Unit conversion Given 20 meq/L K2CO3, find the following units:

a. mol/L

b. mg/L

c. ppm

d. %

Answer:

We have 1.361 moles in the sample

Explanation:

Mass of iron = 76.02g

Molar mass of iron = 55.845 g/ mole ( This we can find in the periodic table, and menas that 1 mole of iron has a mass of 55.845 g).

To calculate the number of moles we will use following formula:

moles (n) = mass / molar mass

moles iron = 76.02g / 55.845 g/ mole

moles iron = 1.36127 moles

To use the correct number of significant digits we use the following rule for multiplication and division :

⇒ the number with the least number of significant figures decides the number of significant digits.

⇒76.02 has 4 digits ( 2 after the comma) and 55.845 has 5 digits (3 after the comma).

⇒ this means 1.361 moles

We have 1.361 moles in the sample

Answer:

Molarity is a sort of concentration for solutions. When you talk about it, means mols of solute, that are in 1000 ml of solution. The molarity at this is 0.57M

Explanation:

As you have the solution in a volume of 150ml with 5 g of solute, in 1000 ml how much solute, do u have? The answer is 33.333g so now, you have to take the molar mass of NaCl and get the mols. Mass/molar mass, you will get the moles, so 33,3333 g / 58,44 g/m is 0.570 moles. That's M

Answer:

See attachment

Explanation:

Bond-line structures are representations of molecules, where lines are drawn to represent the bonds between carbon atoms or between carbon atoms and heteroatoms (atoms other than C or H). Hydrogen atoms are not represented. Heteroatoms are indicated by their symbol but carbon atoms are not. Carbon atoms are located at the intersection of two lines.

A single bond is represented by one parallel line, a double bond by two parallel lines, and a triple bond by three parallel lines.

For (c), the formula is assumed to CH₃COCH₂CH(CH₃)₂

The question asks for bond-line structures of various compounds which are simplified drawings of molecules with the endpoints and intersections of each line representing carbon atoms and hydrogen atoms are understood to be filling any remaining free bonds, not represented in the diagram. An example is provided.

The question asks for bond-line structures of various compounds. A bond-line structure (also known as a line-angle diagram or skeletal formula) is a type of molecular structural formula that simplifies and reduces the drawing of a molecule to its basics, without including non-carbon and non-hydrogen atoms, or any multiple bonds. The endpoints and intersections of each line are carbon atoms and hydrogen atoms are understood to be filling any remaining free bonds, not represented in the diagram.

For example, for compound (CH₃CH₂)₂CHCH₂CH₂OH), the bond-line structure would look like a series of zig-zag lines, representing the carbon backbone of the molecule, with an OH group attached to the end. The CH₃ and CH₂ groups are understood without being explicitly drawn. The same principle applies to all the specified compounds. Due to the textual limitations of this platform, it's not possible to sketch the structures in the response.

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Answer:

The percentage of germanium in germatite is 6.0003%.

Explanation:

Mass of an ore of germanite =  1.00 grams

Mass of germanium chloride = 0.177 grams

Percentage of germanium in germanium chloride = 33.9%

Let the mass of germanium present in germanium chloride be x.

Percentage of an element in a compound:

[tex]\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100[/tex]

[tex]33.9\%=\frac{x}{0.177 grams}\times 100[/tex]

x = 0.060003 grams

Percentage of germanium in an ore of germanite:

[tex]=\frac{0.060003 gram}{1 gram}\times 100=6.0003\%[/tex]

The percentage of germanium in germatite is 6.0003%.

Answer:

b.15 % ( m / v )

Explanation:

The percent concentration ( m / v ) =

mass of the solute / volume of the solution * 100

From the question , the mass of glucose = 10.00 g

The total volume of the solution = 66.67 mL

using the above formula ,and putting the respective values , the percent concentration ( m / v ) is calculated as -

The percent concentration ( m / v ) = 10.00 g  / 66.67 mL * 100 = 15 (m/v)%

Explanation:

The given data is as follows.

         Mass of hexane = 10 kg,        Mass of octane = 30 kg

Formula to calculate average density of mixture is as follows.

                      [tex]\sum x_{i} \rho_{i}[/tex]

where,    [tex]x_{i}[/tex] = mass fraction of i component in mixture

              [tex]\rho_{i}[/tex] = density of i component

Hence, calculating the mass fraction of both hexane and octane as follows.

           [tex]x_{hexane}[/tex] = [tex]\frac{10}{(10 + 30)}[/tex] = 0.25

           [tex]x_{octane}[/tex] = [tex]\frac{30}{(10 + 30)}[/tex] = 0.75

Therefore, calculate the average density as follows.

          [tex]\rho_{mixture}[/tex] = [tex](0.26 \times 660) + (0.75 \times 703)[/tex]

                         = 692.25 [tex]kg/m^{3}[/tex]

Thus, we can conclude that the average density of given hexane/octane mixture is 692.25 [tex]kg/m^{3}[/tex].

Answer:

Maximum gravitational Force: [tex]F_{gmax} = 1,026*10^{-08} N[/tex]

Explanation:

The maximum gravitational force is achieved when the center of gravity are the closer they can be. For the spheres the center of gravity is at the center of it, so the closer this two centers of gravity can be is:

bowling ball radius + billiard ball radius = 0,128 m

The general equation for the magnitude of gravitational force is:

[tex]F_{gmax}  = G \frac{M*m}{r_{min}^{2} }[/tex]

Solving for:

[tex]G = 6,67*10^{-11}  \frac{Nm^{2}}{kg^{2}}[/tex]

[tex]M = 7,2 kg[/tex]

[tex]m = 0,35 kg[/tex]

[tex]r_{min} = 0,128 m[/tex]

The result is:

[tex]F_{gmax} = 1,026*10^{-08} N[/tex]

Answer:

Magnetic fields are the strongest at the poles

Explanation:

The strength of the field varies depending on its location around the magnet.

Magnetic fields are the strongest in either both pole of the magnet. The magnetic fields are equally strong in north and south pole.

This because, near the poles, magnetic field lines are very close to each other. In other words , near the poles the magnetic flux density is maximum so the magnetic field is stronger at that position.

Those flux lines are the mathematical representation of the magnetic field and are continuous - a given line must always form a closed loop, that want to return to the opposite pole via air. Density of those lines is the so called magnetic flux density - the number of lines per unit square - determines how strong the field is in a given area of space.  As they spread out, their density drops, so does the magnetic strength. In actual open-circuited bar magnet you would see the strongest field on the edges of the pole, this is where the flux lines bend and concentrate.

Halfway between the poles, in the middle of the magnet, the magnetic fields are the weakest.

Answer:

Magnetic fields are the strongest at the poles

Explanation:

Answer: Option (d) is the correct answer.

Explanation:

As it is known that like dissolves like. So, water being a polar compound is able to dissolve only polar compounds.

Hence, a compound that is ionic or polar in nature will readily dissolve in water. Whereas non-polar compounds will be insoluble in water.

As [tex]CCl_{4}[/tex] is a non-polar compound. Hence, it is insoluble in water.

On the other hand, [tex]CHCl_{3}[/tex] is a polar compound due to difference in electronegativity of chlorine and carbon atom there will be development of partial charges. Hence, there will be dipole-dipole forces existing between them.

Whereas [tex]NaNO_{3}[/tex] is an ionic compound and it will readily dissociate into ions when dissolved in water. Also, there will be ion-dipole interactions between sodium and nitrate ions.

Hence, [tex]NaNO_{3}[/tex] will readily dissolve in water.

Thus, we can conclude that the compounds correctly arranged in order of increasing solubility in water are [tex]CCl_{4}[/tex] < [tex]CHCl_{3}[/tex] < [tex]NaNO_{3}[/tex].

The correct order of compounds from least soluble to most soluble in water is CH4 < NaNO3 < CHCl3. CH4 is nonpolar and doesn't dissolve well in water, NaNO3 is an ionic compound and readily soluble, and CHCl3 is more soluble than CH4 but less than NaNO3 due to its polar bonds.

Looking at your options, the correct arrangement of compounds in order of increasing solubility in water from least to most soluble is CH4 < NaNO3 < CHCl3. The solubility of a compound in water depends on its molecular structure. CH4 (Methane) is a nonpolar compound and therefore, it doesn't dissolve well in water, a polar solvent.

On the other hand, NaNO3 (Sodium nitrate) is an ionic compound and can dissociate into its ions in water, making it highly soluble. CHCl3 (Chloroform) is a polar compound due to the presence of polar C-Cl and C-H bonds, and it is more soluble in water than CH4 but less soluble than NaNO3.

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Answer:

b) Cu2+

Explanation:

Ksp PbS = 3.4 E-28

Ksp CuS = 6.0 E-37

∴ Ksp = 3.4 E-28 = [ Pb2+ ] * [ S2- ]

∴ [ Pb2+ ] = 0.10 M

⇒ [ S2- ] = 3.4 E-28 / 0.10 = 3.4 E-27 M

∴ Ksp = 6.0 E-37 = [ Cu2+ ] * [ S2- ]

∴ [ Cu2+ ] = 0.10 M

⇒ [ S2- ] = 6.0 E-37 / 0.10 = 6.0 E-36 M

we have:

(1) [ S2- ] PbS >> [ S2- ] CuS

(2) Ksp PbS >> Ksp CuS

from (1) and (2) it can determined, that separation can be carried out and also the cation that precipitates first is the Cu2+

Answer:

The rate constant at T = 100 C is 1.0*10⁻³

Explanation:

The Arrhenius equation relates two rate constants K1 and K2 measured at temperatures T1 and T2 as shown below:

[tex]ln\frac{K_{2}}{K_{1}}=\frac{\Delta H^{0}rxn}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})[/tex]

here, ΔHrxn = standard enthalpy change of the reaction

R = gas constant

From the given information:

K1 = 7.4*10^-4

T1 = 25 C = 25+273 = 298 K

T2 = 100 C = 100+273 = 373K

ΔH°=4.1kJ/mol

[tex]ln\frac{K_{2}}{7.4*10^{-4}}=\frac{4.1 kJ/mol}{0.08314kJ/mol.K}(\frac{1}{298}-\frac{1}{373})K[/tex]

K2 = 1.03*10⁻³