The simplest form of square root of eighty can be written as a times square root of b, where a = and b = .

Answers

Answer 1

The correct answer is:

A=4

B=5

hopes this helps you and future people!

Answer 2

Answer:

a = 4 and b = 5

Step-by-step explanation:

The simplest form of square root of eighty can be written as:

[tex]\sqrt{80}=\sqrt{2\times2\times2\times2\times5}[/tex]

Now as it is a square root function, we will pair up the four 2's in two pairs.

And will take out [tex]2\times2[/tex] outside the square root.

Making the answer = [tex]2\times2\sqrt{5}[/tex]

or [tex]4\sqrt{5}[/tex]

So, a = 4

and b = 5


Related Questions

Who worthy the book “I love fractions”

Answers

I’m guessing we’ll the whole main thing is about Fractions isn’t it?

Answer for number 5?

Answers

Length = 60; Width = 36

The formula for Perimeter is P = 2L + 2W
Where L = length; W = width

192 = 2L + 2W
       = 2(5x) + 2(3x)
       = 10x + 6x
       = 16x
192/16 = 16x/16
         x = 12

Substitute the values:
192 = 2(5x) + 2(3x)
       = 2(5*12) + 2(3*12)
       = 2(60) + 2(36)
192 = 192

The half-life of iodine-123 is about 13 hours. You begin with 52 grams of iodine-123. (a) Write an equation that gives the amount of iodine-123, I , remaining after t hours. Write your answer in the form I ( t ) = a ⋅ b t . Round your answer for b to three decimal places.

Answers

Final answer:

The amount of iodine-123 remaining after t hours can be expressed as I(t) = 52 · 0.945^t, where the constant 0.945 is calculated using the half-life of 13 hours.

Explanation:

The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms to decay. For iodine-123, which has a half-life of approximately 13 hours, we can use an exponential decay model to express the amount of iodine-123 remaining after t hours.

The decay formula is generally given by I(t) = I0e-kt, where I0 is the initial amount, k is the decay constant, and t is time. However, the question asks us to express the equation in the form of I(t) = a · bt, which is another common representation for exponential decay.

To find the value of b, we know that after one half-life, b13 = 1/2. Thus, b = (1/2)1/13.
Let's calculate b: b = (0.5)1/13 ≈ 0.945 (rounded to three decimal places).

Since we start with 52 grams of iodine-123, our initial amount (a) is 52. Therefore, the equation for the amount of iodine-123 remaining after t hours is:

I(t) = 52 · 0.945t

Final answer:

The equation to calculate the amount of iodine-123 remaining after t hours is I(t) = a * b^t, where a is the initial amount of iodine-123, b is the decay constant, and t is the time in hours. The decay constant can be calculated using the formula b = 0.693 / t1/2, where t1/2 is the half-life of iodine-123. In this case, the half-life is 13 hours.

Explanation:

The equation that gives the amount of iodine-123 remaining after t hours can be written as:

I(t) = a * b^t

Where:

I(t) is the amount of iodine-123 remaining after t hoursa is the initial amount of iodine-123b is the decay constant, which can be calculated using the half-life formulat is the time in hours

To calculate the decay constant b, we can use the formula:

b = 0.693 / t1/2

where t1/2 is the half-life of iodine-123. In this case, the half-life is 13 hours, so:

b = 0.693 / 13 = 0.053

Therefore, the equation becomes:

I(t) = a * 0.053^t

Round the value of b to three decimal places, so b = 0.053.

The band is selling wrapping paper for a fundraiser. Customers can buy rolls of plain wrapping paper and rolls of shiny wrapping paper. The band sold a total of 55 rolls and made $950. If a roll of plain wrapping paper cost $14 and a roll of shiny cost $20, how many rolls of each did they sell ?

Answers

x= # plain rolls
y= # shiny rolls

QUANTITY EQUATION:
x+y=55

COST EQUATION:
$14x + $20y= $950

SOLVE:
Solve for one variable in quantity equation. Substitute that answer in cost equation.

STEP 1:
x+y=55
subtract y from both sides
x= 55-y

STEP 2:
$14x + $20y= $950
14(55-y) + 20y= 950

multiply 14 by all in parentheses
(14*55)+(14*-y) + 20y= 950
770-14y+20y= 950

combine like terms
770+6y= 950

subtract 770 from both sides
6y= 180

divide both sides by 6
y= 30 shiny rolls

STEP 3:
Substitute y answer in either equation to solve for x.

x+y=55
x+30=55
subtract 30 from both sides
x= 25 plain rolls

Hope this helps! :)

The roll of plain wrapping paper sold is  25.

The  roll of shiny wrapping paper sold is 30.

What are the linear equations that represent the question?

a + b = 55 equation 1

14a + 20b = 950 equation 2

Where:

a =  roll of plain wrapping paper sold

b = roll of shiny wrapping paper sold

What is the roll of shiny wrapping paper sold?

Multiply equation 1 by 14

14a + 14b = 770 equation 3

Subtreact equation 3 from equation 2

6b = 180

Divide both sides by 6

b  = 30

What is the roll of plain wrapping paper sold?

Subtract 30 from 55

55 - 33 = 25

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Using radicals , write an equivalent expression for the expression 2 1/3

Answers

I'm assuming that the 1/3 is an exponent.

If so, then [tex]2^{1/3} = \sqrt[3]{2}[/tex]

Which is the cube root of 2. Raising any value to the 1/3 power is the same as taking the cube root.

I'm assuming that the 1/3 is an exponent.

If so, then  

Which is the cube root of 2. Raising any value to the 1/3 power is the same as taking the cube root.

Michelle and Andrea are walking laps for charity. The amount of money, y, that each girl raises for a certain number of laps, x, is shown in the tables below. Michelle mc020-1.jpg Andrea mc020-2.jpg Which statement explains who will raise $100 with the fewest number of laps? Michelle will, because the slope of the line described by the data in her table is the greatest. Andrea will, because the slope of the line described by the data in her table is the greatest. Michelle will, because her number of laps are increasing at a faster rate. Andrea will, because her number of laps are increasing at a slower rate

Answers

A. Michelle will, because the slope of the line described by the data in her table is the greatest. 
Michelle's graph has a slope of 3/2 which equals 1.5
Andrea's graph has a slope of 5/4 which equals 1.25

Hope this helps ;)

Answer:

The answer would be a im sure

Step-by-step explanation:

If a triangle is an obtuse triangle then it can not be an isosceles triangle.
a. True
b. False

Answers

If a triangle is an obtuse triangle then it can not be an isosceles triangle. 

FALSE

CB = AC

If three tangents to a circle form an equilateral triangle, prove that the tangent points form an equilateral triangle inscribed in the circle

Answers

I added a figure so you can guide yourself throughout the proof I'm about to write, so I recommend that you download the picture beforehand and have this window and the picture's window open. Alright, let's get started!
Assuming that [tex]FED[/tex] is an equilateral triangle according to the wording of the problem, we have that the angles [tex]\widehat{AFB}=\widehat{BEC}=\widehat{CDA}=60[/tex].
We also know that the circle in green is Inscribed in [tex]FED[/tex].

The following applies to every inscribed circle inside a triangle:
The center of the inscribed circle of a triangle is the intercept of all three angle bisectors of the triangle.

The above theorem implies that the line [tex](FO) [/tex] is an angle bisector because it goes through the vertex F and the center of the inscribed circle.

The previous statement implies that the angle [tex]\widehat{OFB}=30[/tex].

Now let's work on the [tex]OFB[/tex] triangle.
Knowing that [tex]\widehat{OBF}=90[/tex] (because [tex](EF)[/tex] is tangent to the circle at B and [tex]OB[/tex] is a radius of the circle. If you're lost here, remember that a tangent to a circle is always perpendicular to the radius of the circle.) we can then derive that [tex]\widehat{FOB}=180-90-30=60[/tex] (because the sum of the measures of all angles in a triangle is always equal to 180 degrees).

In the same way, we can prove also that:
[tex]\widehat{BOE}=\widehat{EOC}=\widehat{COD}=\widehat{DOA}=\widehat{AOF}=60 degrees[/tex].
Knowing the above we notice that [tex]\widehat{BOC}=\widehat{COA}=\widehat{AOB}=120degrees[/tex].

We're at the last part of our proof here:
Now notice that [tex]\widehat{BOA}[/tex] subtends the same arc on the circle  that [tex]\widehat{BCA}[/tex].
According to the inscribed angle theorem, an angle [tex]\theta[/tex] inscribed in a circle is half of the central angle [tex]2\theta[/tex] that subtends the same arc on the circle. 
Therefore [tex]\widehat{BCA}=\frac{\widehat{BOA}}{2}=60degrees[/tex]

We can prove in a similar fashion that:  [tex]\widehat{CAB}=\widehat{ABC}=60degrees[/tex] 
Therefore all the angles of the [tex]ABC[/tex] triangle have a measure of 60 degrees, we conclude then that  [tex]ABC[/tex] is equilateral.


What is the true solution to 3 in 2 + in 8 = 2 in(4x)
a. x=1
b. x=2
c. x=4
d. x=8

Answers

divide by two

ln is base e. both sides of the equation are base e so the parts inside the parentheses are equal

x=2

The true solution to [tex]3 log 2+log8 =2log(4x)[/tex] is [tex]x=2[/tex]. The correct option is b. [tex]x=2[/tex].

Given expression is

[tex]3 \log 2+\log8 =2\log(4x)[/tex].

We have to calculate the value of [tex]x.[/tex]

Properties of logarithm:

We know that,  

[tex]n \log m= \log(m)^n[/tex]

and

[tex]\log m + \log n = \log(mn)[/tex]

Solving the equation:

[tex]3 \log 2+\log8 =2\log(4x)[/tex][tex]\log(2)^3+\log8 =\log(4x)^2[/tex]

{using [tex]n \log m= \log (m)^n[/tex]}

[tex]\log8+\log 8= \log 16x^2[/tex]

[tex]\log (8 \times8)=\log16x^2[/tex] {using [tex]log m + log n = log(mn)[/tex]}

Since log is on both sides so it is eliminated from both sides,

[tex]8 \times8=16x^2\\64=16x^2\\[/tex]

[tex]x^{2} =\frac{64}{16}\\x^{2}=4\\x=2[/tex]

Hence the true solution to [tex]3 log 2+log8 =2log(4x)[/tex] is [tex]x=2[/tex].

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Which three lengths CANNOT be the lengths of the sides of a triangle?
Question 2 options:

A. 21 m, 6 m, 10 m

B. 11 m, 11 m, 12 m

C. 23 m, 17 m, 14 m

D. 5 m, 7 m, 8 m

Answers

The set of sides that cannot be the sides of a triangle is set A. 
The sum of two sides of a triangle must be longer than the third side, but 6 + 10 is less than 21, so it cannot be a triangle.

Hope this helps =)

Select all that have a value of 0.  

Answers

Answer:

It's 1,3, and 5.

The functions that have  a value of 0 are : [tex]cos(\frac{\pi}{2} ),~sin(0),~tan(\pi)[/tex]

What is function?"It defines a relation between input and output values.""In function for each input there is exactly one output."

For given question,

We have been given some trigonometric functions.

We need to find the functions that have a value zero.

[tex]i)~cos(\frac{\pi}{2} )=0\\\\ii)~cos(0)=1\\\\iii)~sin(0)=0\\\\iv)sin(\frac{3\pi}{2} )=-1\\\\v)tan(\pi)=0[/tex]

From above, we can observe that functions [tex]cos(\frac{\pi}{2} ),sin(0)[/tex] and [tex]tan(\pi)[/tex] have a value of zero.

Therefore, the functions that have  a value of 0 are : [tex]cos(\frac{\pi}{2} ),~sin(0),~tan(\pi)[/tex]

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An initial investment of $200 is now valued at $350. The annual interest rate is 8% compounded continuously. The equation mc022-1.jpg represents the situation, where t is the number of years the money has been invested. About how long has the money been invested? Use a calculator and round your answer to the nearest whole number.

Answers

Answer:

7 years

Step-by-step explanation:

An initial investment of $200 is now valued at $350.

The annual interest rate is 8% compounded continuously.

Formula:

[tex]A=Pe^{rt}[/tex]

Where,

A is amount, A=350

P is principle, P=200

R is rate of interest, r=0.08

t is time, t=?

Substitute the value into formula

[tex]350=200e^{0.08\cdot t}[/tex]

[tex]e^{0.8t}=1.75[/tex]

Taking ln both sides

[tex]0.08t = ln(1.75)[/tex]

[tex]t=6.99\approx 7[/tex]

Hence, 7 years ago money was invested.

Answer:

Its 7 years

Step-by-step explanation:

Find two consecutive even integers such that the smaller added to threetimes the larger gives a sum of 30.

Answers

x+3(x+2)=30
x+3x+6=30
4x=24
x=6
x+2=8

The numbers should be 6 and 8.

The two consecutive even integers that satisfy the given condition are 6 and 8. When the smaller one (6) is added to three times the larger one (8), the sum is 30.

The student has asked for help in finding two consecutive even integers such that the smaller added to three times the larger gives a sum of 30. To solve this, let's designate the smaller even integer as x. Since the numbers are consecutive even integers, the next integer will be x + 2.

The equation based on the problem statement will look like this:

x + 3(x + 2) = 30

Expanding the equation gives:

x + 3x + 6 = 30

Combining like terms:

4x + 6 = 30

Subtracting 6 from both sides:

4x = 24

And dividing by 4:

x = 6

Now, the two consecutive even integers can be determined:

The smaller integer is 6, and the larger integer is 6 + 2, which equals 8. Therefore, the two integers are 6 and 8, and if we check:

6 + 3(8) = 6 + 24 = 30, which matches the required sum.

Seven more than half of the cost , c

Answers

It would be 3.5! Hope this helps and good luck!

A teacher reaches into a bag of game pieces containing 5 black pieces, 3 purple pieces, 1 orange piece, and 6 green pieces. He draws 2 pieces, setting aside the first piece before drawing the second. What is the probability that at least one of the drawn pieces is purple

Answers

The probability of choosing a purple piece is 3/15, choosing an orange piece will be 1/15, that of black pieces is 5/15 and that of choosing a green piece is 6/15.
This would be PP + PW+ PG + PB +WP +GP + BP
                   = (3/15 × 2/14) + (3/15×1/14)+(3/15×6/14) +(3/15+5/14)+(1/15×3/14) + (6/15× 3/14) + (5/15 × 3/14)
                     = 6/210 +3/210 +18/210+15/210+3/210 +18/210+ 15/210 
                     = 78/210
                     = 13/35

Answer:

13/35

Step-by-step explanation:

gradpoint

Consider the diagram. What is the length of segment AB?

Answers

B. 9 I think because it looks like it is bisected in the middle to cut into two equal parts. Please correct me if I am wrong. Thanks. 

we know that

A median of a triangle is a line segment joining a vertex to the midpoint of the opposing side, bisecting it.

In this problem the line DB is a median of triangle ADC

The line DB is also the altitude of a triangle ADC, because is perpendicular to the side AC

so

AB=BC

we have that

[tex]BC=9\ units[/tex]

therefore

[tex]AB=9\ units[/tex]

the answer is the option

[tex]9[/tex]


A test is worth 140 points. Ten percent of those points are from one short-answer question. How many points is the short-answer question worth?

Answers

If the total amount of points in a test is 140, and we want to find 10% of those points, we can do the following to figure out how much points the question is worth...

140 points x 10% = 140 x 0.1 = 14 points for the short-answer quesion.

The short-answer question worth of 14 points.

What is unitary Method?

The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Given:

Total points of test =140

and 10 % of those points are from one short-answer question.

So, the points for short-answer question are

=10 % of 140

=10/100 x 140

=1400/100

=14

Hence,  short-answer question worth of 14 points.

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Eric plans to rent a car for a day from Easy Car Rental. He has a coupon for 25% off the daily base rate of $40. He will also have to pay an additional $0.15 for each mile he drives. Which expression represents the situation? (m represents the number of miles)

Answers

Answer:

30 + 0.15m

Step-by-step explanation:

base rate = 40(1 − 0.25) = 40(0.75) = 30

per mile = 0.15m

thus,

30 + 0.15m

The correct expression represents the situation is,

⇒ 30 + 0.15m

What is an expression?

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

Eric plans to rent a car for a day from Easy Car Rental.

Here,  He has a coupon for 25% off the daily base rate of $40.

And,  He will also have to pay an additional $0.15 for each mile he drives.

Let m represents the number of miles.

Hence, We can formulate;

⇒ 40 (1 - 0.25) + 0.15m

⇒ 40 × 0.75 + 0.15m

⇒ 30 + 0.15m

Thus, The correct expression represents the situation is,

⇒ 30 + 0.15m

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Rene has a coupon for $3.25 off a package of name brand cookies that normally costs $7.89. The store brand cookies coats $5.58. How much will Rene save if she uses her coupon and buys the name brand cookies instead of the store brand cookies? HELP

Answers

she would save 94 cents buying the name brand cookies
Final answer:

Rene will save $0.94 if she uses her coupon and buys the name brand cookies instead of the store brand cookies.

Explanation:

To find out how much Rene will save if she uses her coupon and buys the name brand cookies instead of the store brand cookies, we have to first determine how much the name brand cookies will cost after applying the coupon. We subtract the value of the coupon i.e. $3.25 from the original cost of name brand cookies which is $7.89. The result comes out to be $4.64.

To calculate the savings, we now have to subtract the cost of name brand cookies after coupon ($4.64) from the original cost of the store brand cookies ($5.58). Hence, the savings amount to $5.58 - $4.64 which equals $0.94

So, if Rene uses her coupon and buys the name brand cookies instead of the store brand cookies, she will save $0.94.

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Solve the system of equations using the linear combination method.

{9x+5y=35
{2x+5y=0



Enter your answers in the boxes.

x =_

y =_

Answers

(5,-2)
please mark as brainliest 
hope it helps
the answer was 5, -2 thx

Find the area of the shaded portion in the square (assuming the center point of each arc is the corresponding central point of the line and the arcs intersect at the center point of the circle)

Answers

Answer:

The answer is 2. hope it helps!

Step-by-step explanation:

Answer:  The area of the shaded portion is [tex](\pi-2)~\textup{sq. units}.[/tex]

Correct option is 2.

Step-by-step explanation:  We are given to find the area of the shaded portion in the figure.

Since, the centre point of each arc is the corresponding central point of the line and the arcs intersect at the centre point of the circle,

so let us divide the figure into four equal parts, one of them is square ABCD as shown in the attached figure.

The area of the square ABCD will be

[tex]A_{ABCD}=\left(\dfrac{1}{2}\times 2\right)^2\\\\\\\Rightarrow A_{ABCD}=1~\textup{sq. units}.[/tex]

Now, area of the shaded portion inside the square ABCD will be

[tex]A_s=2\times \textup{area of the quarter circle with radius 1 unit}}-\textup{area of square ABCD}\\\\\Rightarrow A_s=2\times \left(\pi\times \left(\dfrac{1}{2}\right)^2\right)-A_{ABCD}\\\\\\\Rightarrow A_s=2\times\left(\dfrac{\pi}{4}\right)-1\\\\\\\Rightarrow A_s=\left(\dfrac{\pi}{2}-1\right)~\textup{sq. units}.[/tex]

Since all the four squares are identical in the attached figure, so the required area of the total shaded portion in the figure is

[tex]A=2\times\left(\dfrac{\pi}{2}\right)\\\\\\\Rightarrow A=(\pi-2)~\textup{sq. units}.[/tex]

Thus, the area of the shaded portion is [tex](\pi-2)~\textup{sq. units}.[/tex]

The correct option is 2.

Kathleen has been tracking how fast she walks over the last month and determined that she walks 1 1/4 miles in 2/5 of an hour. Lynn has been tracking how fast she walks over the last few weeks and determined that it takes her 19 minutes and 12 seconds to walk 1 mile. Part A: Write both Kathleen's and Lynn's walking rate in the same format, either miles per hour, miles per minute, minutes per mile, or hours per mile and compare their rates to each other. Part B: Give a logical argument on why that format was chosen over the other three.

Answers

A:


K: 24 minutes per 2 3/4 miles
L: 19.12 minutes per mile


B:


I chose minutes per mile because it was already being used for one of them so it takes less work.

Which of the following inequalities is best represented by this graph?

5x + y ≤ 2
5x + y ≥ 2
5x − y ≤ 2 
5x − y ≥ 2

Answers

For this case, the first thing to do is find the equation of the line correctly and then see which of the inequalities represents the shaded region.
 We have then:
 5x - y = 2
 For x = 0 
 5 (0) - y = 2
 -y = 2
 y = -2
 For y = 0
 5x - 0 = 2
 5x = 2
 x = 2/5 = 0.4
 Therefore the line is:
 5x - y = 2 
 Then, we see that for the point (0, 0)
 5x - y ≥ 2
 5 (0) - (0) ≥ 2
 0 ≥ 2
 The inequality is not met, which is correct because this point is not part of the shaded region.
 Answer:
 The inequality that best is represented by the graph if: 
 5x - y ≥ 2

Answer:the answer is d

Step-by-step explanation:

5x - y ≥ 2

The perimeter of an equilateral triangle with a side of 6 inches is
12 in.
18 in.
36 in.

Answers

equilateral means all sides are equal. perimeter is all sides added up. 6+6+6 = 18

negative 1 over 2x + 2 = −x + 7

Answers

Multiply by the denominator and solve the resulting quadratic.
.. -1/(2x +2) = -x +7
.. -1 = (2x +2)(-x +7)
.. 2x^2 -12x -15 = 0
And from the quadratic formula
.. x = (12 ±√((-12)^2 -4(2)(-15)))/(2(2))
.. x = 3 ±√16.5

x ≈ -1.062019 or 7.062019

Find the first six terms of the sequence.
a1 = -4, an = an-1 + 7

-4, 3, 10, 17, 24, 31
-4, 7, 14, 21, 28, 35
3, 10, 17, 24, 31, 38
0, 7, 14, 21, 28, 35

Answers

I think it is the first option

Answer: A) -4, 3, 10, 17, 24, 31

Step-by-step explanation: To solve the given problem we need to calculate the first six terms of the sequence (starting with a1):

a1=-4

a2=a1+7

a2=-4+7

a2=3

a3=a2+7

a3=3+7

a3=10

a4=a3+7

a4=10+7

a4=17

a5=a4+7

a5=17+7

a5=24

a6=a5+7

a6=24+7

a6=31.

Given: What type of angles are ∠2 and ∠3 are adjacent angles.
Which of the following options describes the adjacent angles in terms of their sum? complementary angles, 90° complementary angles, 180° supplementary angles, 90° supplementary angles, 180°

Answers

The correct answer is:  [D]:  "supplementary angles, 180° " .
_____________________________________________________
Note:  

Choices:
_____________________________________________________
   [B]:  "complementary angles, 180° " ; and:
_____________________________________________________
   [C]:  "supplementary angles, 90° "  ;  
_____________________________________________________
can automatically be ruled out ; since by definition:

     →  Complementary angles always add up to 90° — NOT 180° ; 
and:   supplementary angles always add up to 180° — NOT 90° .
_____________________________________________________
Note:  "Adjacent angles" refer to "supplementary angles" ; which, by definition add up to 180° .  Futhermore, looking at the image provided,

we see that ∠1 and ∠2 are, in fact "adjacent" and that ∠1 and ∠2 comprise the entire portion of a "straight line" (being intersected by a transversal)" ;  

  and as such;  ∠1 and ∠2 are supplementary angles—
 
  and as such—add up to 180° .

(which rules out:  Choice [A]:  "complementary angles, 90°) ; 

→  and demonstrates the correct answer:
______________________________________________________
Answer choice:  [D]:  "supplementary angles, 180° " .
 ______________________________________________________

Final answer:

Adjacent angles can be either complementary or supplementary depending on their sum. Complementary angles add up to 90°, while supplementary angles sum to 180°. The term for adjacent angles in terms of their sum is 'supplementary angles', adding up to 180°.

Explanation:

Adjacent angles are two angles that have a common side and vertex, and don't overlap. In terms of their sum, if adjacent angles add up to 90 degrees, they are called complementary angles. If they add up to 180 degrees, they are called supplementary angles. Since the question involves angles ∠2 and ∠3 as adjacent angles but does not provide their specific measures, it's not possible to definitively classify them as complementary or supplementary without additional information. However, the question asks which term describes adjacent angles in terms of their sum. The correct answer is supplementary angles, which have a sum of 180°.

Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is also 53. 6f – 1 evaluated at f = 3 is 17. what is 2f + 4f + 2 – 3 evaluated at f = 3?

Answers

we have that

the expression 2f + 4f + 2 – 3-------> we can group it   (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

let's check it
[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok

Answer: 17

Step-by-step explanation:

Bonnie wants to make a picture frame for a 5 x 8-inch photo. What is the area of the frame if the frame is 1 inch thick? square inches

Answers

Answer: 30 in^2

Explanation:

1) Measure of the picture: 5 in x 8 in

2) The frame can be splited into 4 rectangular figures:

Two of 10 in * 1 in = 2 * 10 in^2 = 20 in^2

Two of 5 in * 1 in = 2 * 5 in^2 = 10 in^2

3) The total area of the frame is 20 in^2 + 10in^2 = 30 in^2

4) You can also see that the dimensions of the picture with the frame are 10 in * 7 in, which leads to an area of 10 in * 7 in = 70 in^2.

So, if you subtract the are of the picture, you will have the are of the frame.

Area of the picture = 5 in * 8 in = 40 in^2

Area of the frame = total area - area of the picture = 70 in^2 - 40 In^2 = 30 in^2.

Which confirms the previous calculation.

The area of the frame if the frame is 1 inch thick will be 30 inch².The area of the frame is found as the product of the length and breadth of the frame.

What is the area?

The space filled by a flat form or the surface of an item is known as the area.

If the  frame is 1 inch thick then the total area is found as;

The area of the rectangular picture is;

[tex]\rm A = 5 \times 8 \\\\\rm A =40 \ inch^2 \\\\[/tex]

The total area of the frame is found as;

Area of frame = Total area -  area of the picture

Area of frame =70 -40

Area of frame = 30 inch²

To learn more about the area refer to the link;

https://brainly.com/question/11952845

#SPJ3

How do I solve and graph this?

Answers

3x -y ⩾ 6

3x - 6 ⩾ y

now, with inequalities, what we do is, we graph the line of 3x - 6 = y, and then we shade the "true region".

if we pick a point on say hmmm (4, 0), namely x = 4 and y = 0, we can plug that in the inequality and see what we get,

3(4) - 0 ⩾ 6

12 - 0 ⩾ 6

12 ⩾ 6   

is 12 really greater or equals to 6?  well yes, therefore, the point (4, 0) lies on the "true region", since it's true, 12 is indeed ⩾ 6, so, where that point is, we shade.

now, the ⩾ means equals to or greater, and therefore, since the values could also equal the boundary points, the line is a solid line, because it includes the line itself, as well as the shading.

check the picture below.
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