What could you make by chopping a copper wire into small pieces?

Answer:

the answer is D: 60o N/60o E

Explanation:

sorry i had to but a o for a degrees sign :)

Answer:

it is a. 30° N/60° W

Explanation:

The ion-molecular attraction between NaCl and water has been Na attracted with the oxygen of water, while Cl has been attracted with the hydrogen of water.

The ion has been the charged molecules that has been formed with the loss or gain of the electrons, while the molecules has been the molecules with the bonded anions and cations.

The water has been the polar molecule, with the development of partial positive charge over hydrogen atoms, and partial negative charge over the oxygen atom.

The like charges repel each other, while unlike charges attract each other.

The addition of NaCl to water results in the formation of positive Na ions, and negative Cl ions.

The interaction is demonstrated in the image attached.

Thus, the molecular attraction between NaCl and water has been Na has been attracted with the oxygen of water while Cl has been attracted with the hydrogen of water.

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Answer:

3.179 atm

Explanation:

Osmotic pressure is expressed as:

π = iMRT , Where

π = osmotic pressure

i = van't Hoff factor  

M = molar concentration

R = universal gas constant (0.08206 L·atm/mol·K )

T = absolute temperature in K

In this case, i = 2, M = 0.065, R = 0.08206 and T = 298. Substitute into the formula:

π = 2 x 0.065 x 0.08206 x 298

   = 3.179 atm

The osmotic pressure is 3.179 atm.

The energy conversion or the energy transformation is the process of changing one form of energy to another , the energy produces certain changes within a system , Changes in the total energy of systems can only be accomplished by adding or removing the energy from them as the energy is a quantity which is conserved ( unchanging ) .

The internal combustion engine in the car converts the potential chemical energy in gasoline and oxygen into thermal energy which is transformed into the mechanical energy that accelerates the vehicle ( increasing its kinetic energy ) by causing the pressure and performing the work on the pistons .

Answer:

4.245 × 10²¹ cubic centimetre of Fe

Explanation:

First step is to find the number of atoms that is present in Fe(Iron)

The atomic mass of Fe(iron) is  55.845

We  have to convert  the atomic weight into grams

1 atomic mass = 1.66 x 10⁻²⁴grams

55.845(atomic mass of Fe) =

55.845 x 1.66 x 10 ⁻²⁴ grams = 9.27 x 10²² grams.

Therefore, the number of atoms in a cubic centimetre of Fe (Iron) =

Density of Fe(solid) ÷ number of grams of Fe

Density of Fe (solid) is known as = 7.874g/cm³

The number of atoms in a cubic centimetre of Fe (Iron =

7.874g/cm³ ÷9.27 x 10²²grams

= 8.494 × 10²¹atoms.

In the question we are told Fe adopted a body centered cubic unit cell

Hence , in Body centered cubic unit cell, we have:

We have one atom at the 8 corners of a cube

We also have one body atom the cube's center

8 corners × 1/8 per corner atom = 8 × 1/8 = 1 atom

(8 corners × 1/8 per corner atom) + (1× 1) = 2 atoms

Therefore, the total number of featoms present per unit cell = 2 atoms.

The number of unit cells are present per cubic centimeter of Fe =

Number of Fe atoms per cubic centimeter ÷ Number of Fe per unit cell

= 8.494 × 10²¹ atoms ÷ 2 atoms.

= 4.247 × 10²¹ cubic centimetre of Fe

Hence the number of unit cells that are present per cubic centimeter of Fe is

4.247 × 10²¹ cubic centimetre of Fe.

Volume of hydrogen sample at [tex]23^\circ\text{C}[/tex] is [tex]\boxed{419.4\text{ mL}}[/tex].

Further Explanation:

Ideal gas equation:

A hypothetical gas comprising of many randomly moving particles having perfectly elastic collisions between them is called ideal gas. The expression for ideal gas equation is mentioned below.

[tex]\text{PV}=\text{nRT}[/tex]                                                      ...... (1)

Here,

P is the pressure of gas.

V is the volume of gas.

T is the absolute temperature of gas.

n is the number of moles of gas.

R is the universal gas constant.

At temperature [tex]\text{T}_{1}[/tex] , volume [tex]\text{V}_{1}[/tex]  and pressure [tex]\text{P}_{1}[/tex] , ideal gas equation for hydrogen gas modifies as follows:

[tex]\text{P}_{1}\text{V}_{1}=\text{nRT}_{1}[/tex]                                                  ...... (2)

At temperature [tex]\text{T}_{2}[/tex] , volume [tex]\text{V}_{2}[/tex]  and pressure [tex]\text{P}_{2}[/tex] , ideal gas equation for hydrogen gas modifies as follows:

[tex]\text{P}_{2}\text{V}_{2}=\text{nRT}_{2}[/tex]                                                  ...... (3)

Dividing equation (3) by equation (2),

[tex]\dfrac{\text{P}_{2}\text{V}_{2}}{\text{P}_{1}\text{V}_{1}}=\dfrac{\text{T}_{2}}{\text{T}_{1}}[/tex]                                                      ...... (4)

Rearrange equation (4) to calculate  .

[tex]\text{V}_{2}=\dfrac{{\text{P}_{1}\text{V}_{1}\text{T}_{2}}}{\text{P}_{2}\text{T}_{1}}[/tex]                                                  …… (5)

The value of [tex]\text{P}_{1}[/tex]  can be calculated as follows:

 [tex]\begin{aligned}\text{P}_{1}=&763\text{ torr}+42.2\text{ torr}\\=&805.2\text{ torr}\end{aligned}[/tex]

The value of [tex]\text{P}_{2}[/tex]  can be calculated as follows:

 [tex]\begin{aligned}\text{P}_{2}=&763\text{ torr}+21.1\text{ torr}\\=&784.1\text{ torr}\end{aligned}[/tex]

The value of  [tex]\text{T}_1[/tex] can be calculated as follows

[tex]\begin{aligned}\text{T}_1=&\left(35+273.15\right)\text{ K}\\=&\ 308.15\text{ K}\end{aligned}[/tex]

The value of  [tex]\text{T}_2[/tex] can be calculated as follows

[tex]\begin{aligned}\text{T}_2=&\left(23+273.15\right)\text{ K}\\=&\ 296.15\text{ K}\end{aligned}[/tex]

Substitute 805.2 torr for [tex]\text{P}_{1}[/tex]  , 425 mL for [tex]\text{V}_{1}[/tex] , 784.1 torr for [tex]\text{P}_{2}[/tex] , 308.15 K for [tex]\text{T}_{1}[/tex]  and 296.15 K for [tex]\text{T}_{2}[/tex]  in equation (5).

[tex]\begin{aligned}\text{V}_{2}&=\dfrac{\left({805.2\text{ torr}\right)\left(425\text{ mL}\right)\left(296.15\text{ K}\right)}}{\left(784.1\text{ torr}\right)\left(308.15\text{ K}\right)}\\&=419.4\text{ mL}\end{aligned}[/tex]

Therefore volume of hydrogen sample at [tex]23^\circ\text{ C}[/tex]  comes out to be 419.4 mL.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: ideal gas equation, R, T, n, P, V, T1, T2, P1, P2, V1, V2, 419.4 mL, pressure, volume, universal gas constant.

Answer: C. A period of drought

Explanation:    

A drought is a natural hazard which occurs when a region receives below average precipitation, the region experiences a shortage of water due to the sources of water like lakes, ponds and river get dry. The region is affected by hot and dry climatic conditions, soil becomes compact and looses it's fertility.

C. A period of drought will cause the agrarian society to begin developing the irrigation techniques required to conserve water. As, the agriculture is necessary practice to meet the food requirement of large human population the drought conditions may pose difficulty in irrigating the agricultural field.

Answer:

A period of drought

Explanation:

got it right on a.p.e.x

You need to add 4.043 grams of anhydrous calcium bromide (CaBr2) to make a 0.202 M aqueous solution in a 125 mL volumetric flask.

To calculate the mass of CaBr2 needed, use the formula molarity  imes volume (in liters)  imes molar mass. The molarity is given as 0.202 M, and the volume needs to be converted to liters (0.125 L). The molar mass of CaBr2 is approximately 199.9 g/mol. Multiplying these values gives us the mass in grams:

0.202 mol/L  imes 0.125 L  imes 199.9 g/mol = 5.0475 g

However, since mass must be measured accurately in the laboratory, this final result must be weighed correctly using a balance and all the necessary safety precautions must be observed when handling calcium bromide.

= [tex]\frac{1000}{18} = 55.55[/tex]

Molarity of the solution = 2.2

The amount of water = moles of solvent

[tex]\frac{55.55}{55.55+2} =0.9619\\\\[/tex]

From Raoults law

Vapor pressure = mole fraction * vapor pressure

= 17.54*0.9619

= 16.87 torr

Lowered vapor pressure

17.54 - 16.87

= 0.67 torr

[tex]\frac{55.55}{55.55+2.2*2} =0.93[/tex]

0.93*17.54 = 16.31

17.54-16.31 = 1.23

The lowered vapor with NACl = 1.23

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Final answer:

The balanced chemical equation for the combustion of propane is C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l). To find the limiting reactant, convert the mass of the reactants to moles, then compare the mole amounts to the ratio in the balanced equation.

Explanation:

Combustion of Propane

The balanced chemical equation for the combustion of propane is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)
To determine the limiting reactant, compare the mole ratio of the reactants to the amounts you have. For propane and oxygen, the mole ratio is 1:5. In the given problem, 30.0 g of propane (C3H8) reacts with 75.0 g of oxygen (O2). First, convert the mass of each reactant to moles using their molar masses (propane: 44.10 g/mol, oxygen: 32.00 g/mol). Then compare the mole amounts given the ratio required by the balanced equation. The reactant that provides the smaller number of moles required by the ratio is the limiting reactant.

A sea breeze is a wind that blows from the sea to the warmer land during the day, while a land breeze blows from the land to the sea at night due to differences in temperature creating distinct pressure areas.

Land Breezes and Sea Breezes Defined

A sea breeze is a local wind pattern that occurs during the day or summer when the land heats up faster than the water. As a result, lower pressure forms over the land, drawing cooler, higher pressure air in from the sea towards the land to replace the rising warm air. Conversely, a land breeze occurs at night when the land cools down more quickly than the water, creating higher pressure over the land and lower pressure over the water.

This causes air to move from the land out towards the sea. Both phenomena are examples of land/sea breezes which occur due to differential heating and cooling of land and water, creating pressure gradients that drive local winds.

Explanation:

Probe melted because the material used in the making of the probe was not that much resistant to the high temperature of the sun. So, now they have to design a probe with material which should have very high resistance to a high temperature so that the probe does not get melt again.

The solubility of cadmium carbonate, CdCO3, in a 0.010-M solution of cadmium bromide can be calculated using the compound's Ksp value. The molar solubility is found to be 1.0 × 10^-6 M. Converting this to grams per liter gives a solubility of 1.724 × 10^-4 g/L.

The solubility of cadmium carbonate, CdCO3, can be determined using the Ksp value. The Ksp value represents the product of the concentrations of the dissolved ions in a saturated solution. In this case, the Ksp of CdCO3 is 1.0 × 10^-12. Since the compound dissociates into Cd2+ and CO3^2- ions, the solubility can be calculated by assuming x as the molar solubility of CdCO3. Thus, [Cd2+] = x and [CO3^2-] = x. Plugging in these values into the Ksp expression, we get:

(x)(x) = 1.0 × 10^-12

x^2 = 1.0 × 10^-12

x = √(1.0 × 10^-12) = 1.0 × 10^-6 M

Since the question asks for the solubility in g/L, we need to convert the molar solubility to grams per liter. We can use the molar mass of CdCO3, which is approximately 172.4 g/mol. Therefore, 1.0 × 10^-6 M is equivalent to 1.724 × 10^-4 g/L.

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One cup of kidney beans with 15 g of protein, 1 g of fat, and 42 g of carbohydrate contains approximately 237 kilocalories, when calculated using the given caloric values for each macronutrient.

To calculate the number of kilocalories in a cup of kidney beans that contains 15 g of protein, 1 g of fat, and 42 g of carbohydrate, we can use the given caloric values of 4 kcal/g for carbohydrates, 4 kcal/g for protein, and 9 kcal/g for fat.

The total kilocalories can be calculated as follows:

Adding these together gives:

168 kcal from carbohydrates + 60 kcal from protein + 9 kcal from fat = 237 kilocalories in total.

Therefore, one cup of kidney beans contains approximately 237 kilocalories, to two significant figures.

Answer: Option (a) is the correct answer.

Explanation:

An equation can only be balanced when number of reactants equal the number of products.

The given equation is as follows.

   [tex]Ca(OH)_{2} + H_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + H_{2}O[/tex]

The number of reactant atoms are as follows.

The number of product atoms are as follows.

To balance the equation, multiply [tex]Ca(OH)_{2}[/tex] by 3, and [tex]H_{3}PO_{4}[/tex] by 2 on the reactant side. Multiply [tex]H_{2}O[/tex] by 6 on the product side. Therefore, the equation will be as follows.

[tex]3Ca(OH)_{2} + 2H_{3}PO_{4} \rightarrow Ca_{3}(PO_{4})_{2} + 6H_{2}O[/tex]

Thus, we can conclude that the coefficient in front of [tex]Ca_{3}(PO_{4})_{2}[/tex] is 1.

Final answer:

The theoretical yield of SiC from 50.0 grams of SiO2 is 33.36 grams, and the actual yield is 29.07 grams, based on an 87.2% percent yield.

Explanation:

The theoretical yield of silicon monocarbide (SiC) can be calculated from the stoichiometry of the reaction between silicon dioxide (SiO2) and carbon (C). Given that 50.0 grams of SiO2 are reacting, we first convert this mass to moles using the molar mass of SiO2 (60.08 g/mol). The balanced chemical equation for the reaction is:

SiO2(s) + 3C(s) → SiC(s) + 2CO(g)

Next, we determine the moles of SiC that can be produced from the moles of SiO2, and convert those moles to grams to find the theoretical yield of SiC. To calculate the actual yield, we use the percent yield (87.2%) and apply it to the theoretical yield.

The steps are:

Convert 50.0 grams of SiO2 to moles: n(SiO2) = 50.0 g / 60.08 g/mol.

Use the stoichiometry of the reaction to determine moles of SiC.

Convert moles of SiC to grams, which is the theoretical yield.

Multiply the theoretical yield by the percent yield (87.2%) to determine the actual yield of SiC.

The theoretical yield: n(SiO2) = 50.0 / 60.08 = 0.832 moles of SiO2, which theoretically yields 0.832 moles of SiC since the molar ratio between SiO2 and SiC is 1:1. Now, using the molar mass of SiC (40.10 g/mol), the theoretical yield in grams: 0.832 moles × 40.10 g/mol = 33.36 grams of SiC. The actual yield of SiC is then calculated as: 33.36 g × 87.2% = 29.07 grams.

No atoms are destroyed or made into new ones. When reactants come into touch with one another, the bonds between their atoms are broken, and the atoms then reorganize and establish new bonds to create the products. This statement is false.

In a chemical reaction, one or more substances also known as reactants are changed into one or more additional substances also known as products. Chemical elements or chemical compounds make up substances.

A chemical change, often known as a chemical reaction, is the process by which one or more substances are converted chemically into another.

A drug combining with another substance may be necessary in this situation. It could also entail a material disintegrating into other substances.

Thus, option B is correct.

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Answer:

0.78 J/g-°C is the correct answer

Explanation: