the angle measures are represented by algebraic expressions. determine the values of x y and z

The polynomial function of least degree with zeros -3, -2, and 4 is f(x) = (x+3)×(x+2)×(x-4), which is a cubic polynomial.

The polynomial function of least degree with given zeros of -3, -2, and 4 is derived from the fact that if a polynomial has zeros at x=a, x=b, and x=c, then it can be represented as f(x) = k×(x-a)×(x-b)×(x-c), where k is any non-zero constant. Given the zeros -3, -2, and 4, the polynomial function is:

f(x) = k×(x+3)×(x+2)×(x-4)

Because the question does not specify a leading coefficient, we can assume k=1 for the least degree polynomial. Thus, the final form of the polynomial would be:

f(x) = (x+3)×(x+2)×(x-4)

Expanding this would give us a cubic polynomial, which is the polynomial of least degree that satisfies the condition of having exactly these three zeros.

Answer:Sheila

Step-by-step explanation:

Answer:

7x/2

Step-by-step explanation:

7x=2y

1) Divide both sides by 2:

y=7x/2

Vertical angles are the same,

Set the two equations to equal each other to solve for x:

5x-7 = 8x-55

Subtract 5x from both sides:

-7 = 3x -55

Add 55 to both sides:

3x = 48

Divide both sides by 3:

x = 48 /3

x = 16

Now you have a value for x, solve angle D:

8x -55 = 8(16) - 55 = 128 - 55 = 73 degrees.

Answer:

The answer is m∠D is 73.

Step-by-step explanation:

In order to determine the answer, we have to know about vertical angles.

Vertical Angles are the angles opposite each other when two lines cross. These angles share the same vertex. I have attached an image that shows vertical angles.

So, according to the definition:

m∠C=m∠D

m∠C=5x-7

m∠D=8x-55

[tex]5x-7=8x-55\\5x-8x=-55+7\\-3x=-48\\x=\frac{-48}{-3}\\ \\x=16[/tex]

m∠D=8*16-55=73

Finally, the angle m∠D is 73.

Answer:

19.125

Step-by-step explanation:

multiply 15.5 by 3 and then divide the answer by 4

Final answer:

To find the distance Adrian's paper airplane traveled, convert Yanni's distance to an improper fraction, calculate 3/4 of that, and then convert back to a mixed number. Adrian's paper airplane flew 11 5/8 feet.

Explanation:

The question asks us to calculate the distance Adrian's paper airplane traveled, given that it is 3/4 of the distance Yanni's airplane traveled, which was 15 1/2 feet. First, we need to convert Yanni's distance to an improper fraction. This gives us 31/2 feet. To find 3/4 of this distance, we multiply 31/2 feet by 3/4:

(31/2) × (3/4) = (31 × 3) / (2 × 4) = 93/8 feet.

Now, we convert the improper fraction back to a mixed number to find the distance. This gives us 11 5/8 feet (since 93 divided by 8 is 11 with a remainder of 5).

Therefore, Adrian's paper airplane traveled a distance of 11 5/8 feet.

Answer:

frist add 3 plus 2 then multiply it by 21 and then you will get 105 and 105 will represent d

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• cot x = [tex]\frac{cosx}{sinx}[/tex]

• sec x = [tex]\frac{1}{cosx}[/tex] and cosec x = [tex]\frac{1}{sinx}[/tex]

Consider the left side

[tex]\frac{cotx}{secx}[/tex]

= [tex]\frac{cosx}{sinx}[/tex] × cosx

= [tex]\frac{cos^2x}{sinx}[/tex]

= [tex]\frac{1-sin^2x}{sinx}[/tex]

= [tex]\frac{1}{sinx}[/tex] - [tex]\frac{sin^2x}{sinx}[/tex]

= cosec x - sin x

= right side ⇒ verified

Answer:

The cost of a ribeye steak dinner is $18.68 and the cost of a grilled salmon dinner is $9.00

Step-by-step explanation:

Let

x ----> the cost of a ribeye steak dinner

y ----> the cost of a grilled salmon​ dinner

we know that

10x+45y=591.99 -----> equation A

24x+15y=583.39 ----> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (18.68,9.00)

see the attached figure

therefore

The cost of a ribeye steak dinner is $18.68 and the cost of a grilled salmon dinner is $9.00

George would weigh

65 kg × 1.6N /kg = 104 Newtons

That's compared to around 650 Newtons on earth.

Answer: Weight of George on Moon =104 N

Step-by-step explanation:

Given : George has a mass of 65 kg.

The gravitational field strength on the Moon is 1.6N/kg.

Then, the weight of George on Moon = George's Mass x Gravitational field strength

=[tex]65\times1.6=104\text{ Newtons}[/tex]

Hence, the weight of George on Moon =104 N

Answer:

20 weeks.

Step-by-step explanation:

So, he has $500 in savings and he's taking out $25 each week. That would be $25 x ?. Which is the same as 500 divided by 25 which equals 20. I hope this helps!

Keith can withdraw $25 each week from his $500 savings account for 20 weeks.

Keith starts with $500 in his savings account and withdraws $25 every week. To determine how many weeks he can continue these withdrawals, we need to divide his initial amount by the weekly withdrawal amount.

Let's perform the calculation step by step:

So, Keith can withdraw money from his account for 20 weeks.

The value of the function f(x) = -5x when x = 0 is 0. This point also represents the y-intercept of a declining straight line graph.

To find the value of the function f(x) when x equals 0, we simply substitute 0 for x in the given function. The function provided is f(x) = -5x, which implies a linear relationship between y and x. Therefore:

f(0) = -5(0) = 0

The value of f(x) at x = 0 is 0, which also represents the y-intercept of the graph. Since the coefficient of x is negative, we know the graph is a declining straight line. However, at the point where x = 0, the graph will intersect the y-axis.

Answer:

first one. Since its X crosses or passes (2,0)

Step-by-step explanation:

The value of function represents with same domain f(x)= g(x) is f(2) = g(2) and f(0) = g(0).

We know that two functions f and g are said to be equal if:

(i) f and g have same domain D

(ii) for all x ∈ D, f(x) = g(x)

Thus, we must select the response that best captures the situation where f(x) = g. (x)

Considering the fact that f(x) and g(x) are defined on the same domain

If they are equivalent for all values of x in the domain, then f(x) = g(x).

Thus, f(2) = g(2) and f(0) = g(0)

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Answer:

A

Step-by-step explanation:

Answer:

Option 1

Step-by-step explanation:

Given : Function f of x equals 4 times one third to the 2 times x power.

To find : Rewrite the function using properties of exponents ?

Solution :

Writing the function in numeric terms,

f of x equals 4 times one third to the 2 times x power

i.e. [tex]f(x)=4\times (\frac{1}{3})^{2x}[/tex]

Solve the expression,

[tex]f(x)=4\times (\frac{1}{3}^2)^{x}[/tex]

[tex]f(x)=4\times (\frac{1}{9})^{x}[/tex]

i.e. f of x equals 4 times one ninth to the x power.

Therefore, Option 1 is correct.

Answer: YEP

Step-by-step explanation: -8 makes it -24=16-40, which is -24

I HOPE THIS HELPS. HAVE THE MOST AMAZING WEEKEND EVER CHILD

༼ つ ◕_◕ ༽つ

Answer:7

Step-by-step explanation:

Ten Thousands Thousands Tens

3                                5                   7

Answer:

7

Step-by-step explanation:

The ones place always starts on the left then it works it way up.

ones, Tens, hundreds, thousands, ten thousands and it goes on in the same ones tens hundreds pattern

Answer:

The house increases by $23,580 and he current value of the house is $285,580

Step-by-step explanation:

A house on the market was valued at $262,000. After several years, the value increased by 9%.

The first part of the question is to find by how much the house's value increase in dollars, to calculate this, we will simply find;

9% of $262,000

= [tex]\frac{9}{100}[/tex]   × $262 000

= [tex]\frac{2358000}{100}[/tex]

=$23580

Therefore, the house's value increase by $23580

The second part of the question is to fin the current value of the house. Hence;

Current value of the house = $262,000 + $23580=$285,589

Therefore the current value of the house is $285,589

Answer:

The answer is 1/2

Step-by-step explanation:

If you look at the distance between P and R and the dilation between P' and R' you would get 4 and 2. This the scale dilation is 1/2. Multiply 1/2 by 4 and you would get 2.

Answer:

1/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

because the two line segments are the same length-->

12+10-x=18

x=22-18=4

The question aims to determine the value of x for two congruent line segments, typically involving algebraic and geometric methods; however, no specific solution can be provided without the diagram.

The question involves finding the value of x when given two congruent line segments in a diagram. This typically requires the use of algebraic methods or the application of geometric theorems to establish relationships between the lengths represented in the diagram and solve for x.

Without the specific diagram, we cannot provide the direct steps to solve for x.

However, the context suggests the use of equations to calculate lengths. Common strategies include setting equations equal to each other when line segments are congruent and simplifying to find x.

The mention of bisectors and lines intersecting at right angles can also imply the use of properties related to parallel and perpendicular lines or the Pythagorean theorem.

Remember, when equations have two solutions for x, it's necessary to consider which solution is consistent with the geometric context of the problem.

Answer:

C

Step-by-step explanation:

Given

2r + (t + r) ← distribute parenthesis by 1

= 2r + t + r ← collect like terms

= 3r + t

Which is not represented by the given options → C

Answer:

Mathew invested $600 and $2400 in each account.

Solution:

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest [tex](I_1)[/tex] earned in first account for one year,

[tex]\text {simple interest}=\frac{\text {pnr}}{100}[/tex]

Where  

p = amount invested in first account

n = number of years  

r = rate of interest

hence, by using above equation we get [tex](I_1)[/tex] as,  

[tex]I_{1}=\frac{P \times 1 \times 3}{100}[/tex] ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest [tex](I_2)[/tex] earned in second account,

[tex]I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2[/tex]

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

[tex]I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3[/tex]

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

[tex]I = I_1+ I_2 ---- eqn 4[/tex]

By substituting eqn 1 , 2, 3 in eqn 4

[tex]\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}[/tex]

[tex]\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}[/tex]

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400  

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600  

Hence, Mathew invested $600 and $2400 in each account.

Answer:$1,199

Step-by-step explanation:

$1,199 X 5.25%=$1,261.95

Answer:

@misterking_59 i 2,000 no prb

Step-by-step explanation:

Answer:

2y^2. 8/4 = 2 and y^7/y^5 is y^2 i don't know if this is what you completely asked for but here is the answer

Step-by-step explanation:

Division of the given polynomial [tex]8y^{7}[/tex]  ÷ [tex]4y^{5}[/tex]is equal to [tex]2y^{2}[/tex].

" Division is defined as the distribution of a given quantity into equal parts as per the given condition."

Formula used

[tex]a^{m}[/tex]  ÷ [tex]a^{n}[/tex] [tex]= a^{m-n} , m > n[/tex]

According to the question,

Given polynomial,

[tex]8y^{7}[/tex]  ÷ [tex]4y^{5}[/tex]

Division of given polynomial also use the formula we get,

[tex]8y^{7}[/tex]  ÷ [tex]4y^{5}[/tex]

[tex]= 2 y^{7-5} \\\\= 2y^{2}[/tex]

Hence, division of the given polynomial [tex]8y^{7}[/tex]  ÷ [tex]4y^{5}[/tex]is equal to [tex]2y^{2}[/tex].

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Answer:

1:3

Step-by-step explanation:

18 / 6 = 3

Answer:

3 feet per inch

Step-by-step explanation:

trust me bro

Answer:

Less than, acute, equal to, and right

Step-by-step explanation:

correct on edge.

Use the drop-down menus to complete the statements.

42 is less than 3^2 + 362.

Therefore, △JKL is acute.

5^2 is equal to 3^2 + 4^2.

Applying the same method, △ABC is right.

Your question is incomplete. Please read below to find the content.

Less than, acute, equal to, and right are the correct drop-down menus.

An angle that is measuring much less than ninety degrees is called an acute angle. This perspective is smaller than the proper angle (that is equal to 90 stages). For an instance, ∠30°, ∠forty-five°, ∠60°

Any shape that could be a rectangular or a rectangle, will have its corners equal to ninety tiers or right angle. A proper attitude is therefore referred to as a ninety-diploma perspective. In geometry, the figure formed through two rays, referred to as the perimeters of the angle, sharing a common endpoint, known as the vertex of the angle is referred to as an attitude.

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Answer:

24

Step-by-step explanation:

Length 9 (3+6)

Width 3

Perimeter = 2 times length + 2 times width

18 + 6 = 24

let's say each restaurant has a container of soup which is the same size, let's say there is a total of "s" amount of soup in the container of each restaurant, so 5/4 of that much will just be (5/4)s and 7/4 of "s" is just (7/4)s.

well, one restaurant makes 20 servings from 5/4 of it and the other makes 25 from 7/4 of it,

[tex]\bf \cfrac{5}{4}s\div 20\implies \cfrac{5}{4}s\div \cfrac{20}{1}\implies \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{4}s\cdot \cfrac{1}{\underset{4}{~~\begin{matrix} 20 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \boxed{\cfrac{1}{16}}s \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{4}s\div 25\implies \cfrac{7}{4}s\div \cfrac{25}{1}\implies \cfrac{7}{4}s\cdot \cfrac{1}{25}\implies \boxed{\cfrac{7}{100}}s[/tex]

now, which one is larger?  well, we can simply put both fractions with the same denominator by multiplying one by the other's denominator,

[tex]\bf \cfrac{1}{16}\cdot \cfrac{100}{100}\implies \boxed{\cfrac{100}{1600}}\qquad \qquad \qquad \stackrel{\textit{\Large larger}}{\cfrac{7}{100}\cdot \cfrac{16}{16}\implies \boxed{\cfrac{112}{1600}}}[/tex]