There are 24 students 8 of the students are boys write the amount of boys in the class as a fraction in its simplest form

The value of the perimeter of quadrilateral MNOP is,

= 22 units

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

We have to given that;

A quadrilateral MNOP is shown in figure.

M = (- 2, 2)

N = (2, 5)

O = (8, 5)

P = (4, 2)

Now, We can formulate;

MP = 6 units

PO = √(8 - 4)² + (5 - 2)²

PO = √ 25

PO = 5

Thus, The value of the perimeter of quadrilateral MNOP is,

= 2 (MP + PO)

= 2 (6 + 5)

= 2 x 11

= 22 units

So, The value of the perimeter of quadrilateral MNOP is,

= 22 units

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Answer:

The answer is 4x^6 + 6x^5 + 8x^4

Step-by-step explanation:

2x^4(2x^2 + 3x + 4)                 Note: You add the exponents for multiplactation

4x^6 + 6x ^5 + 8x^4                 Note: the exponent is 5 instead of 4 for the 2nd                                                                 :)                                                 term of the soultion because there is a x on 3

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Answer:

Step-by-step explanation:

Answer:

qwerty

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

a=false

b=false

c=false

d=true

edge.

We have been given that Daniel's weekly allowance is $10 and we have to figure out his monthly fixed and variable expenses. To tackle this problem we have to figure out what are fixed expenses and what are variable expenses.

Fixed expenses are not going to vary as they are fixed. We have been given that Daniel has  swimming class once a week and pays a $1.50 pool fee. Daniel is also saving for a new swimming trunks  and sets aside $2.50 per week.

Variables expenses vary in a given range. We have been given that Daniel  sometimes goes out to eat with friends and spends $5 to $10. Daniel goes to a swim meet in another town and spends $3 to $9 on bus fare.

Now let us find monthly fixed  expenses first. [tex]1.50+2.50[/tex] are his weekly fixed expenses. To figure out monthly expenses we will multiply weekly expenses by  4 because a month has four weeks.

Monthly fixed expenses=[tex]4\times (1.50+2.50)=4\times 4=16[/tex]$

Now we will figure out monthly variable expenses. We have been given that Daniel has spent $8.50 for lunch and gone for two swim meets costing $7 each.

Monthly variable expenses=[tex]8.50+2\times 7=8.50+14=22.50[/tex]$

The question can be solved using a system of linear equations. The price of each ticket is found to be $20, and the fixed fee added by the ticket agency is $13.

The subject of this question concerns solving a system of linear equations. Given the two scenarios, buying 5 tickets for $93 and buying 3 tickets for $53, we can represent these as equations where 't' represents the price of a ticket and 'f' represents the fixed fee. The equations thus become:

To solve this system of equations, we could subtract the second equation from the first, which would eliminate 'f' and yield an equation only in terms of 't'. This would look like:

2t = 40

From here, we can see that t (the price of each ticket) equals $20. We can then substitute 't' into one of the equations to find the fixed fee 'f', which in this case equals $13.

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Answer:

3 mph

Step-by-step explanation:

Two cyclists leave town at the same time on the same road going in  the same direction.

Cyclist A is going 6 mph faster than cyclist B

Let speed of cyclist B be x mph

Speed of cyclist A be (x+6) mph

Both cyclist leave town at the same time and traveled 8 hours.  

After 8 hours cyclist A has traveled 3 times the distance as cyclist B

Therefore, 8(x+6) = 3(8x)

8x + 48 = 24x

24x - 8x = 48

       16x = 48

          x = 3 mph

Hence, The speed of cyclist B was 3 mph

The temperature in degrees Fahrenheit when it is 90 °C is approximately 194 °F. Therefore, option d is the correct answer.

Let's use the correct formula [tex]F = \frac{9}{5}C +32[/tex] to find the temperature in degrees Fahrenheit when it is 90 °C.

[tex]F = \frac{9}{5} *90+32[/tex]

Now, let's calculate:

[tex]F = \frac{9}{5} *90+32[/tex]

F=162+32

F=194

Therefore, the temperature in degrees Fahrenheit when it is 90 °C is approximately 194 °F.

So, the correct answer is D. 194 °F.

The volume of this box is indeed 84 in^3.  What were you looking for beyond that?

Base:  (7 in)(3 in) = 21 in^2

Height:  4 in

volume = (21 in^2)(4 in) = 84 in^3 (answer)

Answer:

the answer is c

Step-by-step explanation:

Answer:

Option A - 2.2

Step-by-step explanation:

Given : Data  7, 2, 8, 5, 9, 9, 5, 6, 8, 1.

To find : What is the mean absolute deviation for these data?

Solution :

Step 1 - Calculate the mean of the data,

[tex]M=\frac{\sum x_n}{n}[/tex]

[tex]M=\frac{7+2+8+5+9 +9+5+6+8+1}{10}[/tex]

[tex]M=\frac{60}{10}[/tex]

[tex]M=6[/tex]

The mean is 6.

Step 2 - Calculate the distance between each data point and the mean.

Data points     Distance from mean

 7                        |7-6| = 1

 2                        |2-6| = 4

 8                        |8-6| = 2

 5                        |5-6| = 1

 9                        |9-6| = 3

 9                        |9-6| = 3

 5                        |5-6| = 1

 6                        |6-6| = 0

 8                        |8-6| = 2

 1                        |1-6| = 5

Step 3 - Add all the terms of distance from mean

X=1+4+2+1+3+3+1+0+2+5=22

Step 4 - Apply mean absolute deviation formula,

[tex]MAD=\frac{\sum X}{n}[/tex]

[tex]MAD=\frac{22}{10}[/tex]

[tex]MAD=2.2[/tex]

Therefore, Option A is correct.

The mean absolute deviation is 2.2.

The number of milligrams of aluminium in the body is 300 times the number of milligrams of gold in the body.

Given amount of gold is = g =  [tex]2 * 10^{-1}[/tex] mg.

Given amount of aluminium is = a = [tex]6*10^1[/tex] mg.

Let the number of milligrams of aluminium in the body is "k" times the number of milligrams of gold in the body.

So, a = kg

[tex]k=\frac{a}{g}\\k=\frac{6\cdot10^{1}}{2\cdot10^{-1}}\\k=300[/tex]

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The body of a 154-pound person contains approximately 300 times more milligrams of aluminum than milligrams of gold. This is found by dividing the amount of aluminum (60 milligrams) by the amount of gold (0.2 milligrams).

To find out how many times the number of milligrams of aluminum is compared to that of gold in a 154-pound human body, we need to divide the amount of aluminum by the amount of gold. The problem states that there are 2 X 10^-1 milligrams of gold and 6 X 10^1 milligrams of aluminum. If we simplify these expressions, we get 0.2 milligrams of gold and 60 milligrams of aluminum.

Next step is to divide the number of milligrams of aluminum by the number of milligrams of gold. Hence, 60 ÷ 0.2 gives us 300.

Therefore, the body of a 154-pound person contains approximately 300 times more aluminum than gold.

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We are given expression :  5+2x10.

It can be read as 5 plus 2 times 10.

Now, we need to see, what operation should carry out first.

Please note: We always follow the order of operations.

The order of operations could be follow by the rule  PEMDAS.

It stands for Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.

We don't have Parentheses, Exponents in the given problem.

So, we would start order of operations: first multiplication and then addition.

So, we need to multiply 2 × 10 first.

2 × 10 = 20.

Now, we need to apply addition operation.

Therefore, 5+2x10 = 5+20.

On adding 5 and 20, we get 25.

So, the final answer is 25.

Answer:

25 (assuming the x means multiplication)

Step-by-step explanation:

Start by using PEMDAS (Parenthesis, exponents, multiplication and division from right to left, addition and subtraction from right to left) you would start with multiplication or 2x10 which is 20 and then you have 5+20 left and that is obviously just 25

Answer:

7.1  square feet

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

In order to solve this we will need the formula that calculates the Area of a Circle. The formula is the following,

[tex]A = \pi r^{2}[/tex]

Where:

We are given the diameter of the circle in the question but based on the formula we need the radius. The radius is half of the diameter. Therefore,

[tex]r = 3ft / 2[/tex]

[tex]r = 1.5[/tex]

Now that we have the radius we can plug it into the formula to find the area of the circle.

[tex]A = \pi 1.5^{2}[/tex]

[tex]A = \pi 2.25[/tex]

[tex]A = 7.06 [/tex]

Based on the calculations above we can see that 7.1 [tex]ft^{2}[/tex] (rounded to the nearest tenth) needs to painted

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

In 100g of 15% sugar syrup, there is 15g of sugar.

Sugar syrup is a thick viscous liquid that mostly contains water and dissolved sugar in it. therefore, a 20% sugar syrup means having a 20:80 ratio of sugar and water in a unit of sugar syrup.

100g of sugar syrup 15% sugar,

Now, 15% of sugar means having a 15:85 ratio of sugar and water in 100g of sugar syrup. Let the sugar in 100g of sugar syrup be x. so, the water in the syrup is (100-x), therefore,

[tex]\bold{\dfrac{15}{85} = \dfrac{sugar}{water}}[/tex]

Substituing the values we get,

[tex]\dfrac{15}{85} = \dfrac{x}{100-x}\\\\15\times(100-x) = 85x\\1500 - 15x = 85x\\1500 = 85x +15x\\1500 = 100 x\\\\x = \dfrac{1500}{100}\\\\x = 15[/tex]

Hence, In 100g of 15% sugar syrup, there is 15g of sugar.

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Answer:

c

Step-by-step explanation: