1. Equinox
2. Greatest
3. Gravity
4. Penumbra
5. Solar
6. Earth's atmosphere refracts sunlight toward the moon when the moon passes through the umbria. The atmosphere scatters blue light from the sun, but red light is refracted and bent toward the moon.
Answer:
1. Equinox
2. Greatest
3. Gravity
4. Penumbra
5. Solar
6. Earth's atmosphere refracts sunlight toward the moon when the moon passes through the umbria. The atmosphere scatters blue light from the sun, but red light is refracted and bent toward the moon.
When building a home what feature would be the most beneficial in the winter to keeping heat in a home and cold out
Answer:
insulation is what would keep the cold out and bring in heat
Which of the following has the greatest number of particles A) 1 mole of Na B)22.990g of Na C) 1 mole of Be D) 9.012 g of Be E) all are the same
E) all are the same
Explanation:
Mole:
The mole(mol) is a unit of amount in chemistry. One mole of a substance refers to the mass of Avogadro's Number of particles of that substance. The number of particles in 12.00 g of Carbon(12) is called Avogadro's Number which is equal to 6.022 x 10²³.
A particle refers to an atom in case of an element or a molecule in case of a compound. Particles of different substance might vary in mass or size. Thus, equal number of particles of two different substances might have different masses in grams.
1 mole of Na has Avogadro Number of particles.
22.990 g of Na is equal to 1 mole of Na and has Avogadro Number of particles.
Similarly, 9.012 g of Be is also equal to 1 mole and has Avogadro Number of Be atoms.
Hence, the number of particles of all the three options are same.
Keyword: Avogadro Number
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E) all are the same
Explanation:The question requires we identify the amount of an element with the greatest number of particles.
We need to know that 1 mole of an element contains particles equivalent to the Avogadro's number, 6.022 × 10^23.That is, 1 mole of an element = 6.022 × 10^23 particlesIn this case;
Choice A
1 mole of Na
1 mole of Na contains 6.022 × 10^23 atoms
Choice B
22.990 g of Na
The molar mass of sodium is 22.99 g/mol
Therefore, 22.990 g of Na contains 6.022 × 10^23 atoms
Choice C
1 mole of Be
1 mole of Be contains 6.022 × 10^23 atoms
Choice D
9.012 g of Be
But, the molar mass of Be is 9.012 g
Thus; 9.012 g of Be contains 6.022 × 10^23 atoms
We can therefore, conclude that all the given choices are the same, they have equal number of particles.3. Coyotes and rabbits that live in the same area
a. are in direct competition with each other.
b. have a predator-prey relationship.
C. belong to the same population.
d. have the same niche.
Plz helppopo
Coyotes and rabbits that live in the same area have a predator-prey relationship.
WHAT IS PREDATION?Predation is a type of relationship between living organisms in which one organism called the predator kills and eats another organism called the prey for nutritional needs.
Living organisms require energy for their daily tasks but derive it in different ways.
Coyotes are carnivores i.e. they feed on flesh. Rabbits can be a prey for them. This means that coyotes and rabbits that live in the same area have a predator-prey relationship.
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a bucket of mass 2kg is whirled in a vertical circle of radius 1.20M. at the lowest point of its motion the tension in the rope supporting the bucket is 25N. find the speed of the bucket
The speed of the bucket is 1.8 m/s
Explanation:
The bucket is in circular motion, therefore the net force acting on it is equal to the centripetal force:
[tex]F=m\frac{v^2}{r}[/tex]
where
m = 2 kg is the mass of the bucket
v is its speed
r = 1.20 m is the radius of the circle
At the lowest point of motion, there are two forces acting on the bucket:
The tension in the rope, T = 25 N, upward (same direction as the centripetal force, acting towards the centre of the circle)The force of gravity, [tex]mg[/tex], where [tex]g=9.8 m/s^2[/tex] is the acceleration of gravityTherefore the equation of motion for the bucket is:
[tex]T-mg=m\frac{v^2}{r}[/tex]
And solving for v, we find the speed of the bucket:
[tex]v=\sqrt{r(\frac{T}{m}-g)}=\sqrt{(1.20)(\frac{25}{2}-9.8)}=1.8 m/s[/tex]
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a 30kg child who is running at 4m/s jumps onto a stationary 10kg skateboard. what is the approximate speed of the child and skateboard
Answer:
v=3 m/s
Explanation:
the formula for this problem is
V = v 1 ( m 1 / m 1 + m 2 )
we if we substitute ans solve we get this the answer as 3 m/s
Child and stationary skateboard move with same speed, as child jumps onto skateboard. Approximate speed of child and skateboard is 3 m/s.
What is conservation of momentum?Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.
When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
Thus by the law of conservation of momentum,
[tex](m_1u_1)+(m_2u_2)=(m_1+m_2)v[/tex]
Here, [tex]m_1,m_2[/tex] are the masses of two bodies and [tex]u_1,u_2[/tex] are the initial velocities.
Given information-
The mass of the child is 30 kg.
The speed of the child is 10 m/s.
The mass of the skateboard is 10 kg.
Let the speed of the child and skateboard is [tex]v[/tex] m/s.
As the the child and jumps down onto a stationary skateboard then, the speed of child and skateboard should be same.
Thus by the conservation of momentum,
[tex](m_cu_c)+(m_su_s)=(m_c+m_s)v[/tex]
As the initial velocity of the skateboard is 0. Put the values in the above formula as,
[tex](30\times4)+(10\times 0)=(30+10)v\\120+0=40v\\v=3\rm m/s[/tex]
Thus the approximate speed of the child and skateboard is 3 m/s.
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Micha ran 2 miles north in 20 minutes. She then turned back and ran 1 mile in 15 minutes. To cool down, she walked the rest of the way home. It took her 20 minutes.
What was Micha's average velocity for her run north?
What was Micha's average velocity for the whole trip?
What was her average speed for her entire jog?
Answer:
Micha's average velocity for her run north, v₁ = 6.06 miles/hrMicha's average velocity for the whole trip, V = - 0.32 miles/hrThe speed of her jog is, s = 3.03 miles / hrExplanation:
Given data,
The distance Micha run towards the north, d₁ = 2 miles
The time taken by Micha to run 2 miles is, t₁ = 20 min
= 0.33 h
The displacement towards the south, d₂ = -1 mile
The running duration, t₂ = 15 min
= 0.25 h
Walked displacement, d₃ = -1 mile
The time period to cover that distance, t₃ = 0.33 h
1) The average velocity towards north,
v₁ = d₁ / t₁
= 2 / 0.33
= 6.06 miles/hr
Hence, Micha's average velocity for her run north, v₁ = 6.06 miles/hr
2) The average velocity for whole trip,
V = (v₁ + v₂ + v₃) / 3
The velocity towards south,
v₂ = d₂ / t₂
= -1 / 0.25 h
= -4 miles / hr
The walked velocity,
v₃ = d₃ / t₃
= -1 / 0.33
= - 3.03 miles/hr
∴ The average velocity,
V = (v₁ + v₂ + v₃) / 3
= (6.06 - 4 -3.03)/3
= - 0.32 miles/hr
Hence, Micha's average velocity for the whole trip, V = - 0.32 miles/hr
3) The average speed for her entire jog,
The velocity of her jog, v₃ = - 3.03 miles/hr
∴ Speed,
s = |v|
= 3.03 miles / hr
Hence, the speed of her jog is, s = 3.03 miles / hr
If an object is related from top of 200m high building find its velocity and time when it hits the ground.(g=(10m/s^2)
Answer:
The velocity at the ground is 63.25 m/s and time taken is 6.325 s.
Explanation:
Given:
As the object is released, the initial velocity is, [tex]u=0\ ms^{-1}[/tex]
Displacement of the object is, [tex]d=200\ m[/tex]
To find:
Velocity at the bottom, [tex]v=?[/tex]
Time to reach the bottom, [tex]t=?[/tex]
The acceleration of the object is due to gravity and hence equal to [tex]a=g=10\ m/s^2[/tex]
Now, using the following equation of motion:
[tex]v^2=u^2+2ad\\v^2=0+2(10)(200)\\v^2=4000\\\textrm{Taking square root both sides}\\v=\sqrt{4000}=63.25\ m/s[/tex]
Now, using the equation of motion relating time and velocity:
[tex]v=u+at\\63.25=0+10t\\t=\frac{63.25}{10}=6.325\ s[/tex]
Therefore, the velocity at the ground is 63.25 m/s and time taken is 6.325 s.
While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second on a runway that is 70. meters long. What is the magnitude of the acceleration of the jet? Group of answer choices
The acceleration of the jet is [tex]11.4 m/s^2[/tex]
Explanation:
Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m (length of the runway)
Solving for a, we find the acceleration:
[tex]a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2[/tex]
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The magnitude of the acceleration of the jet is approximately 11.43 m/s².While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40.
To determine the magnitude of the acceleration of the jet, we can use the following kinematic equation:
v² = u² + 2as
where:
v is the final velocity (40 m/s),
u is the initial velocity (0 m/s, starting from rest),
a is the acceleration
and s is the displacement (70 m).
a = (v² - u²) / (2s)
a = (40² - 0²) / (2 × 70)
a = 1600 / 140
a ≈ 11.43 m/s²
Therefore, the magnitude of the acceleration of the jet is approximately 11.43 m/s².
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A ramp is used to load furniture onto a moving truck. The person does 1240 J of work pushing
the furniture up the ramp, and the ramp does 822 J of work. Calculate the efficiency of the
ramp.
Answer: 66.29%
Explanation:
Efficiency = work output / work input x 100 %
Work output = 822J
Work input = 1240 L
E = 822/1240 x 100
E = 0.6629 x 100
E = 66.29%
A closed system changes from state 1 to state 2 while 40kj of heat is added and 60kj of work is done by the system. As system is returned to state 1, 20kj of work is done on it. what is the heat transferred during process 2-1
The heat transferred during the process from state 2 to state 1 in a closed system, after adding 40 kJ of heat and doing 60 kJ of work in state 1 to 2, then having 20 kJ of work done on it, is -80 kJ, meaning 80 kJ of heat is removed.
Given the information that a closed system changes from state 1 to state 2 while 40 kJ of heat is added and 60 kJ of work is done by the system, we can use the first law of thermodynamics to determine the heat transferred during the reverse process (state 2 to state 1). The first law of thermodynamics states that the change in internal energy (
Delta U
) of a system is equal to the heat added to the system (Q) minus the work done by the system (W), so:
Delta U = Q - W.
For the process 1 to 2:
Heat added (Q1 to 2) = +40 kJ
Work done by the system (W1 to 2) = -60 kJ
Therefore,
Delta U1 to 2 = 40 kJ - (-60 kJ) = 100 kJ.
Since the system returns to the initial state, the change in internal energy for the entire cycle is zero:
Delta U cycle =
Delta U1 to 2 +
Delta U2 to 1 = 0
So,
Delta U2 to 1 = -
Delta U1 to 2 = -100 kJ
For the process 2 to 1, we are given:
Work done on the system (W2 to 1) = +20 kJ
Using the first law again for process 2 to 1:
Delta U2 to 1 = Q2 to 1 - W2 to 1
-100 kJ = Q2 to 1 - 20 kJ
Q2 to 1 = -100 kJ + 20 kJ = -80 kJ.
Therefore, 80 kJ of heat is removed from the system during the process from state 2 to state 1.
The orbital period of a satellite is 2 x 106 s and its total radius is 2.5 x 1012 m.
The tangential speed of the satellite, written in standard notation, is
m/s.
Answer:
7,853,982 is the correct answer on Edge 2020
Explanation:
Answer: 7,853,982
Explanation:
All it's asking you is:
-- here's the radius of a circle
-- here's how long it takes to go around the circle
-- how fast are you traveling around the circle ?
I hope that's less scary.
_____________________________
Circumference of a circle =
(pi) x (diameter)
= (pi) x (2 x radius)
= (5 pi) x 10¹² meters .
Time to go around the circle = 2 x 10⁶ seconds
Speed = (distance) / (time)
= (5 pi x 10¹² m) / (2 x 10⁶ sec)
= 2.5 pi x 10⁶ m/s
= 7,853,982
What does the lens of an eye do to create an image?
A. focuses light on the cornea
B. focuses light on the retina
C. reflects light away from the retina
D. bends the cornea to correct vision
The eyes creates an image by focusing light on the retina.
The retina is the light sensitive part of the eyes. Images are formed when light is focused on the retina. The light sensitive nerve endings that are connected to the optic nerve conveys visual information to the brain.
Hence, the lens of the eye creates an image by focusing light on the retina of the eye.
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A 233 N weight object is pushed with a force of 474. If friction is 316 what is the net force on the object?
The net force on the object is equal to 158 N.
Explanation:
Net force is the sum of all the forces acting on an object. The forces might be acting in different direction. In some cases, there may be large forces acting on an object but in opposite direction and cancel out each other. The net force will be zero.
Net Force = F1 + F2 + F3 + ..... + Fn
Friction force is the force resisting the relative motion of an object. The frictional force can be because of the medium of a solid surface. As friction is a resistive force, its direction is always opposite to the force that is moving the object.
In the given problem, the force that is moving a 233 N object is F1 given as:
F1 = 474 N
While the frictional Force is F2 in a direction opposite to the motion of the object so we will use negative sign as a convention.
F2 = -316 N
Finding the net Force:
Net Force = F1 + F2
= 474 + (-316)
= 474 - 316
= 158 N
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The students in Miss Washburn’s class use different methods to conduct
investigations. Which of the following is an example of an experiment?
Group of answer choices:
A) Determining the effect of sunlight on the growth of roses
B)Taking notes on where birds prefer to build nests
C) Making a scale model of the planets of the solar system
D) Recording the number of species of birds in an ecosystem
Answer:
b
Explanation:
When you and a friend move a couch to another room you exert a force of 75 N over 5m how much work will you do
The work done is 375 J
Explanation:
The work done by a force in moving an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and the displacement
In this problem,
F = 75 N is the force applied to the couch
d = 5 m is the displacement
Assuming the force applied to the couch is parallel to the motion, [tex]\theta=0[/tex]
And so, the work done is
[tex]W=(75)(5)(cos 0)=375 J[/tex]
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Final answer:
When moving a couch with a force of 75 N over a distance of 5 meters, you and a friend will do a total of 375 Joules of work. The calculation is based on the formula Work = Force x Distance.
Explanation:
When you and a friend move a couch to another room and exert a force of 75 N over 5m, you can calculate the amount of work done with the formula Work = Force x Distance. In this scenario, since the force exerted is 75 N and you move the couch over a distance of 5 meters, the work done can be computed as:
Work = 75 N x 5 m = 375 Joules.
This means you and your friend will do a total of 375 Joules of work in moving the couch to another room, assuming the movement is in the direction of the applied force and that friction or other forces are not taken into account for this particular calculation.
a wrench weighs 5.24 newtons on earth. when it is taken to the Moon, where g =1.16 m/s2 how much does it weigh?
The weight of a wrench on the Moon is 0.624 Newtons.
Weight of the wrench = 5.24 N
The gravitational acceleration on the moon = 1.16 m/s²
Gravitational acceleration on earth = 9.8 m/s².
Weight is calculated by the formula = W = m × g
First, we need to find the mass of the wrench on Earth using Earth's gravity:
m = W ÷ g
m= 5.24 N ÷ 9.8 m/s²
Then we use the mass of the wrench to calculate its weight on the Moon:
Weight on the moon = m × gravity on moon
By substituting the values, we get:
Weight on the moon = m × 1.16 m/s² = (5.24 N / 9.8 m/s²) ×1.16 m/s²
After calculating, the weight of the wrench on the Moon would be:
Weight on the moon = 0.624 N
How can citizen -scientists help with the prediction of future earthquakes
Answer:
Avoid downed power lines and stay away from buildings and bridges from which heavy objects might fall during an aftershock. Stay away until local officials tell you it is safe. A tsunami is a series of waves that may continue for hours. Do not assume that after one wave the danger is over.
You're driving your pickup truck around a curve that has a radius of 17 m.
How fast can you drive around this curve before a steel toolbox slides on the steel bed of the truck?
To find the maximum speed at which the toolbox will slide on the bed of the truck, we need to compare the maximum static frictional force between the toolbox and the truck bed to the maximum centrifugal force required to keep the toolbox in circular motion around the curve. By setting these forces equal to each other and using the equations for static friction and centripetal acceleration, we can calculate the maximum speed.
Explanation:When a toolbox slides on the back of a truck, the forces acting on the toolbox are the gravitational force pulling it downwards and the frictional force between the toolbox and the surface of the truck bed. In order for the toolbox to slide, the frictional force must be overcome. The maximum static frictional force can be calculated using the equation F_friction = μ * F_normal, where μ is the coefficient of static friction and F_normal is the normal force.
To calculate the maximum speed at which the toolbox will slide, we need to find the maximum centripetal force required to keep the toolbox in circular motion as the truck goes around the curve. The maximum centripetal force can be calculated using the equation F_centripetal = m * a_c, where m is the mass of the toolbox and a_c is the centripetal acceleration.
Setting the maximum static frictional force equal to the maximum centripetal force, we can find the maximum speed at which the toolbox will slide:
μ * F_normal = m * a_c
Since the toolbox is on a horizontal surface, the normal force is equal to the weight of the toolbox, which can be calculated using the equation F_normal = m * g, where g is the acceleration due to gravity. Substituting this in the equation above, we get:
μ * m * g = m * a_c
Simplifying and solving for a_c, we have:
a_c = μ * gNow, we can use the equation for centripetal acceleration to solve for the maximum speed:
a_c = v^2 / r
Solving for v, we have:
v = √(a_c * r)Substituting the values of the radius of the curve and the acceleration due to gravity, we can calculate the maximum speed at which the toolbox will slide.
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It takes four barbarians to turn the wheel below. How many barbarians would it take if the wheel radius were doubled and the axle radius stayed the same?
A. Fewer than four barbarians.
B. Exactly four barbarians.
C. More than four barbarians.
D. Not enough information.
Answer:
A. Fewer than four barbarians.
Explanation:
Mechanical advantage = wheel radius / axle radius
If the wheel radius doubles and the axle radius stays the same, then the mechanical advantage doubles. That means the effort force is half. So we expect it would take half as many barbarians to turn the wheel.
If the wheel radius were doubled and the axle radius stayed the same, it would take fewer than four barbarians.
What is mechanical advantage?Assuming there is no friction in the system, the ratio of the force that performs the useful work to the force applied is the theoretical mechanical advantage of a system.
The extent by which the mechanical advantage really differs from the theoretical value in actuality depends on the amount of friction.
Theoretically, for a wheel and axle system is:
the mechanical advantage = Radius of wheel/ radius of the axle.
As the wheel radius were doubled while the axle radius remains the same; the mechanical advantage of the system will become greater and fewer than four barbarians were needed now.
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You wad up a piece of paper and throw it into the wastebasket. How far will
your piece of paper travel if you throw it with a velocity of 4.3 m/s at an angle
of 65°? (Assume no air resistance and that the paper lands at the same
height you threw it from.)
Answer: 1.4m
Explanation:
before radiant energy can be converted to thermal energy,it must be changed to what
Answer:
The radiant energy is converted into electronic energy before it is transformed into thermal energy.
Explanation:
Radiant energy occurs in the form of "Electromagnetic radiation" and it can pass through all types of matter travelling through the universe. There are numerous advantages of radiant energy. When the radiant energy is incident upon a substance the energy from the sun light excites the electrons in the atom. This sets the atoms in vibrational motion.
Thermal energy is the kinetic energy of moving particles. The thermal energy increases with increase in movement and number of moving particles. When the atoms make a transition from electronically excited state to vibrational state, the energy transfer increases the temperature of the substance. This is felt as thermal energy. Hence, the radiant energy is changed into "electronic energy" before it is converted into "thermal energy".
A conservative force does the same work regardless of the path taken.
O
A. True
O
B. False
A conservative force is a force that when work is done against this force the work done does not depend on the path taken only the initial and final position.
Answer:
True
Explanation:
Maye is running an experiment to determine if a car with large tires will move faster than a car with small tires. her ramp is 0.7 m long she recording the following times on each of her trials: Trial 1:2.5 seconds, Trial 2: 2.75 seconds, Trial 3: 2.98 seconds. what was the average speed of her car?
Answer:
0.256 m/s
Explanation:
Speed is distance over time.
Find the speed of each trial and then find the average.
Trial 1: v = 0.7 m / 2.5 s = 0.280 m/s
Trial 2: v = 0.7 m / 2.75 s = 0.255 m/s
Trial 3: v = 0.7 m / 2.98 s = 0.235 m/s
v_avg = (0.280 m/s + 0.255 m/s + 0.235 m/s) / 3
v_avg = 0.256 m/s
Round as needed.
A ramp is used to load furniture onto a moving truck. The person does 1240 J of work pushing
the furniture up the ramp, and the ramp does 822 J of work. Calculate the efficiency of the
ramp.
Answer:
The efficiency of the ramp is, Eff = 6.63 %
Explanation:
Given,
The work done by the person pushing the furniture up the ramp is, W₁ = 1240 J
The work done by the ramp is, W₀ = 822 J
The efficiency of the ramp is given by the formula,
Eff = ( W₀ / W₁ ) x 100%
= ( 822 / 12400 ) x 100%
= 6.63 %
Hence, the efficiency of the ramp is, Eff = 6.63 %
Answer:
The efficiency of the ramp is, Eff = 6.63 %
Explanation:
QUICK: Using this energy transformation diagram of a battery drill, what is the drill’s thermal energy output?
Answer:
35
Explanation:
Which sphere of Earth includes the continental ice sheets and glaciers? Biosphere Cryosphere Geosphere Hydrosphere
Answer:
C. Cryosphere
Explanation:
The definition for Cryo is:
Involving extreme Coldness and etc.
There are studies done on Cyro Freezing the body to preserve the body until there is a cure for a deadly disease. They do this as well to try to live in the future. Our technology hasn't been able to get the people alive yet, but when we do.
If you ever need to think of "Cryo" just think of Cryo Freezing.
Answer:
C.
Explanation:
An 3.3 kg bowling ball rolls with a velocity of 1.3 m/s and strikes a stationary 3.6 kg
bowling ball. The first ball stops after the collision. How fast does the second
bowling ball roll away after the collision?
The velocity of the second ball is 1.2 m/s
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved before and after the collision, so we can write:
[tex]p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2[/tex]
where:
[tex]m_1 = 3.3 kg[/tex] is the mass of the first ball
[tex]u_1 = 1.3 m/s[/tex] is the initial velocity of the first ball
[tex]v_1 = 0[/tex] is the final velocity of the first ball
[tex]m_2 = 3.6 kg[/tex] is the mass of the second ball
[tex]u_2 = 0[/tex] is the initial velocity of the second ball
[tex]v_2[/tex] is the final velocity of the second ball
Re-arranging the equation and solving for v2, we find the velocity of the second ball after the collision:
[tex]v_2 = \frac{m_1 u_1}{m_2}=\frac{(3.3)(1.3)}{3.6}=1.2 m/s[/tex]
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What would happen to Mars (orbiting around the Sun, obviously) if its tangential velocity was reduced
to zero.
a. It would still continue to orbit the sun
b. It would escape the Sun's gravity and travel out of the Solar System
c. It would eventually crash into the Sun
d. None of the above
Answer:
It would eventually crash into the Sun
Explanation:
If the mars is orbiting around the sun, the gravitational force of attraction is between the sun and mars supply the necessary force required for the centripetal motion.
If a planet is in centripetal motion, it is constantly falling towards the sun with the acceleration equal to the gravitational strength at that point.
If the centripetal acceleration of the planet is removed, still the planet would accelerate linearly falling towards the sun.
Hence, if the planets tangential velocity was reduced to zero, It would eventually crash into the Sun
E5. A 0.12-kg ball traveling with a speed of 45 m/s is brought
to rest in a catcher's mitt. What is the size of the impulse
exerted by the mitt on the ball?
The size of the impulse exerted on the ball is 5.4 kg m/s
Explanation:
The impulse exerted on an object is equal to the change in momentum of the object itself:
[tex]I=\Delta p = m(v-u)[/tex]
where:
I is the impulse
m is the mass of the object
v is the final velocity of the object
u is its initial velocity
In this problem, we have:
m = 0.12 kg is the mass of the ball
u = 45 m/s is the initial velocity of the ball
v = 0 is the final velocity (the ball is brought to rest)
Substituting into the equation, we find the impulse:
[tex]I=(0.12)(0-45)=-5.4 kg m/s[/tex]
where the negative sign means that the direction of the impulse is opposite to the initial direction of motion of the ball. Therefore, the size of the impulse is
[tex]I=5.4 kg m/s[/tex]
Learn more about impulse and change in momentum:
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Define momentum in term of mass and velocity
Answer:
Momentum: It is the quantity of motion of a moving body, measured as a product of its Mass and Velocity.
Explanation:
Definition of momentum :
Momentum is the quantity of motion of a moving body, measured as a product of its Mass and Velocity.
Momentum is denoted by pFormula for momentum is[tex]p = mass\times velocity[/tex]Its unit is kg-m/s.For example:
A bowling ball of large mass moving very slowly can have the same momentum as a cricket ball of small mass that is thrown with a very high velocity