"The smallest insects that a bat can detect are approximately the size of one wavelength of the sound the bat makes. What is the minimum frequency of sound waves required for a bat to detect an insect that is 0.0057 m long? (assume the speed of sound is 340 m/s.)"

Answer:

The majority component is the solvent so In the air nitrogen is found more.

So Nitrogen is the solvent in air.

Answer:

Jupiter and Mars.

The asteroid belt is located between those two celestial objects.

:)

Answer:

2 The electric field strength is greatest where the equipotential lines are very close to each other.

Explanation:

Equipotential lines are  contour lines which trace the lines of identical altitudes. In physics, they trace out lines of equal electric potential or voltage.

Equipotential lines are always perpendicular to the electric field. The closer the equipotential lines to each other, the greater the strength of the electric field.

Answer:

a)  10 dB, b) 20dB, c) 10², 10⁴, 10⁸

Explanation:

The logarithmic scale has a great advantage when measuring magnitudes of a large number of scales, since it converts these values ​​to linear, allowing easier viewing.

Part A

  Let's look for decibels for an intensity I = 10 Io

We calculate

           β = 10 log (10Io / Io)

           β = 10 dB

Part b

Let's find the intensity for I = 100 Io

We calculate

    β = 10 log (100Io / Io)

    β = 10 log 100

    β = 10 2

    β = 20 db

Part c

     Δβ2 corresponds to an intensity change of 10² Io, therefore it corresponds to an intensity increase of 10²

    Δβ4 corresponds to a change in intensity of 10⁴Io

    Δβ8 is an intensity change of 10⁸ Io

The sound intensity level in decibels can be calculated using the formula β = 10log(I/I_0). For a sound wave with intensity 10 times the reference intensity, the sound intensity level is 10 dB. For a sound wave with intensity 100 times the reference intensity, the sound intensity level is 20 dB.

Part A: To find the sound intensity level when the intensity is 10 times the reference intensity, we use the formula β = 10log(I/I_0). Plugging in the values, β = 10log(10I_0/I_0) = 10log(10) = 10 x 1 = 10 dB.

Part B: Similarly, when the intensity is 100 times the reference intensity, we get β = 10log(100I_0/I_0) = 10log(100) = 10 x 2 = 20 dB.

Part C: To calculate the change in decibels for different intensities (m), we use the formula Δβ = 10log(m). For m = 2, Δβ2 = 10log(2) = 10 x 0.3 = 3 dB. For m = 4, Δβ4 = 10log(4) = 10 x 0.6 = 6 dB. And for m = 8, Δβ8 = 10log(8) = 10 x 0.9 = 9 dB.

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Answer:

Downwards into the plane

Explanation:

Solution:-

- This is a conceptual application of  hand rule. We will place our palm fingers open vertical to a plane surface. Then curl our fingers in and naturally point the thumb.

- The direction of curl of fingers denotes the direction of of current flow in the coil. Which in our case is "clockwise direction". We will orient/invert our right hand palm in such a way that we curl our fingers in clockwise fashion. Then stick the thumb out to give us the direction of magnetic field or North pole end. In our case the the thumb points downwards into the plane denoting that the magnetic field within the loop is also acting downwards into the plane.

- The bar magnet would be placed in such a way that North pole is pointing downward into the plane in the direction of magnetic field and end up at south pole pointing up out of the plane.

Answer:

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

Explanation:

Given:

Speed of sound in air = 320 m/s

Speed of sound in water = 1600 m/s

Time taken to reach certain distance in air = 2.5 sec

a.

We have to find the distance traveled by sound in air.

Distance = Product of speed and time.

⇒ [tex]Distance = Speed\times time\ taken[/tex]

⇒ [tex]Distance = 320\times 2.5[/tex]

⇒ [tex]Distance = 800[/tex] meters.

b.

Now we have to find how much time the sound will take to travel in water.

⇒ Time = Ratio of distance and speed

⇒ [tex]Time =\frac{distance}{speed}[/tex]

⇒ [tex]Time =\frac{800}{1600}[/tex]     ...distance = 800 m and speed = 1600 m/s

⇒ [tex]Time =\frac{1}{2}[/tex]

⇒ [tex]Time =0.5[/tex] seconds.

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

Answer:

Considering the two cases of when the train is moving towards and away from the stationary observer. The observed frequency of sound waves from the train can decrease when

1) The speed of the train is slowly reducing and its direction is towards the stationary observer.

2) The speed of the train is slowly increasing and its direction is away from the observer for the sound's observed frequency to keep decreasing.

Explanation:

This phenomenon is due to Doppler's Effect.

Doppler's Effect explains how relative frequency of a sound source varies with the velocity of the source or the observer.

Generally, the mathematical expression for Doppler's Effect is given below

f' = f [(v + v₀)/(v - vₛ)]

where

f' = observed frequency

f = actual frequency

v = velocity of sound waves

v₀ = velocity of observer

vₛ = velocity of sound source

When the train is moving towards the stationary observer,

f' = observed frequency of the sound wave = f₁

f = actual frequency of the sound wave = f

v = velocity of sound waves = v

v₀ = velocity of observer = 0 m/s

vₛ = velocity of sound source = vₛ

f' = f [(v + v₀)/(v - vₛ)]

f₁ = f [(v + 0)/(v - vₛ)]

f₁ = fv/(v - vₛ) (eqn 1)

Observed frequency is obviously higher than the frequency of the train.

But if the train keeps reducing its speed (vₛ) towards from the stationary observer, the observed frequency will decrease.

When the train is moving away from the stationary observer,

f' = observed frequency of the sound wave = f₂

f = actual frequency of the sound wave = f

v = velocity of sound waves = v

v₀ = velocity of observer = 0 m/s

vₛ = velocity of sound source = - vₛ (train is moving away from the observer, hence, the negative sign)

f' = f [(v + v₀)/(v - vₛ)]

f₂ = f [(v + 0)/(v - (-vₛ)]

f₂ = fv/(v + vₛ) (eqn 2)

From the expression, it is clear that the observed frequency is smaller than the frequency of the sound waves and it keeps decreasing as the speed of the train (vₛ) increases as the train moves away from the stationary observer.

Hope this Helps!!!

Answer:

The student can conclude that the speed of the train is increasing while the direction of the train is away from her or him

Explanation:

Here we have the Doppler effect given by

For an approaching wave

[tex]F_{obs} =\left [ \frac{v}{v - v_{source}} \right ] f_{source[/tex]

For a receding wave we have

[tex]F_{obs} =\left [ \frac{v}{v + v_{source}} \right ] f_{source[/tex]

Therefore, comparing the denominators of the two equation, it is seen that the frequency heard by the observer is decreases for a receding wave.

That is the student can conclude that the train is moving away from her or him or that the speed of the train is increasing while the direction of the train is away from her or him.

Answer:

Explanation:

The contributions of water properties in Thermoregulation in endotherms and in the plasma membrane structure.

A) Thermoregulation in endotherms: Water contributes to thermoregulation by its property of High specific heat. Water's high specific heat acts as a heat buffer, it is much harder to cool down/heat up, therefore, it will make warmer than the cold environment around it or colder than the hot environment around it. Thermoregulation works in humansas well. Recall Homeostasis which is the body's way of regulating our temperature.

B) Plasma membrane structure:

The property of water, polarity, contributes to the plasma membrane because it creates the arrangement of phospholipids making it a semi-permeable membrane.

Recall that the Plasma Membrane has a hydrophilic end on the outside that is charged and likes water and a hydrophobic end on the inside that has no charge and doesn't like water.

The membrane that separates the interior of the cell from the external environment is known as the plasma membrane, sometimes known as the cell membrane, and it is present in all cells. A cell wall is affixed to the plasma membrane on the exterior of bacterial and plant cells.

Like all other living things, plants need an excretory system to remove extra water from their bodies. Transpiration is the term for this process of removing extra water from the body of the plant. Typically, it is the evaporation of water from the leaf surface.

Now, according to the question :

(A) Thermoregulation in endotherms :

Water helps regulate body temperature since it has a high specific heat. Due to its high specific heat, which acts as a heat buffer, water will either make an area warmer than the surrounding cold environment or colder than the surrounding hot environment. Humans are capable of thermoregulation as well. Remember that the body uses homeostasis to control our body temperature.

(B) Plasma membrane structure:

Because it forms the arrangement of phospholipids that makes the plasma membrane a semi-permeable membrane, water's polarity contributes to the plasma membrane.

Remember that the Plasma Membrane has an exterior hydrophilic end that is charged and prefers water, and an interior hydrophobic end that is uncharged and dislikes water.

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Answer:

when all else remains the same, what effect would decreasing the focal have known a convex lens

Explanation:

It would cause the lens to produce only real images

( Hope This Will Help U Out!!)

Answer:

Block A

Explanation:

Block A will float higher in the water compared to the second Block.

The density of water is 1g/cm³.

According to the principle of floatation "an object that floats in a liquid will displace equal amount of fluid to the weight of the object".

A body will become more submerged in water if it has more density because density is the mass per volume of  body.

An object with a higher density than another will sink in the liquid of the one with lesser density.

Answer:

The block solar winds and other harmful things

Explanation:

The Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation.

Answer:

Explanation:The Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation. One stripping mechanism is for gas to be caught in bubbles of magnetic field, which are ripped off by solar winds.

Answer:

a) [tex]Q_{in} = 13.742\,kW[/tex], b) [tex]\Delta S = 370.15\,\frac{kJ}{K}[/tex]

Explanation:

a) The heat transfered to the egg is computed by the First Law of Thermodynamics:

[tex]Q_{in} +U_{sys,1} - U_{sys,2} = 0[/tex]

[tex]Q_{in} = U_{sys,2} - U_{sys,1}[/tex]

[tex]Q_{in} = \rho_{egg}\cdot \left(\frac{4\pi}{3}\cdot r^{3}\right)\cdot c \cdot (T_{2}-T_{1})[/tex]

[tex]Q_{in} = \left(1020\,\frac{kg}{m^{3}}\right)\cdot \left(\frac{4\pi}{3}\right)\cdot (0.025\,m)^{3}\cdot \left(3.32\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (70\,^{\textdegree}C - 8\,^{\textdegree}C)[/tex]

[tex]Q_{in} = 13.742\,kW[/tex]

b) The amount of entropy generation is determined by the Second Law of Thermodynamics:

[tex]\Delta S = \frac{Q_{in}}{T_{in}}[/tex]

[tex]\Delta S = \frac{13.742\,kJ}{370.15\,K}[/tex]

[tex]\Delta S = 370.15\,\frac{kJ}{K}[/tex]

The heat transferred to the egg is approximately 18.24 kJ. The entropy generation associated with this heat transfer is about 5.68 kJ/K.

To determine how much heat is transferred to the egg, we use the following formula for heat transfer in a substance:

Q = m × cp × (T_final - T_initial)

Given data:

The volume of the egg as a sphere is:

V = (4/3) × π × r³ = (4/3) × π × (0.0275)³ ≈ 8.72 × 10⁻⁵ m³

The mass of the egg is then:

m = ρ × V = 1020 kg/m³ × 8.72 × 10⁻⁵ m³ ≈ 0.0889 kg

Now, calculate the heat transferred:

Q = m × cp × (T_final - T_initial) = 0.0889 kg × 3.32 kJ/kg·°C × (70°C - 8°C) ≈ 18.24 kJ

(b) Calculating Entropy Generation:

Using the formula for entropy change, we have:

ΔS = m × cp × ln(T_final/T_initial)

Temperatures in Kelvin:

Then:

ΔS = 0.0889 kg × 3.32 kJ/kg·°C × ln(343.15 / 281.15) ≈ 5.68 kJ/K

Hence, the amount of entropy generated during the process is approximately 5.68 kJ/K.

Final answer:

To calculate the tangential speed, total acceleration, and angular position of point P on the wheel at t = 2.00 s, we can use the formulas for tangential speed, total acceleration, and angular position. By substituting the given values into these equations, we can find the required values.

Explanation:

To calculate the tangential speed of a point on the wheel, we can use the formula:

Tangential Speed = Angular Velocity x Radius

In this case, the angular velocity is given by the equation:

Angular Velocity = Initial Angular Velocity + (Angular Acceleration x Time)

Substituting the given values and solving the equations, we can find the tangential speed, which is the speed of the point P on the rim at time t = 2.00 s.

To find the total acceleration, we can use the formula:

Total Acceleration = Tangential Acceleration + Radial Acceleration

The tangential acceleration can be calculated using the equation:

Tangential Acceleration = Angular Acceleration x Radius

The radial acceleration can be calculated using the equation:

Radial Acceleration = (Angular Velocity x Angular Velocity) x Radius

By substituting the given values into these equations, we can find the total acceleration at time t = 2.00 s.

To find the angular position of point P at time t = 2.00 s, we can use the equation:

Angular Position = Initial Angular Position + (Initial Angular Velocity x Time) + (0.5 x Angular Acceleration x Time x Time)

Substituting the given values, we can find the angular position of point P at t = 2.00 s.

Answer: Technician B is right.

Explanation:

Evacuation process is used in refrigeration systems to remove moisture, air and non-profit condensable gases in order to achieve maximum function of the system.

vacuum pump is used to draw the sealed AC system into a vacuum. Evacuation of a refrigerant system also helps to maintain pressure, this is so as pulling a vacuum on the system is simply removing matter (mostly air and nitrogen) from inside the system so that the pressure inside drops below atmospheric pressure.

Answer:

Speed will be equal to 1.40 m/sec

Explanation:

Mass of the rubber ball m = 5.24 kg = 0.00524 kg

Spring is compressed by 5.01 cm

So x = 5.01 cm = 0.0501 m

Spring constant k = 8.08 N/m

Frictional force f = 0.031 N

Distance moved by ball d = 15.8 cm = 0.158 m

Energy gained by spring

[tex]KE=\frac{1}{2}kx^2=\frac{1}{2}\times 8.08\times 0.0501^2=0.0101J[/tex]

Energy lost due to friction

[tex]W=Fd=0.031\times 0.158=0.0048J[/tex]

So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J

This energy will be kinetic energy

[tex]\frac{1}{2}mv^2=0.0052[/tex]

[tex]\frac{1}{2}\times 0.00524\times v^2=0.0052[/tex]

v = 1.40 m/sec

The toy cannon's projectile leaves the barrel at approximately 1.42 m/s.

To find the speed at which the 5.24-g soft rubber ball leaves the barrel of the toy cannon, we follow these steps:

1.) Determine the Potential Energy in the Compressed Spring:

The potential energy stored in the spring when it is compressed can be calculated using the formula:

where

    Potential Energy = (1/2) * 8.08 N/m * (0.0501 m)²
    Potential Energy = 0.01017504 J

2.) Calculate the Work Done by Friction:

Friction force is constant at 0.0310 N over a distance of 15.8 cm (0.158 m):

3.) Find the Net Energy Available:

4.) Calculate the Speed of the Ball:

Using the energy conservation principle where Net Energy is converted into kinetic energy:

Solving for velocity (v):

Thus, the speed at which the ball leaves the barrel of the cannon is approximately 1.42 m/s.

Answer:

1) A

2) A

3) D

Explanation:

For parallel plates,the electric field E is given by:

E = σ / ε(o), where

E = Electric Field

σ = surface charge density

E = 10^-5 / 8.85*10^-12

E= 1.13*10^6 which is approximately 1*10^6 N/C, option A

B) K has a charge of 1.6*10^-19

F= q*E= (1.13*10^6) * (1.6*10^-19)

F= 1.8*10^-13 Which is approximately 2*10^-13 N, option A

C) Potential difference ,V = Ed

d = 10 nm= 1*10^-9

V = 1.13*10^6 * 1**10^-9

V = 0.0113 v

V = 1.13×10^-2 which is approximately 1x10^-2v, option D

The answers are 1) 1×10^6 N/C, 2) 2×10^13 N, 3) 6×10^3 V, 4) Toward the inner wall.

1) The magnitude of the electric field between the membranes can be calculated using the formula for electric field strength in a parallel plate capacitor:

E = σ / ε₀ = 10^(-5) C/m^2 / (8.85 x 10^(-12) F/m)

= 1.13 x 10^6 N/C.

Therefore, the answer is (a) 1×10^6 N/C.

2) The force on a K+ ion between the cell walls can be found using the formula F = qE, where q is the charge of the K+ ion. As K+ has a +1 charge, the force will be 1.13 x 10^6 N/C × 1.6 x 10^(-19) C

= 1.80 x 10^(-13) N.

Therefore, the answer is 2×10^13 N.

3) The potential difference between the cell walls can be calculated by multiplying the electric field strength by the distance between the walls:

V = Ed = 1.13 x 10^6 N/C × 10 x 10^(-9) m

= 1.13 x 10^4 V = 11.3 kV.

Therefore, the answer is (a) 6×10^3 V.

4) The direction of the electric field between the walls is from the outer wall to the inner wall.

Therefore, the answer is (b) Toward the inner wall.

Answer:

There is no closed-loop path for the current to flow through the circuit.When the switch is closed,the light bulb operates since the current flows through the circuit.The bulb glows at its full brightness since its receives its full 120 volts and has the design current flow.

Explanation:

Answer with Explanation:

We are given that

[tex]\frac{N_1}{N_2}=10[/tex]

[tex]V_1=120 V[/tex]

[tex]I_1=0.350 A[/tex]

a.[tex]\frac{V_1}{V_2}=\frac{N_1}{N_2}[/tex]

Using the formula

[tex]\frac{120}{V_2}=\frac{10}{1}[/tex]

[tex]V_2=\frac{120}{10}=12 V[/tex]

b.[tex]\frac{I_2}{I_1}=\frac{N_1}{N_2}[/tex]

[tex]\frac{I_2}{0.350}=10[/tex]

[tex]I_2=0.350\times 10=3.5 A[/tex]

c.Power delivered,P=[tex]I_2V_2=I_1V_1[/tex]

[tex]P=120\times 0.350=42 W[/tex]

Answer: neither tension nor compression

Explanation:

The tension in the form of load or forces

And also compression in the form of weight or load since the sagging is negligible as interpreted from the question which say that - horizontal wooden beam sags a bit when supported at its ends. 

Answer:

The magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N

Explanation:

Given;

speed of the electron, v =  8.0 × 10⁶ m/s

magnetic field strength, B = 2.5 T

angle of inclination of the field, θ = 60°

The magnetic force experienced by the electron in the magnetic field is given as;

F = qvBsinθ

where;

q is charge of electron = 1.6 x 10⁻¹⁹ C

B is strength of magnetic field

v is speed of the electron

Substitute the given values and solve for F

F = (1.6 x 10⁻¹⁹)( 8.0 × 10⁶)(2.5)sin60

F = 2.77 x 10⁻¹² N

Thus, the magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N

The magnitude of the magnetic force on the electron is approximately 2.06 x 10^-13 N.

In this scenario, the magnitude of the magnetic force on the electron can be calculated using the equation F = qvBsinθ, where q is the charge of the electron (+1.6 x 10-19 C), v is its velocity (8.0 x 106 m/s), B is the magnetic field (2.5 T), and θ is the angle between the velocity and the magnetic field (60°). Plugging in the values, we get:

F = (1.6 x 10-19 C)(8.0 x 106 m/s)(2.5 T)sin(60°)

Using the trigonometric identity sin(60°) = sqrt(3)/2, we can simplify the equation and calculate the magnitude of the magnetic force to be approximately 2.06 x 10-13 N.

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Answer:

Answer is 14.65

Refer below.

Explanation:

Refer to the picture for brief explanation.

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

[tex]T^2=\frac{4\pi}{GM}r^3[/tex]

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

[tex]T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min[/tex]

the comet takes around 16.63min

Answer:

if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

Explanation:

The incident light is generally random, that is, it does not have a polarization plane, when the first polarized stops by half, this already polarized light arrives at the second polarizer and the causticity passes

                I = I₀ cos² θ

therefore if the two polarizers have the same direction the transmitted light is 50% of the incident and if the two polarizers are at 90º the transmitted light is zero

Answer:

[tex]-0.5\times 10^{-4} A/s[/tex]

Explanation:

We are given that

[tex]\frac{dV}{dt}=-0.01 V/s[/tex]

R=600 ohms

I=0.04 A

[tex]\frac{dR}{dt}=0.5ohm/s[/tex]

[tex]V=IR[/tex]

[tex]\frac{dV}{dt}=\frac{\partial V}{dI}\frac{dI}{dt}+\frac{\partial V}{dR}\frac{dR}{dt}[/tex]

[tex]\frac{dV}{dt}=R\frac{dI}{dt}+I\frac{dR}{dt}[/tex]

Substitute the values

[tex]-0.01=600\times \frac{dI}{dt}+0.04\times 0.5[/tex]

[tex]-0.01-0.04\times 0.5=600\frac{dI}{dt}[/tex]

[tex]-0.03=600\frac{dI}{dt}[/tex]

[tex]\frac{dI}{dt}=\frac{-0.03}{600}=-0.5\times 10^{-4}A/s[/tex]

Final answer:

The student's question concerns finding the rate of change of current in a circuit as described by Ohm's law. By finding partial derivatives of the voltage with respect to current and resistance and applying the provided rates, you solve for the rate of change of current.

Explanation:

The student is asking how the current I is changing over time in a circuit with a given resistance R, current I, and rates of change dR/dt and dV/dt according to Ohm's law. To solve this, we need to find the partial derivatives of voltage V with respect to current I and resistance R, and then use the given differential equation dV dt = ∂V ∂I dI dt + ∂V ∂R dR dt.

Using Ohm's law, we can express the voltage as V = IR. The partial derivative of V with respect to I is R, and with respect to R is I. Substituting these derivatives and the given values into the differential equation, we have: -0.01 = 600 dI dt + 0.04 * 0.5. Solving for dI dt, we get the rate at which the current is changing over time, which is the answer the student is looking for.

The most prevalent in the human body by mass is oxygen.

To find the answer, we need to know more about the elemental composition in human body.

Thus, we can conclude that, the most prevalent in the human body by mass is oxygen.

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Answer:B I think

Explanation:

Answer:

(a) 534.324 rad

(b) 13.45 s

(c) -6.45 rad/s2

Explanation: Please see the attachments below

Final answer:

The grinding wheel's total angle of turn, time to stop, and angular acceleration are calculated using its initial angular velocity, time accelerated, and the angle it turned while coasting.

Explanation:

Calculating Angular Motion of a Grinding Wheel

A grinding wheel starts with an angular velocity of 28.0 rad/s and accelerates for 1.90 s at a constant angular acceleration of 25.0 rad/s2. After a circuit breaker trips, it coasts to a stop through 436 rad.

To find the total angle the wheel turns, calculate the angle turned during the acceleration phase and add the 436 rad it turns while coasting.

The time for the wheel to stop is found by calculating the time from start to when the circuit breaker trips plus the time it takes to coast to a stop.

The angular acceleration during the deceleration phase is determined using the kinematic equations of rotational motion.

Answer:

Lenz's law is responsible for the resistance to advance due to the change in magnetic flux

Explanation:

This system produces electricity by Faraday's law,

        E = - d / dt B.A

Where the electromotive force is generated by the change of the field strength maintained due to the circular movement of the wheel.

As this field changes when Lenz's law increases or decreases, it creates a field that opposes this change, this field is applied to the bicycle and is in the opposite direction to movement, so it is an effect that creates resistance to the advance of the bike.

In summary Lenz's law is responsible for the resistance to advance due to the change in magnetic flux

1.) The atomic radius of the elements in a group or family increase from the top to the bottom.

2.) The ionization energy decrease going down from the top to the bottom of the group.

3.) Electron affinity becomes less negative from the top to the bottom

4.) Element with high ionization energy has high electronegativity. Therefore, electronegativity decreases from top to the bottom of the group.

Periodic table tells us of the arrangement of elements and also the periodic properties of the elements as they are arranged in groups, periods and families.

some of the properties are :

1. Atomic radius

2. Ionization Energy

3. Electron Affinity

4. Electronegativity

5. Metallic character

6. e.tc

1.) The atomic radius of the elements in a group or family increase from the top to the bottom.

2.) The ionization energy decrease going down from the top to the bottom of the group.

3.) Electron affinity becomes less negative from the top to the bottom

4.) Element with high ionization energy has high electronegativity. Therefore, electronegativity decreases from top to the bottom of the group.

Due to the reason mention above, i can conclude the mystery elements are at the top of their families on the periodic table. An element that is in the same family as element C is likely to have all properties mentioned above.

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Answer:

120 N

Explanation:

F=ma therefore 60kg times 2m/s^2 is 120 N