Water behind a dam has a certain amount of stored energy that can be released as the water falls over the top of the dam. It may be enough energy to turn a mill wheel or an electricity-generating turbine. Choose the term that best describes the type of energy stored in the water at the top of the dam.
potential energy
kinetic energy
mechanical energy

Answer:

Will not.

Explanation:

just got the question correct.

Answer:

will not .

Explanation:

Answer:

B

Explanation:

Answer:

Answer in explanation

Explanation:

In this question, we will be providing an explanation as to why OPMD provides more than 10^10 higher rate acceleration than CA

we proceed as follows;

Kcat is a measure of the catalytic activity of an enzyme indicating how many reactions a molecule of enzyme can catalyze per second. But Michaelis constant, Km also plays role during rate acceleration. The kcat/Km ratio is useful for comparing the activities of different enzymes. It is also possible to assess the efficiency of an enzyme by measuring its catalytic proficiency.

This value is equal to the rate constants for a reaction in the presence of the enzyme (kcat/Km) divided by the rate constant for the same reaction in the absence of the enzyme (kn). an enzyme with rapid binding might evolve a mechanism that favored a faster reaction.

An electric field around the OMPD active site enhances the rate of formation of the ES complex. Electrostatic effects allow OMPD to bind and remove OMPD much faster than expected from random collisions of enzyme and substrate.

The spacecraft had an angular acceleration of 0.00873 rad/s². At 6 minutes into the flight, a point on the skin of the spacecraft had a radial (centripetal) acceleration of 0.01167 m/s² and a tangential acceleration of 0.0371 m/s².

First, let's find the angular acceleration which is the rate of change of angular velocity. The spacecraft went from 0 to 1 revolution per minute in 12 minutes. This is an angular acceleration (α) of 1 rev/min/12 min = 1/12 rev/min². However, we generally measure angular acceleration in rad/s², not rev/min². We know that 1 revolution = 2π rad and 1 min = 60 s, so we can convert our units to get α = ((1/12 rev/min²) x (2π rad/rev) x (1 min/60 s)²) = 0.00873 rad/s².

Next, we find the radial (centripetal) and tangential components of linear acceleration at 6 minutes. At 6 minutes, the angular velocity (ω) is (α x t) = ((1/12 rev/min) x 6 min) = 0.5 rev/min. Convert this to rad/s: ω = ((0.5 rev/min) x (2π rad/rev) x (1 min/60 s)) = 0.05236 rad/s. Now, the radial or centripetal acceleration (a_r) is given by (ω² x r) and the tangential acceleration (a_t) is given by (α x r), where r is the radius of the spacecraft, which is half of the diameter or 8.5 m / 2 = 4.25 m. We can plug the numbers in to get: a_r = (ω² x r) = (0.05236 rad/s)² x 4.25 m = 0.01167 m/s² and a_t = α x r = 0.00873 rad/s² x 4.25 m = 0.0371 m/s². So, the radial acceleration is 0.01167 m/s² and the tangential acceleration is 0.0371 m/s².

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Answer:

A C and D

Explanation:

Answer:

A C D

Explanation:

Answer:

Only technician A is correct

Explanation:

Analysis of technician A's statements

The refrigeration cycle contains four major components: the compressor, condenser, expansion device, and evaporator. Refrigerant remains piped between these four components and is contained in the refrigerant loop.

The refrigerant begins as a cool vapor and heads to the first component:

1. the compressor

It forces the refrigerant through the system. In the process of being compressed the cool, gaseous refrigerant is turned to a very hot and high-pressure vapor.

Analysis of technician B's statement

The condenser’s job is to cool the refrigerant so that it turns from a gas into a liquid, or condenses. This happens when warm outdoor air is blown across the condenser coil that is filled with hot, gaseous refrigerant.

The evaporator is responsible for cooling the air going to the space by boiling (evaporating) the refrigerant flowing through it. This happens when warm air is blown across the evaporator as cold refrigerant moves through the evaporator coil. Heat transfers from the air to the refrigerant, which cools the air directly before it is vented to the space.

Answer:

2.36 x 10^5 kg

Explanation:

radius of hose, r = 0.017 m

radius of underground pipe, R = 0.088 m

number of hoses, n = 3

velocity of water in underground pipe, V = 2.7 m/s

Let v is the velocity of water in each hose.

According to the equation of continuity

A x V = n x a x v

π R² x V = n x π x r² x v

0.088 x 0.088 x 2.7 = 3 x 0.017 x 0.017 x v

v = 24.12 m/s

(a) Amount of water poured onto a fire in one hour by all the three hoses              

                    = n x a x v x density of water x time

                    = 3 x 3.14 x 0.017 x 0.017 x 24.12 x 1000 x 3600

                    = 2.36 x 10^5 kg

Thus, the amount of water poured onto the fire in one hour is 2.36 x 10^5 kg.

a) Using the principles of fluid dynamics, specifically the continuity equation, we found that the velocity of water in the hoses is 2.02 m/s. The volume flow rate in the hoses is 0.0055 m³/s. Therefore, the mass of water poured onto a fire in one hour by all three hoses is 19800000 kg.

a) To answer this question, we need to apply the principles of fluid dynamics, specifically the concept of continuity equation which states that the mass flow rate (the mass of water passing through a given spot per unit time) through a pipe system is constant.

First, let's calculate the cross sectional area of the hydrant pipe (A1) which is πr² = π(0.088m)² ≈ 0.0243 m².

Then, calculate the area of one fire hose (A2) which is π(0.017m)² ≈ 0.000907 m².

Since there are three hoses, the total area for the three hoses (A3) is 3 * A2 ≈ 0.00272 m².

Then, we apply the continuity equation, which is

A1v1=A3v3. We can solve for v3 (the velocity of the water in the hoses), v3 = A1v1/A3 ≈ 2.02 m/s.

To find the mass of water delivered in one hour, we first find the volume flow rate in the hoses,

Q= A3v3 = 0.00272 m² * 2.02 m/s ≈ 0.0055 m³/s.

The volume of water in one hour is Q * 3600s = 19800 m³.

Then, since water has a density (ρ) of 1000 kg/m³, the mass (m) of the water is ρ*volume which equals

19800 * 1000 kg = 19800000 kg.

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Answer:

Frequency, f = 59.6 kHz

Explanation:

Given that,

Speed of sound, v = 340 m/s

The bat can detect an insect that is 0.0057 m long, [tex]\lambda=0.0057\ m[/tex]

We need to find the minimum frequency of sound waves required for a bat to detect an insect. The speed of a wave is given by :

[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{340\ m/s}{0.0057\ m}\\\\f=59649.12\ Hz[/tex]

or

f = 59.6 kHz

So, the frequency detected by the bat is 59.6 kHz.

The minimum required frequency of the sound wave is 59.65 kHz

Given information:

speed of sound, v = 340 m/s

the wavelength of insect that the bat can detect, λ = 0.0057 m

The wavelength, frequency, and speed are related as follows:

v = fλ

The minimum frequency of sound wave required is:

f = v/λ

where f is the frequency of the sound

f = 340/0.0057 s⁻¹

f = 59649 Hz

or,

f = 59.65 kHz

So the frequency comes out to be 59.65 kHz

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The given diagram of the magnet shows attraction which occurs between opposite poles therefore, A and C could both be the north poles. Thus, the correct option is C.

A magnet is a material or an object which produces a magnetic field around itself. The magnetic field of this magnet is invisible however it is responsible for the most notable property of a magnet which is a force that is responsible for pulling on other ferromagnetic materials, such as iron, steel, nickel, cobalt, etc. towards it and attracts or repels other magnets as well.

Some important properties of magnet include a magnet has two poles which are north pole and south pole, magnets attract ferromagnetic materials, the similar poles of two magnets repel each other, whereas the opposite poles of two magnets attract each other. A magnet hung up in the air always comes to rest facing the north-south direction. The poles of a magnet are arranged in pairs.

Therefore, the correct option is C.

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Wavelength = speed / frequency

(345 m/s) / (20,000 Hz) = 0.017 m

Formula to solve for the wavelength: w = s/f

w = wavelength

s = speed

f = frequency

Solve using the given values.

w = 345/20000

w = 0.01725

Round if necessary.

0.0173

Therefore, the wavelength is approximately 0.0173 meters.

Best of Luck!

Answer:

(A) Frictional force will be equal to 27.92 N

(B) Mass is equal to 33120 kg

Explanation:

(A) Diameter of nozzle d = 2.20 cm

So radius [tex]r=\frac{d}{2}=\frac{2.20}{2}=1.10cm[/tex]

eight h = 7.5 m

Density of water [tex]\rho =1000kg/m^3[/tex]

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Pressure on the rubber stopper

[tex]P=\rho hg[/tex]

[tex]p=1000\times 7.5\times 9.8=73500Pa[/tex]

Area of cross section [tex]A=\pi r^2[/tex]

[tex]A=3.14\times 0.01^2=3.799\times 10^{-4}m^2[/tex]

So force [tex]F=PA[/tex]

[tex]F=73500\times 3.799\times 10^{-4}=27.92N[/tex]

(B) Speed of the water through nozzle

[tex]v=\sqrt{2gh}[/tex]

[tex]=\sqrt{2\times 9.8\times 7.5}=12.12m/sec[/tex]

Volume of water flow

[tex]V=vA=12.12\times 3.799\times 10^{-4}=0.0046m^3/sec[/tex]

Mass of water flow per sec

[tex]m=\rho V=1000\times 0.0046=4.6kg[/tex]

Total time t = 2 hour = 2×3600 = 7200 sec

So total mass flow

[tex]m=4.6\times 7200=33120kg[/tex]

To calculate the friction force exerted on the stopper by the nozzle, use Bernoulli's equation for fluid flow. To calculate the mass of water that flows from the nozzle, use the equation Q = A * V.

To calculate the friction force exerted on the stopper by the nozzle, we can use Bernoulli's equation for fluid flow. The pressure at the top of the tank is atmospheric pressure, and the pressure at the nozzle is also atmospheric pressure. The friction force can be calculated by the equation F = P * A, where P is the pressure difference and A is the cross-sectional area of the stopper.

To calculate the mass of water that flows from the nozzle in 2.00 hours, we can use the equation Q = A * V, where Q is the volumetric flow rate, A is the cross-sectional area of the nozzle, and V is the velocity of the water.

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Answer:

C) 4.4

Explanation:

The potential of a cylindrical capacitor is given by the formula:

[tex]V=\frac{2kq}{L\epsilon}ln(\frac{a}{b})\\\\\epsilon=\frac{2kq}{LV}ln(\frac{a}{b})[/tex]

where:

k : Coulomb Constant

L : length of the capacitor

a : outer radius

b : inner radius

V : potential

By replacing we obtain:

[tex]\epsilon=\frac{2(8.89*10^{9}N/m^2C^2)(8.8*10^{-6}C)}{(1m)(6000V)}ln(\frac{1.3mm}{1.1mm})=4.35[/tex]

Hence, the answer is C) 4.4 (4.35 is approximately 4.4)

hope this helps!!

Answer:

kinetic energy does not change

Explanation:

you can use the formula for the kinetic energy of the electron and for the radius of the trajectory of an electron in a uniform magnetic field:

[tex]E_k=\frac{1}{2}m_ev^2\\\\r=\frac{m_e v}{qB}[/tex]

me: mass of the electron

B: magnetic field

q: charge of the electron

r: radius

By doing v the subject of the formula and replace it in the expression for the kinetic energy you obtain:

[tex]v=\frac{rqB}{m_e}\\\\E_k=\frac{1}{2}m_e(\frac{rqB}{m_e})^2=\frac{r^2q^2B^2}{2m_e}[/tex]

as youcan see, all parameters r, q, B and me are constant.

hence, the kinetic energy does not change

Answer:

The solution to the question above is explained below:

Explanation:

For which solid is the lumped system analysis more likely to be applicable?

Answer

The lumped system analysis is more likely to be applicable for the body cooled naturally.

Question :Why?

Answer

Biot number is proportional to the convection heat transfer coefficient, and it is proportional to the air velocity. When Biot no is less than 0.1 in  the case of natural convection, then lumped analysis can be applied.

Further explanations:

Heat is a form of energy.

Heat transfer describes the flow of heat across the boundary of a system due to temperature differences and the subsequent temperature distribution and changes. There are three different ways the heat can transfer: conduction, convection, or radiation.

Heat transfer  analysis which utilizes this idealization is known as the lumped system analysis.

The Biot number is a criterion dimensionless quantity used in heat transfer calculations which gives a direct indication of the relative importance of conduction and convection in determining the temperature history of a body being heated or cooled by convection at its surface. In heat transfer analysis, some bodies are observed to behave like a "lump" whose entire  body temperature remains essentially uniform at all times during a heat transfer process.

Conduction is the transfer of energy in the form of heat or electricity from one atom to another within an object and conduction of heat occurs when molecules increase in temperature.

Convection is a transfer of heat by the movement of a fluid. Convection occurs within liquids and gases between areas of different temperature.

Final answer:

The lumped system analysis is more applicable to the solid cooled naturally because natural convection is slower, allowing the solid's temperature to equalize, which suits the assumptions of lumped system analysis better than the enhanced convection caused by a fan.

Explanation:

The lumped system analysis is more likely to be applicable to the solid that is being cooled naturally rather than the one with a fan. The reason for this is that the use of a fan increases the flow of air over the surface, enhancing convection and therefore increasing the rate of heat transfer. This forced convection reduces the likelihood that the temperature gradient within the solid will remain uniform, which is a key assumption of lumped system analysis – that the object's temperature is spatially uniform and can be modeled as a lumped capacitance.

In contrast, when cooling occurs naturally, the heat transfer is driven by natural convection, which tends to be slower as it relies on the thermal expansion of the fluid around the solid due to the heat transfer from the solid. The slower rate of heat transfer allows the temperature within the solid to equalize more readily, making lumped system analysis a more appropriate simplification for predicting the thermal response of the solid.

Answer:

saturated solution is the correct answer.

Explanation:

Answer:

Shares electrons

Answer:

The outer shell electrons in metals are free to move from atom to atln

Explanation:

Answer: C = Q/4πR

Explanation:

Volume(V) of a sphere = 4πr^3

Charge within a small volume 'dV' is given by:

dq = ρ(r)dV

ρ(r) = C/r^2

Volume(V) of a sphere = 4/3(πr^3)

dV/dr = (4/3)×3πr^2

dV = 4πr^2dr

Therefore,

dq = ρ(r)dV ; dq =ρ(r)4πr^2dr

dq = C/r^2[4πr^2dr]

dq = 4Cπdr

FOR TOTAL CHANGE 'Q', we integrate dq

∫dq = ∫4Cπdr at r = R and r = 0

∫4Cπdr = 4Cπr

Q = 4Cπ(R - 0)

Q = 4CπR - 0

Q = 4CπR

C = Q/4πR

The value of C in terms of Q and R is [Q/4πR]

Answer:

[tex]E_n = \frac{kQ}{2} = 2E[/tex]

If the charge is doubled, the electric field is also doubled.

Explanation:

Electric field due to the negative charge is given as:

[tex]E = \frac{kQ}{r^2}[/tex]

where k = Coulomb's constant

Q = electric charge

r = distance between charge and point of consideration

At 2 m from the negative charge, the magnitude of the Electric field due to a negative charge -Q is given as E:

[tex]E = |\frac{-kQ}{2^2}| \\\\\\E = \frac{kQ}{4}[/tex]

If the charge is doubled, the new charge becomes -2Q and the new electric field becomes:

[tex]E_n = |\frac{-2kQ}{4}| \\\\\\E_n = |\frac{-kQ}{2}|[/tex]

[tex]E_n = \frac{kQ}{2} = 2E[/tex]

If the charge is doubled, the electric field is also doubled.

Answer:

E'=(1/4)E

Explanation:

The magnitude of the electric force is given by:

[tex]E=k\frac{q}{r^2}[/tex]

where k is the Coulomb constant (8.89*10^{9}Nm^2/C^2).

When the distance is r=2m we have:

[tex]E=k\frac{q}{(2m)^2}=k\frac{q}{4m^2}[/tex]

when the distance is doubled we obtain:

[tex]E'=k\frac{q}{(4m)^2}=k\frac{q}{16m^2}=\frac{1}{4}k\frac{q}{4m^2}=\frac{1}{4}E[/tex]

Hence, the new electric field is a quarter of the first electric field.

hope this helps!

According to the law of conversion of mass, the mass of a closed system is neither made or taken away in a physical change. It is the same for a chemical change as well.

Therefore, the mass of the substance remains 8g.

Best of Luck!

Answer:

The water level rises more when the cube is located above the raft before submerging.

Explanation:

These kinds of problems are based on the principle of Archimedes, who says that by immersing a body in a volume of water, the initial water level will be increased, raising the water level. That is, the height in the container with water will rise in level. The difference between the new volume and the initial volume of the water will be the volume of the submerged body.

Now we have two moments when the steel cube is held by the raft and when it is at the bottom of the pool.

When the cube is at the bottom of the water we know that the volume will increase, and we can calculate this volume using the volume of the cube.

Vc = 0.45*0.45*0.45 = 0.0911 [m^3]

Now when a body floats it is because a balance is established in the densities, the density of the body and the density of the water.

[tex]Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3][/tex]

Density is given by:

Ro = m/V

where:

m= mass [kg]

V = volume [m^3]

The buoyancy force can be calculated using the following equation:

[tex]F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3][/tex]

Vs > Vc, What it means is that the combined volume of the raft and the cube is greater than that of the cube at the bottom of the pool. Therefore the water level rises more when the cube is located above the raft before submerging.

Answer:

y = 0.1sin(4.5x - 345.6t)

Explanation:

Parameters given:

Length of 5 wavelengths = 7 m

Length of one wavelength, λ = 7/5 = 1.4 m

Frequency of wave, f = 55 Hz

Peak to Valley displacement = 20 cm = 0.2 m

Amplitude is half of the Peak to Valley displacement = 0.1 m

The wave function of a wave traveling in the positive x direction is given generally as:

y = Asin(kx - wt)

Where A = amplitude

k = Wave factor = 2π/λ

x = displacement on the x axis

w = angular frequency = 2πf

t = time taken

=> Wave factor, k = 2π/λ = 2π/(1.4) = 4.5 m^(-1)

=> Angular frequency, w = 2πf = 2π * 55 = 345.6 Hz

Therefore, inserting all the necessary parameters, we get that the wave function is:

y = 0.1sin(4.5x - 345.6t)

Answer:

Work done

Explanation:

The work done on an object is given as the product of force and distance traveled by the object.

J = Ft (Ns)

The change in the momentum of an object is equal to the impulse experienced by the object.

The work done on an object is given as the product of force and distance traveled by the object.

W = Fd (J)

The work done on an object causes change in the position of the object.

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Given that,

Frequency of radio wave is from  f = 10⁵ Hz and f' = 10³ Hz

We need to find the wavelength of radio wave. The speed of a wave is given by formula as follows :

If f = 10⁵ Hz

[tex]v=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{10^5}\\\\\lambda=3000\ m[/tex]

or

[tex]\lambda=3\ km[/tex]

If f' = 10³ Hz

[tex]v=f\lambda\\\\\lambda'=\dfrac{c}{f'}\\\\\lambda'=\dfrac{3\times 10^8}{10^3}\\\\\lambda'=300000\ m[/tex]

or

[tex]\lambda'=300\ km[/tex]

So, the wavelength of this radio wave on the order of kilometres.

The wavelength of this radio wave is on the order of meters.

The wavelength of a radio wave can be calculated using the formula: wavelength = speed of light / frequency. In this case, the given frequency of the radio wave is on the order of 10^5 Hz. To compare it with the lowest audible sound waves with a frequency of 20 Hz, we can use the formula again. Taking the speed of sound in air at 20 °C as 343 m/s, we can calculate the wavelength of the lowest audible sound waves. By comparing the wavelengths of the two waves, we can determine the order of magnitude of the wavelength of the radio wave.

Let's calculate the wavelengths:

Wavelength of radio wave = speed of light / frequency = (3 x 10^8 m/s) / (10^5 Hz) = 3000 m

Wavelength of lowest audible sound wave = speed of sound / frequency = (343 m/s) / (20 Hz) = 17.15 m

Comparing the two wavelengths, we can see that the wavelength of the radio wave is on the order of meters.

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Answer:

12.27 ft/s

Explanation:

At 72 ft above the ground,  the balloons height increases at a rate of 4ft/s. For 66s, vertical distance moved, y = 4ft/s × 66 s = 264 ft. When the balloon is at 72 ft above the ground, just below it, the bicycle which moves at a rate of 12 ft/s in 66 s, covers a horizontal distance, x = 12ft/s 66 = 792 ft.

The distance between the bicycle and the balloon 66 s later is given by

s = √(x² + (y + 72)²) = √(792² + (264 + 72)²) = √(792² + 336²) = √740160 ft = 860.33 ft

From calculus

The rate of change of the distance between the balloon and bicycle s is obtained by differentiating s with respect to t. So,

ds/dt = (1/s)(xdx/dt + ydy/dt)

dx/dt = 12 ft/s, x = 792 ft, dy/dt = 4 ft/s, y = 264 ft, s = 860.33. These are the values of the variables at t = 66 s.

So, substituting these values into ds/dt, we have

ds/dt = (1/860.33)(792 ft × 12 ft/s + 264 ft × 4ft/s) = (1/860.33)(9504 + 1056) = 10560/860.33 = 12.27 ft/s

1) 2 Forces

2) 563 N, upward

3) [tex]8.66 m/s^2[/tex], upward

4) Speed is decreasing

Explanation:

1)

There are two forces acting on teacher during his skydiving:

- The force of gravity (also known as weight), acting downward (towards the Earth's centre), of magnitude

[tex]W=mg[/tex]

where

m is the mass of the teacher

g is the acceleration due to gravity

- The air resistance, of magnitude R = 1200 N, acting upward (air resistance always acts in the direction opposite to the direction of motion)

There are no other forces, therefore the correct answer is:

2 Forces

2)

The net force on the system is given by the vector resultant of the two forces described in part 1). Since the two forces act along the same line but in opposite directions, the net force will be equal to the difference between the two forces, so:

[tex]F_{net}=W-R=mg-R[/tex]

where we have chosen downward as positive direction, and where

m = 65 kg is the mass of the teacher

[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity

R = 1200 N is the air drag

Therefore, the net force on the teacher is

[tex]F_{net}=(65)(9.8)-1200=-563 N[/tex]

And the negative sign means that the direction of the net force is upward.

3)

The acceleration of the system can be found by using Newton's second law of motion, which can be written as

[tex]a=\frac{F_{net}}{m}[/tex]

where

a is the acceleration

[tex]F_{net}[/tex] is the net force

m is the mass of the teacher

Here we have

[tex]F_{net}=-563 N[/tex]

m = 65 kg

Therefore, the acceleration is

[tex]a=\frac{-563}{65}=-8.66 m/s^2[/tex]

And the negative sign indicates that the direction of the acceleration is opposite to the motion (so, upward).

4)

From part 3), we observed that:

- The motion of the teacher is downward (he is moving downward)

- However, the direction of his acceleration is upward

This means that the velocity and the acceleration of the system have opposite directions.

As we know, the velocity of an accelerating system can be written as

[tex]v=u+at[/tex]

where

v is the velocity after time t

u is the initial velocity

a is the acceleration

Since a is negative, we see that [tex]at<0[/tex], so [tex]v<u[/tex]: this means that the velocity of the teacher is decreasing with time, so, the teacher is slowing down, and therefore his speed is decreasing.

(a) Two forces are acting on the system.

(b) The magnitude of net force on the system is 592.4 N.

(c) The magnitude of the acceleration is 9.11 m/s².

(d) The speed of the system decreases with time

The given parameters;

The forces acting on the teacher are downward force due to the teachers weight and drag force acting upward opposing the downward motion.

The magnitude of net force on the system is calculated as follows;

[tex]F_{net}= W - F_f\\\\F_{net}= (65 \times 9.8) - (1200)\\\\F_{net} = -592.4 \ N[/tex]

The magnitude of the acceleration is calculated as follows;

[tex]a = \frac{-592.4}{65} \\\\a = -9.11 \ m/s^2\\\\|a| = 9.11 \ m/s^2[/tex]

The speed of the system is calculated as follows;

[tex]v= u + at\\\\v= 0 + (-9.11)t\\\\v = -9.11t[/tex]

The speed of the system decreases with time.

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Answer:

The answer of the question is None.

Answer:

Period is 1/20 of a second.

Explanation:

Frequency is 20 vibrations per second. Period and frequency are reciprocals (period = 1/f). Period is 1/20 of a second.

Tt will take approximately 0.14 seconds for the force of 2.5 N to bring the 0.25 kg object to rest from an initial velocity of 1.4 m/s

The question involves the application of Newton's second law of motion and the concepts of force, mass, acceleration, and time to bring an object to rest. Given a 0.25-kg object moving at 1.4 m/s, and a force of 2.5 N acting on it, we can first determine the acceleration using Newton's second law, F=ma, which gives us an acceleration of 10 m/s2. Next, we use the kinematic equation v = u + at (where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time) to find the time. Since the object comes to rest, v = 0 m/s, solving the equation for t gives us a time of 0.14 seconds to bring the object to rest.

Answer: GLOMERULUS

Explanation:

The specialized capillary bed responsible for the pressure that drives filtration is the

GLOMERULUS.

The kidney is an organ responsible for the excretion of nitrogenous wastes from the human body and osmoregulation of the blood and body fluids. The structure which is responsible for formation of urine is the nephron( kidney tubule). The GLOMERULUS are found within the Bowman's capsule of the nephrons. It is made up of specialised bundle of capillary beds which are the only capillary beds that are not surrounded by interstitial fluid in the body. In the glomerulus, blood pressure is high because an arteriole enters and exists the capillary beds which is responsible for the pressure that drives filtration.

The glomerulus, a specialized capillary bed in the kidney nephrons, creates pressure driving filtration, a process important for maintaining body homeostasis.

The specialized capillary bed responsible for the pressure that drives filtration is the glomerulus. This structure, located within the nephrons of the kidney, creates a pressure high enough to force substances such as water, glucose, and electrolytes out of the blood and into the nephron tubule, beginning the process of urine formation. The glomerular filtration process is an essential part of maintaining bodily homeostasis, i.e., keeping a stable internal environment in the body.

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