Suppose a vector is drawn at 3 cm long and represents an object traveling at 100 m/s. How fast would an object be traveling if the vector is drawn 6 cm long?

To answer this question, we must use the equation for the volumetric expansion of gases at constant pressure. This equation is given by:

[tex]V=V_{0}(1 + \alpha(T_{2}-T_{1}))[/tex]

We know:

[tex]V_{0}[/tex] is the initial volume [tex]= 0.5 m ^ 3[/tex]

ΔT is the temperature change = 45 ° -20 ° = 25 °

[tex]\alpha[/tex] is the coefficient of gas expansion and is equal to 1/273

Then the final volume of the gas is:

[tex]V=0.5*(1+\frac{1}{273}*25)[/tex]

[tex]V=0.546m^ 3[/tex]

Answer: C) velocity is a vector and requires a direction.

Explanation:

In physics, there are two types of quantities:

- scalars: these are quantities that have only a magnitude

- vectors: there are quantities that have both magnitude and direction

As an example, speed is a scalar while velocity is a vector. Therefore, speed has only a magnitude, while velocity has both magnitude and direction: therefore, the difference between the two quantities is that velocity is a vector and requires a direction, as stated in option C.

Answer:

velocity is a vector and requires a direction.

Explanation:

Speed is defined as the total distance covered per unit time and the velocity is defined as the total displacement per unit time.

Speed is a scalar quantity and velocity is a vector quantity. The quantities that have both magnitude and direction are vector quantity and the quantity that have only magnitude are scalar quantity.The SI unit of both velocity and speed is m/s.

So, the correct option is (c) "  velocity is a vector and requires a direction ".

Final answer:

Air masses are large bodies of air with uniform conditions formed in specific regions, which travel and influence weather by redistributing energy across the Earth's surface. They contribute to balancing the global climate by moving heat from warmer to cooler areas.

Explanation:

Air masses are vast bodies of air that encompass thousands of square miles, with uniform temperature, humidity, and pressure characteristics. Air masses form in source regions typically characterized by low relief and calm winds which allow for the air to acquire the traits of the Earth's surface beneath it. After a period of about 3 to 5 days, an equilibrium is established between the air mass and the source region, via radiative processes and vertical mixing of heat.

High-pressure regions are ideal for the genesis of air masses as the subsiding air promotes homogeneity. Once formed, air masses travel and as they move, they can modify the weather conditions of the regions they pass over. For instance, a maritime tropical (mT) air mass which originates over a warm ocean, if it passes over a colder current, will get chilled and become more stable, while a continental polar (cP) air mass might become less stable if it moves over a warmer region.

Energy redistribution on Earth's surface is a critical function of air masses. The movement of air masses, driven by winds and air currents, helps in transferring heat from warmer regions of the planet to cooler regions, balancing the global energy budget. Without this process, the world would experience extreme temperatures that could threaten the viability of ecosystems and human societies.

The continual movement and interaction of different air masses lead to the formation of weather fronts, and consequently, climatic events like precipitation and storms. This dynamic behavior contributes significantly to the global climate patterns observed.

That is true, i think.

Answer:

True

Explanation:

kinetic energy is what causes objects to move, and the absence of kinetic energy causes energy to stay still. It is also important to remember that energy is neither created or destroyed, and is constantly being reused.

Given:

Time taken: 3.5 hrs

Speed: 120mi/HR

Now we know that

distance = speed x time

Substituting the given values in the above formula we get

Distance= 120mi/hr x 3 hrs

Distance = 360 mi= 579.36 Km

The speed is the distance covered by an object at a particular time. The distance between the Platform 9 and Hogwarts is 360 miles.

The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.

Speed = Distance Covered / Time taken

Given that it takes 3.5 hours for the Hogwarts Express, moving at a speed of 120 mi/hr, to make it from Platform 9 to Hogwarts. Therefore, we can write the given quantities as,

Speed of the Hogwarts Express = 120 miles per hour

Time taken = 3 hours

Now, the distance between the Platform 9 and Hogwarts can be written as,

Speed = Distance / Time

120 miles per hour = Distance / 3 hours

Distance = 120 miles per hour × 3 hours

Distance = 360 miles

Hence, the distance between the Platform 9 and Hogwarts is 360 miles.

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Answer:

Battery

Explanation:

A battery has the most potential energy, due to its chemical potential energy.

Work done on the crate is given by

[tex]W = Fd cos\theta[/tex]

here we have

[tex]F = 142 N[/tex]

[tex]d = 6.1 m[/tex]

[tex]\theta = 37 degree[/tex]

now we have

[tex]W = Fdcos37[/tex]

[tex]W = 142 * 6.1 * cos37[/tex]

[tex]W = 691.8 J[/tex]

So it require 691.8 J work to slide the block across horizontal floor

Before coming into a conclusion, first we have to understand Einstein's mass energy equivalence theory.

As per this theory ,mass and energy are inter convertible.This theory is mathematically written as-

E=mc^2. Where m is the mass and c is the velocity.

So, when some amount of mass is lost, equivalent amount of energy is produced as per this theory.

As per law of conservation of energy, the total energy of the universe is always constant.Energy is neither created nor destroyed.It only changes from one form to another.

In case of sun,the energy is produced due to fusion reaction.In this type of reaction there will be mass defect .Due to this loss of mass, equivalent amount of energy is produced which comes into earth in the form of radiations.

Here the law of conservation of energy is not violated .Before the fusion reaction,the energy was trapped inside the atoms .When the reaction was initiated, correspondingly same amount of energy is produced due to mass defect ,but the total energy is always constant.

Hence,it is also in accordance with the law of conservation of energy.

Hence,the correct answer to the question is D i.e all the energy that reaches Earth from the Sun was originally contained within the Sun’s atoms.

If we assume the acceleration that the sled undergoes is constant throughout its motion, then we have the average velocity [tex]\bar v[/tex] of the sled to be

[tex]\bar v=\dfrac{v_i+v_f}2=\dfrac{\Delta x}{23\,\mathrm s}[/tex]

where [tex]\Delta x[/tex] is the total displacement of the sled, and [tex]v_i[/tex] and [tex]v_f[/tex] are the sled's initial and final velocities, respectively. The sled eventually stops, so we take [tex]v_f=0[/tex] and solve for [tex]v_i[/tex]:

[tex]\dfrac{v_i}2=\dfrac{15\,\mathrm m}{23\,\mathrm s}\implies v_i=1.3\,\dfrac{\mathrm m}{\mathrm s}[/tex]

Now, take the sled's starting position to be the origin. The sled moves in one direction, which we take to be the positive direction. Then because it's slowing down, we expect its acceleration to be in the negative direction (and hence with negative sign). In particular, the sled's position [tex]x[/tex] at time [tex]t[/tex] is

[tex]x=x_i+v_it+\dfrac12at^2[/tex]

We have [tex]\Delta x=x-x_i=15\,\mathrm m[/tex], [tex]v_i=1.3\,\frac{\mathrm m}{\mathrm s}[/tex], and [tex]t=23\,\mathrm s[/tex], so we can solve for acceleration [tex]a[/tex]:

[tex]15\,\mathrm m=\left(1.3\,\dfrac{\mathrm m}{\mathrm s}\right)(23\,\mathrm s)+\dfrac12a(23\,\mathrm s)^2[/tex]

[tex]\implies a=-0.056\,\dfrac{\mathrm m}{\mathrm s^2}[/tex]

With a mass of [tex]m=52.5\,\mathrm{kg}[/tex], we find that the stopping force is

[tex]F=ma=-2.9\,\mathrm N[/tex]

which means the stopping force has magnitude [tex]2.4\,\mathrm N[/tex] in the negative direction (opposite the direction of the sled's initial velocity).

If his velocity is constant, then there is zero net force on him . . . any force acting on him is exactly canceled by an equal force in the opposite direction.

In the case of a sky-diver, the force of gravity on him (his weight, downward) is exactly canceled by the force of air resistance upward.

The net force on him is zero.  If the net force on him were not zero, then his velocity  wouldn't be constant. He would be accelerated in the direction of the net force.

The lava flowed through low-lying valleys and over the smaller Cascade Mountain Range. As it reached the ocean shore, it sank down into the soft sediments, cooling and hardening into thick black basalt.

Hope I Helped

Neither would move.

Hope this helps.

here in this type of collision we can use momentum conservation

[tex]P_{1i} + P_{2i} = P_{1f} + P_{2f}[/tex]

here we know that

[tex]m_1 = 122 kg[/tex]

[tex]v_{1i} = 13 m/s[/tex]

[tex]v_{2i} = -17 m/s[/tex]

[tex]v_{1f} = v_{2f} = - 3.5 m/s[/tex]

now by above equation of momentum conservation

[tex]122* 13 + m_2*(-17) = 122*(-3.5) + m_2*(-3.5)[/tex]

[tex]1586  - 17*m_2 = - 427 - 3.5* m_2[/tex]

[tex]1586 + 427 = (17 - 3.5)*m_2[/tex]

[tex]2013 = 13.5*m_2[/tex]

[tex]m_2 = \frac{2013}{13.5}[/tex]

[tex]m_2 = 149 kg[/tex]

so mass of the player 2 will be approx 149 kg

they can be called polar covalents

Polar molecules are hydrophillic, So you can say hydrophillic (loves water)

The question is unclear regarding the boat's velocity. Is it 20 m/s south relative to the water, or relative to the earth? (It is a river, after all...)

There's also the possibility that the boat's velocity relative to the river is 0. Take the south direction to be negative and north to be positive, and denote by [tex]v_{A/B}[/tex] the velocity of a body A relative to a body B. Under these conditions,

[tex]v_{B/E}=v_{B/W}+v_{W/E}\iff-20\,\dfrac{\mathrm m}{\mathrm s}=0+-20\,\dfrac{\mathrm m}{\mathrm s}[/tex]

(B for boat, E for earth, W for water) so that the passenger's velocity relative to the earth is

[tex]v_{P/E}=v_{P/B}+v_{B/W}+v_{W/E}[/tex]

(P for passenger)

[tex]v_{P/E}=10\,\dfrac{\mathrm m}{\mathrm s}+0-20\,\dfrac{\mathrm m}{\mathrm s}=-10\,\dfrac{\mathrm m}{\mathrm s}[/tex]

or 10 m/s south.

Resistance of our body is given as

[tex]R = 30,000 ohm[/tex]

voltage applied across the body is

[tex]V = 120 V[/tex]

now by ohm's law current pass through our body is given by

[tex]i = \frac{V}{R}[/tex]

[tex]i = \frac{120}{30,000}[\tex]

[tex]i = 4 * 10^{-3} A[/tex]

So current from our body will be 4 * 10^-3 A

m = mass of the bullet = 10 g = 10 x 10⁻³ kg = 0.01 kg       (since 1 g = 10⁻³ kg)

M = mass of pendulum = 2 kg

h = height to which pendulum rises = 12 cm = 0.12 m

V = velocity of the pendulum-bullet combination after collision = ?

Using conservation of energy

kinetic energy of the combination just after collision = Potential energy gained due to raise in height of the center of mass

(0.5) (m + M) V² = (m + M) gh

V = sqrt(2gh)

inserting the values

V = sqrt(2 x 9.8 x 0.12)

V = 1.5 m/s

v = velocity of the bullet before the collision

using conservation of momentum

momentum of bullet before collision = momentum of bullet-pendulum combination after collision

m v = (m + M) V

(0.01) v = (0.01 + 2) (1.5)

v = 301.5 m/s

hence initial speed of the bullet is 301.5 m/s

The initial speed of the bullet is calculated using the conservation of momentum and conservation of mechanical energy by equating the kinetic energy after collision with the potential energy at the pendulum's highest point and then using the momentum conservation to get the bullet's initial velocity.

To calculate the bullet's initial speed when it strikes a ballistic pendulum, we can use the principles of conservation of momentum and conservation of mechanical energy. First, we find the velocity of the bullet-pendulum system just after the collision using energy considerations. Since the bullet becomes embedded in the pendulum, this is an inelastic collision, and mechanical energy is not conserved during the collision. However, the system's mechanical energy is conserved as it swings upwards to its highest point.

As the pendulum rises to a height of 12 cm, all the kinetic energy of the system is converted into potential energy. The potential energy (PE) gained by the pendulum can be calculated using PE = mgh, where m is the total mass of the system (bullet plus pendulum), g is the acceleration due to gravity (9.81 m/s2), and h is the height (12 cm or 0.12 m). The kinetic energy (KE) just after the collision can be equated to this PE.

The total mass m after the bullet is embedded in the pendulum is (10 g + 2000 g). To find the velocity of the system after the collision, we can use the equation KE = 1/2 m v2 and solve for v. Then, by using the conservation of momentum, the initial velocity of the bullet u can be determined, since momentum before collision (bullet's momentum) is equal to the momentum after collision (system's momentum). The bullet's initial speed is found through the equation mu = (m + M)v, where M is the mass of the pendulum.

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Answer: The correct option is 3.5m/s.

Explanation: In the question, conservation of energy is taking place which means that the energy is getting transferred from one form to another form.

Here, elastic potential energy of the spring is getting converted to the kinetic energy of the block.

Mathematically,

[tex]\frac{1}{2}kx^2=\frac{1}{2}mv^2[/tex]

where, k = spring constant = 56N/m

x = compression of extension of spring = 0.75m

m = Mass of the block = 2.5kg

v = velocity of the block = ? m/s

Putting values in above equation, we get:

[tex]\frac{1}{2}\times 56\times (0.75)^2=\frac{1}{2}\times 2.5\times v^2\\\\v=3.54m/s[/tex]

Hence, the block will move at a speed of 3.5m/s

The velocity of the block after the spring is released is approximately 13 m/s.

To find the velocity of the block after the spring is released, we can use the principle of conservation of mechanical energy. The potential energy stored in the spring will be converted into the kinetic energy of the block as it moves.

The potential energy (U) stored in a spring is given by the equation:

[tex]\[ U = \frac{1}{2} k x^2 \][/tex]

where k is the spring constant and x is the compression of the spring.

 For this problem:

[tex]\[ k = 56 \, \text{N/m} \][/tex]

[tex]\[ x = 0.75 \, \text{m} \][/tex]

So the potential energy stored in the spring is:

[tex]\[ U = \frac{1}{2} (56 \, \text{N/m}) (0.75 \, \text{m})^2 \][/tex]

[tex]\[ U = \frac{1}{2} (56 \, \text{N/m}) (0.5625 \, \text{m}^2) \][/tex]

[tex]\[ U = 15.4 \, \text{J} \][/tex]

This potential energy will be converted into the kinetic energy (K) of the block, which is given by:

[tex]\[ K = \frac{1}{2} m v^2 \][/tex]

where m  is the mass of the block and  v  is its velocity.

The mass of the block m is 2.5 kg, so we have:

[tex]\[ \frac{1}{2} m v^2 = U \][/tex]

[tex]\[ \frac{1}{2} (2.5 \, \text{kg}) v^2 = 15.4 \, \text{J} \][/tex]

[tex]\[ (1.25 \, \text{kg}) v^2 = 15.4 \, \text{J} \][/tex]

[tex]\[ v^2 = \frac{15.4 \, \text{J}}{1.25 \, \text{kg}} \][/tex]

[tex]\[ v^2 = 12.32 \, \text{m}^2/\text{s}^2 \][/tex]

[tex]\[ v = \sqrt{12.32 \, \text{m}^2/\text{s}^2} \][/tex]

[tex]\[ v \ = 13 \, \text{m/s} \][/tex]

force applied due to earth on the apple is given as

[tex]F = ma[/tex]

given that

m = 0.37 kg

a = 9.8 m/s^2

now we have

[tex]F = m*a[/tex]

[tex]F = 0.37* 9.8 = 3.63 N[/tex]

now as per Newton's III law equal and opposite force is applied on earth

so now we can find acceleration of Earth using same equation as we used above

[tex]F = ma[/tex]

here we know that

m = mass of earth

F = 3.63 N

[tex]3.63 = 5.98 * 10^{24} * a[/tex]

[tex]a = \frac{3.63}{5.98 * 10^{24}[/tex]

[tex]a = 6.1 * 10^{-25} m/s^2[/tex]

so acceleration of earth is very small and given by above value

According to Newton's third law, the apple and the Earth exert equal and opposite forces upon each other when the apple is in free-fall. The force that the apple exerts on the Earth is its weight (0.37 kg * 9.8 m/s^2 = 3.626 N), and this is the same magnitude of force that the Earth applies on the apple, causing it to accelerate towards the Earth's surface.

Indeed, according to Newton's third law, for every action, there is an equal and opposite reaction. This principle applies to the scenario of an apple falling towards the earth's surface. When you drop the apple, its weight, or the force due to gravity, accelerates it at 9.8 m/s^2, towards the earth. Conversely, the apple exerts an equivalent force back towards earth. However, due to earth's significantly larger mass, the acceleration it experiences as a result of this force isn't noticeable.

Now, let's clarify the concept of this force exerted by the apple. Weight can be computed as the product of mass and gravity (w=mg). In this case, the mass is 0.37 kg and gravity is 9.8 m/s^2, thus the weight of the apple is 3.626 N. This value represents the force that the apple exerts on Earth when it's in free fall, which is also the force that Earth exerts on the apple, causing it to accelerate downwards.

The magnitudes of these forces are equal, aligning with Newton's third law. Yet, the direction of the forces are opposite. When Earth pulls the apple downwards, the apple simultaneously pulls Earth upwards with the same magnitude of force.

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Answer:

There is an arrow up for the air resistance and an arrow down for gravity. The arrow up is shorter than the arrow down.

Explanation:

So in the free-body diagram you have to draw all the forces that are acting over some body.

In this case when the skydiver is falling down there are only 2 forces acting on him, the gravitational force and the air resistance, therefore in the free-body diagram should be 2 arrows, now we have to determinate the direction of this arrows, so like the gravitational force is pulling the skydiver down (towards to earth) the arrow for this one should be down, and for the air resistance as it's trying to stop skydiver's fall it's direction it's upwards. now for the length of the arrows we have to look in which direction is the skydiver speeding up, in the question it says that the skydiver is speeding up down so the bigger arrow should be downwards too.

Answer:

It take the bullet 0.64 seconds to hit the ground.

Explanation;

 We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Here we need to consider only vertical motion of bullet.

Initial velocity = 0 m/s, Displacement = 1.98 m, acceleration = acceleration due to gravity = [tex]9.8m/s^2[/tex], we need to find time taken

Substituting

   [tex]1.98= 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2=1.98\\ \\ t^2=0.404\\ \\ t=0.64 seconds[/tex]

   It take the bullet 0.64 seconds to hit the ground.

A scalar quantity is one in which there is no direction given.

30 Lbs would be the answer, since there is no indicator of direction.

the answer is c another magnet can be attracted or repelled because they have north and south sides

Answer: Option (C) is the correct answer.

Explanation:

A magnet will only be attracted by another magnet as each magnet contains opposite poles. These poles are north pole and south pole.

Hence, like poles are repel each other whereas opposite poles are attracted towards each other.

Therefore, when a magnet comes in contact with a copper wire then there will be attraction between them.

On the other hand, if south pole of a magnet comes in contact with the north pole of another magnet then a force of attraction will occur between them.

Due to this both the magnets get attracted towards each other. But when south pole of a magnet comes in contact with the south pole of another magnet then force of repulsion will occur.

Thus, we can conclude that another magnet will be attracted to or repelled by a magnet.

Time period of simple pendulum is given by formula

[tex]T = 2\pi \sqrt{\frac{L}{g}}[/tex]

here

L = length of pendulum

g = acceleration due to gravity

now as per formula we can see that time period is directly proportional to the square root of the length.

So in order to increase the time period we can increase its length

so correct answer would be

b. by making the string longer

Answer:

by making the string longer

Explanation:

The atomic emission spectra of a sodium atom on earth and of a sodium atom in the sun would be the same.

When atoms of sodium get excited they move to a higher level and when they move back to the ground level, they emit photons.

Thus the emitted energy of photon depends only on the atom of the sodium (element) and is independent of the atmosphere where it is .Since we are comparing the emission spectra of the same element sodium it is the same on both earth and sun.

Level of sound is related to intensity by this equation

[tex]L = 10 Log \frac{I}{I_o}[/tex]

given that

L = 85 dB

also we know that

[tex]I_o = 10^{-12} W/m^2[/tex]

now we have

[tex]85 = 10 Log \frac{I}{10^{-12}}[/tex]

By solving above equation

[tex]I = 10^{8.5} * 10^{-12}[/tex]

[tex]I = 3.16 * 10^{-4} W/m^2[/tex]

now above is the intensity due to two firecrackers and if we wish to find the sound level of one firecracker then we will find its half level intensity

[tex]I_1 = \frac{I}{2}[/tex]

[tex]I_1 = 1.58 * 10^{-4}[/tex]

now again by above formula

[tex]L = 10 Log \frac{1.58 * 10^{-4}}{10^{-12}}[/tex]

[tex]L = 82 dB[/tex]

Answer with Explanation:

Atom=Smallest Particle present on earth

Subatomic Particle=Smaller than Atom(Electron +Proton)

Electron = -vely Charged Particle

Proton =+vely Charged Particle

In J.J Thompson Model of Atom , which is called Plum Pudding model ,Electrons and Protons that is Subatomic particles were uniformly Distributed inside the Nucleus of Atom.

But Rutherford Contradicted Thompson by saying that, Protons are fixed inside the nucleus and Electrons are moving in Elliptical path around the nucleus like the planets around the sun.This Model is Known as Planetary Model.

Answer:

Student’s(50 kg) gravitational potential energy if the cliff is 80 m high = 39.2 kJ

Explanation:

   Potential energy is given by the expression, PE =mgh, m is the mass, g is the acceleration due to gravity value and h is the height.

 Here mass of student, m = 50 kilogram

           Height of cliff , h = 80 meter

           Acceleration due to gravity = [tex]9.8m/s^2[/tex]

 Potential energy, PE = 50 * 9.8 * 80 = 39200 J

                                    = 39.2 kJ

Student’s(50 kg) gravitational potential energy if the cliff is 80 m high = 39.2 kJ