The main organ of the respiratory system

Answers

Answer 1
the airway, lungs, and muscles
Answer 2
The airway, the lungs, and the muscles of respiration. The airway, which includes the nose, mouth, pharynx, larynx, trachea, bronchi, and bronchioles, carries air between the lungs and the body's exterior.

Related Questions

In this layer of Earth's atmosphere, hydrogen and helium are the prime gases and are only present at extremely low densities. What is this layer of the atmosphere called?
A) exosphere
B) ionosphere.
C) mesosphere
D) thermosphere

Answers

The answer would be the EXOSPHERE. The exosphere is the highest layer of the atmosphere. This layer merges with space and the air is extremely thin. Molecules of air here always escape from the from the exosphere to space. This is also the layer where satellites orbit the Earth. 

The answer a. 

Select all that apply.

Images produced by a flat mirror are _____.

inverted (upside down)
left-right reversed
upright
diminished in size
enlarged
real
virtual

Answers

The correct options are:

- upright (the image of a flat mirror always appear in the same vertical-orientation of the object)
- left-right reversed (the image of a flat mirror always appear inverted in the horizontal direction)
- virtual (the image appears in fact behind the plane of the mirror)

Answer:

-left-right reversed

-upright

-virtual

I just did this in my lesson.

Which describes how a turbine works to produce energy for electricity? A. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine. The turbine then powers a generator, which produces electricity. B. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine, which produces electricity. C. The turbine produces energy from various energy sources like wind or burning fossil fuels to drive the generator to make electricity. D. The generator produces energy from various energy sources like wind or burning fossil fuels to drive the turbine to make electricity.

Answers

The answer is A. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine. The turbine then powers a generator, which produces electricity.

Works on simple principle of the turbine blades translation of energy sources causing the mechanical spin of the blades which is connected to a rotor which spins the main shaft of generator thus producing electricity.

Answer:

A. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine.

Explanation:

The answer above mine was EXTREMELY HELPFUL because I had a similar question needing to be answered, and that helped me figure out the correct answer to my question, so THANK YOU!!!

Hope that this was helpful information for anyone needing it! <3

a 920-g empty iron kettle is out on a hot stove. how much heat must the kettle absorb to raise its temperature 15.0 Celsius to 93.0 celsius the especific heat capacity iron is 470 j/kg * k

Answers

Final answer:

The iron kettle must absorb 33,768 joules of heat energy to raise its temperature from 15.0 Celsius to 93.0 Celsius.

Explanation:

To calculate the amount of heat the iron kettle must absorb, we can use the formula:

q = mcΔT

where:

q is the heat absorbed (in joules)m is the mass of the iron kettle (in grams)c is the specific heat capacity (in J/g°C)ΔT is the change in temperature (in Celsius)

Plugging in the given values:

q = (920g) x (0.470 J/g°C) x (93.0°C - 15.0°C)

q = (920g) x (0.470 J/g°C) x (78.0°C)

q = (920g) x (36.66 J/°C)

q = 33768 J

Therefore, the iron kettle must absorb 33,768 joules of heat energy to raise its temperature from 15.0 Celsius to 93.0 Celsius.

what is the energy (in eV units) carried by one photon violet light that has a wavelength of 4.5e-7?

Answers

The energy of a photon is given by
[tex]E=hf[/tex]
where h is the Planck constant and f is the photon frequency.

We can find the photon's frequency by using the following relationship:
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and [tex]\lambda[/tex] is the photon's wavelength. By plugging numbers into the equation, we find
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.67 \cdot 10^{14}Hz [/tex]

And so now we can find the photon energy
[tex]E=hf=(6.6 \cdot 10^{-34} Js)(6.67 \cdot 10^{14}Hz )=4.4 \cdot 10^{-19} J[/tex]

We know that 1 Joule corresponds to
[tex]1 J = 1.6 \cdot 10^{-19} eV[/tex]
So we can convert the photon's energy into electronvolts:
[tex]E= \frac{4.4 \cdot 10^{-19} J }{1.6 \cdot 10^{-19} J/eV}=2.75 eV [/tex]

A photon of violet light with a wavelength of 4.5×10⁻⁷ meters carries approximately 2.75 electron-volts (eV) of energy.

To find the energy of a photon of violet light with a wavelength of 4.5×10⁻⁷ meters, we can use the formula for energy in terms of wavelength:

Energy (E) = h * c / λ

Here,

h is Planck's constant (6.626 × 10⁻³⁴ J·s)c is the speed of light (3 × 10⁸ m/s)λ is the wavelength (4.5 × 10⁻⁷ meters)

Substituting the values into the formula:

E = (6.626 × 10⁻³⁴ J·s) * (3 × 10⁸ m/s) / (4.5 × 10⁻⁷ m)

E = 4.414 × 10⁻¹⁹ J

Since we want the energy in electron-volts (eV), we convert from joules using the conversion factor 1 eV = 1.602 × 10⁻¹⁹ J:

E = (4.414 × 10⁻¹⁹ J) / (1.602 × 10⁻¹⁹ J/eV)

E ≈ 2.75 eV

Therefore, a photon of violet light with a wavelength of 4.5×10⁻⁷ meters carries approximately 2.75 eV of energy.

For a certain transverse wave, the distance between two successive crests is 1.20 m and eight additional crests pass a given point along the direction of travel every 13.00 s. calculate the wave speed.

Answers

The distance between two succesive crests of a wave corresponds to its wavelength, therefore the wavelength of this wave is
[tex]\lambda=1.20 m[/tex]

The frequency of a wave is the number of crests that passes through a given point in a certain time; therefore, for this wave it is:
[tex]f= \frac{N}{t}= \frac{8}{13.00 s}=0.62 Hz [/tex]

And now we can calculate the wave speed, which is given by the product between the wavelength and the frequency:
[tex]v= \lambda f = (1.20 m)(0.62 Hz)=0.74 m/s[/tex]

Final answer:

The wave speed is calculated using the frequency and the wavelength. With the provided distance between crests (1.20 m) and the time for crests to pass (13 s), the wave speed is found to be approximately 0.8308 m/s.

Explanation:

The distance between two successive crests of a transverse wave is equal to one wavelength. If eight additional crests pass a given point in 13 seconds, it means that nine crests in total pass that point in 13 seconds because the first crest is observed at the beginning of the timing. The speed of the wave (v) can be calculated using the formula v = frequency x wavelength. Here, the wavelength (λ) is given as 1.20 meters.

To find the frequency, we use the number of waves passing a point divided by the time taken. Therefore, the frequency (f) is 9 crests / 13 seconds = 0.6923 Hz (where Hz represents Hertz or cycles per second).

Using the wave speed formula, we obtain the speed: v = 0.6923 Hz x 1.20 m = 0.8308 m/s. Thus, the wave speed is approximately 0.8308 meters per second.

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A 4.0 ω resistor, an 8.0 ω resistor, and a 13.0 ω resistor are connected in parallel across a 24.0 v battery. what is the equivalent resistance of the circuit? answer in units of ω.

Answers

104/47 ω
____________

sound

· parallel

· mechanical

· not a vacuum

· needs a medium

· compressions and rarefaction

What type of wave is being described?

A) compaction

B) electromagnetic

C) longitudinal

D) transverse

Answers

It is a longitudinal wave. In a longitudinal wave the particles of the medium vibrate in a direction parallel to the direction of energy transport. Sound waves are mechanical waves as well as longitudinal waves that require a medium. They do not travel through a vacuum.

a type of rock that forms when particles from other rocks or the remains of plants and animals are pressed and cemented together

Answers

A sedimentary rock is a type of rock that forms when particles from other rocks or the remains of plants and animals are pressed and cemented together.

Sedimentary rock is formed from the compaction and cementation of sediment originating from other rocks or organic material. This process results in various types of sedimentary rocks, like sandstone and shale.

The type of rock that forms when particles from other rocks or the remains of plants and animals are pressed and cemented together is known as sedimentary rock. These rocks are created through a multi-step process starting with the deposition of sediment that comes from the weathering and erosion of pre-existing rocks (clasts), or from the accumulation of plant and animal material. Over time, these deposited sediments may harden into rock through two main processes:

Compaction: where sediments are squeezed together under the weight of sediments above them.

Cementation: where minerals fill in the spaces between the loose sediment particles.

This process creates various types of sedimentary rocks, such as clastic rocks which are fragments compacted and cemented together, and organic sedimentary rocks which are formed from the lithification of organic material. Examples of sedimentary rocks include sandstone, formed from cemented sand; shale, formed from compressed mud and silt; and conglomerate, composed of cemented gravel and pebbles.

Photons of what minimum frequency are required to remove electrons from gold? note: the work function for gold is 4.8 ev.

Answers

In the photoelectric effect, the energy given by the incoming photon is used partially to extract the electron from the metal (work function) and the rest is converted into kinetic energy of the electron:
[tex]hf= \phi + K[/tex]
where
hf is the energy of the photon, with h being the Planck constant and f the frequency of the photon
[tex]\phi[/tex] is the work function
K is the kinetic energy of the electron

When K=0, we have the minimum energy required to extract the electron from the metal, so the equation becomes
[tex]hf= \phi[/tex] (1)

If we convert the work function of gold into Joules:
[tex]\phi=4.8 eV = 7.69 \cdot 10^{-19}J[/tex]
We can re-arrange eq.(1) to find the minimum energy of the photon:
[tex]f= \frac{\phi}{h}= \frac{7.69 \cdot 10^{-19}J}{6.6 \cdot 10^{-34} Js} =1.17 \cdot 10^{15} Hz [/tex]

When touched by a plastic straw, the metal sphere will do what?

Answers

I believe that if you touch a metal sphere with a plastic straw, the straw would not have enough strength to push it. So in that case, the metal sphere will not move and will stay in one place.

Please rate a 5 star

if an observer is hearing a rise in pitch that means the frequency of the waves in their position are falling

Answers

The statement above is FALSE.
Pitch refers to the highness or lowness of a sound. The pitch of a sound depends on the frequency of that pitch. The higher the frequency, the higher the pitch and the lower the frequency, the lower the pitch. Thus, if an observer is hearing a rise in pitch that means the frequency of the waves in that position are increasing.

Tony made 14 liters of lemonade for a party. His guests drank 9500 mL of the lemonade. After the party Tony had mL of lemonade left over.

Answers

There are 1000 milliliters (mL) in a liter (L). Remember that the prefix milli- means one thousandth. 

Since Tony made 14 liters, that means he made:
[tex]14 \: L \times \frac{1000\: mL}{L} = 14000 \: mL \: total[/tex]

His guests drank 9500 mL, so subtract from the total amount of lemonade made to get the amount left over:
[tex]14000 \: mL - 9500 \:mL = 4500\: mL[/tex]

------

Answer: 4500 mL

Answer:

4500

Explanation:

What is the frequency of a pressure wave of wavelength 2.5 m that is traveling at 1400 m/s?

Answers

The relationship between the speed, the frequency and the wavelength of a wave is given by:
[tex]f= \frac{v}{\lambda} [/tex]
where
f is the frequency
v is the speed of the wave
[tex]\lambda[/tex] is its wavelength

for the pressure wave in this problem, [tex]\lambda=2.5 m[/tex] and v=1400 m/s, therefore its frequency is
[tex]f= \frac{v}{\lambda}= \frac{1400 m/s}{2.5 m}=560 Hz [/tex]

Determine the number of unpaired electrons in the octahedral coordination complex [fex6]3–, where x = any halide.

Answers

Unpaired electron is the electron, that occupies the a place in orbital without the pair of electron. The number of unpaired electron in 3d sub shell of octahedral coordination complex [tex][FeX_6]^{2-}[/tex] is 3.

The given octahedral coordination complex in the problem is [tex]{FeX_6]^{2-}[/tex]

Here, [tex]X[/tex] is the halogen.

What is unpaired electron?

Unpaired electron is the electron, that occupies the a place in orbital without the pair of electron.

In the given complex ion +3 oxidation state [tex]F[/tex] (iron) represents in,

[tex]_{26}F^{3+}=1s^2, 2s^2 2p^6, 3s^23p^63d^6,4s^2\\[/tex]

[tex]F^{3+}=1s^2, 2s^2 2p^6, 3s^23p^63d^6[/tex]

As the unpaired electron in 3d sub shell is 3.

Hence the number of unpaired electron in 3d sub shell of octahedral coordination complex [tex][FeX_6]^{2-}[/tex] is 3.

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Final answer:

The [FeX₆]³− octahedral complex, with iron in a d5 configuration and halides as weak field ligands, will have five unpaired electrons due to the high-spin configuration created by the ligands.

Explanation:

To determine the number of unpaired electrons in the octahedral coordination complex [FeX₆]³−, where X represents any halide, we will apply crystal field theory (CFT). First, we note that iron in this complex exists in a +3 oxidation state, which gives it a d5 electron configuration since the neutral iron atom has 8 valence electrons (3d6 4s2).

For any halide as a weak field ligand in an octahedral complex, the crystal field splitting is not sufficient to overcome the electron pairing energy. This results in a high-spin complex for iron (III), where all the d-orbitals initially receive one electron each before any pairing occurs.

Thus, the [FeX₆]³− complex will have five unpaired electrons, one in each of the 3d orbitals, as halides create a high-spin configuration for a d5 metal ion like iron (III).

A charged particle is projected with its initial velocity parallel to a uniform magnetic field. what is the resulting path? 1. parabolic arc. 2. circular arc. 3. straight line parallel to the field. 4. straight line perpendicular to the field. 5. spiral.

Answers

If a charged particle is projected with its initial velocity parallel to a uniform magnetic field, then the resulting path would be a straight line parallel to the field, therefore the correct answer is option 3.

What is a magnetic field?

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted .

As given in the problem if a  charged particle is projected with its initial velocity parallel to a uniform magnetic field then we have to find out what would be the resulting path of the particle .

Thus , the right response is option 3, as the path of a charged particle projected with its starting velocity parallel to a uniform magnetic field would be a straight line parallel to the field .

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A block oscillating on a spring has a maximum speed of 20 cm/s. part a what will the block's maximum speed be if its total energy is doubled?

Answers

Final answer:

When the total energy of a system consisting of a block and a spring is doubled, the new maximum speed of the block will be sqrt(2) times its original maximum speed. If the original speed was 20 cm/s, the new max speed will be about 28.28 cm/s.

Explanation:

The maximum speed of a block oscillating on a spring is determined by its total mechanical energy, which is the sum of its kinetic and potential energy. In a frictionless system, when the kinetic energy is maximum, the potential energy is zero, and vice versa. When the total energy of the system is doubled, both the kinetic and potential energy will double when the block is at their maximum values. Since the maximum speed (v_max) is directly related to the maximum kinetic energy (which is 1/2 m v_max^2, where m is the mass of the block), if the total energy doubles and mass remains the same, the new maximum speed will be the square root of 2 times the original maximum speed. Hence, if the original maximum speed is 20 cm/s, the new maximum speed will be 20 cm/s * sqrt(2), approximately equal to 28.28 cm/s.

Given the initial maximum speed of 20 cm/s, the new maximum speed will be approximately 28.3 cm/s.

To determine the block's maximum speed when its total energy is doubled, we need to understand how the energy in a spring-mass system is related to its speed.

In a spring-mass system, the total mechanical energy (E) is the sum of its potential energy (U) and kinetic energy (K). The equation for kinetic energy (K) at maximum speed (V(max)) is given by:

K = ½mV(max)²

where

m is the mass of the block.

Since the problem states that the initial maximum speed (V(max)) is 20 cm/s (or 0.2 m/s), we need to find the new maximum speed when the total energy is doubled.

Knowing that the total energy is proportional to the square of the maximum speed, we can set up the following relationship:

E_new = 2E_original

Considering the kinetic energy component:

½mV(max_new)² = 2(½mV(max)²)

Canceling out the common factors, we get:

V(max_new)² = 2V(max)²V(max_new) = sqrt(2) * V(max)

Given the initial maximum speed (V(max)) is 20 cm/s:

V(max_new) = sqrt(2) * 20 cm/s ≈ 1.414 * 20 cm/s V(max_new) ≈ 28.3 cm/s

Thus, the block's maximum speed will be approximately 28.3 cm/s if its total energy is doubled.

What is the relationship between radiopharmaceuticals, tracers, and radionuclides?

Answers

The radiopharmaceuticals are defined as a radioactive compound used for the treatment of diseases. While this also commonly called in other termed known as Radionuclides or Tracer. It is a radioactive material.

Answer:

They are all radioactive

Explanation:

Radiopharmaceuticals, or medicinal radiocompounds, are a group of pharmaceuticals that contain radioactive isotopes. Radiopharmaceuticals are used as diagnostic and therapeutic agents.

A radioactive tracer, is a chemical compound in which one or more atoms have been replaced by a radionuclide so that as a result of of its radioactive decay the nuclide can be used to explore the mechanism of chemical reactions by carefully tracing the path that the radioisotope follows from reactants to products.

Radionuclides are species of atoms that emit radiation by undergoing radioactive decay leading to the emission of alpha particles (α), beta particles (β), or gamma rays (γ).

From the foregoing, radiopharmaceuticals, tracers, and radionuclides are all radioactive materials. Hence the answer.

At what rate must electrons in a wire vibrate to emit microwaves with a wavelength of 1.00 mm

Answers

The equation to use is v=fλ where v is the speed of light, f is the frequency, i.e. the rate at which they vibrate, and λ is the wavelength in meters.

Rearrange the above equation and you get f=v/λ. So the answer is f=300000000/0.001 or 300GHz.

Answer:

f = 3×10¹¹ Hz

Explanation:

Relation ship between frequency and wavelength

"The wave speed (v) is defined as the distance traveled by a wave per unit time. If considered that the wave travels a distance of one wavelength in one period,

ν=λ/T

As we know that T = 1/f, hence we can express the above equation as,

V = f λ

The wave speed is equal to the product of its frequency and wavelength, and this implies the relationship between frequency and wavelength."

The relation between frequency and wavelength is  

λ×f = c

c = speed of light = 3×10⁸ m/s

λ = 1.00 mm = 10⁻³ m

f=c/λ

f=(3×10⁸ m/s)/   10⁻³ m

f = 3×10¹¹ Hz

If the potential across two parallel plates, separated by 3 cm, is 12 volts, what is the electric field strength in volts per meter? E = _____ volts/m

Answers

there are 100cm in 1m, divide 100 by 3 and you get 33, multiply that by 12 and you get  396 volts/m.

Hope this is correct and helps.

Answer:

E = 400 V/m

Explanation:

It is given that, for a parallel plates :

Potential difference, V = 12 volts

Separation between the plates, d = 3 cm = 0.03 m

The relation between the electric field and the electric potential is given as :

[tex]E=\dfrac{V}{d}[/tex]

[tex]E=\dfrac{12\ V}{0.03\ m}[/tex]

E = 400 volts/m

So, the strength of the electric field is 400 V/m.                

What is the electric potential energy of a charge that experiences a force of 3.6 x 10^-4N when it is 9.8 x 10^-5 from the source of the electric field

Answers

The electric potential energy of the charge is equal to the potential at the location of the charge, V, times the charge, q:
[tex]U=qV[/tex]
The potential is given by the magnitude of the electric field, E, times the distance, d:
[tex]V=Ed[/tex]
So we have
[tex]U=qEd[/tex] (1)
However, the electric field is equal to the electrical force F divided by the charge q:
[tex]E= \frac{F}{q} [/tex]
Therefore (1) becomes
[tex]U=Fd[/tex]
And if we use the data of the problem, we can calculate the electrical potential energy of the charge:
[tex]U=Fd=(3.6 \cdot 10^{-4}N)(9.8 \cdot 10^{-5} m)=3.53 \cdot 10^{-8} J[/tex]

What is the wavelength corresponding to the most intense light emitted by a giant star of surface temperature 4400 k?

Answers

This can be calculated by applying Wein displacement law which is stated as follows;

Maximum wavelength (m)*Temperature (K) = 2.90 *10^-3  m.K

Therefore, substituting for the values given;
Wavelength = (2.90*10^-3)/T = (2.90*10^-3)/4400 = 6.59*10^-7 m ≈ 659 nm

Final answer:

The wavelength corresponding to the most intense light emitted by a giant star with a surface temperature of 4400 K is approximately 681.8 nm.

Explanation:

According to Wien's law, the wavelength at which the most intense light is emitted by a giant star can be determined using the formula:
wavelength = 3 x 10^6 / temperature

In this case, the surface temperature of the giant star is 4400 K. Plugging in this value into the formula, we get:
wavelength = 3 x 10^6 / 4400 = 681.8 nm

Therefore, the wavelength corresponding to the most intense light emitted by the giant star is approximately 681.8 nm.

Microwave ovens emit microwave energy with a wavelength of 13.0 cm. what is the energy of exactly one photon of this microwave radiation?

Answers

First, let's calculate the frequency of this radiation, which is given by:
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and [tex]\lambda[/tex] is the photon wavelength. For this radiation, photons have wavelength of
[tex]\lambda=13.0 cm=0.13 m[/tex]
Therefore their frequency is
[tex]f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{0.13 m}=2.3\cdot 10^9 Hz [/tex]

The energy of a photon with frequency f is given by
[tex]E=hf[/tex]
where h is the Planck constant. By using the frequency we found before, we find the energy of a single photon of this radiation:
[tex]E=hf=(6.6 \cdot 10^{-34} Js)(2.3 \cdot 10^9 Hz)=1.52 \cdot 10^{-24} J[/tex]

The energy of exactly one photon of this microwave radiation is 1.53 × 10⁻²⁴Joule

Further explanation

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

[tex]\large {\boxed {E = h \times f}}[/tex]

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]

[tex]\large {\boxed {E = qV + \Phi}}[/tex]

E = Energi of A Photon ( Joule )

m = Mass of an Electron ( kg )

v = Electron Release Speed ( m/s )

Ф = Work Function of Metal ( Joule )

q = Charge of an Electron ( Coulomb )

V = Stopping Potential ( Volt )

Let us now tackle the problem!

Given:

λ = 13.0 cm = 13.0 × 10⁻² m

Unknown:

E = ?

Solution:

[tex]E = h f[/tex]

[tex]E = h \frac{c}{\lambda}[/tex]

[tex]E = 6.63 \times 10^{-34} \frac{3 \times 10^8}{13.0 \times 10^{-2}}[/tex]

[tex]\large {\boxed {E = 1.53 \times 10^{-24} ~ Joule } }[/tex]

Learn morePhotoelectric Effect : https://brainly.com/question/1408276Statements about the Photoelectric Effect : https://brainly.com/question/9260704Rutherford model and Photoelecric Effect : https://brainly.com/question/1458544Photoelectric Threshold Wavelength : https://brainly.com/question/10015690

Answer details

Grade: High School

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Photoelectric , Effect , Threshold , Frequency , Electronvolt

2) calculate the wavelength, in nanometers, of infrared radiation that has a frequency of 9.76 x 1013 hz.

Answers

The relationship between wavelength, frequency and speed of an electromagnetic wave is given by
[tex]c= \lambda f[/tex]
where
c is the speed of light
[tex]\lambda[/tex] is the wavelength
f is the frequency

The infrared radiation of our problem has frequency [tex]f=9.76 \cdot 10^{13}Hz[/tex], therefore if we re-arrange the previous equation we can calculate its wavelength:
[tex]\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{9.76 \cdot 10^{13} Hz}=3.07 \cdot 10^{-6} m [/tex]
and converted into nanometers,
[tex]\lambda=3070 nm[/tex]

The wavelength of infrared radiation with a frequency of 9.76 x 10^13 Hz is calculated to be 3070 nanometers by using the relationship between wavelength, frequency, and the speed of light.

The question asks us to calculate the wavelength of infrared radiation with a given frequency of 9.76 x 1013 hertz (Hz). To find the wavelength, we will use the formula that relates wavelength (λ), frequency (ƒ), and the speed of light (c):

λν = c

Where λ is the wavelength, ν is the frequency, and c is the speed of light (c = 3 x 108 meters per second). Solving for λ, we get:

λ = c / ν

Now we can plug in the given values:

λ = (3 x 108 m/s) / (9.76 x 1013 Hz)

λ = 3.07 x 10-6 meters

Since the question asks for the wavelength in nanometers, we convert meters to nanometers by multiplying by 109:

λ = 3.07 x 10-6 meters x 109 nm/meter

λ = 3070 nm

Therefore, the wavelength of the infrared radiation is 3070 nanometers.

If a magnet is broken into two pieces what happens to the magnetic poles?

Answers

Answer:

B.) Each piece will still have a north pole and a south pole

Explanation:

I just did it

Final answer:

When a bar magnet is cut into two pieces, each half becomes a smaller magnet with its own north and south pole. Magnetic domains within the magnet ensure that these poles always exist in pairs, a fundamental characteristic of magnets called magnetic dipoles, and cannot be isolated. Even at the smallest scale, no magnet exists with only a single pole.

Explanation:

If you cut a bar magnet into two pieces, you will not end up with one piece having two north poles and another piece having two south poles. Instead, each piece will have its own north and south pole, making each piece a smaller, complete magnet. This property is consistent even down to the smallest particles with magnetic properties.

All magnets have a north and a south pole, and they always occur in pairs—this is why they are called magnetic dipoles ('di' meaning two). The presence of both poles in any fragment of a magnet implies that if you were to continue cutting the magnet, no matter how small, you would still get pieces with both a north and a south pole. No matter the size, from subatomic particles to stars, a magnet cannot have a single isolated pole.

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What is the highest point on this map?

A. 30 meters


B. 35 meters


C. 52 meters


D. 60 meters

Answers

C. 52 meters because you can see that it represents the tip of a mountain. The answer would be 60 meters but there is no 60 meters shown on the map.

where should the property "little voltage loss across long distances" be placed in a Venn Diagram?
A) direct current
B) alternating current
C) both alternating and direct current
D) neither alternating nor direct current

Answers

The correct answer for the question, "Where should the property "little voltage loss across long distances" be placed in a Venn Diagram?" is :  B) alternating current. 
A type of current that periodically reverses in direction is called alternating current. 

The answer is B i know this because i just did it on usatestprep

When a baseball player catches a baseball, the glove "gives" or moves backward. How does this movement affect the change in momentum of the baseball?


A The change in momentum increases because the impact time increases.

B The change in momentum stays the same because the ball still comes to a stop.

Answers


B The change in momentum stays the same because the ball still comes to a stop.

Answer:

The change in momentum increases because the impact time increases.

Explanation:

When a baseball player catches a baseball, the glove "gives" or moves backward. Momentum of a body is equal to the product of mass and velocity. Also, the change of momentum of an object when it is acted by a force is called impulse. It is represented by J. Mathematically, it can be written as :

[tex]J=F.\Delta t=m\Delta v[/tex]

F is applied force

[tex]\Delta t[/tex] is the time taken by an object to change its momentum

The momentum depends on the force and the time of impact. In this case, as the a baseball player catches a baseball, the gloves move in backward direction. By doing so, the ball comes to rest in larger time.

So, the change in momentum increases because the impact time increases.

Why does the amount of water that flows in a river change during the year?

Answers

hey 

in the summer it is because of the meting  of snow 
in the spring it is rain

hope l helped

An ice skater starts a spin with her arms stretched out to the sides. she balances on the tip of one skate to turn without friction. she then pulls her arms in so that her moment of inertia decreases by a factor of two. in the process of her doing so, what happens to her kinetic energy?

Answers

I₁ = initial moment of inertia before pulling in the arms

I₂ = final moment of inertia after pulling in the arms = I₁ /2

w₁ = initial angular velocity before pulling in the arms

w₂ = final angular velocity after pulling in the arms

using conservation of angular momentum

I₁ w₁ = I₂ w₂

I₁ w₁ = (I₁/2 ) w₂

w₂ = 2 w₁

KE₁ = initial rotational kinetic energy before pulling in the arms = (0.5) I₁ w²₁

KE₂ = final rotational kinetic energy after pulling in the arms = (0.5) I₂ w²₂

Ratio of final rotational kinetic energy to initial rotational kinetic energy is given as

KE₂ /KE₁ = (0.5) I₂ w²₂/((0.5) I₁ w²₁ )

KE₂ /KE₁ = ((I₁/2 ) (2 w₁)²)/(I₁ w²₁)

KE₂ /KE₁ = 2

KE₂ = 2 KE₁

hence the kinetic energy becomes twice

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