity of the wirelength of the wire in the fieldSo, the type of wire do not change the induced emf of the coil. Hence, the correct option is (b).
If the mass of an object increases, predict what will happen to the coefficient of sliding friction.
Answer:
The coefficient of friction remains the same. The mass affects the force of friction, however the coefficient of friction depends the structural properties of the surfaces of the object and the floor. Therefore, the mass has no effect of the coefficient of friction.
The coefficient of sliding friction is generally unaffected by the mass of the object.
The coefficient of sliding friction, denoted by μ, is a dimensionless scalar value that represents the ratio of the force of friction between two bodies and the normal force pressing them together. It is determined by the properties of the surfaces in contact, such as their roughness and the materials they are made of, and is independent of the area of contact or the mass of the objects involved.
The formula for the force of friction [tex](F_friction)[/tex] is given by:
[tex]\[ F_{\text{friction}} = \mu \times N \][/tex]
where[tex]\( N \)[/tex] is the normal force, which is equal to the gravitational force on the object if it is resting on a horizontal surface. The gravitational force [tex](F_gravity)[/tex] is the product of the mass of the object (m) and the acceleration due to gravity (g):
[tex]\[ F_{\text{gravity}} = m \times g \][/tex]
Since the normal force is equal to the gravitational force, an increase in mass would increase the normal force, and consequently, the force of friction would also increase, as they are directly proportional. However, the coefficient of friction itself remains constant as it is a property of the surfaces in contact.
In summary, while the mass of an object affects the magnitude of the frictional force because it changes the normal force, it does not affect the coefficient of sliding friction. The coefficient of sliding friction remains constant for a given pair of surfaces in contact.
Dale and Alex push on opposite sides of a couch. Dale pushes to the left with
a force of 100 N, while Alex pushes to the right with a force of 175 N. If the
couch has a mass of 55 kg, what is the acceleration of the couch?
O A. 5 m/s2 right
O B. 5 m/s2 left
O c. 1.4 m/s? right
O D. 1.4 m/s2 left
SUBMIT
Answer:
C. 1.4 m/s² right
Explanation:
Apply Newton's second law. Take right to be positive and left to be negative:
∑F = ma
175 N − 100 N = (55 kg) a
a = 1.4 m/s²
The couch accelerates to the right at 1.4 m/s².
To find the acceleration of the couch, use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The net force is calculated by subtracting the forces applied by the two individuals pushing in opposite directions. By plugging in the given values and solving the equation, the acceleration of the couch is found to be approximately 1.4 m/s² to the right.
Explanation:To find the acceleration of the couch, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the net force is the difference between the forces applied by Dale and Alex, since they are pushing in opposite directions.
The net force can be calculated as 175 N (force applied by Alex) minus 100 N (force applied by Dale), which equals 75 N. The mass of the couch is given as 55 kg. Plugging these values into the equation, we get:
Net force = mass × acceleration
75 N = 55 kg × acceleration
Dividing both sides of the equation by 55 kg gives us:
acceleration = 75 N ÷ 55 kg ≈ 1.4 m/s²
Since the net force is positive (to the right) and greater than zero, the acceleration of the couch is also to the right. Therefore, the correct answer is 1.4 m/s² right (option C).
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Which describes the adiabatic process? Check all that apply.
Heat is released from the system.
Heat is not absorbed by the system.
A rapid shift occurs between gas compression and expansion.
A rapid expansion of gas is caused by a temperature decrease.
All heat is transformed to work done by the system.
Answer:
heat is not absorbed by the system
A rapid shift occurs between gas compression and expansion.
All heat is transformed to work done by the system.
Explanation:
Adiabatic processes involve no heat transfer to or from the system, often due to the insulation or speed of the process. Temperature decreases during expansion because internal energy does work, and increases during compression as work is done on the system. So the correct options are second, third, and fourth statements.
Explanation:An adiabatic process describes a thermodynamic change in which no heat is transferred into or out of the system. This can mean that the system is well insulated or that the process happens so quickly there's no time for heat transfer. During adiabatic expansion of a gas, the temperature decreases because internal energy is converted to work done by the system, and in adiabatic compression, the temperature increases because work is done on the system, increasing its internal energy.
Heat is not absorbed by the system.A rapid shift occurs between gas compression and expansion.A rapid expansion of gas is caused by a temperature decrease because the internal energy of the gas is used to do work.All heat being transformed to work done by the system can be a characteristic of an adiabatic process, particularly in the case of an ideal adiabatic process where no heat is exchanged and all energy changes in the system are due to work.
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The Bernoulli principle states that the pressure inside a liquid increases with depth:
A. True
B. False
C. True only if the channel is horizontal
D. True only if the section of the channel is constant
E. True only if there is no friction
The answer should be B. but why?
Explanation:
According to Bernoulli's principle:
"In an ideal fluid (not viscous and without friction) that circulates through a closed conduit, the energy the fluid possesses remains constant along its path."
From there, Bernoulli deduced that the fluid pressure decreases when the flow rate increases. And this has nothing to do with depth.
To understand it better:
In a fluid that circulates through a closed conduit (a pipe for example), it contains energy in two ways:
-Kinetic energy due to its weight and speed.
-Potential energy in the form of pressure.
Now, if the system has constant flow and the total energy (kinetic + potential) is also constant, the energy is transformed every time the transverse area of the tube is modified.
It should be noted that by modifying this transverse area, the flow rate is also modified.
Therefore, as the kinetic energy increases or decreases, this change is compensated by the decrease or increase in pressure (potential energy), since the total energy of the system cannot be created or destroyed.
Which weathering process is mechanical
Mechanical weathering is the physical breakdown of rock by environmental factors. This process is always at work, and there are a number of different types of mechanical weathering. Thermal expansion is the tendency for minerals to expand and contract based on temperature.
Answer:Mechanical weathering is actually breaking down of rocks into smaller pieces by natural forces. Any weathering processes that can cause the physical breakdown of rocks without any type of change in the chemical composition of rocks, called mechanical weathering.
Exfoliation: It's a process where the rocks erodes by peeling off in sheets or layer by layer rather than grain by grain.
Explanation:therefore exfoliation will match the answer to your question
Write differences between tornado and typhoon
The difference lies in their size, wind velocity, rate of travel, and duration. A tornado reaches rotating speeds up to 300 miles per hour, travels between 25 and 40 miles per hour, and generally lasts for a few minutes (although it can exist for hours). A typhoon (the term used in the Pacific for a hurricane) has winds that vary from 75 to 200 miles per hour, moves between 10 and 20 miles per hour, has a diameter up to 600 miles, and exists from days up to a week. A tornado generally forms several thousand feet above Earth’s surface, usually during warm, humid weather. A typhoon breeds in low-altitude belts over the ocean, generally from 5 to 15 degrees latitude north or south.
Which of the following could be vector magnitudes?
Answer:
Both A and D
Explanation:
Vector magnintude contains both speed and direction and so do these answer choices of 15km and 30m/s
Answer:
A and D
Explanation:
A vector magnitude has a magnitude and a direction Then 15 km are a magnitude that could have a direction for example 15 km in north direction.
The same happends with 30 m/s its a magnitude that could have a direction.
In the case of the option B 25 mililiters is a scalar magnitude because is a volumen then we can not define a direction, and the same for the option C 15 hours.
A rod of length r and mass m is pivoted at its center, and given an angular velocity, ω1. What would be the angular velocity of a second rod, which has the same angular momentum as the first, but whose length is 3r and whose mass is 2m?
Answer:
ω₁ / 18
Explanation:
Angular momentum is the moment of inertia times the angular velocity.
L = Iω
For a rod pivoted at its center, the moment of inertia is:
I = mr² / 12
where m is the mass and r is the length.
For the first rod:
L = (mr² / 12) ω₁
For the second rod:
L = ((2m) (3r)² / 12) ω₂
L = (18mr² / 12) ω₂
They have the same angular momentum, so:
(mr² / 12) ω₁ = (18mr² / 12) ω₂
mr² ω₁ = 18mr² ω₂
ω₁ = 18 ω₂
ω₂ = ω₁ / 18
The angular velocity of a second rod is ω₁ / 18.
What is angular momentum?Angular momentum is the moment of inertia times the angular velocity.
L = Iω
For a rod pivoted at its center, the moment of inertia is I = mr² / 12
where m is the mass and r is the length.
A rod of length r and mass m is pivoted at its center, and given an angular velocity, ω1. the second rod has the same angular momentum as the first, but whose length is 3r and whose mass is 2m.
For the first rod, angular momentum is
L = (mr² / 12) ω₁
For the second rod, angular momentum is
L = ((2m) (3r)² / 12) ω₂
L = (18mr² / 12) ω₂
They have the same angular momentum,
(mr² / 12) ω₁ = (18mr² / 12) ω₂
mr² ω₁ = 18mr² ω₂
ω₁ = 18 ω₂
ω₂ = ω₁ / 18
Thus, the angular velocity of a second rod is ω₁ / 18.
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3- (a) What is the period of rotation of Earth in seconds? (b) What is the angular velocity of Earth? (c) Given that Earth has a radius of 40,075 km at its equator, what is the linear velocity at Earth’s surface?
Explanation:
a) The Earth makes 1 rotation in 24 hours. In seconds:
24 hr × (3600 s / hr) = 86400 s
b) 1 rotation is 2π radians. So the angular velocity is:
2π rad / 86400 s = 7.27×10⁻⁵ rad/s
c) The earth's linear velocity is the angular velocity times the radius:
40075 km × 7.27×10⁻⁵ rad/s = 2.91 km/s
(a)The period of rotation of Earth in seconds will be 86400 second.
(b) The angular velocity of Earth will be 7.27 ×10⁻⁵ sec.
(c)The linear velocity at Earth’s surface will be 2.91 km/sec.
What is angular velocity?The rate of change of angular displacement is defined as angular velocity.
It is stated as follows:
ω = θ t
Where,
θ is the angle of rotation,
t is the time
ω is the angular velocity
The period of rotation of Earth in seconds is found as;
As we know, the complete rotation of the earth took 24 hours.
The total rotational time is converted into the second;
1 hour = 3600 sec
24 hour=24×3600
T= 86400 second
The angular velocity of Earth is;
[tex]\rm \omega= \frac{2\pi}{T} \\\\\ \omega = \frac{2\times 3.14}{86400}\\\\ \omega = 7.27 \times 10^{-5} \ rad/sec[/tex]
The linear velocity at Earth’s surface is found as;
v=r ×ω
v=40075 ×7.27 ×10 ⁻⁵
v=2.91 km/sec
Hence, period of rotation, angular velocity of earth and linear velocity at Earth’s surface 86400 second,7.27 ×10⁻⁵ sec and 2.91 km/sec respectively.
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3. In which activity is no work done?
Answer:
Sleeping, since your brain is working, but your physical body is not moving at all or moving rarely, therefore there is no work done in the activity of sleeping.
Explanation:
A train consists of a diesel shunter of mass 100 tonnes pulling a truck of mass 25 tonnes along a level track. The engine is working at a rate of 125kW. The resistance to motion of the truck and shunter is 50N per tonne. (i)Calculate the constant speed of the train. While travelling at this constant speed, the truck becomes uncoupled. The shunter engine continues to produce the same power. (ii) Find the acceleration of the shunter immediately after this happens. (iii) Find the greatest speed the shunter can now reach.
Answer:
(i) 20 m/s
(ii) 0.00625 m/s²
(iii) 25 m/s
Explanation:
(i) The train moves at constant speed when it has no acceleration, meaning when the sum of the forces is zero.
There are two forces acting on the train. The force of the engine pushing the train forward, and the resistance.
∑F = ma
F − R = 0
F = R
The resistance is:
50 N/tonne × (100 tonne + 25 tonne) = 6250 N
Therefore, the force of the engine is 6250 N. The power of the engine is 125 kW. Power is work per time, and work is force times distance, so:
P = W / t
P = Fd / t
P = Fv
125000 Nm/s = (6250 N) v
v = 20 m/s
(ii) The truck becomes uncoupled. The engine is still pushing with 6250 N of force, but the resistance has changed to:
50 N/ton × 100 tonne = 5000 N
∑F = ma
F − R = ma
6250 N − 5000 N = (100 tonne × 2000 kg/tonne) a
a = 0.00625 m/s²
(iii) When the force of the engine matches the new resistance force:
P = Fv
125000 Nm/s = (5000 N) v
v = 25 m/s
The train's constant speed is 20 m/s. The acceleration of the shunter after the truck is uncoupled is 0.0125 m/s^2. The greatest speed the shunter can achieve, ignoring other physical limits, is 25 m/s.
Calculating Constant Speed, Acceleration, and Maximum Speed of a Shunter
Calculating constant speed: The total resistance to motion for both the diesel shunter and the truck is equal to the resistance force per tonne multiplied by the total mass. This gives a total resistance of (100+25) tonnes imes 50 N/tonne = 6250 N. Since the train is traveling at a constant speed, the power output of the engine is equal to the force times velocity (P = Fv), so the velocity v = P/F = 125000 W / 6250 N = 20 m/s.
Calculating the acceleration of the shunter: After the truck becomes uncoupled, the shunter's mass is 100 tonnes. The resistance force is now 100 tonnes * 50 N/tonne = 5000 N. The power output remains the same, so the available force for acceleration is P/v - resistance = 125000 W / 20 m/s - 5000 N = 1250 N. Acceleration a = F/m = 1250 N / (100 imes 1000 kg) = 0.0125 m/s2.
Finding the greatest speed of the shunter: Assuming there is no upper limit imposed by engine power or other factors, the greatest speed would be when the force output from power equals the resistance force: P/v = resistance. Therefore, maximum speed v = P / resistance = 125000 W / 5000 N = 25 m/s. However, in real-world scenarios, factors like engine capacity and gear ratios would limit the maximum speed.
There are 11 lights in series, and they are in series with 2 lights in parallel. If the 13 lights are identical, which of them will burn brightest?
11 lights
2 lights
all 13 lights
none will be brightest
OPTION 3.
In a circuit, when identical lights are connected in series, they have the same current and burn with the same brightness. Similarly, when identical lights are connected in parallel, they each have the same voltage and burn with the same brightness. Therefore, all 13 lights in the given arrangement will burn with the same brightness.
Explanation:In electrical circuits, when identical lights are connected in series, they all have the same current through them and therefore they all burn with the same brightness. On the other hand, when identical lights are connected in parallel, they share the total voltage (thus each having the same voltage as if it were alone) and they also burn with the same brightness. Therefore, in this case where there are 11 lights in series, and they are in series with 2 lights in parallel, and all 13 are identical, all of them will burn with equivalent brightness. Thus the option 'all 13 lights' is the correct answer.
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Considering the properties of series and parallel circuits and given all 13 lights are identical, they will all shine with the same brightness. Therefore, none of the lights will burn the brightest.
Explanation:In a series circuit, the electrical current is the same through all the components, which in this case are the lights. Therefore, since the 11 lights are in series and have the same current, they will all shine with the same brightness. However, these 11 lights are in series with 2 in parallel. In parallel circuits, the voltage across each component (here, the lights) is the same. So, the 2 lights in parallel will also shine with the same brightness. Because all 13 lights are identical and considering how series and parallel circuits work, all will have the same brightness. Therefore, none of the options will burn the brightest.
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4. A 1,000-kilogram satellite completes a uniform circular orbit of radius 8.0 x 10 meters as
measured from the center of Earth. The mass of Earth is approximately 6.0 x 10-7 kilograms,
and the universal gravity constant is approximately 7.0 x 10-11 N•m/kg. Determine the
work done by gravity as the satellite completes one full orbit around Earth.
Answer:
Zero
Explanation:
The work done by a force on an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and the displacement of the object
In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so [tex]\theta=90^{\circ}[/tex] and [tex]cos \theta =0[/tex]. Therefore, the work done by gravity is also zero.
Answer:
zero
Explanation:
on edg.
A 10 kg box resting on a horizontal, frictionless surface is attached to a 6 kg
weight by a thin, light wire that passes over a pulley . The pulley has the shape of a uniform solid disc of mass 2.5 kg and diameter 0.650 m. After the system is released, calculate
(i) the tension in the wire on both sides of the pulley.
(ii) the angular acceleration of the pulley.
Answer:
T₁ = 34.1 N
T₂ = 38.4 N
α = 10.5 rad/s²
Explanation:
Sum of the forces on the box in the x direction:
∑F = ma
T₁ = m₁ a
Sum of the torques on the pulley:
∑τ = Iα
T₂ r − T₁ r = (½ mr²) α
T₂ r − T₁ r = (½ mr²) (a / r)
T₂ − T₁ = ½ ma
Sum of the forces on the weight in the y direction:
∑F = ma
T₂ − m₂ g = m₂ (-a)
T₂ = m₂ g − m₂ a
Substitute:
(m₂ g − m₂ a) − (m₁ a) = ½ ma
m₂ g = (m₁ + m₂ + ½ m) a
a = m₂ g / (m₁ + m₂ + ½ m)
Given m₁ = 10 kg, m₂ = 6 kg, and m = 2.5 kg:
a = (6) (9.81) / (10 + 6 + ½ (2.5))
a = 3.41 m/s²
Therefore:
T₁ = m₁ a
T₁ = (10) (3.41)
T₁ = 34.1 N
T₂ = m₂ g − m₂ a
T₂ = (6)(9.81) − (6)(3.41)
T₂ = 38.4 N
α = a / r
α = 3.41 / 0.325
α = 10.5 rad/s²
as a hurricane or tropical storm approaches your location, it's forward speed decreases from 20 kt to 10 kt. How might this affect rainfall?
Answer:
The correct answer is c. More total rainfall from a slower moving storm.
When the the forward speed of the hurricanes and tropical storms slows down they tend to increase the rainfall. Because of the slow movement the storm can be for few days over a given region and produce rainfall without stopping, thus create major flooding, pilling up of the coastal water, and produce persistent strong winds even though they have decreased in their forward speed.
Explanation:
Answer:
c. More total rainfall from a slower moving storm.Explanation:
Choices for this question are
a. Less flooding because rain will have more time to soak into the ground.
b. Less total rainfall from a weakening system.
c. More total rainfall from a slower moving storm.
d. Shorter period under the rainbands.
When hurricane's forward speed decreases, they will last more time, because their energy is gonna last more. This means that the rainfall will also last more days. Even-though, slower hurricanes tend to last more time because of this, so, the chances of happening floods is higher, because the rainfall will continue for more days.
The temperature in a room is 56 degrees celcius . What would the velocity of a sound wave be at this temperature ?
Answer:
365 m/s
Explanation:
The velocity of sound in air is approximated as:
v ≈ 331.4 + 0.6 T
where v is the velocity in m/s and T is the temperature in Celsius.
At T = 56:
v ≈ 331.4 + 0.6 (56)
v ≈ 365.0
The velocity is approximately 365 m/s.
Final answer:
The speed of sound in air at 56°C is approximately 364.6 m/s, calculated using the temperature-dependent formula for the speed of sound.
Explanation:
The speed of sound in the air increases as the temperature rises. At 0°C, the speed of sound is about 331 m/s. The speed of sound can be approximated using the formula:
v = v0 + (0.6 × t)
Where:
v is the speed of sound at the desired temperature in m/s.v0 is the speed of sound at 0°C, which is 331 m/s.t is the temperature in degrees Celsius.At a temperature of 56°C, the speed of sound can be calculated as follows:
v = 331 m/s + (0.6 m/s/°C × 56°C)
v = 331 m/s + 33.6 m/s
v = 364.6 m/s
Thus, the speed of sound in air at 56°C is approximately 364.6 m/s.
What is the volume of 282 g of metal with a density of 11.7 g/cm32
Answer:
24.1025641
Explanation:
Density = Mass ÷ Volume
We need to work out volume so the equation is going to be ⇒
Mass ÷ Density
Mass = 282 g
Density = 11.7
282 ÷ 11.7 = 24.1025641
A data table depicts the relationship between two or more _____ _.
variables
units
constants
axes
how are breeder reactors different from nuclear reactors
Answer:
Breeder reactors are different from conventional nuclear reactors because they produce more fuel than they consume when producing energy and can re-use the plutonium they produce to fuel the reactor.
Explanation:
Nuclear reactors use uranium as a source of fuel to generate the required energy.These reactors produce less fissionable matter than they consume.For example, the amount of plutonium produced in nuclear rectors is less than that produced in Breeder reactors.In Breeder reactors, the plutonium produced can be separated and collected to be reused as fuel in the reactor.Additionally, breeder reactors use a coolant such as liquid sodium equipping the neutrons with high energy thus increasing the chances of the neutrons to be captured by uranium isotopes and be converted to plutonium.
A cyclist is riding his bike at a constant speed of S m/s, and experiences a frictional force between the bike and sidewalk of 100 N. The cyclist then changes his speed to 10 m/s What effect does this increase in speed have on the frictional force between the bike and sidewalk?
A) the frictional force doubles because when speed increases frictional force also increases
B) the frictional force becomes half of what it was because when speed increases frictional force decreases
C) the frictional force increases but does not double because although friction increases with the increasing speed it does not increase as fast
D) the frictional force between the bike and sidewalk stays the same because speed does not affect frictional force
Answer:
D) the frictional force between the bike and sidewalk stays the same because speed does not affect frictional force
Explanation:
Friction force is equal to normal force times the coefficient of friction. Since neither of those changes as speed increases, then the friction force stays the same.
A pole vaulter takes 1.3 seconds to fall from peak height to the landing mat. What is his vertical velocity at contact with the mat?
[tex]12.75 \frac{m}{s}[/tex]
Assuming vertical acceleration of [tex]9.81 \frac{m}{s^2}[/tex], the speed after x seconds of falling is [tex]9.81x \to 9.81(1.3) = 12.75[/tex]
Which of the following are steps for balancing chemical equations?
Check all that apply.
] A. Multiply the reactants to get the products.
B. Change subscripts.
O
C. Recheck the numbers of each atom on each side of the equation
to make sure the sides are equal.
D. Choose coefficients that will balance the equation.
Answer:
C. Recheck the numbers of each atom on each side of the equation
to make sure the sides are equal.
D. Choose coefficients that will balance the equation
Explanation:
In balancing of chemical equation, the number of atoms on both sides must be equal in adherence to the law of conservation of mass.
Using the method of inspection, the equation is first observed to know the relationship between the combining atoms and the resulting ones.
After observing the reaction, put a coefficient that will balance the equation. Then recheck the number of each atom on both side of the equation. One can repeat the process till the equation is balanced.
The steps of balancing a chemical equation include rechecking the numbers of each atom and choosing coefficients that will balance the equation. Options A and B are not part of the balancing process.
Explanation:To balance a chemical equation, you normally adhere to a few critical steps. These do not include options A and B. You should not multiply reactants to get products, and you shouldn't change subscripts, which would alter the nature of the substances involved. You should,
C. Recheck the numbers of each atom on each side of the equation to ensure that both sides have equal numbers of each type of atom, D. Choose coefficients that will balance the equation by making sure the number of atoms for each element is the same on both the reactant and product sides of the equation.Balancing chemical equations aims to observe the law of conservation of mass, which states that matter can neither be created nor destroyed.
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