Answers
using a graph tool
I proceed to verify each case to get the answer
see the attached figure
case A)
y> 2x-4 y>=-x y<=3
case B)
y> 2x-4 y>=-x y<3
case C)
y< 2x-4 y>=-x y<=3
the answer is the option A)
y> 2x-4 y>=-x y<=3
Related Questions
0/17 into a decimal using long division
Answers
Brainliest please?
The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it. 4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 Number of Crackers in Each Bag, with Outlier Number of Crackers in Each Bag, without Outlier Which statement comparing the box plots is true? Both the median and the range changed. Both the range and the lower quartile changed. Both the median and the interquartile range changed. Both the interquartile range and the lower quartile changed.
Answers
Answer:
Both the median and the range changed.
Step-by-step explanation:
We first ensure this data set is from least to greatest. This one is.
Next we find the median. This is the middle value; in this set, it is 16.
Next we find Q1, the lower quartile. This is the middle of the lower set of data (once the data is "split" by the median). This is 15.
Next we find Q3, the upper quartile. This is the middle of the upper set of data (once the data is "split" by the median). This is 20.
The IQR is Q3-Q1, or 20-15 = 5.
The range is the max subtracted by the min, or 21-4 = 17.
Any outlier will be 1.5 times the IQR below Q1 or 1.5 times the IQR above Q3.
1.5(5) = 7.5; 15-7.5 = 7.5. Any lower outlier would be below this value; this makes 4 an outlier.
20+7.5 = 27.5. Any upper outlier would be above this value; this means there are no outliers on the upper end.
Taking the data value 4 out, the median is now 17. Q1 would still be 15 and Q3 would still be 20; this means the IQR would still be 5.
The range would now be 21-14 = 7.
This means the median and the range have changed.
The true statement comparing the box plots is that Both the median and the range changed.
What are quartiles?When we get data that can be compared relatively with each other, for finding quartiles, we arrange them in ascending or descending order.
Quartiles are then selected as 3 points such that they create four groups in the data, each group approximately possessing 25% of the data.
The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it.
4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 Number of Crackers in Each Bag, with Outlier Number of Crackers in Each Bag, without Outlier
The median in this set is 16.
Q1, the lower quartile. This is the middle of the lower set of data.
This is 15.
Q3, the upper quartile. This is the middle of the upper set of data. This is 20.
The IQR is Q3-Q1
20-15 = 5.
The range will be
21-4 = 17.
Any outlier will be 1.5 times the IQR below Q1 or 1.5 times the IQR above Q3.
1.5(5) = 7.5
15-7.5 = 7.5.
Any lower outlier would be below this value, this makes 4 an outlier.
20+7.5 = 27.5.
Any upper outlier would be above this value, this means there are no outliers on the upper end.
Taking the data value 4 out, the median is now 17.
Q1 would still be 15 and Q3 would still be 20; this means the IQR would still be 5.
The range would now be 21-14 = 7.
Thus, This means the median and the range have changed.
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convert 0.03 into a fraction
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0.03 converted to a fraction would be [tex] \frac{3}{100} [/tex]
Enjoy.
~Isabella
Hey guys 25 points!! to help me out
In △DEF, DF = 16 and m∠F=45. Find the length of a leg. Leave your answer in simplest radical form.
Answers
the hypotenuse is 16
we use the formula c^2=a^2+b^2
now we have a=b because the triangle is isosceles
c^2=2(a^2)
256=2(a^2)
256/2=a^2
128=a^2
a= 11.31 and b=11.31
Find the mode for the following distribution. Number Frequency 220 6 230 7 240 3 250 1 260 0 270 1 No mode 220 230 260 250 and 270
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They do not occur more frequently than any other value in the distribution, the values 220, 260, 250, and 270 are not modes.
How to finding the value that appears the most frequently will help us determine the mode of a distribution.?Distributed mode is the most common value. From the given frequency distribution we can see that both the values 220 and 230 occur with the highest frequencies of 6 and 7 respectively. Therefore, both 220 and 230 are modes of this distribution.
that the values 260, 250, and 270 are not modes, as they all have frequencies of 0 or 1. Also, the No Mode value is not a valid value in the distribution, indicating that there is no single mode value.
The values 220, 230, 240, 250, 260, and 270 all appear six times in this distribution, seven times each for values 230, seven times for values 240, one for value 250, zero for values 260, and one for value 270.
As a result, the value with the highest frequency—230—is the mode. Therefore, 230 is the mode for this distribution.
Due to the fact that they do not occur more frequently than any other value in the distribution, the values 220, 260, 250, and 270 are not modes.
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Can you square a negative number
Answers
however, you cannot root a negative number (if that was what you wanted)
hope this helps
For example;
(-2) * (-2) = 4.
Edit: Seeing that you meant to square root a negative number-- no, you cannot square root a negative number as you cannot multiply a negative number by a negative number to get a negative product; it will always be positive.
I hope this helps!
A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replacement. what is the probability that the third chip is defective?
Answers
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Chord AC intersects chord BD at point P in circle Z.
AP=3.5 in.
DP=4 in.
PC=6 in.
What is BP?
Enter your answer as a decimal in the box.
Answers
Answer: The value of BP is 5.25.
Step-by-step explanation:
Here's why:
Find the ratio between the two different groups of line segments. If you do it in decimal or fraction, it's the same. So, 4/6 = 0.666666667. Then you must find the number that when 3.5 is divided by it, gives you 0.666666667. So that number is 5.25.
(1+(0.065÷365))^365t=4
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1*(1+0.065/365)^(365t)t=4
take log on both sides,
365t(log(1+0.065/365)=log(4)
=>
365t=log(4)/log(1+0.065/365)
t=(log(4)/log(1+0.065/365))/365
=(1.38629/.000178066)/365
=21.33 years
Check with the rule of 69, applicable to continuous compounding (an approximation to current problem) to double money, it take 69/interest rate in % years.
=69/6.5
=10.62 years
To double twice (quadruple), it takes twice 10.62
=21.24 years, not that far from 21.33 that we got earlier.
lotA has 4,000 spaces. Today Lot A has 2,500 cars in Lot A. Lot B has 2,000 spaces. If both lots have the same ratio of cars to spaces, how many cars are in parking lot B
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Work out the area of rectangle APQR.
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The rectangle diagonally into 2 right triangles: one with base 5 and height 13, another with base 12 and height 5. Doubling their areas (5*13+12*5) gives 180!
The area of a rectangle with a base of 5 cm and a height of 13 cm is indeed 180 square centimeters..
Here's a simpler explanation:
Imagine slicing the rectangle diagonally into two right triangles. One triangle has base 5 cm and height 13 cm. The other triangle has base 12 cm and height 5 cm (using Pythagoras to find the missing side).
Now, the area of the rectangle equals the sum of the areas of these two triangles. Adding their areas (5 * 13 + 12 * 5) gives us 65 + 60, totaling 180 square centimeters.
Therefore, the true area of the rectangle is 180 square centimeters, not 65 or any multiple of the individual base and height alone. This hidden relationship between the diagonal and sides creates the surprising answer.
At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. the diameter of the base of the cone is approximately three times the altitude. at what rate is the height of the pile changing when the pile is 12 feet high?
Answers
dV/dt=10
2. The formula for calculate the volume of a cone, is:
V=1/3(πr²h)
"r" is the radius and "h" is the height.
3. The diameter of the base of the cone is approximately 3 times the altitude. Then, the radius is:
r=diameter/2
diameter=3h
r=3h/2
4. When you susbstitute r=3h/2 into the formula V=πr²h/3, you have:
V=1/3(πr²h)
V=1/3(π(3h/2)²(h)
V=1/3(π9h²/4)(h)
V=9πh³/12
5. Therefore:
dV/dt=(9πh²/4)dh/dt
h=12
dV/dt=10
6. When you substitute the values of dV/dt and h into dV/dt=(9π(12)²/4)dh/dt, you have:
dV/dt=(9π(12)²/4)dh/dt
10=(1017.876)
7. Finally, you obtain:
dh/dt=10/1017.876
dh/dt=9.82x10^-3 ft/min
The problem involves the concept of related rates in Calculus. By using the relationship between the height and radius of the cone and the rate of change of the volume, we set up a differential equation. Upon solving, we find the rate at which the height of the pile changes is 5/(18π) feet per minute when the pile is 12 feet high.
Explanation:The subject matter of this question is related to Calculus, specifically the concept of related rates. In this scenario, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. Here, the given rate is the rate of change of the volume of the sand pile. The diameter of the base of the cone is approximately three times the altitude, which gives the relationship between the height and the radius of the cone: r=h/3. The student is asked to find at what rate the height of the pile is changing when the pile is 12 feet high.
First, let's recall the formula for the volume of a cone, which is V=(1/3)*π*r²*h. Based on the relationship between the radius and the height, we can substitute r with h/3. Therefore, the volume V=(1/3)*π*(h/3)²*h = (1/27)*π*h³. By differentiating this equation with respect to time t, we get dV/dt = (1/9)*π*h²*dh/dt.
We are given that dV/dt is 10 cubic feet per minute, and we want to find dh/dt when h = 12 feet. Substituting these values into the differentiated equation, we get 10 = (1/9)*π*(12²)*dh/dt. Solving this for dh/dt, we find that dh/dt = 10 / [(1/9)*π*(12²)] = 5/(18π) feet per minute.
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Latrell is comparing two job opportunities one job will pay $12 an hour and he will work 40 hour a week. The other one pays an annual salary of $22,00 and he will work 45 hours a week. which job pays more?
Answers
To compare these two jobs, you need to have a common point. In this problem, you have to solve for the annual salary of the first job and compare it with the annual salary of the second job which is already given.
$12 per hour x 40 hours per week x 48 weeks in a year = $23,040
First job’s annual salary is $23,040
Second job’s annual salary is $22,000
Therefore, the job which pays $12 an hour pays more.
Latrell will earn more at the job that pays $12 per hour for a 40-hour workweek, which totals $24,960 per year, compared to the annual salary of $22,000 for a 45-hour workweek.
To determine which job pays more between an hourly wage job and an annual salary job, we need to calculate the total annual income for each option.
For the hourly wage job at $12 per hour for 40 hours a week:
$12/hour times 40 hours/week = $480/week$480/week times 52 weeks/year = $24,960/yearFor the annual salary job of $22,000 for 45 hours a week, the total annual income is:
$22,000/year (no further calculation is needed)Comparing the two annual incomes:
Hourly wage job = $24,960/yearAnnual salary job = $22,000/yearTherefore, the job that pays $12 per hour for 40 hours a week offers a higher annual income than the job with an annual salary of $22,000 for 45 hours a week.
In certain county, the number of charter schools is 4 less than twice the numbervof alternative schools. We know that there are 48 charter schools in the county. How many alternative schools are in the county?
Answers
- The number of charter schools is 4 less than twice the number of alternative schools.
- There are 48 charter schools in the country.
2. So, you have:
x=2y-4 (i)
x=48 (ii)
3. Then, when you substitute x=48 into the equation (i), you obtain:
x=2y-4
48=2y-4
4. Now, you must clear "y, as below:
48+4=2y
2y=52
y=52/2
y=26
How many alternative schools are in the county?
The answer is: There are 26 alternative schools.
A Punnett square is used to _______.
predict the genotypic and phenotypic probabilities of possible offspring
determine if a trait runs in a family
track inherited traits through many generations
identify organisms that are carriers of a specific trait
Answers
The answer is option A "predict the genotypic and phenotypic probabilities of possible offspring".
Reason:
A Punnett square is used to determine (predict) the genotype, and phenotype of a organism. Phenotype is the physical features of a organism fur, ears, nose, etc.... Genotype is most likely the height, eye color, etc....
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
A Punnett square is used to predict the genotypic and phenotypic probabilities of possible offspring. It helps in illustrating how combinations of alleles might come together during fertilization. However, it cannot determine if a trait runs in a family or track inherited traits through generations.
Explanation:A Punnett square is a common tool used in genetic studies to predict the genotypic and phenotypic probabilities of possible offspring when the genetic information of both parents is known. It is not used to determine if a trait runs in a family, track inherited traits through many generations, or identify organisms that are carriers of a specific trait. A Punnett square can help illustrate how different combinations of alleles might come together during fertilization and what traits these combinations could produce. For instance, if both parents carry a recessive trait, a Punnett square can show the possibility of their offspring inheriting that trait.
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The Silver Town people went to a fancy restaurant after the big event. Grammy gave the server a $15 tip. If the tip was 20% of the cost of dinner, how much was dinner? Choose Answer:A.$60 B.$45 C.$75 D.$50
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Point P (-3,-1) is the preimage. Point P’(3,-1) is the image after a reflection is performed. Give the line of reflection.
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x = 0 is the line of reflection.
Let y=3t+6 be a linear function representing the distance from home for an ant t minutes after starting out from a location near its home. What does the number 3 represent in this function?
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A flagpole 3 meters tall casta a shadow of 4 meters long at the same time a nearby building casts a shadow of 62 meters long. How tall is the building
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S22 for 161+147+133+119+...
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Compute the general progression formula of 161,147,133,119 d=-14, a↓n+175
Compute ᵃ₂₂ = -133
The 22nd term of the arithmetic progression in the series 161, 147, 133, 119.... is -133.
Explanation:This question involves finding the 22nd term in a series of numbers where each term is 14 less than the preceding term. This is an arithmetic progression where the first term, 'a' is 161 and the common difference, 'd' is -14.
The formula for the nth term in an arithmetic progression is: a + (n - 1)*d.
Substituting the given values into the formula, we get:
'a' + (22 - 1)*'d' = 161 + (21)*(-14) = 161 - 294 = -133
So, S22 for 161+147+133+119+... = -133.
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Which of the following is the inverse of y=6^x ?
A. Y=log 6x
B. Y=Log x6
C. YLog1/6X
D. Y=Log 6. 6x
Answers
y=6^x
we know
to find the inverse
replace x with y and y with x,
x=6^y
we know that
y=logb(x)----------> x=b^y
therefore
x=6^y---------------> y=log6(x)
the answer is the option A.) Y=log 6x
log y = log 6^x
log y = x log 6
(log y) / (log 6) = x
Inverse: y = (log x) / (log 6)
Suppose x follows a distribution with density function: \begin{equation} f\left(x\right) = \left\{\begin{array}{rl} c\left|x - 2\right|,& 0 \le x \le 3\\ 0, & \text{otherwise}\\ \end{array}\right. \end{equation} (note: for this question you can enter your answer in decimals as well as fractions.) what must the value of c be so that f(x) is a probability density function? tries 0/5 find the cumulative distribution function of f(x) for $ 2 \leq x \leq 3 $. [ the accepted form of answer is an algebraic expression in terms of "x". all algebraically equivalent expressions to the correct answer are accepted. write product as *
e.g 2*3 or 3*x, index/power as superscript,
e.g 2^3 for 2 raised to the power 3, the exponential function as exp(x), the logarithm function as log(x) (and not as ln(x)) ] tries 0/5 find the median of the probability distribution of x tries 0/2 find e(x) tries 0/5 find the cumulative distribution function of f(x) for $ 0 \leq x \leq 2 $. [ the accepted form of answer is an algebraic expression in terms of "x". all algebraically equivalent expressions to the correct answer are accepted. write product as *
e.g 2*3 or 3*x, index/power as superscript,
e.g 2^3 for 2 raised to the power 3, the exponential function as exp(x), the logarithm function as log(x) (and not as ln(x)) ]
Answers
Given the PDF of a random variable [tex]X[/tex]:
[tex]f_X(x)=\begin{cases}c|x-2|&\text{for }0\le x\le3\\0&\text{otherwise}\end{cases}[/tex]
Find [tex]c[/tex], the CDF, the median of [tex]X[/tex], and the expectation of [tex]X[/tex] (in no particular order).
For [tex]f_X(x)[/tex] to be valid PDF, we require
[tex]\displaystyle\int_{-\infty}^\infty f_X(x)\,\mathrm dx=1[/tex]
Note that
[tex]|x-2|=\begin{cases}x-2&\text{for }x\ge2\\2-x&\text{for }x<2\end{cases}[/tex]
We have
[tex]\displaystyle\int_{-\infty}^\infty f_X(x)\,\mathrm dx=c\int_0^3|x-2|\,\mathrm dx=c\int_0^2(x-2)\,\mathrm dx+c\int_2^3(2-x)\,\mathrm dx[/tex]
[tex]\implies\dfrac{5c}2=1\implies c=\dfrac25[/tex]
The CDF is defined by
[tex]F_X(x)=\mathbb P(X\le x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt[/tex]
To find the CDF, we compute the integral above for the four possible cases:
[tex]x<0\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=0[/tex]
[tex]0\le x<2\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=c\int_0^x|t-2|\,\mathrm dt=\frac{4x-x^2}5[/tex]
[tex]2\le x<3\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\frac45+c\int_2^x|t-2|\,\mathrm dt=\frac45-c\int_2^x(2-t)\,\mathrm dt=\frac{8-4x+x^2}5[/tex]
[tex]x\ge3\implies\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=1[/tex]
So the CDF is
[tex]F_X(x)=\begin{cases}0&\text{for }x<0\\\\\dfrac{4x-x^2}5&\text{for }0\le x<2\\\\\dfrac{8-4x+x^2}5&\text{for }2\le x<3\\\\1&\text{for }x\ge3\end{cases}[/tex]
The median is the value [tex]M[/tex] such that [tex]\mathbb P(X\le M)=\dfrac12[/tex]. From the PDF, we can gather that the median must fall somewhere in [tex]0\le x\le2[/tex]. The CDF then tells us that
[tex]\mathbb P(X\le M)=F_X(M)=\dfrac12=\dfrac{4M-M^2}5\implies M=2-\sqrt{\dfrac32}\approx0.775[/tex]
The expected value of [tex]X[/tex] is given by
[tex]\mathbb E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx[/tex]
We have
[tex]\mathbb E[X]=\displaystyle\frac25\int_0^2x(x-2)\,\mathrm dx+\frac25\int_2^3x(2-x)\,\mathrm dx=\frac{16}{15}[/tex]
I don’t know what todo someone help me
Answers
1. The area of the shaded region is the area of the shaded triangle.
2. SΔ=0.5*(14-8)*8=0.5*6*8=24 m².
Jordan places two boards end to end to make one shelf. The first one is 47/100 meter long. The second board is 5/10 meter long. What is the total length, in meters, of the two boards
Answers
Total=(length of board A)+(length of board B)
=47/100+5/10
making the fractions have the same denominator we multiply the numerator and denominator of the second fraction by 10, this will giv us the expression of:
47/100+50/100
=97/100 m
Final answer:
To calculate the total length of the boards, the first board at 47/100 meters (0.47 meters) is added to the second board at 5/10 meters (0.5 meters), resulting in a total length of 0.97 meters.
Explanation:
To find the total length of the two boards placed end to end, we simply add the lengths of the individual boards. The first board is 47/100 meters long, and the second board is 5/10 meters long.
The second board's length can be simplified as 5/10 is equivalent to 1/2, which is 0.5 in decimal form. Adding the lengths together, we get:
Length of board 1: 47/100 meters (or 0.47 meters)
Length of board 2: 5/10 meters (or 0.5 meters)
Total length = 0.47 meters + 0.5 meters
Total length = 0.97 meters
Therefore, the total length of the two boards when placed end to end is 0.97 meters.
Team tool Bella canoed 15 3/4 miles in 5 1/4 hours. What was their average rates of speed in miles per hour?
Answers
Answer:
3 miles per hour
Step-by-step explanation:
Using speed formula:
[tex]\text{Speed} = \frac{\text{Distance}}{\text{Time}}[/tex]
As per the statement:
Team tool Bella canoed 15 3/4 miles in 5 1/4 hours.
⇒[tex]\text{Distance} = 15\frac{3}{4} = \frac{63}{4}[/tex] miles and
[tex]\tetx{Time} = 5\frac{1}{4} = \frac{21}{4}[/tex] hours
Using speed formula we have;
[tex]\text{Speed}= \frac{\frac{63}{4} }{\frac{21}{4}} = \frac{63}{4} \cdot \frac{4}{21} = \frac{63}{21}[/tex]
Simplify:
[tex]\text{Speed} =3[/tex] miles per hour
Therefore, their average rates of speed in miles per hour is, 3 miles per hour
Solve 5+h>7 Graph the solution.
Answers
Subtract 5 from both sides
h > 2
Can you explain how you got it as well?
Answers
.. 15*40% +25*20% = (15+25)*a
.. 6 +5 = 40a
.. a = 11/40 = 27.5% . . . . . . selection C
Rob cuts a 15-foot wire into 8 equal pieces. About how long is each piece ? 1.) Between 1 and 2 feet 2.) Between 3 and 4 feet 3.)Between 2 and 3 feet 4.) Between 2 and 3 feet
Which one is the answer?
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Can someone help me with these two questions?
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2. A=30, B= 70, b = 4
Brad has two lengths of copper pipe to fit together one has a length of 2 5/12 feet and the other has a length of 3 7 12 ft how many feet of Pop does he have
Answers
2 5/12 + 3 7/12 = 5 12/12
Since 12/12 = 1 or a whole, we can simplify this further.
5 12/12 = 6
Hope this helps!