What resistance is needed in this rc circuit if the flash is to charge to 90% of its full charge in 22 s ?
Consider a ball rolling down the decreasing slope inside a semicircular bowl (the slope is steep at the top rim, gets less steep toward the bottom, and is zero (no slope) at the bottom). As the ball rolls from the rim downward toward the bottom, its rate of gaining speed
The earth's radius is about 4000 miles. kampala, the capital of uganda, and singapore are both nearly on the equator. the distance between them is 5000 miles as measured along the earth's surface. part a the flight from kampala to singapore takes 8.3 hours. what is the plane's angular velocity relative to the earth's surface? give your answer in â/h.
Explanation:
Radius of earth, r = 4000 miles
Angular velocity is the ratio of linear velocity and radius.
[tex]\omega =\frac{v}{r}[/tex]
Linear distance from Kampala to Singapore = 5000 miles
Time taken = 8.3 hours
Distance = Time x Velocity
5000 = 8.3 x Velocity
Velocity, v = 602.41 mph
Substituting in angular velocity equation
[tex]\omega =\frac{v}{r}=\frac{602.41}{4000}=0.15rad/hr[/tex]
Plane's angular velocity relative to the earth's surface = 0.15 rad/hr
The plane's angular velocity in hours can be calculated using the angle in radians covered in one hour's flight and the Earth's radius, applying the formula for angular velocity.
Explanation:To find the plane's angular velocity relative to the Earth's surface, we need to calculate how many radians the plane covers in an hour and then convert this to angular velocity in degrees per hour. The formula for angular velocity (ω) is ω = θ / t, where θ is the angle in radians and t is the time in seconds. Given that the Earth's circumference is approximately 24,900 miles, we can determine the angle by using the proportion θ / (2π) = distance / Earth's circumference. With the plane's distance being 5000 miles and the Earth's radius being 4000 miles, we use the arc length formula s = rθ, where s is the arc length (5000 miles), r is the radius of the Earth (4000 miles), and θ is the angle in radians. Solving this for θ gives us θ = s / r.
Learn more about Angular Velocity here:https://brainly.com/question/30733452
#SPJ3
a 50kg box is being pushed along a horizontal surface. the coefficient of kinetic friction between the box and the ground is 0.35.what horizontal force must be exerted on the box for it to accelerate at 1.20m/s^2
Answer:
Net horizontal force, [tex]F_{net}=231.5\ N[/tex]
Explanation:
It is given that,
Mass of the box, m = 50 kg
The coefficient of kinetic friction between the box and the ground is 0.35, [tex]\mu=0.35[/tex]
Acceleration of the box, [tex]a=1.2\ m/s^2[/tex]
We know that the frictional force acts in opposite direction to the direction of motion. The net force acting on it is given by :
[tex]F_{net}=f+ma[/tex]
[tex]F_{net}=\mu mg+ma[/tex]
[tex]F_{net}=m(\mu g+a)[/tex]
[tex]F_{net}=50\times (0.35\times 9.8+1.2)[/tex]
[tex]F_{net}=231.5\ N[/tex]
So, the net force acting on the box is 231.5 N. hence, this is the required solution.
What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.
1.1 × 10–17 J
1.1 × 10–16 J
8.3 × 10–16 J
8.3 × 10–15 J
Answer:
The correct answer is B.
Explanation:
Got a 100% on the Exam
A book rests on a table, exerting a downward force on the table. the reaction to this force is:
When a clock reads 5.0 seconds a cart's velocity in the negative x direction is 3.0 m/s. when the clock reads 6.0 seconds, the cart's velocity in the positive x direction is 4.0 m/s. what is the magnitude (in m/s2) of the average acceleration of the cart?
The kinematic we find the average acceleration of the body is 7 m/s²
Given parameters
The velocity at two instant of time t₁ = 5.0 s, v₁ = -3.0 m / st₂= 6.0 s, v₂ = 4.0 m / s
To find
The average acceleration of the bodyKinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.
Average acceleration is defined as the change in velocity in a given time interval
a_ {avg} = [tex]\frac{\Delta v}{\Delta t}[/tex]
Let's apply this expression to our case
let's set a reference frame where the positive direction of the x axis is positive, so v₁ is negative
a_ {avg} = [tex]\frac{v_2 -v_1}{t_2 -t_1}[/tex]
a_ {avg} = [tex]\frac{4- (-3)}{6-5}[/tex]
a_ {avg} = 7 m / s²
In conclusion using kinematics we find the average acceleration of the body is 7 m / s²
learn more about average acceleration here:
https://brainly.com/question/17355747
The compound PCl5 decomposes into Cl2 and PCl3. The equilibrium of PCl5(g) Cl2(g) + PCl3(g) has a Keq of 2.24 x 10-2 at 327°C. What is the equilibrium concentration of Cl2 in a 1.00 liter vessel containing 0.235 mole of PCl5 and 0.174 mole of PCl3? Remember to use the correct number of significant digits. Cl2 = Are the products or reactants favored?
To find the equilibrium concentration of Cl2 in the decomposition of PCl5, we start with initial concentrations, assume x is the change at equilibrium, and apply the equilibrium expression using Keq = 2.24 x 10^-2. Solving this for x yields the equilibrium concentration of Cl2, showing whether reactants or products are favored.
To determine the equilibrium concentration of Cl2 when PCl5 decomposes into Cl2 and PCl3, we can start with the provided concentrations and use the equilibrium constant (Keq).
The equilibrium equation for this decomposition is:
PCl5(g) \<=> Cl2(g) + PCl3(g)
and the given Keq is 2.24 x 10-2 at 327°C.
Let's assume x is the amount of PCl5 that decomposes to form x moles of Cl2 and x moles of PCl3 at equilibrium:
Initial moles of PCl5 = 0.235 molInitial moles of PCl3 = 0.174 molChange for PCl5 = -xChange for Cl2 = +xChange for PCl3 = +xAt equilibrium, we will have:
[PCl5] = (0.235 - x) mol / 1.00 L[Cl2] = x mol / 1.00 L[PCl3] = (0.174 + x) mol / 1.00 LThe Keq expression is:
Keq = [PCl3][Cl2] / [PCl5]
Plugging in the equilibrium concentrations:
2.24 x 10-2 = ((0.174 + x) × x) / (0.235 - x)
This equation can be solved for x to find the equilibrium concentration of Cl2. With the calculated value of x, it is possible to determine the favorability of the reaction. A small Keq value (< 1) typically indicates that reactants are favored, which suggests in this case, PCl5 would be favored at equilibrium.
An arrow is shot from a bow at an angle of 35 degrees above horizontal with an initial speed of 50 m/s what is the arrows horizontal x and y components ?
Answer: Horizontal component of arrow :40.955 m/s
Vertical component of arrow :28.675 m/s
Explanation:
The initial speed of the arrow = u = 50 m/s
The horizontal component of the arrow =[tex]u_x=u\cos\theta [/tex]
The horizontal component of the arrow =[tex]u_y=u\sin\theta [/tex]
Angle between the velocity vector and x component = 35°
Horizontal component of arrow :
[tex]\cos\theta=\frac{u_x}{u}[/tex]
[tex]\cos35^o=0.8191=\frac{u_x}{50}[/tex]
[tex]u_x=0.8191\times 50=40.955 m/s[/tex]
Vertical component of arrow :
[tex]\sin\theta=\frac{u_y}{u}[/tex]
[tex]\sin35^o=0.5735=\frac{u_y}{50}[/tex]
[tex]u_y=0.5735\times 50=28.675 m/s[/tex]
Horizontal component of arrow :40.955 m/s
Vertical component of arrow :28.675 m/s
Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.
The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of the individual capacitance.
The capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].
What is equivalent capacitance of parallel series?
The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of the individual capacitance.
It can be given as,
[tex]C_{eq}=\dfrac{Q}{V}[/tex]
Here, [tex]Q[/tex] is the charge and [tex]V[/tex] is the voltage.
Given information-
The voltage of the battery is 5.55 V.
The value of charge is [tex]3.45\times10^{-4}[/tex] C.
Put the values in the above formula as,
[tex]C_{eq}=\dfrac{3.45\times10^{-4}}{5.55}\\C_{eq}=6.4\times10^{-4}\rm F[/tex]
Given that the three uncharged capacitors with equal capacitance are combined in parallel.
For the parallel connection of the capacitance the equivalent capacitance can be given as,
[tex]C_{eq}=C+C+C[/tex]
Here, [tex]C[/tex] is the capacitance of each capacitors. Put the values,
[tex]6.4\times10^{-4}\rm =3C\\C=2.1\times10^{-5}\rm F[/tex]
Hence the capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].
Learn more about the equivalent capacitance here;
https://brainly.com/question/5626146
A uniform rod XY of weight 10.0N is freely hinged to a wall at X. It is held horizontal by a force F acting from Y at an angle 30° to the horizontal, as shown.
What is the value of F?
A- 5.0 N B- 8.7cm C- 10.0cm D-20.0cm
The value of the horizontal force acting on the rod is 10 N. Therefore option (C) is correct.:
Given data:
The weight of rod is, W = 10.0 N.
The angle made by force with respect to horizontal is, [tex]\theta = 30^\circ[/tex].
To maintain the steady position (equilibrium condition), the vertical component of force F must be balanced by the moment of force due to weight.
Therefore,
[tex](Fsin\theta) \times L = W \times \dfrac{L}{2} \\\\(F \times sin30^{\circ}) = \dfrac{10}{2} \\F = 10 \;\rm N[/tex]
Thus, the value of the horizontal force acting on the rod is 10 N. And option (C) is correct.
Learn more about the equilibrium of forces here:
https://brainly.com/question/3876381?referrer=searchResults
When photons with a wavelength of 310 nm strike a magnesium plate the maximum velocity of the ejected electrons is 3.45*10^5 m/s. calculate the binding?
rapid energy transfer between ____ and ____ energy make roller coasters thrilling
Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of 50 kilograms. What can Paul do to increase the bike’s kinetic energy?
A. He can let Ivan off at the next stop.
B. He can pedal harder to increase the rate to 10 meters/second.
C. He can reduce the speed to 3 meters/second.
D. He can pick up a third rider.
Answer: The correct answer is option C.
Explanation:
Kinetic energy is the energy possessed by the an object due to its motion.An its calculated by:
[tex]K.E.=\frac{1}{2}mass\times (velocity)^2[/tex]
Kinetic energy depends upon the mass and velocity of the an object.
So, Paul can increase the bike's kinetic energy by increasing the velocity of its bike. Hence, the correct answer is option C.
Increasing the mass will also increase the kinetic energy . But according to option (D) he has to stop the bike first by applying brakes which will reduce the kinetic energy of the bike.And then again have to perform the work to bring the bike in motion
14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?
A proton is fired from far away toward the nucleus of a mercury atom. mercury is element number 80, and the diameter of the nucleus is 14.0 fm. part a if the proton is fired at a speed of 3.4×107 m/s , what is its closest approach to the surface of the nucleus? assume the nucleus remains at rest. express your answer to two significant figures and include the appropriate units.
Answer:
[tex]27fm[/tex]
Explanation:
Kinetic Energy of proton
[tex]Kinetic Energy (K)=\frac{1}{2}mV^{2}[/tex]
[tex]m=Mass of proton[/tex]
[tex]V=Velocity of proton[/tex]
[tex]m=1.67\times 10^{-27} kg[/tex]
[tex]V=3.4\times 10^{7}ms^{-1}[/tex]
[tex]K=\frac{1}{2}\times 1.67\times 10^{-27}kg\times \left (3.4\times 10^{7}ms^{-1} \right )^2[/tex]
[tex]K=\frac{19.305}{2}\times 10^{-13}J[/tex]
[tex]K=9.65\times 10^{-13}J[/tex]
For conservation of energy;
[tex]Kinetic Energy=Potential energy[/tex]
[tex]K= U[/tex]
So,
[tex]U= 9.65\times 10^{-13}J[/tex]
Here,
[tex]U=Potential Energy[/tex]
[tex]U=k_{e}\frac{q_{1}q_{2}}{r}[/tex]
Here,
[tex]k_{e}=Coulomb's law constant[/tex]
[tex]k_{e}=8.99\times 10^{9}Nm^{2}C^{-2}[/tex]
[tex]q_{1}=80e[/tex]
[tex]q_{2}=e[/tex]
[tex]e=1.602\times 10^{-19}C[/tex]
[tex]r=The distance that proton will stop from the center of the nucleus[/tex]
[tex]U=k_{e}\frac{80e\times e}{r}[/tex]
[tex]9.65\times 10^{-13}J=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{r}[/tex]
[tex]r=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{9.65\times 10^{-13}J}[/tex]
[tex]34fm[/tex]
[tex]r_{0}=Radius of the atom[/tex]
[tex]Radius\left ( r_{0} \right )=\frac{diameter\left ( d \right )}{2}[/tex]
[tex]Diameter of the nucleus of mercury atom=14fm[/tex]
[tex]Radius of atom =\frac{14fm}{2}[/tex]
[tex]r=7fm[/tex]
[tex]d=r-r_{0}[/tex]
[tex]d=34fm-7fm[/tex]
[tex]d=27fm[/tex]
Further Explanation:
When a proton approaches a nucleus, it decelerates. Because the repulsive electric field and its kinetic energy converts into electric potential energy.
Then due to this, the proton will stop at a distance “r” from the center of the nucleus.
To find the distance from the surface where the proton hits, we have to subtract the radius of the nucleus.
Learn more:
1. Kinetic energy https://brainly.com/question/1621817 (answer by skyp)
2. Potential energy https://brainly.com/question/12489105 (answer by nitrotype2000)
3. Conservation of energy https://brainly.com/question/11911812 (answer by hrishisup)
Keywords:
Kinetic energy, potential energy, conservation of energy.
Describe the energy transformations that occur from the time a skydiver jumps out of a plane until landing on the ground.
Answer:
Before jumping from the plane, the skydiver has potential energy. When the skydiver jumps, the potential energy is transformed into kinetic energy, which increases until the skydiver reaches terminal velocity. Potential energy is then transformed into thermal energy.
Explanation:
Thats the answer
Why does light refract when it encounters the glass in a lens?
A) because it speeds up, which causes it to bend
B) because it slows down, which causes it to bend
C) because it hits a dense medium, which causes it to bounce off
D) because it gets absorbed, which causes it to lessen in intensity
Answer:
B) because it slows down, which causes it to bend
Explanation:Light hits the glass in a lens because it slows down, which causes it to bend. The material of a lens is more optically dense than the air it is traveling from.
5. Amy and Josh are coasting on their bicycles down a 10° slope at 15 m/s through still air. The mass of Amy and her bicycle is 60 kg. The mass of Josh and his bicycle is 90 kg. The cross-sectional area of Amy and her bicycle is 0.45, while the cross-sectional area of Josh and his bicycle is 0.60. The drag coefficient for both cyclists is 0.70. Other than gravity and air resistance, the external forces acting on the two bicycle and rider systems are the same. Which cyclist is more affected by air resistance? The Answer is Amy but what is the math invovled, Please Show Work and Help!
Amy experiences less air resistance due to her smaller cross-sectional area compared to Josh, but as she has a lower mass, the air resistance has a more significant effect on her, making her more affected by air resistance.
Explanation:To determine which cyclist, Amy or Josh, is more affected by air resistance, we can examine the force due to air resistance, which can be calculated using the formula:
Fd = (1/2)ρCdAv2
where Fd is the force of drag (air resistance), ρ is the air density (which we'll assume to be constant for both cyclists), Cd is the drag coefficient, A is the cross-sectional area, and v is the velocity.
Given that both cyclists have the same drag coefficient (Cd = 0.70) and are traveling at the same velocity (v = 15 m/s), the only variables that differ between the two are their cross-sectional areas. Since Amy has a smaller mass and a smaller cross-sectional area (A = 0.45 m2), the force of air resistance will be smaller in magnitude compared to Josh's due to his larger cross-sectional area (A = 0.60 m2).
However, air resistance's impact on an object is also related to the object's mass. A smaller force applied to a smaller mass can have a more significant effect than the same force applied to a larger mass. Therefore, even if the force of air resistance is absolutely higher for Josh, Amy, with her lower mass, would be more affected by it, as it would constitute a more substantial proportion of her total mass.
Which of the following is the main evidence of life in the early universe?
A.) Dinosaur fossils
B.) Rock layering
C.) Plant remains
D.) Cyanobacteria
Answer:
Cyanobacteria.
Explanation:
The oldest forms of life would be considered the cyanobacteria from the options, this bacteria are called extremists because they can survive in environments with littlo to zero oxygen andis thought that they have been present from the early begining of the universe because they are the only living organisms known to mankind that are able to survive under those conditions.
Tai ran from his home to a position 300 m south of his home in 100 seconds. What was his velocity? A.0.33 m/s south B.0.33 m/s north C.3 m/s north D.3 m/s south
If an object that enters the Earth’s atmosphere does not completely disintegrate, its remains can impact the Earth true or flase
A generator has a terminal voltage of 113 v when it delivers 13.6 a, and 91 v when it delivers 25.3
a. calculate the emf. answer in units of v. 002 (part 2 of 2) 10.0 points calculate the internal resistance. answer in units of Ï.
At what separation will two charges, each of magnitude 6.0fYC,exert a force of 1.4N on each other?
a.0.48m
b.2.0m
c.5.1*10^6m
d.0.23m
e.40m
This question involves the concept of Colomb's Law and electrostatic force.
The separation between charges will be "a. 0.48 m".
COLOMB'S LAWAccording to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
where,
F = electrostatic force = 1.4 Nk = Colomb's constant = 9 x 10⁹ N.m²/C²q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ Cq₂ = magnitude of second charge = 6 μC = 6 x 10⁻⁶ Cr = distance between charges = ?Therefore,
[tex]1.4 N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{r^2}\\\\r=\sqrt{\frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{1.4\ N}}[/tex]
r = 0.48 m
Learn more about Colomb's Law here:
brainly.com/question/9774180
In a thermostat, what property of the bimetallic coil allows it to contract and expand? The two metals absorb different amounts of thermal energy. The two metals are placed perpendicular to each other. The two metals burn at different temperatures. The two metals turn into liquids when absorbing energy.
Answer:
The two metals absorb different amounts of thermal energy.
Explanation:
Temperature controlling device in an electric equipment like a heater, is called a thermostat.
A bimetallic strip contains two different metals. Each metal has its own characteristic property of expansion or cooling. Coefficient of thermal expansion has a different value for different metals.
The metal that has a higher expansion coefficients will expand more when heated, compared to the metal that has a lower coefficient of expansion.
In a thermostat used in a heating circuit, the electric contact is cut off due to the bending of the bimetallic strip, when the desired temperature is reached.
A capacitor with capacitance (c) = 4.50 μf is connected to a 12.0 v battery. what is the magnitude of the charge on each of the plates?
The magnitude of the charge on each plate of a 4.50 μF capacitor connected to a 12.0 V battery is 54 μC.
Explanation:To find the magnitude of charge stored on each plate of a capacitor when a voltage is applied, you can use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage applied. Given a capacitor with a capacitance (C) of 4.50 μF and a voltage (V) of 12.0 V, we can calculate the charge (Q) as follows:
Q = CV = (4.50 μF) (12.0 V) = (4.50 × 10-6 F) (12.0 V) = 54 × 10-6 C = 54 μC
Therefore, the magnitude of the charge on each of the plates of the capacitor is 54 μC.
Learn more about Capacitor Charge Calculation here:
https://brainly.com/question/14048432
#SPJ12
To find the charge stored on a capacitor with given capacitance and voltage, use the formula Q = C × V. Substituting 4.50 μF and 12.0 V into the equation yields a charge of 5.40 × 10⁻⁵ C on each plate.
To determine the charge stored on a capacitor's plates, we use the formula:
Q = C × V
Where:
C is the capacitance in farads (F).V is the potential difference in volts (V).Q is the charge in coulombs (C).In this case, we have a capacitance C = 4.50 μF (which is 4.50 × 10⁻⁶ F) and a voltage V = 12.0 V.
By substituting these values into the formula, we get:
[tex]Q = 4.50 \times 10^{-6} \, \text{F} \times 12.0 \, \text{V}[/tex]
Q = 5.40 × 10⁻⁵C
Therefore, the magnitude of the charge on each of the plates is 5.40 × 10⁻⁵ C.
What properties of titanium make it attractive for use in race-car and jet-engine components?
Why aren’t organisms on the sea floor crushed by water pressure
13) A branch falling from a tree is to gravity as a car driving on the road is to A) a driver's foot off of the accelerator, coasting. B) a driver's foot off the accelerator and on the break pedal. C) a driver's foot on the accelerator pressed down to maintain speed. D) a driver's foot on the accelerator and pressed down gradually more and more.
Its D: A driver's foot on the accelerator and pressed down gradually more and more.
a college student exerts 100N of force to lift his laundry basket the weighs 75N. at what rate is the basket accelerated upwards?