The current in a hair dryer measures 15 amps. The resistance of the hair dryer is 14 ohms. What is the voltage?

i'm pretty terrible at math, if you could explain how to found the correct answer to help future problems i would greatly appreciate it!

Answer:

4.56 km.

Explanation:

Blessings.

Final answer:

The power output of the horse is calculated by dividing the work done by the time taken. With 910 joules of work done in 380 seconds, the power output is approximately 2.4 watts after rounding to two significant figures.

Explanation:

To calculate the power output of the horse, you can use the formula for power, which is work divided by time.

Power (P) = Work (W) / Time (T)

Given the information, the horse does 910 joules (J) of work in 380 seconds. Using the formula:

P = 910 J / 380 s ≈ 2.395 W

Rounded to two significant figures, the power output of the horse is approximately 2.4 watts (W).

It comes out to be approximately 2.394736842 W, which is rounded to 2.4 W to two significant figures. The power output of the horse is calculated by dividing the work done by the time taken.

To calculate the power output of the horse, we use the formula for power (P), which is P = Work done (W) / Time taken (t).

The horse does 910 J of work in 380 seconds.

Therefore, the power output P is:

P = 910 J / 380 s = 2.394736842 J/s

Since 1 watt (W) is equivalent to 1 joule per second (J/s), the power output of the horse is approximately:

P = 2.394736842 W

Rounded to two significant figures, the power output of the horse is 2.4 W.

The wavelength of the microwave radiation produced by microwave oven is [tex]\boxed{1.1\times {10^8}\,{\text{nm}}}[/tex].

Further Explanation:

A microwave is an appliance which is used to heat and cook food by direct exposing it to electromagnetic radiation. Microwave oven uses radio waves to heat and cook food. A magnetron is used as a source of microwave radiation.

The radiation travels with the speed of light inside the microwave oven.

Given:

The operational frequency of the microwave oven is [tex]2.70\text{ GHz}[/tex].

The speed of the radiation is [tex]3\times10^{8}\text{ m/s}[/tex].

Concept:

The frequency and wavelength of an electromagnetic radiation are related according to the following expression.  

[tex]c=f \cdot \,\lambda[/tex]

Rearrange the above expression for [tex]\lambda[/tex] .

[tex]\boxed{\lambda=\dfrac{c}{f}}[/tex]                                 …… (1)

Here, [tex]c[/tex] is the speed of light, [tex]f[/tex] is the frequency of the radiation and [tex]\lambda[/tex] is the wavelength of the radiation.

Converting [tex]\text{GHz}[/tex] into [tex]\text{Hz}[/tex].

[tex]2.70\,{\text{GHz=2}}{\text{.70}} \times {\text{1}}{{\text{0}}^9}\,{\text{Hz}}[/tex]

Substitute [tex]3.00 \times {10^8}\,{\text{m/s}}[/tex] for [tex]c[/tex] and [tex]2.70 \times {10^9}\,{\text{Hz}}[/tex] for [tex]f[/tex] in equation (1).  

[tex]\begin{aligned}\lambda&=\frac{{3.00 \times {{10}^8}\,{\text{m/s}}}}{{2.70 \times {{10}^9}\,{\text{Hz}}}} \\&=0.11\,{\text{m}} \\&=1.1\times10^{8}\text{ nm} \\ \end{aligned}[/tex]

Thus, the wavelength of the microwave radiation produced by microwave oven is [tex]\boxed{1.1\times {10^8}\,{\text{nm}}}[/tex].

Learn more:  

1. Rotational velocity https://brainly.com/question/2887706

2. Current through the inductor https://brainly.com/question/1695461

3. Force applied by car on truck https://brainly.com/question/2235246

Answer Details:  

Grade: High school  

Subject: Physics  

Chapter: Electromagnetic radiation  

Keywords:  

Microwave oven, 2.70 GHz, 2.70 ghz, 2.70 times 10^9 Hz, wavelength, numerically, nanometers, 0.11 m, 0.11 times 10^9 nm, 1.1 times 10^8 nm , magnetron, 0.11 times 10power9 nm, 1.1 times 10 power 8 nm.

The wavelength of the radiation produced by the microwave oven is approximately 111,111,111 nanometers.

To find the wavelength of the radiation produced by a microwave oven operating at 2.70 GHz, you can use the formula:

Wavelength (λ) = Speed of Light (c) / Frequency (f)

Where:

Speed of Light (c) = 3 x [tex]10^8[/tex] meters per second (approximately)

Frequency (f) = 2.70 GHz = 2.70 x [tex]10^9[/tex] Hertz

Now, plug these values into the formula:

λ = (3  x [tex]10^8[/tex]  m/s) / (2.70 x [tex]10^9[/tex] Hz)

λ = 0.1111 meters.

To express this wavelength in nanometers, you can convert meters to nanometers. There are 1 billion nanometers in a meter, so:

λ ≈ 0.1111 meters * 1,000,000,000 nanometers/meter ≈ 111,111,111.11 nanometers

Hence , The wavelength of the radiation produced by the microwave oven is approximately 111,111,111 nanometers.

To know more about wavelength here

https://brainly.com/question/4844737

#SPJ3

The converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

Explanation:

Given information:

Mass of justin [tex]=50 \; \text{kg}[/tex]

Height of water slide [tex]=8\;\text{m}[/tex]

Speed at the bottom [tex]= 12 \;\text{m/s}[/tex]

Now, the total mechanical energy is:

[tex]E_i=U=mgh\\E_i=50\times 9.81\times 8\\E_i=3924\;J[/tex]

And, the kinetic energy :

[tex]E_f=K=(1/2)mv^2\\E_f=0.50\times 50\times 12\\E_f=3600\;\text{J}[/tex]

So, the energy lost by the justin:

[tex]\Delta\;E=E_i-E_f\\\Delta\;E=3924-3600\\\Delta\;E=324J\\[/tex]

Hence, this converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

For more information visit:

https://brainly.com/question/15707891?referrer=searchResults

Answer:

C. Photosphere

Explanation:

The lights shown in the figure comes from the outermost layer of the Sun. This layer is called photosphere.

This is the layer from where the light of the Sun is radiated, before travelling through space and reaching us.

The photosphere is the coldest layer of the Sun: its surface temperature is between 4500 and 6000 K. Its width is approximately 100 km.

A characteristic of the photosphere is the presence of the sunspots, which appear as darker spots, and are regions of lower temperature caused by a concentration of magnetic flux.

The correct option is Option C( Photosphere).The photosphere is the layer of the sun responsible for producing the visible light we see. It has a temperature range of 4500 K to 6800 K. The photosphere is the sun's visible surface.

Answer:

black hole

Explanation:

A black hole is a region which is highly dense and very high gravitational field.

As the density of black hole is very high, so the mass of black g=hole is very large thus the force of gravitation is very large. So, even light cannot escape from the gravitational filed from the black hole.

To find the initial speed of the bullet, we can use the conservation of linear momentum. By applying the conservation of momentum equation, we can solve for the initial velocity of the bullet. In this case, the initial velocity of the bullet is found to be 0 m/s.

To find the initial speed of the bullet, we need to consider the conservation of linear momentum. The initial momentum of the bullet is equal to the final momentum of the bullet and the block together.

The momentum of an object is given by the product of its mass and velocity. The bullet has a mass of 9.00 g and its velocity is the initial speed we want to find. The block has a mass of 1.20 kg and its velocity is 0 m/s initially.

Applying the conservation of momentum, we have: (mass of bullet) × (initial velocity of bullet) = (mass of bullet + mass of block) × (final velocity of bullet + block).

Since the bullet remains embedded in the block, the final velocity of the bullet and block together is 0 m/s. Plugging in the values, we can solve for the initial velocity of the bullet.

9.00 g × (initial velocity of bullet) = (9.00 g + 1.20 kg) × 0

(initial velocity of bullet) = 0 / (10.2 g)

(initial velocity of bullet) = 0 m/s

Answer:

[tex]\rho = \frac{RA}{L}[/tex]

Explanation:

.As we know that the resistance of the wire is given as

[tex]R = \rho \frac{L}{A}[/tex]

here we know that

A = cross-sectional area

L = length

R = resistance of wire

now multiply both sides of above equation with Area

[tex]R A = \rho L[/tex]

now divide both sides with length of the wire

[tex]\rho = \frac{RA}{L}[/tex]

so above is the expression of resistivity of wire in terms of resistance, Area and length of the wire

Answer:

Liquid water is essential for life to exist. Water can occur in a liquid state only within a specific temperature range, so knowing the temperature range on a planet will help astronomers predict whether life exists on that planet.

Explanation:

Final answer:

Temperature is a critical criterion for finding Earthlike exoplanets because it determines the presence of liquid water, a requirement for life. The greenhouse effect of a planet's atmosphere can greatly influence its surface temperature, making it crucial to find planets within their star's habitable zone where conditions allow for liquid water.

Explanation:

Temperature is an excellent criterion for searching for Earthlike exoplanets because it is a fundamental factor that determines a planet's habitability. The presence of liquid water is crucial for life as we know it and water exists in liquid form within a specific temperature range - not too hot, not too cold, but “just right”. Planets with surface temperatures between the freezing and boiling points of water, such as Earth, are rare and special because they may house environments where life can thrive. Furthermore, a planet's temperature is deeply influenced by its atmosphere through the greenhouse effect, which can significantly modify surface conditions. Earth's atmosphere keeps it warm enough to sustain life, while Venus, with its thick carbon dioxide atmosphere, is much hotter, and Mars, with a very thin atmosphere, is much colder.

Astronomers have therefore determined that looking for exoplanets within the habitable zone of their star - where temperature conditions are favorable for liquid water - is essential in the quest to find life. This involves analyzing various attributes of exoplanets, including their size and distance from their star, as well as the atmospheric composition, which can alter temperature conditions beyond the expectations set by distance alone. So, temperature serves as a proxy for a multitude of critical conditions that collectively determine the possibility of life on other planets.

Since there is not quite enough energy for transition from n=1 to n=2. So, the photons will pass through the gas chamber without affecting the gas.

Further explanation:

If the energy of photons is enough to excite all the electrons to go in higher state, the electron absorbs the energy of photon and go from a lower energy state to higher energy state. Transition of electron from lower energy state t higher energy state depends on the energy of photons.

Given:

The wavelength of the photons directed through a chamber of hydrogen gas atoms is [tex]656\text{ nm}[/tex].

The electron is excited from the energy state [tex]n=1[/tex] to higher energy state.

Concept:

The energy associated with a photon is given by the following relation.

[tex]E = \dfrac{{hc}}{\lambda}[/tex]

Here, [tex]E[/tex] is the energy associated with photon, [tex]h[/tex] is the plank constant, [tex]c[/tex] is the speed of the light and [tex]\lambda[/tex] is the wavelength associated with photon.

Substitute [tex]6.625\times{10^{-34}}\text{ J}\cdot\text{s}[/tex] for [tex]h[/tex], [tex]3.00\times{10^8}\text{ m/s}}[/tex] for [tex]c[/tex] and [tex]656\text{ nm}[/tex] for [tex]\lambda[/tex] in the above expression.

[tex]\begin{aligned}E&=\frac{{\left( {6.625 \times {{10}^{ - 34}}\,{\text{Js}}} \right)\left( {3.0 \times {{10}^8}\,{\text{m/s}}} \right)}}{{\left( {656 \times {{10}^{ - 9}}\,{\text{m}}} \right)}}\\&=3.0281 \times {10^{-19}}\,{\text{J}}\\\end{aligned}[/tex]

Rydberg equations is used to find out the energy level of an electron while transition from one energy state to another energy state.

[tex]\dfrac{1}{\lambda}=R{z^2}\left({\dfrac{1}{{n_1^2}}-\dfrac{1}{{n_2^2}}}\right)[/tex]

Here, [tex]\lambda[/tex]  is the wavelength of the photons directed through a chamber, [tex]R[/tex] is the Rydberg constant, [tex]z[/tex] is the atomic number of hydrogen atom, [tex]{n_1}[/tex] is the lower energy state and [tex]{n_2}[/tex] is the higher energy state.

Substitute [tex]656\times{10^{-9}}\,{\text{m}}[/tex] for [tex]\lambda[/tex], [tex]1.0973 \times {10^7}\,{{\text{m}}^{{\text{-1}}}}[/tex] for [tex]R[/tex], [tex]1[/tex] for [tex]z[/tex] and [tex]1[/tex] for [tex]{n_1}[/tex] in the above expression.

[tex]\dfrac{1}{{\left( {656 \times {{10}^{ - 9}}\,{\text{m}}} \right)}} = \left( {1.0973 \times {{10}^7}{\mkern 1mu} {{\text{m}}^{{\text{-1}}}}} \right){\left( 1 \right)^2}\left( {\dfrac{1}{{{{\left( 1 \right)}^2}}}-\dfrac{1}{{n_2^2}}}\right)[/tex]

Simplify the above expression for [tex]{n_2}[/tex]

[tex]\begin{aligned}{n_2}&=\sqrt{\dfrac{1}{{0.861}}}\\&=1.08\\\end{aligned}[/tex]

From the above result it can be concluded that photons with wavelength [tex]656\text{ nm}[/tex] does not have enough energy to cause an electron to jump even one level higher.

Thus, there is not quite enough energy for transition from n=1 to n=2. So, the photons will pass through the gas chamber without affecting the gas.

Learn more:

1.  A Na+ ion moves from inside a cell https://brainly.com/question/9251988

2.  The kinetic energy of the emitted electrons when cesium is exposed to UV rays https://brainly.com/question/9059731

3. The frequency of the light for wavelength 7.1x10^2 nm https://brainly.com/question/9559140

Answer Details:

Grade: College

Subject: Physics

Chapter: Modern physics

Keywords:

Photons, light, energy, 656 nm, 656 times 10^-9 m, 6.56 times 10^-7 m, directed, chamber, hydrogen, gas atom, ground state, ni=1, 1.071, few, absorbed, quite enough, electrons, nf=2.

Final answer:

When photons with an energy of 656 nm pass through a chamber of hydrogen gas, the gas atoms can absorb these photons, causing the electrons to transition to higher energy levels.

Explanation:

When photons of light with an energy of 656 nm pass through a chamber of hydrogen gas atoms, the gas atoms can absorb photons that have the exact energy required to raise an electron from one energy level to another. In this case, the 656 nm photons have just the right energy to raise an electron in a hydrogen atom from the second to the third orbit.

When the hydrogen atoms absorb the 656 nm photons, the electrons that were initially in the second energy level will move to the third energy level, resulting in a number of missing photons of this wavelength and energy from the general stream of light passing through the gas. This phenomenon is known as absorption.

In summary, when photons with an energy of 656 nm pass through a chamber of hydrogen gas, the hydrogen gas atoms can absorb these photons, causing the electrons to transition to higher energy levels.

Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of gravity on blood flow.

Veins must counteract the force of gravity on blood flow. Unlike arteries that carry blood away from the heart under high pressure, blood in veins is under much lower pressure after passing through capillaries.

The presence of one-way valves in veins, particularly in the limbs, is crucial to ensure the unidirectional flow of blood back toward the heart. These valves, along with the help of muscle contractions, prevent backflow and assist venous return to the heart, overcoming the effects of gravity and the reduced pressure in the venous system.

By the time blood reaches the venules and veins, the pressure initially exerted by heart contractions has greatly decreased. The veins are equipped with thin walls, large lumens, and valves that work together with muscle contractions to promote the return of blood to the heart.

This system compensates for the low blood pressure and the pull of gravity that would otherwise hinder the upward movement of blood from the extremities.

Considering the Charles' law, the initial temperature was 390.34 K or 117.34 °C.

Definition of Charles's Law

Charles's Law consists of the relationship that exists between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. For a given amount of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

V÷T=k

Analyzing an initial state 1 and a final state 2, the following is true:

V₁÷T₁=V₂÷T₂

Initial temperature

In this case, you know:

Replacing in Charles' law:

2.30 L÷T₁= 1.75 L÷297 K

Solving:

2.30 L= (1.75 L÷297 K)× T₁

2.30 L÷ (1.75 L÷297 K)= T₁

390.34 K= 117.34 °C= T₁

Finally, the initial temperature was 390.34 K or 117.34 °C.

Answer:

The wave would move faster through the water than through the steam

Explanation:

A mechanical wave is a wave that is transmitted through the oscillations of the particles in a medium. The closer the particles in the medium are, the more efficient the transmission of the wave is (because the collisions between the particles are more frequent), and so the faster the wave.

For this reason, mechanical waves travel faster in liquids (such as water) than in gases (such as the steam): because particles in liquids are closer together than in gases, where they are more spread apart. Therefore, the correct choice is

The wave would move faster through the water than through the steam

The term mechanical advantage is used to described how effectively a simple machine works. Mechanical advantage is defined as the resistance force moved divided by the effort force used. In the lever example above, for example, a person pushing with a force of 30 lb (13.5 kg) was able to move an object that weighed 180 lb (81 kg). So the mechanical advantage of the lever in that example was 180 lb divided by 30 lb, or 6. The mechanical advantage described here is really the theoretical mechanical advantage of a machine. In actual practice, the mechanical advantage is always less than what a person might calculate. The main reason for this difference is resistance. When a person does work with a machine, there is always some resistance to that work. For example, you can calculate the theoretical mechanical advantage of a screw (a kind of simple machine) that is being forced into a piece of wood by a screwdriver. The actual mechanical advantage is much less than what is calculated because friction must be overcome in driving the screw into the wood.

Sometimes the mechanical advantage of a machine is less than one. That is, a person has to put in more force than the machine can move. Class three levers are examples of such machines. A person exerts more force on a class three lever than the lever can move. The purpose of a class three lever, therefore, is not to magnify the amount of force that can be moved, but to magnify the distance the force is being moved. As an example of this kind of lever, imagine a person who is fishing with a long fishing rod. The person will exert a much larger force to take a fish out of the water than the fish itself weighs. The advantage of the fishing pole, however, is that it moves the fish a large distance, from the water to the boat or the shore.

A typical cell membrane in an animal maintains a potential difference across the membrane of ΔV = 70 mV and the membrane has a thickness of about 8 nm. The capacitance of the membrane is about 1 microFarad per square cm. 

(B) If we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? Explain your reasoning.

Now, notice that:

[tex]Q=C\Delta V\\ \Delta V=E.L[/tex]

Where L is the thickness of the membrane.

We then can get the electric field by just using:

[tex]E=\frac{\Delta V}{L}=\frac{70\times10^{-3}}{8\times10^{-9}}=8.75\times10^{6}N.C^{-1}[/tex]

Now using the charge expression and plugging the the expression for [tex]\Delta V[/tex] into it and then solving for [tex]E[/tex] we get:

[tex]E=\frac{Q}{CL}[/tex]

Now let's multiply both denominator and numerator by [tex]\frac{1}{A}[/tex] this yields:

[tex]E=\frac{\sigma}{C_{\sigma}L}[/tex]

Where 

[tex]\sigma=\frac{Q}{A}\\ C_{\sigma}=\frac{C}{A}[/tex]

Notice that the value in the wording of the problem is no actually the capacitance, but the capacitance per area [tex]C_{\sigma}[/tex], also [tex]\sigma[/tex] is the charge density.

Let's transform [tex]C_{\sigma}[/tex] to [tex]\frac{farad}{m^2}[/tex]:

[tex]\frac{1\mu F}{cm^2}=\frac{1\times10^{-2}F}{m^2}[/tex]

Solving for  [tex]\sigma[/tex] we get:

[tex]sigma=E.C_{\sigma}.L=7\times10^{-4}\frac{Coulomb}{m^2}=7\times10^{-8}\frac{Coulomb}{cm^2}[/tex]

Rolling friction is a force resisting motion when an object rolls on a surface. An example could be a ball rolling or a tire.