Answers
A = Ac = v^2/R
so m A = Mjupiter v^2/R (toward sun)
F = G Msun MJupiter /R^2 (toward sun)
so
G Msun/R^2 = v^2/R
G Msun = v^2 R
Time around = circumference /v
T = 2 pi R/v
so
v = 2 pi R/T
v^2 = (2pi)^2 R^2/T^2
so
G Msun = (2 pi)^2 R^3/T^2
(which by the way is Kepler's Third Law)
so
R^3 = G Msun T^2/(2 pi)^2
G is 6.67*10^-11
so
R^3 = 6.67*10^-11*1.99*10^30*14.36*10^16 /39.48
R^3 = 4.828*10^35
= .4828 * 10^36
so
R = .784 * 10^12 = 7.84 * 10^11 meters
The mean distance between the center of the Jupiter and the center of the Sun is "7.85 x 10¹¹ m"
The force of gravitation between the Sun and Jupiter must be equal to the centripetal force between them, for the equilibrium revolution of Jupiter around the Sun.
[tex]Centripeta\ Force\ on\ Jupiter = Gravitational\ Force\ of Attraction\ \\\\\frac{M_{Jupiter}v^2}{r} = \frac{GM_{Jupiter}M_{Sun}}{r^2}\\\\v^2 = \frac{GM_{Sun}}{r}\ -------- eqn(1)\\\\[/tex]
where,
G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
[tex]M_{Sun}[/tex] = Mass of Sun = 1.99 x 10³⁰ kg
r = mean distance between the center of the Jupiter and the Sun = ?
v = linear speed of the Jupiter around the Sun = [tex]\frac{Circumference\ of Jupiter's\ Path}{Time\ Period\ of\ Revolution}[/tex]
[tex]v = \frac{2\pi r}{3.79\ x\ 10^8\ s}\\\\v^2 = \frac{4\pi^2 r^2}{14.36\ x\ 10^{16}\ s^2}[/tex]
Using the values in eqn (1), we get:
[tex]\frac{4\pi^2 r^2}{14.36\ x\ 10^{16}\ s^2} = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{r}\\\\r^3 = \frac{(14.36\ x\ 10^{16}\ s^2)(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{4\pi^2}\\\\r = \sqrt[3]{4.83\ x\ 10^{35}\ m^3}[/tex]
r = 7.85 x 10¹¹ m
Learn more about centripetal force and gravitational force here:
https://brainly.com/question/14021112?referrer=searchResults
https://brainly.com/question/16613634?referrer=searchResults
The attached picture shows the relationship between the centripetal force and the gravitational force acting on a planet (Jupiter) revolving around the sun.
Related Questions
A proton beam in an accelerator carries a current of 130 μa. if the beam is incident on a target, how many protons strike the target in a period of 17.0 s?
Answers
[tex]I= \frac{Q}{\Delta t} [/tex]
We know the current, [tex]I=130 \mu A=130 \cdot 10^{-6} A[/tex], and the time interval, [tex]\Delta t=17 s[/tex], so we can find the total charge:
[tex]Q=I \Delta t= 2.21 \cdot 10^{-3}C [/tex]
The total charge Q is the product between the number of protons N and the charge of each protons, e, which is [tex]e=1.6 \cdot 10^{-19}C[/tex]:
[tex]Q=Ne[/tex]
we can re-write the equation solving for N, so we can find the number of protons striking the target in 17 s:
[tex]N= \frac{Q}{e}= \frac{2.21 \cdot 10^{-3}C}{1.6 \cdot 10^{-19}C} =1.38 \cdot 10^{16} [/tex]
Final answer:
Using the formula relating current, charge, and time, approximately 1.38 × 10^16 protons strike a target when 130 μA of current is directed at the target for 17.0 seconds.
Explanation:
To determine how many protons strike the target in 17.0 seconds with a current of 130 μA (microamperes), we must understand the relationship between electric current, charge, and the quantity of charged particles. Current (I) is defined as the amount of charge (Q) passing through a point in a circuit per unit of time (t), mathematically described by the equation I = Q/t. Given that each proton carries a charge of approximately 1.6 × 10-19 C (coulombs), we can find the total charge that strikes the target over 17.0 seconds and subsequently calculate the number of protons involved.
First, convert the current from microamperes to amperes: 130 μA = 130 × 10-6 A. Then, use I = Q/t to find the total charge Q: Q = I × t = (130 × 10-6 A) × 17.0 s = 2.21 × 10-3 C. Finally, calculate the number of protons by dividing the total charge by the charge of a single proton: Number of protons = Q / charge of one proton = (2.21 × 10-3 C) / (1.6 × 10-19 C/proton) ≈ 1.38 × 1016 protons.
Therefore, approximately 1.38 × 1016 protons strike the target in a period of 17.0 seconds.
The absolute pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa. At what depth does this pressure occur? Assume that atmospheric pressure is 1.01 x 10^5 Pa. and the density of the water is 1.00 x 10^3 kg/m^3
Answers
[tex] P_{total} = P_{atm} + (rgh)[/tex]
Where: [tex] P_{total} [/tex] = Absolute pressure
[tex] P_{atm} [/tex] = atmospheric pressure
r = density
g = [tex] 9.8 \frac{m}{{s^2}} [/tex]
h = depth
We can use this formula to derive our formula for h:
[tex] P_{total} = P_{atm} + (rgh)[/tex] transpose atmospheric pressure
[tex] P_{total} - P_{atm} [/tex] = [tex](rgh)[/tex] transpose r and g
[tex] P_{total} [/tex] - [tex] P_{atm} [/tex]
------------------------- = h
rg
Now let us input our given into our new formula:
3.52 x [tex] 10^{5}[/tex] - 1.01 x [tex] 10^{5}[/tex]
---------------------------------------- = h
1.00 x [tex] 10^{3} [/tex] x 9.8 [tex] \frac{m}{ s^{2} } [/tex]
[tex] \frac{2.51 x {10^5}}{9.8 x {10^3} \frac{m}{s^2}} = h [/tex]
[tex] 25.61 m = h [/tex]
The depth at which the pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa is 24.29 meters.
Explanation:The depth at which the pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa can be calculated using the formula:
Pressure = atmospheric pressure + density of water * gravitational acceleration * depth
In this case, the atmospheric pressure is 1.01 x 10^5 Pa, the density of water is 1.00 x 10^3 kg/m^3, and the gravitational acceleration is 9.8 m/s^2. We can rearrange the equation to solve for depth:
Depth = (pressure - atmospheric pressure) / (density of water * gravitational acceleration)
Plugging in the values, we get:
Depth = (3.51 x 10^5 Pa - 1.01 x 10^5 Pa) / (1.00 x 10^3 kg/m^3 * 9.8 m/s^2)
Depth = 24.29 meters
Learn more about Calculating depth and pressure in fluids here:https://brainly.com/question/35577473
#SPJ3
Marta, Cato, and Juan plan a skit to illustrate one of the methods of charging.
Marta and Cato are walking together. Each has one flower and one box of candy.
Juan offers Cato a huge bouquet of flowers, but Cato can’t take it because his hands are full.
Cato hands his flower to Marta and then turns to Juan to take the bouquet.
Marta walks away in one direction with two flowers and one box of candy. Juan keeps the bouquet and walks away in the other direction. Cato looks sad standing alone with only a box of candy.
How does the skit model a method of charging?
a It models induction because an electron (a flower) transfers from Cato to Marta through direct contact.
b It models friction because an electron (a flower) transfers from Cato to Marta through direct contact.
c It models friction because the offer of flowers represents a charged object that causes an electron (a flower) to transfer from one object to another.
d It models induction because the offer of flowers represents a charged object that causes an electron (a flower) to transfer from one object to another.
Answers
The answer is C. Frictional charging is primarily involved. In the scenario, the bouquet of flowers represents a charged object that causes an electron (or the flower) to transfer from one object to another. Due to the bouquet of flowers, the other flower repelled and moved towards the object with a lesser charge. As a result, the box becomes neutral or has no charge at all.
The answer is D.
I just took the test and got it right
.
ampere. What is the resistance of the radio A radio operating at 3.0 volts and a constant temperature draws a current of 1.8 x 10 -4 circuit?
Answers
The resistance of the radio circuit is 16.7 kΩ.
To calculate the resistance of the radio circuit when it operates at 3.0 volts and draws a current of 1.8 x 10-4 amperes, we can use Ohm's Law, which states that Resistance (R) equals Voltage (V) divided by Current (I), or R = V/I. Plugging in the given values, R = 3.0 V / (1.8 x 10-4 A), we find that the resistance is approximately 16,666.67 Ω, or 16.7 kΩ when rounded to three significant digits. When dealing with electrical circuits, it is important to understand concepts like resistance, voltage, and current, as they are fundamental to analyzing and predicting the behavior of the circuit.
At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?
Answers
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
[tex]\ln( \frac{K_2}{K_1} ) = \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2} ) [/tex]
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
[tex] \frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2} )=12.38 [/tex]
And so
[tex]\ln( \frac{K_2}{K_1})=12.38 [/tex]
And using [tex]K_1=6.1\cdot 10^{-8} s^{-1}[/tex] , we find K2:
[tex]K_2=K_1 e^{12.38}=0.0145 s^{-1}[/tex]
In the process of nuclear fusion, large amounts of energy, at temperatures of approximately 120 million Kelvin, are required to join two nuclei into a single, heavier nucleus. Why does the process of fusion require so much energy in order to take place?
Answers
[tex]U=k \frac{q^2}{r} [/tex]
And since the range of the nuclear strong interaction is very short, r must be very small, and so the amount of energy required U can be huge.
After walking across a carpeted floor in socks, Jim brings his finger near a metal doorknob and receives a shock. what does that demonstrate
Answers
Electric forces can act at a distance
which theory of plate movements involves magma rising all the way from the lower mantle to spread apart plates
Answers
Answer:
hot plumes
Explanation:
what is the definition of work when net force is parallel to the distance?
Answers
W=Fd
What is most likely to happen to light that hits an opaque object?
A. All of the light passes through the object.
B. None of the light passes through the object.
C. Most of the light disappears.
D. Some of the light passes through the object.
Answers
C is not correct because the light is actually reflected off of an opaque object.
When the light hits an opaque object, none of the light will pass through the object. Hence, option B is correct.
What is light?Electromagnetic radiation that the human eye can detect as light. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than roughly 1 1011 meter, electromagnetic radiation occurs throughout a very broad range of wavelengths.
The wavelengths of light that are visible to humans fall into a very small range within that wide spectrum, ranging from about 700 nanometers for red light to roughly 400 nm for violet light.
Infrared and ultraviolet are two spectral bands that are close to the visible region and are repeatedly alluded to as light as well.
Anything that doesn't let any light through is opaque. Instances of opaque materials include concrete, wood, and metal.
To know more about Light:
https://brainly.com/question/15200315
#SPJ2
Two large parallel conducting plates are 17 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. an electrostatic force of 2.9 ✕ 10-15 n acts on an electron placed anywhere between the two plate (neglect fringing). (a) find the electric field at the position of the electron.
Answers
[tex]F=qE[/tex]
where E is the electric field's intensity.
In our problem, the particle is an electron, so its charge is [tex]q=e=-1.6 \cdot 10^{-19}C[/tex]. We know the intensity of the force, so we can find the magnitude of the electric field at the point where the electron is located:
[tex]E= \frac{F}{q}= \frac{2.9\cdot 10^{-15}N}{-1.6 \cdot 10^{19}C}=-1.8 \cdot 10^4 N/C [/tex]
where the negative sign means that the force and the electric field have opposite direction, because the charge is negative.
A tennis ball is thrown from ground level with velocity directed 30° above the horizontal. if it takes the ball 0.5 s to reach the top of its trajectory, what is the magnitude of the initial velocity?
Answers
The component of the velocity on the y-axis is given by the following law:
[tex]v_y(t) = v_{y0}+gt[/tex]
At the time t=0.5 s, the ball reaches its maximum height, and when this happens, the vertical velocity is zero (because it is a parabolic motion): [tex]v_y(0.5 s)=0[/tex]. Substituing into the previous equation, we find the initial value of the vertical component of the velocity:
[tex]v_{y0}=-gt=-(-9.81 m/s^2)(0.5 s)=4.9 m/s[/tex]
However, this is not the final answer. In fact, the ball starts its trajectory with an angle of [tex]30^{\circ}[/tex]. This means that the vertical component of the initial velocity is
[tex]v_{y0}=v_0 sin 30^{\circ}[/tex]
We found before [tex]v_{0y}=4.9 m/s[/tex], so we can substitute to find [tex]v_0[/tex], the initial speed of the ball:
[tex]v_0 = \frac{v_{y0}}{sin 30^{\circ}}=9.81 m/s [/tex]
Using the equation of motion v = u + gt and knowing that at the top of its trajectory the final velocity of the ball is 0, the time it takes to reach there is 0.5 seconds and the acceleration due to gravity is -9.8 m/s², we can determine the magnitude of the initial vertical component of the velocity to be 4.9 m/s. As the ball was thrown at a 30° angle, this means the magnitude of the initial velocity is 9.8 m/s.
Explanation:In order to find the initial velocity of a projectile, we can use a foundational equation from Physics. Specifically, the formula v = u + gt where v is the final velocity, u is the initial velocity, g is acceleration due to gravity, and t is time. We're told that the ball takes 0.5 seconds to reach the top of its trajectory. At the top of its trajectory, the ball's final velocity will be 0 m/s (because it momentarily stops before falling back down). Also, the acceleration due to gravity is -9.8 m/s². Re-arranging the formula to solve for u gives us u = v - gt. Replacing v with 0, g with -9.8 m/s², and t with 0.5 s gives u = 0 - (-9.8 m/s² * 0.5s) = 4.9 m/s. However, this 4.9 m/s is just the vertical component of the initial velocity, because gravity acts vertically. Since the balls is thrown at an angle of 30°, to get the magnitude of the initial velocity, we have to divide 4.9 m/s by sin(30°) which gives us roughly 9.8 m/s. Therefore, the magnitude of the initial velocity is approximately 9.8 m/s.
Learn more about Projectile motion here:https://brainly.com/question/29545516
#SPJ3
Determine the tension developed in the cable ab required to support the traffic light, which has a mass of 19 kg . take h = 3.5 m.
Answers
Final answer:
The tension in the cable AB required to support the traffic light with a mass of 19 kg is equal to the weight of the traffic light, calculated as 186.2 N by multiplying the mass by the acceleration due to gravity.
Explanation:
To determine the tension in the cable AB required to support the traffic light with a mass of 19 kg, we need to use the concept that the tension must balance the weight of the traffic light. Since the traffic light is in equilibrium (not moving), the net force acting on it must be zero.
The weight of the traffic light (W) can be calculated using the formula W = m × g, where m is the mass of the traffic light and g is the acceleration due to gravity (which is approximately 9.8 m/s2 on the surface of the Earth).
Calculating the weight: W = 19 kg × 9.8 m/s2 = 186.2 N.
Now, since we are dealing with a situation where only one cable is mentioned and there are no angles provided, we assume the cable is vertical, and therefore, the tension in cable AB is simply the weight of the traffic light, which is 186.2 N.
Calculate the momentum of a 953kg elephant running at a rate of 3.85 m/s.
Answers
So we got 953kg = mass
And we also got 3.85 = speed
M/S = 953/3.85
953/3.85= 247.532468
ANSWER: 247.532468
Hope I helped! :D
What does the Energy Independence and Security Act of 2007 mandate? A. more use of fossil fuels
B. more use of heavy cars
C. more fuel efficient cars
Answers
Answer: C
The Energy Independence and Security Act of 2007 mandates the use of more fuel efficient cars where car manufacturers are required to boost fleet wide gas mileage to 35 mp (14.8 km/l) by 2020 in order to help reduce petroleum consumption. It encourages the increase in fuel economy standards for passenger cars. Thus, promote production of fuel-efficient vehicles. Additionally, the act also support the use of electric transportation technology.
The answer is C. more fuel efficient car.s
You make a u turn in your car, what provides the centripetal force on the car and on you
Answers
The correct answer is the frictional force.
In fact, the centripetal force is the force that keeps the car in circular motion, and it points toward the centre of the circular trajectory. The frictional force between the tyres of the car and the road provides the centripetal force that keeps the car in the turn: in fact, without the friction (e.g. on an icy road), the car would not be able to make the turn at the same speed.
A ferris wheel of radius r speeds up with angular acceleration α starting from rest. part a find an expression for the velocity of a rider after the ferris wheel has rotated through angle δθ.
Answers
[tex]\alpha = \frac{\Delta \omega}{\Delta t} [/tex]
where [tex]\Delta \omega = \omega-\omega _0[/tex] is the variation of the angular velocity, with [tex]\omega _0[/tex] being the starting velocity (which in our problem is zero), and [tex]\Delta t[/tex] being the time interval. So we can write the angular velocity after an angle [tex]\delta \theta[/tex] as
[tex]\omega (\delta \theta) = \alpha \Delta t[/tex]
We also know the relationship between tangential velocity, v, and the angular velocity v:
[tex]v=\omega r[/tex]
with r being the radius of the wheel. Substituting [tex]\omega[/tex] into the previous equation, we can write an expression for v:
[tex]v(\delta \theta )= \alpha r \Delta t [/tex]
The expression for the velocity of a rider on the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex] is given by:
[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]
To find the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex], we can use kinematic equations for rotational motion.
The kinematic equation relating angular displacement [tex](\( \delta \theta \))[/tex], initial angular velocity [tex](\( \omega_0 \))[/tex], angular acceleration [tex](\( \alpha \))[/tex], and time [tex](\( t \))[/tex] is:
[tex]\[ \delta \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \][/tex]
Since the Ferris wheel starts from rest, [tex]\( \omega_0 = 0 \)[/tex], so the equation simplifies to:
[tex]\[ \delta \theta = \frac{1}{2} \alpha t^2 \][/tex]
We're interested in finding the angular velocity [tex](\( \omega \))[/tex] after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex]. To find [tex]\( \omega \)[/tex], we can use the kinematic equation relating angular displacement, initial angular velocity, angular acceleration, and final angular velocity:
[tex]\[ \omega^2 = \omega_0^2 + 2 \alpha \delta \theta \][/tex]
Since [tex]\( \omega_0 = 0 \)[/tex], this equation simplifies to:
[tex]\[ \omega^2 = 2 \alpha \delta \theta \][/tex]
Taking the square root of both sides:
[tex]\[ \omega = \sqrt{2 \alpha \delta \theta} \][/tex]
This gives us the angular velocity of the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex].
However, to find the velocity of a rider at a particular point on the Ferris wheel, we need to convert this angular velocity to linear velocity. The linear velocity [tex](\( v \))[/tex] is related to the angular velocity [tex](\( \omega \))[/tex] by the equation:
[tex]\[ v = r \omega \][/tex]
Where:
- v is the linear velocity.
- r is the radius of the Ferris wheel.
So, substituting the expression for [tex]\( \omega \)[/tex] into this equation:
[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]
This is the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex].
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s.(a) find the vector position of the particle at any time t (where t is measured in seconds).
Answers
To find the vector position of the particle at any time t, use the kinematic equation r(t) = r0 + vit + 0.5at2. Plug in the values for the initial velocity and acceleration to get the position function.
Explanation:Given that at time t, the particle has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector vi = 9.00î m/s, we can find the vector position of the particle at any time t using the kinematic equations.
The position function is given by:
r(t) = r0 + vit + 0.5at2
Plugging in the values, we have:
r(t) = 0 + (9.00î m/s)(t) + 0.5(2.00ĵ m/s2)(t2)
So, the vector position of the particle at any time t is r(t) = 9.00tî + t2ĵ - t2 km.
I need help with this asap please
A water wave vibrates up and down four times each second, the distance between two successive crests is 5 meters, and the height from the lowest part to the highest part of the wave is 2 meters.
a. What is the frequency of the wave in hertz?
b. What is the period of the wave in seconds?
c. What is the speed of the wave in meters per seconds?
d. What is the amplitude of the wave in meters?
Answers
The frequency of the wave is 4 Hz, the period is 1/4 seconds, the speed is 20 m/s, and the amplitude is 2 meters.
Explanation:a. The frequency of the wave can be calculated by counting the number of complete vibrations in one second. In this case, the wave vibrates up and down four times each second, so the frequency is 4 Hz.
b. The period of the wave is the time it takes for one complete vibration. It can be calculated by taking the reciprocal of the frequency. In this case, the period is 1/4 seconds.
c. The speed of the wave can be determined by multiplying the frequency by the wavelength. Since the distance between two successive crests is 5 meters, the speed of the wave is 20 m/s.
d. The amplitude of the wave is the height from the lowest part to the highest part of the wave. In this case, the amplitude is 2 meters.
Learn more about wave here:https://brainly.com/question/32127292
#SPJ12
How much work does the electric field do in moving a proton from a point with a potential of +125 v to a point where it is -55 v? express your answer both in joules and electron volts?
Answers
The work done by the electric field in moving a proton from +125V to -55V is -expressed as -180 electron volts (eV).
Using the relationship between work (W), charge (q), and electric potential difference (V).
The charge of a proton is +1.602 × 10^-19 coulombs (elementary charge, e), and the potential difference
V is the final potential minus the initial potential.
So, we compute the potential difference first:
V = V_final - V_initial = (-55V) - (+125V) = -180V
Then, we calculate the work done:
W = q
V = (1.602
10^-19 C)
(-180 V) = -2.8836
10^-17 joules
The negative sign indicates that the electric field is doing work against the electric potential. To express the work in electron volts, remember that 1 eV = 1.602
10^-19 joules:
W (in eV) = W (in joules) / (1.602
10^-19 joules/eV)
= (-2.8836
10^-17 joules) / (1.602
10^-19 joules/eV) = -180 eV
The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the table (as shown). the winner of the competition wants to know if he has broken the world record for the break shot of 32 mph (about 14.3 m/s). if the winner\'s ball landed a distance 4.65 m from the table edge, calculate his break shot speed.
Answers
y = gt²/2
0.810 m = (9.81 m/s²)(t)²/2
t = 0.4064 s
whereas the horizontal motion is computed by:
x = (vx)t
4.65 m = (vx)(0.4064 s)
4.65 m/ 0.4064s = (vx)
(vx) = 11.44 m / s
So look for the final vertical speed.
(vy) = gt
(vy) = (9.81 m/s²)(0.4064 s)
(vy) = 3.99 m/s
speed with which it hit the ground:
v = sqrt[(vx)² + (vy)²]
v = sqrt[(11.44 m/s)² + (3.99 m/s)²]
v = 12.12 m / s
what are the inner planets relative distance from the Sun
Answers
There are two types of planets as classifieds by astronomers in our solar system.
The classification is based on the asteroid belt present in our solar system.
These are named as - [1] inner planets
[2]outer planets
The inner planets are the planets which are very close to the sun and present before the asteroid belt starting from sun.
The outer planets which are present after the asteroid belt are Jupiter,Uranus,Neptune and Pluto[if we consider Pluto as a planet]
There are four planets considered as inner planets. These are arranged from closest to the farthest as Mercury,Venus,Earth ad Mars.
The distance of Mercury from the sun is 57.91 million km
The distance of Venus from sun is 108.2 million km
The distance of Earth from sun is 149.6 million km
Finally the distance of Mars from the sun is 227.9 million km
Which type of simple machine is pictured here?
1. wedge
2. inclined plane
3. lever
4. wheel and axel
THANK YOU I NEED THIS DONE BY 10:30 2/23/2018
Answers
Answer: This thing is a lever
Explanation: There isn't a picture, but I took the K12 class, so yeah
The simple machine with a rod fixed to the center of a wheel is a wheel and axle, which is a type of lever used to multiply applied force.
Explanation:The simple machine pictured that consists of a rod fixed to the center of a wheel is known as a wheel and axle. This device is actually a form of lever where the force applied to the wheel results in a greater force being applied to the axle. It exemplifies how simple machines can be used to multiply or augment a force that we apply. The mechanical advantage is calculated by dividing the radius of the wheel by the radius of the axle.
A large jet flying overhead is low enough so that a man on the ground can hear its engines. The man sees the jet before he hears the engines because
Answers
A uniform rod XY of weight 10.0N is freely hinged to a wall at X. It is held horizontal by a force F acting from Y at an angle 30° to the horizontal, as shown.
What is the value of F?
A- 5.0 N B- 8.7cm C- 10.0cm D-20.0cm
Answers
The use of air bags in cars reduces the force of impact by a factor of 110.(The resulting force is only as great.) What can be said about how the airbag changed the duration of the collision?
Answers
[tex]\Delta p = F \Delta t[/tex]
[tex]\Delta p [/tex] does not change whether the car has an airbag or not, because
[tex]\Delta p = m\Delta v[/tex]
and 1) the mass of the car is always the same 2) the change in velocity of the car is always the same,
so if [tex]\Delta p[/tex] is constant and F is reduced by a factor 110, then [tex]\Delta t[/tex] (the duration of the collision) must be increased by a factor 110 with the airbag.
the answer is C. it increases by a factor of 110, i got 100 on the test
Which phrase best describes matter? A. Matter is made of atoms and is too small to see. B. Matter is solid and heavy. C. Matter has mass and takes up space. D. Matter has volume and takes up space.
Answers
Hopes it helped you.
-Charlie
Rank the following from smallest current to largest current.
A 1200W microwave connected to 110V outlet.
I=P/U=1200/110=10.9 A
A 1500W water heater connected to 220V outlet.
I=P/U=1500/220=6.8 A
A 100W light bulb connected to 110V outlet.
I=P/U=100/110=0.9 A
A 2000W oven connected to a 220V outlet.
I=P/U=2000/220=9.1 A
A 40W Light bulb connected to a 12V battery.
I=P/U=40/12=3.3 A
Answers
I=P/U=1200/110=0.9 A
A 40W Light bulb connected to a 12V battery.
I=P/U=40/12=3.3 A
A 1500W water heater connected to 220V outlet.
I=P/U=1500/220=6.8 A
A 2000W oven connected to a 220V outlet.
I=P/U=2000/220=9.1 A
A 1200W microwave connected to 110V outlet.
I=P/U=1200/110=10.9 A
In short, it's:
0.9 A
3.3 A
6.8 A
9.1 A
10.9 A
Explanation:
The power of an electrical appliance is given by :
[tex]P=V\times I[/tex]
Where
V is the voltage source
I is the current flowing in the circuit
1. For 1200 W microwave, Current, I = 10.9 A
2. For 1500 W water heater, Current, I = 6.8 A
3. For 100 W light bulb, Current, I = 0.9 A
4. For 2000 W oven, Current, I = 9.1 A
5. For 40 W light bulb, Current, I = 3.3 A
Out of the above five appliances, the largest current is flowing in microwave and the smallest current is flowing in the light bulb.
So, the sequence from smallest current to the largest current is :
100 W light bulb ( 0.9 A) < 40 W light bulb (3.3 A) < 1500 W water heater (6.8 A) < 2000 W oven (9.1 A) < 1200 W microwave (10.9 A)
A 616 g block is released from rest at height h0 above a vertical spring with spring constant k = 540 n/m and negligible mass. the block sticks to the spring and momentarily stops after compressing the spring 23.3 cm. how much work is done (a) by the block on the spring and (b) by the spring on the block? (c) what is the value of h0? (d) if the block were released from height 2h0 above the spring, what would be the maximum compression of the spring?
Answers
Read more on Brainly.com - https://brainly.com/question/1581851#readmore
Determine which heat transfers below are due to the process of conduction. I) You walk barefoot on the hot street and it burns your toes. II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned. III) A flame heats the air inside a hot air balloon and the balloon rises. IV) A boy sits to the side of a campfire. He is 10 feet away, but still feels warm.
Answers
Answer:
I) You walk barefoot on the hot street and it burns your toes.
II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.
Explanation:
In conduction mode of heat transfer we know that the energy is transferred from one system to other system due to direct contact of two bodies
Here due to this direct contact the energy is transferred via a given solid or liquid medium
In this type of heat transfer medium particles will remain in its own position only the energy is transferred.
So here we can say the correct answer will be
I) You walk barefoot on the hot street and it burns your toes.
II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.