The ph of a 0.175 m aqueous solution of a weak acid is 3.52. what is ka for this acid?

Answer;

= 0.7698 M

Explanation and solution;

AgClO3 ionizes as follows:  

AgClO3 ---> Ag^+ + ClO3^-  

Moles AgClO3 dissolved ---> (0.393 mol/L) (0.925 L) = 0.424865 mol

From the chemical equation, one mole of AgClO3 dissolving yields one mole of ClO3^- in solution.

Moles ClO3^- = 0.424 865 mol

Similarly;

Mn(ClO3)2 dissolves as follows:

Mn(ClO3)2 ---> Mn^2+ + 2ClO3^-

Moles Mn(ClO3)2 dissolved ---> (0.283 mol/L) (0.685 L) = 0.413139 mol

From the chemical equation, one mole of Mn(ClO3)2 dissolving yields two moles of ClO3^- in solution.

Moles ClO3^- = 0.413139 mol x 2 = 0.826277 mol  

Total moles ClO3^- in solution;

0.826277 mol + 0.413139 mol = 1.239416 mol  

Total volume of solution ---> 0.925 L + 0.685 L = 1.61 L  

Molarity of ClO3^- ---> 1.239416 mol / 1.61 L = 0.7698 M

Answer: The concentration of chlorate ion is 0.467 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]     .....(1)

Molarity of [tex]AgClO_3[/tex] solution = 0.393 M

Volume of solution = 925 mL = 0.925 L      (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

[tex]0.393M=\frac{\text{Moles of }AgClO_3}{0.925L}\\\\\text{Moles of }AgClO_3=(0.393mol/L\times 0.925L)=0.364mol[/tex]

Molarity of [tex]Mg(ClO_3)_2[/tex] solution = 0.283 M

Volume of solution = 685 mL = 0.685 L

Putting values in equation 1, we get:

[tex]0.283M=\frac{\text{Moles of }Mg(ClO_3)_2}{0.685L}\\\\\text{Moles of }Mg(ClO_3)_2=(0.283mol/L\times 0.685L)=0.194mol[/tex]

The chemical equation for ionization of silver chlorate follows:

1 mole of silver chlorate produces 1 mole of silver ion and 1 mole of chlorate ion

Moles of chlorate ion = 0.364 moles

The chemical equation for ionization of magnesium chlorate follows:

[tex]Mg(ClO_3)_2\rightarrow Mg^{2+}+2ClO_3^-[/tex]

1 mole of magnesium chlorate produces 1 mole of magnesium ion and 2 moles of chlorate ion

Moles of chlorate ion = (2 × 0.194) = 0.388 moles

Moles of chlorate ion = (0.364 + 0.388) = 0.752 moles

Volume of solution = (925 + 685) = 1610 mL = 1.610 L

Putting values in equation 1, we get:

[tex]AgClO_3\rightarrow Ag^++ClO_3^-[/tex]0.752[tex]\text{Molarity of chlorate ion}=\frac{0.752mol}{1.610L}\\\\\text{Molarity of chlorate ion}=0.467M[/tex]

Hence, the concentration of chlorate ion is 0.467 M

The answer is 125 gms.

Answer:

The values of Y are: 18, 9, 6, 3, 2, 1

Explanation:

It is given that X and Y are inversely related. This can be depicted mathematically as:

[tex]X \alpha \frac{1}{Y}[/tex]

i.e. as X increases the value of Y is expected to decrease.

(or) [tex]X =k* \frac{1}{Y}[/tex]

where k = proportionality constant which is given as 18

In terms of Y, the above equation becomes:

[tex]Y =k* \frac{1}{X}[/tex]

Based on the above equation the table can be filled as :

X     Y     K

1      18    18

2     9      18

3     6      18

6     3      18

9     2      18

18     1     18

Answer: x y k

1 18 18

2 9 18

3 6 18

6 3 18

9 2 18

18 1 18

Explanation:

The relationship is r = 2.5Z + 130.

From your graph, I estimate the slope of the line to be:

[tex]\text{slope} = \frac{\Delta y }{\Delta x } = \frac{260-130}{56-4} = \frac{130}{52} = 2.5\\[/tex]

The y-intercept ≈ 130.

So, the equation for the line is  

r = 2.5Z + 130.

The relation tells us that the atomic size increases as the atomic number increases.

This makes sense because, as you go down a Group, you are adding electrons to the next shell further out.

Answer;

55.86 moles

Explanation;

Six molecule of H2O is needed for every molecule of C6H12O6 to be produced.

This means the ratio of H2O: C6H12O6 is 6:1  

Let H2O mole= X  

Therefore...

X/9.31 = 6/1  

X= 6 x 9.31

X = 55.86 moles

55.86 moles of H2O are needed to produce 9.31 moles of C6H12O6.

The chemical formula for glucose (C6H12O6) indicates that there are 6 moles of water (H2O) needed for every mole of glucose produced. Therefore, to find out how many moles of water are needed for 9.31 moles of glucose (C6H12O6), you can multiply the number of moles of glucose by the ratio of moles of water to moles of glucose:

Number of moles of H2O = Number of moles of C6H12O6 × (6 moles of H2O / 1 mole of C6H12O6)

Number of moles of H2O = 9.31 moles × 6

Number of moles of H2O = 55.86 moles

So, 55.86 moles of H2O are needed to produce 9.31 moles of C6H12O6.

Read more on chemical formula here https://brainly.com/question/2778716

#SPJ4

1. A) Bohr

2. D) When excited electrons return back to the ground state, a photon of light is emitted.

3. D) 10.812 amu

Hope this helps! :)

Answer:

1.A

2.D

3.D

Explanation:

1.We have to fill correct answer  in blank  space given in the question.

Bohr's postulates

1.Electron revolve in certain stable  orbits around the nucleus without radiating any energy .The stable orbits or energy levels  are called stationary orbits and these orbits at a certain discrete distance from the nucleus.

2.The stationary orbits are attained at distances for which the  angular momentum is integral multiple of plank;s constant

L=mvr=nh

Where n is called principle quantum number

3.Electrons gain or lose energy when they jump from one energy lever to other energy lever or when higher energy level to low energy level.

Hence, the mystery of periodic laws was solved when Bohr proposed his planetary atomic model of the atom ,providing an understanding of the electronic structure of the elements and the organization of electrons into shells,

Option A is true.

2.When am electron absorb energy then the electrons jump from low energy level to high energy level .When the electron return from higher energy level to low energy level then it emit colored flame.

When Christ put copper chloride into Bunsen burner flame then it began to emit a green color because when excited electron returns back to the ground state , then  photon of light is emitted.

Hence, option D is true.

3.Boron-10 has abundance 19.8% and actual mass of 10.013 amu and boron-11 has an abundance of 80.2% and actual mass of 11.009.

We have to find the average atomic mass for all isotopes of boron

Average atomic mass of boron =[tex]0.198\times 10.013+0.802\times 11.009[/tex]

Average atomic mass of boron=10.811792=10.812 amu

Hence, option D is true.

The correct answer is 2.73.

HF is a weak acid which partially dissociates to release H+ and F-

                HF           →         H⁺   + F⁻

Initial      0.0050                   0       0

Change    -x                        +x       +x

Equilibrium 0.0050–x         +x     +x

Solve by using the equilibrium expression: =  [H⁺] [F⁻]/ [HF]

6 .8 x 10⁻⁴= x. x / 0.0050   –x

6 .8 x 10⁻⁴= x² /0.0050  

x²  = 6 .8 x 10⁻⁴ x 0.0050  

x²  = 3.4 x 10⁻⁶

x = 3.4 x 10⁻⁶

[H⁺]  = 1.84 x 10⁻³

pH = - log [H⁺] = - log (1.84 x 10⁻³)

pH = 2.73

A solution may exist in any phase so your answer is D. any of the above

hope this helps :)

Final answer:

A solution can be made up of any combination of solids, liquids, and gases, including solid and liquid, two solids, or two liquids. Hence, the correct answer is (d) Any of the above.

Explanation:

Solutions can be composed of various states of matter. A solution is defined as a homogeneous mixture where the particles of one or more substances (the solute) are distributed uniformly throughout another substance (the solvent).

Considering these examples, the correct answer to the student's question is d. Any of the above.

A) The volume of the block is 125 cm³.

[tex]V = l^{3} = (\text{5.0 cm})^{3} = 125 \text{ cm}^{3}\\[/tex]

B) The density of the block is 4.5 g/cm³.

[tex]\text{Density} = \frac{\text{Mass}}{\text{Volume}} = \frac{\text{563.75 g}}{125 \text{ cm}^{3}} = \text{4.5 g/cm}^{3}\\[/tex]

Pyridinium will react with both OH- and HCO3-, whereas the ketones will only react with concentrated OH-, while Butan-2-one cannot react with either of above.

a) Butan-2-one: cannot react with both hydroxide ion and bicarbonate.

b) Pyridinium: can react with both hydroxide ion and bicarbonate.

c) ketones : can only react with concentrated OH-

Silicon atoms fuse to form nickel in stars. Emission spectra help in detecting elements in deep space. The isotopic mass of vanadium-50 is approximately 49.944 amu.

Stars, including the sun, produce energy by fusing helium and hydrogen together through a process known as nuclear nucleosynthesis.

As stars consume their helium, their temperature escalates, allowing for heavier elements to undergo fusion.

The fusion of two atoms of silicon can yield nickel, which is the heaviest element that can be produced through fusion due to the net energy requirements.

Emission spectra are used by scientists to detect elements in clouds of gas and dust in deep space.

The isotopic mass of vanadium-50 can be obtained using the formula: (mass of isotope × abundance of isotope / total abundance).

Given that vanadium-50 has an abundance of 0.250% and vanadium-51 has an abundance of 99.750% with a mass of 50.944 amu, the isotopic mass of vanadium-50 is approximately 49.944 amu.

Learn more about nucleosynthesis here:

https://brainly.com/question/35897140

#SPJ3

The scientific theory of the matter of nature.

2C4H10 + 8O2 → 8CO2 + 10H2O

There should be 8 molecules of oxygen which react with 2 molecules of butane to produce 8 molecules of carbon dioxide and 10 molecules of water.

Answer:

Explanation:

Answer:

2C4H10 + 13O2 → 8CO2 + 10H2O

Explanation:

2C4H10 + O2 → CO2 + H2O

There are 8 carbon atoms on the left side of the equation thus , there should be equal number of carbon atoms on the right side

So, if we balance carbon atoms only, the new eqation becomes

2C4H10 + O2 → 8CO2 + H2O

Now carbon atoms are balance but there are 20 , hydrogen atoms on the left side but 2 atoms only on the right side. So the new equation after balancing hydrogen atom becomes

2C4H10 + O2 → 8CO2 + 10H2O

Now both carbon and hydrogen atoms are balanced but oxygen atoms are pending. There are 26 atoms of (O) on the right side , while 1 molecule of (O2)

So the balanced equation would be  

2C4H10 + 13O2 → 8CO2 + 10H2O

The 'endpoint' in a titration refers to the measured volume of the titrant solution that results in a visible change, marking the completion of the reaction.

The 'endpoint' in a titration process refers to the measured volume of the titrant solution that causes a change in appearance, usually associated with a change in an indicator. A titrant, also known as a titrator, is a reagent of known concentration that is added from a burette to a solution of the analyte until the reaction is complete. This reaction completion, seen as a visible change, is the 'end point' of titration.

For Instance, in an acid-base titration, the endpoint is reached when the amounts of acid and base are stoichiometrically equal, and the pH of the solution suddenly changes. This process typically involves an indicator, such as phenolphthalein, that changes color at the endpoint.

https://brainly.com/question/32469016

#SPJ12

The 'end point' during a titration refers to the volume of the 'titrant' solution that leads to a noticeable color change in an indicator, signifying that the reaction has concluded.

In the process of a titration, the so-called 'end point' is the measured volume of the titrant solution (option B) that causes an observable change in appearance. This noticeable transformation usually takes the form of a change in an indicator. The end point of a titration is crucial as it signifies exactly when the reaction has reached completion.

For instance, let's consider a standard acid-base titration. In this case, the titrant (the solution in the burette) is gradually added to the analyte (the substance or solution being analyzed in the conical flask). An acid-base indicator, such as phenolphthalein, changes color to indicate the attainment of the end point, i.e., when stoichiometrically equivalent amounts of acid and base have reacted.

https://brainly.com/question/31271061

#SPJ12

Answer : A - carboxyl group.

The carbon in the carboxyl group is bonded to a hydroxyl group and also it is double bonded to an oxygen group.

The carboxyl group when it is dissolved in a solution donates it's hydrogen ion(H+ ion). When it is dissolved in water, the carboxyl group loses its H+ ion to form negatively charged ion.

RCOOH + H2O⇄RCOO- + H3O+

Thus the carboxyl group act as an acid when dissolved in water.

The functional group that acts most like an acid in water is the carboxyl group found in carboxylic acids, due to its ability to release a hydrogen ion and form a carboxylate anion and hydronium ion in solution.

The correct answer to the question of which functional group acts most like an acid in water is A) carboxyl. Carboxylic acids have a carboxyl group, which is made up of a carbonyl (C=O) and a hydroxyl (-OH) group. In water, the hydroxyl group can release a hydrogen ion, making the molecule an acid. Carboxylic acids, like acetic acid, partially dissociate in water to form carboxylate anions and hydronium ions, exhibiting their acidic nature. This is different from hydroxyl groups, which generally act as weak acids and do not donate protons as readily as carboxylic acids.

Count the quantity of each particle in the container in each of the diagrams:

[tex]\begin{array}{cccc} \text{H}_2 & \text{I}_2 & \text{HI} & \\3 & 3 & 0 & \text{as in figure i} \\2 & 2 & 2 & \text{as in figure ii} \\1 & 1 & 4 & \text{as in figure iii} \\1 & 1 & 4 & \text{as in figure iv}\\1 & 1 & 4 & \text{as in figure v} \\\end{array}[/tex]

The container appears to be of constant volume and thus the concentration of each species is directly related to the number of particle present. By definition, the system is in equilibrium once the relative concentration becomes constant, which is in this scenario achieved at the time point depicted in diagram iii. Thus the answer.

Final answer:

To find the volume of water displaced by 46kg of copper, mass is converted to grams and divided by copper's density, which results in 5155.16 mL of water displaced. Copper granules will sink in water as its density is higher than water's.

Explanation:

To determine the volume of water displaced by 46kg of copper granules, we first convert the mass of copper to grams (since the density is given in grams per cubic centimeter). We have:

46 kg of copper * 1000 g/kg = 46000 g of copper.

Now, we use the density of copper (8.92 g/cm3) to find the volume of copper, which is the same as the volume of water displaced:

Volume of copper = Mass of copper / Density of copper = 46000 g / 8.92 g/cm3 = 5155.16 cm3.

Since 1 cm3 is equivalent to 1 mL, 5155.16 cm3 would be 5155.16 mL of water displaced.

Regarding the second question, since the density of water is 1.00 g/mL, which is lower than that of copper, copper granules will sink in the water.

Hey there!:

a conjugate base  contains  one less  hydrogen atom and one more negative charge thant the acid  that formed  it . All acids have a conjugate base  , all base have a conjugate acid, acids  donate H⁺ when react.

Therefore:

H3PO4 -------------- H2PO4⁻

Hope that helps!

Hey there!:

ka = kw/ kb

Ka = 1.0*10⁻¹⁴ / 1.8* 10⁻⁵

Ka = 5.56*10⁻¹⁰

Now Cl⁻ is spectator ion

NH⁴⁺ --->  NH3 + H⁺

Kb =  [NH⁴⁺ / [NH3] [H⁺]

at equilibrium  the concentration of products is taken as x each  and that of ammonium  ion will be  ( 0.10 -x )

5.56*10⁻¹⁰ = x² / [0.10 -x]

x =  7.54* 10⁻⁶ M

pH = - log [ H⁺ ]

pH = - log [ 7.54*10⁻⁶ ]

pH =  5.13

Answer C

Hope that helps!

The pH of a 0.10 M solution of NH4Cl is calculated using the Kb value of NH3 and the relationship between Ka, Kb, and Kw. By using the hydrolysis reaction equation and finding [H3O+], we can apply the formula pH = -log[H3O+] to get the pH value of 5.13.

The pH of a 0.10 M NH4Cl solution can be determined using the Kb value of NH3 and the relationship between Ka, Kb, and Kw (ion product for water). Ammonium chloride, NH4Cl, will associate in water to form NH4+ and Cl-. The NH4+ ion reacts with water in a hydrolysis reaction: NH4+ + H2O ⇌ NH3 + H3O+. This reaction has a Ka (acid dissociation constant) that can be calculated from the Kb (base dissociation constant) of NH3, using the relationship Kw=Ka x Kb (Kw is the ion product for water, 1.0 x 10-14 at 25°C). Therefore, Ka = Kw/Kb = 1.0 x 10-14 / 1.8 x 10-5 = 5.56 x 10-10.

This is a weak acid equilibrium, use ICE table and solve for [H3O+] using the equation Ka = [NH3][H3O+] / [NH4+]. After calculating the [H3O+], we can find the pH using the formula pH = -log[H3O+]. The correct pH value will be close to values between 4 and 6, thus the answer is 5.13.

https://brainly.com/question/34432529

#SPJ6

Final answer:

To find the formula of a hydrate, calculate the molar ratio of CuSO4 to H2O, which for the provided masses is approximately 8:1. Thus, the hydrate formula is CuSO4·8H2O, known as copper(II) sulfate octahydrate.

Explanation:

To determine the formula of a hydrate with given amounts of CuSO4 and H2O, we first need to calculate the molar ratio of the two substances. We do this by finding the number of moles of each substance and dividing them to get their ratio. The molar mass of CuSO4 is 159.61 g/mol, and the molar mass of H2O is 18.02 g/mol. Therefore:

Now we calculate the simplest ratio of moles of H2O to moles of CuSO4, which is 0.2997 mol H2O ÷ 0.0375 mol CuSO4 ≈ 8. Therefore, the compound is copper(II) sulfate octahydrate, and the chemical formula for this hydrate is CuSO4·8H2O.

Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.

              b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.

Explanation: The decomposition of carbon disulfide is given as:

                          [tex]CS_2(g)\rightarrow CS(g)+S(g)[/tex]

at t=0                    4.83g             0          0

at t=37 days        4.83 - x            x           x

here,

x = amount of [tex]CS_2[/tex] utilised in the reaction

This reaction follows first order kinetics so the rate law equation is:

[tex]k=\frac{2.303}{t}log\frac{A_o}{A}[/tex]

where, k = rate constant

t = time

[tex]A_o[/tex] = Initial mass of reactant

A = Final mass of reactant

a) For this, the value of

[tex]k=2.80\times10^{-7}sec^{-1}[/tex]

t = 370 days = 3196800 sec

[tex]A_o[/tex] = 4.83

A = 4.83-x

Putting values in the above equation, we get

[tex]2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)[/tex]

x = 2.85g

Amount of [tex]CS_2 [/tex] remained after 37 days = 4.83 - x

                                                                     = 1.97g

b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.

Amount of carbon monosulfide formed = 2.85g

The chart is about atomic structure: at the top, the left box is "nucleus" and the right is "electron cloud".

On the left, under nucleus, the two boxes are: "protons" on the right and "neutrons" on the left.  Under proton is elements which is given and under neutrons, it is "isotopes".

On the right, under electron cloud, the next box is "electrons" and then the lower box is "ions".

The table shows the classical model of atoms.

An atom is made up of a dense nucleus (left) and electron cloud (right) whirling around the nucleus.

Within the nucleus, there are protons (left) and neutrons (middle). Within the electron cloud are the electrons (right most).

If the number of neutrons is different but the no. of protrons is the same, that is called isotope (left). If a neutral atom gains or loses, it becomes an ion (right).

The Boyle's Law states an inverse relationship between the pressure of a gas and its volume when its temperature stays constant.

For the question

[tex]T_1/T_2 = P_1/P_2[/tex]

Thus

[tex]V_2 = V_1 \cdot (P_1 / P_2) = 0.315[/tex]

The flow of heat from Earth's interior to the surface is estimated at terawatts (TW) and comes from two main sources in roughly equal amounts:

the answer is A:

Photosynthesis release O2 (oxygen)

then animals use oxygen for respiration and release Co2

The correct answer is A) Photosynthesis O2 Respiration CO2. Photosynthesis converts CO2 to O2, which is then used in respiration to be converted back into CO2. Both processes together create a continuous cycle.

The correct diagram that represents the cycling of gases between photosynthesis and respiration is A) Photosynthesis O2 Respiration CO2. Through the process of photosynthesis, plants convert carbon dioxide (CO2) and sunlight into oxygen (O2) and glucose. Organisms, including the plants themselves, then use that oxygen for respiration, during which they convert the oxygen back into carbon dioxide. The glucose is used for energy. This continuous cycling plays a critical role in life on Earth.

https://brainly.com/question/11267534

#SPJ3

Barium Sulfate [tex]\text{BaSO}_4[/tex] is chemically stable and safe for human consumption.

Barium Sulfide [tex]\text{BaS}[/tex] is toxic and shall be handled with care.

Barium ions [tex]\text{Ba}^{2+}[/tex] ions can damage cell membranes and are thus toxic to the human body.

Barium ions in barium sulfate, however, are held tightly in ionic lattice and barely dissolve in water. Barium sulfate thus stay intact and give rise to no harmful [tex]\text{Ba}^{2+}[/tex] ions when orally ingested.

Barium sulfide can dissolve in water at significant quantities to produce barium [tex]\text{Ba}^{2+}[/tex] ions and sulfide [tex]\text{S}^{-2}[/tex] ions. Barium ions are toxic aforementioned whereas sulfide ions can undergo hydrolysis to produce hydrogen sulfide, a weak acid that evolves and behaves as a toxic gas.

[tex]\text{BaS} \; (s)\to\text{Ba}^{2+} \; (aq) + \text{S}^{2} \; (aq)\\\text{S}^{2-}\; (aq) + 2\; \text{H}_2\text{O} \; (l) \rightleftharpoons \text{H}_2\text{S} \; (g) + 2 \; \text{OH}^{-} \; (aq)[/tex]

Hey There:

First order  half life equation :

T 1/2  = ln ( 2 ) /K

T 1/2 = 0.693 / 3.40

T 1/2 = 0.204 s

Answer B

Answer: The half life of the decomposition reaction is 0.204 s

Explanation:

The equation used to calculate half life for first order kinetics:

[tex]t_{1/2}=\frac{0.693}{k}[/tex]

where,

k = rate constant of the reaction = [tex]3.40s^{-1}[/tex]

[tex]t_{1/2}[/tex] = half life of the reaction = ?

Putting values in above equation, we get:

[tex]t_{1/2}=\frac{0.693}{3.40s^{-1}}\\\\t_{1/2}=0.204s[/tex]

Hence, the half life of the decomposition reaction is 0.204 s

The deeper the the water is the freasher/ cleaner it is

hey i'm late but if any of other readers need help on this question here it is Surface impurities easily reach the shallow water source.  ask me if you need any help why

Answer:

answer is 0.225 atm

Explanation:

was right on edge