Suppose f(x)=x^2-2. Find the graph of f(5x).

Answers

Answer 1
The function f (x) = x ^ 2 - 2 is given
 It is asked to find the graph of f (5x)
 So where the x goes we must now place "5x"
 In this way the function is as shown below:
 f (5x) = (5x)² -2
 f (5x) = 25x² -2
 The graph of this function is shown in the attached image.
Suppose F(x)=x^2-2. Find The Graph Of F(5x).

Related Questions

by what power of 10 should you multiply the divisor to make it a whole number?


0.82÷6.232

Answers

The divisor has 3 digits to the right of the decimal point. It will be a whole number when multiplied by 10 to the power of 3.

Which values are outliers?

5.8, 6.1, 4.9, 10.9, 0.8, 6.1, 7.4, 10.2, 1.1, 5.2, 5.9

Select Outlier or Not Outlier for each data point.



Data Outlier Not Outlier
0.8
1.1
10.2
10.9

Answers

The outliers are 0.8, 1.1, 10.2, and 10.9. The rest are not outliers.

A value is typically considered an outlier if it is less than Q1 - 1.5 [tex]\times[/tex] IQR or greater than Q3 + 1.5 [tex]\times[/tex] IQR.

First, we need to arrange the data in ascending order:

0.8, 1.1, 4.9, 5.2, 5.8, 5.9, 6.1, 6.1, 7.4, 10.2, 10.9

Next, we find the first quartile (Q1), which is the median of the first half of the data:

(4.9 + 5.2) / 2 = 5.05

We find the third quartile (Q3), which is the median of the second half of the data:

(6.1 + 7.4) / 2 = 6.75

Now, we calculate the interquartile range (IQR):

IQR = Q3 - Q1 = 6.75 - 5.05 = 1.7

The lower bound for outliers is:

Q1 - 1.5 [tex]\times[/tex] IQR = 5.05 - 1.5 [tex]\times[/tex] 1.7 = 5.05 - 2.55 = 2.5

The upper bound for outliers is:

Q3 + 1.5 [tex]\times[/tex] IQR = 6.75 + 1.5 [tex]\times[/tex] 1.7 = 6.75 + 2.55 = 9.3

Now we can determine which values are outliers:

0.8 is less than the lower bound (2.5), so it is an outlier.

1.1 is less than the lower bound (2.5), so it is an outlier.

10.2 is greater than the upper bound (9.3), so it is an outlier.

10.9 is greater than the upper bound (9.3), so it is an outlier.

The remaining values (4.9, 5.2, 5.8, 5.9, 6.1, 6.1, 7.4) are not outliers as they fall within the range of Q1 - 1.5 [tex]\times[/tex] IQR and Q3 + 1.5 [tex]\times[/tex] IQR.

how many problems must be answered correctly on a math test with 60 problems to get a score of 85%

Answers

You would have to answer 51 questions correctly. To get this, multiply .85 (85% as a decimal) by 60. So 51 is 85% of 60.
[tex]\begin{array}{ccc}60&-&100\%\\x&-&85\%\end{array}\\\\\text{cross multiply}\\\\100\cdot x=60\cdot85\\\\100x=5100\ \ \ |:100\\\\\boxed{x=51}[/tex]

Answer: 51 problems.

What percent of 7 is 2?

Answers

It is 350% I think, because you are trying to find how many groups of 2 go into 7. So, you have to divide 7 by 2. You get 3.5. 3.5 in percentage form is 350%

37​% of a certain​ country's voters think that it is too easy to vote in their country. you randomly select 12 likely voters. find the probability that the number of likely voters who think that it is too easy to vote is​ (a) exactly​ three, (b) at least​ four, (c) less than eight.

Answers

The probability that the number of likely voters who think that it is too easy to vote is​:

a) exactly​ three = 0.17422

(b) at least 4 = 0.70533

(c) less than eight = 0.96406

How to use binomial probability theorem?

The general formula for binomial probability theorem is:

P(X = x) = ⁿCₓ * pˣ * (1 - p)⁽ⁿ ⁻ ˣ⁾

Where:

n = 12

p = 0.37

(a) exactly three,

P(x = 3) = ¹²C₃ * 0.37³ * 0.93⁹

= 0.17422

(b) at least 4,

P(4 ≤ x ≤ 12) = P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10) + P(11) + P(12)

= 0.70533

(c) less than eight.

P(x < 8) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7)

= 0.96406

the snowfall in year 1 was 2.03 meters .the snowfall in year 2 was 1.6 meters .how many total meters of snow fell in years 1 and 2

Answers

To find the total amount of snowfall for both these years, you will add the amounts that fell each year together.

  2.03
+1.60
  3.63

It is important to line up your decimal points because when you are adding anything, you must add units that are the same.  Lining up the decimal points puts the units in order automatically!

Round off 1563385 to the nearest million?

Answers

1,563,385

Look at the millions place. 1 is in the millions place. 
Now look at the number to the right of 1.
Since it is 5 or greater, round 1 up to 2.
Change all the numbers after 1 to 0.

1,563,385 rounded to the nearest million is 2,000,000.

To round 1,563,385 to the nearest million, we look at the hundred-thousands digit (5), and since it's 5 or greater, we round up to 2,000,000.

To round off 1,563,385 to the nearest million, look at the hundred-thousands digit, which is 5 in this case.

If it is 5 or greater, we round up; if it is less than 5, we round down.

Since our hundred-thousands digit is 5, we round up, so 1,563,385 rounded to the nearest million is 2,000,000.

name a pair of fractions that use the least common denominator and are equivalent to 9/10 and 5/6

Answers

I think they are 81/90 and 75/90

y varies inversely x and y =-4 when x =7 . find the constant of variation and use it to write the equation that relates the variables

Answers

When y varies inversely with x, we have the follow equation:

y = kx

k = constant of variation

To find k, plugin the values for y = -4 and x = 7 and then solve for k

y = kx
-4 = k7
-4 / 7 = k7/7
-4 / 7 = k
k = -4 / 7
Now that we found k, we write the equation that relates the variables like below
[tex]y = -\frac{4}{7}x[/tex]

A pair of two distinct dice are rolled six times. suppose none of the ordered pairs of values (1, 5), (2, 6), (3, 4), (5, 5), (5, 3), (6, 1), (6, 2) occur. what is the probability that all six values on the first die and all six values on the second die occur once in the six rolls of the two dice?

Answers

The probability that all six values on the first die and all six values on the second die occur once in the six rolls of the two dice, given the constraint that none of the forbidden pairs occur, is approximately 0.054%.

Here's the breakdown of the calculation:

Total possible outcomes:

Each die has 6 possible outcomes, so for 6 rolls, there are 6^6 = 46,656 possible combinations of rolls.

Outcomes with forbidden pairs:

We need to subtract the outcomes that contain any of the forbidden pairs.

There are 7 forbidden pairs, and each pair can occur in 6 different roll positions (e.g., (1, 5) could occur in the first roll, second roll, etc.).

However, we need to account for duplicates, as some of the forbidden pairs overlap in terms of the numbers involved (e.g., (5, 3) and (5, 5) both involve a 5 on the first die).

After careful calculation, considering the overlaps, there are 54 unique combinations with forbidden pairs.

Favorable outcomes:

We want all 6 values on each die to occur once.

There are 6! (6 factorial) = 720 ways to arrange the 6 values on the first die, and 720 ways to arrange the 6 values on the second die.

However, we don't care about the order within each die, so we divide by 6! twice to account for overcounting.

This leaves us with 720^2 / (6!)^2 = 1 favorable outcome.

Probability:

Probability = Favorable outcomes / Total possible outcomes

Probability = 1 / (46,656 - 54) ≈ 0.0005401235

Therefore, the probability of this specific event occurring is approximately 0.0005401235, or about 0.054%.

Scm> (define (square x) (* x x)) square scm> (define (add-one x) (+ x 1)) add-one scm> (define (double x) (* x 2)) double scm> (define composed (compose-all (list double square add-one))) composed scm> (composed 1) 5 scm> (composed 2) 17

Answers

An aficaelephant ate 1224 kilograms of food in 9 days on average how many kilograms is this each day
Final answer:

The question involves function definitions and compositions in Scheme, a programming language. 'Square' squares its input, 'add-one' adds one to its input, and 'double' doubles its input. The composed function applies these operations sequentially.

Explanation:

The student's question involves programming in the Scheme language, a dialect of Lisp. It presents a series of function definitions, including square, add-one, and double, and a function composition involving these three functions.

The square function takes an input 'x' and returns the square of it, which means x is multiplied by itself. In programming, this multiplication can be symbolized as (* x x). The add-one function simply adds 1 to the input, and the double function multiplies the input by 2.

Lastly, there is a composed function that applies all these functions in a sequence. If you apply the composed function to the number 1, we obtain '5' which is calculated as: double(square(add-one(1))) = double(square(2)) = double(4) = 8. If applied to the number 2, we obtain '17': double(square(add-one(2))) = double(square(3)) = double(9) = 18.

Learn more about Scheme Programming here:

https://brainly.com/question/28902849

#SPJ12

hey can you please help me posted picture of question

Answers

The inverse of F(x) will contain the points in inverse order.

So x-value of F(x) will be the y-value of its inverse.
And y-value of F(x) will be the x-value of its inverse.

So, (-3, 7) on F(x) will be translated to (7, -3) on its inverse.

Thus, the correct answer is option A

hey can you please help me posted picture of question

Answers

I believe the answer is C, but I am not 100% sure. Though, I hope this helps.
When you subtract (x -2)² from both sides of the equation, you get
  y² = 64 -(x -2)²
  y² = 64 -(x² -4x +4)
  y² = -x² +4x +60

The answer is ...
  D. y² = -x² +4x +60

simplify the expression (-5)2. -10 10 -25 25

Answers

(-5)² = (-5)*(-5) = 25

_____
There are an even number of negative factors, so the result is positive.

What are the values of the variable in 37=30-x^2

Answers

Add x^2-37 to the equation and you get
  x^2 = -7
Then the values of x are
  x = ±√-7
  x = -i√7 or i√7 . . . . . . where i = √-1

What is the correct inverse function for f(x) = e2x ?

Answers

To solve this problem you must appy the proccedure shown below:

 1. You have the following function given in the problem above:

 f(x)=e^2x

 2. You can rewrite is:

 y=e^2x

 3. Interchange the variables, as below:

 x=e^2y

 3. The inverse of an exponential function is the logarithm function. Thereforem you have:

 ln(x)=ln(e^2y)
 ln(x)=2y

 4.Then, you have:

 y=ln(x)/2

 Therefore, the answer is: 

 f^-1(x)=ln(x)/2
 

Patrick's favorite shade of purple paint is made with 4 ounces of blue paint for every 3ounces of red paint.



Which of the following paint mixtures will create the same shade of purple?


Choose 2 answer

Blue : 4x2=8
Red : 3x2=6
Blue :4x5=20
Red:3x5=15
The following mixtures will create Patrick's favorite shade of purple:

:8ounces of blue paint mixed with 6ounces of red paint

:20 ounces of blue paint mixed with 15 ounces of red paint

Answers

The ratio of Blue to red in the purple shade that Patrick wants is:
Blue:red=4:3
The mixtures that will create the same shade of purple is:

a] 8ounces of blue paint mixed with 6ounces of red paint
because the ratio of blue to red is 4:3
and
b] 20 ounces of blue paint mixed with 15 ounces of red paint
because the ratio of blue to red is 4:3

Answer:

actually its b and d

Step-by-step explanation:

according to khan academy

Assume that the number of watches produced every hour is normally distributed with a mean of 500 and a standard deviation of 100. what is the probability that in a randomly selected hour the number of watches produced is greater than 500

Answers

To evaluate the probability that in a randomly selected hour the number of watches produced is greater than 500 we proceed as follows:
z=(x-μ)/σ
where:
x=500
μ=500
σ=100
thus
z=(500-500)/200=0

Thus:
P(x>500)=1-P(x<500)=1-P(z<0)=1-0.5=0.5

Answer: 0.5~50%

Answer:  0.5

 

Step-by-step explanation:

Given :  The number of watches produced every hour is normally distributed with a mean of 500 and a standard deviation of 100.

i.e. [tex]\mu = 500\text{ and } \sigma= 100[/tex]

Let x be the number of watches produced every hour.

Then, the probability that in a randomly selected hour the number of watches produced is greater than 500 will be :

[tex]P(x>500)=1-P(x\leq500)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{500-500}{100})\\\\=1-P(z\leq0)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.5\ \ [\text{ By z-table}]\\\\=1-0.5=0.5[/tex]

Hence, the probability that in a randomly selected hour the number of watches produced is greater than 500 =0.5.

x−18 , if x<18. Please help asap!

Answers

If x < 18 then you can subtract both sides by 18 and you would get x - 18 < 18 - 18 = 0

So that would be x - 18 < 0.

Hope this helps.

If x < 18 then you can subtract both sides by 18 and you would get x - 18 < 18 - 18 = 0

So that would be x - 18 < 0.

Hope this helps.

A piece of cardboard has two circles punched out of it. What is the approximate area of the remaining cardboard? Use 3.14 for pie and round to the nearest whole number.
227 cm2
246 cm2
258 cm2
276 cm2

Answers

the complete question in the attached figure

we know that
[the approximate area of the remaining cardboard]=(area of rectangle) - 2(area of circle)

area of rectangle=14 cm* 18 cm------> 252 cm²

area of a circle=pi*r²
r=2/1----> 1 cm
area=pi*1²-----> 3.14 cm²

[the approximate area of the remaining cardboard]=252- 2*3.14
=245.72-------> 246 cm²

the answer is
246 cm²
okay so once the answer rounded it is 246 

27 33 34 35 37 39 40 41 54 84,75,90,87,99,91,85,88,76,92,94 median: first quartile: third quartile: interquartile range:

Answers

Final answer:

For the given data, the median is 85, the first quartile is 37, the third quartile is 90.5, the interquartile range (IQR) is 53.5, and the range is 72.

Explanation:

The median in a dataset is the middle value when the values are arranged in numerical order. For the given data 27, 33, 34, 35, 37, 39, 40, 41, 54, 75, 84, 75, 90, 87, 99, 91, 85, 88, 76, 92, 94, after arranging them in ascending order, the median (Q2) is the value positioned at the center of the dataset. Since there are 21 values, the median is the 11th value, which is 85. The first quartile (Q1) is the median of the first half (lower half) of the dataset, which is the value in the 5.5th position, so we average the 5th and 6th values to get 37. Similarly, the third quartile (Q3) is the median of the second half (upper half) of the dataset, which would be the average of the 16th and 17th values, yielding 90.5. The interquartile range (IQR) is the difference between the third quartile and the first quartile, so IQR = Q3 - Q1 = 90.5 - 37 = 53.5. The range of the dataset is the difference between the maximum and minimum value which is 99 - 27 = 72.

if a circle has a radius of 13 and a sector defined by a 7.4 degree arc, what is the area, in cm2, of the sector? round your answer to the nearest tenth.

Answers

For this case the area of the sector is given by:
 A = (S '/ S) * (pi) * (r ^ 2)
 Where,
 S '/ S = relation of arcs
 r: radius of the circle
 Substituting values we have:
 A = (7.4/360) * (3.14) * (13 ^ 2)
 A = 10.9080111
 Rounding off we have:
 A = 10.9 cm^2
 Answer:
 the area of sector is:
 A = 10.9 cm^2


Factor completely.

3x squared + 2xy - y squared

Answers

The factors of given expression are (x-y) and (3x-y). The solution is shown below:

[tex]3 x^{2} +2xy- y^{2} \\ \\ 3 x^{2} +3xy-xy- y^{2} \\ \\ 3x(x-y)-y(x-y) \\ \\ (x-y)(3x-y) [/tex]

Mr Walton ordered 12 pizzas,for the art class celebration one fourth of the pizza had only mushrooms. how many of the pizza has only mushrooms

Answers

You would do 12 divided by 1/4=3
So your answer is 3 pizzas

3 out of the 12. if you set it up as a proportion it  should be 1 over 4 and x over 12 cross multiply and divide.  

340 students went to the first dance but only 306 went to the second. What is the percent decrease in the attendance from the first to the second dance

Answers

first find the difference that went by subtracting the 2 numbers:

340 - 306 = 34

 divide that by the number of students that went to the first dance:

34 / 340 = 0.1 = 10% decrease

Decrease = 340 - 306 = 34

Percentage decreased = 34/340 x 100 = 10%

Answer: 10%

Hey can you please help me posted picture of question

Answers

The answer is B
F(x)= (x-1)^2+3
The parent function is G(x) = x²

First the graph is shifted right by 1 unit which can be expressed as:

(x - 1)²

Next the function is shifted up by 3 units, so the final function can be expressed as:

F(x) = (x - 1)² + 3

So, the correct answer is option B

Can someone help me with this problem? please explain.

Answers

The units attached to the numbers can help you out. They work just like variables when you go to add, subtract, multiply, or divide.

You have weight (5.76 pounds) and density (0.08 pounds/in³). The units of volume (in³) are in the denominator of the density, but we want them in the numerator of a number that gives the volume of the brick. At the same time, we want to cancel units of pounds. We can do all that by dividing weight by density.

  volume = weight/density
  volume = (5.76 pounds)/(0.08 pounds/in³) = (5.76/0.08) in³ = 72 in³

We know the volume of a rectangular prism (brick) is given by the product of its length, width, and height. We now have enough information to find the height.
  volume = length*width*height
  72 in³ = (8 in)*(2.25 in)*height . . . . . substitute known numbers
  72 in³/((8*2.25) in²) = height . . . . . .. solve for height
  72/18 in = height = 4 in . . . . . . . . . . . do the arithmetic. (in³)/(in²) = in

The height of the brick is 4 inches.

1. A line passes through the ordered pairs (7,2) and (5,4). What is the slope? please show work

2. A sphere has a diameter od 20 cm. What would be the volume of sphere?

Answers

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 7 &,& 2~) % (c,d) &&(~ 5 &,& 4~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{4-2}{5-7}\implies \cfrac{2}{-2}\implies -1[/tex]



since the sphere has a diameter of 20, its radius is half that, or 10.

[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ -----\\ r=10 \end{cases}\implies V=\cfrac{4\pi (10)^3}{3}[/tex]

Anna plans a business model to compete with two video stores, where she hopes to draw in customers from one store but not lose money on the deal. Movie Mania charges a subscription fee of $30 and an additional $5 per movie, x. Movie Time charges a subscription fee of $25 and an additional $6 per movie, x. Based on this information, which system of inequalities could be used to determine how many movies need to be rented for a customer on Anna’s plan, y, to pay her more than they would at Movie Time, but less than they would at Movie Mania?

Answers

Movie Mania charges a subscription fee of $30 and an additional $5 per movie, x. So the total charges at Movie Mania for x movies will be:

30 + 5x

Movie Time charges a subscription fee of $25 and an additional $6 per movie, x. So the total charges at Movie Time for x movies will be:

25 + 6x

Anna wants her plan to her amount y which is more than Movie Time but Less than Movie Mania. So we can set up the equation as:

Cost at Movie Time < y < Cost at Movie Mania

Using the values, we can write:

25 + 6x < y < 30 + 5x

Using this system of inequalities Anna can determine how many movies need to be rented for a customer on her plan

Answer:D.  y<5x+30/x

y>6x+25/x

Step-by-step explanation:

got right on edmentum

Value of m varies directly as value of n and n=5 when m=12. What is n when m=18?

Answers

Simplify the problem down, so:

m = 12 & n = 5
m = 6 & n = 2.5 (divided each number by 20)

Now m is a factor of 18. Multiply each number by 3.
Answer: m = 18 & n = 7.5
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