Answer:
10
3.4641
2.8965
12.8965
Step-by-step explanation:
Given: 10, 8, 12, 15, 13, 11, 6, 5
c = 95%
a. The point estimate of the population mean is the sample mean. The mean is the sum of all values divided by the number of values:
x = 10 + 8 + 12 + 15 + 13 + 11 + 6 + 5 /8
= 80/8
= 10
b. The point estimate of the population standard deviation is the sample standard deviation. The variance is the sum of squared deviations from the mean divided by n - 1. The standard deviation is the square root of the variance:
s = /(10 – 10)^2 +.... + (5– 10)^2/8 – 1
s = 3.4641
c. Determine the t-value by looking in the row starting with degrees of freedom df = n-1 = 8 –1 = 7 and in the column with [tex]\alpha[/tex] = (1 – c)/2 = 0.025 in table :
t_[tex]\alpha[/tex]/2 = 2.365
The margin of error is then:
E = t_[tex]\alpha[/tex]/2 * s/√n
= 2.365 x s 3.4641/ √8
= 2.8965
d. The confidence intent)] then becomes:
7.1035 = 10 – 2.8965 = x – E <u<x +E= 10 + 2.8965 = 12.8965
The point estimate of the population mean will be 10.
How to calculate the point estimate?The point estimate of the population mean will be calculated thus:
= (10 + 8 + 12 + 15 + 13 + 11 + 11 + 6 + 5) / 8
= 80/8
= 10
Also, the margin of error will be:
= 2.365 × 3.4641/✓8
= 2.8965
In conclusion, the margin of error is 2.8965.
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Find the area of the fairway between two streams on a golf course
A particular solution and a fundamental solution set are given for the nonhomogeneous equation below and its corresponding homogeneous equation. (a) Find a general solution to the nonhomogeneous equation. (b) Find the solution that satisfies the specified initial conditions.
y(1)--2, y'(1)-1, and y'(1)--36
Answer:
A.y=2x^5 + c1+ c2x + c3x^5
B. Y = 2x² + 9+7x+2x^5
Step-by-step explanation:
See attached file
5/4 - 4/4 ples tell me
The value of the expression 5/4 - 4/4 will be equal to 1 / 4.
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
The given expression is ( 5 / 4) - ( 4 / 4). The value of the expression will be solved as,
E = 5 / 4 - 4 / 4
E = (5 - 4) / 4
E = 1 / 4
Therefore, the value of the expression 5/4 - 4/4 will be equal to 1 / 4.
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Place all the nummbers from 1 to 6
Answer:
Step-by-step explanation:
1 2 3 4 5 6
Find the radius of a circle with an area of 529π square inches.
Answer:
Step-by-step explanation:
Given
Area (A) = 529[tex]\pi[/tex] square inch
radius(r) =?
Now
we have the formula
[tex]\pi r^{2} = area[/tex]
[tex]\pi r^{2} = 529\pi[/tex]
Both pie will be cancelled and we get
[tex]r^{2} = 529[/tex]
[tex]r =\sqrt{529}[/tex]
r = 23 inch
Hope it helped:)
"The correct answer is 14 inches.
To find the radius of a circle given its area, one can use the formula for the area of a circle, which is [tex]\( A = \pi r^2 \)[/tex], where[tex]\( A \)[/tex] is the area and[tex]\( r \)[/tex] is the radius.
Given that the area [tex]\( A \) is \( 529\pi \)[/tex] square inches, we can set up the equation:
[tex]\[ 529\pi = \pi r^2 \][/tex]
To solve for \( r \), we can divide both sides of the equation by [tex]\( \pi \)[/tex]:
[tex]\[ r^2 = \frac{529\pi}{\pi} \][/tex]
[tex]\[ r^2 = 529 \][/tex]
Taking the square root of both sides gives us the radius:
[tex]\[ r = \sqrt{529} \][/tex]
[tex]\[ r = 23 \][/tex]
Therefore, the radius of the circle is 23 inches. However, the question states that the correct answer is 14 inches. This discrepancy arises because the square root of 529 is actually 23, not 14. It seems there was a mistake in the provided answer. The correct radius, based on the calculation, should indeed be 23 inches, not 14 inches."
If you are a student with no assets of any value and have liability insurance on an old car that pays a maximum of $50,000 per accident, what is most likely to happen if you cause an accident that results in $75,000 in damage to the passengers in another car?
A. They will not pursue any action against you or your insurance company
B. They will sue you, personally, for more than $100,000
C. They will accept the $50,000 maximum offered by your insurance company
D. They will sue for the entire $75,000
Answer:
They will accept the $50,000 maximum offered by your insurance company
In this scenario, with $50,000 liability insurance, if you cause a $75,000 accident, the other party is likely to accept the $50,000 from your insurance (Option C) but could also sue you for the remaining $25,000 (Option D).
In this scenario, if you cause an accident resulting in $75,000 in damage to the passengers in another car, your liability insurance has a maximum coverage limit of $50,000 per accident. Typically, insurance policies cover up to the policy limits, and the insurance company would pay out up to $50,000 to the injured parties.
The most likely outcome in this situation would be that the injured parties may initially pursue a claim with your insurance company, and the insurance company would pay up to its policy limit of $50,000. However, since the damages exceed the policy limit, the injured parties may still have the option to sue you personally for the remaining $25,000 to cover their damages.
So, the answer could be a combination of options C and D: They may accept the $50,000 maximum offered by your insurance company but could also potentially sue you for the remaining $25,000 if they believe it's necessary to cover their damages. The actual outcome may vary depending on the specific circumstances, local laws, and the decisions made by the injured parties and their legal advisors. It's crucial to notify your insurance company as soon as an accident occurs so they can handle the situation accordingly.
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is 0 an irrational
number
Answer: no
Step-by-step explanation:
0 is a rational number.A rational number is a number that can be expressed as the quotient or fraction m/n of two integers, a numerator m and a non-zero denominator n.0 can be expressed as 0/n ;therefore 0 is a rational number.SpymoreSimplify the expression 13+(x+8)=?
Answer:
x +21
Step-by-step explanation:
13+(x+8)=
Combine like terms
x +13+8
x +21
what does 3(7y − 1) =
Answer: 21y-3
Step-by-step explanation:
3(7y-1)=
3(7y)-3(1)=
21y-3
Answer: 21y-3
Step-by-step explanation: The way to get a answer out of this problem you have to multiply 3 time 7, and 1 then subtract the two numbers you get which is 21y and 3 and the problem with this question is that you can’t subtract because of the variable but sense they aren’t the same put the answer like this 21y-3 hope this helps!
Which transformation will result in an image which is similar, but not congruent, to the pre image
Answer:
Dilation
Step-by-step explanation:
The type of transformation that will produce a similar, but not congruent figure is a dilation. A dilation is a transformation , with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'.
Affine Transformation and Similarity Transformation are essential in creating images that are similar but not congruent. Linear transformations play a role in maintaining the properties of lines and parallelism in geometric transformations.
Affine Transformation is a type of transformation that can result in an image that is similar but not congruent to the pre-image. It involves accommodating differences in scale, rotation, and offset along each dimension of the coordinate systems.
A similarity transformation can also be used, which involves a rotation with an angle, scale change, and translation. It preserves the shape but not necessarily the size.
Linear transformations, as in the case of similar transformations, are essential in transforming lines into lines and preserving parallel lines. These transformations play a crucial role in mathematical concepts related to geometry and spatial transformations.
jackie makes 15 dollars an hour by babysitting. George makes 18.50 for mowing the lawn. if jackie babysits for 4 hrs and george mows the lawn for 3 hours. who makes more money?
Answer:
Jackie
Step-by-step explanation:
Find how much each person makes by multiplying their hourly wage by hours worked
Jackie
hourly wage * hours worked
15*4=60
$60
George
hourly wage * hours worked
18.50*3=55.5
$55.50
Jackie made more money because 60>55.5
After calculating the total earnings, Jackie makes more money ($60) than George ($55.50) based on their hourly rates and the number of hours worked.
The student asks who makes more money, Jackie who makes $15 an hour for babysitting and works for 4 hours, or George who makes $18.50 an hour for mowing the lawn and works for 3 hours. To solve this, let's calculate the total money each person makes:
Jackie's earnings: 4 hours * $15/hour = $60George's earnings: 3 hours * $18.50/hour = $55.50Comparing the earnings, Jackie makes a total of $60, while George makes $55.50. Therefore, Jackie makes more money than George after their respective hours of work.
if a rabbit can move 4/5 of a mile every hour then how many hours would it take for a rabbit to go 8 Miles
A study found that 1% of Social Security recipients are too young to vote. If 800 social security recipients are randomly selected find the Mean, Variance and the Standard deviation of social security recipients who are too young to vote. Present your answer in two decimal places and in order: mean, Variance, Standard deviation.
Answer:
8, 7.92, 2.81
Step-by-step explanation:
For each Social Security recipient, there are only two possible outcomes. Either they are too young to vote, or they are not. The probability of a Social Security recipient is independent of any other Social Security recipient. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The variance of the binomial distribution is:
[tex]V(X) = np(1-p)[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
In this problem, we have that:
[tex]n = 800, p = 0.01[/tex]
So
Mean:
[tex]E(X) = np = 800*0.01 = 8[/tex]
The variance of the binomial distribution is:
[tex]V(X) = np(1-p) = 800*0.01*0.99 = 7.92[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{800*0.01*0.99} = 2.81[/tex]
Formatted answer: 8, 7.92, 2.81
For a certain candy, 20% of the pieces are yellow, 5% are red, 5% are blue, 10% are green, and the rest are brown. a) If you pick a piece at random, what is the probability that it is brown? it is yellow or blue? it is not green? it is striped? b) Assume you have an infinite supply of these candy pieces from which to draw. If you pick three pieces in a row, what is the probability that they are all brown? the third one is the first one that is red? none are yellow? at least one is green?
Answer:
A) i) the probability it is brown = 60%. (ii)The probability it is yellow or blue = 25% (iii) The probability it is not green = 90% (iv)The probability it is striped =0%
B) i)The probability they are all brown = 21.6%. (ii) Probability the third one is the first one that is red = 4.51% (iii) Probability none are yellow = 51.2% (iv) Probability at least one is green = 27.1%
Step-by-step explanation:
A) The probability that it is brown is the percentage of brown we have. However, Brown is not listed, so we subtract what we are given from 100%. Thus;
100 - (20 + 5 + 5 + 10) = 100 - (40) = 60%.
The probability that one drawn is yellow or blue would be the two percentages added together: 20% + 5% = 25%.
The probability that it is not green would be the percentage of green subtracted from 100: 100% - 10% = 90%.
Since there are no striped candies listed, the probability is 0%.
B) Due to the fact that we have an infinite supply of candy, we will treat these as independent events.
Probability of all 3 being brown is found by taking the probability that one is brown and multiplying it 3 times. Thus;
The percentage of brown candy is 60% from earlier. Thus probability of all 3 being brown is;
0.6 x 0.6 x 0.6 = 0.216 = 21.6%
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100% - 5% = 95% = 0.95
Now, for the first two and the probability that it is red = 5% = 0.05
Thus for the last being first one to be red = 0.95 x 0.95 x 0.05 = 0.0451 = 4.51%.
The probability that none are yellow is found by raising the probability that the first one is not yellow, 100 - 20 = 80%=0.80, to the third power:
0.80³ = 0.512 = 51.2%.
The probability that at least one is green is; 1 - (probability of no green).
We first find the probability that all three are NOT green:
0.90³ = 0.729
1 - 0.729 = 0.271 = 27.1%.
Final answer:
To find the probability of an event happening, divide the number of favorable outcomes by the total number of possible outcomes. The probability that a candy is brown is 60%, the probability that it is yellow or blue is 25%, the probability that it is not green is 90%, and the probability that it is striped cannot be determined without additional information. If the candies are replaced after picking, the probability of three brown candies in a row is 21.6%, the probability of the third candy being the first red candy is 5%, the probability of no yellow candies is 90.25%, and the probability of at least one green candy is 27.1%.
Explanation:
To find the probability of an event occurring, we divide the number of favorable outcomes by the total number of possible outcomes.
a) The probability of picking a brown candy is 100% - (20% + 5% + 5% + 10%) = 60%. The probability of picking a yellow or blue candy is 20% + 5% = 25%. The probability of not picking a green candy is 100% - 10% = 90%. The probability of picking a striped candy is not given in the question, so we cannot calculate it.
b) If the candies are replaced after picking, the probability of picking three brown candies in a row is (60%)^3 = 21.6%. The probability of the third candy being the first red candy is the same as the probability of picking a red candy, which is 5%. The probability of none of the candies being yellow is (100% - 5%)^2 = 90.25%. The probability of at least one candy being green is 1 - (100% - 10%)^3 = 27.1%.
Ahalyzing Sluuenl WUIN
Which error did Mathieu make?
Mathieu is finding the x-intercepts of the function
f(x) = x2 + 4x + 3. His work is shown below.
He factored incorrectly.
He did not use the constant as the x-intercept.
He set the factored expressions equal to each other.
He incorrectly solved the equation x + 3 = x + 1.
1.0 = x2 + 4x + 3
2.0 = (x + 3)(x + 1)
3. x + 3 = x + 1
4. x= x-2
5.0=-2
6. There are no x-intercepts.
Answer: he set the factored expressions equal to each other
Step-by-step explanation:
Answer:he set the factored expressions equal to each other.
Step-by-step explanation:
Write a real-world problem that can be represented by the equation 1/2x+6=20
Step-by-step explanation:
The given expression in word problem can be translated as:
Six more than half of a number is 20
A real-world problem for the equation 1/2x + 6 = 20 could be determing the number of days a person should work, earning a rate of half the square of the number of days, to achieve a total sum of $20. The person initially has $6 and after working for 28 days, he or she achieves the goal.
Explanation:Consider a real-world example represented by the equation 1/2x + 6 =20. Imagine your grandmother gives you $6 and says you can do chores for her on some days to earn half the square of the number of days you worked in dollars. If you want to accumulate $20 in total, how many days should you work? This problem asks the same as solving for 'x' in the equation where 'x' is the number of days and the total sum of money is $20.
To solve this, you would need to subtract 6 from both sides of the equation, leaving you with 1/2x =14. Then, you multiply both sides by 2 to get x = 28, so it takes 28 days of work.
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What is the midpoint of EC ?
A: (t + p, r)
B: (p – t, r)
C: (2p – 2t, r)
D: (p, r)
Given:
Given that the graph OACE.
The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)
We need to determine the midpoint of EC.
Midpoint of EC:
The midpoint of EC can be determined using the formula,
[tex]Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})[/tex]
Substituting the coordinates E(2t,0) and C(2p, 2r), we get;
[tex]Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})[/tex]
Simplifying, we get;
[tex]Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})[/tex]
Dividing, we get;
[tex]Midpoint=(t+p,r)[/tex]
Thus, the midpoint of EC is (t + p, r)
Hence, Option A is the correct answer.
) The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second). a. Find the probability that the demand will exceed 120 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.) b. What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.09? (Round your answer to two decimal places.)
Answer:
a) 0.3012 = 30.12% probability that the demand will exceed 120 cfs during the early afternoon on a randomly selected day.
b) 240.79 cfs.
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
In this problem, we have that:
[tex]m = 100, \mu = \frac{1}{100} = 0.01[/tex]
a. Find the probability that the demand will exceed 120 cfs during the early afternoon on a randomly selected day.
This is [tex]P(X > 120)[/tex]
[tex]P(X > 120) = e^{-0.01*120} = 0.3012[/tex]
0.3012 = 30.12% probability that the demand will exceed 120 cfs during the early afternoon on a randomly selected day.
b. What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.09?
We want x for which
[tex]P(X > x) = 0.09[/tex]
So
[tex]e^{-0.01x} = 0.09[/tex]
[tex]\ln{e^{-0.01x}} = \ln{0.09}[/tex]
[tex]-0.01x = \ln{0.09}[/tex]
[tex]0.01x = -\ln{0.09}[/tex]
[tex]x = -\frac{\ln{0.09}}{0.01}[/tex]
[tex]x = 240.79[/tex]
So 240.79 cfs.
The probability that the demand will exceed 120 cfs is approximately 30.12%. To ensure that the demand won't exceed capacity on 91% of early afternoons, the water-pumping station should maintain a capacity of approximately 230 cfs.
Explanation:a. Finding the Probability That Demand Will Exceed 120 cfsThe mean (λ) of the exponential distribution equals the rate (1/λ), which in this case is 100 cfs. To find the probability that the demand will exceed 120 cfs, we need to calculate the cumulative distribution function (CDF) for 120 cfs and subtract it from 1. The formula for the CDF is F(x) = 1 - e^(-λx). Replacing x with 120 and λ with 1/100, we get: F(120) = 1 - e^(-120/100) = 1 - e^-1.2. The value of e^-1.2 is approximately 0.3012. Thus, F(120) = 1 - 0.3012 = 0.6988. Therefore, the probability that the demand will exceed 120 cfs is 0.3012 or 30.12%, rounded to four decimal places.
b. Finding the Water-Pumping Capacity Needed to Limit the Probability of Exceeding Demand to 0.09We want to find the volume of water (x) such that the probability that the demand will exceed x is 0.09. To do this, we set F(x) = 1 - 0.09 (or 0.91), and use the CDF formula: F(x) = 1 - e^(-λx). Solving the equation 0.91 = 1 - e^(-x/100) for x yields x = -100ln(1 - 0.91) cfs, which when calculated equals 230 cfs, rounded to two decimal places. Therefore, the water-pumping capacity that should be maintained during early afternoons is approximately 230 cfs.
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Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable? Round your answer to four decimal places.
Answer:
0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
[tex]\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34[/tex]
What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?
pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So
X = 990
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{990 - 975}{9.34}[/tex]
[tex]Z = 1.61[/tex]
[tex]Z = 1.61[/tex] has a pvalue of 0.9463
X = 960
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{960 - 975}{9.34}[/tex]
[tex]Z = -1.61[/tex]
[tex]Z = -1.61[/tex] has a pvalue of 0.0537
0.9463 - 0.0537 = 0.8926
0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable
Please Hurry 20 Points. Use your knowledge of scale drawings and image sizes to fill in the missing information in the table.
Empire State Building
Original Image
Actual Height (in feet)
1,450
1,450
1,450
Reduced Image
Model Height (in blocks)
145
Scale Factor
1/25
1 /50
Answer:
it 1595
Step-by-step explanation:
For the reduced image with a scale factor of 1/25, the model height is 58 blocks; with a 1/50 scale, it's 29 blocks.
To fill in the missing information, we can use the scale factor to calculate the model height for the reduced image.
For the reduced image with a scale factor of [tex]\( \frac{1}{25} \)[/tex], we can calculate the model height by dividing the actual height by the scale factor:
[tex]\[ \text{Model Height} = \frac{\text{Actual Height}}{\text{Scale Factor}} \][/tex]
[tex]\[ \text{Model Height} = \frac{1450}{25} = 58 \text{ blocks} \][/tex]
For the reduced image with a scale factor of [tex]\( \frac{1}{50} \)[/tex], we repeat the calculation:
[tex]\[ \text{Model Height} = \frac{1450}{50} = 29 \text{ blocks} \][/tex]
Now, the completed table looks like this:
| | Original Image | Reduced Image |
|-------------|----------------|---------------|
| Actual Height (in feet) | 1,450 | 1,450 |
| Model Height (in blocks) | - | 58 (1/25 scale) |
| | - | 29 (1/50 scale) |
Thus, the missing information in the table has been filled in using the scale factor and calculations based on the actual height of the Empire State Building.
Karla spent 9/2 hours of her time for preparing the exam and 5/2 hours on homework per day. If she sleeps 7 hours per day, how many spare hours does she have?
Answer:
2 hours if they go to school.
10 hours if they dont go to school.
Step-by-step explanation:
add up the hours.
9/2+5/2=14/2=7hours +7 hour of sleep= 14 hours.
if they go to school for 8 hours then add 8. then it =22 hours witch gives you 2 hours
if they dont go to school then you got 24-14 hours=10 hours.
Data on the numbers of hospital admissions resulting from motor vehicle crashes are given below for Fridays on the 6th of a month and Fridays on the following 13th of the same month. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Construct a 95% confidence interval estimate of the mean of the population of differences between hospital admissions. Use the confidence interval to test the claim that when the 13th day of a month falls on a Friday, the numbers of hospital admissions from motor vehicle crashes are not affected.
Answer:
a) 95% confidence interval estimate of the mean of the population of differences between hospital admissions = (1.69, 11.91)
b) This confidence interval shows there is indeed a significant difference between the number of hospital admissions from motor vehicle crashes on Friday the 13th and the number of hospital admissions from motor vehicle crashes on Friday the 6th as the interval obtained doesn't contain a zero-value of difference.
Hence, the claim that when the 13th day of a month falls on a Friday, the numbers of hospital admissions from motor vehicle crashes are not affected is not true.
Step-by-step explanation:
The missing data from the question
The numbers of hospital admissions from motor vehicle crashes
Friday the 6th || 10 | 8 | 4 | 4 | 2
Friday the 13th | 12 | 10 | 12 | 14 | 14
The differences can then be calculated (number on the 13th - number on the 6th) and tabulated as
Friday the 6th || 10 | 8 | 4 | 4 | 2
Friday the 13th | 12 | 10 | 12 | 14 | 14
Differences ||| 2 | 2 | 8 | 10 | 12
To obtain the confidence interval, we need the sample mean and sample standard deviation.
Mean = (Σx)/N
= (2+2+8+10+12)/5 = 6.80
Standard deviation = σ = √[Σ(x - xbar)²/N]
Σ(x - xbar)² = (2-6.8)² + (2-6.8)² + (8-6.8)² + (10-6.8)² + (12-6.8)² = 84.8
σ = √[Σ(x - xbar)²/N] = √(84.8/5) = 4.12
Confidence Interval for the population's true difference between the number of hospital admissions from motor vehicle crashes on Friday the 6th and Friday the 13th is basically an interval of range of values where the population's true difference can be found with a certain level of confidence.
Mathematically,
Confidence Interval = (Sample true difference) ± (Margin of error)
Sample Mean = 6.8
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error of the sample true difference)
Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.
To find the critical value from the t-tables, we first find the degree of freedom and the significance level.
Degree of freedom = df = n - 1 = 5 - 1 = 4.
Significance level for 95% confidence interval
(100% - 95%)/2 = 2.5% = 0.025
t (0.025, 4) = 2.776 (from the t-tables)
Standard error of the mean = σₓ = (σ/√n)
σ = standard deviation of the sample = 4.12
n = sample size = 5
σₓ = (4.12/√5) = 1.84
95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]
CI = 6.8 ± (2.776 × 1.84)
CI = 6.8 ± 5.10784
95% CI = (1.69216, 11.90784)
95% Confidence interval = (1.69, 11.91)
b) This confidence interval shows there is a significant difference between the number of hospital admissions from motor vehicle crashes on Friday the 13th and the number of hospital admissions from motor vehicle crashes on Friday the 6th as the interval obtained doesn't contain a difference of 0.
Hope this Helps!!!
Which number is bigger? 0.183 or 0.18
Answer:
.183 give me brainliest
Step-by-step explanation:
Find each value and measure. Assume that segments that appear to be tangent are tangent.
Given:
Given that AC and BD are chords of the circle.
The two chords intersect at the point E which makes an angle 93°
The measure of arc BC is 161°
We need to determine the measure of arc AD.
Measure of arc AD:
The measure of arc AD can be determined using the property that "if two chords intersect in the interior of the circle, then the measure of each angle is half the sum of the arcs intercepted by the angles and its vertical angle".
Thus, applying the above theorem, we have;
[tex]m \angle E=\frac{1}{2}(m \widehat{BC}+m \widehat{AD})[/tex]
Substituting the values, we have;
[tex]93^{\circ}=\frac{1}{2}(161^{\circ}+m \widehat{AD})[/tex]
[tex]186^{\circ}=161^{\circ}+m \widehat{AD}[/tex]
[tex]25^{\circ}=m \widehat{AD}[/tex]
Thus, the measure of arc AD is 25°
Arc angle AD is 25 degrees
What are secant:Secant are lines that intersect a circle at two points.
Secant AC intersect secant BD at angle 93 degree.
Using secant rule , in circle theorem,
93° = 1 /2 (arcBC + arcAD)Therefore,
93° = 1 / 2(AD + 161)
93 = AD / 2 + 161 / 2
93 = AD + 161/ 2
cross multiply
186 = AD + 161
AD = 186 - 161
arc AD = 25°
learn more on secant here:https://brainly.com/question/14290293?referrer=searchResults
7/15+(-5/6)
What is the answer and how do I get it
-11/30
Step-by-step explanation: Create a common denominator (30) and then subtract
What is the solution to the system of equations graphed below?
A. (2, 4)
B. (4, 2)
C. (0, 6)
D. (6, 0)
Given:
Given that the graph of the system of equations.
We need to determine the solution to the system of equation.
Solution:
The solution to the system of equations is the point of intersection of these two lines.
The point of intersection of the two lines in the graph is the point at which the two lines meet.
From the graph, it is obvious that the two lines intersect at a common point.
Thus, the common point is the point of intersection of the two lines.
Hence, the point of intersection is (4,2)
Thus, the solution to the system of equation is (4,2)
Therefore, Option B is the correct answer.
Answer:
its B (4,2)
Step-by-step explanation:
A hang glider is soaring over a 100-acre area that consists of thick forest and open fields. In the diagram below, the forested area is shaded in green and the open field is the white space. Upon landing, the hang glider realizes she has dropped her keys.
Answer:
the answer will be 0.8
Step-by-step explanation:
hard to explain
Answer:
C. 0.8
Step-by-step explanation:
A large moving box has a volume of 45 cubic meters. The width of the box i:
1.5 meters. The length and the height of the box are each whole number
measurements that are greater than 2 meters. What could be the dimension
the box? Give two possible answers,
Answer:
3x10, 6x5
Step-by-step explanation:
45 / 1.5 = 30
Find any two factors of 30 and you have an answer.
2x15 and 1x30 don't work because they are less than or equal to 2.
Answer:
3x10x1.5, 6x5x1.5
Step-by-step explanation:
45 / 1.5 = 30
Find any two factors of 30 and you have an answer.
2x15 and 1x30 don't work because they are less than or equal to 2.
Suppose shirts are one of 3 colors (red, blue, and purple) and pants are black, brown, or white. An outfit consists of a shirt and pants. What is the minimum number of people that need to be in a room together to guarantee that at least two of them are wearing same-colored outfits
Answer:
10 people
Step-by-step explanation:
Given:
Colors of shirts: 3 (red, blue, and purple)
Colors of pants: 3 (black, brown, or white)
Total number of outfits ( both shirts and pants) =
3 * 3 = 9
The minimum number of people that need to be in a room together to guarantee that at least two of them are wearing same-colored outfits will be:
Total number + 1
= 9 + 1
= 10 people
A small private college is interested in determining the percentage of its students who live off campus and drive to class. Specifically, it was desired to determine if less than 20% of their current students live off campus and drive to class. Find the large-sample rejection region for the test of interest to the college when using a level of significance of 0.01.
Answer:
The rejection region is the one defined by z<-2.326.
Step-by-step explanation:
We have to calculate the critical value for a test of hypothesis on the proportion of students of this college who live off campus and drive to class.
The sample is large enough, so we can use the z-statistic.
As the claim, taht will be stated in the alternative hypothesis, is that less than 20% of their current students live off campus and drive to class, the test is left tailed.
Alternative hypothesis:
[tex]Ha: \pi<0.20[/tex]
Then, for a significance level of 0.01, 99% of the data has to be over (or 1% below) this critical z-value.
In the standard normal distribution this z-value is z=-2.326.
[tex]P(z<-2.326)=0.01[/tex]
The critical value that divide the regions is z=-2.326. The rejection region is the one defined by z<-2.326.
To determine if less than 20% of students at a college live off campus and drive to class with a significance level of 0.01, we would reject the null hypothesis if the z-score is less than approximately -2.33. This critical value corresponds to the 1% left tail cut-off point on the standard normal distribution.
The question concerns conducting a hypothesis test to determine if less than 20% of students at a small private college live off campus and drive to class, using a level of significance of 0.01. The rejection region for this one-sided test is determined by finding the critical z value that corresponds to the significance level of 0.01. Since the test is left-tailed, we look for the z score that cuts off 1% of the area in the left tail of the standard normal distribution.
Using the standard normal distribution table, the critical value z* that cuts off the lower 1% of the distribution is approximately -2.33. Therefore, if the test statistic calculated from the sample data is less than -2.33, we would reject the null hypothesis and conclude that there is significant evidence to suggest that less than 20% of students live off campus and drive to class.
This method ensures that the null hypothesis is only rejected when there is sufficient evidence against it, as more conservative research would deem necessary at the 0.01 level of significance.