The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.

Select one:
a. 52.8
b. 728
c. 0.198
d. 3490

Answer:

a. It is equal to zero

Explanation:

As the possible results of a continuous random variable are infinite, it is most common to talk about probabilities on intervals; A singular and particular value is so difficult to obtain in an experiment because there are infinite possibilities, and a specific value is just a very little part of the possibilities.

That is the reason why, as a definition, that probability is always zero when you have a continuous random variable.

The probability that a continuous random variable takes a specific value is zero; instead, probabilities are defined over intervals as found using the probability density function.

The probability that a continuous random variable takes any specific value is equal to zero. This is because every point in a continuous space has an infinitely small probability, and hence, when we speak about probabilities for continuous random variables, we talk in terms of intervals rather than specific values. This is reflected in the probability density function (pdf), which provides the likelihood over an interval. Calculating the probability for an event involving a continuous random variable involves finding the area under the pdf curve between two points that define the range of interest.

As an example, if we have P(x < 5) = 0.35, it follows that P(x > 5) = 1 - P(x < 5) = 0.65, given that the total area under the pdf curve sums up to 1. This principle illustrates how continuous probability distributions work and why probabilities for specific values are not feasible.

Answer:

Explanation:

To solve the problem, we must know the kind of compounds we are dealing with.

For the first compound, P1 and second compound P2:

                                N                       O                         N                     O

Mass percent       64.17                 35.73                  47.23               52.79

Atomic mass          14                      16                         14                    16

Number of

moles            64.17/14            35.73/16            47.23/14    52.79/16      

                            4.58                  2.23                     3.37                  3.30

Simplest

ratio                 4.58/2.23            2.23/2.23             3.37/3.30         3.3/3.3

                              2                           1                             1                        1

P1 compound is N₂O

P2 compound is NO

These are the compounds,

   In N₂O = 28:16

          NO = 14:16

This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.

Answer:

1.17mole

Explanation:

Given parameters:

Volume of gas = 60.82L or 60.82dm³

Temperature of the gas = 31.0°C or 304K

Pressure on the gas = 367mmHg

To make calculation easier we convert the pressure from mmHg to atm.

           1 atm = 760mmHg

           367mmHg gives [tex]\frac{367}{760}[/tex]atm = 0.48atm

Solution

Assuming ideality, we can find the number of moles of the gas used. The ideal gas law combines Boyle's law, Charles's Law and Avogadro's law. It is expressed below:

                   PV = nRT

P is the pressure

V is the volume

n is the number of moles

R is the gas constant given as 0.082atmdm³mol⁻¹K⁻¹

T is the temperature in kelvin

The unknown is n, which is the number of moles.

Making n the subject of the formula, we have ;

                    n = [tex]\frac{PV}{RT}[/tex]

      n = [tex]\frac{0.48 x 60.82}{0.082x304}[/tex]= 1.17mole

The question is asking to identify the number of moles in a gas given certain conditions using the Ideal Gas Law (PV=nRT). We do this by first converting all units to the necessary format and then substituting them into the rearranged Ideal Gas Law equation to solve for n (moles).

The student's question is basically asking about the amount of moles in a gas under specified conditions. We can decipher this answer through the Ideal Gas Law equation which states that PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. To apply the equation, we first need to convert the given conditions to the correct units compatible with R (Ideal Gas Constant) which is typically 0.0821 L·atm/K·mol.

Once we have these conditions correctly converted, we substitute them into the Ideal Gas Law. Rearranging the equation to solve for n (moles), the equation becomes n = PV/RT. Thus, substituting our numbers in gives n = (0.483 atm*60.82 L)/ (0.0821 L·atm/K·mol * 304.15 K).

Simplifying this will give the answer for the amount of moles.

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Answer:

Explanation:

1 . periodicity  

   repeating nature of atomic structure

   Periodicity is the repeating nature or trend of an atom on the periodic table. Periodicity can be inform of ionization energy, atomic radius, nuclear charge etc.

2 . shell

     location of an electron

   Electrons are located in shells. It is where electrons are found in an atom and the probability of finding electrons there are high

3 . non-metals

     high ionization energies

    Non-metals have high ionization energies which is the energy required to remove a loosely bonded electron in an atom. Metals have low ionization energies.

4 . noble gases

       least reactive family

  Noble gases are called inert gases. They have complete electronic configuration and this makes them unreactive.

5 . neutral

       charge on a neutron

   Neutrons have no charge on them. They are subatomic particles found in the nucleus alongside the protons

6 . repel

         like charges

   Like charges repel one another

7 . attract

         unlike charges

  Unlike  charges attracts. Positve attracts negative charges.

Answer:

sorry in need  question for points

Explanation:

1 . periodicity  

  repeating nature of atomic structure

  Periodicity is the repeating nature or trend of an atom on the periodic table. Periodicity can be inform of ionization energy, atomic radius, nuclear charge etc.

2 . shell

    location of an electron

  Electrons are located in shells. It is where electrons are found in an atom and the probability of finding electrons there are high

3 . non-metals

    high ionization energies

   Non-metals have high ionization energies which is the energy required to remove a loosely bonded electron in an atom. Metals have low ionization energies.

4 . noble gases

      least reactive family

 Noble gases are called inert gases. They have complete electronic configuration and this makes them unreactive.

5 . neutral

      charge on a neutron

  Neutrons have no charge on them. They are subatomic particles found in the nucleus alongside the protons

6 . repel

        like charges

  Like charges repel one another

7 . attract

        unlike charges

 Unlike  charges attracts. Positve attracts negative charges.

Heating and cooling are the processes can change sedimentary rock into igneous rock.

When Sedimentary rocks are heated with tremendous heat and pressure, it will melt and be back again to magma. After some time it will cool and harden and will become Igneous rocks.

So we can conclude that Heating and cooling are the processes can change sedimentary rock into igneous rock.

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Answer:

Erosion and lithification

Explanation:

Answer:

C5H5N is the base and C5H5NH+ is the conjugate acid

H2O is the acid and OH− is the conjugate base

Explanation:

Hydrogen + is also called a proton

C5H5N is the base because it receives the proton (H+) and C5H5NH+ is its conjugate acid

H2O is the acid  because it gives up the proton and OH− is the conjugate base because it is capable of receiving the proton

Answer:

HNO3 is the acid and NO3- is the conjugate base

H2O is the base and H3O+ is the conjugate acid

Explanation

HNO3 is the acid and NO3− is its conjugate base, capable of receiving a proton

H2O is the base because it receives the proton and H3O+ is a conjugate acid capable of giving up the proton.

In the reactions given, C5H5N acts as the Brønsted-Lowry base and H2O as the acid in the first reaction, forming C5H5NH+ as the conjugate acid and OH- as the conjugate base. In the second reaction, HNO3 is the acid and H2O is the base, yielding H3O+ as the conjugate acid and NO3- as the conjugate base.

According to the Brønsted-Lowry theory, an acid is a substance that donates a proton (H+), and a base is a substance that accepts a proton. When an acid donates a proton, it forms its conjugate base, and when a base accepts a proton, it forms its conjugate acid. In the provided reactions:

Answer:

Explanation:

The equilibrium expression for the general equilibrium represented by the equation:

is:

Then, following that sketch, you obtain:

        (C₁₉ H₈ Br₄ O₅ S) H⁻ ⇄ (C₁₉ H₈ Br₄ O₅ S)²⁻ + H⁺

         Keq = [ (C₁₉ H₈ Br₄ O₅ S)²⁻ ] [ H⁺ ] / [ (C₁₉ H₈ Br₄ O₅ S) H⁻  ]

The square brackets are used to mean molar concentration (molariy).

Approximately 88.6 grams of ice would need to melt to lower the temperature of the water from 26 ∘C to 6 ∘C.

To determine the amount of ice that would need to melt to lower the temperature of the water, we can use the equation Q = mLf, where Q is the amount of heat transferred, m is the mass, and Lf is the latent heat of fusion. In this case, the water needs to be cooled from 26 ∘C to 6 ∘C, which is a decrease of 20 degrees. The specific heat capacity of water is 4.184 J/g °C, and the density of water is 1.0 g/mL. So, for the water to cool down, it would lose 4.184 J/g °C * 353 mL * 20 °C = 2.96 x 104 J of heat. To convert this to grams of ice, we can use the equation m = Q / Lf. The latent heat of fusion for water is 334 J/g. Substituting the values, we get m = 2.96 x 104 J / 334 J/g = 88.6 g. Therefore, approximately 88.6 grams of ice would need to melt to lower the temperature of the water from 26 ∘C to 6 ∘C.

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Approximately 3.44 grams of ice would need to melt to lower the temperature of 353 mL of water from 26 °C to 6 °C.

To calculate the amount of ice that would need to melt to lower the temperature of water, we need to use the formula Q = mL. The heat transferred to melt the ice is equal to the mass of ice multiplied by the latent heat of fusion. In this case, the initial temperature of the water is 26 °C and the final temperature is 6 °C. We need to find the mass of ice in grams, so we can use the density of water, which is 1.0 g/mL. The volume of water is given as 353 mL, so the mass of water is 353 g. Since the density of water is the same as the density of ice, we can assume that the volume of ice is also 353 mL. Therefore, the mass of ice is also 353 g. We can now calculate the amount of ice that would need to melt.

Q = mL,

mL = Q / Lf,

m = (Q / Lf) / 1000

where Q is the amount of energy absorbed or released during a phase change, Lf is the latent heat of fusion (334 J/g), and m is the mass of ice.

Substituting the values into the equation, we get:

m = (Q / Lf) / 1000 = (1.15 × 10^6 J) / (334 J/g) / 1000 = 3.44 g.

Therefore, approximately 3.44 grams of ice would need to melt to lower the temperature of 353 mL of water from 26°C to 6 °C.

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Answer:

D. supersaturated

Explanation:

The solution is said to be supersaturated. Generally, the rate of solubility of substances can be increased by grinding, stirring and heating.

For a solution that contains enough solute than it can normally dissolve at a particular temperature, we say it is supersaturated.  

The point where the additional solute crystals begins to sink to the bottom of the container points to the fact that the solution is saturated already and would no more dissolve any more solute. When the solution becomes heated, dissolution is induced and more solute begins to dissolve, this makes the solution supersaturated. This solution now contains more solute than it can normally hold.

Answer:

B. unsaturated

Explanation:

Answer:its D

Explanation:

Answer: D. Important for any information you look up, on any topic.

Explanation:

The resources can be considered as reliable and credentials when they consists of information which comes from an authentic source. Also the resource which has been verified by many reviewers who exhibit special knowledge and expertise in the related field of the topic can be considered as reliable and credential.  

Such a resource can be looked upon for retrieving desired information on any topic.  

Answer: Option A

Explanation:

Since we have a relationship between KC and KP as given below

KP=KC(RT)^dn

dn= difference in the no of gaseous products and Reactants

For A,dn= 1+1-(1+1)= 2-2=0

KP=KC(RT)^0

KP=kc(1) since a^0=1

Hence KP=KC

For B,dn=2-(2+1)=2-3=-1, hence KP not equal to KC

For C, dn=2+6-(4+3)=8-7=1

For D,dn=2-3=-1, KP is not equal to KC

So option A is correct answer

The equilibrium gas constants of the gaseous mixture are Kc and Kp.  Equilibrium constants are dependent on moles and partial pressure. Kc = Kp in [tex]\rm SO_{3}(g) + NO(g) \leftrightarrow SO_{2}(g) + NO_{2}(g).[/tex]

Kc is the equilibrium constant of the moles while Kp is of the partial pressure, the relation between these two are:

[tex]\rm Kp=Kc(RT)^{dn}[/tex]

Here dn is the difference of the amount or the number of the products and the reactants of the reaction.

The value of dn for reaction A is 1+1-(1+1)=0, since the value of the power is zero Kp will be equivalent to Kc. For B, C and D reactions the value of dn are -1, 1 and -1 respectively hence Kp is not equal to Kc.

Therefore, the reaction in option A. [tex]\rm SO_{3}(g) + NO(g) \leftrightarrow SO_{2}(g) + NO_{2}(g)[/tex] will have an equal value of Kp and Kc.

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Answer:

168.0 g

Explanation:

First thing, write a balanced chemical equation:

[tex]H_{2}SO_{4}+ 2NaHCO_{3}  ----> Na_{2}SO_{4} + 2H_{2}O+2CO_{2}[/tex]

n(H2SO4) = concentration * volume

                = 1.0 M * 2.0 L

                = 2.0 mol

According to the balanced equation, 1 mol of acid requires 2 mol of sodium bicarbonate. This means that 2 mol of acid requires 2 mol of sodium bicarbonate. What mass of sodium bicarbonate is this?

mass (NaHCO3) = number of moles * molar mass

                           = 2.0 mol * 84.0065 g/mol

                           = 168.0 g

To neutralize the 1.0 M H2SO4, you will need 336.04 g of sodium bicarbonate (NaHCO3).

To neutralize the 1.0 M H2SO4, we can use the balanced chemical equation for the reaction between sodium bicarbonate (NaHCO3) and sulfuric acid (H2SO4):

2 NaHCO3 + H2SO4 → Na2SO4 + 2 H2O + 2 CO2

From the equation, we can see that 2 moles of NaHCO3 are required to neutralize 1 mole of H2SO4. Therefore, we can determine the mass of NaHCO3 required using the molar mass and stoichiometry:

Therefore, the mass of sodium bicarbonate required to neutralize the H2SO4 is 336.04 g.

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Answer:

1.  Solid phase.

Explanation:

The  molecules in a solid are held in a definite pattern which is not true of a liquid or gas.

Answer:

Solid State

Explanation:

in the solid state of matter substances have the particles arranged in a definite geometric pattern and are constantly vibrating, the main difference is the arrangement of the particles in a definite geometric pattern, compared to the liquid state in which particles take the shape of the conteiner where they are in.

Answer:

5.4 x 10²²molecules

Explanation:

Given parameters = 2L

Unknown; number of molecules

Condition of the water vapor is at standard Temperature and Pressure

Solution

To solve this problem, we simply find the number of moles the given volume would yield at STP using the relationship below:

             Number of moles = [tex]\frac{volume occupied}{22.4}[/tex]

    Number of moles = [tex]\frac{2}{22.4}[/tex] = 0.089mole

To find the number of molecules in the solved mole of the water vapor:

we use the avogadro's constant to evaluate.

             1 mole of a water vapor = 6.02 x 10²³ molecules

             0.089 mole of water vapor =  0.54 x 10²³molecules

Number of molecules of water is 5.4 x 10²²molecules

Answer: cost of Na = 7.59

Explanation:

From the given balanced equation , 2 mol Na/2x23 g produced 1 mol of H2 gas

And cost of Na is 165 for per Kg or 1000 g Na

Then cost of Na for 2x23=46 g Na

Cost = 46x165/1000= 7.59

Answer:

$7.59

Explanation:

From the balanced reaction equation, 2moles of sodium is required to produce 1.0 mole of hydrogen.

Now, the mass of 2 moles of sodium is 23.0×2 = 46 of sodium.

The mass of sodium required in kilograms is 46/1000= 0.046Kg of sodium

If 1 Kg of sodium cost $165

0.046Kg of sodium will cost 0.046×165 = $7.59

Therefore it will cost $7.59 to produce 1.0 moles of hydrogen gas according to the equation.

Answer:

a) Higher than −34 °C because dispersion forces are stronger in iodine due to a greater number of electrons.

Explanation:

Both chlorine and Iodine are halogens. They belong to the 7th group on the periodic table.

To examine the trend of boiling point in this group we must consider the nature of the intermolecular bonds that would be formed by the molecules of these elements. We know that London dispersion forces, a type of van der Waals attraction would be more prevalent. This is so because the molecules here would be non-polar and the uneven distribution of the constantly moving electrons would initiate the intermolecular bonding.

The uneven charge distribution leads to the formation of a temporary dipole.

This makes boiling point increase down the group because more electrons becomes involved and the bond becomes stronger.

Answer:

Higher than −34 °C because dispersion forces are stronger in iodine due to a greater number of electrons.

Explanation:

Answer:

-65.897°C.

Explanation:

ΔTf = Kf.m,

where, ΔTf is the depression in freezing point.

Kf is the molal depression constant of water (Kf = 4.70°C/m).

m is the molality of the solution (m = 0.51 m).

∴ ΔTf = Kf.m = (4.70°C/m)(0.51 m) = 2.397°C.

∴ The freezing point of the solution = freezing point of pure chloroform - ΔTf = -63.5°C - 2.397°C = -65.897°C.

Answer:

c

c

Explanation:

[tex]h3po4 + 12.81 - p40.10[/tex]

Answer:

A. 837 grams of [tex]H_3PO_4[/tex] are produced when 12.81 moles of water react with an excess of [tex]P_4O_{10}[/tex]

Explanation:

The balanced chemical equation is

[tex]P_4 O_10  + 6 H_2 O > 4 H_3 PO_4[/tex]

Mole ratio of [tex]H_2 O:H_3 PO_4[/tex] is 6 : 4 or 3 : 2

As per the Equation

6 moles of water produces 4 moles of Phosphoric acid

So let us convert  

12.81 moles [tex]H_2 O[/tex] to moles [tex]H_3 PO_4[/tex] by using mole ratio and then to mass [tex]H_3 PO_4[/tex] by  multiplying with molar mass [tex]H_3 PO_4[/tex]

[tex]12.82 mol H_2 O \times \frac {(4mol H_3 PO_4)}{(6molH_2 O)} \times \frac {(98gH_3 PO_4)}{(1mol H_3 PO_4 )}[/tex]

[tex]=837g H_3 PO_4[/tex] is produced

Please note:  

Molar mass is the mass of 1 mole of the substance and its unit is g/mol

We find the molar mass by adding the atomic mass of the atoms present in it.

For example [tex]H_3  PO_4[/tex] contains 3 atoms of H, 1 atom of P and 4 atoms of O

So the molar mass

[tex]=(3\times1.008)+(31\times1)+(4\times16)=98 g/mol[/tex]

This is melting or boiling

Answer:

Objects made of stone, like marble headstones, are worn away.

Explanation:

Acid deposition on earth is mostly as a result of acid rain. Acid rain forms which oxides of non-metals such as nitrogen and carbon dissolves in rain water to produce weak acid.

This weak acid that is produced easily wears away materials made up of marble and other sculptures. The most active of the acid is weak carbonic acid produced by dissolution of carbon dioxide in rain water.

Acid deposition leads to the deterioration of objects made of stone, such as marble headstones, because of the corrosion of metals and the wearing away of stone due to acidic precipitation.

Acid deposition results from the chemical reaction of air pollutants, like sulfur dioxide (SO2) and nitrogen oxides (NOx), with the atmosphere to form acids such as nitric and sulfuric acids. These acidic compounds can fall to Earth in various forms, either as wet precipitation like rain, sleet, or snow, or as dry particles. The impacts of acid deposition are numerous and widespread, including ecological and material damage.

One of the notable consequences of acid deposition is the deterioration of objects made of stone, such as marble headstones. Acid rain and acid particles contribute to the corrosion of metals and the deterioration of paint and stone, including culturally significant statues, monuments, and other stonework. This corrosive effect leads to the loss of structural integrity and the diminishment of aesthetic and historical value.

Therefore, among the listed options, the result of acid deposition is that objects made of stone, like marble headstones, are worn away.

Answer:

3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂

Explanation:

                           3H₂SO₄ + 2Al₂(SO₄)₃  → Al₂(SO₄)₃ + 3H₂

In this type of reaction, one substance is replacing another:

                      A + BC  →  AC + B

In a single displacement reaction, atoms replace one another based on the activity series. Elements that are higher in the activity series. Also, if the element that is to replace the other in a compound is more reactive the reaction will occur. If it is less reactive, there will be no reation.

In the first equation, fluorine is more reactive than bromine. Therefore, bromine cannot replace bromine.

In the second equation, the displacement is between hydrogen and aluminium. Hydrogen is lower in the activity series, this implies that aluminum will replace it.

The balanced equation for a single displacement reaction is 3H2SO4 + 2Al
ightarrow Al2(SO4)3 + 3H2, where aluminum displaces hydrogen in sulfuric acid to form aluminum sulfate and hydrogen gas.

To identify the balanced chemical equation that represents a single displacement reaction, we can look at the provided options. A single displacement reaction is a type of chemical reaction where one element is replaced by another in a compound. We can consider the following valid general form for a single displacement reaction: A + BC
ightarrow B + AC, where A replaces B in the compound BC.

Now, the correct balanced equation among the provided examples that represents a single displacement reaction is:

This equation follows the pattern of a single displacement reaction, where aluminum (Al) displaces the hydrogen (H) in sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3) and hydrogen gas (H2). The equation is also balanced, with equal numbers of each type of atom on both sides of the equation.

Answer:

The remain gases are [tex]o_{2}_{(g)}[/tex] and [tex]NO_{2}_{(g)}[/tex]

Pressure of [tex]O_{2}_{(g)}[/tex] [tex]1.09 atm O_{2}_{(g)}[/tex]

Pressure of [tex]NO_{2}_{(g)}[/tex] [tex]1.09 atm NO_{2}_{(g)}[/tex]

Explanation:

We have the following reaction

[tex]2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}[/tex]

Now we calculate the limit reagents, to know which of the two gases is completely depleted and which one is in excess.

Excess gas will remain in the tank when the reagent limits have run out and the reaction ends.

To calculate the limit reagent, we must calculate the mols of each substance. We use the ideal gas equation

[tex]PV= nRT[/tex]

We cleared the mols

[tex]n=\frac{PV}{RT}[/tex]

PV=nrT

replace the data for each gas

Constant of ideal gases

[tex]R= 0.082\frac{atm.l}{mol.K}[/tex]

Transform degrees celsius to kelvin

[tex]25+273=298K[/tex]

[tex]NO_{g}[/tex]

[tex]n=\frac{0.500atm.3.90l}{298k.0.082\frac{atm.l}{k.mol} } \\ \\ n=0.080mol NO_{(g)} \\[/tex]

[tex]O_{2}_{(g)[/tex]

[tex]n=\frac{1atm.2.09l}{298k.0.082\frac{atm.l}{k.mol} } \\ \\ n=0.086mol O_{2}_{(g)} \\[/tex]

Find the limit reagent by stoichiometry

[tex]2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}[/tex]

[tex]0.086mol O_{2}_(g).\frac{2mol NO_{(g)} }{1mol O_{2}_{(g)} } =0.17mol NO_{(g)}[/tex]

Using [tex]O_{2}_{(g)}[/tex]as the limit reagent produces more [tex]NO_{(g)}[/tex] than I have, so oxygen is my excess reagent and will remain when the reaction is over.

[tex]NO_{(g)}[/tex]

[tex]2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}\\ \\ 0.080mol NO_{(g)}.\frac{1mol O_{2}_ {(g)} }{2mol NO_{(g)} } =0.04mol O_{2}_{(g)}[/tex]

Using [tex]NO_{(g)}[/tex] as the limit reagent produces less [tex]O_{2}_{(g)}[/tex] than I have, so [tex]NO_{(g)}[/tex]  is my excess reagent and will remain when the reaction is over.

Calculate the moles that are formed of [tex]NO_{2}_{(g)}[/tex]  

[tex]2NO_{(g)} +O_{2}_{(g)}\longrightarrow 2NO_{2}_{(g)}\\ \\ 0.080mol NO_{(g)}.\frac{2mol NO_{2}_ {(g)} }{2mol NO_{(g)} } =0.080mol NO_{2}_{(g)}[/tex]

We know that for all [tex]NO_{(g)}[/tex] to react, 0.04 mol [tex]O_{2}_{(g)}[/tex] is consumed.

we subtract the initial amount of [tex]O_{2}_{(g)}[/tex] less than necessary to complete the reaction. And that gives us the amount of mols that do not react.

[tex]0.086-0.04= 0.046[/tex]

The remain gases are[tex]O_{2}_{(g)}[/tex] and [tex]NO_{2}_{(g)}[/tex]

calculate the volume that gases occupy  

[tex]0.080 mol NO_{2}_{(g)} .\frac{22.4l NO_{2}_{(g)} }{1molNO_{2}_{(g)} }}  =1.79 lNO_{2}_{(g)}[/tex]

[tex]0.046 mol O_{2}_{(g)} .\frac{22.4 l O_{2}_{(g)} }{1molO_{2}_{(g)} }}  =1.03 l O_{2}_{(g)}[/tex]

Calculate partial pressures with the ideal gas equation

[tex]PV= nRT[/tex]

[tex]P=\frac{nRT}{V}[/tex]

Pressure of [tex]O_{2}_{(g)}[/tex]

[tex]P=\frac{0.046mol.0.082\frac{atm.l}{K.mol} 298K}{1.03l}= 1.09 atmO_{2}_{(g)}[/tex]

Pressure of [tex]NO_{2}_{(g)}[/tex]

[tex]P=\frac{0.080mol.0.082\frac{atm.l}{K.mol} 298K}{1.79l}= 1.09 atmNO_{2}_{(g)}[/tex]

Answer:

It will remain O₂ and NO₂, with partial pressures: pO₂ = 0.186 atm, and pNO₂ = 0.325 atm.

Explanation:

First, let's identify the initial amount of each reactant using the ideal gas law:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas equation (0.082 atm.L/mol.K), and T is the temperature (25°C + 273 = 298 K).

n = PV/RT

NO:

n = (0.500*3.90)/(0.082*298)

n = 0.0798 mol

O₂:

n = (1.00*2.09)/(0.082*298)

n = 0.0855 mol

By the stoichiometry of the reaction, we must found which reactant is limiting and which is in excess. The limiting reactant will be totally consumed. Thus, let's suppose that NO is the limiting reactant:

2 moles of NO ------------------ 1 mol of O₂

0.0798 mol ------------------- x

By a simple direct three rule:

2x = 0.0798

x = 0.0399 mol of O₂

The number of moles of oxygen needed is lower than the number of moles in the reaction, so O₂ is the limiting reactant, and NO will be totally consumed. The number of moles of NO₂ formed will be:

2 moles of NO --------------- 2 moles of NO₂

0.0798 mol ---------------- x

By a simple direct three rule:

x = 0.0798 mol of NO₂

And the number of moles of O₂ that remains is the initial less the total that reacts:

n = 0.0855 - 0.0399

n = 0.0456 mol of O₂

The final volume will be the total volume of the containers, V = 3.90 + 2.09 = 5.99 L, so by the ideal gas law:

PV = nRT

P = nRT/V

O₂:

P = (0.0456*0.082*298)/5.99

P = 0.186 atm

NO₂:

P = (0.0798*0.082*298)/5.99

P = 0.325 atm

Explanation:

Atomic mass means the sum of total number of protons and neutrons present in an atom.

When an atom is neutral then number of protons equal the number of electrons.

Mass of a proton equals to 1.007276 u, mass of neutron equals to 1.008664 u.

For example, in a [tex]^{19}_{9}F[/tex] atom there are total 9 protons and number of neutrons is 19 - 9 = 10.

Since, it is a neutral atom so number of electrons will also be 9.

So, total mass will be calculated as follows.

                  Total mass = 9 (mass of electron + mass of proton)

                                      = 9 (1.007825 u)

                                      = 9.07043 u

Therefore, we can conclude that total mass of protons and electrons in [tex]^{19}_{9}F[/tex] is  9.07043 u.

The total mass of the protons and electrons in 19 9F is approximately 9.07065 amu. This calculation is made by multiplying the number of each particle by their respective masses and summing the results.

In order to calculate the total mass of the protons and electrons in 19 9F, you first need to understand that the number '9' represents the atomic number, which is the number of protons in the atom, and hence, in a neutral atom, the number of electrons as well. The mass of a proton is roughly 1.0073 amu and the mass of an electron is approximately 0.00055 amu. With 9 protons and 9 electrons, the total mass would be (9 protons * 1.0073 amu/proton)+(9 electrons * 0.00055 amu/electron).

So, the mass of the protons and electrons is equal to 9.0657 amu for the protons and 0.00495 amu for the electrons. Adding these together gives a total mass of approx 9.07065 amu.

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Answer: [tex]6.4\times 10^{-7}M[/tex].

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n= moles of solute

[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.6597g}{158g/mol}=0.004mole[/tex]  

[tex]V_s[/tex] = volume of solution in ml = 500 ml

[tex]Molarity=\frac{0.004\times 1000}{500}=0.008M[/tex]

According to the dilution law:

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock  solution = 0.008 M

[tex]V_1[/tex] = volume of stock solution = 2 ml

[tex]M_2[/tex] = molarity of resulting solution = ?

[tex]V_2[/tex] = volume of resulting solution = 1000 ml

[tex]0.008\times 2 ml=M_2\times 1000ml[/tex]

[tex]M_2=0.000016M[/tex]

According to the dilution law:

[tex]M_1V_1=M_2V_2[/tex]

where,

[tex]M_1[/tex] = molarity of stock  solution = 0.000016 M

[tex]V_1[/tex] = volume of stock solution = 10 ml

[tex]M_2[/tex] = molarity of resulting solution = ?

[tex]V_2[/tex] = volume of resulting solution = 250 ml

[tex]0.000016\times 10 ml=M_2\times 250ml[/tex]

[tex]M_2=0.00000064M=6.4\times 10^{-7}M[/tex]

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

Therefore, the concentration of of the final solution is [tex]6.4\times 10^{-7}M[/tex].

A solution is prepared by dissolving 0.6597 g of KMnO₄ in a 500.0 mL volumetric flask and then is subjected to 2 successive dilutions. The final molarity of the solution is 6.680 × 10⁻⁷ M.

A solution is prepared by dissolving 0.6597 g of KMnO₄ in a 500.0 mL volumetric flask and then is subjected to 2 successive dilutions.

The initial molarity of the solution is:

[tex]M = \frac{mass\ solute }{molar\ mass\ solute \times liters\ solution} = \frac{0.6597g}{158.03g/mol \times 0.5000L } = 8.349 \times 10^{-3} M[/tex]

A 2.000−mL (V₁) sample of this solution was transferred to a 1000−mL (V₂) volumetric flask and diluted to the mark with water. We can calculate the final concentration using the dilution rule.

[tex]C_2 = \frac{C_1 \times V_1 }{V_2} = \frac{(8.349 \times 10^{-3}M )\times 2.000mL }{1000mL} = 1.670 \times 10^{-5}M[/tex]

10.00 mL (V₁) of the diluted solution was transferred to a 250.0−mL (V₂) flask and diluted to the mark with water. We can calculate the final concentration using the dilution rule.

[tex]C_2 = \frac{C_1 \times V_1 }{V_2} = \frac{(1.670 \times 10^{-5}M )\times 10.00mL }{250.0mL} = 6.680 \times 10^{-7}M[/tex]

A solution is prepared by dissolving 0.6597 g of KMnO₄ in a 500.0 mL volumetric flask and then is subjected to 2 successive dilutions. The final molarity of the solution is 6.680 × 10⁻⁷ M.

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Answer: The enthalpy of the formation of [tex]AgNO_2(s)[/tex] is coming out to be -44.35 kJ/mol.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as [tex]\Delta H^o[/tex]

The equation used to calculate enthalpy change is of a reaction is:  

[tex]\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)][/tex]

For the given chemical reaction:

[tex]AgNO_3(s)\rightarrow AgNO_2(s)+\frac{1}{2}O_2(g)[/tex]

The equation for the enthalpy change of the above reaction is:

[tex]\Delta H^o_{rxn}=[(1\times \Delta H^o_f_{(AgNO_2)})+(\frac{1}{2}\times \Delta H^o_f_{(O_2)})]-[(1\times \Delta H^o_f_{(AgNO_3)})][/tex]

We are given:

[tex]\Delta H^o_f_{(AgNO_3)}=-123.02kJ/mol\\\Delta H^o_f_{(O_2)}=0kJ/mol\\\Delta H^o_{rxn}=78.67kJ[/tex]

Putting values in above equation, we get:

[tex]78.67=[(1\times \Delta H^o_f_{(AgNO_2)})+(\frac{1}{2}\times 0)]-[1\times (-123.0))]\\\\\Delta H^o_f_{(AgNO_2)}=-44.35kJ/mol[/tex]

Hence, the enthalpy of the formation of [tex]AgNO_2(s)[/tex] is coming out to be -44.35 kJ/mol.

The standard enthalpy of formation AgNO2(s) is calculated from the standard enthalpy change for the thermal decomposition of silver nitrate and the standard enthalpy of formation of AgNO3(s). It is found to be -44.35 kJ/mol.

This question is based on the calculation of the standard enthalpy of formation for AgNO2(s). The standard enthalpy change ΔH for the thermal decomposition of silver nitrate is given as 78.67 kJ according to the following equation: AgNO3(s) → AgNO2(s) + 1 2 O2(g). Additionally, we know that the standard enthalpy of formation of AgNO3(s) is −123.02 kJ/mol.

The standard enthalpy of formation for AgNO2 can be calculated using the formula ΔHf [AgNO2] = ΔH [reaction] + ΔHf [AgNO3]. Substituting the given values, we get ΔHf [AgNO2] = 78.67 kJ/mol + (-123.02 kJ/mol) = -44.35 kJ/mol. Therefore, the standard enthalpy of formation of AgNO2(s) is -44.35 kJ/mol.

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Answer:

Here's what I get.

Explanation:

Quinine contains phosphors, substances that glow when they are hit with certain wavelengths of light.

The phosphors in quinine absorb UV light, which is invisible to our eyes.

Electrons in the phosphors absorb the UV energy and are excited to higher energy levels.

When the electrons drop back to lower energy levels, they emit some of this energy as a glowing blue visible light.  

Answer:

The amino acids tryptophan, phenylalanine and tyrosine are aromatic amino acids. That means they have in their structure an aromatic ring. Reagents like Coomasie Blu can react with an amino acid in an unspecific way. UV spectroscopic is a specific technic for identifying aromatic amino acids

Explanation:

Commasie Blu reagent has a Sulphate group (negative) which reacts with the positive part of the amino group. All amino acids have an amine group. It is because of that they have their name.  

On another hand, Aromatic amino acids can absorb ultraviolet light because it makes resonate the bonds pi in the aromatic ring.  

In conclusion, with Commasie Blu reagent it is possible to identify amino acids and with the UV light, you can identifying aromatic amino acids.

Answer:

1st image, 17.79 g Mg(NO3)2

2nd image 1.47 mol NH3

3rd image Molar Mass Al(OH)3 = 78 g/mol

Explanation:

1st image

Molar Mass  Mg(NO3)2 = 148. 31 g/mol

0,12 mol Mg(NO3)2 x (148, 31 g Mg(NO3)2 / 1 mol Mg(NO3)2) = 17.79 gMg(NO3)2

2nd image

Molar Mass  NH3 = 17g/mol

25 g NH3 x ( 1 mol NH3/ 17 g NH3) = 1.47 mol NH3

3rd image

Molar Mass Al(OH)3 = 1 Al *(27) + 3 O * (16) + 3 H * (1) = 78 g/mol

Answer:

1. Gas

2. Liquid

3. Solid

4. Gas

5. Solid

Hope this helps!

The gaseous state is characterized by the lowest density and is influenced by temperature and pressure changes. The liquid state has an indefinite shape and a higher density. The solid state has particles that are less free to move around than in the other states.

1. This state is characterized by the lowest density of the three states. This describes the gaseous state, as gas particles are spread out and not closely packed together.

2. This state is characterized by an indefinite shape and high density. This refers to the liquid state, which adapts its shape to fit its container but has particles that are still relatively close together, contributing to a higher density than gases.

3. Temperature changes significantly influence the volume of this state. This is typical of the gaseous state, as gases expand or contract significantly with temperature changes according to the Ideal Gas Law.

4. Pressure changes influence the volume of this state more than the other two states. This also pertains to the gaseous state, where pressure changes can lead to notable volume changes, as predicted by the Ideal Gas Law.

5. In this state, constituent particles are less free to move around than in other states. This describes the solid state, where particles are in fixed positions and can only vibrate in place.

The correct answer is option E.

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ions  concentration in a solution. Mathematically written as:

[tex]pH=-\log[H^+][/tex]

The pOH of the solution is defined as negative logarithm of hydroxide ions  concentration in a solution. Mathematically written as:

[tex]pOH=-\log[OH^-][/tex]

The sum of ph and pOH is equal to 14.

pH + pOH = 14

A solution has a pH of 4.20.

[tex]pOH=14-pH=14-4.20=9.8[/tex]

[tex]pOH=9.8=-\log[OH^-][/tex]

[tex][OH^-]=1.58\times 10^{-10} M\approx 6.0\times 10^{-10} M[/tex]

Hence, the correct answer is option E.

Answer:

E. 1.6 x 10 -10 M is the correct answer