Treatment of an alpha,beta-unsaturated ketone with basic aqueous hydrogen peroxide yields an epoxy ketone. the reaction is specific to unsaturated ketones; isolated alkene double bonds do not react. on a sheet of paper, write a mechanism for the alkene to epoxide reaction. then, in the window below, draw the first intermediate in your mechanism.
Answers
After the intermediate is formed, the lone pair from the oxygen pushes back down to form the carbonyl once more and this breaks a carbon-carbon bond which attacks the oxygen of the peroxy group, ultimately substituting an -OH group and forming the final epoxide ketone product.
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What concentration of the barium ion, ba2+, must be exceeded to precipitate baf2 from a solution that is 1.00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2.45×10−5 . express your answer with the appropriate units?
Answers
Answer is: concentration of the barium ion is 0.245 M.
Chemical reaction: BaF₂ → Ba²⁺ + 2F⁻.
[F⁻] = 1.00·10⁻² M.
Ksp = 2.45·10⁻⁵.
Ksp = [Ba²⁺] · [F⁻]².
[Ba²⁺] = Ksp ÷ [F⁻]².
[Ba²⁺] = 2.45·10⁻⁵ ÷ (1.00·10⁻² M)².
[Ba²⁺] = 0.245 M.
Answer: The concentration of barium ions that must exceed to precipitate the salt is 0.245 M
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is represented as [tex]K_{sp}[/tex]
Barium fluoride is an ionic compound formed by the combination of 1 barium ion and 2 fluoride ions.
The equilibrium reaction for the ionization of barium fluoride follows the equation:
[tex]BaF_2(s)\rightleftharpoons Ba^{2+}(aq.)+2F^-(aq.)[/tex]
The solubility product for the above reaction is:
[tex]K_{sp}=[Ba^{2+}]\times [F^-]^2[/tex]
We are given:
[tex][F^-]=1.00\times 10^{-2}M\\\\K_{sp}=2.45\times 10^{-5}[/tex]
Putting values in above equation, we get:
[tex]2.45\times 10^{-5}=[Ba^{2+}]\times (1.00\times 10^{-2})^2[/tex]
[tex][Ba^{2+}]=\frac{2.45\times 10^{-5}}{(1.00\times 10^{-2})^2}=0.245M[/tex]
Hence, the concentration of barium ions that must exceed to precipitate the salt is 0.245 M
when the ph of a solution changes from a ph of 5 to a ph of 3 the hydronium ion concentration is
Answers
When the pH of a solution changes from 5 to 3, the hydronium ion concentration increases significantly.
PH of Solution:
The relationship between pH and hydronium ion concentration
[H₃O⁺] is given by the formula:
pH = -log [H₃O⁺]
To find the hydronium ion concentrations at pH 5 and pH 3:
At pH 5: [H₃O⁺] = 10⁻⁵ M
At pH 3: [H₃O⁺] = 10⁻³ M
Thus, the hydronium ion concentration increases by a factor of 100 when the pH changes from 5 to 3
What is the molality of a solution that contains 75.2 grams of AgClO4 in 885 grams of benzene? Question 5 options: 0.41 m 4.10 m 8.20 m 0.83 m
Answers
molality = moles solute / kg solvent
moles AgClO4 = 75.2 g / 207.389 g/mol
= 0.3626 mol
molality = 0.6326 mol / 0.885 kg
= 0.410 m
The asnwer is 0.41.
The molality of the solution is 0.41 molal and the correct option is option 1.
What is Molality?
Molality is also known as molal concentration. It is a measure of solute concentration in a solution. The solution is composed of two components; solute and solvent.
The number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent is known as molality.
Molality = number of moles of solute ÷ mass of solvent in kg
Given,
Mass of AgClO₄ = 75.2g
Mass of benzene = 885g
Molality = number of moles of solute ÷ mass of solvent in kg
moles of AgClO₄ = 75.2 / 207
= 0.363 moles
Molality = 0.363 / 0.885
= 0.41 molal
Therefore, the molality of the solution is 0.41 molal and the correct option is option 1.
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2no2(g)⇌n2o4(g) kp=6.7at298k a 2.35-l container contains 0.053 mol of no2 and 0.084 mol of n2o4at298k. is the reaction at equilibrium? if not, in what direction will the reaction proceed?
Answers
Q> K hence the reaction proceeds in the reverse direction.
First we must obtain the concentration of each of the species;
NO2 - 0.053 mol/2.35-l = 0.023 M
N2O4 - 0.084 mol/2.35-l = 0.036 M
Hence;
Q = [N204]/[NO2]^2
Q = [0.036]/[0.023]^2
Q = 68.05
Since Q > K, it follows that the reaction moves towards the left hand side.
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The reaction quotient Q was found to be 69.86, which is greater than the equilibrium constant Kp of 6.7. Therefore, the reaction will shift towards the formation of NO2 (g) to reach equilibrium.
Explanation:To determine whether the reaction is at equilibrium, we need to calculate the reaction quotient (Qp) and compare it with the given equilibrium constant (Kp). The reaction we are analyzing is:
2 NO2 (g) ⇌ N2O4 (g), with Kp = 6.7 at 298 K.
The reaction quotient Qp is defined similarly to Kp but for an initial or non-equilibrium state and is calculated using partial pressures. Since we are given the number of moles and the volume of the container, we can use the ideal gas law to find the partial pressures of NO2 and N2O4. However, the student question provides moles instead of partial pressures, so we will assume ideal gas behavior and calculate the reaction quotient (Q) with concentrations, which can be used in place of Qp for our rough estimation, knowing they are related in the circumstance of gasses at same temperature and pressure.
The molar concentrations are:
[NO2] = 0.053 moles / 2.35 L = 0.0226 M
[N2O4] = 0.084 moles / 2.35 L = 0.0357 M
Now we calculate the reaction quotient Q using the given concentrations:
Q = [N2O4]1 / [NO2]2
= 0.0357 / (0.0226)2
= 0.0357 / 0.000511
= 69.86
Since Q (69.86) is greater than Kp (6.7), the reaction will proceed in the direction that reduces Q to equal Kp, which is towards the formation of NO2 from N2O4.
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Calculate the freezing point of a solution containing 15 grams of kcl and 1650.0 grams of water. the molal-freezing-point-depression constant (kf) for water is 1.86 ∘c/m
Answers
Answer : The freezing point of a solution is [tex]-0.454^oC[/tex]
Explanation : Given,
Molal-freezing-point-depression constant [tex](K_f)[/tex] for water = [tex]1.86^oC/m[/tex]
Mass of KCl (solute) = 15 g
Mass of water (solvent) = 1650.0 g = 1.650 kg
Molar mass of KCl = 74.5 g/mole
Formula used :
[tex]\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of KCl}}{\text{Molar mass of KCl}\times \text{Mass of water in Kg}}[/tex]
where,
[tex]\Delta T_f[/tex] = change in freezing point
[tex]\Delta T_s[/tex] = freezing point of solution = ?
[tex]\Delta T^o[/tex] = freezing point of water = [tex]0^oC[/tex]
i = Van't Hoff factor = 2 (for KCl electrolyte)
[tex]K_f[/tex] = freezing point constant for water = [tex]1.86^oC/m[/tex]
m = molality
Now put all the given values in this formula, we get
[tex]0^oC-T_s=2\times (1.86^oC/m)\times \frac{15g}{74.5g/mol\times 1.650kg}[/tex]
[tex]T_s=-0.454^oC[/tex]
Therefore, the freezing point of a solution is [tex]-0.454^oC[/tex]
Answer:
The freezing point of the solution containing 15 grams of KCl and 1650 grams of water is [tex]\rm -0.454^\circ\;C[/tex].
Explanation:
The freezing point of the solution can be calculated by:
Molarity = [tex]\rm \frac{mass\;of\;KCl\;}{molar\;mass\;of\;KCl\;\times\;Mass\;of\;water}[/tex]
Molarity = [tex]\rm \frac{15}{74.5;\times\;1650}[/tex]
Molarity = 1.2 [tex]\rm \times\;10^-^4[/tex] M
[tex]\rm \Delta\;T\;=\;i\;\times\;K_f\;\times\;Molarity[/tex]
[tex]\rm T^\circ\;\times\;T_f\;=\;i\;\times\;K_f\;\times\;Molarity[/tex]
[tex]\rm T_f=\;2\;\times\;1.86\;\times\;1.2\;\times\;10^-^4[/tex]
[tex]\rm T_f[/tex] = [tex]\rm -0.454^\circ\;C[/tex]
The freezing point of the solution containing KCl is [tex]\rm -0.454^\circ\;C[/tex].
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Is oil used by other organisms on Earth? If yes, explain.
Answers
Sam wants to demonstrate how water changes from a solid to a gas. He places ice in a pot on a stove. What variable is causing water to change state?
A) the heat from the stove
B) the container the ice is placed in
C) the temperature of the air surrounding the ice
D) the time that has lapsed since the ice was removed from the freezer
Answers
The answer is option A "the heat from the stove".
Reason:
The answer is option A because the variable the heat from the stove is causing the ice to change into water. Its not option B because thats not in the procedures. Its not option C because it is not a variable. Its also not D because thats also not a variable.
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
Answer: Option (A) is the correct answer.
Explanation:
When Sam placed ice in a pot on a stove then there will be transfer of heat from the stove to the pot and then from the pot to the ice.
As a result, solid state of ice changes into liquid state of water because of melting of ice.
Thus, we can conclude that the heat from the stove is the variable that is causing water to change state.
Draw the lewis structure with the atoms arranged as hclo. include all non-bonding electronsand non-zero formal charges. do not draw cl with an expanded octet.
Answers
Formal charge = (Valence electrons) - (electrons shared in bonds) - (non-bonded electrons)
H: Formal charge = 1 - 1 - 0 = 0
Cl: Formal charge = 7 - 2 - 4 = +1
O: Formal charge = 6 - 1 - 6 = -1
This structure is not the actual way these atoms arrange. The atoms will actually arrange in the order of H-O-Cl to form hypochlorous acid with a single bond between the three atoms and formal charges of 0 on each atom.
The Lewis structure of HClO consists of bonds from Cl to each of H and O, with Cl having 5 pairs of non-bonding electrons and O having 2 pairs.
Explanation:To create the Lewis structure for HCLO, start by counting valence electrons. Hydrogen (H) has 1, Oxygen (O) has 6, and Chlorine (Cl) has 7. This totals to 14. Next, choose the atom with the least electronegativity (Cl in this case) to be the central atom, and draw bonds to other elements. A bond to each H and O from Cl uses up 4 electrons, leaving 10. Now fill the octets of the H and O atoms.
The Lewis structure should then look like this:
H - Cl - O
With 5 pairs of non-bonding electrons around Cl and two pairs of non bonding electrons around O.
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When hydrogen is burned, it reacts with oxygen and produces _____. carbon dioxide water oil helium
Answers
so your answer is c
Radon (rn) is the heaviest and the only radioactive member of group 8a(18), the noble gases. it is a product of the disintegration of heavier radioactive nuclei found in minute concentrations in many common rocks used for building and construction. in recent years, health concerns about the cancers caused from inhaled residential radon have grown. if 1.00 × 1015 atoms of radium (ra) produce an average of 1.373 × 104 atoms of rn per second, how many liters of rn, measured at stp, are produced per day by 9.64 g of ra?
Answers
Explanation:
1) convert 9.64 g of Ra to number of moles, using the atomic mass of Ra
number of moles = mass in grams / atomic mass
atomic mass of Ra = 226 g/mol
number of moles Ra = 9.64 g / 226 g/mol = 0.042654867 moles
2) number of atoms in 0.042654867 moles
number of atoms = number of moles * Avogadro's number
number of atoms of Ra = 0.042654867 * 6.022 * 10^ 23 = 2.568676 * 10^ 22 atoms of Ra
3) atoms of Rn produced
Proportion
1.00 × 10^15 atoms of Ra 2.568676 × 10^22 atoms of Ra
------------------------------------- = --------------------------------------------
1.373 × 10^4 atoms of Rn/s x
x = 3.52679 × 10^ 10 atoms of Rn/s
4) liters per day
PV = nRT => V = nRT /P
STP => T = 273.15K, P = 1 atm
n = 3.52679 × 10^ 10 atoms of Rn/s / (6.022 * 10^ 23 atoms / mol) =5.85651 * 10 ^ -14 mol/s
=> V = 5.85651 * 10^ -14 mol/s * 0.0821 atm*liter / mol*K * 273.15 / 1 atm =
V = 1.3133 * 10 ^ -13 liter / s
Per day => 1.313 * 10 ^ -13 liter / s * 24 h/day * 3600 s/h = 1.1347 * 10 ^ - 8 liter / day
And that is the answer:
The amount of Rn produced per day by 9.64 g of Ra is 1.13 [tex]\rm \times\;10^-^8[/tex] L.
Moles of Radon (Ra) in 9.64 g of Ra are;
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of Ra = [tex]\rm \dfrac{9.64}{226}[/tex]
Moles of Ra = 0.0426
Number of atoms of Ra in 0.0426 moles of Ra are:
Number of atoms = moles [tex]\times[/tex] Avagadro number
= 0.426 [tex]\times\;6.203\;\times\;10^2^3[/tex]
number of atoms of Ra produced by 9.64 g of Ra are 2.56 [tex]\rm \times\;10^2^3[/tex]
the proportion of atoms : atom\sec will be:
[tex]\rm \dfrac{atoms\;of\;Ra}{atoms\;of\;Ra/sec}\;=\;\dfrac{atoms\;of\;Rn}{x}[/tex]
[tex]\rm \dfrac{1\;\times\;10^1^5}{1.373\;\times\;10^4}\;=\;\dfrac{2.56\;\times\;10^2^2}{x}[/tex]
Atoms of Rn produced per second are 3.53 [tex]\rn \times\;10^1^0[/tex] atoms/sec.
Moles of Rn produced = [tex]\rm \dfrac{atoms\;per\;sec}{avagadro\;number}[/tex]
Moles of Rn produced = [tex]\rm \dfrac{3.52\;\times\;10^1^0}{6.023\;\times\;10^2^3}[/tex] moles
Moles of Rn produced = 5.85 [tex]\rm \times\;10^-^1^4[/tex] mol/sec.
From the ideal gas equation,
PV = nRT
The volume of Rn produced = [tex]\rm \dfrac{nRT}{P}[/tex]
= [tex]\rm \dfrac{5.85\;\times\;10^-^1^4\;\times\;0.0821\;\times\;273.15}{1}[/tex]
= 1.31 [tex]\rm \times\;10^-^1^3[/tex] liter/sec.
The amount of Rn produced per day = amount produced per second [tex]\times[/tex] 3600
The amount of Rn produced per day = 1.31 [tex]\rm \times\;10^-^1^3[/tex] [tex]\times[/tex] 24 [tex]\times[/tex] 3600 L
The amount of Rn produced per day by 9.64 g of Ra is 1.13 [tex]\rm \times\;10^-^8[/tex] L.
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Vitellium (Vi) has the following composition:
Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%
Based on this data, what can you predict about the average atomic mass of vitellium?
A.)It will be equal to the arithmetic mean of the masses of the three isotopes.
B.)It will be closer to the mass of Vi–188.
C.)It will be closer to the mass of Vi–193.
D.)It will be equal to the mass of Vi–193.
And I am a PLATO user so I already know it's not A!
Answers
Average atomic mass of vitellium =
Ar(Vi-188) · ω(Vi-188) + Ar(Vi-191) · ω(Vi-191) + Ar(Vu-193) · ω(Vi-193).
Average atomic mass of vitellium =
187.9122 amu · 0,10861 + 190.9047 amu · 0,12428 + 192.8938 amu · 0,76711.
Average atomic mass of vitellium = 20,409 + 23,725 + 147,970.
Average atomic mass of vitellium = 192,104.
An unknown substance has the composition of 77.87% C, 2.63% H and 55.62% O. The compound has a molar mass of 345.2 g/mole. What is the molecular formula?
Answers
m(C) = 0,7787 · 100 g = 77,87 g.
n(C) = 77,87 g ÷ 12 g/mol = 6,49 mol.
m(H) = 0,0263 · 100 g = 2,63 g.
n(H) = 2,63 g ÷ 1 g/mol = 2,63 mol.
m(O) = 0,5562 · 100 g = 55,62 g.
n(O) = 55,62 g ÷ 16 g/mol = 3,48 mol.
n(C) : n(H) : n(O) = 6,49 mol : 2,63 mol : 3,48 mol.
n(C) : n(H) : n(O) = 2,5 : 1 : 1,33.
From molecular mass only possible is C₁₂H₉O₁₂.
When assigning electrons to orbitals, which would be the most likely 'address' for the next electron following the 5s2 electron? 5s3 5p1 4d1 5d1
Answers
Filling of electrons in an orbitals takes place by using following rules:
Aufbau rule: Filling of electrons takes place in an energy levels in the increasing order of energy that is the one having lowest energy will fill first.
Hunds rule: No second electron will be filled in an orbital until each orbital occupies a single electron.
Pauli exclusion principle: No two electrons can have same spin in an orbital.
So here also also the rules must be applied in filling electrons , by Aufbau rule, energy level that is having lower energy in this case after 5s it will be 4d¹, will fill first. So the answer is 4d¹.
How many grams of sodium metal are needed to react completely with 25.8 liters of chlorine gas at 293 Kelvin and 1.30 atmospheres? Ideal gas law after stoichiometry I don't need the answer please don't give it just explain how to solve it.
Answers
To answer this question you need to first write the chemical equation for this reaction:
2Na(s) + Cl₂ → 2NaCl
Now, you know that to react 1 mol of Chlorine gas you'll need 2 moles of sodium, this can be written as follows:
[tex]2*mol Na=mol Cl_{2} \\ \\ mol Na=molCl_2* \frac{1}{2} [/tex] (1)
So, the last step in solving this problem is to know how many moles of Chlorine you have. For that, you'll use the Ideal Gas Law which states that:
[tex]P*V=n*R*T[/tex]
[tex]n= \frac{P*V}{R*T} [/tex] (2)
Where P is pressure, V is volume, n is the amount of the gas in moles, R is the Constant of the Ideal Gases and T is the temperature.
The final step is replacing the expression (2) in (1) and you're good to go!
I won't give the answer to this problem, just leave the equation for you to replace the values.
The decomposition of hi has a rate constant of 1.80 × 10-3 m-1s-1. how much hi remains after 8.50 min if the initial concentration of hi is 4.78 m?
Answers
1/(A)t =Kt + 1/(A)o
k= constant
t= time in second= 8.50 x60= 510 sec
( A)o= initial concentration
(A)t =final concentration
1/(A)t =(1.80 x10^-3) (510) +1 /4.78
1(A)t= 1.127 multiply both side by (A)t
1=1.127 (A)t divide both side by 1.127
(A)t= 0.887 M
A mixture is two or more substances that are mixed together but not chemically combined. The substances in a mixture each keep their own properties and can be separated from the mixture.
Identify the substance in a mixture of sand, salt, sawdust, and iron filings that can easily be separated by dissolving the mixture in water.
A) sand
B) salt
C) sawdust
D) iron filings
Plz help!
Answers
At high pressures, real gases do not behave ideally. calculate the pressure exerted by 18.0 g h2 at 20.0°c in a 1.00 l container assuming in part 1 non-ideal behavior and in part 2 ideal behavior.
Answers
we will use Van der Waals formula:
P = (nRT/(V-nb)) - (n^2 a/V2)
when n (moles of H2) = 18 g / 2 = 9 moles
R (constant) = 0.0821
T(tempreature in kelvin = 20 +273 = 293 K
V(Volume) = 1 L
a (constant for H2) = 0.2476
b(constant for H2) = 0.02661
So by substitution:
∴P = (9*0.0821*293/(1-(9*0.02661))) - (9^2*0.2476/1)
∴P ≈264.6 atm
Part 2 (ideal behavior):
we will use the ideal gas formula :
PV = nRT
when we have n = 9
R= 0.0821
T=293 K
V= 1 L
∴P = (9*0.0821*293)/1 L
∴P = 216.5 atm
Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom?
Dalton’s atomic model
Thomson’s atomic model
Rutherford’s atomic model
Bohr’s atomic model
quantum atomic model
Answers
The Bohre's atomic model represents movement of electrons in specific orbit around the nucleus of an atom.
Hope it helps.
Answer: The correct answer is Bohr's atomic model.
Explanation:
For the given options:
Dalton's atomic model: This model states that every matter is made up of smallest unit known as atom.
Thomson's atomic model: He proposed a model known as plum pudding model. He considered atom to be a pudding of positive charge in which negative particles are embedded such as plum.
Rutherford's atomic model: He gave an experiment known as gold foil experiment. In his model, he concluded that in an atom, there exist a small positive charge in the center.
Bohr's atomic model: This model states that electron revolve around the nucleus in discrete orbits in an atom.
Quantum atomic model: This model determines the location of electrons in an atom in a 3-D space.
Hence, the correct answer is Bohr's atomic model.
Consider the following equilibrium:
4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g)
Which of the following is a correct equilibrium expression?
Keq=[KOH]4[O2]3[KO2]4[H2O]2
Keq=[H2O]2[O2]3
Keq=[KO2]4[H2O]2[KOH]4[O2]3
Keq=[O2]3[H2O]2
Answers
Answer:
[tex]Keq=\frac{[O_{2}]^{3} }{[H_{2}O]^{2} }[/tex]
Explanation:
The equilibrium constant (Keq) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. In Keq we include gases and aqueous species, but not solids nor pure liquids because their concentration remains almost constant over time.
Let's consider the following reaction.
4 KO₂(s) + 2 H₂O(g) ⇄ 4 KOH(s) + 3 O₂(g)
Then, the equilibrium constant is:
[tex]Keq=\frac{[O_{2}]^{3} }{[H_{2}O]^{2} }[/tex]
He hydroxide ion concentration in household ammonia is 3.2 × 10−3 m at 25 °c. what is the concentration of hydronium ions in the solution
Answers
and when Kw is the ionic constant for water at 25°C = 1 x 10^-14
and we have [OH-] = 3.2 x 10^-3
this the concentration at equilibruim.
so by substitution:
1 x 10^-14 = 3.2 x 10^-3 * [H3O+] .
∴ [H3O] = (1 x 10^-14) / (3.2 x 10^-3)
= 3.125 x 10^-12 m.
so, the answer is: concentration of hydronium ions is = 3.125·10⁻¹² M
Answer:- [tex][H_3O^+]=4.2*10^-^1^1[/tex]
Solution:- Ammonia is a weak base. So, to calculate the hydroxide ion concentration we make the ice table:
[tex]NH_3(aq)+H_2O(l)\rightleftharpoons NH_4^+(aq)+OH^-(aq)[/tex]
I 0.0032 0 0
C -X +X +X
E (0.0032-X) X X
[tex]K_b=\frac{[NH_4^+][OH^-]}{[NH_3]}[/tex]
Kb value for ammonia is [tex]1.8*10^-^5[/tex] . Let's plug in the values and solve for X.
[tex]1.8*10^-^5=\frac{X^2}{0.0032-X}[/tex]
Kb value is very low so we can neglect the X on the bottom.
[tex]1.8*10^-^5=\frac{X^2}{0.0032}[/tex]
On cross multiply:
[tex]X^2=1.8*10^-^5*0.0032[/tex]
[tex]X^2=5.76*10^-^8[/tex]
On taking square root:
[tex]X=2.4*10^-^4[/tex]
From ice table, [tex][OH^-]]=X[/tex]
So, [tex][OH^-]=2.4*10^-^4[/tex]
hydronium ion and hydroxide ion concentrations are related to each other by the formula:
[tex][H_3O^+][OH^-]=K_w[/tex]
where, Kw is the water dissociation constant and its value is [tex]1.0*10^-^1^4[/tex]
[tex][H_3O^+]=\frac{1.0*10^-^1^4}{2.4*10^-^4}[/tex]
[tex][H_3O^+]=4.2*10^-^1^1[/tex]
The balanced net ionic equation for the neutralization reaction involving equal molar amounts of hno3 and koh is ________.
Answers
Explanation:
1) Write the molecular chemical equation:
HNO₃(aq) + KOH(aq) ---> H₂O(l) + KNO₃(aq)
2) Identify the kind of reaction:
It is a acid base neutralization, which is a double replacement equation.
3) Set the ionization (dissociation) of the acid and the base compounds:
i) HNO₃(aq) ---> H⁺ (aq) + NO₃⁻ (aq)
ii) KOH (aq) --> K⁺ (aq) + OH⁻ (aq)
4) Identify whether the products are soluble ionic compounds and they dissociate in water or remain solids (phases).
i) KNO₃ is soluble, so it will dissociate: KNO₃(aq) --> K⁺(aq) + NO₃⁻(aq)
ii) H₂O slightly dissociates, so it will remain liquid: H2O (l)
5) Write the total ionic equation:
H⁺ (aq) + NO₃⁻(aq) + K⁺(aq) + OH⁻ (aq) --> K⁺ (aq) + NO₃⁻(aq) + H₂O(l)
6) Eliminate the spectator ions (those that are repeated in reactant and product sides, K⁺(aq) y NO₃⁻(aq):
H⁺(aq) + OH⁻(aq) --> H₂O(l)
That is the net ionic equation.
Final answer:
The balanced net ionic equation for the neutralization reaction involving equal molar amounts of HNO3 and KOH is H+(aq) + OH−(aq) → H2O(l), illustrating the direct interaction between hydrogen and hydroxide ions to form water.
Explanation:
The balanced net ionic equation for the neutralization reaction involving equal molar amounts of HNO3 and KOH is represented by the equation:
H+(aq) + OH−(aq) → H2O(l)
This equation demonstrates that the hydrogen ion (H+) from nitric acid (HNO3) combines with the hydroxide ion (OH−) from potassium hydroxide (KOH) to form water (H2O). The potassium ion (K+) and the nitrate ion (NO3−) are spectator ions and do not participate in the reaction. Therefore, they are not included in the net ionic equation. Neutralization reactions like this involve the combination of an acid and a base to produce water as one of the products.
What is true about the element Francium (Fr, atomic number 87)? choose 3
A. It has seven valence electrons
B. It is likely to form ionic bonds
C. It is a nonmetal
D. It is in period Seven
E. It is a metal
Answers
Answer :
(B) It is likely to form ionic bonds
(D) It is in period seven
(E) It is a metal
Explanation :
Francium is an element whose symbol is 'Fr' and atomic number is 87.
Group 1 alkali metals consists elements Lithium, Sodium, Potassium, Rubidium, Caesium and Francium. Periodic table also shown below.
Francium belongs to the group 1 (alkali metal) and it is in period seven.
It has one valence electron, the electronic configuration of Francium is [Rn} [tex]7s^{1}[/tex].
Alkali metals have tendency to form ionic compounds because they have +1 charge.
The correct statements about Francium (Fr, atomic number 87) are that it is likely to form ionic bonds, is in period seven, and is a metal.
Explanation:The element Francium (Fr, atomic number 87) has several characteristics based on its position in the periodic table. Firstly, as an element in Group 1, it has one valence electron which makes statement A incorrect. This single valence electron also means Francium is highly probable to form ionic bonds with nonmetals seeking to gain electrons, making statement B true. Francium is not a nonmetal, so statement C is false. Statement D is correct as Francium is located in period seven of the periodic table. Lastly, because Francium is in Group 1, it is indeed an alkali metal, making statement E true. Therefore, the correct statements about Francium are B, D, and E.
Identify the oxidizing agent in the reaction: 8h+(aq) + 6cl−(aq) + sn(s) + 4no3−(aq) → sncl62−(aq) + 4no2(g) + 4h2o(l)
Answers
The oxidizing agent in the reaction is the NO3- ions.
Explanation:In the given reaction,
8H+(aq) + 6Cl-(aq) + Sn(s) + 4NO3-(aq) → SnCl62-(aq) + 4NO2(g) + 4H2O(l)
The oxidizing agent is the species that gets reduced. In this reaction, the NO3- ions are reduced from a +5 oxidation state to a +4 oxidation state, so the NO3- ions are the oxidizing agent.
Learn more about oxidizing agent here:https://brainly.com/question/10547418
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In the given reaction, the nitrate ion (NO₃⁻) is the oxidizing agent as it gets reduced from an oxidation number of +5 to +4. The tin (Sn) is oxidized from 0 to +4.
The identification is based on changes in oxidation numbers during the reaction.
To identify the oxidizing agent in the given reaction:
8H⁺(aq) + 6Cl⁻ (aq) + Sn(s) + 4NO₃⁻(aq) → SnCl₆²⁻(aq) + 4NO₂(g) + 4H₂O(l)Assign oxidation numbers to each element in the reaction:
Sn (tin) in its elemental form has an oxidation number of 0.In SnCl₆²⁻ tin’s oxidation number is +4.In NO₃⁻ (nitrate ion), nitrogen has an oxidation number of +5.In NO₂ (nitrogen dioxide), nitrogen has an oxidation number of +4.Determine what is being oxidized and reduced:
sn is oxidized from 0 to +4, losing electrons.NO₃⁻ is reduced from +5 to +4, gaining electrons.Identify the oxidizing and reducing agents:
The species that gets reduced is the oxidizing agent.So, in this reaction, NO₃⁻ (nitrate ion) is the oxidizing agent.
Correct question is: Identify the oxidizing agent in the given reaction:
8H⁺(aq) + 6Cl⁻ (aq) + Sn(s) + 4NO₃⁻(aq) → SnCl₆²⁻(aq) + 4NO₂(g) + 4H₂O(l)
The nucleus of the atom contains what subatomic particle(s)? Protons only Neutrons only Electrons only Protons and neutrons Protons and electrons
Answers
The answer is option C protons and neutrons.
Reason:
The middle of the nucleus contains the protons and the neutrons which contain the positive and electrical charges which decides the element which means option C will be your answer.
If you need anymore help feel free to ask me!
Hope this helps!
~Nonportrit
Answer:
c
Explanation:
substract 10x +9 from 7x-10
Answers
This is a subtraction of expression. You should remember the rules in subtracting or adding expression. You can only add or subtract two terms if they are similar terms which mean they have the same variable with the same exponents.
(7x – 10) – (10x + 9)
You have to distribute the negative to the parenthesis.
7x – 10 – 10x – 9
7x – 10x – 10 – 9
-3x - 19
Which of the following is the best definition of a chemical change?
Answers
Answer: A change in a substance where one or more new substances form
Explanation: Apex
Maple syrup has a density of 1.325 g/ml, and 100.00 g of maple syrup contains 67 mg of calcium in the form of ca2+ ions. what is the molarity of calcium in maple syrup?
Answers
1000 ml contains 1325 g of maple syrup
In 100 g of maple syrup - 67 mg of Ca ions
Therefore in 1325 g of maple syrup - 67 mg /100g * 1325 g
= 887.75 mg of Ca
this means in 1000 ml - 887.75 mg of Ca
molar mass of Ca - 40 g/mol
therefore number of moles in 1000 ml - 0.88775 g /40 g/mol
molarity of Ca - 0.022 mol/dm³
The molarity of calcium in maple syrup is 33.4 M.
Explanation:To find the molarity of calcium in maple syrup, we need to first convert the given amount of calcium from milligrams to grams. Since there are 1000 milligrams in a gram, 67 mg is equal to 0.067 g. Next, we divide the mass of calcium by the density of maple syrup to find the volume of maple syrup.
Volume of maple syrup = mass of calcium / density of maple syrup = 0.067 g / 1.325 g/ml = 0.0506 ml
Now, we can calculate the molarity of calcium (Ca2+) in maple syrup by dividing the moles of calcium by the volume of maple syrup in liters:
Molarity = moles of calcium / volume of maple syrup = (0.067 g / 40.08 g/mol) / (0.0506 ml / 1000 ml/L) = 33.4 M
The equation below shows hydrogen reacting with oxygen to produce water. 2H2+O2>2H2O if 16mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?
Answers
Answer : The number of moles of water produced would be, 32 moles.
Explanation : Given,
Moles of [tex]O_2[/tex] = 16 mole
The given chemical reaction is:
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
From the balanced chemical reaction we conclude that,
As, 1 mole of [tex]O_2[/tex] gas react to give 2 moles of [tex]H_2O[/tex]
So, 16 mole of [tex]O_2[/tex] gas react to give [tex]16\times 2=32[/tex] moles of [tex]H_2O[/tex]
Thus, the number of moles of water produced would be, 32 moles.
When a collision occurs between two reactant particles that, between them, have the required minimum kinetic energy, or activation energy, a product does not always form. Which of the following reasons explains this?
a.low temperature
b.small surface area
c.unfavorable geometry
d.low concentration
Answers
c.unfavorable geometry
Answer: C. Unfavorable geometry
Explanation: When collision occurs between two reactants in order to make a reaction possible there are 3 factors which are responsible.
a) Orientation factor
b) Energy factor
c) rate of collision
Thus out of the given options, unfavorable geometry is the correct one as temperature and concentration as well as surface area will have very little effect on the reaction.
If the geometry of the reactant is not complementary then the reaction would not lead successfully.
In which relationship stage are the individuals in the following scenario?
Heather and Mona became good friends about ten years ago. For the last year, though, things haven't been the same. They no longer make the effort to meet up for lunch or go shopping together. They try to remember to call on birthdays and holidays, but sometimes they forget.
terminating
differentiating
stagnating
circumscribing
avoiding
Answers
I would say the answer is B - Differentiating
Explanation:
Differentiating is a process of loosing or separating. During this stage, variations between the relationship associates are highlighted and what was considered to be connections starts to crumble. The people avoid discussing the relationship because they believe they understand what the other will respond.