The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver breathes when he is 132 ft below the surface of the water where the pressure is 5.00 atm?

Answer:

hola como estas

Explanation:

Answer:

1. F

2. F

3. F

Explanation:

Determine if the following statements are true or false.

Final answer:

The statements regarding the rate law being written using coefficients from the overall equation and the rate-determining step always being the first step of the reaction are both false. A catalyst does lower activation energy but is not included in the rate law nor in the overall balanced equation.

Explanation:

Determining the rate law of a chemical reaction and the rate-determining step is a critical part of understanding reaction kinetics in chemistry. The first statement, 'The rate law for an overall reaction can be written using the coefficients from the overall reaction,' is false. The rate law cannot be directly inferred from the stoichiometric coefficients in the balanced chemical equation; it is determined empirically and often depends on the mechanism and the slowest, rate-determining step of the reaction.

The second statement, 'The rate-determining step of the reaction is always the first step of the reaction,' is also false. While the rate-determining step can be the first step, this is not always the case. It is the slowest step with the highest activation energy, and not necessarily the first step in the reaction mechanism.

The third statement about a catalyst being a species that lowers the activation energy and shows up in the rate law (most of the time) is partly correct. A catalyst does lower the activation energy and speeds up the reaction but does not appear in the rate law and is not present in the overall balanced equation because it is not consumed in the reaction; thus, this statement is false in the context given.

In the tripeptide Gly-Ala-Ser, the amino acid at the N-terminal end is Ser. More than one polypeptide chain may be present in a conjugated protein but not in a simple protein. In solution at physiological pH, the side chain of a polar basic amino acid does not bear a negative charge.

A tripeptide is a chain consisting of three amino acid units. In the tripeptide Gly-Ala-Ser, the amino acid at the N-terminal end is Ser. This is because the N-terminal end is the end of a peptide or protein whose amino group is free, while the C-terminal end has a free carboxyl group. Therefore, statement (1) is true.

Conjugated proteins can consist of more than one polypeptide chain, while simple proteins consist of only one polypeptide chain. Therefore, statement (2) is true.

In solution at physiological pH, the side chain of a polar basic amino acid does not bear a negative charge. Instead, it is positively charged. Therefore, statement (3) is false.

Answer:

c. 9.94 g

Explanation:

From the question,

Using

mt = m₀e⁻kt.................... Equation 1

Where mt = mass of the leaf remaining in the bag, m₀ = original mass of leave that was placed in the bag, k = decay constant, t = time.

Given: m₀ = 33 g, k = 0.04, t = 30 days.

Substitute into equation 1

mt = 33(e⁻(0.04ˣ30))

mt = 33e⁻¹²/¹⁰

mt = 33/e¹²/¹⁰

mt = 33/3.320

mt = 9.94 g.

Hence the right answer is c. 9.94 g

To find the value of ΔG for the reaction MSO4⋅3H2O(s)↽−−⇀MSO4(s)+3H2O(g) at the given vapor pressure of water, use the equation ΔG = -RTln(K), where ΔG is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

The reaction can be represented as: MSO4·3H2O(s) <--> MSO4(s) + 3H2O(g)

The equilibrium vapor pressure of water above the solid is 14.7 Torr.

Since we are given the equilibrium condition, we can use the equation ΔG = -RTln(K), where ΔG is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

By plugging in the given values, we can calculate the value of ΔG at the equilibrium condition.

The value of [tex]\Delta G[/tex] for the reaction when the vapor pressure of water is 14.7 Torr is approximately 2.005 kJ/mol.

The value of [tex]\Delta G[/tex] for the reaction at 298 K when the vapor pressure of water is 14.7 Torr is given by the equation:

[tex]\[ \Delta G = -RT \ln \left( \frac{P_{H_2O}^3}{P_{H_2O}^{eq}} \right) \][/tex]

where:

- [tex]\( \Delta G \)[/tex] is the change in Gibbs free energy,

- [tex]R[/tex] is the universal gas constant (8.314 J/(mol·K)),

- [tex]T[/tex] is the temperature in Kelvin (298 K in this case),

- \[tex]\( P_{H_2O}^3 \)[/tex] is the partial pressure of water raised to the power of the moles of water in the reaction (which is 3),

- [tex]\( P_{H_2O}^{eq} \)[/tex] is the equilibrium vapor pressure of water (14.7 Torr).

First, we need to convert the equilibrium vapor pressure of water from Torr to atmospheres to match the units of the gas constant [tex]R[/tex]. The conversion factor is 1 atm = 760 Torr.

[tex]\[ P_{H_2O}^{eq} = \frac{14.7 \text{ Torr}}{760 \text{ Torr/atm}} = 0.01934 \text{ atm} \][/tex]

Now we can plug in the values into the equation:

[tex]\[ \Delta G = -(8.314 \text{ J/(mol·K)}) \times (298 \text{ K}) \times \ln \left( \frac{(0.01934 \text{ atm})^3}{(0.01934 \text{ atm})} \right) \][/tex]

[tex]\[ \Delta G = -8.314 \times 298 \times \ln \left( (0.01934)^2 \right) \][/tex]

[tex]\[ \Delta G = -8.314 \times 298 \times \ln \left( 0.000373 \right) \][/tex]

[tex]\[ \Delta G = -8.314 \times 298 \times (-7.936) \][/tex]

[tex]\[ \Delta G = 8.314 \times 298 \times 7.936 \][/tex]

[tex]\[ \Delta G = 2004.8 \text{ J/mol} \][/tex]

[tex]\Delta G = 2.005 kJ/mol[/tex]

Answer:

pC6H5CHO = 0.180 atm

Fraction dissociated = 0.756

Explanation:

Step 1: Data given

Temperature = 523 K

the value of its equilibrium constant is K = 0.558

Mass of benzyl alcohol = 1.20 grams

Molar mass of benzyl alcohol = 108.14 g/mol

Volume = 2.00 L

heated to 523 K

Step 2: The balanced equation

C6H5CH2OH(g) ⇆ C6H5CHO(g) + H2(g)

Step 3: Calculate moles benzyl alcohol

Moles benzyl alcohol = Mass / molar mass

Moles benzyl alcohol = 1.20 grams / 108.14 g/mol

Moles benzyl alcC6H5CH2OHohol = 0.0111 moles

Step 4: Initial moles

Moles C6H5CH2OH = 0.0111 moles

Moles C6H5CHO = 0 moles

Moles H2O = 0 moles

Step 5:  moles at the equilibrium

Moles C6H5CH2OH = 0.0111 - X moles

Moles C6H5CHO = X moles

Moles H2O = X moles

Step 6: Calculate the total number of moles at equilibrium

Total number of moles = (0.0111 - X moles) + X moles + X moles

Total number of moles = 0.0111 + X moles

Step 7: Calculate the total pressure at the equilibrium

p*V = n*R*T

p = (n*R*T) / V

⇒with p = the total pressure at the equilibrium = TO BE DETERMINED

⇒with n = the total number of moles = 0.0111 + X moles

⇒with R = the gas constant = 0.08206 L*atm / mol * K

⇒with T = the temperature = 523 K

⇒with V = the volume of the vessel = 2.00 L

p = (0.0111 - X moles ) * 0.08206*523 / 2.00

p = 21.46(0.0111 - X moles)

Step 8: Define the equilibrium constant K

K = 0.558 =  (pC6H5CHO)*(pH2) / (pC6H5CH2OH)

0.558 = (X / (0.0111 + X)*P)²  /  ((0.0111-X)/(0.0111+X)*P)

0.558 = (X²(21.46 * (0.0111+X))) / ((0.0111 + X) (0.0111-X))

X = 0.00839

Step 9: Calculate the equilibrium partial pressure

pC6H5CHO = X / (0.0111 + X)  * (21.46 * (0.0111 +X))

pC6H5CHO = 0.180 atm

Step 10: What fraction of benzyl alcohol is dissociated into products at equilibrium?

Fraction dissociated = Δn / n°

Fraction dissociated = X / 0.0111

Fraction dissociated = 0.00839 / 0.0111

Fraction dissociated = 0.756

Answer:

b

Explanation:

Answer:

The molarity of the Br anion is 0.00136 M = 0.0014 M to 2 s.f

Explanation:

Complete full question

A chemist prepares a solution of sodium bromide (NaBr) by measuring out 14. mg of NaBr into a 100 mL volumetric flask and filling to the mark with distilled water. Calculate the molarity of Br anions in the chemist's solution. Be sure your answer is rounded to 2 significant digits.

To do this, we first calculate the molarity of the aqueous solution of NaBr.

Molarity = (Concentration in g/L) ÷ (Molar Mass)

(Concentration in g/L)

= (Mass of solute in g) ÷ (Volume of solution in L)

Mass of solute = 14 mg = 0.014 g

Volume = 100 mL = 0.10 L

(Concentration in g/L)

= (Mass of solute in g) ÷ (Volume of solution in L)

(Concentration in g/L) = (0.014/0.1) = 0.14 g/L

Molarity = (Concentration in g/L) ÷ (Molar Mass)

Molar Mass = 102.894 g/mol

Molarity = (0.14/102.894) = 0.0013606236 M = 0.00136 M

Assuming complete dissociation, NaBr dissociates into

NaBr → Na⁺ + Br⁻

1 mole of NaBr gives 1 mole of Br⁻

0.00136 M of NaBr will give 0.00136 M of Br⁻

So, the molarity of the Br anion is 0.00136 M = 0.0014 M to 2 s.f

Hope this Helps!!!

The question given is incomplete because the Ka of the acids were not provided. I got the complete question from google as below:

Three buffers are prepared using equal concentrations offormic acid (HCOOH) and sodium formate, hydrofluoric acid (HF) andsodium fluoride, and acetic acid (CH3COOH)and sodium acetate. Rank the three buffers from highest to lowest pH.

According to the text, the Ka of the acids are as follows:

HCOOH: 1.77 × 10–4

HF: 6.8 × 10–4

CH3COOH: 1.76 × 10–5

Answer:

Based on the Ka values of the acids given, the arrangement of the acids given from the highest to lowest pH is as below:

HF > HCOOH > CH3COOH

Explanation:

For acids, the higher the pH, the higher the pK , also, the lower the pH, the lower the pK.

then

pKa = -log(Ka)

So,

The acid with the highest pH will have the highest Ka value , while the acid with the lowest pH will have the lowest Ka value.

Thus, based on the Ka values of the acids given, the arrangement of the acids given from the highest to lowest pH is as below:

HF > HCOOH > CH3COOH

The buffers are ranked from highest to lowest pH based on the pKa values of the weak acids: acetic acid (highest pH), formic acid, and hydrofluoric acid (lowest pH).

To rank the buffers from highest to lowest pH, we can refer to the pKa values of the corresponding weak acids, since the buffers are prepared using equal concentrations of the weak acids and their conjugate bases. The higher the pKa, the weaker the acid, and therefore the higher the pH of its buffer when the concentrations of the acid and its conjugate base are equal.

The pKa of acetic acid (CH₃COOH) is approximately 4.76.

The pKa of formic acid (HCOOH) is approximately 3.75.

The pKa of hydrofluoric acid (HF) is approximately 3.17.

Therefore, the acetic acid and sodium acetate buffer will have the highest pH, followed by the formic acid and sodium formate buffer, with the hydrofluoric acid and sodium fluoride buffer having the lowest pH.

When an area has a net flow of electric charge, an electric current is considered to be present. Electrons traveling via a wire in electric circuits frequently carry this charge.

One or more of the electrons from each atom are only weakly connected to the atom in metals, allowing them to move around freely inside the metal. Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). The more electricity flowing across the circuit, the higher the ampere value.

If you imagine electricity as the flow of water in a river, it will be simple to understand. When the electrons collide, the current is the number of electrons flowing per second.

Like current, voltage is a word that is frequently used in relation to electrical circuits. Volts are used to measure voltage (V). Voltage and the movement of electrons in a circuit are connected, just like current and current are. Voltage is the amount of force driving the flowing electrons, whereas the current is the flow of electrons.

Therefore, when there is a net flow of electric charge through an area, an electric current is said to exist. In electrical circuits, electrons traveling over a wire frequently carry this charge.

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This is an incomplete question, here is a complete question.

Consider the reaction: [tex]NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)[/tex]

Kc = 0.30 at some temperature.

If the initial mixture has the concentrations below, the system is_______.

Chemicals   Concentration (mol/L)

- NO₂            0.024

- CO               0.360

- NO               0.180

- CO₂             0.120

Possible answers:

1) not at equilibrium and will remain in an unequilibrated state.

2) not at equilibrium and will shift to the left to achieve an equilibrium state.

3) not at equilibrium and will shift to the right to achieve an equilibrium state.

4) at equilibrium

Answer : The correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

Explanation:

Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

First we have to determine the value of reaction quotient (Qc).

The given balanced chemical reaction is,

[tex]NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)[/tex]

The expression for reaction quotient will be :

[tex]Q_c=\frac{[NO][CO_2]}{[NO_2][CO]}[/tex]

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

[tex]Q_c=\frac{(0.180)\times (0.120)}{(0.024)\times (0.360)}=2.5[/tex]

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When [tex]Q>K[/tex] that means product > reactant. So, the reaction is reactant favored.

When [tex]Q<K[/tex] that means reactant > product. So, the reaction is product favored.

When [tex]Q=K[/tex] that means product = reactant. So, the reaction is in equilibrium.

The given equilibrium constant value is, [tex]K_c=0.30[/tex]

From the above we conclude that, the [tex]Q>K[/tex] that means reactant < product. So, the reaction is reactant favored that means reaction must shift to the reactant or left to be in equilibrium.

Hence, the correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

Answer: Concentration or pressure of a reactant and temperature

Explanation: The two major factors that can affect the rate of a chemical change are concentration or pressure of a reactant  and temperature.

Answer:

Amino acids join by linking the acid group of one amino acid to the amino group of another.

Explanation:

Amino acids are organic molecules that form the basic molecules for making proteins and there are. An amino acid comprises of an acidic carboxyl (-COOH) functional group and an amino group (-NH2)  as well as a side an organic side chain (R group).

In the formation of proteins, several amino acids join together by the formation of peptide bonds between each amino acids to form a long polypeptide. These peptide bods are formed by the linking of the acidic carboxyl group of one amino acid to the amino group of another amino acid, during this process water is removed.

Answer:

The element is magnesium

[Ne]3s2

Explanation:

When an atom is excited, electrons move from a lower to a higher energy level. These higher energy levels are called excited states. The ground state is the lowest energy arrangement of electrons.

Excited states are important in spectroscopy. It gives scientists an idea of the unoccupied orbitals in the ground state. This is easily deduced from the fact that the specie has twelve electrons in all.

Magnesium has ground state configuration as shown in the answer but has an excited state as shown in the question.

Answer:

0.55mL of carbon tetrachloride

Explanation:

CH4(g) + 2Cl2(g) -------> CCl4(g) + 2H2(g)

From the balanced reaction equation

44800mL of chlorine produces 22400 ml of carbon tetrachloride

If 1.1mL of chlorine were consumed, volume of carbon tetrachloride= 1.1×22400/44800

=0.55mL of carbon tetrachloride

Note: 1 mole of a gas occupies 22.4L volume or 22400mL

Answer:

B) The molecules gain energy, and their relative motion decreases

The change in the molecular motion should be option B.

The molecular motion refers to the movement of constituent particles or molecules in a specific direction. It should be impacted by heat and temperature. When there is the transformation from liquid to solid so the change in the molecular motion of the substance should be that the molecular gained the energy and there should be a decrease in the relative motion.

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Answer:

Aldol

Explanation:

The reaction will be an aldol.

Answer:

Explanation:

find the solution below

Answer:

Step 1 H2 + 2 NO → N2O + H2O (slow)

step 2 N2O + H2 → N2 + H2O (fast)

Explanation:

It is known that the slowest step in a reaction is the rate determining step in a sequence of reactions (reaction mechanism).

We have two important pieces of information in the question to guide our decision making process.

The overall reaction equation, and the rate expression. The two;

2 H2 + 2 NO → N2 + 2 H2O and rate = k[H2][NO]2 all support the answer given above.

The best matching mechanism to the given rate law is 'H2 + 2 NO → N2O + H2O (slow)' followed by 'N2O + H2 → N2 + H2O (fast)'. This mechanism results in first-order dependence on H2 and second-order dependence on NO, matching the observed rate law.

To find a mechanism that matches the given rate law (rate = k[H2][NO]²), we need to find one where NO is involved in the slow (rate-determining) step twice (which will make the overall reaction second-order with respect to NO), and H2 is involved once (making it first-order with respect to H2). From the proposed mechanisms, we can agree that the first one:

is most likely because the slow step involves one H2 and two NO molecules.

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Answer:

We need 420 cal of heat

Explanation:

Step 1: Data given

Mass of the aluminium = 200.0 grams

Temperature rises with 10.0 °C

Specific heat of aluminium = 0.21 cal/g°C

Step 2: Calculate the amount of heat required

Q =m * c* ΔT

⇒with Q =  the amount of heat required= TO BE DETERMINED

⇒with m = the mass of aluminium = 200.0 grams

⇒with c = the specific heat of aluminium = 0.21 cal/g°C

⇒with ΔT = the change of temperature = 10.0°C

Q = 200.0 grams * 0.21 cal/g°C * 10.0 °C

Q = 420 cal

We need 420 cal of heat (option 2 is correct)

Answer:

420 cal of heat

Explanation:

Answer:

The decrease in free energy is 113.299kJ

Explanation:

K for enzyme catalyzed reaction = 500s^-1

Temperature (T) =298k

ΔG =?

ΔG = - 2.303 RT log k

ΔG = (-2.303)(8.314)(298) log 500

ΔG = - 15399.9 J

ΔG catalyzed = - 15. 399kJ

The first order reaction is given as:

t1/2= 0.693/k

or k= 0.693/t1/2

0.693/10^17

Therefore,

K= 0.693 × 10^-17

Now,

K= 0.693 × 10^-17

T= 298k

ΔG uncatalyzed =?

ΔG uncatalyzed = - 2.303 RT log k

ΔG uncatalyzed = (-2.303)(8.314)(298) log0.693 × 10^-17

= 97908.1J

ΔG uncatalyzed = 97.9081kJ

Therefore,

The decrease in free energy is:

ΔG uncatalyzed - ΔG catalyzed

97.908 - (-15.399)

= 113.299KJ

The decrease in free energy is 113.299kJ

Final answer:

The free energy of activation for the CO2 loss step can be calculated using the Arrhenius equation. The enzyme lowers the free energy of activation by comparing the activation energies of the catalyzed and uncatalyzed reactions.

Explanation:

The free energy of activation for the CO2 loss step can be calculated using the Arrhenius equation:

k = Ae^(-Ea/RT)

Where k is the rate constant, A is the frequency factor, Ea is the activation energy, R is the gas constant (8.314 J/mol·K), and T is the temperature in Kelvin.

Since the rate-determining step is the loss of CO2, we can use the kcat value (500 s-1) as the rate constant for this step. To find the activation energy, we need to rearrange the Arrhenius equation:

Ea = -RT ln(k/A)

Now we can substitute the given values into the equation:

Ea = -(8.314 J/mol·K)(298 K) ln(500 s-1/A)

To calculate the value of A, we can use the half-life for the uncatalyzed reaction:

t1/2 = ln(2)/(kuncat)

Replacing kuncat with the appropriate value, we can solve for A:

A = e^(ln(2)/(kuncat) - ln(2)/(kcat))/t1/2 = e^(ln(kcat/kuncat))/t1/2

Finally, we can substitute the values of kcat, kuncat, and t1/2 into the equation to find A.

To calculate how much the enzyme lowers the free energy of activation, we can compare the activation energies of the uncatalyzed and catalyzed reactions:

∆∆G (ΔEa) = ∆Ga - ∆Ga,uncat

Where ∆Ga is the activation energy of the catalyzed reaction and ∆Ga,uncat is the activation energy of the uncatalyzed reaction.

Answer: seen below

Explanation:

HCH3CO2 + NaOH --------------> CH3CO2- + H2O

Acid specie- HCH3CO2

base- NaOH

Neutral- Na+

CH3COOH + KOH ----------> CH3COOK + H20

Acid- CH3COOH

Base- KOH

Neutral- K+

Answer:

Option A and D

Explanation:

The element with electronic configuration 1s^22s^22p^63s^23p^3 and the element with electronic configuration 1s^22s^22p^3 will show similar chemical properties as they both have the same valence electrons of 5 each. The valence electron of the two elements shows that they both belong to the same group. Elements in the same group naturally have the same chemical properties because they have the same combining power i.e valence electron.

The pair of elements that tend to show the same chemical properties are a and d.

The elements belonging to the same group tend to show the same chemical properties. Based on the electronic configuration, the element having the same number of valence electrons belongs to the same group.

The valence electrons in the given configurations are:

a. [tex]\rm 1s^2\;2s^2\;2p^6\;3s^2\;3p^3[/tex] = 5

b. [tex]\rm 1s^2\;2s^2\;2p^6\;3s^2\;3p^6\;3d^1^0\;4s^2\;4p^5[/tex] = 7

c. [tex]\rm 1s^2\;2s^2\;2p^6\;3s^2\;3p^6[/tex] = 8

d. [tex]\rm 1s^2\;2s^2\;2p^3[/tex] = 5

The element a and d tend to show the same number of valence electrons. Thus both the elements will show the same chemical properties.

The pair of elements that tend to show the same chemical properties are a and d.

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Answer:

Local fishermen will lose their jobs

Answer:

"Hawaii has better weather" is an opinion.

Therefore, you would need to support it with facts in order to deem it accurate or not.

If the text suggests that Hawaii has nice weather, then the statement would be accurate.

If the text hints that Hawaii does not have ideal weather, the statement would be inaccurate.

Final answer:

The statement that 'Hawaii has better weather' is subjective; Hawaii has a tropical type A climate with wet and dry areas due to the rain shadow effect. While it's warm, Kauai receives over 460 inches of rain annually, and snow can occur on mountain peaks in winter.

Explanation:

Whether or not Hawaii has 'better weather' is subjective and depends on personal preferences. However, based on the text provided, the statement that Hawaii has better weather because it has a tropical type A climate may not be entirely accurate for everyone. While Hawaii does have a warm and tropical climate, there are variations across the islands. For example, the island of Kauai is one of the wettest places on Earth, receiving over 460 inches of rain per year. Moreover, the rain shadow effect caused by Mount Wai'ale'ale leads to heavy rainfall on the windward side and dry conditions on the leeward side, creating a semi-desert environment. Additionally, it's noteworthy that snow can be found on the tops of Hawaii's highest mountains in the winter.

The diverse climate conditions in Hawaii mean that the weather can vary significantly from one part of the island to another, which might be pleasant for some but not for others. Therefore, whether Hawaii has 'better weather' is based on an individual's weather preferences and what they consider to be better.

Answer:

The question is incomplete. The structures were not added to the question. Find attached of the structure and the given answer.

Explanation:

See the attached file for explanation

Answer:

7. Phosphoric acid H₃PO₄ 7.5×10⁻³ 6.2×10⁻⁸ 4.8×10⁻¹³

3. Carbonic acid H₂CO₃ 4.2×10⁻⁷ 4.8×10⁻¹¹

Explanation:

Their blend will result to the closest pH of 8.00

Answer: The enthalpy of reaction is, -173.2 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

[tex]5C(s)+6H_2(g)\rightarrow C_5H_{12}(l)[/tex]    [tex]\Delta H=?[/tex]

The intermediate balanced chemical reaction will be,

(1) [tex]C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(g)[/tex]     [tex]\Delta H_1=-3244.8kJ[/tex]

(2) [tex]C(s)+O_2(g)\rightarrow CO_2(g)[/tex]    [tex]\Delta H_2=-393.5[/tex]

(3) [tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]    [tex]\Delta H_3=-483.5kJ[/tex]

Reversing (1) , Multiply (2) by 5 , (3) by 3 and add

[tex]\Delta H=\Delta H_1+5\times \Delta H_2+3\times \Delta H_3[/tex]

[tex]\Delta H=(+3244.8)+(5\times -393.5)+(3\times -483.5)[/tex]

[tex]\Delta H=-173.2kJ[/tex]

Therefore, the enthalpy of reaction is, -173.2 kJ

Answer:

[tex]p_2=347.9kPa[/tex]

Explanation:

Hello,

In this case, we use the Gay-Lussac's law which allows us to understand a gas' pressure-temperature behavior as a directly proportional relationship:

[tex]\frac{p_1}{T_1}= \frac{p_2}{T_2}[/tex]

Whereas it is convenient to use the pressure in kPa and the temperature in kelvins in order to compute the required resulting pressure, therefore:

[tex]p_1=55.0psi*\frac{6.89476kPa}{1psi} =379.2kPa\\T_1=30.0+273.15=303.15K\\T_2=5.0+273.15=278.15K[/tex]

Thus, we obtain:

[tex]p_2= \frac{p_1T_2}{T_1}=\frac{379.2kPa*278.15K}{303.15K}\\ \\p_2=347.9kPa[/tex]

Best regards.

Answer:

The pressure in the tire at 5.0 °C is 347.91 kPa

Explanation:

Step 1: Data given

The pressure in a bicycle tire is 55.0 psi

Temperature = 30.0 °C = 303 K

Temperature decreases to 5.0 °C = 278 K

Volume and Amount of moles are held constant

Step 2: Calculate the pressure at the new temperature

P1/T1 = P2 / T2

⇒with P1 = the initial pressure of the bicycle tire is 55.0 psi

⇒with T1 = the initial temeprature = 303 K

⇒with P2 = the pressure at the new temperature

⇒with T2 = the decreased temperature = 278 K

55.0 psi / 303 K = P2 / 278 K

P2 = (55.0 psi / 303 K) * 278 K

P2 = 50.46 psi

Step 3: Convert pressure from psi to kPa

50.46 psi = 50.46 * 6.895 = 347.91 kPa

The pressure in the tire at 5.0 °C is 347.91 kPa