Suppose the universe contained only low-mass stars. Would elements heavier than carbon exist?

Explanation:

Given that,

Speed of light in vacuum, [tex]v=3\times 10^8\ m/s[/tex]

Refractive index of the liquid, n = 2

We need to find the speed of light in the liquid. Th refractive index of material is given by the ratio of speed of light in vacuum to the speed in the medium. i.e.

[tex]n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{2}\\\\v=1.5\times 10^8\ m/s[/tex]

So, the correct option is (c). Hence, this is the required solution.

Answer:

A negative charge

Explanation:

If there is an excess of electrons in a substance, this will have a negative net charge. This is because electrons have negative charge

q = -1.67*10^{-19}

each electron will contribute with this charge to the total negative net charge of the substance.

hence, the answer is "A negative charge"

A substance with an excess number of electrons on its surface has a negative charge due to the negatively charged nature of electrons.

If a substance has an excess number of electrons on its surface, it will have a negative charge. This is because electrons have a negative charge, and having more electrons than protons results in a net negative charge for the substance. By contrast, if a substance had more protons than electrons, it would have a positive charge. Substances are typically electrically neutral when the number of electrons equals the number of protons, and this balance means there is no net electric charge.

An atom that gains one or more electrons will exhibit a negative charge and is called an anion. Conversely, when an atom loses one or more electrons, it becomes a positively charged atom, also known as a cation. For instance, when a neutral sodium atom loses one electron, it becomes a sodium cation with a 1+ charge. Conversely, an oxygen atom that gains two electrons becomes an anion with a 2- charge.

Answer:

a) 1.26e^-10F

b) 1.47e^-10F

c) 2.39e^-8C   2.89e^-8C

d) E=4500.94N/C

e) E'=5254.23N/C

f) 100.68V

g) 1.65e^-10J

Explanation:

To compute the capacitance we can use the formula:

[tex]C=\frac{k\epsilon_o A}{d}[/tex]

where k is the dielectric constant of the material between the plates. d is the distance between plates and A is the area.

(a) Before the material with dielectric constant is inserted we have that k(air)=1. Hence, we have:

[tex]k=1\\A=0.30m^2\\d=0.021m\\e_o=8.85*10^{-12}C^2/(Nm^2)\\\\C=\frac{(1)(8.85*10^{-12}C^2/(Nm^2))(0.30m^2)}{0.021m}=1.26*10^{-10}F[/tex]

(b) With the slab we have that k=4.8 and the thickness is 4mm=4*10^{-3}m. In this case due to the thickness of the slab is not the same as d, we have to consider the equivalent capacitance of the series of capacitances:

[tex]C=(\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_1})\\\\\\C_1=\frac{(1)(8.85*10^{-12}C^2/(Nm^2))(0.30m^2)}{8.5*10^{-3}m}=3.1*10^{-10}F\\\\C_2=\frac{(4.8)(8.85*10^{-12}C^2/(Nm^2))(0.30m^2)}{4*10^{-3}m}=3.186*10^{-9}F\\\\C=1.47*10^{-10}F[/tex]

(c)

The charge between the plates for both cases, with the slab is given by:

Q : without the slab

Q': with the slab

[tex]Q=CV=(1.26*10^{-10}F)(190V)=2.39*10^{-8}C\\\\Q'=C'V=(1.47*10^{-10F})(190V)=2.79*10^{-8}C\\[/tex]

(d) The electric field between the plate is given by:

[tex]E=\frac{Q}{2\epsilon_o A}[/tex]

E: without the slab

E': with the slab

[tex]E=\frac{2.39*10^{-8}C}{2(8.85*10^{-12}C^2/Nm^2)(0.30m^2)}=4500.94N/C\\\\E'=\frac{2.79*10^{-8}C}{2(8.85*10^{-12}C^2/Nm^2)(0.30m^2)}=5254.23N/C\\[/tex]

(f) We can assume the system as composed by V=V1+V'+V1 as in (c). By using the equation V=Ed we obtain:

[tex]V=2(4500.94)(8.85*10^{-3}m)+(5254.23)(4*10^{-3}m)=100.68V[/tex]

(g) External work is the difference between the energies of the capacitor before and after the slab is placed between the parallels:

[tex]\Delta E=\frac{1}{2}[(1.26*10^{-10}F)(120V)-(1.47*10^{-10})(100.6V)]=1.65*10^{-10}J[/tex]

Answer:

V = -0.3 m/sec.

Explanation:

5.0 x 0.12 + 2.0 x v = 0. Which means that V = -0.3 m/sec.

The -ve sign shows it moves in the opposite direction.

Answer:

F = 5.33*10^-4N

Explanation:

to find the electrostatic force you use the Coulomb's law, given by the formula:

[tex]F=k\frac{q_Aq_B}{r^2}[/tex]

k: Coulomb's constant = 8.89*10^9 Nm^2/C^2

q_a: charge of A = 2.0*10^{-6}C

q_B: charge of B = -3.0*10^{-6}C

r: distance between the spheres = 10.0m

By replacing all these values you obtain:

[tex]F=(8.89*10^9Nm^2/C^2)\frac{(2.0*10^{-6}C)(-3.0*10^{-6}C)}{(10.0m)^2}=5.33*10^{-4}N[/tex]

hence, the forcebetween the spheres is about 5.33*10^-4N

Answer:

4. Personnel policies and programs

Explanation:

The Health care organizations that apply for Magnet status must demonstrate new ways of doing things and innovations in professional practice.

Personnel policies and programs is one of the forces of magnetism that impacts the structural empowerment of the organization.

The Personnel policies of an organization should provide an innovative environment in which the staff are developed and empowered. Empirical quality outcomes are reviewed by assessing the quality of care. New knowledge, innovations, and improvements are reviewed by assessing the quality improvement of the health care organization. Interdisciplinary relationships are assessed to review exemplary professional practice.

The Magnet Recognition Program evaluates 'Structural Empowerment' to review the structural empowerment of a healthcare organization. It accounts for professional engagement, community involvement, personnel policies and programs, professional development, and diversity.

The Magnet Recognition Program, a healthcare organization accreditation program initiated by the American Nurses Credentialing Center (ANCC), assesses the performance of hospitals based on 14 forces of magnetism that form five model components. The 14th force, known as Structural Empowerment, is evaluated to review the ability of the organization to provide an infrastructure that supports professional development and interprofessional collaboration. It includes professional engagement, community involvement, personnel policies and programs, professional development, and diversity.

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Answer:

Work done will be equal to 35 J

So option (c) will be correct answer

Explanation:

We have given force F = 50 N

Frictional force f = 43 N

So net force will be equal to [tex]F_{net}=50-43=7N[/tex]

Distance covered on the ground d = 5 m

We have to find the work done

Work done is equal to [tex]W=F_{net}\times d=7\times 5=35J[/tex]

So option (C) will be the correct answer.

The correct option is A 250 J.

Given, Horizontal  force is 50 N.

Frictional force is 43 N.

The distance between worker and pushing of wheelbarrow is 5 m.

We know that, Work is a physics term describing the amount of energy transferred when it is moved over a distance by an external force.

So Work = Force . Displacement

 work = F D cos [tex]\Theta[/tex]......(eq 1)

Here [tex]\Theta[/tex] is 0 .

So, [tex]work = 50 \times 5 \times 1[/tex] ( cos 0 = 1 )

Work = 250 J

Hence 250 J of work is done on the wheelbarrow by the worker.

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Answer:

photosphere

Explanation:

Photosphere, visible surface of the Sun, from which is emitted most of the Sun’s light that reaches Earth directly. Since the Sun is so far away, the edge of the photosphere appears sharp to the naked eye, but in reality the Sun has no surface, since it is too hot for matter to exist in anything but a plasma state—that is, as a gas composed of ionized atoms.

Source :

Photosphere astronomy

Written By:. Harold Zirin

Answer:

Oumuamua is outside the solar system which is in cigar shaped.

Hope it will help you :))

Every star, except the Sun, is outside the solar system.

ω = ?

mass = 45.8kg

r = 0.512m

E = 2.99*10⁹J

Kinetic Energy of rotation = I * ω²

K.E = I * ω²

I = ½ m*r²

I = ½ * 45.8 * (0.512)²

I = 6.0kgm²

K.E = ½ * I * ω²

ω = √(2K.E / I )

ω = √[( 2* 2.99*10⁹) / 6]

ω = 3.157*10⁴ rad/s

Answer:

Explanation:

Without seeing the options i can tell you this:

A balanced force is equal on both sides

The friction would equal the force

The amount on the left (friction side) would equal the amount on right (force side)

Or the net force would equal zero

You should post the answer options for more help

Answer: A book falls to the floor.

A car skids to a stop.

A foam ball launches

Explanation:

Answer:

Density = 1464.8kg/m3

the density of the metal is 1464.8kg/m^3

Explanation:

Given;

Mass m = 450g

Density = Mass/Volume = m/V

Volume V = change in height × base area = ∆h × A

∆h = 4.8cm

A = 8×8 = 64cm^2

V = 4.8×64 = 307.2cm^3

Density = 450g/307.2cm^3

Density = 1.4648g/cm^3

Density = 1.4648 × 1000kg/m^3

Density = 1464.8kg/m3

the density of the metal is 1464.8kg/m^3

Answer:

1464.84 kg/m³

Explanation:

Density = mass/volume.

D = m/v................. Equation 1

But from Archimedes principle,

every object immersed in water will displaced an amount of water equal to its own volume

Therefore,

v = v'................... Equation 2

Where v = volume of the irregular object, v' = volume of water displaced.

Since the base of the container is a square,

Then,

v' = L²(d)...................... Equation 3

Where L = length of the square base of the container, d = rise in water level.

Substitute equation 3 into equation 1

D = m/L²d......................... Equation 4

Given: m = 450 g = 0.45 kg, L = 8 cm = 0.08 m, d = 4.8 cm = 0.048 m

Substitute into equation 4

D = 0.45/(0.08²×0.048)

D = 0.45/0.0003072

D = 1464.84 kg/m³

Final answer:

The apparent weight that the pilot feels at the bottom of the loop-the-loop is calculated by summing the gravitational force and the centripetal force, resulting in an apparent weight of 4012.9 N.

Explanation:

The student's question is asking to calculate the apparent weight that a pilot feels at the bottom of a loop-the-loop. To find the apparent weight, we must calculate the normal force on the pilot, which is the combination of the gravitational force and the centripetal force required to keep the pilot in a circular path at the bottom of the loop.

Firstly, we calculate the gravitational force (weight) acting on the pilot: W = m × g, where m is the mass of the pilot, and g is the acceleration due to gravity. For the pilot with a mass of 84.0 kg, W = 84.0 kg × 9.8 m/s² = 823.2 N.

Next, we determine the centripetal force required for circular motion at the bottom of the loop: Fc = (mv²) / R, where m is the mass, v is the constant speed, and R is the radius of the loop. With v = 345 m/s and R = 3.033 km (or 3033 m), Fc = (84.0 kg × (345 m/s)²) / 3033 m = 3189.7 N.

The apparent weight of the pilot at the bottom of the loop is the sum of the gravitational force and the centripetal force: Apparent weight = W + Fc = 823.2 N + 3189.7 N = 4012.9 N.

Therefore, the pilot feels an apparent weight of 4012.9 N at the bottom of the loop-the-loop.

The fraction of the distance from the central maximum to the first minimum where the intensity is I1 is 1/2.

The intensity at the central maximum of a double-slit interference pattern is 4I1 and the intensity at the first minimum is zero. To find the fraction of the distance from the central maximum to the first minimum, we can use the formula for intensity in double-slit interference:

I = 4I1 cos2(πd/λ)

At the first minimum, the intensity is zero. Therefore, we have:

0 = 4I1 cos2(πd/λ)

Simplifying this equation, we find that cos2(πd/λ) = 0.

If cos2(πd/λ) = 0, then cos(πd/λ) = 0.

And if cos(πd/λ) = 0, then πd/λ = π/2.

Solving for d/λ, we get d/λ = 1/2. Therefore, the fraction of the distance from the central maximum to the first minimum where the intensity is I1 is 1/2.

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Answer:

a) 4.25 x 10∧-5 T

b) 16.03 mv

Explanation:

the solution is shown in the pictures attached

The maximum magnetic field that could be induced at the base of the power line towers would be around 1.67 µT, directed upwards. For a person lying down near the base of these power lines, the approximate maximum emf produced around their perimeter would be about 5.6 mV. The magnetic field strength is quite weak and its likelihood to cause biological impact is low.

First, for (a), the field is the result of both sources, with one of the currents in opposite direction. So, we can just take the double of it, giving us that the magnitude of magnetic field is B = (2μ₀I)/(2πr). Plugging the known values in, we get B = 2 x (4π x 10⁻⁷ Tm/A) x (4x10⁴A) / (2πx19m) approximately equal to 1.67 µT directed upward.

For (b), we will consider the person as a rectangular coil. In this case, we can use Faraday's Law of Electromagnetic Induction which states that emf = -N ∆Φ/∆t, where ∆Φ is the change in magnetic flux and N is the amount of loops or turns. Here, N=1 as the person is considered as a single loop.

The flux changes from B*A to -B*A, so ∆Φ = 2BA. Resulting, emf = (2BA Δt) with Δt = 1/120 second (as it's 60 Hz, so frequency = 2 per every 1/60 seconds). Plugging all the known values, we get emf approximately equal to 0.0056 V or 5.6 mV. Even though it changes over time, this magnetic field strength is still very weak and thus, is less likely to cause biological effects.

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Answer: Tension = 53.6N

Explanation:

Given that

Height h = 1 m

Time t = 1.7 s.

Mass m = 5.1 kg 

From the equation of the motion we can get the acceleration of the elevator:

h = X0+ V0t + at2/2;

Th elevator starts from rest with a constant upward acceleration. Initial velocity Vo = 0, also Xo = 0; thus

a = 2h/t2 = 2 × 1/1.7^2

a = 0.69 m/s2.

Then we can find the tension in the cord by using the formula

T = mg + ma

= 5.1 (9.8 + 0.69)

= 5.1 × 10.5

= 53.6N

Answer:

It depends on the current

Explanation:

The formula for the energy stored in an inductor is W =1/2 *L*I2

We can state that an electric current flowing in inductor , there is energy stored in the magnetic field. let consider the pure inductor L, and the power which is supplied to initiate the current in inductor.

consider the equation P = i*v

write the equation in terms of inductor.

P = L*i di/dt

P*dt = L*i di

rewrite the Energy equation W = \int_{0}^{t}P*dt

W = \int_{0}^{t} L*i di

by solving we will get the W = 1/2 *L*I2

From this information and formula we can state that he energy stored in an inductor depends on the current.

Answer:

The complete option for the question

a.it depends on the self induced emf

b it depends on the inverse of the self induced emf

C.it depends on the current

d.it depends on the inverse of current

Answer is.it depends on the current

Explanation:

The energy stored in an inductor is W=1/2LI^2

From this equation it can be seen that energy in inductor L depends on current L

Answer:

See explanation

Explanation:

Solution:-

- A wire of arbitrary shape,which is confined to the x-y plane,carries a current I from point A to point B in the x-y plane.

- See diagram (attached) for clarity.

- Let’s assume that the horizontal distance between A and B is "s" and the vertical distance between A and B is "d". Then for the straight line path vector ( L ):

                    L = s i^ + d j^

- The force on the straight wire with current I is then:

                    F = I * ( L x B )

Where,  L: The path vector between points A and B

             B: The magnetic field strength vector

For the curved wire vector "ds = dx i^ + dy j^" and the force on the wire is:

                   F = ∫ [ I (ds x B) = I ∫ (dx i^ + dy j^) x B

When current "I" and magnetic field "B" are uniform then we can pull both of them out of the integral. Separate the integral and calculate each differential separately:

                  F = I ∫ (dx i^) x B + I ∫ (dy j^) x B

                     = I (s i^ x B) + I ( d j^ x B ) = I ( L x B )

- The force of curved and straight line have the same force:

                 F = I ( L x B ) acting on them.

The mass that should be displaced 20.0 cm should be 20000 N/m.

At the time When a spring should be stretched or compressed its length so it changed by an amount x from its equilibrium length due to which the restoring force is exerted.

here,

spring constant is [tex]k = 1.00 * 10^3 N/m[/tex]

mass is x = 20.0 cm

Now

As per Hooke's law

We know that

F = - kx

[tex]= - 1.00 *10 ^3 * 20.0[/tex]

F = 20000 N/m

Hence, The mass that should be displaced 20.0 cm should be 20000 N/m.

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To find the restoring force, use Hooke's Law: F = -kx. With a spring constant of 1.00 × 10³ N/m and a displacement of 20.0 cm (0.200 m), the restoring force is 200 N.

To answer this, we use Hooke's Law, which states:

F = -kx

Where:

F indicates the restoring force

k denotes the spring constant

x indicates the displacement

Given the spring constant k = 1.00 × 10³ N/m and displacement x = 20.0 cm (which we convert to meters, so x = 0.200 m), we substitute these values into the equation:

F = - (1.00 × 10³ N/m) × (0.200 m)

This simplifies to:

F = -200 N

The negative sign indicates that the force is directed opposite to the direction of displacement, which is typical for restoring forces. Therefore, the restoring force is 200 N.

Answer:

Emitted power will be equal to [tex]7.85\times 10^{-5}watt[/tex]

Explanation:

It is given factory whistle can be heard up to a distance of R=2.5 km = 2500 m

Threshold of human hearing [tex]I=10^{-12}W/m^2[/tex]

We have to find the emitted power

Emitted power is equal to [tex]P=I\times A[/tex]

[tex]P=I\times 4\pi R^2[/tex]

[tex]P=10^{-12}\times 4\times 3.14\times 2500^2=7.85\times 10^{-5}watt[/tex]

So emitted power will be equal to [tex]7.85\times 10^{-5}watt[/tex]

Answer:

The idea that little children are continually coming up with ideas and testing them is called the general theory.

Answer:

1. The planet doesn't have a thick enough atmosphere.

2. There have been multiple impacts on the planet.

Explanation:

As the planet is very close to the star, there is high possibility that it will not have an atmosphere. Just like Mercury doesn't have one. Presence of a very large crater with basin indicates that in the past a huge body had hit the planet and thus creating the crater with basin. Also, it must be very old.

Second observation that is given is the presence of smaller craters in the basin. This indicates impact craters created by smaller objects. If the planet had an atmosphere, these smaller objects would not be able to penetrate and reach the surface. Thus presence of these smaller crater indicate towards the planet not having any atmosphere.

The total energy of the pendulum is directly proportional to the square of the amplitude. Hence, if the amplitude is increased by a factor of 4, the total energy in the system will increase by a factor of 16.

The subject of your question is related to the energy of a pendulum in simple harmonic motion. The total energy stored in an oscillating pendulum depends on the square of its amplitude. The total energy E of an oscillator is the sum of its kinetic energy K = mu² / 2 and the elastic potential energy of the force U(x)= k_x²/2 (formula for potential energy in a harmonic oscillator). These two forms of energy: kinetic energy and potential energy oscillate back and forth but their sum remains constant.

Since the total energy ETotal = (1/2)kA² is proportional to the square of the amplitude, if the amplitude of the pendulum's oscillations is increased by a factor of 4, this means you're multiplying the square of the quantity by 4. As a result, the energy in the pendulum increases by a factor of 4² which is 16.

So, as the amplitude of the pendulum increases by a factor of 4, the total energy increases by a factor of 16.

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When the amplitude of a swinging pendulum is increased by a factor of 4, the total energy stored in the moving pendulum increases by a factor of 16.

The total energy of a swinging pendulum is given by the sum of its potential energy and kinetic energy, which is proportional to the square of the amplitude.

In this case, when the amplitude is increased by a factor of 4, the total energy increases by a factor of 16.

This is because the total energy is directly proportional to the square of the amplitude, so increasing the amplitude by a factor of 4 results in an increase of the total energy by the square of that factor.

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The term phenotype in a more specific context to describe the collective expression of the genotype in conjunction with the environment on a plant's observable characteristics.

Explanation:

Some of the phenotypic traits includes Height, color, shape.

Phenotype is a physical properties or expression of a gene in an individual.

Phenotype are features that is observable or can be seen. This could include the physical appearance where we have height, color, shape.

Phenotypic traits are the observable features such as plant height and eye color, hair color.

Therefore, some of the phenotypic traits that scientist can investigate are height, shape and color.

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Answer:

0.552 m/s

Explanation:

Given,

Mass of the block = 2.05 Kg

initial compression, x₁ = 0.03690 m

Spring constant, k = 830 N/m

coefficient of friction of the block, μ = 0.380

distance moved by the block,x₂ = 0.20 m

Speed, v  = ?

Using conservation of energy

Initial spring energy + Work done by friction = Final spring energy + kinetic energy

[tex]\dfrac{1}{2}kx_1^2 - \mu mg x_2 = \dfrac{1}{2}kx_2^2 + \dfrac{1}{2}mv^2[/tex]

[tex]\dfrac{1}{2}\times 830\times 0.039^2 - 0.38\times 2.05\times 9.81\times 0.02 = \dfrac{1}{2}\times 830 \times 0.02^2 + \dfrac{1}{2}\times 2.05\times v^2[/tex]

v² = 0.3047

v = 0.552 m/s

Hence, the speed of the block is equal to 0.552 m/s

Final answer:

The distance between adjacent fringes near the center of the interference pattern in a double-slit experiment decreases by the same factor when the distance between the slits is decreased by a factor of 2.

Explanation:

The distance between adjacent fringes near the center of the interference pattern in a double-slit experiment is determined by the wavelength of the light and the distance between the slits. When the distance between the slits is decreased by a factor of 2, the distance between adjacent fringes near the center of the interference pattern also decreases by the same factor. This is because the interference pattern is directly related to the slit separation.

Answer:

[tex]t_{air} - t_{iron} = 282.17 sec[/tex]

Explanation:

The distance covered = 100 km = 100,000 m

The speed of sound in iron, [tex]v_{iron}[/tex] = 5130 m/s

The speed of sound in air at 0° C, [tex]v_{air}[/tex]= 331.5°C

Speed = distance/time

Time = Distance /speed

[tex]t_{iron} = \frac{d_{iron} }{v_{iron} } \\t_{iron} = 100000/5130\\t_{iron} = 19.49 sec[/tex]

[tex]t_{air} = \frac{d_{air} }{v_{air} } \\t_{air} = 100000/331.5\\t_{air} =301.66 sec[/tex]

[tex]t_{air} - t_{iron} = 301.66 - 19.49\\ t_{air} - t_{iron} = 282.17 sec[/tex]

Answer:

option C

Explanation:

Given,

Refractive index of medium 1 = n₁

Refractive index of medium 2 = n₂

For total internal reflection to take place light should move from denser medium to the rarer medium.

Here Total internal reflection take place at the boundary of medium 1 and medium 2 so, the refractive index of medium 1 is more than medium 2

 n₁ > n₂

The correct answer is option C

Answer:

In high jump as well as long jump, instateneous velocity is more important than average velocity.

In relay races and 400m races, average is more important than instateneous velocity.

Explanation:

Instantaneous velocity is the velocity of anything in motion at a specific point in time. This is determined quite similarly to average velocity, however, we look at the period of time so that it approaches zero. If there is a standard velocity over a period of time, its average and instantaneous velocities may be the same. Instantaneous velocity is calculated as the limit as t approaches zero of the change in d over the change in t.

The range or length of long jump depends on the instantenous velocity of the jump and the height of high jump depends on the instantenous velocity of the height.

A person with greater average velocity wins a race. The average velocity of anything or object is referred to as its total displacement divided by the total time taken. That is to say, it is the rate at which an object changes its position from one place to another. Average velocity is also a Vector quantity. Meters per second is the SI unit. Although, any distance unit per any time unit can be used when necessary, such as miles per hour (mph) or kilometer per hour (kmph)

Instantaneous velocity is more important in specific instances like a tennis stroke or a football collision, while average velocity is more important for calculating average rates of change in situations like road trips or rehab.

Instantaneous velocity is more important than average velocity in situations where we need to know the velocity at a specific instant in time. Examples of this include a tennis player's stroke in which they aim to hit the ball on the sweet spot of the racket for maximum velocity and minimal vibration, and in a collision in football where a player with the same velocity but greater mass has a greater impact due to their greater momentum.

On the other hand, average velocity is more important in situations where we need to calculate the average rate of change of position over a given time interval. Examples include calculating the average velocity of a car during a road trip to determine the time taken to reach a destination, and in rehab where the average velocity of a patient's movement is measured to track progress over time.

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