the equation 8- 4X=0 has blank real solutions

Answers

Answer 1

Answer:

8-4x= 0 has only 1 solution

Step-by-step explanation:

This can only have one solution because there will only be one value that can set the equation equal to 0 that number is 2. -2 on the other hand will not work because you will get 8+8=0 which does not make sense so you can only have 1 solution.

Hope this helps


Related Questions

Find the next three terms in the geometric sequence -36, 6, -1, 1/6

Answers

Answer:

in fraction form: -1/36, 1/216, -1/1296

in decimal form: -.03, .005, -.0008

Step-by-step explanation:

Each term is the previous term divided by -6:

-36 ÷ -6= 6

6 ÷ -6= -1

and so on...

-1/36

The numbers divide by -6 each time

Arnob, Bella, Colin, Dante, and Erin are going to a baseball game. They have a total budget of $100.00 to spend. Each game ticket costs $17.50 and each drink costs $2.00. The inequality below relates x, the number of drinks the 5 friends could buy in all, with their ticket costs and budget. 5 (17.5) + 2 x less-than-or-equal-to 100 Which best describes the restrictions on the number of drinks they can buy?

Answers

Answer:

they can get at most 6 drinks

Step-by-step explanation:

5 (17.5) + 2x ≤100

87.5 + 2x≤100

2x≤ 12.5

x≤6.25

Answer:

0 to 6 drinks, but no more.

Step-by-step explanation:

Calculate the lateral area of the cube if the perimeter of the base is 12

Answers

Answer:

The lateral surface area of cube = 4

Step-by-step explanation:

Explanation:-

Given perimeter of the cube is 12

let 'a' be the base of cube

we know that the perimeter of cube formula = 12 a

        12 a= 12

           a = 1

The side of cube = 1cm

The lateral surface area of cube = 4 × a²

                                                      = 4 X (1)²

                                                      = 4

Final answer:-

The lateral surface area of cube = 4

The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below.

Assume the population is normally distributed.

2.3 3.1 2.8
1.7 0.9 4.0
2.1 1.2 3.6
0.2 2.4 3.2

Find the standard deviation

Answers

Answer:

[tex]\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29[/tex]

[tex] s=1.09[/tex]

Step-by-step explanation:

For this case we have the following data given:

2.3 3.1 2.8

1.7 0.9 4.0

2.1 1.2 3.6

0.2 2.4 3.2

Since the data are assumedn normally distributed we can find the standard deviation with the following formula:

[tex]\sigma =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}[/tex]

And we need to find the mean first with the following formula:

[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

And replacing we got:

[tex]\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29[/tex]

And then we can calculate the deviation and we got:

[tex] s=1.09[/tex]

Answer:

X ~ Norm ( 2.29167 , 1.09045^2 )

Step-by-step explanation:

Solution:-

- The (GPA) for 12 randomly selected college students are given as follows:

            2.3 , 3.1 , 2.8 , 1.7 , 0.9 , 4.0 , 2.1 , 1.2 , 3.6 , 0.2 , 2.4 , 3.2

- We are to assume the ( GPA ) for the college students are normally distributed.

- Denote a random variable X: The GPA secured by the college student.

- The normal distribution is categorized by two parameters:

- The mean ( u ) - the average GPA of the sample of n = 12. Also called the central tendency:

                        [tex]Mean ( u ) = \frac{\sum _{i=1}^{\ 12 }\: Xi }{n}[/tex]

Where,

           Xi : The GPA of the ith student from the sample

           n: The sample size = 12

          [tex]Mean ( u ) = \frac{2.3 + 3.1 + 2.8 + 1.7 + 0.9 + 4.0 + 2.1 + 1.2 + 3.6 + 0.2 + 2.4 + 3.2}{12} \\\\Mean ( u ) = \frac{27.5}{12} \\\\Mean ( u ) = 2.29167[/tex]

- The other parameter denotes the variability of GPA secured by the students about the mean value ( u ) - called standard deviation ( s ):

          [tex]s = \sqrt{\frac{\sum _{i=1}^{\ 12 }\: [ Xi - u]^2}{n} } \\\\\\\sum _{i=1}^{\ 12 }\: [ Xi - u]^2 = ( 2.3 - 2.29167)^2 + ( 3.1 - 2.29167)^2 + ( 2.8 - 2.29167)^2 + ( 1.7\\\\ - 2.29167)^2+ ( 0.9 - 2.29167)^2 + ( 4 - 2.29167)^2 + ( 2.1 - 2.29167)^2 + ( 1.2 - 2.29167)^2 +\\\\ ( 3.6 - 2.29167)^2 + ( 0.2 - 2.29167)^2 + ( 2.4 - 2.29167)^2 + ( 3.2 - 2.29167)^2 \\\\\\\sum _{i=1}^{\ 12 }\: [ Xi - u]^2 = 14.26916 \\\\\\s = \sqrt{\frac{ 14.26916 }{12} } \\\\s = \sqrt{1.18909 } \\\\s = 1.09045[/tex]

- The normal distribution for random variable X can be written as:

                 X ~ Norm ( 2.29167 , 1.09045^2 )

           

3. A small company has just bought two software packages to solve an accounting problem. They are called Fog and Golem. On first trials, Fog crashes 5% of the time and Golem crashes 10% of the time. Of 10 employees, 3 are assigned Fog and 7 are assigned Golem. Sophia was assigned a program at random. It crashed on the first trial. What is the probability that she was assigned Golem? Express your answer as a whole-number percentage.

Answers

Answer:

82%

Step-by-step explanation:

Final answer:

The probability that Sophia was assigned Golem given that her software crashed is approximately 82%, calculated using Bayes' Theorem.

Explanation:

When software crashes and we want to know the likelihood Sophia was using Golem, we need to consider both the probability of being assigned Golem and the probability of that software crashing. This is known as the application of Bayes' Theorem, which is a way to find conditional probabilities. In this case, we calculate as follows:

Probability of being assigned Golem (P(G)) = 7/10Probability of being assigned Fog (P(F)) = 3/10Probability Golem crashes (P(C|G)) = 0.10 or 10%Probability Fog crashes (P(C|F)) = 0.05 or 5%

We want to find the probability that Sophia was assigned Golem given that her software crashed (P(G|C)). We use the formula:

P(G|C) = (P(C|G) * P(G)) / (P(C|G) * P(G) + P(C|F) * P(F))

Inserting the above probabilities yields:

P(G|C) = (0.10 * 7/10) / ((0.10 * 7/10) + (0.05 * 3/10))

P(G|C) = 0.07 / (0.07 + 0.015)

P(G|C) = 0.07 / 0.085

P(G|C) = 0.8235 or approximately 82%

Expressed as a whole-number percentage, the probability that Sophia was using Golem is 82%.

The price of a tv was decreased by 20% to £1440. What was the price before the decrease?

Answers

Answer:

   £1800

Step-by-step explanation:

The lower price is 80% of the original, so the original price is ...

   £1440 = 0.80×original

   £1440/0.80 = original =  £1800

The price before the decrease was  £1800.

The measure of angle 2 is 126°, the measure of angle 4 is (7x)°, and the measure of angle 5 is (4x + 4)°. What is the measure of angle 7 to the nearest degree

Answers

Complete question:

CHECK ATTACHMENT FOR THE DIAGRAM.

Answer:

Angle 7 is 76°

Step-by-step explanation:

From the diagram, notice that angle 4 = angle 5

That is,

Δ4 = Δ2

Because vertically opposite angles are equal.

Δ4 = 7x

Δ2 = 126

So

126 = 7x

Divide both sides by 7

x = 126/7 = 18

Again, angle 5 = angle 7

Δ5 = Δ7

Because vertically opposite angles are equal.

Since Δ5 = (4x + 4)°

And x = 18

Then

Δ7 = 4(18) + 4 = 72 + 4 = 76°

Use​ Green's Theorem to evaluate the following line integral. Assume the curve is oriented counterclockwise The circulation line integral of Fequalsleft angle 4 xy squared comma 2 x cubed plus y right angle where C is the boundary of StartSet (x comma y ): 0 less than or equals y less than or equals sine x comma 0 less than or equals x less than or equals pi EndSet

Answers

Answer:

The answer is [tex]\pi(\pi-6)[/tex]

Step-by-step explanation:

Recall that green theorem is as follows: Given a field F(x,y) = (P(x,y),Q(x,y)) and a closed curve C that is counterclockwise oriented. If P and Q are continuosly differentiable, then

[tex]\oint_C F\cdot dr = \int_{R} \frac{\partial P }{\partial y}-\frac{\partial P }{\partial x} dA[/tex]

where R is the region enclosed by the curve C.

In this particular case, we have the following field [tex]F(x,y) = (4xy^2,2x^3+y)[/tex]. We are given the description of the region R as [tex]0\leq y \leq \sin(x), 0\leq x \leq \pi[/tex]. So, in this case (calculations are omitted)

[tex]\frac{\partial P}{\partial y} = 8xy, \frac{\partial Q}{\partial x} = 6x[/tex]

Thus,

[tex]\oint_C F\cdot dr =\int_{0}^{\pi}\int_{0}^{\sin(x)}(8xy-6x)dydx[/tex]

So,

[tex] \int_{0}^{\pi}\int_{0}^{\sin(x)}(8xy-6x)dydx=\int_{0}^{\pi}4x\left.y^2\right|_{0}^{\sin(x)}-6x\left.y\right|_{0}^{\sin(x)} = \int_{0}^{\pi} 4x\sin^2(x)-6x\sin(x)dx[/tex]

Since [tex]\sin^2(x) = \frac{1-\cos(2x)}{2}[/tex], then

[tex] \int_{0}^{\pi} 4x\sin^2(x)-6x\sin(x)dx = \int_{0}^{\pi} 2x(1-\cos(2x))-6x\sin(x)dx[/tex]

Consider the integrals

[tex] I_1 = \int_{0}^{\pi} x\cos(2x)dx, I_2 = \int_{0}^{\pi}x\sin(x)dx[/tex]

Then, by using integration by parts (whose calculations are omitted) we get

[tex]\int_{0}^{\pi} x\cos(2x) = \left.\frac{x\sin(2x)}{2}+\frac{\cos(2x)}{4}\right|_{0}^{\pi} = \frac{\pi\sin(2\pi)}{2}+\frac{\cos(2\pi)}{4}- \frac{0\sin(2\cdot 0)}{2}+\frac{\cos(2\cdot 0)}{4}=0[/tex]

[tex] \int_{0}^{\pi}x\sin(x) = \left.-x\cos(x)+\sen(x)\right |_{0}^{\pi} = -\pi\cos(\pi)+\sen(\pi)- (-0\cdot \cos(\pi)+\sin(0)) = \pi[/tex]

Then, we have that

[tex]\int_{0}^{\pi} 2x(1-\cos(2x))-6x\sin(x)dx = \left.x^2\right|_{0}^{\pi} -2I_1-6I_2 = \pi^2-2\cdot 0 -6\pi = \pi(\pi-6)[/tex]

The probability density function of the time to failure of an electronic component in a copier (in hours) is f(x)= e^-x/100 /1000. Determine the probability that



a. A component lasts more than 3000 hours before failure.


b. A component fails in the interval from 1000 to 2000 hours.


c. A component fails before 1000 hours


d. Determine the number of hours at which 10% of all components have failed.


e. Determine the cumulative distribution function for the distribution. Use the cumulative distribution function to determine the probability that a component lasts more than 3000 hours before failure.

Answers

Answer:

Check the explanation

Step-by-step explanation:

The fundamentals

A continuous random variable can take infinite values in the range associated function of that variable. Consider [tex]f\left( x \right)f(x)[/tex] is a function of a continuous random variable within the range [tex]\left[ {a,b} \right][a,b][/tex] , then the total probability in the range of the function is defined as:

[tex]\int\limits_a^b {f\left( x \right)dx} = 1 a∫b​ f(x)dx=1[/tex]

The probability of the function [tex]f\left( x \right)f(x)[/tex] is always greater than 0. The cumulative distribution function is defined as:

[tex]F\left( x \right) = P\left( {X \le x} \right)F(x)=P(X≤x)[/tex]

The cumulative distribution function for the random variable X has the property,

[tex]0 \le F\left( x \right) \le 10≤F(x)≤1[/tex]

The probability density function for the random variable X has the properties,

[tex]\\\begin{array}{c}\\{\rm{ }}f\left( x \right) \ge 0\\\\\int\limits_{ - \infty }^\infty {f\left( x \right)dx} = 1\\\\P\left( E \right) = \int\limits_E {f\left( x \right)dx} \\\end{array} f(x)≥0[/tex]

Kindly check the attached image below to see the full explanation to the question above.

When wiring a house, an electrician knows that the time she will take is given by the formula
Time = 2hour +12 mins per lightswitch
She charges her customers a call out fee of £35, plus £30 per hour.
How much should a customer be charged for wiring a house with 10 lightswitch?

Answers

Answer:

£155

Step-by-step explanation:

look at the formula

first solve 12 minutes per light switches

12*10(lightswitches)= 120 minutes

we know that 120 minutes = 2 hours

the task says that she charges £30 per hour

so, 2 hours+ 2 hours= 4 hours

now do

4*30= £120

120+35(call-out fee)= £155

I really hope this helped.



Triangle Q R S.

Complete the statements to apply the triangle inequality rule to the given triangle.

QS + QR >


QR + RS >


RS + QS >

Answers

Answer:

QS + QR > RS

QR + RS > QS

RS + QS > QR    

Step-by-step explanation:

    ∧ ∧

( Ф∨Ф)

Answer:

hm here <3

Step-by-step explanation:

1 RS

2 QS

3 QR

<3

Weaning weights are used to evaluate di erences in growth potential of calves. A random sample of 41 steer calves is taken from a large ranch. The sample yields a mean weaning weight of 578 with a standard deviation of 87 lbs. This particular ranch is targeting an average weaning weight of 610 lbs. Perform a hypothesis test using = 0:01 to determine if the average weaning weight of cows at this ranch is di erent than 610 lbs.

Answers

Answer:

We accept H₀  the weaning weights of cows at this ranch is 610 lbs

Step-by-step explanation:

We assume normal distribution

Population mean      μ₀  = 610  lbs

Population standard deviation     unknown

sample size  n = 41

degree of fredom    df = n - 1    df  =  41 - 1   df = 40

Sample mean    X = 578  lbs

Sample standard deviation   s  =  87

As we don´t know standard deviation of the population we will use t- student test, furthemore, as  we are looking for any difference upper and lower we are in presence of a two tails test

Test Hypothesis    Null  hypothesis    H₀                X  =  μ₀

Alternative hypothesis                         Hₐ                X  ≠  μ₀

Now at α  = 0,01 ,   df  = 40   and two tail test we find   t = 2,4347

We have in t table

30 df           t  =  2,457        for       α  = 0,01

60 df           t  = 2,390         for      α   = 0,01

Δ = 30               0,067

     10                    x  ??       x = 0,022

then  2,457  -  0,022  =  2,4347

t = 2,4347

Now we compute the interval:

X ±  t * ( s/√n)    ⇒   578  ±  2,4347 * ( 87/√41)

578  ±  2,4347 * 13,59

578  ±  33,09

P [ 578 + 33,09  ;  578 - 33,09 ]

P ( 611,09 ; 544,91]

We can see that vale 610 = μ₀   is inside the iinterval , so we accept H₀ the weaning weight of cows in the ranch is 610 lbs

Fresh cut flowers need to be in at least 4 inches of water. A spherical vase is filled until the surface of the water is a circle 5 inches in diameter. Is the water deep enough for the flowers?

Answers

The requried, water depth is less than the minimum required depth of 4 inches, and the water is not deep enough for the flowers.

To determine if the water depth in the spherical vase is sufficient for the flowers, we need to compare the height of the water to the minimum required depth of 4 inches.

Given that the surface of the water forms a circle with a diameter of 5 inches, we can calculate the radius of this circle by dividing the diameter by 2.

Radius = Diameter / 2

Radius = 5 inches / 2

Radius = 2.5 inches

Since the shape of the vase is spherical, the water depth will be equal to the radius.

Therefore, the water depth in the spherical vase is 2.5 inches.

Since the water depth is less than the minimum required depth of 4 inches, the water is not deep enough for the flowers.

Learn more about circle here:
https://brainly.com/question/15541011

#SPJ12

Final answer:

Given that the spherical vase’s surface water diameter is 5 inches, translating to a radius of 2.5 inches at the water's surface level, the maximum depth at the center might be close to 2.5 inches, falling short of the 4 inches required for fresh cut flowers. Therefore, the water is not deep enough for the flowers.

Explanation:

The question asks if the water in a spherical vase, with a surface diameter of 5 inches, is adequate (at least 4 inches deep) for fresh cut flowers. To determine this, we need to consider the properties of a sphere and how the depth of water relates to its diameter.

Since the diameter of the water's surface is given as 5 inches, the radius of the spherical vase (at the water's surface level) is 2.5 inches. The depth of the water in a spherical vase does not evenly translate to its diameter because the shape curves upwards from every point on its surface. However, considering that the vase is filled to a level where the diameter is 5 inches, we must acknowledge that the depth in the very center might be more but decreases as we move towards the edge of the water's surface.

Given the spherical shape, the maximum depth of the water could be close to the radius of 2.5 inches in the center, assuming the vase is filled to exactly half its height. This depth is less than the required 4 inches for fresh cut flowers. Therefore, without a specific height indication of the water level relative to the vase's total height, and based on the central depth potentially being 2.5 inches at most, it is unlikely the flowers would have the required 4 inches of water depth across the entirety of the vase's base.

A swimming pool is in the shape of a regular decagon. One edge of the pool is directly against the outside wall of a house. Find the measure x of the angle between the house and the pool.

Answers

Answer:

36 degrees.

Step-by-step explanation:

Total Sum of the Exterior Angle of a Regular Polygon[tex]=360^0[/tex]

One Exterior Angle of a n-sided regular polygon[tex]=\dfrac{360^0}{n}[/tex]

A decagon has 10 sides.

One Exterior Angle of a decagon[tex]=\dfrac{360^0}{10}=36^0[/tex]

Therefore, the measure x of the angle between the house and the pool is 36 degrees.

Final answer:

To find the measure x of the angle between the house and a pool shaped as a regular decagon, calculate the exterior angle of the decagon, which is 36 degrees. This is the angle measure sought in the question.

Explanation:

The question involves finding the measure x of the angle between the house and the pool, where the pool is in the shape of a regular decagon.

First, let's recall that a regular decagon is a ten-sided polygon with all sides and angles equal. The sum of the interior angles of any polygon can be calculated using the formula (n-2) × 180, where n is the number of sides. For a decagon, n = 10, so the sum of the interior angles is (10-2) × 180 = 1440 degrees. Since all angles in a regular decagon are equal, each interior angle measures 1440 ° / 10 = 144 °.

Now, to find the measure x of the angle between the house and the pool, we need to understand that the exterior angle of the decagon will be involved, as this is the angle made between one side of the decagon (lying against the house) and an extension of an adjacent side. The measure of an exterior angle of a regular polygon is 360 ° / n. For our decagon, this is 360 ° / 10 = 36 °.

Therefore, the measure x of the angle between the house and the pool is 36 °, which is the measure of the exterior angle of the regular decagon.

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