Two lines, R and M, are represented by the following equations:
Line R: 2x + 2y = 18
Line M: x + y = 9
Which statement is true about the solution to the set of equations? (4 points)

A.There is no solution.

B.It is (18,9).

C.There are infinitely many solutions.

D.It is (9, 18).

Answer:

because hygiene

Step-by-step explanation:

a

a

a

a

a

a

a

a

a

a

a

There is no answer, there is no table.

Given:

The figure contains a right triangle.

The two angles of the triangle are 45° each.

The length of one leg is 3 units.

The length of the hypotenuse is x units.

We need to determine the value of x.

Value of x:

The value of x can be determined using the formula,

[tex]cos \ \theta=\frac{adj}{hyp}[/tex]

where [tex]\theta=45^{\circ}[/tex], adj = 3 and hyp = x.

Substituting these values, we get;

[tex]cos \ 45^{\circ}=\frac{3}{x}[/tex]

Simplifying, we get;

[tex]x=\frac{3}{cos \ 45^{\circ}}[/tex]

[tex]x=\frac{3}{\frac{\sqrt{2}}{2}}[/tex]

[tex]x=3 \times \frac{2}{\sqrt{2}}[/tex]

[tex]x=\frac{6}{\sqrt{2}}[/tex]

Thus, the value of x is [tex]x=\frac{6}{\sqrt{2}}[/tex]

Answer:

The factors are 7 * 2 * 2 * 2

Step-by-step explanation:

Step 1:  Find all of the factors

                     56

               28        2

          14        2

      7        2

Answer: The factors are 7 * 2 * 2 * 2

Answer:

x = - 2, y = 3

Step-by-step explanation:

Given

22 + yi = 20 - x + 3i

Compare the coefficients of like terms on both sides, that is

22 = 20 - x ( subtract 20 from both sides )

2 = - x ( multiply both sides by - 1 )

x = - 2

And

yi = 3i , hence y = 3

Answer:-4x+3y=1

Step-by-step explanation:

First put the equations above one another

-2x+7y=-5

-2x-4y= 6

Just add the corresponding number from the top from the one right below it

-2x plus -2x is 4x

7y plus -4y is 3y

-5 plus 6

Then bring down the equal sign

And you get

-4x+3y=1

The addition of the two equations -2x+7y=-5 and -2x-4y=6 is -4x +3y = 1.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the two equations are -2x+7y=-5 and -2x-4y=6. The equations can be added as below,

Write the two equations with the like terms adjacent to each other than perform the algebraic operation and get the final solution.

-2x+7y=-5

-2x-4y=6

________

-4x + 3y = 1

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Answer:

4/h+7

Step-by-step explanation:

4 is on top of H+7

Answer:

x = 15.65

y = 3.5

Step-by-step explanation:

Step 1

Find the equation for x and y

Equation for x is given as

x² = 7( 7+28) ..........Equation 1

14(14 + y) = x²........ Equation 2

Solving for Equation 1

x² = 7( 7+28)

x² = 7(35)

x² = 245

x = √245

x = 15.65

From Equation 1 , x² has been determined to be 245

Therefore we substitute 245 for y in Equation 2

14(14 + y) = x²........ Equation 2

14(14 + y) = 245

196 + 14y = 245

14y = 245 - 196

14y = 49

y = 49 ÷ 14

y = 3.5

The transformation (x, y) → (x, 2y) doubles the y-coordinates of the parallelogram ABCD vertices, resulting in a new parallelogram with doubled height and consequently doubled area, demonstrating that the change in height is proportional to the original height.

The question posed relates to the effect of a transformation on the coordinates of a parallelogram's vertices. Specifically, we look at the transformation (x, y) → (x, 2y), which stretches the y-coordinates of the vertices while keeping the x-coordinates unchanged. For the given parallelogram ABCD with vertices A(0, 0), B(1, 1), C(3, 1), and D(2, 0), we apply the transformation to each vertex:

The transformation doubles the height (y-coordinate) of the parallelogram, while the base (x-coordinate) remains the same. Consequently, the area of the parallelogram also doubles, confirming that the change in height is proportional to the original height. By applying the transformation to a simple geometric figure, students can visualize and understand the properties of transformations and their effects on the shapes.

Answer:

Step-by-step explanation:

[tex]\frac{4}{5}(\frac{1}{4}-5)=\frac{4}{5}*\frac{1}{4}-\frac{4}{5}*5\\\\=\frac{1}{5}-4\\\\=\frac{1}{5}-\frac{4*5}{1*5}\\\\=\frac{1}{5}-\frac{20}{5}\\\\=\frac{1-20}{5}\\\\=\frac{-19}{5}[/tex]

Answer:

Compare the equivalent temperatures as a ratio; if the ratios are equivalent, then the temperatures vary directly.

Step-by-step explanation:

Took the test - answer got deleted :/

Answer: The weight of mail at noon is 104 pounds.

Step-by-step explanation:

Given that , At a post office, the weight of the mail at 10.00 A.M was 80 pounds.

Two hours later, the weight of the mail had increased by 30%.

Since , time after 2 hours of 10 A.M would be 12 P.M which is known as noon.

Mathematically , the weight of the mail at noon = (Weight at 10 AM) +30% of (Weight at 10 AM)

= 80 + 0.30(80) pounds

= 80 (1+0.30) pounds

= 80 (1.30) pounds

= 104 pounds

Hence, the weight of mail at noon is 104 pounds.

Answer:

There were 60 nano-related patents granted in 1991

Step-by-step explanation:

Answer:

1109

Step-by-step explanation:

The first term is -27, and the common difference is 16.

The nth term is:

a = a₁ + d (n − 1)

a = -27 + 16 (n − 1)

a = -27 + 16n − 16

a = 16n − 43

The 72nd term is:

a = 16(72) − 43

a = 1109

The 72nd term of the arithmetic sequence -27, -11, 5 is 1109.

The sequence provided, -27, -11, 5, is arithmetic, which means it has a common difference between consecutive terms. To find the 72nd term in this sequence, we first determine the common difference by subtracting the first term from the second term, so the common difference (d) is
[tex]-11 - (-27) = 16.[/tex]

The nth term of an arithmetic sequence can be found using the formula
[tex]a_n = a_1 + (n - 1) * d[/tex], where
[tex]a_n[/tex] is the nth term,
[tex]a_1[/tex] is the first term, and
n is the term number. Applying this formula to find the 72nd term, we get:

[tex]a_{72} = -27 + (72 - 1) * 16 \\a_{72} = -27 + 71 * 16 \\a_{72} = -27 + 1136 \\a_{72} = 1109.[/tex]

Therefore, the 72nd term of the sequence is 1109.

Answer:

the answer is b

Step-by-step explanation:

Answer: 1.875 days

Step-by-step explanation:

Hi, to answer this question we simple have to divide the total day of the month (30 days) by the number of days that she offers tutoring (16).

Mathematically speaking:

30 /16 =1.875 days

1.875 days is equivalent to the fraction of days that tutoring was offered in November

Feel free to ask for more if needed or if you did not understand something.

Answer:0.533

Step-by-step explanation:

Sam's mathematics teacher offered after school tutoring 16 days out of the 30 days that were in November in order to help students review for the mid-term exam.

To convert this to a decimal, we divide the number of days tutorial was offered in November by the number of days in November. This will be:

= 16/30

= 0.533

The decimal that is equivalent to the fraction is 0.533.

Answer:

4^-2

Step-by-step explanation:

4^4(4^-7)(4)      I solved this separately

256(0.00006103515625)(4)         Multiply

0.015625(4)                                    Multiply

0.0625

This decimal is equivalent to 4^-2

4^-2 = 0.0625

If this answer is correct, please make me Brainliest!

Final answer:

The expression [tex]4^4(4^-7)(4[/tex]) simplifies to [tex]4^-2[/tex] by adding the exponents of the same base, resulting in a single exponent expression.

Explanation:

To simplify the expression [tex]4^4(4^-7)(4)[/tex] using a single exponent, you'll need to apply the rules of exponents. When you have the same base being multiplied, you can add the exponents. Start by looking at the terms 4^4 and 4^-7. The rule says to add the exponents when multiplying: 4 + (-7) = -3. So those two terms combine to make 4^-3.

Next, we have the single 4, which can also be written as 4^1 since any number to the power of 1 is itself. Now add the exponents again: -3 + 1. This gives us[tex]4^-2[/tex], which is the expression simplified with a single exponent.

The correct answer to this problem is therefore [tex]4^-2.[/tex]

Answer:

See below.

Step-by-step explanation:

RSTV is a quadrilateral. We see that segments RV and RS are congruent. We also see that segments TV and TS are congruent. That makes quadrilateral RSTV a kite. A kite is a quadrilateral that has one set of congruent adjacent sides and a second set of congruent adjacent sides. One set of congruent adjacent sides may or may not be congruent to the second set of congruent adjacent sides. In this case they are not.

The diagonals of a kite are perpendicular which is shown in your figure with segment VS perpendicular to segment RT. The diagonals form 4 right triangles. The 4 right triangles are VRW, SRW, VTW, and STW.

Triangles VRW and SRW are congruent.

Triangles VTW and STW are congruent.

Let's work on the angles first.

Let's work on triangle VTW.

Angle VWT is a right angle.

m<VWT = 90

m<WVT = 42

m<VWT + m<VTW + m<WVT = 180

90 + 42 + m<WVT = 180

m<WVT + 132 = 180

m<WVT = 48

Triangle SWR is a right triangle.

m<RWS + m<RSW + m<SRW = 180

90 + m<RSW + 21 = 180

m<RSW + 111 = 180

m<RSW = 69

Triangles WVR and WSR are congruent with corresponding angles WVR and WSR.

m<WVR = m<WSR = 69

m<TVR = m<WVT + m<WVR

m<TVR = 48 + 69 = 117

m<TVR = 117

Now we deal with sides.

Let's look at triangle VWT.

Side VT is the hypotenuse.

m<VTW = 42 deg

VT = 15

For angle VTW, VW is the opposite leg, and VT is the hypotenuse.

The trig ratio that relates the opposite leg and the hypotenuse is the sine.

[tex] \sin \angle A = \dfrac{opp}{hyp} [/tex]

[tex] \sin \angle VTW = \dfrac{VW}{VT} [/tex]

[tex]\sin 42^\circ = \dfrac{VW}{15}[/tex]

[tex]VW = 15 \sin 42^\circ[/tex]

VW = 10

Since triangles RVW and RSW are congruent, corresponding sides VW and SW are congruent.

SW = VW = 10

Trianlge RSW is a right triangle with right angle RWS.

For angle WRS, SW is the opposite leg. RW is the adjacent leg.

[tex] \tan A = \dfrac{opp}{adj} [/tex]

[tex] \tan \angle WRS = \dfrac{SW}{RW} [/tex]

[tex] \tan 21^\circ = \dfrac{10}{RW} [/tex]

[tex] RW \tan 21^\circ = 10 [/tex]

[tex] RW = \dfrac{10}{\tan 21^\circ} [/tex]

RW = 26

We now know VW and RW. Using the Pythagorean theorem we can find RV.

(RW)^2 + (VW)^2 = (RV)^2

26^2 + 10^2 = (RV)^2

RV = 28

Perimeter:

Triangles RVT and RST are congruent, so we have:

RV = RS = 28

VT = ST = 15

perimeter = RS + RV + VT + ST

perimeter = 28 + 28 + 15 + 15

perimeter = 86

108 / 1376 is the probability that a student participates in both sports and music.

Step-by-step explanation:

It is given that,

A suburban high school has a population of 1376 students.

The number of students who participate in sports is 649.

The number of students who participate in music is 433.

To find the probability of event A (sports) :

P(sports) = No.of students participated in sports / Total students.

⇒ 649 / 1376

∴ P(A) = 649 / 1376

To find the probability of event B (music) :

P(music) = No.of students participated in music / Total students.

⇒ 433 / 1376

∴ P(B) = 443 / 1376

From the question, we know that the probability that a student participates in either sports or music is 974 /1376.

∴ P(A∪B) = 974 / 1376

To find the probability that a student participates in both sports and music :

The formula used here is,

P(A∩B) = P(A) + P(B) - P(A∪B)

⇒ 649 / 1376 + 433 / 1376 - 974 /1376

⇒ 108 / 1376

∴ P(A∩B) = 108 / 1376

The probability that a student participates in both sports and music is 108/1376

The given parameters are:
Total = 1376

Sport = 649

Music = 433

P(Sport or Music) = 974/1376

The required probability is:

P(Sport and Music) = P(Sport) + P(Music) - P(Sport or Music)

This gives

P(Sport and Music) = 649/1376 + 433/1376 - 974/1376

Evaluate the expression

P(Sport and Music) = 108/1376

Hence, the probability that a student participates in both sports and music is 108/1376

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Answer:

The independent variable is the variable that can be changed.

The dependent variable is wjat you measure in an experiment

To rewrite the integral over an appropriate region G in the​ uv-plane, we need to use the given transformation x = u/v and y = uv. The region G is defined by certain constraints on u and v, which can be found by solving the inequalities derived from the boundaries of R in the xy-plane. Finally, we can set up and evaluate the double integral over G.

To rewrite the integral over an appropriate region G in the​ uv-plane, we need to use the given transformation x = u/v and y = uv. Let's consider each boundary of R separately:

Now, we need to find the region G in the uv-plane that corresponds to R in the xy-plane. The region G is defined by the following constraints: u^2 ≤ v, 9v ≥ u^2, uv ≤ u/v, and uv ≥ 4(u/v). Combining these constraints, we get u^4 ≤ v^2 ≤ 9u^3 and u^2 ≤ 4v. The boundaries of G can be found by solving these inequalities.

To evaluate the integral over G, we need to determine the limits of integration for u and v. Once we have the limits, we can set up the double integral of the function over G and evaluate it.

Answer:

T=2000(x)+1200

Step-by-step explanation:

Let the number of years that you attend xollege be x.

Every year, you receive $2000 as academic scholarship hence for x years, you will receive $2000x

However, for books, you receive it once and rhe amount is $1200

The total expenditure will be expressed as

T=2000(x)+1200

Substitute the number of years for x with an integer to get equivalent amount received for scholarship

Answer:

k=8

Step-by-step explanation:

You can solve this by setting up an equation.

7*(k-5)=21

k-5=3

k=8

Hope this helps!

Answer:

[tex]=50m^{\frac{5}{3}}n^{\frac{3}{8}}[/tex]

Step-by-step explanation:

[tex]\left(5m^{\frac{4}{3}}\cdot \:5n^{\frac{1}{4}}\right)\left(m^{\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}\right)[/tex]

[tex]=m^{\frac{4}{3}}\cdot \:5^{1+1}n^{\frac{1}{4}}m^{\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}[/tex]

[tex]=m^{\frac{4}{3}}\cdot \:5^2n^{\frac{1}{4}}m^{\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}[/tex]

[tex]=5^2n^{\frac{1}{4}}m^{\frac{4}{3}+\frac{1}{3}}\cdot \:2n^{\frac{1}{8}}[/tex]

[tex]=5^2m^{\frac{4}{3}+\frac{1}{3}}\cdot \:2n^{\frac{1}{4}+\frac{1}{8}}[/tex]

[tex]=5^2\cdot \:2m^{\frac{5}{3}}n^{\frac{1}{4}+\frac{1}{8}}[/tex]

[tex]=5^2\cdot \:2m^{\frac{5}{3}}n^{\frac{3}{8}}[/tex]

[tex]=50m^{\frac{5}{3}}n^{\frac{3}{8}}[/tex]

Answer:

Step-by-step explanation:

Answer:

it's C my doods

Step-by-step explanation:

Yes, 9²+40²=41²

Pythagoras theorem states that, a right-angled triangle, the square of the one side is equal to the sum of the squares of the other two sides.

Pythagorean Triples where any 2 side the sum of the squares adds up to be equal the other side.

A triangle has side lengths are 40, 9 and 41

∵ 41 is the longest side length and that makes it the hypotenuse

The square of the two other sides is 9²+40² = 1,681

Also, 41² = 1,681

As we can see, the sum of the squares equal the square of the hypotenuse

Since this triangle follows the theorem, we can conclude that the triangle is a right triangle

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Answer:

The domain is all real numbers

The y-intercept is 3.

Step-by-step explanation:

Let's analyze each statement separately. The function is

[tex]f(x)=(x+1)^2+2[/tex]

We have the following statements:

The domain is all real numbers, --> TRUE. The domain of a function is the set of values that the variable x can take. For this function, there are no restriction on the values that x can take, so the domain is all real numbers.

The range is all real numbers greater than or equal to 1  --> FALSE. The range of a function is the set of values that the variable y can take. For this function, we see that the factor [tex](x+1)^2[/tex] is always equal or greater than zero; this means that the minimum of the function is [tex]f(x)=2[/tex], so the range is all real numbers greater than or equal to 2.

The y-intercept is 3.  --> TRUE. The y-intercept is the value of the function when x = 0. For this function, if we substitute x = 0, we find:

[tex]f(0)=(0+1)^2+2=1^2+2=3[/tex]

The graph of the function is 1 unit up and 2 units to the left from the graph of [tex]y=x^2[/tex] --> FALSE. The graph of a function is scaled n units up when [tex]g(x)=f(x)+n[/tex]; in this case, we see that the factor n in our fuction is n = 2, so the function is actually scaled 2 units up, not 1.

The graph has two x-intercepts --> FALSE. The x-intercept of a graph is the value of x when [tex]f(x)=0[/tex]. If we require [tex]f(x)=0[/tex] for our function, we get:

[tex]0=(x+1)^2+2\\\rightarrow (x+1)^2=-2[/tex]

However, this equation has no solutions: so, the graph has no x-intercepts.

The graph of the function [tex]f(x) = (x + 1)^2 + 2[/tex] has a domain of all real numbers, a range of all real numbers greater than or equal to 2, a y-intercept of 3, and is 1 unit left and 2 units upwards shifted from the base graph [tex]y = x^2[/tex]. It has one x-intercept, not two.

The function in question is f(x) = (x + 1)2 + 2. To analyze its characteristics, we first need to look at its general shape, domain, and range. Since it is based on the parent function f(x) = x2, which is a parabola, the transformations will affect the position but not the overall shape or domain.

Answer:

(C) Nathaniel can build at most 3 birdhouses.

Step-by-step explanation:

Given that:

[tex]43B+215H \leq 3000[/tex]

where:

Nathaniel wants to build 50 birds(B) using lego Blocks, we want to determine how many birdhouses(H) he can build with the remaining Lego blocks.

If B=50

[tex]43(50)+215H \leq 3000\\2150+215H \leq 3000\\\text{Subtract 2150 from both sides}\\215H \leq 3000-2150\\215H \leq 850\\\text{Divide both sides by 215}\\H \leq 3.95[/tex]

Therefore, Nathaniel can build at most 3 Birdhouses.

Answer: 3

Step-by-step explanation:

We are given that the number of birds Nathaniel wants to build using Lego blocks is \blue{50}50start color #6495ed, 50, end color #6495ed. When we substitute \blue B = \blue {50}B=50start color #6495ed, B, end color #6495ed, equals, start color #6495ed, 50, end color #6495ed in the given inequality, we will obtain an inequality for HHH alone:

\begin{aligned}43B+215H &\leq 3000\\\\ 43(\blue {50})+215H &\leq 3000 \\\\ 215H &\leq 850\\\\ H&\leq 3 \dfrac{41}{43}\end{aligned}

43B+215H

43(50)+215H

215H

H

​

≤3000

≤3000

≤850

≤3

43

41

​

​

Hint #22 / 3

So HHH must be less than or equal to 3\dfrac{41}{43}3

43

41

​

3, start fraction, 41, divided by, 43, end fraction. However, we should remember that the number of birdhouses Nathaniel can build must be an integer.

Since 333 is the biggest integer less than or equal to 3\dfrac{41}{43}3

43

41

​

3, start fraction, 41, divided by, 43, end fraction, Nathaniel can build 333 birdhouses at most with the remaining Lego blocks.

Hint #33 / 3

Nathaniel can build at most 3 birdhouses.

Step-by-step explanation:

1 pie in total: $13.66

1 slice: $1.70

1 pie in total: $20.11 (75+1.36×4)÷4

1 slice: $1.67