Answer:
A. 30 meters
Step-by-step explanation:
Let's find the answer.
The problem established a quadratic relationship between height (h) and time (t), then we can establish:
h(t)=K*t where 'K' is a coefficient.
Because an experiment was done, we can find 'K' as follows:
h(t)=K*t
90meters=K*(3seconds)
90meters/3seconds=K
30m/s=K
Now we can solve the problem, so for 2 seconds:
h(t)=K*t
h(t)=(30m/s)*(2s)
h(t)=60m
But notice that the obtained 60 meters are the distance traveled in 2 seconds from the top the building to the ground. So 'how far from the ground' can be calculated as:
(far from the ground) = (total building height) - (distance traveled in 2s)
(far from the ground) = 90m - 60m = 30m
In conclusion, after 2 seconds, the ball is 30 meters far from the ground. The answer in then A. 30 meters.
Answer:
40 meters
Step-by-step explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{90-\frac{1}{2}\times 9.81\times 3^2}{3}\\\Rightarrow u=15.285\ m/s[/tex]
u = 15.285 m/s
[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow s=15.285\times 2+\frac{1}{2}\times 9.81\times 2^2\\\Rightarrow s=50.19\ m[/tex]
The ball has fallen 50.19 m from the top of the building.
So, the ball is 90-50.19 = 39.81 = 40 meters off the ground
If X || Y and Y || Z then___
Answer:
X is parallel to Z
X || Z
Step-by-step explanation:
This is called the transitive property.
It says something like:
If f is related to g and g is related to h, then f is related to h.
The parallel relationship is transitive.
That is,
if X is parallel to Y and Y is parallel to Z, then X is parallel to Z.
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy claims that the scatterplot could have a nonlinear association. Which statement about their claims is true?
Joseph is correct because only a line will increase along the whole data set. The scatterplot will have a positive, linear association.
Joseph is correct because only a line will decrease along the whole data set. The scatterplot will have a negative, linear association.
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
Amy is correct because only a nonlinear association could increase along the whole data set. A line has the same slope at any point, but a curve can get steeper at different points.
Answer:
The answer is C
Step-by-step explanation:
Answer:
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
Step-by-step explanation:
Both linear and nonlinear associations could increase along the whole data set. That's why Joseph and the fourth option are incorrect.
what is the domain of this function?
Answer:
x ≥ 0
Step-by-step explanation:
The domain of the function is the inputs, or in this case, the x values.
The inputs are x greater than or equal to zero all the way to infinity.
Answer:
Step-by-step explanation:
The domain includes 0 and all real numbers greater than 0: x ≥ 0
Polygon ABCD is translated to create polygon A’B’C’D’. Point A is located at (1,5), and point A’ is located at (-2,3). Which expression defines the transformation of any point (x,y) to (x’,y’) on the polygons?
Answer:
The expression is (x,y) -----> (x-3,y-2)
Step-by-step explanation:
we have that
A(1,5) ----> A'(-2,3)
so
The rule of the translation is equal to
(x,y) -----> (x',y')
(x,y) -----> (x-3,y-2)
That means-----> the translation is 3 units at left and 2 units down
A triangular field has sides of 120.32 m and 204.61 m, and the angle between them measures 60.881°. Find the area of the field
Answer:
A=10753.5715 m^2.
Step-by-step explanation:
The area of a triangle with the information SAS given is:
A=1/2 * (side) * (other side) * sin(angle between)
A=1/2 * (204.61)*(120.32) * sin(60.881)
A=10753.5715 m^2.
SAS means two sides with angle between.
Answer: [tex]10,753.57\ m^2[/tex]
Step-by-step explanation:
You need to use the SAS area formula. This is:
[tex]A=\frac{a*b*sin(\alpha)}{2}[/tex]
You know that the triangular field has sides of 120.32 meters and 204.61 meters and the angle between them measures 60.881°. Then:
[tex]a=120.32\ m\\b=204.61\ m\\\alpha =60.881\°[/tex]
Substituting these values into the formula, you get that the area of this triangle is:
[tex]A=\frac{(120.32\ m)(204.61\ m)*sin(60.881\°)}{2}\\\\A=10,753.57\ m^2[/tex]
evaluate 3^-3 please explain
Answer:
D) 1/27
Step-by-step explanation:
The question is: 3^(-3).
Note that there is a negative sign in the number at the power place. This means that you must flip the number, and in this case, put it over 1. The rest is solved as usual:
3^-3 = 1/(3^3) = 1/(3 * 3 * 3) = 1/27
1/27, or D) is your answer.
~
Using the given points and line, determine the slope of the line.
(1, 2) and (2, 1)
Answer:
-1
Step-by-step explanation:
To find the slope of a line given two points, you can use [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are points on the line.
Or you could just line up the points vertically and subtract them vertically, then put 2nd difference over first.
Like so:
( 2 , 1 )
-( 1 , 2 )
--------------------
1 -1
So the slope is -1/1 or just -1.
Jeri is 3 years younger than Laura, whose age is x. How old is Jeri? x - 3 yrs old x + 3 yrs old 3x yrs old
Answer:
3x yrs old
Step-by-step explanation:
Arnold has x amount of money in
his checking account. He spends
$12.36 for breakfast but has at least
$31.24 left in his account. How much
money did he have originally?
Answer:
43.60
Step-by-step explanation:
12.36+31.24
janis jogs around a rectangular park that is 3/4 mi long and 1/4 mi wide. how far is it around the park?
Answer:
[tex]2\ miles[/tex]
Step-by-step explanation:
we know that
The distance around the park is equal to the perimeter of the rectangular park
The perimeter is equal to
[tex]P=2(L+W)[/tex]
we have
[tex]L=\frac{3}{4}\ mi[/tex]
[tex]W=\frac{1}{4}\ mi[/tex]
substitute the values
[tex]P=2(\frac{3}{4}+\frac{1}{4})[/tex]
[tex]P=2(\frac{4}{4})[/tex]
[tex]P=2\ mi[/tex]
Answer:
3 219⁄1000 km. [2 mi.]
Step-by-step explanation:
P = 2l + 2w
P = 2[¾] + 2[¼]
P = 1½ + ½
P = 2
I am joyous to assist you anytime.
Suppose BC is congruent to CA. Can you use the SSS Postulate or the SAS Postulate to prove ABD is congruent to DCA
Answer:
probably sas
Step-by-step explanation:
sas because the 2 sides are congruent, but i don't have enough information to know for sure
In the table, the parts of strawberry concentrate and the parts of water to prepare a strawberry drink are given. There is a proportional relationship between these two quantities. Find the value of x.
Parts of Water 3 9 36
Parts of Concentrate 1 3 x
Answer:
12
Step-by-step explanation:
[tex]\frac{Parts of Water}{Parts of Concentrate} =3[/tex]
3/1=3
9/3=3
36/12=3
(3a-2b)(3a+3b) so this is foil but i always get messed up on it does anyone now how to do it
Answer:
9a^2 + 3ab - 6b^2
Step-by-step explanation:
(3a-2b)(3a+3b)
First term of each grouping is 3a and 3a.
Multiply those you get 9a^2.
Outer term of each grouping is 3a and 3b.
Multiply those you get 9ab.
Inner term of each grouping is -2b and 3a.
Multiply those you get -6ab.
Last term of each grouping is -2b and 3b.
Multiply those you get -6b^2.
Add up all your products from above.
9a^2+9ab+-6ab+-6b^2
There are like terms here. The 9ab+-6ab which is 3ab.
So you can write your expression now as:
9a^2 + 3ab +-6b^2
9a^2 + 3ab - 6b^2
Step-by-step explanation:
[tex]\text{Use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd:\\\\(3a-2b)(3a+3b)\\\\=(3a)(3a)+(3a)(3b)+(-2b)(3a)+(-2b)(3b)\\\\=9a^2+9ab-6ab-6b^2\qquad\text{combine like terms}\\\\=9a^2+3ab-6b^2[/tex]
Jamin wants to paint a wall in his bedroom. Not only does he need to buy paint, but he also needs to buy tape to tape off all sides of the wall and the window. How many feet of painter's tape will Jamin need to buy (assume no overlap)? [Note: The wall and window are both rectangular.]
17.5 ft
35 ft
28 ft
21 ft
The perimeter of the walls is 6 + 6 + 8 + 8 = 28 feet.
The perimeter of the window is 2 + 2 + 1.5 + 1.5 = 7 feet.
Total = 28 + 7 = 35 feet of tape.
I would say B.35 is the answer.
What is the volume of the regular pyramid bellow?
Answer:
128 units^3
Step-by-step explanation:
[tex]v = \frac{b \times b \times h}{3} = \\ = \frac{8 \times 8 \times 6}{3} = \\ = 128 \: {units}^{3} [/tex]
Step-by-step explanation:
base areas x height / 3
a^2 . h / 3
8^2 . 6 / 3
= 128 units^3
iyi ödevler
have a good lesson
Which of the following is an integer?
0
4
© -12.5
0 0.454545...
Answer: 4
Step-by-step explanation: 4 is the answer because an integer is any whole number, but not 0.
You have $60. The jacket you want costs $25.50 and 7% tax. what is the top tag price (excludes sales tax) left to also buy a pair of shorts?
the assumption being, that there's a 7% sales tax on any item in the store.
so if you buy the jacket, you pay 25.5 plust 7% of 25.5.
and if you buy the shoes for price say "s", then you pay "s" plus 7% of "s".
whatever those two amounts are, they must be $60, because that's all you have in your pocket anyway.
[tex]\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 25.5}}{\left( \cfrac{7}{100} \right)25.5}\implies 0.07(25.5)~\hfill \stackrel{\textit{7\% of "s"}}{\left( \cfrac{7}{100} \right)s}\implies 0.07s \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \stackrel{\textit{jacket}}{25.5}+\stackrel{\textit{jacket's tax}}{0.07(25.5)}+\stackrel{\textit{shoes}}{s}+\stackrel{\textit{shoe's tax}}{0.07s}~~=~~\stackrel{\textit{in your pocket}}{60} \\\\\\ 25.5+1.785+s+0.07s=60\implies 27.285+1.07s=60 \\\\\\ 1.07s=60-27.285\implies 1.07s=32.715\implies s=\cfrac{32.715}{1.07}\implies s\approx 30.57[/tex]
PLEASE HELP ASAP
Of the three functions in the tables, which represent linear relationships?
A. f and h
B. all three functions
c. f and g
D. g and h
Answer:
A. f and h
Step-by-step explanation:
For a linear function the First Differences of the y-values must be a constant. i.e. if we take the difference between any two consecutive y values or values of f(x) it should be the constant. For this rule to work, x values must change by the same number every time, which is true for all three given functions.
For function f:
The values of f(x) are: 5,8,11,14
We can see the difference in consecutive two values is a constant i.e. 3, so the First Difference is the same. Hence, function f is a linear function.
For function g:
The values of g(x) are: 8,4,16,32
We can see the difference among two consecutive values is not a constant. Since the first differences are not the same, this function is not a linear.
For function h:
The values of h(x) are: 28, 64, 100, 136
We can see the difference among two consecutive values is a constant i.e. 36. Therefore, function h is a linear function.
To identify the linear relationships in the tables, we need to look for constant rates of change. Functions f and g have this property, while h does not.
Explanation:In order to identify which functions represent linear relationships, we need to look for patterns in the tables. A linear relationship is characterized by a constant rate of change.
Looking at the tables, we can see that functions f and g have a constant difference between the values in the input column (x) and the output column (y). However, function h does not have a constant rate of change, so it does not represent a linear relationship.
Therefore, the correct answer is A. f and h, as these two functions represent linear relationships.
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If f(x) = -x + 8 and g(x) = x^4, what is (gºf)(2)?
Answer:
[tex]\large\boxed{(g\circ f)(2)=1296}[/tex]
Step-by-step explanation:
[tex](g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(x)=-x+8,\ g(x)=x^4\\\\(g\circ f)(x)=\g\bigg(f(x)\bigg)=(-x+8)^4\\\\(g\circ f)(2)\to\text{put x = 2 to the equation}\ (g\circ f)(x):\\\\(g\circ f)(2)=(-2+8)^4=(6)^4=1296[/tex]
[tex]\bf \begin{cases} f(x)=&-x+8\\ g(x)=&x^4\\ (g\circ f)(x) =& g(~~f(x)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(2)=-(2)+8\implies f(2)=\boxed{6} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{(g\circ f)(2)}{g(~~f(2)~~)}\implies g\left( \boxed{6} \right) = (6)^4\implies \stackrel{(g\circ f)(2)}{g(6)} = 1296[/tex]
A light bulb company produces a constant number of new light bulbs in their factory each week, and stores them in a warehouse where old light bulbs from the previous year are also stored. After 3 weeks, they have 15,000 bulbs in the warehouse. After 7 weeks, they have 65,000 bulbs.
What is the equation in point-slope formula?
Answer:
y - 15000 = 12500(x-3)
What is the solution to the system?
X+y+z=2
2x+y-z=-1
X=5-2z
Answer:
x = 1, y = -1, z = 2 → (1, -1, 2)Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}x+y+z=2&(1)\\2x+y-z=-1&(2)\\x=5-2z&(3)\end{array}\right\\\\\text{Substitute (3) to (1) and (2):}\\\\\left\{\begin{array}{ccc}(5-2z)+y+z=2\\2(5-2z)+y-z=-1&\text{use the distributive property}\end{array}\right\\\left\{\begin{array}{ccc}5-2z+y+z=2\\10-4z+y-z=-1\end{array}\right\qquad\text{combine like terms}\\\left\{\begin{array}{ccc}5+y-z=2&\text{subtract 5 from both sides}\\10+y-5z=-1&\text{subtract 10 from both sides}\end{array}\right[/tex]
[tex]\left\{\begin{array}{ccc}y-z=-3\\y-5z=-11&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y-z=-3\\-y+5z=11\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad4z=8\qquad\text{divide both sides by 4}\\.\qquad\qquad \boxed{z=2}\\\\\text{Put it to the first equation:}\\\\y-2=-3\qquad\text{add 2 to both sides}\\\boxed{y=-1}\\\\\text{Put the values of}\ z\\text{to (3):}\\\\x=5-2(2)\\x=5-4\\\boxed{x=1}[/tex]
- The whole batch cost $28,000 and contained 140 items. Write the two rates (ratios) implied
by this statement. What would be the price for 200 items?
Please show work
Answer:
The answer would be 14
Step-by-step explanation:
you just divide 28,00 by 200 and that gives you 14
Why is the x intercept wrong?
True or false? An angle whose vertex is at the center of the circle is a central angle of that circle.
This statement would be true: if the vertex of an angle is at the center of the circle, then it would be the central angle.
Which equation is used to help form the combined gas law?
Need help ASAP !
If pressure is constant
then PV= nRT
is equivalent to V= ( nR/P) T
V= kT ( where k is constant nR/P)
As V is directly proportional to T
So V1/T1 = V2/T2
Answer:
The correct answer
Step-by-step explanation:
Find the length of RJ
Answer:
Option C 89
Step-by-step explanation:
In this problem we know that
KJ=KR+RJ
we have
KJ=95 units
KR=6 units
substitute and solve for RJ
95=6+RJ
subtract 6 both sides
RJ=95-6=89 units
Answer:
The correct option is C.
Step-by-step explanation:
We need to find the length of line segment RJ.
From the given figure it is clear that line segment KJ is the sum of line segments KR and RJ.
[tex]KJ=KR+RJ[/tex]
The length of line segment KJ is 95 units and the length of KR is 6 units.
Substitute KJ=95 and KR=6 in the above equation.
[tex]95=6+RJ[/tex]
Subtract 6 from both the sides.
[tex]95-6=6+RJ-6[/tex]
[tex]89=RJ[/tex]
The length of segment RJ is 89 units. Therefore the correct option is C.
The length of a new rectangular playing field is 5 yards longer than triple the width. If the perimeter of the rectangular playing field is 346 yards, what are itsdimensions?
The length and width of the rectangular field are determined using algebra by setting up and solving two equations which represent the relationships between the length, width, and perimeter of the field. The dimensions are found to be 46 yards for the width and 137 yards for the length.
Explanation:The dimensions of the rectangular playing field can be found using algebra, specifically the formulas for the dimensions and perimeter of a rectangle. The problem can be translated into two equations reflecting the relationships of the field's width and length to the perimeter.
The first equation is: L = 3W + 5, which represents the relationship that the length is 5 yards longer than triple the width.
The second equation is derived from the formula for the perimeter of a rectangle (P = 2L + 2W), which given the problem's perimeter of 346 yards gets us: 2L + 2W = 346.
Substitute the first equation into the second to solve for the width, then use that result to find the length. The solution indicates that the width of the rectangular playing field is 46 yards, and the length is 137 yards.
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what is the approximate area of the circle shown below? 16 cm
Answer:
201.143 (approx.) cm²
area of circle = (pi)x(radius)^2
= 22/7 x (8)^2
=22/7 x 64
= 1408/7
= 201.142857143
= 201.143 cm^2 (approx.)
Answer:
the approximate area of circle is 201 cm²
D is the correct option.
Step-by-step explanation:
From, the given figure, the diameter of the circle is 16 cm.
The radius is half of the diameter.
Hence, the radius of circle is 16/2 = 8 cm
The area of a circle is given by
[tex]A=\pi r^2[/tex]
Substituting the value of r and π
[tex]A=3.14(8)^2\\\\A=200.96\\\\A\approx201[/tex]
Therefore, the approximate area of circle is 201 cm²
D is the correct option.
the terminal side of an angle in standard position passes through P(-3,-4). what’s the value of tan(Theta)
Answer:
4/3
Step-by-step explanation:
I drew a picture in the attachment to show what we are looking at.
I found the point (-3,-4). I drew my angle my triangle from the x-axis and the origin to the point.
The angle that is theta is the one formed by the x-axis and the hypotenuse of the triangle where this hypotenuse was formed from the line segment from the origin to the given point.
[tex]\tan(\theta)=\frac{\text{opposite to }\theta}{\text{adjacent to }\theta}=\frac{-4}{-3}=\frac{4}{3}[/tex]
So we could have said [tex]\tan(\theta)=\frac{y}{x}[/tex].
Given the functions, F (x)=√(2x-5) and g(x) = 3x 2 + 2, perform the indicated operation. f(g(x))
Answer:
[tex]f(g(x)) =\sqrt{6x^2-1}[/tex]
Step-by-step explanation:
Given
f(x) = √2x-5
and
g(x) = 3x^2+2
We have to find the composition of both function
f(g(x)) means that we have to put function g in place of x in function f.
[tex]f(g(x))= \sqrt{2*g(x)-5}\\ =\sqrt{2(3x^2+2)-5}\\=\sqrt{6x^2+4-5}\\=\sqrt{6x^2-1}[/tex]
..
The composite function f(g(x)) is given by f(g(x)) = √(6x^2 - 1).
To find the composite function f(g(x)), you need to substitute the expression for g(x) into the function f(x). Here's how you can do it step by step:
Start with the function g(x):
g(x) = 3x^2 + 2
Now, substitute this expression into the function f(x):
f(g(x)) = √(2(3x^2 + 2) - 5)
Simplify the expression inside the square root:
f(g(x)) = √(6x^2 + 4 - 5)
Further simplify the expression inside the square root:
f(g(x)) = √(6x^2 - 1)
So, the composite function f(g(x)) is given by:
f(g(x)) = √(6x^2 - 1)
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