Suppose two parents, a father with the genotype AaBbCcDdee and a mother with the genotype aabbCcDDEe, wanted to have children. Assume each locus follows Mendelian inheritance patterns for dominance. What proportion of the off spring will have each of the following characteristics? Round your answers to two decimal places.

Answers

Answer 1

The fork line method is used to get genotypic and phenotypic proportions. In this case, 0.03 of the progeny have the father's genotype, 0.03 have the mother's genotype, 0.09 looks like the father, 0.09 looks like the mother, and 0.81 are different from both parents.

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Available data:

Five diallelic genes Mendelian inheritance patterns for dominancefather ⇒  AaBbCcDdeemother ⇒  aabbCcDDEe

Cross: Mother x Father

Parentals) aabbCcDDEe x AaBbCcDdee

To avoid making a Punnett square -which whould be very complex-, we will perform crosses separately for each gene, and then multiply their proportions. This is the fork line method, and is useful to get the proportions of the desired genotypes and phenotypes among the progeny.

Gene A:

Parentals) aa   x    Aa

Gametes) a  a     A   a

F1) 1/2 = 50% Aa  

    1/2 = 50% aa

Gene B:

Parentals) bb   x    Bb

Gametes) b  b       B   b

F1) 1/2 = 50% Bb  

    1/2 = 50% bb

Gene C:

Parentals) Cc   x    Cc

Gametes) C   c      C    c

F1) 1/4 = 25% CC  

    1/2 = 50% Cc

    1/4 = 25% cc

Gene D:

Parentals) DD   x    Dd

Gametes) D   D      D    d

F1) 1/2 = 50% DD

    1/2 = 50% Dd

Gene E:

Parentals) Ee   x    ee

Gametes) E   e     e   e

F1) 1/2 = 50% Ee

    1/2 = 50% ee

F1) Genotypes

a. Same genotype as the father ⇒ AaBbCcDdee

1/2 Aa x 1/2 Bb x 1/2 Cc x 1/2 Dd x 1/2 ee = 1/32 = 0.03 AaBbCcDdee

[tex]1/2 Aa x 1/2 Bb x 1/2 Cc x 1/2 Dd x 1/2 ee = 1/32 = 0.03 AaBbCcDdee[/tex]

b. same genotype as the mother ⇒ aabbCcDDEe

1/2 aa x 1/2 bb x 1/2 Cc x 1/2 DD x 1/2 Ee = 1/32 = 0.03 aabbCcDDEe

[tex]1/2 aa x 1/2 bb x 1/2 Cc x 1/2 DD x 1/2 Ee = 1/32 = 0.03 aabbCcDDEe[/tex]

     Phenotypes

c. phenotypically resemble the father  ⇒ A-B-C-D-ee

1/2 A-x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 = 0.09 A-B-C-D-ee

[tex]1/2 A-x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 = 0.09 A-B-C-D-ee[/tex]

d. phenotypically resemble the mother ⇒ aabbC-D-E-

1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 D- = 3/32 = 0.09 aabbC-D-E-

[tex]1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 D- = 3/32 = 0.09 aabbC-D-E-[/tex]

e. phenotypically resemble neither parent 26/32 = 0.81

1/2 A- x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-B-C-D-E-

[tex]1/2 A- x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-B-C-D-E-[/tex]

1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-B-ccD-E-

[tex]1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-B-ccD-E-[/tex]

1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-B-ccD-ee

[tex]1/2 A- x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-B-ccD-ee[/tex]

1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-bbC-D-E-

[tex]1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 E- = 3/32 A-bbC-D-E-[/tex]

1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-bbccD-E-

[tex]1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- = 1/32 A-bbccD-E-[/tex]

1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 A-bbC-D-ee

[tex]1/2 A- x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 A-bbC-D-ee[/tex]

1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-bbccD-ee

[tex]1/2 A- x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 A-bbccD-ee[/tex]

1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 aaB-C-D-E-

[tex]1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 E- = 3/32 aaB-C-D-E-[/tex]

1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 aaB-C-D-ee

[tex]1/2 aa x 1/2 B- x 3/4 C- x 1 D- x 1/2 ee = 3/32 aaB-C-D-ee[/tex]

1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 aaB-ccD-E-

[tex]1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 E- = 1/32 aaB-ccD-E-[/tex]

1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 aaB-ccD-ee

[tex]1/2 aa x 1/2 B- x 1/4 cc x 1 D- x 1/2 ee = 1/32 aaB-ccD-ee[/tex]

1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- =1/32 aabbccD-E-

[tex]1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 E- =1/32 aabbccD-E-[/tex]

1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 aabbC-D-ee

[tex]1/2 aa x 1/2 bb x 3/4 C- x 1 D- x 1/2 ee = 3/32 aabbC-D-ee[/tex]

1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 aabbccD-ee

[tex]1/2 aa x 1/2 bb x 1/4 cc x 1 D- x 1/2 ee = 1/32 aabbccD-ee[/tex]

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Difference between spinal tap and epidural

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Answer:

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Hope it helps!

Chymotrypsin
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b. digests proteins into peptides
c. works in the small intestine
d. all of the above

Answers

Answer: d. all of the above

Explanation:

Chymotrypsin is produced by the Pancreas and has the function of digesting proteins.It consists of three polypeptide chains connected by two inter-chain disulfide bridges. Chymotrypsin exerts an important biological function which is the hydrolysis of proteins in the small intestine. The cleavage of peptide bonds is selective, occurring only on the carboxyl side of aromatic side chains of tyrosine, tryptophan and phenylalanine, and large hydrophobic radicals such as methionine. Chymotrypsin also hydrolyzes ester

True or False. The anterior pituitary gland is connected to the hypothalamus through capillaries that form the hypothalamus pituitary portal vasculature.

Answers

Answer:

True.

Explanation:

The anterior pituitary gland is connected to the hypothalamus through capillaries that form the hypothalamus pituitary portal vasculature.

The apical ends of intestinal cells face the intestinal channel and have long processes that facilitate the absorption of nutrients. What is the name of these processes and what cytoskeletal element forms their internal skeleton?

Answers

Answer:

microvilli, actin filaments

Explanation:

The apical ends of intestinal cells face the intestinal channel and have long processes that facilitate the absorption of nutrients. the name of these processes is microvilli and actin filaments from the cytoskeletal element forms their internal skeleton.

The newly-discovered organism Yawle nhoj, has a diploid chromosome number of 56. Suppose that one of the chromosome pairs fails to disjoin properly during Meiosis I. How many chromosomes will be present in each of the four gametes that result from that meiosis? Assume meiosis II is normal.

Answers

Answer:

The correct answer will be 2 gametes with 29 chromosomes and 2 gametes with 27 chromosomes will be formed.

Explanation:

Meiosis is a type of cell division which produces four daughter cells. Chromosomes separate or the disjunction of chromosomes takes place during anaphase I and anaphase II of meiosis I and II respectively.

If a chromosome fails to disjoin at meiosis I this will result in the production of four gametes with an unequal number of chromosomes. Out of four gametes, 2 gametes produced will be trisomic gametes that are with one additional copy of chromosome and 2 gametes will be monosomic with one less number of chromosome.  It means the trisomic gametes will have 29 chromosomes while 2 monosomic gametes will have 27 chromosomes.

Thus, 2 gametes with 29 chromosomes and 2 gametes with 27 chromosomes will be formed is the correct answer.

3. Mammals lack the enzymes for the net conversion of acetyl-CoA into oxaloacetate or any other citric acid cycle intermediate, but if oxaloacetate (or some other citric acid cycle intermediate) is drawn off for biosynthesis, it must be replenished. How is oxaloacetate replenished? Under what cellular conditions would this enzymatic step be favored?

Answers

Answer:

-Oxaloacetate is replenished by enzyme pyruvate carboxylase.

-This enzymatic reaction is favored when there is an increased demand of energy required by the cell.

Explanation:

Citric acid cycle is a major pathway for the ATP production. Oxaloacetate plays an important role in citric acid cycle as it starts with transfer of acetyl group of acetyl CoA to oxaloacetate with formation of citrate.

As mammals lack enzyme to convert acetyl-CoA into oxaloacetate, in mammals oxaloacetate is replenished by enzyme pyruvate carboxylase that performs carboxylation of pyruvate to form oxaloacetate.

Activity of this enzymatic reaction increases by high energy demand of cell,  and increased level of acetyl CoA as it shows increased demand of oxaloacetate to perform citric acid cycle for energy production.

where would you not find a cholinergic nicotine receptor

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Answer:

All parasympathetic target organs

Final answer:

Cholinergic nicotine receptors, which transmit signals in the nervous system and muscles, are not found in red blood cells, whose function is to carry oxygen and carbon dioxide.

Explanation:

Cholinergic nicotine receptors are found in many areas throughout the body, particularly in the nervous system and muscles where they play a crucial role in transmitting signals. However, you wouldn't find cholinergic nicotine receptors in red blood cells. The function of red blood cells is to transport oxygen from the lungs to the body's tissues and carbon dioxide from the tissues back to the lungs. These cells, unlike neurons or muscle cells, do not have the need for synaptic signal transmission, thus they do not have these specific receptors.

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What are the 3 portions of the brain stem and what do each do?

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Answer: The brain stem is a terminology used to refer collectively to the midbrain, pons, and medulla oblongata.

Explanation:

The midbrain is composed primarily of the optic lobes, which receive and process visual information it is responsible for reflexes involving eyes and ears. Pons is responsible for the reticular activating system and visceral control. The Medulla Oblongata is responsible for the sensory nuclei, reticular activating system, and visceral control.

Which condition involves an uninjured body part experiencing pain as the result of injury to another part of the body?
Select one:
a. sensory adaptation
b. referred pain
c. receptor potential
d. interceptors

Answers

Answer:

Referred pain

Explanation:

Referred pain may be defined as the pain perceived at differnet location of body other than the individual pain location.

Referred pain depends upon the intensity and duration of the pain. Refereed pain is generally generated by the potent mechanism of temporal summation. Referred pain is the condition of the body  in which the uninjured body part experiences pain due to the injury of another body part.

Thus, the correct answer is option (b).

Some digestive products, such as water and electrolytes, will be absorbed by diffusion. They diffuse from an area of ____________ concentration in the intestinal lumen to an area of ____________ concentration in the cell.

Answers

Answer: Higher concentration; Lower concentration.

Explanation: The food that we eat undergoes digestion and breaks down into smaller components.

These small components of the food needs to be absorbed first by the process of diffusion.

The water molecules along with the electrolytes are absorbed from an area of its higher concentration in the lumen is transported to area where its concentration is very low.

Hence, the correct answer is diffusion, which is responsible for the transportation of products from one place (higher concentration) to another parts (lower concentration)in the body.

Final answer:

Digestive products like water and electrolytes are absorbed by diffusion, moving from an area of higher concentration in the intestinal lumen to an area of lower concentration in the cells. This happens both in the context of water and electrolytes and is guided by concentration gradients. The small intestine is the primary site for these absorption processes.

Explanation:

Some digestive products, such as water and electrolytes, will be absorbed by diffusion. They diffuse from an area of higher concentration in the intestinal lumen to an area of lower concentration in the cell. This is a process driven by concentration gradients. The small intestine absorbs most of these substances with the aid of its absorptive cells and specialized structures like the microvilli.

For example, each day, about nine liters of fluid, containing water and electrolytes, enter the small intestine from ingested food, beverages, and GI secretions. About 90% of this water is absorbed in the small intestine, moving from an area of higher concentration in the chyme (the digestive substance in the lumen) to an area of lower concentration in the epithelial cells of the intestine. Similarly, electrolytes dissociate into ions in water and most of them are absorbed via active transport mechanisms throughout the small intestine.

Water movement in the body is facilitated by osmosis, a specialized form of diffusion. Water flows from regions of higher concentration to regions of lower concentration along an osmotic gradient across semi-permeable membranes, helping maintain an appropriate balance of solutes inside and outside of cells to ensure their proper function.

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What is a ductless gland?

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I need the picture for the ductless gland

Superficial region around the renal medulla

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Answer:

Renal cortex

Explanation:

The renal medulla of a kidney is surrounded by renal cortex. The renal cortex is the granulated layer. It is the renal cortex in which the renal corpuscle (glomerulus and Bowman's capsule) are present. The renal cortex is reddish brown in color. This is due to the fact that most of the renal arteries deliver the blood to the cortex.

Indicate whether each of the following reactions is anabolic or catabolic by circling the appropriate word: Reaction Type of Reaction 1. Glucose + glucose → glycogen

Answers

Answer:

The reaction of Glucose + Glucose → Glycogen is called glycogenesis and is an anabolic reaction.

Explanation:  

Metabolic reactions can be anabolic or catabolic. Anabolic reactions are those where small molecules are joined to form a larger molecule; and the use energy. On the other hand, catabolic reactions are those where large molecules are broken in smaller molecules; and they release energy.  

Glucose molecules are smaller than Glycogen. For this reason, the metabolic reaction of Glucose + Glucose → Glycogen is an anabolic reaction called glycogenesis.

glycogenesis  

Two types of metabolic reactions take place in the cell: 'building up' (anabolism) and 'breaking down' (catabolism).

Anabolic reactions use up energy. They are endergonic. In an anabolic reaction small molecules join to make larger ones. For example, the following condensation reactions that occur in cells are anabolic:

5. Discuss about the narrow sense conception of cytoskeleton and the classification and function of each components

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Answer:

The narrow sense conception of cytoskeleton is introduced to protein fibres. These fibres are present inside the eukaryotic cells. This concept refers to the study of cytoskeleton.  Cytoskeleton maintains the cell shape. Cytoskeleton have two components. These are nuclear skeleton and cytoplasmic skeleton.

Nuclear skeleton consist of core layer, nuclear matrix and chromosomal skeleton. Cytoplasmic skeleton comprises of microtubules, microfilaments and intermediate filaments.

Explanation:

The narrow sense conception of cytoskeleton is related to protein fibre structure in eukaryotic cells. The cytoskeleton system comprises of nucleus skeleton and cytoplasmic skeleton.

The nucleus skeleton consist of chromosomal skeleton, nuclear matrix and core layer.

Nuclear Matrix: It organize DNA into the cell with the help of nuclear lamina.

Core layer: It is the inner layer which connects nuclear matrix and outside fibres. It forms a grid structure between nucleus and cytoplasm.

Chromosome Skeleton: It is involved in packaging of chromosomes.

The cytoplasmic filaments consist of intermediate filament, microtubules and microfilaments.

Intermediate Filaments: It provides mechanical support to plasma membrane.

Microtubules: It maintains shape of the cell. It is involved cell wall formation.

Microfilaments: It is involved in myofibrils formation, acrosomal reaction and cytoplamic splitting like processes.

what is melatonin's main function? what are its other functions?

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melatonin is a hormone secreted by the pineal gland and its main function is to regulate sleep rhythm (circadian rhythm)

Melatonin mediates function through, antioxidant action in most of disorders. Melatonin is a chronobiotic substance that acts as synchronizer by stabilizing bodily rhythms. Its synthesis occurs in various locations throughout the body, including the pineal gland, skin, lymphocytes and gastrointestinal tract (GIT)

Sympathetic nervous system vs parasympathetic nervous system

Answers

Answer:

Differences between Sympathetic and Parasympathetic

1. Anatomical: The location of preganglionic neurons of the autonomic ganglia and the extension of preganglionic and postganglionic fibers are different in these two systems;

2. Pharmacological: In the Sympathetic system we have the presence of Cholinergic fibers (Ach) and in the Parasympathetic system we have the presence of Noradrenergic fibers (NE);  

3. Physiological: They act antagonistically, they rarely work harmoniously synergistically in coordinating visceral activity (balance)

The sympathetic nervous system readies the body for action, while the parasympathetic nervous system helps the body relax and recover. Sympathetic and parasympathetic divisions of the autonomic nervous system work in opposition to each other, regulating different bodily functions.

The sympathetic nervous system prepares the body for 'fight or flight,' whereas the parasympathetic nervous system allows the body to 'rest and digest.' Sympathetic neurons release norepinephrine onto target organs; parasympathetic neurons release acetylcholine. Activation of the sympathetic nervous system increases heart rate and blood pressure and decreases digestion and blood flow to the skin. Activation of the parasympathetic nervous system decreases heart rate and blood pressure and increases digestion and blood flow to the skin.

Consider a gene with two alleles that show complete dominance. When a homozygous recessive individual (qq) is crossed with a heterozygous individual (Qq), they have a 50 percent chance of producing a homozygous recessive offspring. The next time these two individuals breed, what are the chances that they will once again have a homozygous recessive progeny?

Answers

Answer:

There will be [tex]50[/tex]% chances of occurrence of a  homozygous recessive progeny

Explanation:

Complete dominance is a situation in which the trait which is considered as dominant overshadow the trait represented by recessive allele.

Hence Q will always over dominate q

Thus, when next time a cross is carried out between homozygous recessive individual (qq) and heterozygous individual (Qq), the following offspring will be produced-

q q

Q Qq Qq

q qq qq

Thus, as we can see out of four offspring , two have homozygous recessive progeny i.e qq

Hence, the chances of occurence of a  homozygous recessive progeny again is equal to

[tex]\frac{2}{4} * 100\\= 50[/tex]%

Explain the possible problems associated with the high diastolic pressure.

Answers

Answer:

High diastolic pressure can leads to kidney damage, vision less and chronic renal failure.

Explanation:

Diastolic pressure may be defined as the blood pressure in the arteries when the heart is completely filled. When the blood pressure is measured the lower value of blood pressure indicates the diastolic blood pressure.

Different problems associated with high diastolic pressure are:

Kidney damage: The high blood pressure can cause the narrow areteies around the kidney and may result in kidney damage.

Vision less: The blood vessel may damage in high diastolic pressure that may hinder the blood flow in the retina and results in vision less.

Chronic renal failure: High diastolic pressure damages the renal artery and causes chronic renal failure in an individual.

Acid chyme produced by the stomach is neutralized in the intestine by what?

Answers

Answer: Sodium bicarbonate produced by the Pancreas.

Explanation:

The mixture of partially digested food and gastric juice is called chyme. Chyme leaves the stomach through the pyloric sphincter to enter the small intestine. This is where all terminal digestion of carbohydrates, lipids, and proteins occurs, and where the products of digestions—amino acids, glucose, and so on—are absorbed into the blood. The first 25 centimeters is the duodenum; the remainder of the small intestine is divided into the jejunum and the ileum. The duodenum receives acidic chyme from the stomach, digestive enzymes, and bicarbonate from the pancreas, and bile from the liver and gallbladder. The pancreatic juice enzymes digest larger food molecules into smaller fragments.

Final answer:

Acid chyme from the stomach is neutralized in the intestine by bicarbonate, which is released by the pancreas. This happens in the duodenum, the first part of the small intestine.

Explanation:

The acid chyme produced by the stomach is neutralized in the intestine by a substance called bicarbonate. Bicarbonate is released by the pancreas and works to neutralize the acidity of the chyme which is essential for the enzymes in the intestine to function properly. This process takes place in the duodenum, the first section of the small intestine, right after the stomach.

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Which of the following vitamins is used to construct the coenzymes NADH and NADPH?
a. Riboflavin
b. Panthothenic acid
c. Vitamin B12
d. Niacin

Answers

Answer: d. Niacin

Explanation:

Many vitamins are parts of coenzymes. In numerous oxidation-reduction reactions that are catalyzed by enzymes, the electrons pass in pairs from the active site of the enzyme to a coenzyme that serves as the electron acceptor. Vitamin B3 or Niacin is used to construct the coenzymes NADH and NADPH, their sources for human ingestion are liver, lean meats, and grains. Its deficiency in consumption leads to Pellagra, inflammation of nerves and mental disorders.

Final answer:

D) Niacin (Vitamin B3) is the vitamin used to construct the coenzymes NADH and NADPH, which are essential for metabolic processes such as energy production.

Explanation:

The vitamin that is used to construct the coenzymes NADH and NADPH is niacin (B3). These coenzymes play a crucial role in various metabolic processes, including energy production and synthesis of fatty acids and steroids. Niacin is therefore essential for the conversion of food into energy and for maintaining healthy cells.

It's important to note that riboflavin (B2) is involved in the formation of another coenzyme, flavin adenine dinucleotide (FAD), which is also used in cellular respiration but is different from NADH and NADPH.

Describe difference between dehydration reaction and hydrolysis. How do these reactions relate to macromolecules?

Answers

Answer:

Dehydration reaction includes removal of water molecule from compounds to facilitate formation of bonds between them while hydrolysis reactions break the compounds by breaking the bonds.

Dehydration reactions form the complex macromolecules while hydrolysis reactions break them down into the simpler elements.

Explanation:

During dehydration reactions, removal of a water molecule from two compounds leads to the formation of a covalent bond between them. These reactions are mainly part of anabolic pathways. Two amino acids are joined together by peptide bond and a water molecule is released during the reaction.

Hydrolysis reactions are the opposite of dehydration reactions and are involved in catabolic pathways of macromolecules. The peptide bonds between amino acids are broken down by hydrolysis.  

Final answer:

Dehydration reactions involve the formation of new bonds, while hydrolysis reactions break bonds and release energy. Each macromolecule is broken down by a specific enzyme.

Explanation:

Dehydration and hydrolysis reactions are catalyzed, or "sped up," by specific enzymes; dehydration reactions involve the formation of new bonds, requiring energy, while hydrolysis reactions break bonds and release energy. These reactions are similar for most macromolecules, but each monomer and polymer reaction is specific for its class. For example, in our bodies, food is hydrolyzed, or broken down, into smaller molecules by catalytic enzymes in the digestive system. This allows for easy absorption of nutrients by cells in the intestine. Each macromolecule is broken down by a specific enzyme. For instance, carbohydrates are broken down by amylase, sucrase, lactase, or maltase. Proteins are broken down by the enzymes pepsin and peptidase and by hydrochloric acid. Lipids are broken down by lipases. The breakdown of these macromolecules provides energy for cellular activities.

Blood returning to the heart from the pulmonary circuit first enters the

Answers

Answer:

Veins

Explanation:

Blood returning to the heart from the pulmonary circuit first enters the veins.

Blood returning from the pulmonary circuit enters the heart at the left atrium.

This is a part of the circulatory system process that helps deliver oxygen-rich blood to the rest of the body.

Blood returning to the heart from the pulmonary circuit first enters the left atrium.

The blood travels from the lungs, where oxygen has just been absorbed and carbon dioxide has been expelled, through the pulmonary veins and into the left atrium.

Ultimately, the oxygen-rich blood will be pumped to the rest of the body.

This process is part of the circulatory system, which delivers nutrients and oxygen to cells and removes waste products.

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Compare sympathetic vs parasympathetic nervous system

Answers

Sympathetic vs. Parasympathetic. Both part of the autonomic nervous system, the sympathetic and parasympathetic nervous systems work involuntarily. Sympathetic is responsible for the response commonly referred to as "fight or flight," while parasympathetic is referred to as "rest and digest."

Which muscle have their insertion on the calcaneus?

Answers

Answer:

Gastrocnemius, plantaris and soleus muscle have insertion on calcaneus.

Explanation:

Calcaneus is also known as heel bone. This is the tarsus bone of the foot and other animals consist it as a point of hook.

Three muscles involved in the insertion of calcaneus are Gastrocnemius muscle, plantaris muscle and soleus muscle. These muscles are present in the posterior compartment of leg and helps in running, jumping and walking.

Briefly differentiate "White Matter" & "Grey Matter".

Answers

Answer:

The CNS, or central nervous system is comprised of neurons, the cell units that form it. These cells, in turn, are formed by their cell bodies, the dendrites on them and the terminal ends of the axons, which are like the connectors, or roadways, for neurons. When viewed on a microscope, brain tissue, particularly, looks stained with two different colors: grey, or pinkisk, for the grey matter, and whiter for the white matter, which are the axons. This is basically why the two are called grey matter and white matter of the CNS.

So one difference between these two matters is the color they display when viewed. The second is the parts of the neuron that form the two; while the white matter is formed from the neuronal axons, the grey matter is formed by the dendrites, cell bodies and axonal terminals. A third differentiation is that most synaptic activity takes place in the grey matter, while most conduction of information from the cell bodies is performed by the axons.

Final answer:

White matter, consisting of myelinated axons, contributes to the CNS's communication network, while gray matter contains neuronal cell bodies and is involved in processing. Their composition difference, particularly the presence of fatty myelin in white matter, makes them distinguishable on MRI images. Brain development continues through adolescence, affecting the gray to white matter ratio.

Explanation:

White matter and gray matter are two distinct types of nervous tissue found in the central nervous system (CNS). Gray matter consists primarily of neuronal cell bodies, dendrites, and non-myelinated axons, which give it a grayish appearance and is primarily involved in processing and cognition. It makes up the outer cortex of the brain. White matter, on the other hand, is made up of myelinated axons that form tracts and facilitate rapid communication between different gray matter areas.

The fatty myelin sheath around the axons gives white matter its characteristic lighter color. This difference can be easily identified in MRI images due to the contrast provided by the fatty tissue and water content. While gray matter is associated with the cortex and processing centers, white matter acts as a network of conduits providing connectivity and communication across different brain regions.

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You are studying a protein called myprotein in the cytosol. You want to see if another protein called, otherprotein, is required for folding. You isolate the cytosolic fraction using salt precipitation. You want to perform an experiment to find if otherprotein binds and interacts with mylittleprotein. Which assay would be best to perform first?
a. SDS PAGE to see the banding pattern showing all the proteins that interact
b. Immunopreciptation, because this will allow us to pull down proteins that interact
c. Size chromatography, because chances are the proteins that interact are the same size
d. Affinity Chromatography, because we know that it binds other proteins

Answers

Answer:

size chromatography, because chance are the protein that interact are the same size

Explain why there would be more errors in dna replication if thymine was sometimes able to form bonds with cytosine. PLEASE HELP

Answers

Answer:

DNA contains four base pairs: adenine, thymine, cytosine and guanine. Adenine forms bond with thymine, its a double bond, and cytosine forms triple bond with guanine.

Cytosine in natural process does not forms bond with thymine, but if it happen then many errors could occur in replication. As DNA is the basic material of cell and all genetic information lies in it, a single mutation can lead to fatal disorders, and when cytosine forms bond with thymine instead of guanine then the backbone of DNA would be distorted, RNA being formed from this DNA would also be have errors that would result in mutated proteins  that can cause serious illness and destroy many natural processes.

Bacteria are grown in 15N (heavy) medium and then transferred to 14N (light) medium and are allowed to replicate for 1 generation. The DNA is subsequently isolated and centrifuged in a CsCl2 gradient to yield what type of gradient band(s)?

Answers

Answer:

The intermediate density band is observed.

Explanation:

Messelson and Sthal's explained the model of  semi conservative nature of DNA replication. According to this model, the newly synthesized DNA molecule contains one newly synthesized strand and one parental strand.

Firstly, bacteria grown in 15N media is transferred to 14N media. The isolated DNA is centrifuged and intermediate density DNA  band is observed that contains one strand of 15N (parental strand) and one strand of 14N (newly synthesized strand).

Final answer:

Bacteria grown in a 15N medium and then transferred to a 14N medium for one generation produce DNA that, when centrifuged in a CsCl2 gradient, forms a band at an intermediate position between DNA formed in 15N and 14N. This supports the semi-conservative replication model of DNA.

Explanation:

The experiment you're referring to was conducted by Matthew Meselson and Franklin Stahl. They used E. coli and grew it initially in a heavy nitrogen medium (15N). Afterward, these bacteria were transferred into a 14N (lighter nitrogen) medium where they were grown for one generation.

During the replication in the 14N medium, DNA from the bacteria was isolated and centrifuged in a cesium chloride (CsCl2) gradient. The result was, that a single band was observed which settled at an intermediate position between DNA formed in 15N and 14N. This finding supports a semi-conservative replication model where each new DNA molecule consists of one old and one new strand.

Learn more about Semi-conservative replication here:

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Where is the first electrical wave in the heart initiated?

Answers

Answer:

Sinoatrial Node

Explanation:

The sinoatrial node is like the natural pacemaker of the heart because it controls the heart beat or in other words, the cardiac rhythm. The sinoatrial node is found on the right atrium and it sends signals to both atria and then they contract. The signal is then carried to the atrioventricular node which spreads the signal to the ventricles and then the ventricles contract. The contractionof the ventricle is the pumping action of the heart.

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