To select the center of a line what option must be selected? A. Ortho B. Dynamic input C. Object snap

Answers

Answer 1

Answer:

The correct answer is c. object snap  

Explanation:

In Autocad, the object snap is defined as a drawing aid that is used together with other different commands to help to draw accurately.  It also allows snapping onto a specific object location when there is a picking point. and thus, it helps to select the center of a line.


Related Questions

Different between boring and turning?

Answers

Boring is not interesting. Turning is a place where a road branches off another.

Answer:

The difference between them lies in the area of the workpiece from which the material is removed. Turning is designed to remove material from the external surface of a workpiece, whereas boring is designed to remove material from the internal surface of a workpiece.

Explanation:

The point where all three phases coexist on a P-T diagram.

Answers

Answer:

The point where all three phases coexist on a P-T diagram is called triple point.

Explanation:

A phase diagram of a substance is a graphical representation of the transition of its physical state under various temperature and pressure conditions.

A typical phase diagram usually consists of:

(A) Fusion curve - The curve that shows that the solid and the liquid state in in equilibrium with each other.

(B) Vaporization curve - The curve that shows that the liquid and the gaseous state in in equilibrium with each other.

(C) Sublimation curve - The curve that shows that the solid and the gaseous state in in equilibrium with each other.

(D) Triple point - This is a point in the phase diagram in which all the three state exists in equilibrium.

For example, Considering the phase diagram of water, The triple point occurs at a pressure of 0.6 kPa and 0.01⁰C.

The phase diagram is shown in image below:

For water the critical temperature is 374 C, water at T- 400 C exist as vapor (____)

Answers

Answer:

The statement is False.

Explanation:

Critical temperature is defined as the temperature at and above which the liquid and the gaseous states are indistinguishable. This is the temperature at and above which the liquid cannot be liquefied.

Above critical temperature or pressure, the substance is in supercritical fluid (SCF) state. A supercritical fluid is the one in which liquid and gaseous state can not be distinguished. It can dissolve like liquids and can effuse like solids.

Water above its critical temperature exists in SCF state which is neither vapor nor liquid.

Thus, the statement is false.

Glass-ceramic is a fine-grained crystalline ceramic formed by the controlled crystallization of a ceramic. ( True , False )

Answers

The answer to the question is true

A coil of wire 8.6 cm in diameter has 15 turns and carries a current of 2.7 A. The coil is placed in a magnetic field of 0.56 T. What is the magnitude of the maximum torque that can be applied to the coil by the magnetic field?

Answers

Answer:

Explanation:

it is given that diameter = 8.6 cm

[tex]radius =\frac{8.6}{2}=4.3\ cm=4.3\times 10^{-2}\ m[/tex]

current =2.7 ampere

number of turns = 15

[tex]area =\pi r^2=3.14\times \left ( 4.3\times 10^{-2} \right )^{2}=0.005806 m^{2}[/tex]

magnetic field =0.56 T

maximum torque= BINASINΘ  for maximum torque sinΘ=1

so maximum torque==0.56×2.7×0.005806×15=0.13174 Nm

Which of the following is least likely to affect the convection heat transfer coefficient? a)- Thermal conductivity of the fluid b)-Geometry of the solid body c)-The roughness of the solid surface d)-Type of fluid motion (laminar or turbulent) e)- Fluid velocity f)- Density of the solid body g)-Dynamic viscosity of the fluid

Answers

Answer:

f)Density of the solid body

Explanation:

We know that heat transfer due to convection is given by

            Q=hAΔT

Where

A is the area ,which represent the geometry of solid body or surface.

h is the heat transfer coefficient which depends on

                             1.Thermal conductivity of fluid

                             2.Motion of fluid

                             3.Type of fluid flow(Laminar or Turbulent)

                             4.Viscosity of fluid

                             5.Surface condition

So from the above parameters ,we can say that heat transfer due to convection does not depends on density of the solid body.

               

Silicon is an intrinsic semiconductor. Adding a small amount of phosphorus provides extra electrons. As a resuit, phosphorus is an p-type dopant. (True , False )

Answers

It's an n-type dopants, as it makes the silicone n-type after the doping. so, False

The speed of sound in air is proportional to the square root of the absolute temperature. If the speed of sound is 349 m/s when the air temperature is 20 °C, what is the temperature of the air when the speed of sound is 340 m/s? Give your answer in °C, K, °F, and R (Rankine).

Answers

Given:

Let the speed of sound be represented by 'v' then

v ∝ [tex]\sqrt{T}[/tex]              (1)

[tex]v_{1}[/tex] = 349 m/s

[tex]v_{2}[/tex] = 340 m/s

[tex]T_{1}[/tex] = 20°C = 273+20 = 293 K

Formulae used:

1)  °C = K + 273

2) K = °C - 273

3) °F = 1.8°C + 32

4) °R = °F + 459.67

Solution:

From eqn (1),

[tex]\frac{v_{1}}{v_{2}} = \sqrt{\frac{T_{1}}{T_{2}}}[/tex]

[tex]T_{2}[/tex] = [tex]T_{2} = (\frac{v_{2}}{v_{1}})^{2}T_{1}[/tex]

[tex]T_{2} = (\frac{340}{349})^{2}{293}[/tex] = 278.08 K

Now, Usinf formula (1), (2), (3) and (4) respectively, we get

1) T = 293 K

2) T = 293 -278.8 = 5.08°C

3) T = 1.8(5.08) + 32=41.14°F

4) T = 41.14 + 459.67 = 500.81°R

Using the saturated table, the specific entropy of of subcooled liquid water at 75 C and 200 kPa is______

Answers

Answer Explanation :

We know that entropy is the measure of molecular randomness it is denoted by S It is a thermodynamic property of gas it is an extensive property means its depend on the mass of the the system and specific entropy is defined as the entropy per unit mass its unit is KJ/kg.k

by using standard table the specific entropy for the subcooled liquid is 1.057 KJ/kg.k standard table is used for knowing the specific entropy of different liquid and gaes

At the mid-plane of a plate in pure bending the stresses are minimum. a)True b)- False

Answers

Answer:

I'm pretty sure its true

Explanation:

How to called crystalline lattice changes at the temperature change a) oxidation; b) primary crystallization c) allotropy d) anisotropy.

Answers

Answer: (c)Allotropy

Explanation: Allotropy is defined as the feature of the material to exist in different chemical forms or state while being in the same physical state. So, allotropy responsible for maintenance of the crystalline lattices during the temperature changes and does not alter the physical state of it. It helps elements to exist in different forms by modifying the structure of the chemical state.

Convective heal transfer is defined as______

Answers

Answer: Convective heat transfer is defined as the transfer of heat from a particular place to another with the help of fluid movements.

Explanation: Convective heat also knows as convection that is transfer of heat from one place to another place by the help of fluid movements around the area having different temperatures. This process has many examples in everyday life to understand the process better.

Ex.- the melting of ice from solid to liquid form as it comes in contact of high temperature as heat surrounds the ice in form of air.

What is Potential flow?

Answers

Answer: Potential flow states about the velocity field considering it as gradient of scalar function such as the velocity potential. It is considered same as irrotational flow.

Explanation:In the study of fluid dynamics , potential flow is stated as the term for describing about the velocity field taking it as the gradient of a scalar function. Therefore, potential flow is stated by an irrotational velocity field  and there is a irrotation because of the curl of the gradient of scalar quantity is zero.Potential flow is considered same as the irrotational flow that is the particles in the fluids that do not rotate.

A nozzle in a horizontal orientation is designed to have steady flowing steam exit it with a velocity of 250 m/s. If the outlet specific enthalpy of the steam is 1,986 kJ/kg, what is the required inlet specific enthalpy? Assume that heat transfer to the surroundings and the inlet steam velocity are negligible.

Answers

Answer:

[tex]h_{1}[/tex] = 2017.25 kJ/kg

Explanation:

GIVEN DATA:

Exit velocity [tex]v_{2}[/tex] = 250 m/s

outlet enthalpy [tex]h_{2}[/tex]= 1986 kJ/kg

inlet velocity  [tex]v_{1}[/tex]= 0

heat transfer Q = 0

from steady flow energy equation(SFEE) between inlet and exit point

[tex]h_{1}+\frac{v_{1}^{2}}{2}=h_{2}+\frac{v_{2}^{2}}{2}+ Q[/tex]

[tex]h_{1}=h_{2}+\frac{v_{2}^{2}}{2}[/tex]

[tex]h_{1}[/tex]=2017.25 kJ/kg

Not a characteristic property of ceramic material (a) high temperature stability (b) high mechanical strength (c) low elongation (d) low hardness

Answers

Low hardness is not a characteristic property of ceramic material.

Answer: Option D

Explanation:

One of the most important properties of ceramic material is the hardness that the material displays. The hardness owes to the joining of brittle fracture and plastic flow that makes the material to defend against penetration.

The hardness can be tested with the Vickers test. The hardness of ceramic makes its dominance in the use of construction purpose and manufacture of products. Other general properties are less conductivity, high melting temperature, etc.

Not a characteristic property of ceramic material (d) low hardness.

(a) High temperature stability is a defining feature of ceramics, as they can withstand extreme temperatures without significant degradation.

(b) High mechanical strength is another key characteristic, making ceramics suitable for applications where strength and durability are essential.

(c) Low elongation refers to the minimal deformation under stress, which is typical of ceramics due to their brittle nature.

(d) However, low hardness is not a characteristic property of ceramics. Ceramics are known for their high hardness, making them resistant to wear and abrasion.

Which of the following is/are NOT an alloy (mark all that apply)? a. Type M tool steel b. Stainless steel c. Titanium d. Brass e. Inconel

Answers

Answer:

The correct option is : c. Titanium

Explanation:

1. Type M tool: It belongs to the high- speed group of tool steels and used as a cutting tool material. It is a multi component alloy system Fe–C–X, where X is molybdenum.

2. Stainless steel: It is also called inox steel. It is a steel alloy with about 10.5% chromium and 1.2% carbon by mass.

3. Titanium: It is a chemical element, having atomic number 22 and mass 47.867 u. It is silver lustrous transition metal with a symbol Ti.

4. Brass: It is an alloy of zinc and copper metal.

5. Inconel: It is a family of austenitic nickel-chromium based superalloys.

Therefore, Titanium is not an alloy.

A Carnot engine whose low-temperature reservoir is at 19.1°C has an efficiency of 30.7%. By how much should the Celsius temperature of the high-temperature reservoir be increased to increase the efficiency to 52.0%?

Answers

Answer:

The temperature of the high-temperature source must increase in 12.23ºC.

Explanation:

For a Carnot engine, the efficiency is defined as:

[tex]n = 1- T2/T1 [/tex]

Where T2 and T1 are the low and the high-temperature sources respectively. Therefore for the value of T2 of 19.1ºC and the n equal to 30.7% (0.307), the T1 Temperature can be calculated as:

[tex]n = T1/T1 - T2/T1[/tex]

[tex]n = (T1-T2)/T1[/tex]

[tex]T1.n = (T1-T2)[/tex]

[tex] T1-T1.n =T2[\tex]

[tex] T1(1-n) =T2[/tex]

[tex] T1 =T2/(1-n)[/tex]

[tex] T1 = 19.1\ºC /(1-0.307)[/tex]

[tex] T1 = 27.56\ºC[/tex]

Then for the new effciencie n' of 52% (0.52) the new temeperature T1' will be:

[tex] T1' =T2/(1-n')[/tex]

[tex] T1' = 19.1\ºC /(1-0.52[/tex]

[tex] T1' = 39.79\º C[/tex]

Finally the increment of temperature is:

[tex] AT1 =T1'-T1[/tex]

[tex] AT1 =39.79\º C-27.56\º C[/tex]

[tex] AT1 =12.23\º C[/tex]

[tex] AT1 =12.23\º C[/tex]

Carbon dioxide at 20°C flows in a pipe at a rate of 0.005 kg/s. Determine the minimum diameter required if the flow is laminar (answer in m).

Answers

Answer:

the required diameter is 0.344 m

Explanation:

given data:

flow is laminar

flow of carbon dioxide Q = 0.005 Kg/s

for  flow to be laminar,  Reynold's number must be less than 2300 for pipe flow and it is given as

[tex]\frac{\rho VD}{\mu }<2300[/tex]

arrange above equation for diameter

\frac{\rho Q D}{\mu A }<2300

dynamic density of carbon dioxide = 1.47×[tex]10^{-5}[/tex] Pa sec

density of carbon dioxide is 1.83 kg/m³

[tex]\frac{1.83\times 0.0056\times D}{1.47\times 10^{-5}\times \frac{\pi}{4} \times D^{2} }<2300[/tex]

[tex]\frac{1.83\times 0.0056}{1.47\times 10^{-5}\times \frac{\pi}{4} \times 2300}= D[/tex]

D = 0.344 m

(true/false) Moment thickness, is an index that is proportional to an increment in momentum flow due to the presence of the boundary layer. if false explain why?

Answers

Answer:

True

Explanation:

Moment thickness, is an index that is proportional to an increment in momentum flow due to the presence of the boundary layer.

Oxygen enters an insulated 14.2-cm-diameter pipe with a velocity of 60 m/s. At the pipe entrance, the oxygen is at 240 kPa and 20°C; and, at the exit, it is at 200 kPa and 18°C Calculate the rate at which entropy is generated in the pipe.

Answers

Answer:

Entropy generation==0.12 KW/K

Explanation:

[tex]s_2-s_1=C_p\ln \frac{T_2}{T_1}-R\ln \frac{P_2}{P_1}[/tex]

[tex]s_2-s_1=0.891\ln \frac{291}{293}-0.2598\ln \frac{200}{240}[/tex]

[tex]s_2-s_1=0.0412\frac{KJ}{kg-K}[/tex]

Mass flow rate= [tex]\rho\times\dfrac{\pi}{4}d^2V[/tex]

[tex]\rho_1=\dfrac {P_1}{RT_1}[/tex]

[tex]\rho_1=\dfrac {240}{0.2598\times 293}[/tex]

[tex]\rho_1=3.51\frac{kg}{m^3}[/tex]

mass flow rate=[tex]\rho_1A_1V_1[/tex]

So by putting the values

Mass flow rate=2.97 kg/s

So entropy generation=(2.97)(0.0412)

                                    =0.12 KW/K

Saturated water vapor undergoes a throttling process from 1bar to a 0.35bar. What is the change in temperature for this process? O -4.2C O -11.3C CA-17.7C O No change in temperature for a throttling process

Answers

Answer:

-25.63°C.

Explanation:

We know that throttling is a constant enthalpy process

      [tex]h_1=h_2[/tex]

From steal table

We know that if we know only one property in side the dome then we will find the other property by using steam property table.

  Temperature at saturation pressure 1 bar is 99.63°C and  Temperature at saturation pressure 0.35 bar is about 74°C .

So from above we can say that change in temperature is -25.63°C.

But there is no any option for that .

Which of the following statements are correct? (a) A substance will emit radiation at a particular wavelength only (b) All substances emit radiation (c) Only some substances emit radiation (d) Bodies black in colour are known as black bodies

Answers

Answer: b)All substances emit radiation

Explanation: This is a universal statement that all bodies emit radiations . The radiations are usually in the form of electromagnetic radiations that are being emitted in accordance with temperature that varies from body to body.Even human bodies along with any other body emit radiations These radiations are absorbed by the black body.Therefore the correct option is option(b).

In an air compressor the compression takes place at a constant internal energy and 50KJ of heat are rejected to the cooling water for every Kilogram of air. Calculate the work input for the compression stroke per kilogram of air?

Answers

Answer:

work is 50 kj

Explanation:

Given  data

heat (Q) = 50 kj

To find out

work input for the compression stroke per kilogram of air

Solution

we will apply here "first law of thermodynamics" i.e.

The First Law of Thermodynamics states that heat is a form of energy, subject to the principle of conservation of energy, that heat energy cannot be created or destroyed. It can be transferred from one location to another  location. i.e.

ΔU = Q – W                        ................1

here ΔU is change in internal energy, Q is heat and W is work done

here U = 0 because air compressor the compression takes place at a constant internal energy in question

so that by equation 1

Q = W

and Q = 50

so work will be 50 kj

What is hot tear in casting? How can we avoid it?

Answers

Answer:

Hot tear casting is the discontinuity or failures occurs during cooling or solidification phase in casting process. It is also known as hot crack

Explanation:

In case when the casting is of weak metal, when it is hot and casted, during the process residual stresses cause failures or discontinuity in casting as it cools resulting in hot tears i,e., material casted is partly liquid and partly solid.

Preventive measures:

Ensure proper mold designA no. of gates should be used to even out temperature gradient. Over heated mold parts should not be usedProper choice of mold materials

Solid rockets can experience significant 2 phase flow. a) True b) False

Answers

Answer:

the answer is false solid rockets can experience significant 2 phase flow

Stated as an equation, what is the Clausius Inequality?

Answers

Answer:

Clausius inequality is defined as, it applies in the cycle of real engine and there is negative entropy change. When the entropy given in the cycle during the environment is larger than entropy transferred into heat engine from hot reservoir. As, entropy of reversible system are zero.

Clausius Inequality is defined as:

[tex]R_2-R_1> \oint_{T_1}^{T_2}\frac{dQ}{T}[/tex]

Where R1 and R2 are not be equal.

What are "primary alpha" and "primary beta"?

Answers

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In this type of projection, the angles between the three axes are different:- A) Isometric B) Axonometric C) Trimetric D) Dimetnic

Answers

Answer:

The correct answer is C) Trimetric

Explanation:

The most suitable answer is a trimetric projection because, in this type of projection, we see that the projection of the three angles between the axes are not equal. Therefore, to generate a trimetric projection of an object, it is necessary to have three separate scales.

At any given state the specific internal energy of a gas is always greater its specific enthalpy. a)True b) False

Answers

Answer:

(b)False

Explanation:

We know that specific  Internal energy of gas u=[tex]C_v[/tex]T

      and specific enthalpy of gas h=[tex]C_p[/tex]T

If we take the case of air we know that

[tex]C_v[/tex]=0.707 KJ/Kg=K  , [tex]C_p[/tex]=1.005 KJ/Kg=K

If we take A fixed temperature T=300 K

so    u=212.1 KJ/ kg   ,h=301.5 KJ/kg

So we can say that specific enthaply of gas is always greater than its specific   internal energy.

                                 

     

Segmented solid rockets require what special component? A. Igniters B. Liners C. O-rings D. Nozzle gimbals

Answers

Answer: D) Nozzle gimbals

Explanation: Igniters are present for the ignition power in the segmented solid rocket, liners are the basic requirement in the engine of the rocket,O-rings are also a general part of the segmented solid rocket .So, these are the general purpose parts of the segmented solid rocket but nozzle gimbals are the special units of the rocket as they provide improved thrust in various direction in accordance with the rocket.So, option (d) is the correct option.

Answer:

D. Nozzle gimbals

Explanation:

Segmented solid rockets require the special component, nozzle gimbals.

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