Suppose you want to transform the graph of the function y=tan(x+pi/4)-1 into the graph of the function y=-tan(x+pi/2)+1
Answers
In the given equation
+1 will shift the function upward by 1 unit
minus(-) sign will reflect the graph across x_axis
see the attached diagram of -tan(x+π/2) +1
Answer:
A) Reflect the graph of the first function across the x-axis, translate it pi/4 units to the left, and translate it 2 units up
Related Questions
hey can you please help me posted picture of question
Answers
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b =coefficient of x term = -1
a = coefficient of squared term = 4
c = constant term = 9
Using the values in the above formula we get:
[tex]x= \frac{1+- \sqrt{1-4(4)(9)} }{2(4)} \\ \\ x= \frac{1+- \sqrt{-143} }{8} \\ \\ x= \frac{1+-i \sqrt{143} }{8} [/tex]
So, option D gives the correct answers
What does point A represent in this box plot?
A. first quartile
B. third quartile
C. the smallest value
D. the largest value
*Don't troll on these answers.
Answers
answer
C. the smallest value
Answer:
point A that is the first point represents the smallest value
Step-by-step explanation:
find point A represent in this box plot
first point is the smallest value of all the data
last point is the largest value of all the data
second point is the first quartile
Middle point is the second quartile
fourth point is the third quartile
So point A that is the first point represents the smallest value
You have a 45-gallon jug and a 124-gallon jug. neither of the jugs has any markings (although you do know their capacities). describe a way to measure exactly one gallon of water.
Answers
Amount of water = 124 x 4 = 496 gallons
Then use the 45-gallon jug to scoop out the water 11 times.
Amount of water scooped out = 11 x 45 = 455 gallons
Water remaining = 496 - 450 = 1 gallon.
11*45 = 495
Fill the 124-gallon jug 4 times, emptying it each time into the 45-gallon jug. After the 45-gallon jug has been filled 11 times, there will be 1 gallon remaining in the 124-gallon jug.
_____
Mathematically, this works fine. In practice, you're looking for a 1-gallon difference after handling 495 gallons of water. That's about 0.2% of the total amount of water transferred. Any error along the way will substantially affect the outcome.
Determine whether the two figures are similar. If so, give the similarity ratio of the smaller figure to the larger figure. The figures are not drawn to scale
A. yes; 1:1:2
B. yes; 1:1:4
C. yes; 1:2:4
D. no
Answers
smaller figure
ha=8.7
ra=1.6
larger figure
hb=10.44
rb=1.92
ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83
ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members
[1.6/1.6]/[1.92/1.6]-------> 1/1.2
the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and the ratio smaller figure to the larger figure is equal to----> 1/1.2
the answer is
the option
yes 1/1.2
sq root of x +11 =15
Answers
You can solve for x by subtracting 11 from 15 to get 4. Once you've got 4, you can power 4 by 2 (4²) to get 16 as your answer
x=16
So the value of x is 16
I hope this helps!
I take it you want to find x.
Square both sides.
(sqrt(x + 11))^2 = (15)^2
x + 11 = 225 Subtract 11 from both sides.
x = 225 - 11
x = 214
Edit
This answer is edited to reflect which interpretation is correct. If you give out Brainlys (and you should) give it to Brick123. We all need them.
Sqrt(x) + 11 = 15 Subtract 11 from both sides.
sqrt(x) = 15 - 11
sqrt(x) = 4 Square both sides.
(sqrt(x)^2 = 4^2
x = 16
Find the area of the figure
Answers
The parallelogram, you can just do base * height. The base is 11 yards, and the height is 4 yards. 11 * 4 = 44 square yards.
Now for the trapezoid. If you split it up into a rectangle and a triangle, it becomes much more easier to solve. The rectangle and triangles can be made by splitting the figure down the center. This makes a rectangle with a length of 7 yards and a height of 8, and a triangle with a base of 7 yards and a height of 8 as well.
Solve for the area of both shapes.
The rectangle: Multiply length * height: 7 * 8 = 56 square yards
The triangle: Multiply base * height, and then divide by 2: 7 * 8 = 56
56 / 2 = 28 square yards
Now add the areas together.
28 + 56 + 44 = 128 square yards
Hope this helped!
1. Find area of the trapezium.
2. Find area of the parallelogram.
3. Add the 2 areas together.
Step 1: Find the area of the trapezium:
Formula : area = 1/2 (a + b) h
Area = 1/2(7 + 14) (8) = 84 yd²
Step 2: Find the area of the parallelogram:
Formula : area = base x height
Area = 11 x 4 = 44 yd²
Step 3: Find the total area:
Total Area = 84 + 44 = 128 yd²
Answer: 128 yd²
What fuction respersents a slope of -4 and yintrersection -2?
Answers
y = -4x -2
How would you solve:
|*| 2x + 7 = 3 |*|
????
Answers
2x = 3 - 7
2x = -5
x = -5/2
the answer to this is going to be
we do this math
2x + 7 = 3
and then
2x = 3 - 7
then
2x = -5
and we get
x = -5/2
hope l helped
have a good day
average of 1.99 3.29 2.45
Answers
[tex]1.99 + 3.29 + 2.45 = 7.73 \\ 7.73 \div 3 = 2.58[/tex]
Hope this helps! :)
derivative, by first principle
[tex] \tan( \sqrt{x } ) [/tex]
Answers
Employ a standard trick used in proving the chain rule:
[tex]\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h[/tex]
The limit of a product is the product of limits, i.e. we can write
[tex]\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)[/tex]
The rightmost limit is an exercise in differentiating [tex]\sqrt x[/tex] using the definition, which you probably already know is [tex]\dfrac1{2\sqrt x}[/tex].
For the leftmost limit, we make a substitution [tex]y=\sqrt x[/tex]. Now, if we make a slight change to [tex]x[/tex] by adding a small number [tex]h[/tex], this propagates a similar small change in [tex]y[/tex] that we'll call [tex]h'[/tex], so that we can set [tex]y+h'=\sqrt{x+h}[/tex]. Then as [tex]h\to0[/tex], we see that it's also the case that [tex]h'\to0[/tex] (since we fix [tex]y=\sqrt x[/tex]). So we can write the remaining limit as
[tex]\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}[/tex]
which in turn is the derivative of [tex]\tan y[/tex], another limit you probably already know how to compute. We'd end up with [tex]\sec^2y[/tex], or [tex]\sec^2\sqrt x[/tex].
So we find that
[tex]\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}[/tex]
find the volume of the cylinder in terms of pi h=11 r=3.4
Answers
=3.142 * (3.4*3.4) * 11
=3.142 * 11.56 * 11
=36.32152 * 11
=399.53672
V=399.54
Hope this helps
11.56 * 11 = 127.16
The answer is 127.6(Pi)m^3
Hope this helps
Jordana is putting a fence around a garden that is shaped like a half circle and a rectangle.How much fencing will Jordana need? Use 22/7 for pi
64 ft
86 ft
92 ft
114 ft
Answers
28 ft + 14 ft + 28 ft = 70 feet for the straight sides.
To find the distance around the circular side, you will need to find half of the circumference of the circle.
1/2 x pi x d
1/2 x 22/7 x 14 = 22 feet
70 feet + 22 feet = 92 feet
Jordana will need 92 feet of fencing to enclose this space.
Answer:
awnser c on edge 2020
Step-by-step explanation:
92
A half cylinder lies on its side. What is the exact volume of the half cylinder?
150 π in3
300 π in3
450 π in3
600 π in3
Answers
pi*r²*h
pi*r²*h/2
r=10/2-----> r=5 in
h=12 in
=pi*5²*12/2----> 150*pi in³
so finally the correct answer would be the first option
150*pi in3
The required exact volume of the half cylinder is 150 π in³. Option A is correct.
To calculate the volume of a half cylinder, we need to find the volume of a full cylinder and then divide it by 2.
The formula for the volume of a cylinder is given by:
Volume = π * r² * h
where π is a constant approximately equal to 3.14159, r is the radius of the cylinder, and h is the height or length of the cylinder.
Given that the diameter of the cylinder is 10 inches, we can find the radius by dividing the diameter by 2:
Radius (r) = 10 in / 2 = 5 in
The height or length of the cylinder is given as 12 inches.
Now we can calculate the volume of the full cylinder:
Volume = π * (5 in)² * 12 in = 300 π in^3
Finally, to find the volume of the half cylinder, we divide the volume of the full cylinder by 2:
Volume of Half Cylinder = (300 π in³) / 2 = 150 π in³
Therefore, the exact volume of the half cylinder is 150 π in³.
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Which calculation will always give a result greater than 1
Answers
Answer:
the answer is 1 3/4 - less than 3/4
Step-by-step explanation:
ik bc i used ttm and got this answer and it was correct
A rectangular storage area is to be constructed along the side of a tall building. a security fence is required along the remaining 3 sides of the area. what is the maximum area that can be enclosed with 800 m of fencing? (a = lw)
Answers
A = lw = l(800 -l)/2
This is the equation of a downward-opening parabola with zeros at l=0 and l=800. The zeros are symmetrical about the axis of symmetry of the parabola, which axis goes through the vertex. That is, the vertex is located at
l = (0 +800)/2 = 400
The maximum aea that can be enclosed is 400 m long by 200 m wide, so is
(400 m)×(200 m) = 80,000 m²
To find the maximum area enclosed with 800 m of fencing, the dimensions of the rectangular storage area need to be determined. The perimeter equation is derived to eliminate a variable, allowing the area to be expressed in terms of the remaining variable. Using this approach, the dimensions that maximize the area can be found.
Explanation:To find the maximum area that can be enclosed with 800 m of fencing, we need to determine the dimensions that will result in the largest possible area. Let's assume the length of the rectangular storage area is L and the width is W.
Since there are 3 sides already covered by the security fence, the perimeter of the rectangular storage area will be: 2L + W = 800 m.
To find the maximum area, we need to eliminate one variable from the equation above. We can do this by expressing W in terms of L and substituting it back into the area formula A = LW.
By applying this approach, we can find the dimensions of the rectangular storage area that will enclose the maximum area with 800 m of fencing.
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Then find the area bounded by the two graphs of y=2x^2−24x+42 and y=7x−2x^2
Answers
[tex] \int\limits^a_b {(f(x)-g(x))} \, dx [/tex]
If you think about it, we are really doing this with all integration, only the second function is just y=0.
First, we need to figure out which function is on top. In this case we know that [tex]2x^2-24x+42[/tex] is a positive parabola while [tex]7x-2x^2[/tex] is negative, so the negative parabola will be on top. It is always a good idea to draw a rough sketch of the graphs because the curves could intercept multiple times, flipping which graph is on top at different intervals.
Next, we need to determine the bounds. These will be where the two graphs intercept, so we can just set them equal to each other and solve for x:
[tex]2x^2-24x+42=7x-2x^2[/tex]
Combine like terms:
[tex]4x^2-31x+42[/tex]
Now factor and find the zeros. We can use the quadratic formula:
[tex] \frac{31+ \sqrt{31^2-4(4)(42)} }{8} [/tex]
and
[tex] \frac{31- \sqrt{31^2-4(4)(42)} }{8} [/tex]
x = 1.75 and 6
[tex] \int\limits^6_{1.75} {((7x-2x^2)-(2x^2-24x+42))} \, dx [/tex]
[tex] \int\limits^6_{1.75} {(-4x^2+31x-42)} \, dx [/tex]
Solve:
[tex] \frac{-4x^3}{3} + \frac{31x^2}{2} - 42x [/tex]
Plug in bounds:
[tex]\frac{-4(6)^3}{3} + \frac{31(6)^2}{2} - 42(6)-(\frac{-4(1.75)^3}{3} + \frac{31(1.75)^2}{2} - 42(1.75))[/tex] = 51.17708
Noa was paid a 25 percent commission for selling a used car.
Percents
Total
100%
If she was paid $1,631.24, what was the selling price of the car?
Answers
.25*4 is equal to 100 percent
Substitute
1631.24*4=x
x=6524.96
Answer:
$6,524.96 Is Your Answer :3
This graph shows how much Marie earns babysitting compared with the number of hours she works select the correct statement about the graph
Answers
The graph reflects that she is getting paid 10 dollars an hour
If you plot the points, you will see she makes 5 dollars every half hour
Answer:
Option D is the answer.
Step-by-step explanation:
This graph represents a linear function representing earnings of Marie at y axis and hours of working at x axis. To get the change in Marie's earnings for every 5 hours we will find the slope of the given line.
Slope of the line will define the rate of change in earning of Marie with respect to the time.
End points of the line at time t = 0 and t = 5 hours are (0, 0) and (5, 50).
Therefore slope = [tex]\frac{y-y'}{x-x'}=\frac{50-0}{5-0}=\frac{50}{5}=10[/tex]
So for each hour she works her earnings go up by $10.
Option D is the correct option.
Joe and jill set sail from the same point, with joe sailing in the direction s4 degrees e and jill sailing in the direction s9 degrees w. after 4 hr, jill was 2 miles due west of joe. how far had jill sailed?
Answers
Jill's distance = (distance to Joe)*(sin(86°)/sin(13°))
Jill's distance = (2 mi)*0.99756/0.22495
Jill's distance = 8.869 mi
Jill had sailed 8.9 miles in 4 hours.
Oil-rich countries in the middle east cover about 4% of earth’s total land area but possess about 48% of the world’s known oil reserves. what is the main reason for the high concentration of reserves in this part of the world?
Answers
Geological processes are things such as erosion, tectonic plate shifts, e.t.c.
Determine whether quantities vary directly or inversely and find the constant of variation.
It takes four identical water pumps 6 hours to fill a pool. How long would it take three of these same pumps to fill the pool, assuming they all pump at the same rate?
Answers
Time taken by 1 pump will be:
4×6=24 hours
fraction of pool filled by a single pump in 1 hour will be:
1/24
To calculate how long it would take 3 pumps to fill the pool we proceed as follows:
Fraction of pool filled with water in 1 hour is:
3×1/24
=1/8
thus the time taken to fill the pool by 3 pumps is:
8/1=8 hours
Suppose a city has 810 high-rise buildings, and 29 of these buildings have rooftop gardens. Find the percentage of high-rise buildings with rooftop gardens in this city. Round your answer to the nearest tenth of a percent.
Answers
810 ---------> 100%
29 -----------> x
From here, we clear the value of x.
We have then:
x = (29/810) * (100)
x = 3.580246914%
Round to the nearest tenth of a percent:
x = 3.6%
Answer:
The percentage of high-rise buildings with rooftop gardens in this city is:
x = 3.6%
To find the percentage of high-rise buildings with rooftop gardens, divide the number of buildings with gardens (29) by the total number of buildings (810), and then multiply by 100. Round the final result to the nearest tenth, which is approximately 3.6%.
To calculate the percentage of high-rise buildings with rooftop gardens, we use the formula:
Percentage = (Part / Whole) imes 100
Where the Part is the number of buildings with rooftop gardens, and the Whole is the total number of high-rise buildings.
Substituting the given values:
Percentage = (29 / 810) times 100
Carrying out the division first gives us:
Percentage ≈ 0.035802469 times 100
Finally, multiplying by 100 to find the percentage, we get:
Percentage ≈ 3.58
After rounding to the nearest tenth of a percent, we obtain:
Percentage ≈ 3.6%
3.6% of the high-rise buildings in the city have rooftop gardens.
Find the derivative of f(x) = (1 + 5x2)(x − x2) in two ways. use the product rule. f '(x) = perform the multiplication first. f '(x) = do your answers agree? yes no
Answers
Answer:
The answers agree.
[tex]f^{\prime}(x) = - 20x^{3} + 15x^{2} - 2x + 1[/tex]
Step-by-step explanation:
The product rule is:
[tex]f(x) = g(x)h(x)[/tex]
[tex]f^{\prime}(x) = g^{\prime}(x)h(x) + g(x)h^{\prime}(x)[/tex]
In this problem, we have that:
[tex]f(x) = (1 + 5x^{2})(x - x^{2})[/tex]
So
[tex]g(x) = 1 + 5x^{2}[/tex]
[tex]g^{\prime}(x) = 10x[/tex]
[tex]h(x) = x - x^{2}[/tex]
[tex]h^{\prime}(x) = 1 - 2x[/tex].
[tex]f^{\prime}(x) = g^{\prime}(x)h(x) + g(x)h^{\prime}(x)[/tex]
[tex]f^{\prime}(x) = (10x)*(x - x^{2}) + (1 + 5x^{2})(1-2x)[/tex]
[tex]f^{\prime}(x) = 10x^{2} - 10x^{3} + 1 - 2x + 5x^{2} - 10x^{3}[/tex]
[tex]f^{\prime}(x) = - 20x^{3} + 15x^{2} - 2x + 1[/tex]
Multiplication first:
[tex]f(x) = (1 + 5x^{2})(x - x^{2})[/tex]
[tex]f(x) = x - x^{2} + 5x^{3} - 5x^{4}[/tex]
[tex]f(x) = -5x^{4} + 5x^{3} - x^{2} + x[/tex]
[tex]f^{\prime}(x) = -20x^{3} + 15x^{2} - 2x + 1[/tex]
Comparing the results, we can see that the derivatives obtained using the two methods are indeed the same. The answer is yes.
What's the function about?The derivative of f(x) = (1 + 5x2)(x − x2) can be found using the product rule and by performing the multiplication first.
Using the product rule:
The product rule states that the derivative of f(x)g(x) is f′(x)g(x)+f(x)g′(x).
In this case, f(x) = 1 + 5x2 and g(x) = x − x2. So the derivative of f(x)g(x) is:
f′(x)g(x)+f(x)g′(x)
=(10x+10x3)(x−x2)+(1+5x2)(2x−2x3)
=10x2−10x3+10x3−10x4+2x−2x3+1+10x2−10x3
=−10x4+12x2+2x
Performing the multiplication first:
We can first multiply out the expression (1 + 5x2)(x − x2) to get:
x2−5x4+x3−5x3+x−x2
=−5x4+12x2+x
Then, we can take the derivative of this expression to get the same derivative as we found using the product rule:
f′(x)=−10x4+12x2+2x
Therefore, the derivative of f(x) = (1 + 5x2)(x − x2) is -10x4+12x2+2x, regardless of whether we use the product rule or perform the multiplication first.
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Annette is stacking boxes in her closet. There are 15 boxes in all. If each box weighs 7.5 pounds, his much do the boxes weigh together
Answers
15*7.5
Multiply:
112.5
15 boxes weight 112.5 pounds
hey can you please help me posted picture of question
Answers
y² = 4 - [tex] \frac{4x^2}{25} [/tex]
Explanation:
The given expression is:
4x² + 25y² = 100
We need to isolate the y².
This can be done as follows:
4x² + 25y² - 4x² = 100 - 4x²
25y² = 100 - 4x²
[tex] \frac{25y^2}{25} = \frac{100-4x^2}{25} [/tex]
y² = [tex] \frac{x100-4x^2}{25} [/tex]
y² = [tex] \frac{100}{25} - \frac{4x^2}{25} [/tex]
y² = 4 - [tex] \frac{4x^2}{25} [/tex]
Hope this helps :)
a proton moves in an electric field such that its acceleration a is a=-20(1+2t)^-2, where t is the time in seconds. Find the velocity as a function of time if v sub zero =30 when t=0
Answers
a = -20/(1+2t)^2
v = (1/2)*20/(1+2t) + k = 10/(1+2t) + k
At t = 0:
v0 = 10/1 + k = 30
Therefore, k = 20, and the expression for v(t) is
v(t) = 10/(1+2t) + 20
How many lines of symmetry does a regular polygon with 32 sides have
Answers
A regular polygon with 32 sides has 16 lines of symmetry.
What is Polygon?A polygon is a plane figure made up of line segments connected to form a closed polygonal chain.
We need to find the number of lines of symmetry does a regular polygon with 32 sides have.
The imaginary line or axis along which you can fold a figure to obtain the symmetrical halves is called the line of symmetry
A regular polygon with 32 sides has 16 lines of symmetry.
This is because each side is equal in length and angles, creating a mirrored effect when each side is divided in half.
Hence, a regular polygon with 32 sides has 16 lines of symmetry.
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the angle of elevation of an object from a point 200 meters above a lake is 30 degrees and the angle of depression of it's image in the lake is 45 degrees. Find the height of the object above the lake.
Answers
Looking at the reflection of the object in the lake's surface is equivalent to observing the object at distance h below the lake's surface, or observing it from 200 m below the lake's surface. Considering the latter case, we have
(h+200)/d = tan(45°)
(h -200)/d = tan(30°)
Solving these for d and equating the results gives
(h+200)/tan(45°) = (h -200)/tan(30°)
Solving for h, we get
h(1/tan(30°) -1/tan(45°)) = 200(1/tan(45°) +1/tan(30°))
h = 200(tan(45°) +tan(30°))/(tan(45°) -tan(30°))
h ≈ 746.41
The object is about 746.4 meters above the lake.
Evaluate 10m + n2/4 when m = 5 and n = 4
Answers
Answer:
[tex]54[/tex]
Step-by-step explanation:
we have
[tex]10m+\frac{n^{2}}{4}[/tex]
For [tex]m=5.n=4[/tex]
substitute the values of m and the value of n in the equation
so
[tex]10(5)+\frac{4^{2}}{4}[/tex]
[tex]50+4[/tex]
[tex]54[/tex]
Answer:54
Step-by-step explanation:
hey can you please help me posted picture of question
Answers
[tex]x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a} [/tex]
b =coefficient of x term = -2
a = coefficient of squared term = 1
c = constant term = 10
Using the values in the above formula we get:
[tex]x= \frac{2+- \sqrt{4-4(1)(10)} }{2(1)} \\ \\ x= \frac{2+- \sqrt{-36} }{2} \\ \\ x= \frac{2+-6i}{2} \\ \\ x=1+3i, x=1-3i [/tex]
So the correct answer to this question is option A