study the motion map shown. what do the circled vectors represent?

a. velocity
b. speed
c. positive acceleration
d. negative acceleration

Study The Motion Map Shown. What Do The Circled Vectors Represent?a. Velocity B. Speedc. Positive Acceleration

Answers

Answer 1

Answer:

It's option d - Negative acceleration

Explanation:

Let's start by demonstrate why it's not option b - Speed : Speed is a scalar quantity so it can not be represented by a vectorLet's check that the green  vectors represent velocity (velocity is a vector quantity, velocity is a direction aware, while speed is just a scalar)

Now let's  show that the circled vectors are acceleration vectors:

Mathematically position X , velocity V and acceleration A are:

[tex] \frac{dX}{dt} = V [/tex] and [tex] \frac{dV}{dt} = A [/tex]

Where X, V, A are vectors and [tex] \frac{d(a)}{dt} = b [/tex]  indicates the derivate a of a time is equal to b.

So, this show that acceleration is a rate respect of time of velocity ⇒ When acceleration is positive, velocity increments, when acceleration is negative, velocity decrements.

The above explanation correspond to the motion map shown, getting demonstrated that the answer is D - Negative acceleration

Answer 2

The answer is:

Acceleration

Related Questions

Wire 1 has a resistance R1. Wire 2 is made of the same material, with length 1/2 as long and diameter 1/4. What is the resistance ratio R2/R1?

Answers

-- reduce the length of a wire to 1/2 . . . cut the resistance in half

-- reduce the diameter to 1/4 . . . reduce the cross-section area by (1/4²) . . . increase the resistance by 16x .

-- R2 = (R1) · (1/2) · (16)  =  8 · R1

-- R2 / R1  =  8

How much work does an elephant do while moving a circus wagon 20 meters with a pulling force of 200n

Answers

Given:

s(distance)= 20 meters

F(force)=200N

Now we know that

work done= Force applied x distance

Substituting the given values in the above formula we get

Work done= 20 x 200= 4000J

Final answer:

The work done by an elephant while moving a circus wagon 20 meters with a pulling force of 200N is calculated using the formula: Work = Force x Distance. Plugging the values into the formula gives us 4000 Joules.

Explanation:

The work done by the elephant pulling the circus wagon can be calculated using the formula for work, which is Work = Force x Distance. In this situation, the Force applied by the elephant is 200N and the Distance moved by the wagon is 20 meters.

So, the Work done would be: 200N x 20m = 4000 Joules.

This means the work done by the elephant is 4000 Joules.

Learn more about Work Done here:

https://brainly.com/question/35917320

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Consider a brick that is totally immersed in water, with the long edge of the brick vertical. The pressure on the brick is

A) greatest on the sides of the brick
B) greatest on the top of the brick
C) greatest on the bottom of the brick
D) greatest on the face with the largest area
E) the same on all surfaces of the brick

Explain your answer

Answers

The answer is C because only the bottom has the water pressure applied to it because it's the only thing emersed in the water.

The pressure on a brick that is totally immersed in water, with the long edge of the brick vertical is: C. greatest on the bottom of the brick.

Pressure can be defined as a measure of the external force acting upon a surface area. Mathematically, the pressure acting on an area is given by the formula:

[tex]Pressure = \frac{Force}{Area}[/tex]

In this scenario, the pressure on the brick with a long, vertical edge, that is totally immersed in water is greatest on its bottom because the long, vertical edge displaces water.

Read more: https://brainly.com/question/22480179

A 32.5-kg rock is traveling at a constant velocity through space. Then a force of 140 N is exerted on the rock. What acceleration does the force produce?

3.31 m/s^2
2.32m/s^2
4.31 m/s^2
45.5 m/s^2
10.7 m/s^2

Answers

As per Newton's II law we can say force applied on an object is product of mass and acceleration

[tex]F = ma[/tex]

given that

Force = 140 N

mass = 32.5 kg

now we can use above formula

[tex]140 = 32.5* a[/tex]

[tex]a = \frac{140}{32.5}[/tex]

[tex]a = 4.31 m/s^2[/tex]

so its acceleration must be 4.31 m/s^2

What are graphs used for? Select all that apply.

analyzing what data means
forming experiments
diagram showing the correlation between two quantities
predicting outcomes and patterns

Answers

Answer:

analyzing what data means

diagram showing the correlation between two quantities

Explanation:

Graph is the plot of two physical quantities and it describes the relation between both quantities. It gives a specific relation between the two physical quantities which is used to analyze the result.

Thus, the following options are correct,

analyzing what data means

diagram showing the correlation between two quantities


Answer: Analyzing what data means, diagram showing the correlation between two quantities, and predicting outcomes and patterns.

The first, third, and forth.

Starting from rest, the Road Runner accelerates at 3 m/s for ten seconds. What is the final velocity of the Road Runner?

Answers

Answer

The answer to this question is [tex]30 ms^{-1}[/tex]

Explanation

As we know that accelartion is the rate of change of velocity. So, it can be write as

[tex]a = (V_f -V_i) /t[/tex]

where

[tex]V_f[/tex] is the final velocity

[tex]V_i[/tex] is the initial velocity

t is the time

a is the accelartion

as we konw

[tex]a = 3 ms^{-2}[/tex]

t = 10 s

From rest So,

[tex]V_i[/tex] = 0

[tex]V_f[/tex] = ?

Putting values

[tex]3 = (V_f - 0)/10[/tex]

[tex]3 * 10 = V_f[/tex]

[tex]30 = V_f[/tex]

[tex]V_f = 30 ms^{-1}[/tex]

So, the right answe is [tex]30 ms^{-1}[/tex]

(3 m/s²) x (10 s) = 30 m/s

His speed at the end of 10 sec is 30 m/s.  We can't describe his velocity, because we have no information about the direction he's moving.

An object's true weight is 123 N. When it is completely submerged in water, its
apparent weight is 82.0 N. If the density of water is 1000 kg/m3
, then what is the density of the object?

Answers

Object true weight is given as

[tex]mg = 123 N[/tex]

now we know that g = 9.8 m/s^2

[tex]m* 9.8 = 123 [/tex]

[tex] m = \frac{123}{9.8} = 12.55 kg[/tex]

now when it is complete submerged in water its apparent weight is given as 82 N

apparent weight = weight - buoyancy force

apparent weight = 82 N

weight = 123 N

now we have

82 = 123 - buoyancy force

buoyancy force = 123 - 82 = 41 N

now we also know that buoyancy force is given as

[tex]F_b = p_{liq}Vg[/tex]

[tex]41 = 1000*V*9.8[/tex]

[tex]V = \frac{41}{1000*9.8}[/tex]

[tex]V = 4.18 * 10^{-3} m^3[/tex]

now as we know that mass of the object is 12.55 kg

its volume is 4.18 * 10^-3 m^3

now we know that density will be given as mass per unit volume

[tex]density = \frac{m}{V}[/tex]

[tex]density = \frac{12.55}{4.18*10^{-3}[/tex]

[tex]density = 3002.4 kg/m^3[/tex]

so here density of object is 3002.4 kg/m^3

Answer:

3000 kg/m^3

Explanation:

True weight = weight in air = 123 N

Apparent weight = weight in water = 82 N

Loss in weight of the object = true weight - apparent weight

Loss in weight = 123 - 82 = 41 N

According to the Archimedes principle, the loss in weight of the object is equal to the buoyant force acting on the object.

Let V be the volume of the object an d be the density of the object.

Buoyant force = volume of the object x density of water x gravity

41 = V x 1000 x g

[tex]V = \frac{41}{1000 g}[/tex]       .... (1)

Now, true weight = Volume of the object x density of object x gravity

[tex]123 = \frac{41}{1000 g} \times d\times g[/tex]      from (1)

d = 3000 kg/m^3

Just before snapping backup in the air, my speed is 50m/s. What is my kinetic energy just before snapping back up

Answers

Kinetic energy of anything is (1/2) (mass) (speed)² .

Your kinetic energy just before you snap back up (? ?) is

(1/2) (your mass in kilograms) (50 m/s)² =

(1/2) (your mass in kilograms) (2,500 m²/s²) =

(1,250 x your mass in kilograms) .  The unit is Joules.

A 47-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 37 degrees above the horizontal. If the tension in the rope is 142 N, how much work is done on the crate to move it 6.1m?

Answers

Tension in the rope due to applied force will be given as

[tex]F = 142 N[/tex]

angle of applied force with horizontal is 37 degree

displacement along the floor = 6.1 m

so here we can use the formula of work done

[tex]W = F d cos\theta[/tex]

now we can plug in all values above

[tex]W = 142 * 6.1 * cos37[/tex]

[tex]W = 691.8 J[/tex]

So here work done to pull is given by 691.8 J


what does pascals principle state

Answers

Pascal's law (also Pascal's principle or the principle of transmission of fluid-pressure) is a principle in fluid mechanics that states that a pressure change occurring anywhere in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere.


Answer: The pressure at two pistons within an enclosed fluid system is always the same.

Explanation:

Cereal plants gain chemical potential energy as they grow. Which form of energy is converted to create the chemical potential energy? A. gravitational potential energy B. kinetic energy C. light energy D. thermal energy

Answers

Answer:

C. light energy

Explanation:

In all these plants the energy is converted from the photosynthesis process. As per this photosynthesis phenomenon plants get energy by the light received from the sun.

This will help to make the plants to grow and make fruits in the plant.

in this word photosynthesis we can see it is combination of photo + synthesis

which clearly means that this energy synthesis is with the help of photons received from the sun.

These photons are light photons

So here correct answer will be

C. light energy

Answer:

light energy

Explanation:

A father lifts a toddler 1.5m up in the air. The child gains 187.5J of gravitational potential energy as a result. What is the mass of the toddler? (Assume that the gravitational field strength is 10N/kg.)

Answers

Answer:

Mass of toddler = 12.5 kg

Explanation:

 The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

 Potential energy = 187.5 J

 Height = 1.5 m

 Substituting

     187.5 = m * 10 * 1.5

     m = 12.5 kg

So mass of toddler = 12.5 kg

Calculate how much energy is needed to get a typical car with a mass of 1500 kg up to a speed of 40 mph ignoring friction or any other losses or inefficiencies. Show all work, and give your answer in kWh.

Answers

m = mass of the car = 1500 kg

we know that 1 mph = 0.45 m/s

hence

v = speed gained by the car = 40 mph = 40 x 0.45 m/s = 18 m/s

since the car is gaining speed here , hence the energy need is same as the kinetic energy gained by the car

kinetic energy is given as

KE = (0.5) m v²                     where m = mass , v = speed

inserting the above values in the formula

KE = (0.5) (1500) (18)²

KE = 2.43 x 10⁵ J

we know that , 1 J = 2.78 x 10⁻⁷ kwh

hence

KE = (2.43 x 10⁵) (2.78 x 10⁻⁷)

KE = 0.068 kwh

hence the energy needed is 0.068 kwh

As you climb a high mountain, the buoyant force exerted on you by the atmosphere _____.

Answers

As you climb a high mountain, the buoyant force exerted on you by the atmosphere DECREASES

________ fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

Answers

Gasoline fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

Answer:

Hydrogen fuel is a renewable alternative to petroleum fuels that is made through either biologically or chemically driven production in a process called gasification.

What moon phase occurs 3-4 days after a waning gibbous?

Answers

The "waning gibbous" begins immediately after the Full Moon and lasts about a week.

At the end of the week, the moon is no longer gibbous, but it's still waning.  At the instant it's exactly half-illuminated, it's called "Third Quarter", and then it continuous to wane for another week.

So 3 to 4 days after the END of the waning gibbous phase, it's a Waning Crescent. It still has another 3 to 4 days of waning to go, before it wanes away to nothing and we have the next New Moon.

The waning gibbous phase is the phase between the full and last quarter moon late at night or in the early morning . The waning crescent is the phase that occurs 3-4 days later a waning gibbous.

What is waning gibbous ?

The waning gibbous phase is the phase between the full and last quarter moon late at night or in the early morning.

The waning gibbous phase moon appears more than half-lighted but less than the full moon. A full sunset is a time when the full moon rises. The rising time of the waning gibbous moon is late at night.

It looks red like a  full moon when it’s near the horizon.

To learn more about the waning gibbous refer to the link ;

https://brainly.com/question/15045629

When a 60 g (=0.06 kg) tennis ball is served by a newly invented machine, it accelerates from zero to 50 m/s. The ball experiences a constant acceleration due to the impact with the racket over a distance of 0.5 m. What is the

Answers

here tennis ball is accelerated from initial speed zero to final speed 50 m/s

In this accelerated motion the distance moved by the ball is 0.5 m

So here we can use kinematics to find the acceleration of the ball during this distance

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

here given that

vf = 50 m/s

vi = 0

d = 0.5 m

[tex]50^2 - 0 = 2*a*0.5[/tex]

[tex]2500 m/s^2 = a[/tex]

now if we have acceleration during its motion so we can find the applied force by using Newton's II law

[tex]F = ma[/tex]

[tex]F = 0.06*2500[/tex]

[tex]F = 150 N[/tex]

now the applied force will be 150 N on the ball by racket

A hiker travels in a straight line for 40 minutes with an average velocity that has a magnitude of 1.2 m/s. How far is she from her starting point?

Answers

Given:

Time taken for the travel: 40 mins=2400 secs

Velocity: 1.2m/s

Speed and velocity have the same magnitude. Speed is a scalar where as velocity is a vector quantity.

Distance traveled= speed x time.

Distance traveled: 1.2 x 2400=2880m

A racing car whose mass is 1.2 X 10^3 kg is travelling at 8.9 m/s. It stops with a constant deceleration in a distance of 1.8X10^1 m. What force must the brakes apply to the car if the friction in the car’s engine is 1.8 X 10^3 N.

Answers

given that initial speed of the car is

[tex]v_i = 8.9 m/s[/tex]

now after travelling the distance d = 1.8 * 10^1 m the car will stop

so here we can use kinematics to find the acceleration of car

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

[tex]0 - 8.9^2 = 2 a d[/tex]

here we have

[tex]- 79.21 = 2*(18)*a[/tex]

[tex]a = -2.2 m/s^2[/tex]

net force applied due to brakes of car is given by Newton's II law

[tex]F = ma[/tex]

here we have

mass = 1.2 * 10^3 kg

[tex]F_{net} = 1.2 * 10^3 * 2.2[/tex]

[tex]F_{net} = 2.64 * 10^3 N[/tex]

now we can say

[tex]F_{net} = F_1 + F_2[/tex]

[tex]2.64 * 10^3 = 1.8 * 10^3 + F_2[/tex]

[tex]F_2 = 8.4 * 10^2 N[/tex]

So the force applied due to brakes is given as above

Which of these statements about family relationships is true on Colonel Lloyd’s plantation?

Answers

Hello!

I'm unfamiliar with the book you are reading,

However, based on textual evidence, I think your answer relies somewhere in answer choice A or D.

I hope this helps!

Answer:

THE ANSWER IS D

Explanation:

I DID THE TEST

a race car accelerates uniformly from 18.5m/s to 46.1m/s in 2.4 seconds. determine the acceleration of the car and the distance traveled

Answers

The car's (average) acceleration would be

[tex]a=\dfrac{46.1\,\frac{\mathrm m}{\mathrm s}-18.5\,\frac{\mathrm m}{\mathrm s}}{2.4\,\mathrm s}=11.5\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]

The car's position over time would be given by

[tex]x=v_0t+\dfrac12at^2[/tex]

so that after 2.4 seconds, the car will have traveled a distance of

[tex]x=\left(18.5\,\dfrac{\mathrm m}{\mathrm s}\right)(2.4\,\mathrm s)+\dfrac12\left(11.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(2.4\,\mathrm s)^2[/tex]

[tex]\implies x=77.5\,\mathrm m[/tex]

Hello!

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.

* Determine the acceleration of the car....

We have the following data:

V (final velocity) = 46.1 m/s

Vo (initial velocity) = 18.5 m/s

ΔV  (speed interval)  = V - Vo → ΔV  = 46.1 - 18.5 → ΔV  = 27.6 m/s

ΔT (time interval) = 2.4 s

a (average acceleration) = ? (in m/s²)

Formula:

[tex]\boxed{a = \dfrac{\Delta{V}}{\Delta{T^}}}[/tex]

Solving:  

[tex]a = \dfrac{\Delta{V}}{\Delta{T^}}[/tex]

[tex]a = \dfrac{27.6\:\dfrac{m}{s}}{2.4\:s}[/tex]

[tex]\boxed{\boxed{a \approx 11.5\:m/s^2}}\longleftarrow(acceleration)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

* The distance traveled ?

We have the following data:

Vi (initial velocity) = 18.5 m/s

t (time) = 2.47 s

a (average acceleration) = 11.5 m/s²

d (distance interval) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

[tex]d = v_i * t + \dfrac{a*t^{2}}{2}[/tex]

[tex]d = 18.5 * 2.4 + \dfrac{11.5*(2.4)^{2}}{2}[/tex]

[tex]d = 44.4 + \dfrac{11.5*5.76}{2}[/tex]

[tex]d = 44.4 + \dfrac{66.24}{2}[/tex]

[tex]d = 44.4 + 33.12[/tex]

[tex]\boxed{\boxed{d = 77.52\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

________________________________  

[tex]\bf\red{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}[/tex]

A certain metal has a coefficient of linear expansion of 2.00 × 10-5 K-1. It has been kept in a laboratory oven at
325°C for a long time. It is now removed from the oven and placed in a freezer at ‐145°C. After it has reached
freezer temperature, the percent change in its density during this process is closest to
A) +2.90%.
B) ‐2.90%.
C) +2.74%.
D) ‐2.74%.
E) It is not possible to tell without knowing the mass and original volume of the metal.

Answers

Hi, the answer is A) +2.90%.

A: +2.90% is the answer

Eric decided to go for a walk from his home. He headed 6 meters east and x meters north. The angle formed by the displacement vector and the horizontal vector is 37°. What is the length of the displacement vector?

Answers

Answer:

 Length of displacement vector = 7.51 m

Explanation:

 Consider east as positive X axis and North as positive Y axis.

 Eric headed 6 meters east, Displacement = 6 i

 Then he headed X meters north, Displacement = X j

 Total displacement = 6 i + X j

  Angle it makes with horizontal axis, θ = tan⁻¹(X/6) = 37°

  X/6 = tan 37

   X = 4.52 m

Total displacement = 6 i + 4.52 j

Magnitude = [tex]\sqrt{6^2+4.52^2} =7.51m[/tex]

 Length of displacement vector = 7.51 m

The answer is A. 7.5.

60 g of vinegar was used in a chemical reaction with baking soda. The total mass of the products is 140 g. What was the mass of the baking soda

Answers

The mass of the baking soda was 80 g

Answer: the mass is 80g

Explanation: In a solution of 140g, we knot that there are 60g of vinegar, the only other component in the solution is baking soda.

Now we want to find the mass of the baking soda in the solution.

Because there are only two components in the solution, if we remove the 60g of vinegar, the residue mass is the mass of the baking soda.

then we need to calculate:

Mass = 140g - 60g = 80g

So the mass of baking soda in the solution is 80g.

what gas is most abundant greenhouse gas ? a) ozone b) chlorofluorocarbon c) carbon dioxide d) methane e) water vapor

Answers

i believe the answer is water vapor

hope this helps


Answer:

WATER VAPOR

Explanation:

I got a 100% on my test

Match the following examples of energy with the primary form of energy exhibited.

friction:
nuclear power plant:
toaster element:
welding torch:
eraser sitting on a desk edge:
light bulb:
campfire:
moving car:
lump of coal in a storage bin:
stick of TNT:

Options are nuclear, heat, kinetic, potential, light, and solar energy

Answers

The primary energy exhibited is:

friction:  Heat energy

Due to friction. there is heat loss in mostly all machines.

nuclear power plant:  Nuclear energy

In nuclear power plant, fission or fusion of radio-active substances produces large amount of nuclear energy.

toaster element:  Heat energy

Heat energy is produced in the toaster when electricity passes through the element. This is used to heat the toasts.

welding torch:  Heat energy

The heat energy produced in the welding torch is used in welding.

eraser sitting on a desk edge:  Potential energy

Potential energy is possessed by a body due to virtue of its height.

light bulb:  Heat energy and light energy.

The element inside the bulb gets heated first and then light energy is produced.

campfire:  Heat energy

Heat is produced and then light energy in case of campfire.

moving car:  Kinetic energy

A moving body has kinetic energy.

lump of coal in a storage bin:  Potential energy

A lump of coal in a storage bin has potential energy.

stick of TNT: potential energy

Stick of TNT is formed of explosive mixture. It contains potential energy.

Answer:

• Friction ( heat )

• Nuclear power plant ( nuclear )

• Toaster element ( heat )

• welding torch ( heat )

• eraser sitting on a desk edge (potential)

• light bulb ( light )

• campfire ( heat )

• moving car ( kinetic )

• lump of coal in a storage bin ( potential )

• stick of tent ( potential)

Explanation: hope this helps !



Please Help Quick






Consider the average speed of a runner who jogs around a track four times. The distance (400m) remains constant for each lap. However, each lap is run 5 seconds slower than the first. The time for each lap increases. The average speed for each lap ______________. This is an example of a(n) _____________ relationship.

A) increases, direct

B) decreases, direct

C) increases, inverse

D) decreases, inverse

Note: If you have a question please do not ask it in the answer section of this question.

Answers

(D) decreases, inverse

Average speed of a body is defined as the ratio of the distance traveled to the time taken to travel the distance. The runner runs the same distance  of 400 m during each lap but takes 5 seconds more for each lap.

Since [tex]v_a_v_g=\frac{d}{t}[/tex], as time increases, the average speed for each lap increases.

Thus, [tex]v\alpha \frac{1}{t}[/tex] when the distance traveled is the same. This is an example of an inverse proportionality relationship.

The force it would take to accelerate a 700-kg car at a rate of 5m/s2 is

Answers

mass of car =700kg

Required acceleration =5m/s^2

According to newton's second law

F=ma

F=(700)(5)

F=3500 Kgm/sec^2

Answer:3500

Explanation: mass of car =700 kg

Required acceleration =5 m/s^2

According to newton's second law

F=ma

F=(700)(5)

F=3500 K gm/sec^2

A cheetah can go from the state of rest to running at 20m/s in just two seconds. What is the Cheetahs average acceleration

Answers

acceleration = change in velocity/change in time

so...

a = 20 m/s / 2 seconds

a = 10


hope that helps :)

P.S. found this from Brainly User, sometimes all you have to do is search to find the answer.

A resource (like the Sun) that essentially never "runs out" is said to be _____.

A. reusable
B. recyclable
C. inexhaustible
D. nonrenewable

asap please

Answers

the answer youre looking for is (C

Other Questions
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