Suppose p(x1) = .75 and p(y2 | x1) = .40. what is the joint probability of x1 and y2?

Answers

Answer 1
By definition of conditional probability,

[tex]\mathbb P(Y_2\mid X_1)=\dfrac{\mathbb P(Y_2\cap X_1)}{\mathbb P(X_1)}[/tex]

so

[tex]\mathbb P(Y_2\cap X_1)=0.40\times0.75=0.3[/tex]
Answer 2

The joint probability of x1 and y2 is  P (Y₂/X₁ ) = P(Y₂ ∩ X₁ )/ P (X₁) will be 0.3.

What is the probability about?

In the joint probability of x1 and y2 is  P (Y₂/X₁ )= P(Y₂ ∩ X₁ )/ P (X₁).

Therefore:

P(Y₂ ∩ X₁ )

=0.40 x 0.75

= 0.3

Therefore by following the law of conditional probability, the outcome of the The joint probability of x1 and y2 is  P (Y₂/X₁ ) = P(Y₂ ∩ X₁ )/ P (X₁) will be 0.3.

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Answers

Answer: option 2

Step-by-step explanation:

Answer:

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Which equation represents a direct linear variation?

y=1/x

y=x+2

y=x^2

y=(1/2)x

Thanks for helping. Im pretty sure its either the 2nd or the fourth but im not Sure

Answers

y=(1/2)x cause the constant variation is 1/2

Answer: y=(1/2)x represents a direct linear variation.

Step-by-step explanation:

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