The tired of a car support the weight of a stationary. If onetire has a slow leak, the air pressure within the tire will_____with time, the surface area between the tire and the roadwill____in time, and the net force the tire exerts on the roadwill_____in time.a) Increase, Increase, Increaseb) Decrease, decrease, decreasec) Decrease. increase,increased) Decrease, increase, remain constante) Decrease, increase, decrease

Answer:

Yes

Explanation:

Gravity and forces form the axle (external forces) do not cause forces that tend to cause rotation around the turntable's axle.

Answer:

x = 0.6034 m

Explanation:

Given

L = 5 m

Wplank = 225 N

Wman = 522 N

d = 1.1 m

x = ?

We have to take sum of torques about the right support point.  If the board is just about to tip, the normal force from the left support will be going to zero.  So the only torques come from the weight of the plank and the weight of the man.

∑τ = 0  ⇒     τ₁ + τ₂ = 0  

Torque come from the weight of the plank = τ₁

Torque come from the weight of the man = τ₂

⇒  τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)

⇒  τ₂ = Wman*x = 522 N*x   (clockwise)

then

τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0

⇒  x = 0.6034 m

Answer:

Time, t = 2 minutes

Explanation:

Given that,

Length of Duplain st. d = 300 m = 0.3 km

If keith is strolling east from Baron at an average velocity of, v = 3 km/hr

Sue is power-walking west from Burkey at an average velocity of, v' =  6 km/hr

To find,

How long will it take them to meet ?

Solution,

When both objects are travelling in opposite direction, then the total speed is given by :

V = v + v'

V = 3 km/hr + 6 km/hr

V = 9 km/hr

Let t is the time taken will it take them to meet. It can be calculated as :

[tex]t=\dfrac{d}{V}[/tex]

[tex]t=\dfrac{0.3\ km}{9\ km/hr}[/tex]

t = 0.033 hour

or

t = 1.98 minutes

i.e. t = 2 minutes

So, they will take 2 minutes to meet. Hence, this is the required solution.

Answer:

Molar mass due to different atomic masses

Explanation:

Two gases that have the same volume, pressure and gases have the same number of moles, as we can deduce from the ideal gas equation. So the gases will have the same number of moles of gases but they can have densities due to the fact that they have different molar masses due to the fact that they have different atomic masses. So one gas will be heavier than the other, for the same volume.

Answer:

x = 7.62 m

Explanation:

First we need to calculate the weight of the rocket:

W  = mg

we will use the gravity as 9.8 m/s². We have the mass (500 g or 0.5 kg) so the weight is:  

W  = 0.5 * 9.8 = 4.9 N

We know that the rocket exerts a force of 8 N. And from that force, we also know that the Weight is exerting a force of 4.9. From here, we can calculate the acceleration of the rocket:

F - W = m*a

a = F - W/m

Solving for a:

a = (8 - 4.9) / 0.5

a = 6.2 m/s²

As the rocket is accelerating in an upward direction, we can calculate the distance it reached, assuming that the innitial speed of the rocket is 0. so, using the following expression we will calculate the time which the rocket took to blast off:            

y = vo*t + 1/2 at²

y = 1/2at²

Solving for t:

t = √2y/a

t = √2 * 20 / 6.2

t = √6.45 = 2.54 s

Now that we have the time, we can calculate the horizontal distance:

x = V*t

Solving for x:

x = 3 * 2.54 = 7.62 m            

Answer:

B. Color perception is achieved by activation of various combinations between the tree cone types.

Explanation:

Human eye have only three photo receptor ( three wavelength) but they can see several thousands of shades of color because color perception is gained by combination of these three wave length cone types ( RED, BLUE AND GREEN) into various combinations. Our retina have two types of cell:- cone cells and cylindrical cells. Cone cells are responsible for the identification of color.

The frequency of the yellow light is [tex]5.17\cdot 10^{14}Hz[/tex]

Explanation:

The relationship between wavelength, frequency and speed of a wave is given by the wave equation:

[tex]v = f \lambda[/tex]

where

v is the speed of the wave

f is the frequency

[tex]\lambda[/tex] is the wavelength

For the yellow light in this problem, we have:

[tex]v=1.97\cdot 10^8 m/s[/tex] is the speed

[tex]\lambda=3.81\cdot 10^{-7} m[/tex] is the wavelength

Solving for f, we find its frequency:

[tex]f=\frac{v}{\lambda}=\frac{1.97\cdot 10^8}{3.81\cdot 10^{-7}}=5.17\cdot 10^{14}Hz[/tex]

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The frequency of the yellow light in the glass block is [tex]5.17 \times 10^{14}Hz[/tex]

Yellow light travels through a certain glass block at a speed of 1.97 × 108 m/s. The wavelength of the light in this particular type of glass is 3.81 × 10−7 m (381 nm).

[tex]= 1.97 \times 10^8 \div 3.81 \times 10^{-7}\\\\= 5.17 \times 10^{14}Hz[/tex]

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Answer:

Gold nugget diameter    22,24 cm

Silver nugget price   38860  $

Explanation:  

Gold price    1400  $ /ou            1  ounce  = 31.1035 grs

so  1400 /31.1035

Gold price is 45,01   $/grs.

If a nugget worth   5000000 $  then  5000000/ 45.01

a nugget mass  :  111086,43 grs

Now gold density  is  d = 19.3 grs/cm³

And she volume is  V = 4/*π*r³

d = m/V         V = m/d           V  =   111086.43/19.3    cm³

V = 5755,77 cm³

Now V of the sphere is  V =  5755,77 = 4/3*π*r³

r³  =3*5755,77 / 4π        r³  = 1374,79

r  =  11.12 cm      2r  =  22,24  =  Φ (sphere diameter)

B)  d (silver)  =  m/V       m = d*V

V = 5755,77 cm³     The same size the same volume

m =  10,5 * 5755,77 [grs/cm³ * cm³]       m  = 60435,59 grs

Silver nugget worth  :

20  $ /ou         20/31.1035  =   0.643  $ /grs

Price   0,643 *  60435,59  =  38860  $

Answer:

Covalent bonding

Explanation:

Covalent bonding is the type of bonding found in all molecular substances much as water, carbon dioxide or methane. Unlike ionic bonding which is found in ionic substances, covalent bonding involves sharing, not transfer, of electrons between the bonding atoms to form molecules.

The initial speed of the mountain biker can be determined using principles of projectile motion, by first calculating the time of flight from the vertical displacement and then substitifying this into the equation for horizontal displacement.

This problem can be solved using principles of projectile motion, where motion is analysed separately along the vertical and horizontal axes.

The time of flight can be determined by considering the vertical displacement and using the equation y = V0y*t - 0.5*g*t^2, where y is the vertical displacement, V0y is the initial vertical velocity, t is the total time, and g is the acceleration due to gravity. Solving for t, we can substitute this into the equation for horizontal displacement x = V0x*t, where x is the horizontal displacement and V0x is the initial horizontal velocity. This allows us to solve for the initial speed.

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The mountain biker's initial speed is found using the principles of projectile motion by resolving into horizontal and vertical components and solving a quadratic equation. The initial speed needed to achieve the jump is approximately 13.65 m/s.

Determining the Initial Speed of the Mountain Biker

To find the initial speed of the mountain biker, we'll use the principles of projectile motion. We'll perform a step-by-step analysis considering horizontal and vertical components separately.

Given data:

Step-by-Step Solution

Step 1: Separate the initial speed into horizontal (Vx) and vertical (Vy) components:

[tex]V_x = V_0 \cos(35.2^o) \\V_y = V_0 \sin(35.2^o)[/tex]

Step 2: Use the horizontal motion formula to express time (t):

[tex]x=V_xt[/tex]

[tex]$\begin{equation}t = \frac{x}{Vx} = \frac{30.1}{V_0 \cos(35.2^o)}\end{equation}$[/tex]

Step 3: Use the vertical motion formula considering the displacement:

[tex]$\begin{equation}y = V_y t + \frac{1}{2} a t^2\end{equation}$[/tex]

Substituting known values and simplifying, we have:

[tex]$\begin{equation} -14.7 = (V_0 \sin(35.2^o)) \times \frac{30.1}{V_0 \cos(35.2^o)} + \frac{1}{2}(-9.8) \left( \frac{30.1}{V_0 \cos(35.2^o)}\right)^2\end{equation}$[/tex]

[tex]or, -14.7=V_0\times0.57\times \frac{30.1}{V_0\times 0.817} -4.9\times (\frac{30.1}{V_0\times 0.817})^2 \\or,-14.7=20.99-4.9\times\frac{906.01}{V_0^2\times0.66} \\or, 6650.9/V_0^2=20.99+14.7\\or,V_0^2=6650.9/35.69\\or, V_0=13.65m/sec[/tex]

The initial speed is 13.65 m/sec.

The velocity of the ball is 7 m/s

Explanation:

The motion of the ball is a free fall motion, so it means that the ball falls down under the effect of the force of gravity only. Therefore, it has a constant acceleration (acceleration of gravity, g), and we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the ball in this problem, we have:

u = 0 (initial velocity, the ball is dropped from rest)

[tex]a=g=9.8 m/s^2[/tex] (acceleration of gravity)

s = 2.5 m (vertical displacement)

Solving for v, we find the velocity at which the ball hits the concrete surface:

[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(2.5)}=7 m/s[/tex]

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Final answer:

The piano tuner should loosen the piano string after hearing an increase from three beats per second to six beats per second upon tightening the string, as this indicates the string's frequency was adjusted away from the tuning fork's frequency.

Explanation:

When a piano tuner hears beats, it indicates that there is a frequency difference between a tuning fork and the piano string that is being compared. Initially, the tuner hears three beats per second, which means the frequency of the piano string is either slightly higher or lower than that of the tuning fork. After tightening the string, the number of beats per second increases to six. This indicates that the frequency of the string has moved further away from the frequency of the tuning fork.

The fact that the beats increased after tightening the string implies that the tuner has adjusted the frequency of the piano string in the wrong direction. Since the goal is to eliminate the beats entirely by matching frequencies, the tuner should loosen the string to reduce the frequency instead of tightening it further.

Answer:

1.07 m

Explanation:

x = Compression of the spring

k = Spring constant = 53 N/m

Initial length = 18 cm

P = Kinetic energy

K = Kinetic energy

At the lowest point of the mass the energy conservation is as follows

[tex]P_{ig}+P_{is}+K_i=P_{fg}+P_{fs}+K_f\\\Rightarrow mgx+0+0=mgx+\frac{1}{2}kx^2\\\Rightarrow x=\frac{2mg}{k}\\\Rightarrow x=\frac{2\times 2.4\times 9.81}{53}\\\Rightarrow x=0.89\ m[/tex]

At its lowest position the mark on the ruler will be

[tex]x_f=0.18+0.89\\\Rightarrow x_f=1.07\ m[/tex]

The spring line will end up at 1.07 m

In this scenario, when a 2.4 kg mass is attached to a spring, the spring gets displaced due to the force exerted by the mass due to gravity. The displacement can be calculated using Hooke's Law (F = kx), resulting in a mark of 62.4 cm on the ruler when the mass is at its lowest position.

The phenomenon described in this question is related to Hooke's Law of Physics, which states that the force required to extend or compress a spring by a distance is proportional to that distance. The force exerted by the spring is measured in Newtons (N) and is given by the equation F = kx, where k is the spring constant and x is the distance the spring is stretched or compressed.

In this case, when the 2.4 kg mass is attached to the spring, it will exert a force due to gravity which is equal to the mass times the acceleration due to gravity (g = 9.8 m/s²), therefore F = m*g = 2.4kg * 9.8m/s² = 23.52 N. The spring reacts to this force and gets displaced, which can be calculated using x = F/k = 23.52N / 53N/m = 0.444 m or 44.4 cm. Therefore, with the mass attached, the bottom of the spring would fall to 18cm + 44.4 cm = 62.4 cm on the ruler.

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Answer:

Running or Jogging

Running and jogging are both great options for aerobic conditioning. Whether you run at the gym or outside, you are in control of setting the intensity of your workout. When aiming to build muscle mass, you can add more resistance or jog at an incline, along with increasing your speed.

Explanation:

Answer:

Running

Jogging

Yoga

Explanation:

Running Jogging and yoga best describes aerobic exercise plan. Aerobic exercises are those where cardiovascular conditioning happen it can be swimming, cycling ,running, jogging etc. aerobic exercise is good for health as it reduces risk of:- obesity, high blood pressure type 2, diabetes, metabolic syndrome , strokes and some type of cancer too can be avoided by doing aerobic exercise.

Answer:

None of the given options

Explanation:

If the angular speed is constant, there is no angular acceleration:

α=0

If there is no angular acceleration, tangential acceleration will also be 0.

Centripetal acceleration, on the other hand, will be:

[tex]ac =\omega^2*R[/tex]  (Different to 0)

Answer:

Explanation:

Relation between Celsius and Kelvin is

K = C + 273

Relation between Kelvin and Fahrenheit is

[tex]\frac{K-273}{100}=\frac{F -32}{180}[/tex]

(a) 379 K

Relation between Celsius and Kelvin is

K = C + 273

So, C = K - 273 = 379 - 273 = 106

Thus, 379 K = 106°C.

(b) 379 K

Relation between Kelvin and Fahrenheit is

[tex]\frac{K-273}{100}=\frac{F -32}{180}[/tex]

[tex]\frac{379-273}{100}=\frac{F -32}{180}[/tex]

F = 222.8°F

Thus, 379 K = 222.8°F

(c) 1.04 x 10^2 K = 104 K

Relation between Celsius and Kelvin is

K = C + 273

So, C = K - 273 = 104 - 273 = -169

Thus, 104 K = - 169°C.

(d) 1.04 x 10^2 K = 104 K

Relation between Kelvin and Fahrenheit is

[tex]\frac{K-273}{100}=\frac{F -32}{180}[/tex]

[tex]\frac{104-273}{100}=\frac{F -32}{180}[/tex]

F =- 272.2°F

Thus, 104 K = - 272.2°F

Answer:

C. Both Technicians A and B

Explanation:

To loosen a fastener immediately especially if it is a rusted one we can follow these steps.

1. Tap the sides of the fastener so that the rust particle fall off.

2. These rust particles can be brushed off.

3. Spray the fastener with the penetrating oil.

4. Again tap the sides with a hammer to let the oil penetrate the inter-locked parts (threads in case of a nut and bolt).

5. Loosen the fastener after oil has penetrated.

Note: It should be kept in consideration that spraying alone won't do the job, tapping is essential to let the oil penetrate deep in to free the rusted parts.

Answer:

a) The screen should be located at 1.08 meters

b) The width of the central maximum is 1.7 mm

c) See figure below.

Explanation:

a) This is a single slit diffraction problem, the equation that describes this kind of phenomenon is:

[tex]a\sin\theta=m\lambda [/tex] (1)

Because we’re interested in a minimum near the center of the screen, we can use the approximation [tex] \sin\theta\approx\tan\theta=\frac{y}{x} [/tex]

So equation (1) is now:

[tex]a\frac{y}{x}=m\lambda [/tex] (2)

Solving (2) for x:

[tex] x=\frac{ay}{m\lambda}=\frac{(0.75\times10^{-3})(0.85\times10^{-3})}{1(587.5\times10^{-9})}\approx1.08m [/tex]

b) As you can see on the figure below a maximum is approximately between the two adjacent minimums, because the diffraction pattern is approximately symmetric respect the center of the screen the width of the central maximum is 2*0.850mm = 1.7 mm.

Answer:

so throwers new velocity = 2.18032m/s

so catchers new velocity = 0.02577m/s

Explanation:

Directly by conservation of momentum we can write

[tex]m_1u_1+m_2u_2= m_1v_1+m_2v_2[/tex]

let x be the thrower's new velocity

(70+0.042)×2.2 + 57×0 = 70× x +0.042×35 +57×0

x = 2.18032m/s

so the velocity of 70 kg man = 2.18032m/s

so throwers new velocity = 2.18032m/s

now again by conservation of momentum

0.042×35 = (57+0.042) ×y

y = 0.02577m/s

so catchers new velocity = 0.02577m/s

Answer: To form a cloud, the air that rises must cool to the point where some of the water vapor molecules "clump together" at a faster pace than they are pulled apart by their thermal energy. These molecules then condense to form the clouds and water droplets.

We can see here that Cloud formation in the atmosphere requires two main conditions: the presence of water vapor and the cooling of air.

The atmosphere is a layer of gases that surrounds a planet or celestial body, held in place by gravity. On Earth, the atmosphere is the layer of gases that envelops the planet and sustains life. It plays a crucial role in protecting and supporting life on Earth by providing essential elements, regulating temperature, and facilitating various atmospheric processes.

Clouds play a crucial role in the Earth's climate system by reflecting sunlight back into space (resulting in cooling) and trapping heat radiated from the Earth's surface (resulting in warming).

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Answer:

8000

Explanation:

cause in the problem we dont have any ext Forces we know that the momentum of system is constant.

Fext=0

P1 + P2 = P1' + P2'

P2 = 0

5000 = -3000 + P2'

P2' = 5000+3000 = 8000

Final answer:

The linear velocity of the space telescope is about 17,193.2 miles per hour when rounded to the nearest tenth. This is calculated using the orbit radius of 4340 miles and the orbital period of 1.5833 hours.

Explanation:

To calculate the linear velocity of a space telescope traveling around Earth, we need to use the formula v = 2πr / T, where v is the linear velocity, r is the radius of the orbit, and T is the orbital period. To find the orbit radius, we add Earth's radius and the altitude of the telescope above Earth's surface: r = 3960 miles + 380 miles = 4340 miles.

Next, we convert the orbital period from minutes to hours. There are 60 minutes in an hour, so T = 95 minutes / 60 minutes/hour = 1.5833 hours. We can then plug the radius and period into the formula to find the linear velocity: v = 2 x π x 4340 miles / 1.5833 hours = 17,193 miles/hour. When rounded to the nearest tenth, the linear velocity is approximately 17,193.2 miles per hour.

Answer:

(A) COP = 2.64

(B) rate of heat absorption= 1.9637 kW

Explanation:

mass flow rate (m) = 0.018 kg/s

work input (Win) = 1.2kW

inlet pressure (P1) = 800kPa

inlet temperature (T1) = 35 degree Celsius

h1 = 271.24 KJ/Kg

outlet pressure (P2) = 800 kPa

outlet temperature (T2) = ?

entalphy (h2) = 95.48 KJ/Kg

The entalphies are gotten from tables for refrigerant 134a at the temperatures and pressures above

(A) COP = Qh ÷ Win

     where Qh  = m(h1 -h2) from the energy balance equation

     Qh = 0.018 ( 271.24 - 95.48 ) = 3.1637 kW

     COP = 3.1637 ÷ 1.2 = 2.64

(B) rate of heat absorption = Qh - Win

    = 3.1637 - 1.2 = 1.9637 kW

The COP of a heat pump is calculated by using the formula COP = Q_H/W, where Q_H is the heat delivered to the house and W is the work done. Utilizing the specific enthalpies and flow rate, Q_H can be calculated. Subsequently, the rate of heat absorption from the outside can be deduced using Q_L = Q_H - W.

The thermal efficiency or COP (Coefficient of Performance) of the heat pump can be calculated using the equation: COP = Q_H/W where Q_H is the heat delivered to the house and W is the work input. In this case, since the fluid leaves the condenser as a saturated liquid, Q_H = m_dot*(h_1 - h_2), where h_1 and h_2 are the specific enthalpies at the state 1 and state 2 and m_dot is the mass flow rate of refrigerant.

From the saturated liquid tables, we know that the specific enthalpy h_2 = 257 kJ/kg for Refrigerant-134a at 800 kPa. Thus, Q_H can be calculated and this value (in kW) can be used to calculate COP.

Then, to answer part (b), the rate of heat absorption from the outside air can be calculated using the equation Q_L = Q_H - W. Q_L is the rate of heat absorption, Q_H is the heat delivered to the house and W is the power absorbed by the compressor.

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Answer:

option A

Explanation:

The correct answer is option A

People fighting forest fire carry emergency tent which has a shiny outer surface because the radiation of the heat which is downward toward firefighter the aluminium tents reflects the heat from the fire.

Aluminium Reflects 95 % of the infrared heat that hit the shiny surface of aluminium i.e. it is used by the firefighter to prevent from the heat radiation.

Final answer:

Emergency tents with shiny aluminum outer surfaces protect firefighters from heat primarily by reflecting infrared radiation. Convection plays a lesser role as hot air rises, and conduction is minimal. Radiative heat, the main form of heat transfer from fire, is what the tents are designed to protect against.

Explanation:

The reason emergency tents with shiny aluminum outer surfaces help firefighters when they lie under them to block heat from burning trees overhead is due to the tent's ability to reflect infrared radiation. Heat from fires is primarily transferred through radiation, particularly infrared radiation, which the shiny aluminum surface is effective at reflecting away. This reflection helps to protect the firefighter by reducing the amount of heat that reaches them. Convection plays a smaller role in transferring heat downward in this scenario, since hot air tends to rise, and conduction is negligibly slow here, especially from the fire to the tent. Therefore, the tents are designed to reflect the intense radiative heat that a fire emits, which is the main mechanism at play in this scenario for heat transfer.

The intensity of the sound will be B. Nine times lower

Explanation:

The intensity of a sound follows an inverse square law, which means that it is inversely proportional to the square of the distance from the source:

[tex]I\propto \frac{1}{r^2}[/tex]

where

I is the intensity

r is the distance from the source

In this problem, the siund has an intensity of I when the receiver is placed at a distance r from the source.

Later, the receiver is placed three times farther away, so the new distance is

r' = 3r

Therefore, the new intensity of the sound will be:

[tex]I'\propto \frac{1}{r'^2}=\frac{1}{(3r)^2}= \frac{1}{9} (\frac{1}{r^2})= \frac{1}{9}I[/tex]

Therefore, the intensity of the sound received will be nine times lower.

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Answer:     B. Nine times lower

Explanation:

Answer:

The angular momentum in this case is [tex] \mathbf{24\,\frac{kg\,m^{2}}{s}} [/tex]

Explanation:

The angular momentum of a point mass moving around an axis of rotation is the cross product between the distance of the object to the axis (r) of rotation and the linear momentum (p) of the particle:

[tex] \overrightarrow{L}=\overrightarrow{r}\times\overrightarrow{p} [/tex] (1)

But linear momentum is defined as mv, so (1) is:

[tex]\overrightarrow{L}=\overrightarrow{r}\times m\overrightarrow{v} [/tex](2)

And its magnitude is:

[tex]L=rmv*\sin\theta=(4)(2)(3)\sin(90)=\mathbf{24\,\frac{kg\,m^{2}}{s}} [/tex] (3)

It is important to note that [tex] \theta [/tex] is the angle between the radius vector and the velocity vector, because the axis of rotation is perpendicular to the circle and through its center this angle is equal to 90° and [tex] \sin(90) = 1 [/tex]

Answer:

B. the stars of spectral type A and F are considered reasonably to have habitable planets but much less likely to have planets with complex plant - or animal - like life.

Explanation:

The appropriate spectral range for habitable stars is considered to be "late F" or "G", to "mid-K" or even late "A". This corresponds to temperatures of a little more than 7,000 K down to a little less than 4,000 K (6,700 °C to 3,700 °C); the Sun, a G2 star at 5,777 K, is well within these bounds. "Middle-class" stars (late A, late F, G , mid K )of this sort have a number of characteristics considered important to planetary habitability:

• They live at least a few billion years, allowing life a chance to evolve. More luminous main-sequence stars of the "O", "B", and "A" classes usually live less than a billion years and in exceptional cases less than 10 million.

• They emit enough high-frequency ultraviolet radiation to trigger important atmospheric dynamics such as ozone formation, but not so much that ionisation destroys incipient life.

• They emit sufficient radiation at wavelengths conducive to photosynthesis.

• Liquid water may exist on the surface of planets orbiting them at a distance that does not induce tidal locking.

Thus , the stars of spectral type A and F are considered reasonably to have habitable planets but much less likely to have planets with complex plant - or animak - like life.

Answer

given,

number of dog = 8

mass of each dog= 19 Kg

mass of sled = 210 Kg

average force = 185 Nss

a) writing all the horizontal force

   force acting by dog - friction force = (M + 8m) a

   8 F_d - μ m g = (M + 8m) a

assuming coefficient of friction of snow be μ = 0.14

    8 x 185 - 0.14 x 210 x 9.8 = (210 + 8 x 19 ) x a

               a = 3.29 m/s²

b)  the kinetic friction of coefficient is less than static friction

 hence, we can suggest that acceleration of the sled will increase once the sled start to move.

                a > 3.29 m/s²

Answer:

See explanation below

Explanation:

To do this, we need the relation between a fermi and angstrom. We know the relation between the angstrom and meters, and fermi and meters, so, we can actually solve this by doing the conversion of meters.

1 A = 1x10^-10 m

1 m = 1 A / 1x10^-10 m

1 m = 1x10^10 A

Now if we do the same thing with the fermi:

1 f = 1x10^-15 m

1 m = 1 f / 1x10^-15 m

1 m = 1x10^15 f

then:

1x10^10 A = 1x10^15 f

A/f = 1x10^10 / 1x10^15

A/f = 1x10^-5

Answer:

Rate of plane in still air = P = W (t1 +t2)/ (t1-t2)

Rate of wind in still air = W = P (t1 - t2)/(t1 + t2)

Explanation:

Assuming speed of plane are the same on both trips

Rate (D/t1) = (P-W).... EQU 1 going from city a to b

Rate (D/t2) = (P +W)...Equ2 going back to city a

Where t1 is not equal to t2

Where D=distance between two cities

P &W are the speed of plane and wind

t1 &t2 = time taken for travel

Equ 1 & equ 2 becomes

D = ( P - W ) t1.. equ3

D = ( P + W ) t2 equa4

Equating equ 3 and 4

Pt1 - Wt1 = Pt2 +Wt2

P ( t1 - t2) = W ( t1 + t2)

Rate of plane in still air = P = W (t1 +t2)/ (t1- t2)

Rate of wind in still air = W = P (t1 - t2)/(t1 + t2)