The pressure of 9.0 L of an ideal gas in a flexible container is decreased to one-eighth of its original pressure, and its absolute temperature is decreased to one-ninth of the original. What is the final volume of the gas

Answer:

Explanation:

A Brönsted-Lowry acid is defined as any substance that has the ability to lose, or "donate a proton" [H +].

A Brönsted-Lowry base is a substance capable of gaining or "accepting a proton" [H +].

Then a proton transfer occurs, which requires the presence of a proton donor, that is, an acid and a base that accepts them.

This theory has the disadvantage of leaving out several substances that are acidic and that do not have protons.

Thiocyanic acid is a chemical compound that can be considered, but not a Bronsted Lowry base, giving up the proton and generating the anion [SCN] -

Answer:

It can be a bronsted Lowry acid but not a bronsted Lowry base

Explanation:

Bronsted Lowry acid are proton donors, and HSCN can donate a proton, but it cannot accept a proton, hence not a bronsted Lowry base

Answer:

he can bang metal pipes but i would rather say that he has to yell for help

Explanation:

why because the basement is very loud and echo so when is parents hear him they can run to basement and get him out

hope this helped

The specific characteristic of the metal is to emit a resonant sound when banged. Metals are sonorous, so, banging on the metal pipes can help Jonathan to let his parents know his condition, i.e., option B.

Metals are materials that are lustrous, ductile, good conductors of heat and electricity, and malleable.

Other properties include the state of metals which are solids at room temperature except mercury and gallium, which is liquid at room temperature.

The property of sonority of metals can help Jonathan to let his parents know his condition.

Thus, the correct answer is B.

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Answer:

P(Ar) = 27 Kpa

Explanation:

Given data:

Total pressure of tire = 150.0 Kpa

Partial pressure of O₂ = 43.5 Kpa

Partial pressure of Ar  = ?

Partial pressure of N₂ = 79.5 kPA

Solution:

According to Dalton law of partial pressure,

The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.

Mathematical expression:

P(total) = P₁ + P₂ + P₃+ ............+Pₙ

Now we will solve this  problem by using this law.

P(total) = PO₂ +  PN₂ + P(Ar)

150.0 Kpa = 43.5 Kpa + 79.5 Kpa + P(Ar)

150.0 Kpa = 123 Kpa + P(Ar)

P(Ar) = 150.0 Kpa - 123 Kpa

P(Ar) = 27 Kpa

Answer:

Explanation:

Marine debris consists of most anything used and discarded by humans. Winds, rivers and storms can carry this debris to the ocean from far inland, so it is not solely a case of pollution along shorelines. It is also true that oceangoing ships directly contribute to marine debris while they are at sea and not associated with any particular nation.

Answer:

Explanation:

[OH⁻] = 1.07  x 10⁻¹⁰

[H⁺] x [ OH⁻ ] = 10⁻¹⁴

[H⁺] x 1.07  x 10⁻¹⁰ =  10⁻¹⁴

[H⁺] = 10⁻¹⁴ / 1.07  x 10⁻¹⁰

= .93458 x 10⁻⁴

= 9.3458 x 10⁻⁵

= 9.35 x 10⁻⁵

= 9.35e-5. M.

Answer:

Too much phosphorus in the water causes algae to grow faster than ecosystems can handle. Large growths of algae are called algal blooms and they can severely reduce or eliminate oxygen in the water, leading to illnesses in fish and the death of large numbers of fish.

Explanation

Futhermore, with a loss of fish the whole ecosystem will be upset and will be in need of serious recovery.

Final answer:

Phosphate acts as an environmental contaminant by promoting eutrophication, excessive growth of algae in water. It is introduced through human activities and contributes to the overgrowth of algae, leading to negative effects on the aquatic ecosystem.

Explanation:

Phosphate acts as an environmental contaminant due to its role in promoting eutrophication. Eutrophication is the excessive growth of algae in a body of water, which leads to a decrease in dissolved oxygen levels that can harm aquatic organisms. Phosphates are introduced into the environment through human activities, such as the use of phosphate-containing detergents and the leaching of phosphate from rock by weathering. These phosphates contribute to the overgrowth of algae and the subsequent negative effects on the aquatic ecosystem.a

Answer:

Radon

Explanation:

The element represented by [Rn]7s1 is francium (Fr), an alkali metal in Group 1 of the periodic table. Francium is highly reactive and extremely rare, with a short half-life.

The element represented by [Rn]7s1 is francium (Fr).

Fr is an alkali metal in Group 1 of the periodic table and has the atomic number 87. It is highly reactive and can be found in very small amounts in minerals.

Fr is the second rarest naturally occurring element and is extremely unstable, with a very short half-life.

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Answer:

5.24×10^3 L

Explanation:

Considering the volume occupied by 454.5g of H2 at 1.050 atm and 25°C.

Likewise, using ideal gas equation.

pV = nRT

Answer: The volume occupied by the gas is 5295.1 L

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of hydrogen gas = 454.5 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of hydrogen gas}=\frac{454.5g}{2g/mol}=227.25mol[/tex]

To calculate the volume, we use the equation given by ideal gas equation:

PV=nRT

where,

P = pressure of the gas = 1.050 at m

V = Volume of gas = ?

n = number of moles of gas = 227.25 moles

R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]

T = temperature of the gas = [tex]25^oC=[25+273]K=298K[/tex ]

Putting values in above equation, we get:

[tex]1.050atm\times V=227.25mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\V=\frac{227.25\times 0.0821\times 298}{1.050}=5295.1L[/tex]

Hence, the volume occupied by the gas is 5295.1 L

Answer:First: the coefficients give the number of molecules (or atoms) involved in the reaction. In the example reaction, two molecules of hydrogen react with one molecule of oxygen and produce two molecules of water. Second: the coefficients give the number of moles of each substance involved in the reaction.

Explanation: PLESE GIVE BRAINLIEST

The coefficients tells us about the number of atoms, molecules or compound present in a reaction. They are actually the numbers or terms which are used in a balanced chemical equation.

A chemical equation in which amount of reactants and products on both sides of the equation are equal is defined as the balanced chemical equation. The number of atoms of reactants and products on both sides will be equal.

The coefficients are the numbers which are added in front of the chemical formulae or symbol in order to balance the chemical equation. Only by adding the coefficients a balanced equation obeys the law of conservation of mass.

An equation is balanced with the help of coefficients.

For example, in the given reaction:

2H₂ + O₂ → 2H₂O

The coefficients of H₂,O₂ and H₂O are 2, 1 and 2.

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Answer:

c

Explanation:

Answer:

Percent yield = 50%

Explanation:

Given data:

Mass of CH₄ = 16 g

Mass of O₂ = 32 g

Mass of CO₂ = 11 g

Percent yield of CO₂ = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →  CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/ molar mass

Number of moles = 16 g /16 g/mol

Number of moles = 1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 32 g /32 g/mol

Number of moles = 1 mol

Now we will compare the moles of CO₂ with both reactant.

                             O₂             :            CO₂

                              2              :               1

                              1               :          1/2×1= 0.5 mol

                          CH₄              :            CO₂

                             1               :               1

Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.

Theoretical yield:

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.5 mol × 44 g/mol

Mass = 22 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 11 g/ 22 g × 100

Percent yield = 50%

Answer:

6.56%

Explanation:

mass of solute = 22.8 g

mass of solution = mass (solute) + mass (water) = 22.8 + 325 = 347.8 g

% by mass = [mass(solute)/ mass(solution)]*100% =(22.8/347.8)*100% = 6.56%

Answer: The number of moles of calcium carbonate is 0.637 moles

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

We are given:

Given mass of calcium carbonate = 63.8 g

Molar mass of calcium carbonate = 100.09 g/mol

Putting values in above equation, we get:

[tex]\text{Number of moles of calcium carbonate}=\frac{63.8g}{100.09g/mol}\\\\\text{Number of moles of calcium carbonate}=0.637mol[/tex]

Hence, the number of moles of calcium carbonate is 0.637 moles

Answer:

0.24 g/mL

Explanation:

The density of an object is given by the ratio between its mass and its volume:

[tex]\rho=\frac{m}{V}[/tex]

where

m is the mass of the object

V is its density

In this problem, we have:

m = 7.0 g is the mass of the object

The volume of an irregular shaped object can be measured by putting it into water, and by measuring the difference in water volume.

In this case,

[tex]V_1=25 mL[/tex] is the initial volume of water

[tex]V_2=54 mL[/tex] is the final volume of water

So the volume of the object is

[tex]V=V_2-V_1=54-25=29 mL[/tex]

Therefore, the density of the object is:

[tex]\rho = \frac{7.0 g}{29 mL}=0.24 g/mL[/tex]

Final answer:

To find the density of an irregular shaped object submerged in water, the volume displaced by the object is calculated first, and then the density is found by dividing the mass of the object by the displaced volume. In this case, the density is 0.241 g/mL.

Explanation:

When an irregular shaped object is placed in a graduated cylinder with a starting volume of 25 mL of water and causes the water level to rise to 54.0 mL upon submersion, the object displaces a volume of water equal to the difference in these measurements. To calculate the density of the object, you have to use the formula for density, which is mass divided by volume. Given that the mass of the object is 7.0 grams and the volume displacement is 54.0 mL - 25 mL = 29.0 mL, the density of the object can be found using these values.

The calculation would be as follows: Density = Mass / Volume = 7.0 grams / 29.0 mL = 0.241 g/mL.

Therefore, the density of the object is 0.241 g/mL, indicating how compact the object's mass is within its volume.

Answer:

5C + 6O₂ → 5CO + 7/2 O₂

Explanation:

According to the question the reaction is between carbon and oxygen molecule . The reactant side was given as 5 moles of carbon reacting with 6 moles of oxygen molecules.   The chemical reaction between carbon and excess oxygen will form carbon dioxide but with limited oxygen it will form carbon monoxide.  

Now let us write and balance the actual chemical equation as required from the question. In limited oxygen the reaction will be

The reactant said 5 moles of carbon which is 5 atoms of carbon reacting with 12 atoms of oxygen.  The number of atoms of element on both sides of the chemical equation need to be balance . The balanced equation when oxygen is limited is written as

5C + 6O₂ → 5CO + 7/2 O₂

The product will be 5 moles of carbon monoxide and 3.5 moles of oxygen molecules(7 atoms) since the oxygen is limited . The carbon monoxide later reacts with more oxygen to form carbon dioxide.

Limiting reactant is the reactant that stops the reaction when it is completely consumed.  The product of the given reaction is Carbon dioxide.

Balanced Reaction:

A reaction in which the number of moles of atoms in reactants is equal to the number of moles of the atoms in the product.

The given reaction,

[tex]\bold{5C + 6O_2 \rightarrow 5CO_2 \\\\}[/tex]

Therefore, the product of the given reaction is Carbon dioxide.

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Answer:

It is not possible, since the total weight of all the reagents involved in the reaction is equal to the total weight of the product, since it is not possible to create or destroy atoms, thus, it is not possible to change the weight of the product. It is equal to the weight of the reagent.

Explanation:

Answer:

I don't understand

Explanation:

Sorry

Answer:

Butanol

Explanation:

By counting, we know this is C4H9OH

C4H9OH is Butanol

Answer:

52 atm

Explanation:

25 + 12 + 15 = 52 atm

- Please let me know you agree with this or if it is right or wrong. If wrong, I will fix it.

Answer:

THE CORRECT ANSWER TO THE QUESTION ABOVE IS " UREA"

Explanation:

SOLUTE is defined as solid, liquid, or gas that is dissolved in a solution.

URINE is a by-product of metabolism that is produced by the kidneys in their process of blood purification. URINE contains of water, urea, chloride, sodium, potassium, dissolved ions, and inorganic and organic compounds.

Physical characteristics of URINE include color, smell, pH, density and turbidity.

UREA (also known as carbamide) is a non-toxic molecule, it is made up of ammonia and carbon and is the major organic component of human urine. UREA in urine is 9.3 g/L.

Answer:

78 mmHg is the partial pressure of the nitrogen.

Explanation:

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

[tex]P=p_{1}+p_{2}+p_{3}[/tex]

where,

[tex]P[/tex] = total pressure of the gas mixture = 456 mmHg

[tex]p_{1}[/tex] = partial pressure of hydrogen gas = 230 mmHg

[tex]p_{2}[/tex] = partial pressure of oxygen gas = 148 mmHg

[tex]p_{3}[/tex] = partial pressure of nitrogen gas = ?

Now put all the given values is expression, we get the partial pressure of the nitrogen gas i.e.  [tex]p_3[/tex] .

[tex]456 mmHg=230 mmHg+148 mmHg+p_3[/tex]

[tex]p_3=456 mmHg-230 mmHg-148 mmHg=78 mmHg[/tex]

78 mmHg is the partial pressure of the nitrogen.

Answer:

22.7%

Explanation:

We must first put down the equation of reaction to guide our work while solving the problem.

KCN(aq) + HCl (aq)--> KCl(aq) + HCN(aq)

The questions specifically state that HCl is in excess so KCN is the limiting reactant.

Number of moles of KCN reacted= mass of KCN reacted / molar mass of KCN

Mass of KCN reacted= 3.2 g

Molar mass of KCN= 65.12 g/mol

Number of moles of KCN= 3.2/65.12 g/mol= 0.049 moles

Theoretical yield of HCN is obtained thus;

From the reaction equation;

1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.

Mass of HCN = number of moles ×molar mass

Molar mass of HCN= 27.0253 g/mol

Hence mass of HCN produced= 0.049mol × 27.0253 g/mol= 1.32g of HCN

Actual yield of HCN= 0.30g

% yield= actual yield/ theoretical yield ×100

% yield= 0.30/1.32 ×100

%yield= 22.7%

Answer:

The theoretical yield HCN is 1.33 grams

The percent yield HCN is 22.56 %

Explanation:

Step 1: Data given

Mass of KCN = 3.2 grams

Molar mass KCN = 65.12 g/mol

Mass of HCN produced = 0.30 grams

Step 2: The balanced equation

KCN + HCl --> KCl + HCN

Step 3: Calculate moles KCN

Moles KCN = mass KCN / moalr mass KCN

Moles KCN = 3.2 grams / 65.12 g/mol

Moles KCN = 0.0491 moles

Step 4: Calculate moles HCN

For 1 mol KCN we need 1 mol HCl to produce 1 mol KCl and 1 mol HCN

For 0.0491 moles HCN we'll have 0.0491 moles HCN

Step 5: Calculate mass HCN

Mass HCN = moles HCN * molar mass HCN

Mass HCN = 0.0491 moles * 27.03 g/mol

Mass HCN = 1.33 grams = the theoretical yield

Step 6: Calculate the percent yield HCN

Percent yield = (actual yiel / theoretical yield) * 100 %

Percent yield = (0.30 grams / 1.33 grams)

Percent yield = 22.56 %

Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

Explanation:

First we have to calculate the moles of diethyl ether

[tex]\text{Moles of diethyl ether}=\frac{\text{Mass of diethyl ether}}{\text{Molar mass of diethyl ether}}=\frac{75.0g}{74g/mole}=1.01moles[/tex]

As, 1 mole of diethyl ether require heat = 26.5 kJ

So, 1.01  moles of diethyl ether require heat = [tex]\frac{26.5}{1}\times 1.01=26.8kJ[/tex]

Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

The energy i.e. needed is 26.8 kJ of energy

the moles of diethyl ether is

[tex]= 75.0 g \div 74\\\\[/tex]

= 1.01 moles

Since one  mole of diethyl ether require heat = 26.8 kJ

Now the energy should be the same i.e. 26.8

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Answer:

ATCCGAT

Explanation:

A always matches with T

G always matches with C

Answer: The molarity of solution is 2 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute = 1.4

[tex]V_s[/tex] = Volume of solution in ml = 700 ml

Now put all the given values in the formula of molality, we get

[tex]Molality=\frac{1.4\times 1000}{700}=2mole/L[/tex]

Therefore, the molarity of solution is 2 M

Answer:

Approximately [tex]\rm 31.5\; g[/tex].

Explanation:

The mass of a solution can be divided into two parts:

In this particular [tex]\rm KOH[/tex] solution in water,

The number [tex]35\%[/tex] here likely refers to the concentration of [tex]\rm KOH[/tex] in this solution. That's ratio between the mass of the solute ([tex]\rm KOH[/tex]) and the mass of the whole solution (mass of solute plus mass of solvent.) That is:

[tex]\displaystyle \frac{m(\text{KOH})}{m(\text{solution})} = 35\% = 0.35[/tex].

Hence, [tex]m(\mathrm{KOH}) = 0.35\, m(\text{solution})[/tex].

However, since the solution contains only the solute and the solvent, [tex]m(\text{solution}) = m(\text{solute}) + m(\text{solvent})[/tex].

For this solution in particular,

[tex]\begin{aligned}&m(\text{solution})\\&= m(\text{solute}) + m(\text{solvent}) \\ &= m(\text{KOH}) + m(\text{water})\end{aligned}[/tex].

As a result,

[tex]\begin{aligned}&m(\mathrm{KOH})\\ &= 0.35\, m(\text{solution}) \\&= 0.35\, (m(\mathrm{KOH}) + m(\text{water}))\\&= 0.35\, m(\mathrm{KOH}) + 0.35 \, m(\text{water})\end{aligned}[/tex].

Subtract [tex]0.35\, m(\mathrm{KOH})[/tex] from both sides of the equation:

[tex](1 - 0.35)\, m(\mathrm{KOH}) = 0.35\, m(\text{water})[/tex].

[tex]\begin{aligned} &m(\mathrm{KOH}) \\ &= \left(\frac{0.35}{1 - 0.35}\right)\cdot m(\text{water}) \\ &= \frac{0.35}{0.65} \times 58.5\; \text{g} = 31.5 \; \text{g}\end{aligned}[/tex].

Note, that for this calculation, there's nothing special about this [tex]35\%[/tex] solution of [tex]\mathrm{KOH}[/tex] in water. In general,

[tex]\displaystyle m(\text{solute}) = \left(\frac{\%\text{concentration}}{100\% - \%\text{concentration}}\right)\cdot m(\text{solvent})[/tex].

Answer:

d. stimulus generalization

Explanation:

Stimulus generalization consists of the appearance of the unconditional response to conditioned stimuli that had never been paired with it but that have a similarity to it.

Answer:

There are three main measures of central tendency: the mode(the number that occurs most often) the median ( the middle value in the list of numbers) and the mean (the average number in the list of numbers)

Explanation:

I learned this

Answer:

The amount (mass) of water we will have is 17.869 grams

Explanation:

The molar mass of hydrogen gas H₂ = 2.016 grams/mole

The molar mass of oxygen gas = 31.999 g/mol

Therefore, 2.00 g of hydrogen will give;

2.00/2.016 = 0.9921 moles of H₂ gas and

15.87 g of O₂ will give;

15.87/31.999 = 0.49595 moles

The reaction is as follows;

2H₂ (g) + O₂ (g) → 2H₂O (l)

Two moles of H₂ react with one mole of O₂ to produce two moles of H₂O

Therefore 0.9921 moles of H₂ will react with 0.9921/2 or 0.49595 moles of O₂ to produce 0.9921 moles of H₂O

From the above we note that all the H₂ and O₂ are completely consumed to form 0.9921 moles of H₂O

Molar mass of H₂O = 18.01528 g/mol

Number of moles = Mass/(Molar mass)

∴ Mass of H₂O = (Molar mass) × (Number of moles)

= 18.01528 g/mol × 0.9921 moles = 17.869 grams

Therefore the amount (mass) of water we will have = 17.869 grams.

Answer:

308.15

Explanation:

To convert 35 degrees Celsius to Kelvin, you add 273.15, resulting in 308.15 Kelvin.

This conversion is straightforward because the size of one Kelvin is the same as one degree Celsius.

For instance, to find the Kelvin equivalent of 35 degrees Celsius, you would calculate as follows: