Answer:
for the water cycle
Explanation:
Predict the effect of adding a non competitive inhibitor to the reaction mixture on the rate of reaction at a high substrate concentration. Support your prediction by describing how a non competitive inhibitor affects the structure and function of an enzyme.
Answer:
A noncompetitive inhibitor can only bind to an enzyme with or without a substrate at several places at a particular point in time
Explanation:
this is because It changes the conformation of an enzyme as well as its active site, which makes the substrate unable to bind to the enzyme effectively so that the efficiency of the enzyme decreases. A noncompetitive inhibitor binds to the enzyme away from the active site, altering/distorting the shape of the enzyme so that even if the substrate can bind, the active site functions less effectively and most of the time also the inhibitor is reversible
Examine the reaction C 3 H 8 +5O2—>3CO 2 +4H 2 O. If the reaction starts with 2.5g C 3 H 8 what is the theoretical yield of water ? If the reactant yields 75 % of the theoretical yield of water, how many grams of water were produced?
Answer:
Theoretical yield = 4.09 g water.
75% yield = 3.07g water.
Explanation:
C3H8 + 5O2 ---> 3CO2 + 4H2O
Using atomic masses:
(12 *3 + 8 * 1.008) g C3H8 yield (theoretically) (4* (2*1.008 + 16) g water
44.06g C3H8 yields 72.06g water
So 2.5 g yields (72.06/44.06) * 2.5
= 4.09 g water.
If the yield is 75% then it is 4.09 * 0.75
= 3.07 g water.
If I correct, answer is C, 75%.
Exactly 16 mL of a solution A is diluted to 300 mL, resulting in a new solution B that has 0.50 M concentration. If the solution was made with NaCl (58.443 g/mole), determine the number of grams of NaCl needed to make 1.00 L of the original solution A.
Answer:
8.77g
Explanation:
Step 1:
Data obtained from the question.
This includes the following:
Concentration of A (C1) =.?
Volume of A (V1) = 16 mL
Volume of B (V2) = 300 mL
Concentration of B (C2) = 0.50 M
Molar Mass of NaCl = 58.443 g/mol
Mass of NaCl =.?
Step 2:
Determination of the concentration of A.
Applying the dilution formula:
C1V1 = C2V2
The concentration of A i.e C1 can be obtained as follow:
C1V1 = C2V2
C1 x 16 = 0.5 x 300
Divide both side by 16
C1 = (0.5 x 300) / 16
C1 = 9.375 M
Therefore, the concentration of A is 9.375 M
Step 3:
Determination of the number of mole of NaCl in 9.375 M NaCl solution. This is illustrated below:
Molarity = 9.375 M
Volume = 16 mL = 16/1000 = 0.016 L
Mole of NaCl =?
Molarity = mole /Volume
Mole =Molarity x Volume
Mole of NaCl = 9.375 x 0.016
Mole of NaCl = 0.15 mole
Step 4:
Determination of the mass of NaCl. This is illustrated below:
Mole of NaCl = 0.15 mole
Molar Mass of NaCl = 58.443 g/mol
Mass of NaCl =?
Mass = number of mole x molar Mass
Mass of NaCl = 0.15 x 58.443
Mass of NaCl = 8.77g
Therefore, 8.77g of NaCl is needed to make 1 L of the original solution A.
Answer:
We need 8.77 grams of NaCl
Explanation:
Step 1: Data given
Volume of solution A = 16 mL = 0.016 L
Volume of solution B = 300 mL = 0.300 L
Concentration of solution B = 0.50 M
Step 2: Calculate molarity of solution A
C1*V1 = C2*V2
⇒with C1 = the concentration of solution A = TO BE DETERMINED
⇒with V1 = the volume of solution A = 0.016 L
⇒with C2 = the concentration of solution B = 0.50 M
⇒with V2 = the volume of solution B = 0.300 L
C1 * 0.016 L = 0.50 M * 0.300 L
C1 = 9.375 M
Step 3: Calculate moles of solution A
Moles = molarity * volume
Moles = 9.375 M * 0.016 L
Moles = 0.15 moles
Step 4: Calculate mass of NaCl needed
Mass NaCl = moles / molar mass
Mass NaCl = 0.15 moles * 58.443 g/mol
Mass NaCl = 8.77 grams
We need 8.77 grams of NaCl
1.Which has a larger radius Ca atom or Ca+2 ion?
2.Which has a greater radius F atom or F- ion?
3.Which is the correct way of understanding the trend for Ionic radius Vs. Atomic radius?
Answer:
1.Ca atom has greater radius than Ca+2
2.F- ion has larger radius than F
1. The Ca+2 ion has a smaller radius than the Ca atom. 2. The F- ion has a larger radius than the F atom. 3. The trend for ionic radius vs. atomic radius is that ions are generally smaller than their corresponding atoms.
Explanation:1. The Ca+2 ion has a smaller radius than the Ca atom. When an atom loses electrons to become a cation, it loses its outermost electrons, resulting in a decrease in the size of its electron cloud and thus a smaller radius.
2. The F- ion has a larger radius than the F atom. When an atom gains electrons to become an anion, it adds electrons to its outermost energy level, resulting in an increase in the size of its electron cloud and thus a larger radius.
3. The trend for ionic radius vs. atomic radius is that ions are generally smaller than their corresponding atoms. Cations are smaller than their parent atoms because they have lost electrons, which reduces the electron cloud and decreases the size. Anions are larger than their parent atoms because they have gained electrons, which increases the electron cloud and increases the size.
Which is the correct equation for: iron + sulfur → iron (III) sulfide
The correct option is D.
What are Chemical Equations?
They are equations that make use of chemical formulae and symbols to represent chemical reactions. The left-hand side of a chemical equation represents the reactants and the right-hand side represents the products. These entities are separated by a symbol that describes the direction of the reaction. Each reacting entity is also assigned its corresponding stoichiometric coefficient.
What are the 5 types of equations?There are five basic categories given below.
synthesis, decomposition, combustion, single replacement,double replacement.Learn more about chemical equations here https://brainly.com/question/26227625
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Which statement defines the heat capacity of a sample?
Answer:
The specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample. Informally, it is the amount of energy that must be added, in the form of heat, to one unit of mass of the substance in order to cause an increase of one unit in its temperature.
Explanation:
More explanation...
The ratio of the heat energy absorbed by a substance to its increase in temperature. Heat capacity is also called thermal capacity. The specific heat or specific heat capacity of a substance is the heat capacity per unit mass, usually measured in joules per kilogram per degree Kelvin.
- Without the statements, I will not be able to give an exact answer. Hope this helps!
Answer:
D) the quantity of heat that is required to raise 1 g of the sample by 1°C (Kelvin) at a constant pressure
Explanation:
on edg
Select the word(s) to complete the word equation that matches the description of the reaction.
Electrolysis breaks down water to form hydrogen and oxygen gas.
A. The word equation that represents this reaction is: water A bright light is produced when magnesium reacts with the oxygen in air to form magnesium oxide.
B. The word equation that represents this reaction is: magnesium oxygen When methane burns, it reacts with oxygen to produce water and carbon dioxide.
C. The word equation that represents this reaction is: methane oxygen
The word equation can be represented as the constituents of the equation are written in their full name rather than a symbol.
The word equations for the following descriptions are:
Electrolysis breaks down water to form hydrogen and oxygen gas:Water = Hydrogen + Oxygen
A bright light is produced when magnesium reacts with the oxygen in the air to form magnesium oxide.Magnesium + Oxygen = Magnesium Oxide
When methane burns, it reacts with oxygen to produce water and carbon dioxide.Methane + Oxygen = Carbon dioxide + water
For more information about the word equation, refer to the link:
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To complete the given word equations:
A. Water -> hydrogen + oxygen;
B. Magnesium + oxygen -> magnesium oxide;
C. Methane + oxygen -> carbon dioxide + water.
To complete the word equations for the described reactions, we need to identify the reactants and products in each case:
A. Electrolysis: The word equation that represents the breakdown of water into hydrogen and oxygen gas is:
water -> hydrogen + oxygenB. Magnesium Oxidation: The word equation describing the reaction of magnesium with oxygen to form magnesium oxide is:
magnesium + oxygen -> magnesium oxideC. Methane Combustion: The word equation for the burning of methane in oxygen to produce water and carbon dioxide is:
methane + oxygen -> carbon dioxide + waterWrite the word(s) to complete the word equation that matches the description of the reaction.
A. Electrolysis breaks down water to form hydrogen and oxygen gas. The word equation that represents this reaction is:
water -->
B. A bright light is produced when magnesium reacts with the oxygen in air to form magnesium oxide. The word equation that represents this reaction is:
magnesium + oxygen -->
C. When methane burns, it reacts with oxygen to produce water and carbon dioxide. The word equation that represents this reaction is:
methane + oxygen -->
Use the following information on Cr to determine the amount of heat required to convert 159.6 g of solid Cr at 1760°C into liquid Cr at 2060°C. melting point = 1860°C; boiling point = 2672°C ΔHfus = 20.5 kJ/mol; ΔHvap = 339 kJ/mol; c(solid) = 44.8 J/g°C; c(liquid) = 0.94 J/g°C Enter your answer in units of kJ to three significant figures.
Answer:
793 kJ
Explanation:
Given that :
[tex]T_1 = 1760^0C\\\\T_2 = 2060^0C\\\\ c_s = 44.8 \ J/g \ ^0C[/tex]
Then; the heat needed to convert solid from [tex]1760^0C \ to \ 1860^0C[/tex] is calculated as:
[tex]Q_1 = mc_s \delta T[/tex]
[tex]Q_1 = mc_s (T_f - T_i)[/tex]
[tex]Q_1 = 159.6*44.8(1860-1760)^0C \\ \\ Q_1 = 715008 \ J[/tex]
Also;
[tex]\delta H_f = 20.5 \ kJ/mol = 20500 \ J/mol \\ \\ Molar \ mass \ of \ Cr = 52.0 g/mol \\ \\ number \ of \ moles\ of \ Cr = \frac{mass \ of \ Cr}{molar \ mass} \\ \\ = \frac{159.6}{52.0}\\\\= 3.069 \ mol[/tex]
Now; the heat required to convert solid to liquid at [tex]1860^0C[/tex] is;
[tex]Q_2 = n* \delta H_f[/tex]
= 3.069 × 20500
= 62914.5 J
Also ; given that :
[tex]c__l}} = 0.94 \ J/g \ ^0C \\ \\[/tex]
Then the heat needed to convert liquid from [tex]1860^0C[/tex]to [tex]2060^0C[/tex] is;
[tex]Q_3 = m*c__l} (T_f-T_l)[/tex]
[tex]Q_3 = 159.6*0.94*(2060-1760)[/tex]
[tex]Q_3 = 15002.4 \ J[/tex]
∴ The total heat required = [tex]Q_1 + Q_2 + Q_3[/tex]
= (715008 + 62914.5 + 15002.4) J
= 792924.9 J
= 793 kJ
Teking into accoun the definition of calorimetry, sensible heat and latent heat, the amount of heat required is 808 kJ.
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
Latent heat is defined as the energy required by a quantity of substance to change state.
When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.
1760 °C to 1860 °CIn firts place, you know that the melting point is 1860°C. So, first of all you must increase the temperature from 1760 ° C (in solid state) to 1860 ° C, in order to supply heat without changing state (sensible heat).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case, you know:
c(solid)= 44.8 [tex]\frac{J}{gC}[/tex]m= 159.4 gΔT= Tfinal - Tinitial= 1860 °C - 1760 °C= 100 °CReplacing:
Q1= 44.8 [tex]\frac{J}{gC}[/tex]× 159.6 g× 100 °C
Solving:
Q1=715,008 J= 715.008 kJ
Change of stateThe heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to
Q = m×L
where L is called the latent heat of the substance and depends on the type of phase change.
In this case, you know:
n= 159.6 grams×[tex]\frac{1 mole}{52 grams}[/tex]= 3.069 moles, where 52[tex]\frac{gr}{mole}[/tex] is the molar mass of Cr, that is, the amount of mass that a substance contains in one mole.ΔHfus= 20.5 [tex]\frac{kJ}{mol}[/tex]Replacing:
Q2= 3.069 moles×20.5 [tex]\frac{kJ}{mol}[/tex]
Solving:
Q2=62.9145 J
1860 °C to 2060 °CSimilar to sensible heat previously calculated, you know:
c(liquid)= 0.94 [tex]\frac{J}{gC}[/tex]m= 159.4 gΔT= Tfinal - Tinitial= 2060 °C - 1860 °C= 200 °CReplacing:
Q3= 0.94 [tex]\frac{J}{gC}[/tex]× 159.6 g× 200 °C
Solving:
Q3=30,004.8 J= 30.0048 kJ
Total heat requiredThe total heat required is calculated as:
Total heat required= 715.008 kJ + 62.9145 kJ + 30.0048 kJ
Total heat required= 807.9273 kJ ≅ 808 kJ
In summary, the amount of heat required is 808 kJ.
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A patient excretes a large volume of very dilute urine on a continuing basis. This is may be due to
Answer:
arterial hypertension
Explanation:
When increasing the arterial pressure, in the renal glomerulus the filtration of liquids increases since the liquids diffuse from zones of greater pressure to less pressure.
In this way, the liquid content of the urine increases and it is more diuluid because this does not apply to proteins or solutes, since these are affected by discrepancies in concentrations and not in pressures.
Excessive excretion of dilute urine, or polyuria, can be caused by conditions such as diabetes insipidus or diabetes mellitus, as well as the excessive use of diuretics, kidney disease, and excessive water intake. Diabetes insipidus reduces the number of water channels leading to the loss of water, while diabetes mellitus results in glucose in the urine which also causes the loss of water.
Explanation:If a patient is excreting a large volume of very dilute urine on a continuing basis, this can be due to a condition known as polyuria. Polyuria is characterized by urine production in excess of 2.5 L per day, and it can be caused by a number of potential factors.
One such factor could be diabetes insipidus, a condition caused by an insufficient release of the pituitary hormone known as antidiuretic hormone (ADH), or insufficient numbers of ADH receptors in the kidneys. This results in an insufficient number of water channels, known as aquaporins, which reduces water absorption and leads to high volumes of very dilute urine.
Another potential cause is diabetes mellitus, a condition where blood glucose levels exceed the number of available sodium-glucose transporters in the kidneys. This causes glucose to appear in the urine, and its osmotic properties attract water, leading to its loss in urine. Other potential causes of polyuria can also include the excessive use of diuretics, kidney disease, and excessive water intake.
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Question about thermodynamics
Answer:
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy.
Creatine phosphate
a. is produced by the process of anaerobic respiration.
b. can replace ATP in binding to myosin molecules during contraction.
c. acts as an energy reserve in muscle tissue.
d. is only formed during strenuous exercise.
e. cannot transfer its phosphate group to ADP.
Answer: C. Acts as energy reserve in muscle tissue.
Explanation:
Creatine Phosphate is a high energy compound that can be found in muscle tissue.
It serves as an extra energy storage, since the normal metabolism cannot supply the high energy requirement of a muscle at work.
Creatine Phosphate is quickly transfered to ADP, for the production of ATP needed for muscle contraction.
If a plastic container of food at 1.0°C and 750. mm Hg is heated in a microwave to 80. °C, what is the new pressure inside the container? mmHg are the units of the answer and you can just enter the number value for the pressure.
Answer:
966.12 mmHg
Explanation:
-We apply Gay-Lussac's Law which holds that the pressure of a given gas is directly proportional to it's temperature(in Kelvins) for a constant volume:
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
Given that:
[tex]0\textdegree C=273.15K\\\\T_1=1.0\textdegree C=274.15K\\P_1=750.0\ mmHg\\\\T_2=80\textdegree C=353.15K\\\\P_2=?[/tex]
#We therefore substitute in the formula above to solve for the final pressure, P2:
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}\\\\P_2=T_2\times\frac{P_1}{T_1}\\\\=353.15K\times\frac{750\ mmHg}{274.15K}\\\\=966.12\ mmHg[/tex]
Hence, is the new pressure inside the containe is 966.12 mmHg
Applying the concept of Gay-Lussac's law from physics, the pressure inside the plastic container of food, when heated from 1.0°C to 80°C, would increase to 966.67 mmHg.
Explanation:To answer this question, we need to use the concept of Gay-Lussac's Law from physics, which states that the pressure of a gas is directly proportional to its temperature, keeping volume constant. This means when you heat a gas, its pressure will increase.
However, it's important to note that the temperatures must be in Kelvin, not degrees Celsius. So, firstly we convert our temperatures from Celsius to Kelvin. 1°C = 274.15K and 80°C = 353.15K.
Using the formula P1/T1 = P2/T2 (P stands for pressure and T for temperature, the 1's indicating initial conditions and the 2's final), we plug in the values:
750mmHg/274.15K = P2/353.15K. Solving the equation we find P2 = 966.67 mmHg.
So, by heating the plastic container of food from 1.0°C to 80.0°C, the pressure inside the container would increase to 966.67 mmHg.
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how many oranges are in 1 mole of oranges?
Answer: 2.07 x 1020 tons
Explanation:
Answer:
6.022X10^23
Explanation:
ehh i had this and this is what i answered your welcome?
How does the volume of the balloon change after moving it to the hot room?How does the volume of the balloon change after moving it to the hot room?
Answer: The balloons volume would increase.
Explanation: This is because when the balloon enters a warmer climate it expands due to more freedom within the molecules movement.
Answer:
✔ increasesExplanation:
the next one would be 2.1 L
A chemical reaction has an energy of activation Ea = 1∙104 J mol-1 at T = 300 K. The first-order rate constant for this reaction was found to be 15.0 s-1. In the presence of a catalyst, the activation energy is reduced to 1∙103 J mol-1. Calculate the pre-exponential factor in the Arrhenius equation
Answer : The pre-exponential factor in the Arrhenius equation is, 14.99 s⁻¹
Explanation :
Using Arrhenius equation,
[tex]K=A\times e^{\frac{-Ea}{RT}}[/tex]
Taking ln on both the sides, we get:
[tex]\ln K=\frac{-Ea}{RT}+\ln A[/tex]
where,
K = rate constant = [tex]15.0s^{-1}[/tex]
Ea = activation energy = 1.104 J/mol
T = temperature = 300 K
R = gas constant = 8.314 J/mole.K
A = Arrhenius constant
Now put all the given values in the above formula, we get the value of \ln a.
[tex]\ln (15.0s^{-1})=\frac{1.104J/mol}{(8.314J/mole.K)\times (300K)}+\ln A[/tex]
[tex]\ln A=2.708s^{-1}[/tex]
[tex]A=14.99s^{-1}[/tex]
Therefore, the pre-exponential factor in the Arrhenius equation is, 14.99 s⁻¹
A small amount wet of hydrogen gas can be prepared by the reaction of zinc with excess hydrochloric acid and trapping the gas produced in an inverted tube initially filled with water. If the total pressure of the gas in the collection tube is 729.7 mmHg at 25 C, what is the partial pressure of the hydrogen
Answer : The partial pressure of the hydrogen is, 705.9 mmHg
Explanation :
According to the Dalton's law of partial pressure,
[tex]P_T=P_{H_2}+P_{H_2O}[/tex]
where,
[tex]P_T[/tex] = total pressure of the gas = 729.7 mmHg
[tex]P_{H_2}[/tex] = partial pressure of the hydrogen gas = ?
[tex]P_{H_2O}[/tex] = partial pressure of the water = 23.8 mmHg (standard value)
Now put all the given values in the above expression, we get:
[tex]729.7mmHg=P_{H_2}+23.8mmHg[/tex]
[tex]P_{H_2}=705.9mmHg[/tex]
Therefore, the partial pressure of the hydrogen is, 705.9 mmHg
Reactions leading to nucleic acid and protein synthesis are inherently different from those of intermediary metabolism. Such reactions must be essentially ________. The synthesis of polynucleotides is thus coupled to ________ _________ hydrolysis.
Answer:
irreversible, exergonic, pyrophosphate
Explanation:
Reactions leading to nucleic acid and protein synthesis are inherently different from those of intermediary metabolism. Such reactions must be essentially irreversible. The synthesis of polynucleotides is thus coupled to exergonic pyrophosphate hydrolysis.
A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distilled water, the student adds excess Na2SO4(s), which causes a precipitate of BaSO4(s) to form, as represented by the equation above. The student filters the BaSO4(s), rinses it, and dries it until its mass is constant. Which of the following scientific questions could best be answered based on the results of the experiment? Is the Na2SO4(s) used in the experiment pure? A Is the BaCl2(s) used in the experiment pure? B What is the molar solubility of BaCl2 in water? C What is the molar solubility of BaSO4 in water?
Answer:
(B.) What is the molar solubility of barium chloride, BaCl2 in water?
Explanation:
Molar solubility is the number of moles of a substance that can dissolve in a liter of solution to the point of the solution's saturation. It can be calculated stoichiometrically from a substance's solubility product constant in mol/L.
Since all the [tex]BaCl_{2}[/tex] reacted all the [tex]Na_{2} SO_{4}[/tex] from the information, we can easily assume all the substances were consumed in the reaction, and hence account for their purity. Furthermore, [tex]BaSO_{4}[/tex] is insoluble in water, the most probable scientific query would be the molar solubility of the [tex]BaCl_{2}[/tex] used in the experiment.
Answer:
The best question is A Is the BaCl2(s) used in the experiment pure?Explanation:
Step 1: Data given
Mass of the BaCl2 sample = 10.0 grams
Volume of water = 50.0 mL
We add excess Na2SO4
A precipitate BaSO4 will be formed
Step 2: The balanced equation
BaCl2(aq) → Ba^2+(aq) + 2Cl-(aq)
Ba^2+(aq) + SO4^2-(aq) →BaSO4(s)
Step 3: Calculate moles BaCl2
Moles BaCl2 = 10.0 grams / 208.23 g/mol
Moles BaCl2 = 0.048 moles
Step 4: Calculate moles Ba^2+
For 1 mol BaCl2 we have 1 mol Ba^2+
For 0.048 moles BaCl2 we have 0.048 moles Ba^2+
Step 5: Calculate mass Ba^2+
Mass Ba^2+ = moles Ba^2+ * molar mass Ba^2+
Mass Ba^2+ = 0.048 moles * 137.33 g/mol
Mass Ba^2+ = 6.59 grams
After measuring the mass of barium in BaSO4 we can determine if the BaCl2 was pure or not.
If the mass = 6.59 grams the BaCl2 was pure
If the mass <6.59 grams the BaCl2 wasn't pure
The best question is A Is the BaCl2(s) used in the experiment pure?
A chemist makes 360mL of calcium sulfate working solution by adding distilled water to 90.0mL of a 10.7mmol/L stock solution of calcium sulfate in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.
Answer: The concentration of the chemist's working solution is 0.00268 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock solution = 10.7 mmol/L = 0.0107 mol/L [tex]1mmol=10^{-3}mol[/tex]
[tex]V_1[/tex] = volume of stock solution = 90.0 ml
[tex]M_2[/tex] = molarity of working solution = ?
[tex]V_2[/tex] = volume of working solution = 360 ml
[tex]0.0107\times 90.0=M_2\times 360[/tex]
[tex]M_2=0.00268M[/tex]
Thus the concentration of the chemist's working solution is 0.00268 M
If velocity is positive, which would most likely yield a negative acceleration?
Afinal velocity that is faster than an initial velocity.
A time that is less than a half hour.
An initial velocity that is faster than a final velocity.
A time that is greater than a half hour.
Answer:
an initial velocity that is faster than the final velocity
Explanation:
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Answer:
C
Explanation:
what causes the hydro carbons to condense in the fractional distillation process?
Answer:
Substances with high boiling points condense at the bottom and substances with lower boiling points condense on the way to the top. The crude oil is evaporated and its vapours condense at different temperatures in the fractionating column.
Explanation:
answer above
What is a base used in toothpaste?
sorbitol
O carrageenan
O magnesium hydroxide
sodium lauryl sulfate
Answer: Option:C
Explanation:
When pollution or harmful substances get into an environment what is it called
Answer:
it is called pollutant
Explanation:
this means a subtance that pollutes something especially the environment.
Deoxyribonucleotides are so named because they lack a hydroxyl at which position?
Answer:
deoxyribonucleotides are so named because the lack a hydroxyl at the carbon position 2
How many grams are there in 5.00 moles of lead Pb?
What happens when a glass of water is set in the sun until the water
evaporates?
Answer:
entropy increases when a glass of water is set in the sun until the water evaporates.
Hope it will help you :)
Explanation:
In the water cycle, evaporation occurs when sunlight warms the surface of the water. The heat from the sun makes the water molecules move faster and faster, until they move so fast they escape as a gas. ... When it is cool enough, the water vapor condenses and returns to liquid water.
A student determines that according to the reaction N2(g) + 3H2(g) --> 2NH3(g), if 34g of nitrogen gas is reacted with excess hydrogen, 41g of ammonia can be produced. When the actual reaction was complete, only 38g of ammonia formed. Determine the percent yield for the reaction.
Answer:
The percent yield of this reaction is 92.7 %
Explanation:
Step 1: Data given
Mass of nitrogen gas (N2) = 34.0 grams
Mass of ammonia (NH3 produced = 41.0 grams
Molar mass of N2 = 28.0 g/mol
Molar mass of NH3 = 17.02 g/mol
Actual yield of ammonia = 38 grams
Step 2: The balanced equation
N2(g) + 3H2(g) → 2NH3(g)
Step 3: Calculate moles
Moles = mass / molar mass
Moles N2 = 34.0 grams / 28.0 g/mol
Moles N2 = 1.214 moles
Step 4: Calculate moles NH3
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
For 1.214 moles N2 we'll have 2* 1.214 = 2.428 moles NH3
Step 5: Calculate mass NH3
Mass NH3 = moles * molar mass
Mass NH3 = 2.428 moles * 17.02 g/mol
Mass NH3 = 41 grams
Step 6: Calculate percent yield for the reaction
Percent yield = (actuald yield / theoretical yield) * 100 %
Percent yield = (38 grams / 41 grams ) * 100 %
Percent yield = 92.7 %
The percent yield of this reaction is 92.7 %
Answer:
[tex]Y=92\%[/tex]
Explanation:
Hello,
In this case, by considering the given chemical reaction, with given mass of nitrogen, one could compute the theoretical yield of ammonia as shown below and considering their 1 to 2 molar relationship in the chemical reaction:
[tex]m_{NH_3}^{theoretical}=34gN_2*\frac{1molN_2}{28gN_2}*\frac{2molNH_3}{1molN_2}*\frac{17gNH_3}{1molNH_3} \\m_{NH_3}^{theoretical}=41.3gNH_3[/tex]
In such a way, the percent yield is obtained as shown below:
[tex]Y=\frac{m_{NH_3}^{actual}}{m_{NH_3}^{theoretical}} *100\%=\frac{38g}{41.3g} *100\%\\\\Y=92.0\%[/tex]
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Electrical energy is used to spin the blades of a ceiling fan. If the electricity is cut off, the fan blades will slow down and eventually stop spinning. Why?
A.
All the kinetic energy of the fan blades has been transformed into potential energy.
B.
All the potential energy of the fan blades has been transformed into kinetic energy.
C.
All the kinetic energy of the fan blades has been transformed into heat energy.
D.
All the potential energy of the fan blades has been transformed into heat energy.
Answer:
c
Explanation:
all of the friction from the fan blades and the fan inside has stopped the fan from spinning and friction is heat.
If the electricity is cut off, the fan blades will slow down and further eventually stop spinning in case of all the kinetic energy of the fan blades has been turned into heat energy. The correct option is C.
What is kinetic energy?In physics, an object's kinetic energy is the energy it has basically as a consequence of its motion.
It is described to as the amount of work required to accelerate a body of a given mass from initial state to a given velocity.
The body usually regains its kinetic energy after gaining it during acceleration unless its speed changes.
Kinetic energy is the energy that an object has as a consequence of its movement. The ability of kinetic energy to do work is perhaps its most crucial mandatory property.
Work is renowned as force acting in the direction of motion on an object. Work as well as energy are so inextricably interlinked that they can be utilized even interchangeably.
Thus, the correct option is A.
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Which of the following groups contain elements that are gaseous at room temperature?
a) alkali metals and alkaline earth metals
b) alkali metals and transition metals
c) noble gases and transition metals
d) noble gases and halogens
Final answer:
The group that contains elements that are gaseous at room temperature are noble gases and halogens. Noble gases include helium, neon, argon, krypton, xenon, and radon, and halogens like fluorine and chlorine are gases under standard conditions. So the correct option is D.
Explanation:
The question at hand involves identifying which groups of elements are gaseous at room temperature. Of the options provided, d) noble gases and halogens contain elements that are gaseous at room temperature. Noble gases, which include elements like helium, neon, argon, krypton, xenon, and radon, are all gases under standard conditions. Halogens such as fluorine and chlorine are also gaseous at room temperature. Alkali metals and alkaline earth metals are solid at room temperature. Furthermore, most transition metals are also solid at room temperature, with mercury being an exception as it is liquid.
To define the subject for the questions based on the examples given, we can use the keywords: alkali metal, halogen, noble gas, and alkaline earth metal as they relate to the classifications on the periodic table. The given examples classify elements like lithium as an alkali metal (Group 1), argon as a noble gas (Group 18), and chlorine as a halogen (Group 17), which are key aspects of elementary Chemistry covered in high school.
A sample of neon gas occupies a volume of 2.8L at 1.8 atm. What would its volume be at 1.2 atm?
Answer:
4.2 L
Explanation:
Use Boyle's Law and rearrange formula.
- Hope this helps! Please let me know if you need further explanation.
To find the volume of the neon gas at 1.2 atm, we can use the combined gas law equation.
Explanation:To solve this problem, we can use the combined gas law equation:
P1V1 / T1 = P2V2 / T2
First, we need to convert the given volume in liters to moles using the ideal gas law equation:
V1 = nRT1 / P1
Then, we can rearrange the combined gas law equation to solve for V2:
V2 = (P2 * V1 * T2) / (P1 * T1)
Substituting the given values, we get:
V2 = (1.2 atm * 2.8 L * 273 K) / (1.8 atm * 273 K) = 1.233 L
Therefore, the volume of the neon gas at 1.2 atm would be 1.233 liters.
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