Answer:
Fuerza de roce = 15 N
Hacia la izquierda
Explanation:
Las leyes de Newton explican el comportamiento de cuerpos bajo efectos de fuerzas externas. La primera ley especifica que un cuerpo no cambiará su estado de movimiento mientras una fuerza desequilibrante no lo acelere. Es decir, un cuerpo que se mueve a velocidad constante, tiene cero fuerza desequilibrante.
Como el cuerpo se está moviendo a velocidad constante, no hay aceleración y por lo tanto la fuerza total es cero.
Dado que estamos aplicando una fuerza horizontal de 15N y aún así el cuerpo se mueve a velocidad constante, significa que esa fuerza está siendo contrarrestada por la fuerza de roce hasta producir un equilibro de fuerzas y por lo tanto, cero fuerza desequilibrante.
La fuerza de roce es entonces, en módulo igual a la fuerza aplicada, es decir, 15 N
Su dirección siempre es opuesta al movimiento, así que la fuerza de roce se dirige hacia la izquierda
Mg represents the element
Answer:
Mg is the symbol for Magnesium. Atomic #- 12
Explanation:
A net force of 50 N is applied to a 10 kg cart that is already moving at 3 m/s. The final velocity of the cart was 8 m/s. For How long was the force applied
Answer:
1 second
Explanation:
Assuming that the force is in the same direction as speed we can do the graphic.
Draw the forces present on the problem (weight and the net force).Newton's second law. The summation of the forces is equal to the product between mass and aceleration.[tex]F = m * a[/tex]Plan the equation on x direction (because the mass is moving on that way). The result would be: [tex]50 = 10 * a[/tex]From that equation we know that the aceleration is 5m/s2.Also, we know (because it is a uniform line movement) that the aceleration is related with the speed. [tex]s_{f} = s_{0} + a * t[/tex] Clearing the equation: [tex]\frac{s_{f} - s_{0} }{t} = a[/tex]And replacing: [tex]\frac{8-3}{t} = 5[/tex]So, the force is applied for 1 second.A 0.0625 tank contains 0.0925kg nitrogen at a gauge pressure of 5.17atm.Find the temperature of the gas in degree Celsius
-271.96 °C
Explanation:We are given;
Volume of the tank as 0.0625 L Mass of nitrogen gas as 0.0925 kg or 92.5 g Pressure of the gas as 5.17 atmwe are required to calculate the temperature of the gas.
Step 1: Calculate the number of moles of nitrogen gasMoles = Mass ÷ Molar mass
Molar mass of nitrogen gas = 28.0 g/mol
Therefore;
Moles of N₂ = 92.5 g ÷ 28.0 g/mol
= 3.304 moles
Step 2: Calculate the temperature of the gas;According to the ideal gas equation;
PV = nRT , where n is the number of moles and R is the ideal gas constant, 0.082057 L.atm/mol.K
Rearranging the formula;
T = PV ÷ nR
= ( 5.17 atm × 0.0625 L) ÷ (3.304 moles × 0.082057)
= 1.19 K
But, °C = K - 273.15
Therefore;
T = 1.19 K - 273.15
= -271.96 °C
Thus, the temperature of the gas will be -271.96 °C
Andre really likes his new car, and he knows it has a certain amount of mechanical energy. Which types of energy are included in the mechanical
energy of the car? Choose the two that apply.
A. electrical energy from the battery
B. kinetic energy from any movement the car has
C. potential energy based on its position
D. thermal energy from when fuel burns in the engine
Option - B and Option - C are correct.
We have Andre's new car.
We have to determine what types of Energies are included in the Mechanical energies of the car.
What is Mechanical Energy?The energy possessed by an object due to its motion or its position is called Mechanical Energy.
According to the question -
The Mechanical energy of the new car would include the following two types of energy -
Kinetic Energy of Car - The kinetic energy of the car is the energy possessed by the car by virtue of its motion. Mathematically -[tex]$E(K) = \frac{1}{2} mv^{2}[/tex]
Potential Energy of Car - The potential energy of the car is due to its position. Assume that the car of mass 'm' is parked over the mountain at height 'h'. Then its potential energy will be -U(h) = mgh
Hence, Option B and C are correct.
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4. When referring to the element phosphorus on the periodic table
osphorus on the periodic table, the number 15 represents
A. energy level.
B. atomic weight.
C. atomic number.
D number of atoms.
Answer:
the answer is C
Explanation:
A 5.5Kg block is hanging from a rope that is wrapped around the outside of a 13Kg flywheel disk witha radius of 33cm that is hagning form the ceilin. Friction in the flywheel provides a constant torque of 2.5Nm. When the block is released what is the magnitude of its acceleration as it falls
Answer:
[tex]3.9m/s^{2}[/tex]
Explanation:
Using second law of motion
[tex]a =\frac {m1 * g - \frac {T}{r}}{m1 + 0.5 * m2}[/tex] where m1 is mass of block, m2 is mass of flywheel, g is acceleration due to gravity whose value is taken as [tex]9.81 m/s^{2}[/tex], T is torque and r is radius
Substituting 5.5 Kg for m1, 13 Kg for m2, 0.33 m for r, 2.5 Nm for T we obtain
[tex]a = \frac {5.5 \times 9.81 - \frac {2.5}{0.33}}{(5.5 + 0.5 \times13)}=3.9m/s^{2}[/tex]
To find the acceleration of the 5.5 kg block, we consider both gravitational force and frictional torque acting on a 13 kg flywheel. The calculated acceleration of the block is approximately 2.73 m/s².
To determine the magnitude of the acceleration of the 5.5 kg block as it falls, we need to consider several forces and torques involved in the system. These include the gravitational force on the block, the tension in the rope, the rotational inertia of the flywheel, and the frictional torque opposing the motion.
First, let’s identify the key forces:
Gravitational force on the block (Fg): Fg = mblock * g = 5.5 kg * 9.8 m/s² = 53.9 NFrictional torque (τfriction): τfriction = 2.5 NmThe rotational inertia (I) of the flywheel (a disk) is given by:
I = 0.5 * mflywheel * r² = 0.5 * 13 kg * (0.33 m)² = 0.70785 kg·m²
Applying Newton’s second law for rotation, we have:
∑τ = I * α → τtension - τfriction = I * α
Here, τtension is the torque due to the tension in the rope, which is equal to T * r. Hence, we have:
T * r - τfriction = I * α
Also, the linear acceleration (a) of the block is related to the angular acceleration (α) of the flywheel by the equation:
a = α * r
Combining these equations, we get:
T * r - τfriction = I * (a / r)
Solving for T in terms of a:
T = (I * a / r²) + (τfriction / r)
Newton’s second law for the falling block gives us:
mblock * g - T = mblock * a
Substitute T from the earlier equation into this one and solve for a:
mblock * g - [(I * a / r²) + (τfriction / r)] = mblock * a
Rearranging terms to isolate a:
a = [mblock * g - (τfriction / r)] / [mblock + (I / r²)]
Substitute the known values:
mblock = 5.5 kgg = 9.8 m/s²τfriction = 2.5 NmI = 0.70785 kg·m²r = 0.33 ma = [5.5 kg * 9.8 m/s² - (2.5 Nm / 0.33 m)] / [5.5 kg + (0.70785 kg·m² / (0.33 m)²)]
a ≈ 2.73 m/s²
Thus, the magnitude of the acceleration of the block as it falls is approximately 2.73 m/s².
If you are rolling a car down a ramp, the speed at the top of the ramp will be (faster/slower) than the speed at the bottom. Is it faster or slower?
Answer:
slower
Explanation:
Due to the fact that it is falling, the object experiences an acceleration due to gravity, so this acceleration will make the car go faster every moment, so the speed at the top will be lower than the speed at the bottom.
The situation can also be thought of as a transaction of potential energy (energy due to the mass of an object and its position on the ground) and kinetic energy (energy due to movement). At the top is the point where the object has the greatest potential energy, and as it moves down this potential energy is exchanged for kinetic energy. The kinetic energy increases while going down the ramp, so it will have greater speed as it falls.
The answer is: the speed at the top of the ramp will be slower than the speed at the bottom.
A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and the coefficient of kinetic friction is 0.03.
A - Find the net force applied to the motorcycle.
B - Find the acceleration of the motorcycle.
C - What is its speed at the end of 350m?
D - Find the elapsed time of this acceleration.
[Explain and Show Work]
A) The net force on the motorbike is 205.9 N
B) The acceleration of the motorbike is [tex]1.37 m/s^2[/tex]
C) The final speed is 5.2 m/s
D) The elapsed time is 3.80 s
Explanation:
A)
There are two forces acting on the motorbike:
- The applied force, F = 250 N, forward
- The frictional force, [tex]F_f[/tex], backward
The frictional force can be written as
[tex]F_f = \mu mg[/tex]
where
[tex]\mu=0.03[/tex] is the coefficient of kinetic friction
[tex]m=150 kg[/tex] is the mass of the motorbike
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Therefore the net force is given by
[tex]\sum F = F - F_f = F - \mu mg[/tex]
And substituting, we find
[tex]\sum F=250 - (0.03)(150)(9.8)=205.9 N[/tex]
2)
The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:
[tex]\sum F = ma[/tex]
where
m is the mass
a is the acceleration
In this problem, we have
[tex]\sum F = 205.9 N[/tex] is the net force
m = 150 kg is the mass
Solving for a, we find the acceleration:
[tex]a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2[/tex]
C)
Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For this motorbike, we have:
u = 0 (it starts from rest)
[tex]a=1.37 m/s^2[/tex]
s = 350 m
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s[/tex]
4)
For this part of the problem, we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the elapsed time
Here we have:
v = 5.2 m/s
u = 0
[tex]a=1.37 m/s^2[/tex]
Solving for t, we find
[tex]t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s[/tex]
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Answer:
This is a great question
*copy and paste for my physics homework* lol
A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long string. The balls undergo a head-on, perfectly elastic collision, after which the 110 g ball swings out to a maximum angle θmax = 50.0. What was v0?
I think you need to find the tangential velocity using the angle that the ball swings to, but I am not sure how to go about beginning this problem.
Answer:
[tex]7.3 ms^{-1}[/tex]
Explanation:
Consider the motion of the ball attached to string.
In triangle ABD
[tex]Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50[/tex]
height gained by the ball is given as
[tex]h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m[/tex]
[tex]M[/tex] = mass of the ball attached to string = 110 g
[tex]V[/tex] = speed of the ball attached to string just after collision
Using conservation of energy
Potential energy gained = Kinetic energy lost
[tex]Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}[/tex]
Consider the collision between the two balls
[tex]m[/tex] = mass of the ball fired = 26 g
[tex]v_{o}[/tex] = initial velocity of ball fired before collision = ?
[tex]v_{f}[/tex] = final velocity of ball fired after collision = ?
using conservation of momentum
[tex]m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85[/tex]
Using conservation of kinetic energy
[tex]m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}[/tex]
At a maximum angle of 50°, the initial velocity ([tex]V_0[/tex]) of the ball is equal to 7.3 m/s.
Given the following data:
Mass of ball 1 = 26.0 g.
Mass of ball 2 = 110.0 g.
Length = 1.10 m.
Maximum angle = 50°
How to calculate the initial velocity.First of all, we would determine the height of the ball in motion through this derivation:
[tex]h = L-Lcos\theta\\\\h = 1.10-1.10cos50\\\\h = 1.10-0.7071[/tex]
Height, h = 0.3929 meter.
Next, we would determine the velocity of the ball by applying the law of conservation of energy:
[tex]P E=KE\\\\mgh=\frac{1}{2} mv^2\\\\V=\sqrt{2gh} \\\\V=\sqrt{2 \times 9.8 \times 0.3929 }[/tex]
V = 2.7750 m/s.
Also, we would determine the final velocity by applying the law of conservation of momentum:
[tex]m_1v_o=m_1vf+m_2V\\\\26v_0=26v_f+110(2.7750)\\\\26v_f=26v_0-305.25\\\\v_f=(v_0-11.7404)\;m/s[/tex]
Now, we can determine the initial velocity:
[tex]m_1v_o^2=m_1v_f^2+m_2V^2\\\\26v_0^2=26(v_0-11.7404)^2+110(2.7750)^2\\\\26v_0^2=26(v_0-11.7404)^2-847.0688\\\\V_0=7.3\;m/s[/tex]
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Leah is making a chart to compare and contrast renewable and non-renewable resources. Which of the following would best complete the chart? Renewable Resources Non-renewable Resources __ Used faster than they can be replaced Most sources do not emit greenhouse gases Availability decreases over time Includes solar power, wind power, and geothermal power Includes fossil fuels, natural gas, and coal
Renewable resources can be replaced as quickly as they are used, while non-renewable resources are being used up faster than they can be made by nature.
Explanation:Renewable resources are those that can be replaced by natural processes as quickly as humans use them. Examples include solar power, wind power, and geothermal power. On the other hand, non-renewable resources are consumed or used up faster than they can be made by nature. Examples include fossil fuels such as coal, natural gas, and oil. These resources take millions of years to form and are being used up at a much faster rate than they can be replenished.
What can electromagnetic radiation, which moves as electromagnetic waves, move through?
A. only space
B. both air and space
C. only air
Answer:
i think its B
Answer:
B. both air and space
Explanation:
Electromagnetic waves propagate through an oscillation of electric and magnetic fields. Therefore, they do not need a material means to propagate, thanks to this we can observe the light emitted by a distant star. In other words, they can travel through vaccum space or a medium like air.
Lucille is finding it difficult to play soccer after school. Her doctor thinks that her cells might not be getting enough oxygen. When Lucille talked about it with her friend, her friend said there might be a problem with Lucille‘s respiratory system or circulatory system.
What do Lucille cells need an order for her body to function properly? How might a problem with Lucille‘s respiratory system and circulatory system make it difficult for Lucille to play soccer?
Answer:
See the explanation below.
Explanation:
Circulation of blood and oxygen is possible in body when circulatory system work along with respiratory system. Through tranche air moves in and out from lungs, whereas, through pulmonary arteries and veins (both connected to heart) blood moves in and out from the lungs. As Lucille is facing problem in his respiratory and circulatory system hence, it is difficult for him to play soccer because under normal circumstances when there is increase in physical activity then muscle cell respire more as compare to when the body is on rest. So, with increase of physical activity there is also increase in the rate of breathing which result in more absorption of oxygen and more removal of carbon dioxide but if there is problem in respiratory and circulatory system, for example, infection in throat due to pollution,etc. then this normal process of breathing gets affected which sometime may prove fatal to the person.
Lucille's cells require oxygen for cellular respiration to produce energy, and issues with her respiratory or circulatory systems can impair oxygen delivery and carbon dioxide removal, causing difficulties in playing soccer.
Explanation:In order for Lucille's body to function properly, her cells need oxygen to run the oxidative stages of cellular respiration, which produces energy in the form of adenosine triphosphate (ATP). Problems with Lucille's respiratory system or circulatory system could hinder the delivery of oxygen to her cells and removal of carbon dioxide from her body, which is critical for maintaining energy levels necessary for activities like playing soccer. Both systems work in tandem to ensure oxygen is inhaled into the lungs, transferred to the red blood cells, and delivered to body tissues, while carbon dioxide, a by-product, is picked up and exhaled.
The respiratory system includes the lungs where gas exchange occurs, and any condition like asthma, emphysema, COPD, or lung cancer can impair this function. Similarly, the circulatory system, consisting of the heart, blood, and blood vessels, is responsible for transporting gases to and from the lungs and body tissues. If the circulatory system is impaired, it can result in inadequate oxygen supply to muscles and organs, making it difficult for Lucille to sustain the physical exertion needed for soccer.
sound energy cannot travel through
A vacuum,a wooden table,polluted air,pond water
Sound energy cannot travel through a vacuum.
Explanation:
Waves are periodic disturbance of the space, which travel carrying energy but not matter.
There are two types of waves:
Mechanical waves: mechanical waves propagate through the vibrations of the particles in a medium. Examples of mechanical waves are sound waves.Electromagnetic waves: these waves consist of periodic oscillations of electric and magnetic fields, perpendicular to each other. These waves do not need a medium to propagate, so they can also travel in a vacuum.In this problem, we are analyzing sound energy, which is the energy carried by sound waves. Sound waves are mechanical waves, so they need a medium to propagate: therefore, they cannot travel through a vacuum, since there is no medium.
So, sound energy cannot travel through a vacuum.
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Amazon has hired you to help design a new fleet of robots to work in their warehouse. You are trying to decide how powerful the motor that allows the robots to climb vertically up the selves should be. assume that the robot itself will have a mass of 15 kg and needs to be able to carry an object with a mass of 5 kg up to the top of a 20 m shelf in 8 seconds. What minimum wattage should you use?
The minimum power is 490 W
Explanation:
The work that needs to be done by the robot in order to climb the shelves is equal to the gain in gravitational potential energy of the robot + object, therefore:
[tex]W=mg \Delta h[/tex]
where
m = 15 kg + 5 kg = 20 kg is the total mass of the system
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
[tex]\Delta h = 20 m[/tex] is the change in height
Substituting,
[tex]W=(20)(9.8)(20)=3,920 J[/tex]
Now we can calcualte the power (wattage) that the robot must have, using the equation
[tex]P=\frac{W}{t}[/tex]
where
W = 3,920 J is the work done
t = 8 s is the time interval
Substituting,
[tex]P=\frac{3920}{8}=490 W[/tex]
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1. When a particle moves in a circle with constant speed, its acceleration is
A) constantly increasing.
constant in direction.
C) zero.
D) constant in magnitude.
E) constant in magnitude and direction.
Answer:
Its A.
Explanation:
a rabbit hops 50 m to the south in 5 seconds
Answer:
nice, thats a fast rabbit
Explanation:
Which statement about distance and displacement is correct?
Distance does not take direction of motion into account, but displacement does.
Displacement does take direction of motion into account but, but distance does.
Both distance and displacement must take direction of motion into account.
Answer:
The answer i believe is A..
Explanation:
.
Answer:
Distance does not take direction of motion into account, but displacement does.
Explanation:
Distance is said to be how much ground an object covers during motion. Distance is a scalar quantity. Distance has magnitude but no direction. It only concerns how much ground an object covers without considering the start or end points. For example a person covering a distance from point A to B can be computed without considering it starting and ending point. The distance from A to B can be computed as 100 meters.The change in position is not considered, only the distance it covered(100 meters)
While
Displacement is the change in position of an object. Displacement is a vector quantity as it incorporates both direction and magnitude. Displacement considers the starting and ending points of an object in motion. Example a person moving from point A to B, the change in position from point A to B shows their is a displacement.
A Tesla Roadster car accelerates from rest at a rate of 7.1m/s for a time of 3.9s
Calculate the distance it travels in this time.
The distance covered is 54.0 m
Explanation:
Since the motion of the car is a uniformly accelerated motion, we can use the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
u is the initial velocity
t is the time
a is the acceleration
s is the distance covered
For the car in this problem, we have
u = 0 (it starts from rest)
[tex]a=7.1 m/s^2[/tex] is the acceleration
t = 3.9 s is the time
Substituting, we find s:
[tex]s=0+\frac{1}{2}(7.1)(3.9)^2=54.0 m[/tex]
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A deputy sheriff rides a horse while directing traffic, what energy is being used?
Answer:
Kinetic Energy
Explanation:
In relation to the question, as the sheriff rides a horse, the sheriff is in motion and a body in motion is said top possess kinetic energy.
Kinetic energy is that energy of the body that it gains due to the motion or speed of the body which it gains and maintains.
In other words, we can say that the amount of work needed to accelerate an object from its position of rest and set it into motion at some certain velocity.
A spy satellite is orbiting earth and experiences a gravitation Force F if a similar satellite with one half the mass is placed in an orbit that is twice as far from the earths center the gravitational force between the earth and the second satellite will be what multiple of F?
The gravitational force on the second satellite is 1/8 of the force exerted on the 1st satellite.
Explanation:
The magnitude of the gravitational force exerted by the Earth on the satellite is given by:
[tex]F=G\frac{Mm}{r^2}[/tex]
where
G is the gravitational constant
M is the Earth's mass
m is the mass of the satellite
r is the radius of the orbit of the satellite
Let's call F the gravitational force on the first satellite, of mass m, with an orbit of radius r.
The second satellite has mass
[tex]m'=\frac{m}{2}[/tex]
and the radius of its orbit is
[tex]r'=2r[/tex]
So, the gravitational force exerted on the second satellite is
[tex]F'=G\frac{M(\frac{m}{2})}{(2r)^2}=\frac{1}{8}(\frac{GMm}{r^2})=\frac{1}{8}F[/tex]
Therefore, the force on the second satellite is 1/8 of the force exerted on the 1st satellite.
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Select the correct answer.
Thirst is a sign of dehydration.
A.
True
B.
False
Reset
Next
Answer:
this is a trap ur done
An object can be broken up by a planet's gravity once it passes the _______. The Jovian planets are composed primarily of _______ and helium. Hydrogen and helium don't exist in Earth's _______ because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. _______ is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of _______ is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.
Answer:1. Roche limit
2.hydrogen
3.atmosphere
4.mercury
5.venus
6.when an object passes the Roche limit, the strength of gravity on the object increases. If the density of the planet is higher, then the object can break up farther away from the planet. If the density is lower, then the Roche limit is located closer to the planet
7.Farther our in the solar system, beyond the frost line, hydrogen was at a low enough temperature that it could condense. This allowed hydrogen to accumulate under gravity, eventually forming the Jovian planets
Explanation:
An object breaks apart at a planet's Roche limit; Jovian planets mainly consist of hydrogen and helium. Earth's atmosphere lacks these gases due to weaker gravity. Mercury, close to the sun, has little atmosphere, and Venus has a hot, dense atmosphere.
Explanation:An object can be broken up by a planet's gravity once it passes the Roche limit. The Jovian planets are composed primarily of hydrogen and helium. Hydrogen and helium don't exist in Earth's atmosphere because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. Mercury is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of Venus is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.
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Using the equation for force (due to weight) and your mass , calculate your force
F=m x 9.8m/s2
F=69.3 x 9.8 m/s2 =???
The weight of the object is 679.1 N
Explanation:
The weight of an object is given by:
[tex]W=mg[/tex]
where
W is the weight
m is the mass of the object
g is the acceleration of gravity
For an object near the Earth's surface, the acceleration of gravity is
[tex]g=9.8 m/s^2[/tex]
The mass of the object in this problem is
m = 69.3 kg
Therefore, its weight is
[tex]W=(69.3)(9.8)=679.1 N[/tex]
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A force does work on a 50 g particle as the particle moves along the following straight paths in the xy-plane: 25 J from (0 m, 0 m) to (5 m, 0 m); 35 J from (0 m, 0 m) to (0 m, 5 m); -5 J from (5 m, 0 m) to (5 m, 5 m); -15 J from (0 m, 5 m) to (5 m, 5 m); and 20 J from (0 m, 0 m) to (5 m, 5 m).
Is this a conservative force?
If the zero of potential energy is at the origin, what is the potential energy at (5m, 5m)?
1) Yes, it is a conservative force
2) The potential energy at (5m, 5m) is 20 J
Explanation:
1)
A force is defined to be conservative if the work done by the force when moving an object does not depend on the path taken, but only on the initial and final position of the object.
Let's verify if this condition is met for the force in this problem:
- For going from (0 m, 0 m) to (5 m, 5 m), the work done is 20 J (A)
Then we can go from (0 m, 0 m) to (5 m, 5 m) through a different path:
- from (0 m, 0 m) to (5 m, 0 m) (work done: 25 J)
- from (5 m, 0 m) to (5 m, 5 m) (work done: -5 J)
Total work done in the second path: 25 J + (-5 J) = 20 J --> same as (A)
We can also go from (0 m, 0 m) to (5 m, 5 m) through a different path:
- from (0 m, 0 m) to (0 m, 5 m) (work done: 35 J)
- from (0 m, 5 m) to (5 m, 5 m) (work done: -15 J)
Total work done in the third path: 35 J + (-15 J) = 20 J --> same as (A)
So, the force is conservative, since the work done does not depend on the path taken.
2)
For a conservative force, the change in potential energy of the object moved by the force is equal to the work done by the force in moving the object from A to B.
Here have:
Point A: (0m, 0m)
Point B: (5m, 5m)
So, the change in potential energy is equal to the work done from A to B:
[tex]W=\Delta U = U_B-U_A[/tex]
where
[tex]U_B[/tex] is the potential energy in point B
[tex]U_A[/tex] is the potential energy in point A
In this problem, the potential energy at the origin (point A) is zero, so
[tex]U_A = 0[/tex]
Also we know that the work done is
W = 20 J
So, we find
[tex]U_B = W+U_A = 20 + 0 = 20 J[/tex]
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The force exerted is not conservative as different amounts of work are being done to move the particle along different paths between the same points. Potential energy isn't defined in the usual sense because the force isn't conservative, but if taken as the average of the works done, the potential energy at (5,5) could be taken as 20J.
Explanation:A conservative force is defined as one in which the work done on a particle by the force as the particle moves from one point to another is independent of the path taken. Specifically, in the case of a conservative force, the work done is only dependent on the initial and final positions. In the given scenario, different amounts of work are being done to move the particle along different paths between the same points. This indicates that the force is not a conservative one.
The potential energy at a point in a field due to a conservative force is equal to the work done by the force to move the particle from a reference point (in this case, the origin point) to that point. Since the force in this scenario isn't conservative, potential energy isn't defined in the usual sense. Nevertheless, if we insist on measuring it, we could take the average of the works done: for instance, between (0,0) and (5,5) the works done are 35+(-15)=20 and -5+25=20, so we could say the potential energy at (5,5) is 20J considering the origin as the reference point with zero potential energy.
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what is the magnitude of an electric field which will balance the weight of an electron on the surface of earth ?
The magnitude of the electric field must be [tex]5.59\cdot 10^{-11} N/C[/tex]
Explanation:
In order for the electron to be in equilibrium, the force of gravity acting on the electron must be equal to the force due to the electric field.
The force of gravity on the electron located on the Earth's surface is:
[tex]F_G = mg[/tex]
where
[tex]m=9.11\cdot 10^{-31} kg[/tex] is the electron mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
The force due to the electric field is
[tex]F_E = qE[/tex]
where
[tex]q=1.6\cdot 10^{-16}C[/tex] is the electron charge
E is the magnitude of the electric field
Since the two forces must be balanced,
[tex]F_G = F_E[/tex]
So we find:
[tex]mg=qE\\E=\frac{mg}{q}=\frac{(9.11\cdot 10^{-31})(9.81)}{1.6\cdot 10^{-19}}=5.59\cdot 10^{-11} N/C[/tex]
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an object weighs 50 N on Jupiter and another object weighs 50 N on the earth. Which has greater mass?
The object on Earth has greater mass
Explanation:
The weight of an object is given by
[tex]W=mg[/tex]
where
W is the weight
m is the mass of the object
g is the strength of the gravitational field at the location of the object
The strength of the gravitational field on Jupiter ([tex]g_J[/tex]) is much larger than that on Earth ([tex]g_E[/tex]), so we can write
[tex]g_J > g_E[/tex]
The weight of the first object on Jupiter is
[tex]W_J = m_1 g_J = 50 N[/tex] (1)
where [tex]m_1[/tex] is the mass of the first object, while the weight of the second object on Earth is
[tex]W_E = m_2 g_E = 50 N[/tex] (1)
while [tex]m_2[/tex] is the mass of the second object.
By dividing eq.(1) by (2), we get
[tex]\frac{m_1 g_J}{m_2 g_E}=1\\\frac{m_1}{m_2}=\frac{g_E}{g_J}[/tex]
And since [tex]g_J > g_E[/tex], this means that [tex]m_2 > m_1[/tex], so the object on Earth has greater mass.
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A car travels 5 miles north and then 2 miles south in 1/4 hour. What was its average speed?
The average speed of the car is 28 mph
Explanation:
The average speed of an object is equal to the ratio between the total distance covered by the object (regardless of its direction) and the time taken. Therefore:
[tex]speed = \frac{d}{t}[/tex]
where
d is the total distance
t is the time taken
The car in this problem travels 5 miles north and 2 miles south, so the total distance covered is
d = 5 + 2 = 7 miles
While the time taken is
t = 1/4 h = 0.25 h
Therefore, the average speed is
[tex]speed = \frac{7}{0.25}=28 mph[/tex]
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A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is reduced by half?
Answer:
The lose of thermal energy is, Q = 22500 J
Explanation:
Given data,
The mass of aluminium block, m = 1.0 kg
The initial temperature of block, T = 50° C
The final temperature of the block, T' = 25° C
The change in temperature, ΔT = 50° C - 25° C
= 25° C
The specific heat capacity of aluminium, c = 900 J/kg°C
The formula for thermal energy,
Q = mcΔT
= 1.0 x 900 x 25
= 22500 J
Hence, the lose of thermal energy is, Q = 22500 J
The thermal energy loose by the aluminum block will be Q = 22500 J
What will be the amount of energy aluminum block will lose?It is given that Given data,
The mass of the aluminum block, m = 1.0 kg
The initial temperature of the block, T = 50° C
Since the temperature of the block is halved then,
The final temperature of the block, T' = 25° C
The change in temperature, ΔT = 50° C - 25° C = 25° C
The specific heat capacity of aluminum,
c = 900 J/kg°C
The formula to find out the thermal energy will be
[tex]Q=m\times c\times\Delta T[/tex]
[tex]Q=1.0\times 900\times 25[/tex]
[tex]Q= 22500J[/tex]
Thus the thermal energy loose by the aluminum block will be Q = 22500 J
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2. Which of the following cell structures is the site of photosynthesis?
O A. Golgi apparatus
O B. Mitochondria
C. Chloroplasts
D. Centrioles
Answer:
Option C. The chloroplasts contain chlorophyll pigments requires for photosynthesis.
The cell structure that is considered the site of photosynthesis is known as chloroplasts. Hence, option C is the correct answer.
Photosynthesis is a significant process that takes place in plants. The process in which light energy obtained from the sun is converted into sugar molecules for the utilization by plants cells is known as Photosynthesis.
Photosynthesis occurs at chloroplasts. Some of the significant features of the chloroplasts are listed as follows:
Chloroplasts contain chlorophyll which is defined as the primary pigment required for photosynthesis to take place It is present in plants and certain algae It is oval-shaped and is composed of two different membranes namely outer and inner membraneThus, we can conclude that the chlorophyll present in chloroplasts is vital for photosynthesis and hence, chloroplasts are the cell structure that acts as the site of photosynthesis. Therefore, option C is the correct answer.
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According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first object that is:
Question 2 options:
equal in magnitude and opposite in direction
equal in magnitutde and in the same direction
different in magnitude compared to the original force
the same direction as the original force
Answer: equal in magnitude but opposite in direction to the force that it exerts.
Explanation:
Answer:
The second object exert a force that is equal in magnitude and opposite in direction.
Explanation:
Newton's third law of motion states that for every action there is a reaction which is equal in magnitude to the action but acts in opposite directions as the action.