The highest element in the hierarchical breakdown of the Work Breakdown Structure (WBS) is the project itself. This project is then divided into definable and measurable tasks or subtasks forming a hierarchical structure.
Explanation:The highest element in the hierarchical breakdown of the Work Breakdown Structure (WBS) is the project itself. WBS is a tool used in project management to divide a project into manageable chunks or portions. It begins with the final deliverable or project at the top level. This is subsequently broken down into definable and measurable tasks or subtasks forming a multi-level structure. A good example could be a software development project. The entire project would be the highest element and might be divided into phases like planning, design, coding, testing, and implementation. Each of these could be further broken down into more specific tasks.
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In Robin’s linguistics class, the teacher and students are discussing how the word “nice” once meant “foolish” and how “awful” used to mean “full of awe.” They are most likely discussing ______
A.
morphemes
B.
semantics
C.
phonemes
D.
syntax
Read the article by Michael Fumento, writer for the New York Post editorial blog, who does not support global warming. Back in 2005 I and others reviewed the entire hurricane record, which goes back over a century, and found no increase of any kind. Yes, we sometimes get bad storms—but no frequently now than in the past. The advocates simply ignored that evidence. Fact is, the earth was cooling and warming long before greenhouse gases could have been a factor. The [global warming supporters] have been proved wrong time and time again. Which best describes the reliability of the source? Nationally certified organizations are considered an unreliable source because the public can access their information. Charities are considered a reliable source because the public makes financial contributions to them. Editorial blogs are considered an unreliable source because the author may not have a science background. Editorial blogs are considered a reliable source because authors contribute to them regularly.
Answer:
the 3rd choice is the answer
Explanation:
Which of these pollutants is transferred from soil to water by organic pesticides and fertilizer runoff from farms?
A coliform
B oxygen
C carbon
D phosphates
Answer: Option D
Explanation: The fertilizers consists of the phosphates and nitrates. These aids in the growth of the plant. Fertilizers used by the plants are sometimes carried away due to the rain.
The run off from the agricultural field contains phosphates that is transferred from the field to the nearby water bodies.
when the diaphragm contracts , air pressure in the chest increases . True or False ?
Answer: False
When the diaphragm contracts, the muscles will also contract and pull upward and increase the size of the thoracic cavity thus decreases air pressure inside during inspiration. After the diaphragm contracts, it goes to relaxation, the muscles will also relaxed. It gets looser and return to its original position higher up in the chest. This increase the pressure in the chest, which force the air in the lungs out through the nose.
A baseball is launched horizontally from a height of 1.8 m. The baseball travels 0.5 m before hitting the ground.
How fast is the baseball moving, rounded to the nearest hundredth?
m/s
Here we’re solving a problem where a ball is projected horizontally from a height of h=1.8 m with a horizontal velocity of Vx. At the impact with the ground, the ball has travelled 0.5 m horizontally.
Solution:
We will need kinematic equations
V1^2-V0^2=2aS ………………….(1)
S=V0*t + (1/2)at^2………………..(2)
Where
S=displacement (distance), m
V0=initial velocity, m/s
V1=final velocity, m/s
a=acceleration, m/s^2
t=time, seconds
At the point of impact, there a vertical velocity (downwards) of Vy.
The horizontal velocity Vx remains constant since projection till impact.
Vertical velocity Vy:
Using equation (1),
V0=0 (projected horizontally, so vertical velocity=0)
S=1.8 m (downwards)
a=9.81 m/s^2 (acceleration due to gravity, downwards)
=>
Vy=V1=sqrt(V0^2+2*a*S)=sqrt90+2*9.81*1.8)=5.9427
Horizontal velocity, Vx:
ball travelled 0.5m in time t it took ball to hit ground.
Using equation (2),
S=1.8m
V0=0
a=9.81
=>
1.8=0*t+(1/2)(9.81)t^2
Solve for t
t=sqrt(2*1.8/9.81)=0.60578 s
Horizontal velocity, Vx = 0.5/0.60578 = 0.82538 s
Speed of ball on impact is the vectorial sum of Vx and Vy:
Speed = sqrt(Vx^2+Vy^2)=sqrt(5.9427^2+0.82538^2)=5.99977 m/s, say 6.0 m/s.
Answer: 0.82
On ED2020
What is the internal resistance of a 12.0-v car battery whose terminal voltage drops to 8.3 v when the starter motor draws 89 a ?
Final answer:
To find the internal resistance of a 12.0-V car battery with specific measurements, use Ohm's Law.
Explanation:
Internal resistance of a battery can be calculated using Ohm's Law, where internal resistance = (emf - terminal voltage) / current. In this case, with an EMF of 12.0 V, terminal voltage of 8.3 V, and current of 89 A, the internal resistance would be calculated as (12.0 V - 8.3 V) / 89 A.
This gives an internal resistance of approximately 0.0427 ohms.
Which best characterizes a crystal? a number of high speed particles moving randomly a dense substance that is hard and incompressible a high-energy state of matter made up of a swirling, ionized gas a loose association of particles moving past one another Mark this and return
a dense substance that is hard and incompressible
The maximum allowed power dissipation for a 27.3-ω resistor is stated to be 10.0 w. find the largest current that this resistor can take safely without burning out.
The amount of flow of charge per unit time is known as the current. The largest current that this resistor can take safely without burning out will be 0.6 amperes.
What is power dissipation in a resistor?The process of losing power in the form of heat as a result of the main activity is known as power dissipation. Dissipation of power is a natural occurrence.
All of the circuit's resistors that have a voltage drop across them will dissipate power. Due to the conversion of electrical energy to thermal energy, all resistors will have a power rating.
The power dissipated on a resistor is given as
P = I²R
I is current flowing through it
R is the resistance
[tex]\rm {P = I^2R}\\\\I=\sqrt{\frac{P}{R} }\\\\I=\sqrt{\frac{10}{27.36\\}[/tex]
I = 0.6 A
Hence the largest current that this resistor can take safely without burning out will be 0.6 amperes.
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Consider two copper wires. one has twice the length of the other. how do the resistivities of these two wires compare?
The resistivity of two copper wires remains the same regardless of their lengths because resistivity is an intrinsic property of the material.
Comparing resistivities of two copper wires of different lengths but the same material, we need to understand that resistivity is an intrinsic property of the material and does not depend on the geometry of the wire. Therefore, regardless of whether one wire is twice as long as the other, the resistivity of both wires remains the same. This is a fundamental concept in the study of electrical resistance and materials.
Antagonistic muscles move a body part in _____.
1. the same directionAnswer: Opposite direction
Skeletal muscles arise in antagonistic pairs where the muscles contract to produce opposite movements at the same joint. Antagonistic muscles move a body part in one direction by contraction, the other moves that part in opposite direction.
In addition, when a muscle contracts to produced movement, its antagonist relaxes to allow movement to take place such as biceps muscles is a flexor muscle for elbow joint and triceps is the antagonist.
Which statement best compares momentum and kinetic energy? If you double the velocity of an object, its kinetic energy doubles. But for the same increase in velocity, the momentum increases four times. If you double the velocity of an object, its momentum doubles. But for the same increase in velocity, the kinetic energy increases four times. If you double the velocity of an object, its momentum and kinetic energy doubles. If you double the velocity of an object, its momentum and kinetic energy increases four times.
If you double the velocity of an object, its momentum doubles. But for the same increase in velocity, the kinetic energy increases four times.
Explanation:
We can prove this statement by looking at the formulas for the momentum and kinetic energy of an object.
Momentum: [tex]p=mv[/tex]
Kinetic energy: [tex]K=\frac{1}{2}mv^2[/tex]
where m is the mass of the object and v its velocity.
From the two formulas, we see that the momentum is directly proportional to the velocity, while the kinetic energy is proportional to the square of the velocity. Therefore, if we double the velocity, the momentum increases by a factor 2, while the kinetic energy increases by a factor [tex]2^2=4[/tex].
Momentum is directly proportional to an object's mass and velocity, while kinetic energy is directly proportional to an object's mass and the square of its velocity. When velocity is doubled, kinetic energy increases four times, while momentum doubles.
Explanation:Momentum and kinetic energy are both physical quantities that describe the motion of an object. Momentum is directly proportional to an object's mass and velocity, while kinetic energy is directly proportional to an object's mass and the square of its velocity.
In terms of velocity, if you double the velocity of an object, its kinetic energy increases four times (K = (1/2)mv²), but its momentum doubles. This is because momentum is equal to mass times velocity (p = mv), so when velocity doubles, momentum also doubles. However, since kinetic energy is proportional to the square of velocity, when velocity doubles, kinetic energy increases by a factor of four.
Therefore, the statement that best compares momentum and kinetic energy is: If you double the velocity of an object, its kinetic energy increases four times. But for the same increase in velocity, the momentum doubles.
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You are walking in the forest and see a bear. According to the Cannon-Bard theory, what happens next?
for the whole quiz of intro to psychology ;)
1. Stimulus--> Physiological changes--> emotion
2. Darwin
3.You experience physiological changes and a feeling of fear simultaneously
4. Cannon-Bard theory
5. James-Lange theory
6. David G. Myers
7. Happiness
8. Acting happy
9. negative and dysfunctional aspects of emotion and behavior.
10. an aspect of consciousness characterized by a certain physical arousal involving facial and bodily changes, brain activation, and tendencies toward action, all shaped by cultural rules.
I do this cause i wished someone did this for me. So stress no more from falling behind and Ace that quiz. your welcome comrades
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According to the Cannon-Bard theory, physiological changes and the feeling of fear occur simultaneously.
What is Cannon-Bard theory?The Cannon–Bard theory is also called the thalamic theory of emotion which is related to the thalamus. It is a part of the brain that deals with sensory and motor functions. The main concepts of this theory are that emotional expression arises from the function of hypothalamic structures while emotional feeling arises from stimulation of the dorsal thalamus.
This theory states that the lower part of the brain controls the experience of emotion while the upper part of the brain, called the cortex, controls the expression of emotion. These two parts of the brain react together
In this theory, stimulating events trigger emotions and physiological responses that occur at the same time. For example, seeing a bear in the woods can cause both a feeling of fear (an emotional response) and a faster heartbeat (a physical response).
Thus, according to the Cannon-Bard theory, physiological changes and the feeling of fear occur simultaneously.
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It takes 2.40s for a small ball with a mass of 0.08 kg released from rest from a tall building to reach the ground. calculate the height from which the ball is released. follow 1 answer if that ball had been released from the same height, but this time above the surface of the moon, how long would it have taken for the ball to hit the ground?
A car drives over the top of a hill that has a radius of 30 m . part a what maximum speed can the car have without flying off the road at the top of the hill?
The answer i got was 50 miles per hour
(ENVIRONMENTAL SCIENCE NOT PHYSICS)
7. gradually taking over farmland over a long period of time is known as commodities. True or False
8. The 2002 farm bill gives money to farmers who grow crops like wheat and soybeans but not to fruit and vegetable farmers. True or False
9. some farmers have been selling their land to developers because it is more cost efficient to do so than to grow crops. True or False
10. The FBI regulates the use of pesticides in agricultural crops. True or False
How do the planets Venus and Neptune differ in terms of atmospheric composition?
(A)Venus has carbon dioxide in its atmosphere, while Neptune has methane in its atmosphere.
(B)Venus has oxygen in its atmosphere, while Neptune has carbon monoxide in its atmosphere.
(C)Venus has hydrogen chloride in its atmosphere, while Neptune has helium in its atmosphere.
(D)Venus has nitrogen in its atmosphere, while Neptune has oxygen and hydrogen in its atmosphere.
(E)Venus has sulfur dioxide in its atmosphere, while Neptune has nitrogen dioxide in its atmosphere.
Answer: The correct option is Option A.
Explanation:
Atmosphere is defined as the layer of gases which form an envelope around a planet.
Venus is the second and Neptune is the last planet of our solar system.
Venus's atmosphere mainly consists of carbon dioxide with trace amounts of nitrogen, argon , helium and neon.
Neptune's atmosphere mainly consists of helium and hydrogen with 2.5 to 3% of methane gas in it.
From the above information, the correct answer comes out to be Option A.
A force of 15 N is applied to a spring, causing it to stretch 0.3 m. What is the spring constant for this particular spring?
An iron robot falls from rest at a great height. neglecting air resistance, what is its speed after it has fallen for 3.5 seconds? 13.3 m/s 9.8 m/s 34.3 m/s 9.8 m/s2
According to Binet, mental age relates to chronological age because ___________.
A.
they are the same thing
B.
mental age involves calculating the chronological age at which a person functions
C.
chronological age involves calculating how a person is mentally functioning
D.
they are opposites
Answer: The correct answer for the fill in the blank is B. Mental age involves calculating the chronological age at which a person functions.
Mental age corresponds to the attainment of mental abilities by an individual. It is related to intelligence and based on the chronological age ( calculated from the date on which individual was born) at which any average individual attains the same level of mental abilities.
Therefore, mental age involves calculation of the chronological age at which a person functions and attains mental abilities.
Three people pull simultaneously on a stubborn donkey. jack pulls directly ahead of the donkey with a force of 97.9 n, jill pulls with 72.7 n in a direction 45° to the left, and jane pulls in a direction 45° to the right with 145 n. (since the donkey is involved with such uncoordinated people, who can blame it for being stubborn?) find the magnitude of the net force the people exert on the donkey.
To find the net force on the donkey, we decompose the angled forces into horizontal and vertical components and add them accordingly. Since the vertical components cancel out, the net force is the sum of Jack's force and the combined horizontal components from Jill and Jane, resulting in a net force of 149 N ahead.
The problem presented requires an analysis of forces and vector addition to calculate the net force exerted on a donkey by three different people. We have Jack applying 97.9 N directly ahead, Jill pulling with 72.7 N at a 45° angle to the left, and Jane pulling with 145 N at a 45° angle to the right. To solve this, we must break down Jill's and Jane's forces into their horizontal and vertical components and then combine these with Jack's force.
Jill's horizontal component: 72.7 N × cos(45°) = 51.4 N to the left
Jill's vertical component: 72.7 N × sin(45°) = 51.4 N up
Jane's horizontal component: 145 N × cos(45°) = 102.5 N to the right
Jane's vertical component: 145 N × sin(45°) = 102.5 N up
Now we can subtract Jill's horizontal component from Jane's because they are in opposite directions: 102.5 N (Jane's right) - 51.4 N (Jill's left) = 51.1 N to the right. The vertical components from Jill and Jane will cancel each other since the donkey is stubborn and not moving vertically, hence we are left with only the horizontal forces to combine with Jack's force.
The total horizontal force exerted by Jack and combined with the net horizontal force from Jill and Jane is 97.9 N (Jack's force)+ 51.1 N (net horizontal force) = 149 N.
Thus, the magnitude of the net force the people exert on the donkey is 149 N directly ahead, assuming no vertical movement.
When the particles of a medium move with simple harmonic motion, this means the wave is a __________. when the particles of a medium move with simple harmonic motion, this means the wave is a __________. harmonic wave sinusoidal wave sound wave standing wave transverse wave?
If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.
Explanation:
A body is considered to be performing the Simple Harmonic Motion if it repeats its motion in a particular path with a specific time period. The two and fro motion of the pendulum about a fixed mean position is termed as the Simple Harmonic Motion.
The motion of the simple pendulum repeats itself after a particular time period and it continuously retraces its path during the motion. Therefore, it is termed as the simple harmonic motion.
The wave depicting the motion of a body performing the simple harmonic motion is shown in the sinusoidal manner. The motion of the body from its mean position to its extreme and then from extreme position to its mean position shows the positive cycle of the sinusoidal waveform.
The motion of the pendulum on the other side of the mean position of the pendulum represents the other half of the sinusoidal waveform.
Thus, If the particle is under the Simple Harmonic Motion, the wave is considered to be sinusoidal wave.
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A property is a characteristic of a substance that can be observed and does not change the identity of the substance brainly.com/question/859623The amount of kinetic energy an object has depends on its brainly.com/question/137098Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off. What is the net force acting on the refrigerator brainly.com/question/4033012Answer Details:
Grade: High School
Chapter: Simple Harmonic Motion
Subject: Physics
Keywords:
simple, harmonic, SHM, motion, pendulum, oscillates, mean position, extreme, repeats, time period, sinusoidal.
A research van de graaff generator has a 2.00-mdiameter metal sphere with a charge of 5.00 mc on it. (a) what is the potential near its surface? (b) at what distance from its center is the potential 1.00 mv? (c) an oxygen atom with three missing electrons is released near the van de graaff generator. what is its energy in mev when the atom is at the distance found in part b?
Part A: The potential on the surface of the charged sphere is [tex]4.5 \times 10^7[/tex] volts.
Part B: The distance is [tex]4.5 \times 10^{10}[/tex] m from the center of the sphere where the potential is 1 mv.
Part C: The energy of the oxygen atom found at the distance of [tex]x = 4.5 \times 10^{10} \;\rm m[/tex] is 3me V.
How do you calculate the potential?
Given that the diameter of the sphere is 2.00 m and the charge of 5.00 mc.
Part A
The potential on the surface of a charged sphere is given below.
[tex]V = k\dfrac {Q}{R}[/tex]
Where V is the potential on the surface, Q is the charge, R is the radius and k is the Coulomb's constant.
[tex]V = 8.99 \times 10^9\times \dfrac {5 \times 10^{-3}}{\dfrac {2}{2}}[/tex]
[tex]V = 4.5 \times 10^7 \;\rm Volts[/tex]
Hence the potential on the surface of the charged sphere is [tex]4.5 \times 10^7[/tex] volts.
Part B
The potential of 1 mv generated at a certain distance x from the centre of the sphere is given below.
[tex]V_x = k \dfrac {Q}{x}[/tex]
[tex]1 \times 10^{-3} = 8.99 \times 10^9 \times \dfrac{5 \times 10^{-3}} {x}[/tex]
[tex]x = 4.5 \times 10^{10} \;\rm m[/tex]
Hence the distance is [tex]4.5 \times 10^{10}[/tex] m from the center of the sphere where the potential is 1 mv.
Part C
Given that an oxygen atom with three missing electrons is released near the van de-Graaff generator. It means that the charge Q = +3e
The electric potential energy of a charged particle located at some point with voltage V is given below.
[tex]U = QV[/tex]
At the distance found in part b, which is [tex]x = 4.5 \times 10^{10} \;\rm m[/tex], the energy of the oxygen atom is,
[tex]U = +3e \times 1 \times 10^{-3}[/tex]
[tex]U = 3me \;\rm V[/tex]
Hence the energy of the oxygen atom found at the distance of [tex]x = 4.5 \times 10^{10} \;\rm m[/tex] is 3me V.
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Which part of a wind-powered system ultimately produces the electricity? A. nacelle B. blade C. turbine D. generator
Answer:
C) TURBINE
Explanation:
As we know that wind powered system is used to generate electricity using wind energy.
Here wind powered system has different components
1) Blades: these are long plates connected to the turbine. when these plates encountered high speed wind they start rotating on its axle.
This will produce kinetic energy in the axle which is transferred to the turbine.
2) Turbine: It is used to convert mechanical energy of the wind into useful electrical energy.
This is continuously driven by the kinetic energy of wind
So here correct answer is
C) Turbine
Which of the following is the best definition of a short circuit
A. A circuit that has a gap in the wire
B.A circuit that has little or no resistance
C.A circuit that uses little voltage
D.A circuit that uses very little wire
Answer:
B.A circuit that has little or no resistance
Explanation: a circuit is said to be short circuit if it has little or no resistance.
Shirt circuiting is very dangerous and can be done intentionally or unintended
D could also be correct if an amount of wire is ought to be used and you use a little wire. Knowing that wires have internal resistance too.
It could lead to short circuit
A stone is thrown upward at an angle. what happens to the horizontal component of its velocity as it rises? as it falls?
The horizontal component of the velocity of a stone thrown upward at an angle remains constant during its flight, as there is no horizontal force to affect it. This is due to the principles of projectile motion in physics. Gravity only affects the vertical velocity, not the horizontal.
Explanation:In physics, the motion of a projectile thrown at an angle can be separated into its vertical and horizontal components. Both of these components operate independently of each other. When a stone is thrown upward at an angle, the horizontal component of its velocity remains constant throughout the flight, under ideal conditions, because there's no horizontal force to cause acceleration or deceleration.
So, as the stone rises and falls, the horizontal velocity remains unchanged because gravity only affects the vertical component of the velocity. In this process known as projectile motion, gravity pulls the object downward, causing the vertical component of velocity to decrease as the stone rises, and increase as it falls, but the horizontal component is unaffected by gravity. The effect of air resistance is typically ignored in basic physics problems, but in reality, it would gradually decrease the stone's velocity in both directions.
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The acceleration of gravity at the surface of the moon is approximately 1/6 that at the surface of the earth (9.8 m/s2). what is the weight of an astronaut standing on the moon whose weight on earth is 210 lb?
The weight of an astronaut standing on the moon can be calculated using the equation weight = mass × acceleration due to gravity. By calculating the weight using the ratio of acceleration due to gravity on the moon compared to that on Earth, we find that an astronaut with a weight of 210 lb on Earth would weigh approximately 158.18 lb on the moon.
Explanation:The weight of an astronaut standing on the moon can be calculated using Newton's second law of motion. The formula to calculate weight is weight = mass × acceleration due to gravity. Since the acceleration due to gravity on the moon is approximately 1/6 that at the surface of the earth, we can calculate the weight using this ratio.
First, we need to convert the weight on earth from pounds to kilograms. Since 1 kilogram is approximately 2.2 pounds, we divide the weight on earth (210 lb) by 2.2 to get the weight in kilograms.
Next, we multiply the weight in kilograms by the acceleration due to gravity on the moon (1/6 of 9.8 m/s^2) to find the weight of the astronaut on the moon.
This results in a weight of approximately 158.18 lb on the moon for an astronaut whose weight on earth is 210 lb.
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When mass m is tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is 180 hz . adding an additional 1.2 kg to the hanging mass increases the second-harmonic frequency to 270 hz . part a what is m?
Given second-harmonic frequencies and added mass, solve [tex]\(1.5^2 = \frac{m + 1.2}{m}\) to find \( m = 0.96 \)[/tex] kg.
To find the mass [tex]\( m \)[/tex] that results in the given second-harmonic frequencies, we will use the formula for the frequency of standing waves on a wire under tension.
The second-harmonic frequency for a wire is given by:
[tex]\[f = \frac{2}{L} \sqrt{\frac{T}{\mu}}\][/tex]
where:
- [tex]\( f \)[/tex] is the frequency,
- [tex]\( L \)[/tex] is the length of the wire,
- [tex]\( T \)[/tex] is the tension in the wire,
- [tex]\( \mu \)[/tex] is the linear mass density of the wire.
The tension [tex]\( T \)[/tex] in the wire is due to the hanging mass [tex]\( m \)[/tex] and is given by:
[tex]\[T = mg\][/tex]
where [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]).
The second-harmonic frequency is given, so for the initial mass [tex]\( m \)[/tex]:
[tex]\[f_1 = 180 \, \text{Hz}\][/tex]
[tex]\[180 = \frac{2}{L} \sqrt{\frac{mg}{\mu}}\][/tex]
When an additional 1.2 kg is added to the mass, the new mass becomes [tex]\( m + 1.2 \)[/tex] kg and the second-harmonic frequency becomes:
[tex]\[f_2 = 270 \, \text{Hz}\][/tex]
[tex]\[270 = \frac{2}{L} \sqrt{\frac{(m + 1.2)g}{\mu}}\][/tex]
To find [tex]\( m \)[/tex], we will set up the ratio of the two frequencies and solve for [tex]\( m \)[/tex]:
[tex]\[\frac{f_2}{f_1} = \frac{270}{180} = 1.5\][/tex]
Using the ratio of the frequencies:
[tex]\[\frac{270}{180} = \frac{\sqrt{\frac{(m + 1.2)g}{\mu}}}{\sqrt{\frac{mg}{\mu}}}\][/tex]
Squaring both sides to eliminate the square roots:
[tex]\[\left(\frac{270}{180}\right)^2 = \frac{(m + 1.2)g}{mg}\][/tex]
[tex]\[\left(1.5\right)^2 = \frac{(m + 1.2)}{m}\][/tex]
[tex]\[2.25 = \frac{m + 1.2}{m}\][/tex]
Multiplying both sides by [tex]\( m \)[/tex]:
[tex]\[2.25m = m + 1.2\][/tex]
Solving for [tex]\( m \)[/tex]:
[tex]\[2.25m - m = 1.2\][/tex]
[tex]\[1.25m = 1.2\][/tex]
[tex]\[m = \frac{1.2}{1.25}\][/tex]
[tex]\[m = 0.96 \, \text{kg}\][/tex]
Therefore, the mass [tex]\( m \)[/tex] is [tex]\( 0.96 \)[/tex] kg.
Which statement correctly describes the current in a circuit that is made up of any two resistors connected in series with a battery
A. The current in the battery is less than the current in either resistor.
B. The current in the battery equals the product of the currents in the resistors.
C. The current in the battery equals the sum of the currents in the resistors.
D. The current in the battery and in each resistor is the samattery?
for those on ~ a p e x ~ note that this question asks when the resistors are connected in SERIES
if you have the question for in PARALLEL the answer is:
> The current the battery equals to the sum of the currents in the resistors
wink wonk
To what potential should you charge a 0.900 μf capacitor to store 1.50 j of energy
A small object carrying a charge of -2.50 nc is acted upon by a downward force of 18.0 nn when placed at a certain point in an electric field
B.What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"
Solution:
A) A charge q under an electric field of intensity E will experience a force F equal to:
[tex]F=qE[/tex]
In our problem we have [tex]q=-2.5 nC=-2.5\cdot 10^{-9} C[/tex] and [tex]F=18 nN = 18 \cdot 10^{-9} N[/tex], so we can find the magnitude of the electric field:
[tex]E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m [/tex]
The charge is negative, therefore it moves against the direction of the field lines. If the force is pushing down the charge, then the electric field lines go upward.
B) The proton charge is equal to
[tex]e=1.6\cdot 10^{-19} C[/tex]
Therefore, the magnitude of the force acting on the proton will be
[tex]F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N[/tex]
And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.