Answer:
Angle θ = 30.82°
Explanation:
From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ
where;
I_o is the intensity of the polarized wave before passing through the filter.
In this question,
I is 0.708 W/m²
While I_o is 0.960 W/m²
Thus, plugging in these values into the equation, we have;
0.708 W/m² = 0.960 W/m² •cos²θ
Thus, cos²θ = 0.708 W/m²/0.960 W/m²
cos²θ = 0.7375
Cos θ = √0.7375
Cos θ = 0.8588
θ = Cos^(-1)0.8588
θ = 30.82°
Look at the diagram showing resistance and flow of electrons. A top box labeled X contains 2 circles with plus signs and 2 circles with minus signs. A bottom box labeled Y contains 4 circles with minus signs and 8 circles with plus signs. An arrow Z runs from the bottom box to the top box. Which labels best complete the diagram? X: High resistance Y: Low resistance Z: Flow of electrons X: Low resistance Y: Flow of electrons Z: High resistance X: Flow of electrons Y: High potential energy Z: Low potential energy X: Low potential energy Y: High potential energy Z: Flow of electrons
Answer:
D: X: Low potential energy
Y: High potential energy
Z: Flow of electrons
Explanation: trust
Answer:
d
Explanation:
The wavelength of a sound wave in this room is 1.13 m and the frequency is 301 Hz.
a. What is the speed of the wave in the room?
©Modeling Instruction Program 2004 3 W2, Mechanical Waves in 1D, WS 5 v3.2
b. If you double the frequency of the sound wave, determine its speed.
c. What happens to the wavelength if you cut the frequency in half? How do you know?
I'll throw in brainiest too.
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
Nuclear power plants are designed to convert nuclear energy into what type of energy
Answer:
Nuclear plants are plants that involve the fission of relatively large atoms to produce electricity as its final product.
In nuclear power plants, the nuclear energy is converted to heat energy, after which the heat energy is converted to mechanical( rotational energy) which helps in the spinning of the turbines. The mechanical energy is then converted to electrical energy.
A hockey player uses a hockey stick to hit a puck such that the stick provides an applied force on the puck. The puck travels for distance of 0.85 m while experiencing the force from the stick. The puck leaves the stick with a speed of 8.0 m/s and travels at constant speed in a straight line along the horizontal ice for a distance of 12 m. The frictional force between the puck and the ice surface is negligible. How does the magnitude of the force exerted by the stick on the puck Fpuck, stick compare to the magnitude of the force exerted by the puck on the stick Fstick, puck at the time interval in which the stick is in contact with the puck?
A) Fpuck, stick < Fstick, puck
B) Fpuck, stick > Fstick, puck
C) Fpuck, stick = F stick, puck
D) It cannot be determined because the masses of the puck and stick are unknown.
Answer:
D
Explanation:
It cannot be determined because the masses of the puck and stick are unknown.
Answer:
the answer is D
Explanation:
It cannot be determined because the masses of the puck and stick are unknown.
A 7310 kg space probe, moving nose-first toward Jupiter at 88.3 m/s relative to the Sun, fires its rocket engine, ejecting 54.0 kg of exhaust at a speed of 246 m/s relative to the space probe. What is the final velocity of the probe
Answer:
[tex]v_{1f} = 90.12m/s[/tex]
Explanation:
As we know that Probe along with rocket system is an isolated system
So here net force on this system must be zero
and we can use momentum conservation for this system
So we will have
[tex](m_1 + m_2)v_{i} = m_1v_{1f} + m_2v_{2f}[/tex]
here we know that
[tex]7310 \times 88.3 = (7310- 54)v_{1f} + 54(v_{1f} - 246)[/tex]
[tex]645473 = 7310\times v_{1f} - 13284\\658757 = 7310 \times v_{1f}[/tex]
so we have,
[tex]v_{1f} = 90.12m/s[/tex]
Answer:
Final velocity of Probe; V_f = 656.314 m/s
Explanation:
We are given;
Mass of space probe; m_i = 7310 kg
Initial velocity of probe ; v_i = 88.3 m/s
Mass of exhaust fuel; m = 54 kg
V_rel = 246 m/s
Mass of fuel; m_f = m_i - m = 7310 kg - 54kg = 7256 kg
From Rocket equation;
V_f - V_i = V_rel[In(m_i/m_f)]
Where V_f is final velocity of probe.
Thus, plugging in the relevant values to get ;
V_f - 88.3 = 246[In(7310/7256)]
V_f - 88.3 = 246 x 2.309
V_f - 88.3 = 568.014
Thus, V_f = 568.014 + 88.3 = 656.314 m/s
. How does the type of medium affect a sound wave?
Answer:
As a result, sound waves travel faster in solids than in liquids, and faster in liquids than in gasses. While the density of a medium also affects the speed of sound, the elastic properties have a greater influence on the wave speed. The density of a medium is the second factor that affects the speed of sound. ( sorry its a bit long :b)
Explanation:
If a system absorbs 300.5J of heat and performs 1.50kJ of work on the surroundings, what is the ΔE?
Complete question:
If a system absorbs 300.5J of heat and performs 1.50kJ of work on the surroundings, what is the change in internal energy of the system ΔE?
Answer:
Change in internal energy of the system is 1800.5 J
Explanation:
Given:
heat transferred to the system, Q = 300.5J
work done on the surroundings, W = 1.50kJ
Change in internal energy of the system ΔE, can be calculated by applying thermodynamic equation of change in internal energy, work done and heat transferred.
ΔE = Q + W
Where;
ΔE is change in internal energy
Q is heat transfer
W is work done
ΔE = 300.5 J + 1500 J
ΔE = 1800.5 J
Therefore, change in internal energy of the system is 1800.5 J
Answer:
The intern energy of the system is -1199.5 J
Explanation:
Given:
System absorbs 300.5 J of heat
Performs 1.5 kJ = 1500 J of work on the surroundings
Question: What is the ΔE?
When a system absorbs heat, it will have a positive sign, therefore +300.5 J
When the system performs work on the surroundings, its sign will be negative, therefore, -1500 J
According the first law of thermodinamic:
ΔE = q + W = 300.5 - 1500 = -1199.5 J
587 kJ of work against gravity when it lifts a 6500 kg concrete from at a construction site. Calculate the height, in m, the form was lifted
Answer:
The answer to your question is height = 9.20 m
Explanation:
Data
Work = 587 kJ
mass of the body = 6500 kg
height = ?
Mechanic work is defined as the force applied to a body times its mass.
Process
1.- Calculate the weight of the body
weight = mass x gravity (9.81)
weight = 6500 x 9.81
= 63765 N
2.- Calculate the height
height = work / weight
-Substitution
height = 587 000 / 63765
-Result
height = 9.20 m
What’s the formula for work
Answer:
Fd
Explanation:
Work is force times distance. If you push on an object really hard but it does not budge, you have still performed no work on it, because anything times zero is still zero.
Answer:
W = F * d
Explanation:
Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasoning
Help help help
Answer:
ive answered this
Explanation:
please check your previose question
The palm of the hand has more touch receptors than the back, making it more sensitive to touch. This density of receptors allows the palm to better distinguish two closely spaced points. The difference in receptor density and receptive field sizes results in the increased tactile sensitivity of the palm.
In terms of touch receptor density, you would expect to have more touch receptors on the palm of your hand compared to the back of your hand. This is because areas of the skin with a high density of touch receptors, such as the palms, are more sensitive and can detect finer details. The palm of your hand has many more receptors with smaller receptive fields, which allows it to distinguish between two closely spaced points better than the back of your hand. Skin areas with small receptive fields are better able to distinguish two similarly-spaced points. The palm has a smaller threshold for discerning between two points than the back, a result of the differences in the size of receptive fields.
If you were to perform a two-point discrimination test, you would notice that the minimum distance at which you can perceive two points as separate is much smaller on the palm than on the back of the hand. This increased sensitivity is due to the higher density of touch receptors in the palm, which is essential for tasks that require precise touch, such as gripping objects and feeling textures.
What is the period that corresponds to a
frequency of 39.5 Hz?
Answer in units of s.
The answer for the following problem is mentioned below.
Therefore the time period is 0.02 seconds.Explanation:
Frequency:
The number of waves that pass a fixed place in a given amount of time. (or)
The number of waves that pas by per second.
The SI unit of the frequency is Hertz(Hz).
Time period:
The time taken for one complete cycle of vibration to pass a given point.
The SI unit of time period is seconds. (s)
Given:
Frequency (f) = 39.5 Hz
To calculate:
Time period (T)
We know;
According to the problem;
From the problem;
f = [tex]\frac{1}{T}[/tex]
Where;
f represents the frequency
T represents the time period
f = [tex]\frac{1}{39.5}[/tex]
f = 0.02 seconds
Therefore the time period is 0.02 seconds.
Given values,
Frequency,
F = 39.5 HzNow,
→ [tex]Frequency = \frac{1}{Time \ period}[/tex]
or,
→ [tex]F = \frac{1}{t}[/tex]
By substituting the values,
[tex]39.5 = \frac{1}{t}[/tex]
[tex]t = \frac{1}{39.5}[/tex]
[tex]= 0.02 \ seconds[/tex]
Thus the answer above is correct.
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What would happen if the voltage impressed across a circuit is held constant while the resistance doubles
Answer:
What would happen if the voltage impressed across a circuit is held constant while the resistance doubles.
The answer is:
A change will occur in the current which is, "The new current will be half the initial value."
Explanation:
Voltage, also called electromotive force, is the measure of specific potential energy between two locations in an electrical field.
V= IR
Where, V= Voltage
I= Current
R= Resistance
The greater the voltage in a circuit, the greater its ability to push more electrons and do work.
Voltage is measured in volts (V). Voltage is the difference in charge between two points, and can also be considered as the pressure that forces the charged electrons to flow in an electrical circuit.
Current is the rate at which charge is flowing. An electric current flows when electrons move through a conductor, such as a metal wire.
Resistance is a material's tendency to resist the flow of charge (current). Resistance is measured in ohms, and can be further explained as a measure of the opposition to current flow in an electrical circuit. Resistance is good because it protects humans from the harmful energy of electricity. Resistance, R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A).
Current is directly proportional to the voltage and inversely proportional to the resistance.
If voltage is increased, the current will also increase. The higher the resistance, the lower the current flow. The lower the resistance, the higher the current flow.
Doubling the voltage will cause the current to be doubled. Also, doubling the resistance will cause the current to be one-half the original value.
How does the law of inertia relate to how the planets in our solar system revolve around the sun?
Answer:
The law of inertia relates to revolution of planets round the sun due to constant motion of the planets round the sun.
Explanation:
Law of inertia states that a body at rest or uniform motion will continue to be at rest or uniform motion unless it is acted upon by an external force.
The gravitational force keeps the planets revolving round the sun in a uniform motion, this will continue till infinity unless equal and opposite force acts on our planets.
Therefore, the law of inertia relates to revolution of planets round the sun due to constant motion of the planets round the sun.
You blow dry your wet hair. Is it physical or chemical
Answer: physical
Explanation: it's still hair, it's just dry instead of wet now
The position of a full moon is located
Answer:
opposite the sun. between the Earth and the sun. rising perpendicular to the sun.
Explanation:
What is the speed of a particle whose kinetic energy is equal to its rest energy.
Answer:
The speed of the particle whose kinetic energy is equal to its rest energy is 4.242*10⁸m/s.
Explanation:
The rest energy is defined as the energy equal to the mass of the particle at rest in the inertial frame of reference equal to the rest mass time square of speed of light
E₀ = mc²
The kinetic energy is defined as the energy possessed by the particle due to its motion.
K.E =0.5mv².
where, m is the mass of the particle
c is the speed of light,
v is the velocity of the particle
It is given that Kinetic energy is equal to rest energy ie K.E = E₀
0.5mv² = mc²
v² = 2c²
v =√2c
= 1.414*3*10⁸
v =4.242 *10⁸ m/s
The speed of the particle whose kinetic energy is equal to its rest energy is 4.242*10⁸m/s.
The speed of a particle whose kinetic energy equals its rest energy would be a significant fraction of the speed of light, approximately 0.914c or 91.4% of the speed of light for an electron with kinetic energy 150% of its rest mass energy.
Explanation:The question asks about the relationship between kinetic energy and speed for a particle when the kinetic energy is equal to the particle's rest energy. Using the principles of relativity, we know that a particle's total energy is the sum of its rest mass energy and its kinetic energy. According to Einstein's theory of relativity, the kinetic energy (K) of a particle approaches infinity as its speed (v) approaches the speed of light (c). Therefore, for a particle to have its kinetic energy equal to its rest mass energy (E0), it must be traveling at a significant fraction of the speed of light.
Specifically, in the case of an electron with a rest mass energy of 0.511 MeV, if its kinetic energy is 150% of this value, calculations would show that the electron is traveling at a velocity approximately 0.914c, which is around 91.4% of the speed of light. This result is consistent with relativistic effects, which become significant as particles move at speeds approaching the ultimate speed limit, c, as stated by the theory of relativity.
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What impact or changes do you think this invasion of zebra mussels will have on the native species living in the Hudson River ecosystem? (Hint: Think about what it means to be the only freshwater mussel species that can attach itself toobjects.)
Answer:
The native species will be endangered or even go into extinction.
A drastic change in the food web
Explanation:
The zebra mussel or Dreissena
polymorpha is a small bivalve that originated from the Caspian Sea region, In mid 1980s the Zebra Mussels moved to North America in the ballast water of a ship.
They took over the
Great Lakes and the waters draining them. It is speculated that the Zebra mussels will eventually
move to most of the waters in North America with the exception of waters that are too warm or too saline for them to survive.
They were first discovered in the Hudson at very low densities in 1991, spreading rapidly that by 1992 they can be found throughout the river, with biomass that was greater than the combined biomass of all
other consumers viz; fish, zooplankton and bacteria, in the river.
Their densities can reach over
100,000 individuals per square meter. Because they are so many, they are able to filter all of the
water in the freshwater portion of the Hudson River every 2-4 days.
Whereas the native mussels could filter the water only every 2-3 months.
Zebra mussels are suspension feeders, eating
phytoplankton, small zooplankton, large bacteria, and organic detritus by filtering the water and straining out the edible material.
Now, because they filter small
organisms and organic particles out of the water at very high rates. (Very efficient filter-feeders)
Phytoplankton and zooplankton which form the base of the aquatic food web, as many animals depend on them for survival, this balance is tilted.
This has brought great changes and effects on the Hudson Ecosystem. The food web changes that the mussel has caused compare in magnitude to disturbances in other aquatic ecosystems caused by toxins, nutrient pollution, or acid rain. and have been found. These mussels were most likely
brought to those areas by careless human activity.
Furthermore, most of the species on the Hudson river will be endangered and some must have gone into extinction and this is due to the speed with which the Zebra mussels feed on them.
As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.05 m 1.05 m long rod as you jog at 3.27 m/s 3.27 m/s , holding the rod perpendicular to your direction of motion. What is the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.275 mV 0.275 mV across the rod? Express the answer in milliteslas.
Answer:
The strength of the magnetic field is 0.08 mT
Explanation:
Given:
Length of rod [tex]l = 1.05[/tex] m
Velocity of rod [tex]v = 3.27[/tex] [tex]\frac{m}{s}[/tex]
Induced emf [tex]\epsilon = 0.275 \times 10^{-3}[/tex] V
According to the faraday's law
We know that the induced emf of rod is given by,
[tex]\epsilon = Blv[/tex]
Where [tex]B =[/tex] magnetic field
For finding the magnetic field,
[tex]B = \frac{\epsilon }{lv}[/tex]
[tex]B = \frac{0.275 \times 10^{-3} }{1.05 \times 3.27}[/tex]
[tex]B = 0.08 \times 10^{-3}[/tex]
[tex]B = 0.08[/tex] mT
Therefore, the strength of the magnetic field is 0.08 mT
Help ASAP
Just answer the first question for me please!
Answer:
Im pretty sure its b
A and B are mutually exclusive events. PA) = 0.50 and P(B) = 0.30. What is
PA or B)?
Answer:
P(A∪B)=0.8
Explanation:
Given that,
A and B are mutually exclusive events such that,
P(A)=0.5 and P(B)=0.3
We need to find P(A or B). It means we need to find P(A∪B). If two events are mutually exclusive, P(A∩B)=0. So,
P(A∪B)=P(A)+P(B)-P(A∩B)
Putting P(A) and P(B), we get :
P(A∪B)=0.5+0.3-0
P(A∪B)=0.8
So, the value of P(A or B) is 0.8
Two spherical inflated rubber balloons each have the same amount of charge spread uniformly on their surfaces. If the repelling force is 2.5 N and the distance between the balloon centers is 0.30 m, find how much charge is on each balloon.
Answer:
[tex]5.0\cdot 10^{-6}C[/tex]
Explanation:
The magnitude of the electrostatic force between two charged objects is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the two charges on the two objects
r is the separation between the two charges
The force is:
- Repulsive if the two charges have same sign
- Attractive if the two charges have opposite sign
In this problem:
F = 2.5 N is the force between the two balloons
r = 0.30 m is their separation
[tex]q_1=q_2=q[/tex] is the charge on each balloon (they have the same charge)
So, re-arranging the equation, we can find the value of q:
[tex]F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(2.5)(0.30)^2}{8.99\cdot 10^9}}=5.0\cdot 10^{-6}C[/tex]
We are also told that the force between them is repulsive: this means that the charges on the two balloons have same sign (so, either they are both positive, or both negative).
Using Coulomb's Law, we derive the formula to calculate the charge on each balloon to be q = sqrt(F * r^2 / k). By substituting the provided force and distance values into the formula, we can find the magnitude of charge on the spherical balloons.
Explanation:The question involves calculating the charge on each of two spherical balloons which repel each other with a given force, using Coulomb's Law. Coulomb's Law states that the magnitude of the electrostatic force of interaction between two point charges is directly proportional to the scalar multiplication of the magnitudes of charges and inversely proportional to the square of the distance between the two charges.
According to Coulomb's Law, F = k * (|q1 * q2|) / r^2, where F is the force between charges, k is Coulomb's constant (8.9875 x 10^9 N·m^2/C^2), q1 and q2 are the amounts of charge on the balloons which are equal in this case, and r is the distance between the centers of the two charges.
To find the amount of charge on each balloon, we rearrange the formula to solve for q: q = sqrt(F * r^2 / k). We are given that the repelling force F is 2.5 N and the distance r is 0.30 m. Plugging in these values and the value for k, we can calculate the amount of charge on each balloon.
All of the noble gases, Group 18, have eight valence electrons in its outer shell (excluding helium which only has two). Which of these would represent the oxidation number of the noble gases such as xenon and argon?
Answer:
Zero or +2
Explanation:
The noble gases already have a avplete outermost shell. They are the least reactive elements of earth?
Their normal oxidation number is zero but some have been shown to be reactive.
Answer:
Explanation:
Since oxidation number is derived from the number of electron in the outermost shell of an element and further more this oxidation number is a function of how much electron is needed by an element to achieve a duplet ( He) or octet configuration ( complete outer most shell which is the attributes of group 18 elements or noble gases) and they don't readily react with any compound.. Since Xenon and argon are noble gases , they will have their outer most shell completely feel hence their oxidation number will be zero (0)
What is a sentence for absolute strength?
Sciencium-380 has a half-life of 3 days. If you started with a 100 gram sample, how much Sciencium-380 will remain after 9 days?
Answer: 12.5 grams will remain.
Explanation:
The half life time means that if we start with a quantity A of a given subtance/material, after the half time we will have half that quantity, or A/2.
We know that the half life of Sciencium-380 is 3 days.
So if we have 100 grams, after 3 days we will have 100/2 = 50 grams.
After other 3 days we will have 50/2 = 25 grams
After other 3 days we will have 25/2 = 12.5 grams.
So if we start with 100 grams, after 9 days we will have 12.5 grams.
Answer:
12.5 grams
Explanation:
Solution:-
- By definition, the half-life is the amount of time t that a substance of mass M to decay to half its its initial mass.
- We are given the mass of the Sciencium-380, M = 100 g
- The half-life for the radioactive isotope is, h = 3 days
- The amount of mass left after t = 9 days.
- We will first estimate the number of half-lives that have passed in te duration of t = 9 years.
- The number of half lives are:
n = t / h
n = 9 / 3
n = 3
- For every half life the mass is halved or mathematically the mass ( m ) of a substance remaining after " n " number of half lives can be expressed as:
m = M*0.5^n
- Plug in the given values and evaluate the mass ( m ) of the substance after n = 3 half lives.
m = 100*0.5^3
m = 12.5 grams.
Answer: We are left with 12.5 grams of Sciencium after 3 half lives have passed.
How does an unbalanced force affect an object?
Answer:
it can change the speed only or can change direction only or can change both
ck-12 Refraction
2/10
SKILL LEVEL
To be de
Light coming straight from a laser pointer passes from air into a
tub of liquid. It hits the surface of the liquid at an angle of 28°
from vertical, and continues into the liquid at an angle of 22°.
What is the index of refraction of the substance in the tub? n =
Answer:
1.25
Explanation:
From refractive index of the substance in the tub, n = sini/sinr where i = angle of incidence = 28° and r = angle of refraction = 22°
So, n = sini/sinr = sin28°/sin22° = 1.253 ≅ 1.25
The index of refraction of the substance in this tub is equal to 1.25.
Given the following data:
Angle of incidence = 28°.Angle of refraction = 22°.What is Snell's law?Snell's law gives the relationship between the angle of incidence and angle of refraction with respect to light or other waves passing through a media or two different substances such as glass, water or air.
Snell's Law states that the when light travels from one medium to another, it generally refracts. Mathematically, it is given by this formula:
[tex]n=\frac{sini}{sinr}[/tex]
Substituting the given parameters into the formula, we have;
[tex]n=\frac{sin28}{sin22}\\\\n=\frac{0.4695}{0.3746}[/tex]
n = 1.25
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On the incomplete ray diagram for an object in front of a curved mirror, trace the path of Ray 1 as you would do to find the location and size of the image. F labels the focal point of the mirror.
You do not have to trace additional rays for this question.
Answer:
Answer:
See attached the ray diagram with the path of Ray 1, which must pass through the focal point, F.
Explanation:
The curved mirror shown is a converging lens.
To find the location and size of the image formed by a converging lens, you must draw two rays: one ray is from the upper tip of the object (the pen in your figure) that is in front of the mirror, parallel to the horizontal axis until the lens (Ray 1 in your figure) which then bends through the focal point (F in your figure). That is the ray that you must complete in your figure.
The attached figure shows this ray in blue.
The other ray would be from the upper tip of the pen straight through the center of the lens (this is not included in the figure, by instructions of the question).
For finding the location and size of the image we have to prepare it for that please look below.
Curved mirror:It is to be shown like a converging lens. For determining the location and image size i.e. created by the converging lens here two rays should be drawn i.e. one ray from the upper tip of the project that should be front of the mirror also parallel to the horizontal axis that bends via the focal point. It represents that ray that should finished the given figure.
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How does the frequency of gamma rays compare to the frequency of microwaves?
Answer:
Frequency of gamma rays is more than microwave.
Explanation:
The number of vibrations per unit time is called frequency of a wave. The SI unit of frequency is Hertz. It is equal to [tex]s^{-1}[/tex].
The frequency of gamma rays is of the order of [tex]10^{20}\ Hz[/tex]. The frequency of microwave is of the order of [tex]10^8\ Hz[/tex].
It is clear that gamma rays have more frequency that of the microwave.
Two balls of the same shape and size have charges of +8 and-2. The balls are brought together, allowed to touch, and then separated. What is the net charge on each ball now?
Explanation:
Initially, two balls of the same shape and size have charges of +8 and-2. The balls are brought together, allowed to touch, and then separated.
When they are touched, the total charge is evenly distributed among the whole surface and they behaves as if it is a single piece. Net charge at this point is +8-2=6 C. When they are separated, each ball will have a charge of 6/2 = 3 C.
When two identical balls with charges of +8 and -2 are brought into contact and then separated, each ball ends up with a net charge of +3, due to the conservation of charge and even distribution across identical conducting surfaces.
When two balls of the same shape and size with charges of +8 and -2 are brought together, allowed to touch, and then separated, the net charge on each ball is a result of the equal distribution of the total charge across both balls. Initially, the total charge is the sum of +8 and -2, which equals +6. Since the balls are identical and they come into contact, this total charge of +6 is evenly divided between them. Therefore, after they are separated, each ball will have a net charge of +3.
This occurs because, when conducting objects touch, charges redistribute themselves evenly across the surfaces of the objects until they reach an equilibrium while maintaining the conservation of charge. In simpler terms, the total quantity of charge is conserved, and since the two balls are identical, the charge divides evenly.
A metal object is to be gold-plated by an electrolytic procedure using aqueous aucl3 electrolyte. Calculate the number of moles of gold deposited in 3.0 min by a constant current of 10. A.
Answer:
Explanation:
charges passed = current x time
= 10 x 3 x 60
= 1800 C
mole of charge = 1800 / 96500
= .01865 moles
Au⁺³ contains 3 positive charges
3 mole of charge will deposit 1 mole of Au
.01865 moles will deposit .01865 / 3 mole
= 6.2167 x 10⁻³ moles .