Tom is marking the locations of active volcanoes on a world map.Explain how the locations of a volcanoes are related to earth's plates

Neither plate subducts because the crust have approximately the same density. Instead, the rocks are smashed together causing them to recrystallize due to the intense heat and pressure from the colliding plates.

Answer:

0.089.

Explanation:

Cl₂O + H₂O ⇄ 2HClO,

Kc = [HClO]²/[Cl₂O][H₂O].

[H₂O] = 0.077 M , [Cl₂O] = 0.077 M , [HClO] = 0.023 M.

∴ Kc = [HClO]²/[Cl₂O][H₂O] = (0.023 M)²/(0.077 M)(0.077 M) = 0.08922 ≅ 0.089.

Answer:

A

Explanation:

It told me

Srry if I'm late the answer to the first question about chemical changes is B. when a new substance is formed, it's going to be chemical. For example, when you burn paper, it turns into ash, which is a new substance. The burning is a chemical change. C is wrong because you can undo the mixture.

For number 2, the trick is to check if there is a carbon is double bonded to another carbon. Then it would be unsaturated. You can also check if there's a kink the chain. So therefore,

saturated is 3-methl..  and propane

unsaturated is propyne heptyne and cyclpentene

good luck!

The statement that describes a Chemical changes in hematite is B. The hematite particles rearrange to form a new substance.

The statement that describes a chemical change in hematite is B. The hematite particles rearrange to form a new substance.

A chemical change involves the formation of new substances with different chemical properties.

In this case, the rearrangement of hematite particles leads to the formation of a new substance.

Example: When hematite (Fe2O3) is heated strongly, it undergoes a chemical change and turns into magnetite (Fe3O4).

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Here we have to get the correct molecular formula of the compound.

The molecular formula of the compound is C₆H₆O₆ i.e. option C.

Let assume, the empirical formula of the compound is [tex](CHO)_{n}[/tex].

The given molar mass of the compound is 176.124 g/mole.

The percent of carbon in the compound is [tex]\frac{283.4}{692.5}[/tex]×100 = 40.924.

The percent of hydrogen in the compound is [tex]\frac{31.7}{692.5}[/tex]×100 = 4.577.

The percent of oxygen in the compound is [tex]\frac{377.4}{692.5}[/tex]×100 = 54.498.

Now the ratio of the atomic number in the compound for carbon is [tex]\frac{40.924}{12}[/tex] = 3.410

Now the ratio of the atomic number in the compound for hydrogen is [tex]\frac{4.577}{1}[/tex] = 4.577

Now the ratio of the atomic number in the compound for oxygen is [tex]\frac{54.498}{16}[/tex] = 3.406

So, the C, H and O lowest ratio is [tex]\frac{3.410}{3.406}[/tex] = 1, [tex]\frac{4.577}{3.406}[/tex] = 1 and [tex]\frac{3.406}{3.406}[/tex] = 1

Thus the empirical formula of the compound is [tex][CH_{1}O] _{n}[/tex] (where n = integer.

12n + 1n + 16n = 176.24

29n = 176.24

n = 6 (approx)

Thus the molecular formula of the compound is C₆H₆O₆.

Final answer:

By calculating the number of moles of carbon, hydrogen, and oxygen and deriving the ratio among them, it is determined that the molecular formula of the compound with a molar mass of 176.124 grams/mole is C6H8O6 (D).

Explanation:

To find the molecular formula of the compound used as a food additive with a molar mass of 176.124 grams/mole from the given decomposition data, we first need to calculate the number of moles of each element present in the given sample.

For carbon: (283.4 g) / (12.0 g/mol) = 23.62 moles
For hydrogen: (31.7 g) / (1.0 g/mol) = 31.7 moles
For oxygen: (377.4 g) / (16.0 g/mol) = 23.59 moles

Next, we divide by the smallest number of moles to get the atom ratio.
C: 23.62 / 23.59 ≈ 1
H: 31.7 / 23.59 ≈ 1.34
O: 23.59 / 23.59 = 1

The ratio of hydrogen is not a whole number, so we multiply all ratios by the smallest whole number that gives us whole number ratios for each element, which in this case would be 3 (since 1.34 is approximately 4/3).

After multiplying, the moles of each element become:
C: 1 x 3 = 3
H: 1.34 x 3 ≈ 4
O: 1 x 3 = 3

Thus, the empirical formula of the compound is C3H4O3, and the molecular formula is the same as the empirical formula because the molar mass of C3H4O3 (3(12.0) + 4(1.0) + 3(16.0) = 88.0 g/mol) is half that of the given molar mass. Therefore, the molecular formula must be C6H8O6, which is twice the empirical formula.

The correct molecular formula of the compound is D. C6H8O6.

Neutrons are very important in provide stability for an atom. When atoms are created by fusion, neutrons are included in this process. Because protons don't like each other and repel each other that's where neutrons come in.

answer: the role of a neutron in an atom holds the center of the atom so it provides the stability of the center of the atom.

hope this helps! ❤ from peachimin

The correct option is A. which is the concentration of calcium in the myofibril must decrease.

Close geometric correspondence of continental coastlines.

Answer:

As explained below

Explanation:

1. Drifting away from the continents due to the pole wandering forces.

2. Jigsaw ft puzzle that coasts of South America and those of Africa have the same geologic and tectonic origin.

3. Presence of large and long mountain chains of mountains and ranges present in all the contents that form a chain.

4. Floral and Faunal evidence found in the lands of South America and Africa and the opening of the s-shaped Atlantic ocean that separated them apart.

5. Presence of similar climatic zones over the continents of the Gondwanaland and the northern Laurentia continent.

Answer :

Example : In nuclear power plant, the energy released from the process of nuclear fission which is converted into electrical energy that is used in our homes and factories.

Example : This process occurs in the sun and stars. In this, the isotopes of Hydrogen, Tritium and Deuterium combine together to form a neutron and a helium atom under high pressure and temperature.

Answer:

B.0.456 g

Explanation:

It is that becuase if u convert miligrams to grams it is 1000mg =1g

The main function of concept mapping is: C. Organization

A map can be defined as a representation of all or some parts of the Earth drawn to scale on a flat surface.

In Science, there are different types of map and these include;

A concept map can be defined as a visual representation of information and ideas, so as to depict (illustrate) the relationships between two or more concepts while organizing them.

Hence, main function of concept mapping is for the proper organization or structuring of information and ideas in a graphic format.

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1] Find out how many moles  

2] Use Avagadro's number to find number of molecules  

1] [2.3 g (NH4)2SO4] x [1 mol (NH4)2SO4] / [132.14g(NH4)2SO4 )] = 0.017406 moles (NH4)2SO4  

2] 0.017406 moles x 6.022 x 10^23 molecules/mole = 1.05 x 10^21 molecules (NH4)2SO4

Hello!

To find the mass in grams of 100 atoms of carbon, we need to use Avogadro's number, which is 6.02 x 10^23 grams, and divide that by the total number of atoms.

Next, we would need to find how much one mole of carbon weighs. In this case, it is exactly 12 grams.

1. Divide by Avogadro's number

100 / (6.02 x 10^23) ≈ 1.66 x 10^-22  

2. Multiply by one mole of carbon

(1.66 x 10^-22) x 12 ≈ 2.0 x 10^-21

Therefore, the mass of 100 atoms of carbon is equal to about 2.0 x 10^-21 grams.

Explanation:

An atom consists of electrons, protons, and neutron. The protons and neutrons are present inside the nucleus whereas the electrons are present outside the nucleus.

These electrons revolve around the nucleus in circular motion. Therefore, an electron pair surrounds the central atom of a molecule. It is known that an electron contains a negative charge and like charges repel each other.

Hence, in an atom the force of repulsion between electron pairs pulls the atoms away from each other.

As a result, a molecules atoms are as far away from each other as they can get.

Answer:

forces between electron pairs push the atom apart

Explanation:

apex

Answer: Resulting solution will not be neutral because the moles of [tex]OH^-[/tex]ions is greater. The remaining concentration of [tex][OH^-][/tex]ions =0.0058 M.

Explanation:

Given,

[HCl]=0.100 M

[tex][HNO_3][/tex] = 0.200 M

[tex][Ca(OH)_2][/tex] =0.0100 M

[RbOH] =0.100 M

Few steps are involved:

Step 1: Calculating the total moles of [tex]H^+[/tex] ion from both the acids

moles of [tex]H^+[/tex] in HCl

[tex]HCl\rightarrow {H^+}+Cl^-[/tex]

if 1 L of [tex]HCl[/tex]solution =0.100 moles of HCl

then 0.05L of HCl solution= 0.05 [tex]\times [/tex]0.1 moles= 0.005 moles    (1L=1000mL)

moles of [tex]H^+[/tex] in HCl = 0.005 moles

Similarliy

moles of [tex]H^+[/tex] in [tex] HNO_3[/tex]

[tex]HNO_3\rightarrow H^++NO_3^-}[/tex]

If 1L of [tex]HNO_3[/tex] solution= 0.200 moles

Then 0.1L of [tex]HNO_3[/tex] solution= 0.1 [tex]\times [/tex] 0.200 moles= 0.02 moles

moles of [tex]H^+[/tex] in [tex]HNO_3[/tex] =0.02 moles

so, Total moles of [tex]H^+[/tex] ions  = 0.005+0.02= 0.025 moles     .....(1)

Step 2: Calculating the total moles of [tex][OH^-][/tex] ion from both the bases

Moles of [tex]OH^-\text{ in }Ca(OH)_2[/tex]

[tex]Ca(OH)_2\rightarrow Ca^2{+}+2OH^-[/tex]

1 L of [tex]Ca(OH)_2[/tex]= 0.0100 moles

Then in 0.5 L [tex]Ca(OH)_2[/tex] solution = 0.5 [tex]\times [/tex]0.0100 moles = 0.005 moles

[tex]Ca(OH)_2[/tex] produces two moles of [tex]OH^-[/tex] ions

moles of [tex]OH^-[/tex] = 0.005 [tex]\times [/tex] 2= 0.01 moles

Moles of [tex]OH^-[/tex] in [tex]RbOH[/tex]

[tex]RbOH\rightarrow Rb^++OH^-[/tex]

1 L of RbOH= 0.100 moles

then 0.2 [RbOH] solution= 0.2 [tex]\times [/tex] 0.100 moles = 0.02 moles

Moles of [tex]OH^-[/tex] = 0.02 moles

so,Total moles of [tex]OH^-[/tex] ions = 0.01 + 0.02=0.030 moles      ....(2)

Step 3: Comparing the moles of both [tex]H^+\text{ and }OH^-[/tex] ions

One mole of [tex]H^+[/tex] ions will combine with one mole of [tex]OH^-[/tex] ions, so

Total moles of [tex]H^+[/tex] ions  = 0.005+0.02= 0.025 moles....(1)

Total moles of [tex]OH^-[/tex] ions = 0.01 + 0.02=0.030 moles.....(2)

For a solution to be neutral, we have

Total moles of [tex]H^+[/tex] ions = total moles of [tex]OH^-[/tex] ions

0.025 moles [tex]H^+[/tex] will neutralize the 0.025 moles of [tex]OH^-[/tex]

Moles of [tex]OH^-[/tex] ions is in excess        (from 1 and 2)

The remaining moles of [tex]OH^-[/tex] will be = 0.030 - 0.025 = 0.005 moles

So,The resulting solution will not be neutral.

Remaining Concentration of [tex]OH^-[/tex] ions = [tex]\frac{\text{Moles remaining}}{\text{Total volume}}[/tex]

[tex][OH^-]=\frac{0.005}{0.85}=0.0058M[/tex]

Ca has the largest atomic radius because it is further down the periodic table than Mg, and its cation, Ca²⁺, is still larger than Mg²⁺ because it retains an extra shell of electrons.

The atomic radius tends to increase as you move down a group in the periodic table because each successive element has an additional energy level, or shell. Conversely, atomic radius generally decreases as you move from left to right across a period because the effective nuclear charge increases, pulling the electrons closer to the nucleus. In the case of ions, cations (positively charged ions) are smaller than their neutral atoms because they have lost one or more electrons, reducing electron-electron repulsion and allowing the electrons to be pulled closer to the nucleus.

In comparing Mg, Mg²⁺, Ca, and Ca²⁺, we must remember that the neutral atoms will have a larger atomic radius than their respective cations. Between Mg and Ca, Ca is larger because it is lower on the periodic table. However, for the cations, Ca²⁺ is larger than Mg²⁺ because even though they have both lost two electrons, the calcium ion still has an additional shell of electrons compared to magnesium.

Therefore, among the given species, Ca has the largest atomic radius followed by Mg, then Ca²⁺, and finally Mg²⁺ having the smallest atomic radius.

Answer: ca

Explanation: .

Answer:

Mg+2     Its D

Explanation:

DDDDDDDDDDDDDDDDDD on edge 2020

Answer:

Its D.

Explanation:

Got it correct in the question.

Jon should report his answer to one significant digit only.

When several numbers are multiplied, the number of significant digits in the final answer is determined by the number that has the least number of significant digits.

In this case, 1 has only one significant digit, whereas 2.0 has two, 3.00 has three, and 4.000 has four significant digits. Hence, 1 strongly affects the number of significant figures in the answer.

Answer: A. for those who dont like to read

Explanation:

Answer: Option (C) is the correct answer.

Explanation:

According to collision theory, more is the number of collision between the reactant molecules more will be the rate of reaction.

For example, [tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]

When we increase the concentration of reactants then it means there is increase in number of molecules. Hence, more is the number of molecules more will be the number of collisions.

Thus, we can conclude that by increasing the concentration of Mg in the reaction mixture we increase the rate of collisions between the reactants in this reaction.

Answer:

C. Increase the concentration of Mg in the reaction mixture.

Explanation:

two hydrogen atoms and one oxygen atom. hope this helped.

By the mass percentage, [tex]100[/tex] grams of the sample would contain

Which corresponds to

Hence the approximate ratio [tex]n(\text{N}) : n(\text{C}) \approx 1 : 1[/tex] and the empirical formula [tex]\text{CN}[/tex].

Apply the idea gas formula to determine the number of moles of the gas molecules present in the [tex]462 \; \text{cm}^{3} = 0.462 \; \text{L} [/tex] sample:

[tex]\begin{array}{lll}n &= & (\text{P}\cdot \text{V}) / (\text{R} \cdot \text{T})\\ & = & 1.01 \times 10^2 \times 0.462 /(8.314 \times 273) \\ &= &0.0206\; \text{mol}\end{array}[/tex]

Thus

[tex]M = m / n = 1.048 / 0.0206 = 51.0 \; \text{g} \cdot \text{mol}^{-1}[/tex]

which is approximately twice of [tex]26.02\; \text{g} \cdot \text{mol}^{-1}[/tex], formula mass for the empirical formula [tex]\text{CN}[/tex]. Hence the molecular formula [tex]\text{C}_2\text{N}_2[/tex]

The molecular formula of the compound is C2N2.

From the ideal gas equation;

PV = nRT

P = 1.01 x 10^5 Pa or 1.01 atm

V = 462 cm^3 or 0.462 L

R = 0.082 atm Lmol-1K-1

T = 273 K

n = ?

n = PV/RT

n = 1.01 atm × 0.462 L/ 0.082 atm Lmol-1K-1 × 273 K

n =0.467 /22.386

n = 0.02086 moles

Now;

Molar mass of the compound  is obtained from;

number of moles  = mass/molar mass

molar mass = mass/number of moles

molar mass =  1.048g/0.02086 moles

molar mass = 50.24 g/mol

The empirical formula of the compound is;

C - 53.8%/12,         N - 46.2%/14

C - 4.48,                 N - 3.3

Dividing through by the lowest ratio

C -4.48/3.3            N - 3.3/3.3

C - 1                       N - 1

The empirical formula is CN

The molecular formula is obtained thus;

[12 + 14]n = 50.24

n = 50.24/26

n = 2

The molecular formula of the compound is C2N2

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The nuclear fusion reaction is the source of energy in a star. In nuclear fusion reactions, the nuclei of two atoms combine to create a new atom with the release of a lot of energy. The nuclear fusion reaction takes place in the core of the star where two hydrogen atoms fuse to become one helium atom.

²₁H + ³₁H --> ⁴₂He + ¹₀n + 17.59 MeV

In the fusion reaction above deuterium fuses with tritium to form helium and releases ~18 mega electron volt of energy.

Start by determining the oxidation numbers of each element on both sides of the equation CuO(s) + H2 (g) → Cu(s) + H2O (l)

Let's start with the reactants.

In the compound CuO(s), the oxidation number of O is -2 and the oxidation number of Cu is +2. (Remember, oxygen's oxidation number is -2 unless it's in a peroxide)

In H2(g) the oxidation number of H is 0 because it is in its elemental form.

Now onto the products

The oxidation number of Cu(s) is 0 because it is in its elemental form

In H2O(l) the oxidation number of oxygen is -2, and the oxidation number of H is +1.

Now let's summarize the change in the oxidation numbers of each element.

Cu: started as +2 and became 0

O: started as -2 and became -2 (didn't change)

H: started as 0 and became +1

To determine which element was oxidized, we look at which element lost electrons, and thus became more positive. So, we can determine that H was oxidized in this reaction, because it started with the oxidation number 0 and became +1.

Answer: you are a god

Explanation:

Moles of a gas = 0.500

Volume = 2.50 L

Pressure = 13. atm

Temperature = ?

Solution:

Formula:

                       PV = n RT

Putting the values in formula:

 T = PV/nR = 13 * 2.5 / 0.5 *  0.082057

   =  32.5/0.041 = 792.68 K

                    T = 792.68 K

Answer:- Molar mass of [tex]CO_2[/tex] .

Solution:- It is a stoichiometry problem. Mass of the grill is 30.0 kg and the mass after burning the grill is also 30.0 kg. It means all the charcol is burned and the gas is given off.

2.0 kg of charcol are converted to grams which is 2000 g. Since charcol is pure solid carbon, the grams are divided by the atomic mass of carbon which is 12.

The combustion equation of charcol is written as:

[tex]C(s)+O_2(g)\rightarrow CO_2(g)[/tex]

From this balanced equation, there is 1:1 mol ratio between charcol and carbon dioxide. So, the moles of carbon dioxide gas formed are equivalent to the moles of charcol. To convert the moles of carbon dioxide to grams we multiply the moles by it's molar mass.

Carbon dioxide has one carbon and two oxygen atoms so it's molar mass = 12 + 2(16) = 12 + 32 = 44

So, 44 is the molar mass of carbon dioxide and above calculations clearly shows how and where we get this.

a. Monatomic ions

Cs is in Group 1. It has one valence electron that it can lose to form a Cs⁺ ion.

Mg is in Group 2. It has two valence electrons that it can lose to form an Mg²⁺ ion.

N is in Group 15. It can gain three valence electrons to complete its octet and form an N³⁻ ion.

b. Ionic compounds

In an ionic compound there must be the same number of positive and negative charges.

It takes three Na⁺ ions to balance the charge on one N³⁻ ion, so the formula of sodium nitride is Na₃N.

It takes three Mg²⁺ ions (charge = +6) to balance the charge on two N³⁻ ions

(charge = -6), so the formula of magnesium nitride is Mg₃N₂.

Magnesium forms a Mg²⁺ cation, cesium forms a Cs⁺ cation, and nitrogen forms an N³⁻ anion. Magnesium nitride, cesium nitride, and magnesium ceside are the ionic compounds formed, with formulas Mg₃N₂, Cs₃N, and MgCs₂, respectively. Ionic compounds must have balanced total charges.

1. (a). First, let's identify the ions that each element forms:

Magnesium (Mg) is in Group 2 of the periodic table and forms a cation by losing two electrons: Mg²⁺. Cesium (Cs) is in Group 1 and forms a cation by losing one electron: Cs⁺. Nitrogen (N) is in Group 15 and forms an anion by gaining three electrons: N³⁻.

1. (b). Next, let's determine the formulas of the ionic compounds these ions can form:

To determine the formulas, I considered the need for ionic compounds to be electrically neutral, meaning the total positive and negative charges must equal zero.