Sitting for long hours without any interruption may cause painful neck, swayed back in the long run and sometimes disc damage.
Explanation:
Human bodies are designed to stand upright. Cardiovascular and bowel functions work effectively in that way. Sitting too long may weaken and deplete large leg and gluteal muscles which are significant in walking and stabilizing the body.
It also causes stress and reduced social skills. It can also lead to serious health hazards such as cardiovascular complications, diabetes, imbalances in spinal structure. To avoid all these exercises, yoga, stretching regularly is mandatory.
How are energy of motion and speed are related to each other?
The energy transferred is known as kinetic energy, and it depends on the mass and speed achieved. Kinetic energy can be transferred between objects and transformed into other kinds of energy.
A boy is pulling a load of 150N with a string inclined at an angle 30 to the horizontal if the tension of string is 105N the force tending to lift the load off the ground is
The force tending to lift the load (vertical force) is equal to 22.5N.
Why?
Since the boy is pulling a load (150N) with a string inclined at an angle of 30° to the horizontal, the total force will have two components (horizontal and vertical component), but we need to consider the given information about the tension of the string which is equal to 105N.
We can calculate the vertical force using the following formula:
[tex]VerticalForce=Force*Sin(30\° )=(BoysForce-StringForce)*\frac{1}{2}\\\\VerticalForce=(150N-105N)*\frac{1}{2}=VerticalForce=45N*\frac{1}{2}=22.5N[/tex]
Hence, we can see that the force tending to lift the load off the ground (vertical force) is equal to 22.5N.
Have a nice day!
A block with mass m = 6 kg is sitting on a horizontal surface and not moving. The free-fall acceleration is g = 9.81 m/s2. Please answer the following questions.
a. Write an expression for the magnitude of the force of gravity Fg on the block.
b. Calculate the magnitude of the force of gravity Fg on the block in Newtons.
c. In what direction is the force of gravity in this problem?
d. What is the magnitude of the normal force FN in Newtons?
e. In what direction does the normal force act?
Answer:
a. expression for force of gravity is mg
b. Value of force of gravity is 58.86 N
c. Direction of force of gravity is downwards
d. Value of normal force is -58.86 N
e. direction of normal force is upwards.
Explanation:
Given that mass of the block [tex]m=6 kg[/tex]
acceleration due to gravity [tex]g=9.81 m/s^2[/tex]
a. Expression for force of gravity is [tex]F_g=m\times g[/tex]
b. [tex]F_g=mg=6 \times 9.81=58.86 N[/tex]
force of gravity is [tex]58.86 N[/tex]
c. Force of gravity always acts in the downward direction.
d. Normal force[tex]F_N[/tex] acts in the direction opposite to the weight of the block and their magnitudes are same. since the object is at rest the upward and downward forces on the block are balanced.
[tex]F_N=-F_g=-58.86 N[/tex]
e. Normal force [tex]F_N[/tex]acts in the upwards.
The force of gravity on a 6 kg block is 58.86 N, acting downwards, while the normal force is 58.86 N, acting upwards, since the block is stationary on a horizontal surface.
Explanation:Forces Acting on a Stationary Block
a. The expression for the magnitude of the force of gravity Fg on the block is given by Newton's second law of motion: Fg = m × g where m is the mass of the object and g is the acceleration due to gravity.
b. To calculate Fg, simply multiply the mass m by the acceleration due to gravity g: Fg = 6 kg × 9.81 m/s² which equals 58.86 N.
c. In this problem, the direction of the force of gravity is vertically downwards, towards the center of the Earth.
d. The magnitude of the normal force FN on the block is equal to the force of gravity acting on the block when it is stationary on a horizontal surface, therefore FN = 58.86 N.
e. The normal force acts in a direction perpendicular to the surface, which in this case is vertically upwards.
Which of the following represents the wavelength of a wave?
Diagram of a wave. The point between the highest and lowest points is labeled A; the height is labeled B; the highest point is labeled C; the distance between the highest points of consecutive waves is labeled D.
A
B
C
D
Answer: D. the distance between the highest points of consecutive waves
Explanation:
The wavelength of a wave is defined as the distance traveled by a periodic perturbation that propagates through a medium in a given time interval. It is usually represented by [tex]\lambda[/tex] and can be calculated if the frequency of the wave is known, since there is an inverse relationship between both.
In the specific case of a periodic sine wave (which is the way in which a wave is usually represented graphically) the wavelength can be determined as the distance between two consecutive maxima of the disturbance.
Therefore, the correct option is D.
Answer:
Explanation:
D. the distance between the highest points of consecutive waves
What is needed to create change in a system?
5. A car is traveling at 100 km/hr. How many hours will it take to cover a displacement of 750 km?
Answer:
It will take 1 hour for a car to cover a displacement of 750 km at a constant speed of 100 km / hr.
Explanation:
Velocity is associated with the change of position of a body over time. In other words, speed expresses the relationship between the space traveled by an object, the time taken for it and its direction.
That is, speed implies the change of position of an object in space within a certain amount of time (that is, speed), added to the direction in which said movement occurs.
Then, 100 km / hr is the speed of the car and indicates that every hour the car travels 100 kilometres.
Then it is possible to apply a rule of three to calculate the time it takes for the car to travel 750 km. The three employee rule is: if 100 km are traveled in 1 hour, 750 km in how long is it traveled?
[tex]time=\frac{750 km*1hour}{100 km}[/tex]
time=7.5 hour
It will take 1 hour for a car to cover a displacement of 750 km at a constant speed of 100 km / hr.
19) Suppose that a car traveling to the east (+x direction) begins to slow down as it approaches a traffic
light. Which statement concerning its acceleration must be correct?
A) Its acceleration is in the -x direction.
B) Its acceleration is zero.
Its acceleration is decreasing in magnitude as the car slows down.
D) Its acceleration is in the +x direction.
Answer: C) Its acceleration is decreasing in magnitude as the car slows down.
Explanation:
According to the described situation the car's final velocity is less than its initial velocity, this means the car's velocity decreased as it slows down.
On the other hand, acceleration [tex]a[/tex] is defined as the variation of velocity in time:
[tex]a=\frac{\Delta V}{\Delta t}[/tex]
If the car's velocity decreases, its acceleration is negative. Hence, the acceleration is decreasing in magnitude as well.
In the context of a car slowing down while traveling east, its acceleration must be in the -x direction (towards the west) which means its acceleration is in the opposite direction of its motion, hence option A is correct.
The question concerns the acceleration of a car traveling east (considered the +x direction) as it begins to slow down when approaching a traffic light. According to the principles of physics, when an object is slowing down, its acceleration is in the opposite direction of its motion. Since the car is moving to the east and slowing down, its acceleration must be towards the west, which is the -x direction in our coordinate system. Therefore, its acceleration is in the -x direction, making the correct answer to the question Option A.
To further clarify, when a car traveling in a positive direction (to the east in this case) decelerates or slows down, it undergoes negative acceleration because the deceleration is opposite to the direction of its velocity. Hence, in the context of our coordinate system where the east is positive, the westward acceleration (slowing down) is considered negative.
What is gas pressure
Answer:
Pressure is a force exerted by the substance per unit area on another substance. The pressure of a gas is the force that the gas exerts on the walls of its container. When you blow air into a balloon, the balloon expands because the pressure of air molecules is greater on the inside of the balloon than the outside.xplanation:
Answer:
Pressure is a force exerted by the substance per unit area on another substance. The pressure of a gas is the force that the gas exerts on the walls of its container. When you blow air into a balloon, the balloon expands because the pressure of air molecules is greater on the inside of the balloon than the outside.
Explanation:
Which of the following will not conduct an electrical current?
pure water
tap water
aquarium water
ocean water
Answer:
Pure water won’t conduct electricity
Option A
Explanation:
Pure water doesn’t contain salts or impurities. It is the salts that dissociate to form ions that act as charge carriers in conducting solutions. For a medium to conduct electricity it should have carriers to carry the electrical charge.
Thus absence of charge carriers make pure water non conducting. Charge carriers in metals are electrons and in ionic solutions they are positive and negative ions.
Tap water, aquarium water and ocean water contains dissolved electrolytes. When electricity is passed through them the electrolytes dissociates into ions and these ions conduct electricity.
Answer:
pure water. plz vote brainliest
Explanation:
A nonuniform, but spherically symmetric, distribution of charge has a charge density ρ(r) given as follows:
ρ(r)=ρ0(1−r/R) for r≤R
ρ(r)=0 for r≥R
where ρ0=3Q/πR3 is a positive constant.
Express your answer in terms of some or all of the variables r, R, Q, and appropriate constants.
Obtain an expression for the electric field in the region r≥R.
Obtain an expression for the electric field in the region r≤R.
Find the value of r at which the electric field is maximum.
Find the value of that maximum field.
Answer:
r ≥ R, E = Q / (4πR²ε₀)
r ≤ R, E = 12Q (⅓ (r/R)³ − ¼ (r/R)⁴) / (4πr²ε₀)
Maximum at r = ⅔ R
Maximum field of E = Q / (3πε₀R²)
Explanation:
Gauss's law states:
∮E·dA = Q/ε₀
What that means is, if you have electric field vectors E passing through areas dA, the sum of those E vector components perpendicular to the dA areas is equal to the total charge Q divided by the permittivity of space, ε₀.
a) r ≥ R
Here, we're looking at the charge contained by the entire sphere. The surface area of the sphere is 4πR², and the charge it contains is Q. Therefore:
E(4πR²) = Q/ε₀
E = Q / (4πR²ε₀)
b) r ≤ R
This time, we're looking at the charge contained by part of the sphere.
Imagine the sphere is actually an infinite number of shells, like Russian nesting dolls. For any shell of radius r, the charge it contains is:
dq = ρ dV
dq = ρ (4πr²) dr
The total charge contained by the shells from 0 to r is:
q = ∫ dq
q = ∫₀ʳ ρ (4πr²) dr
q = ∫₀ʳ ρ₀ (1 − r/R) (4πr²) dr
q = 4πρ₀ ∫₀ʳ (1 − r/R) (r²) dr
q = 4πρ₀ ∫₀ʳ (r² − r³/R) dr
q = 4πρ₀ (⅓ r³ − ¼ r⁴/R) |₀ʳ
q = 4πρ₀ (⅓ r³ − ¼ r⁴/R)
Since ρ₀ = 3Q/(πR³):
q = 4π (3Q/(πR³)) (⅓ r³ − ¼ r⁴/R)
q = 12Q (⅓ (r/R)³ − ¼ (r/R)⁴)
Therefore:
E(4πr²) = 12Q (⅓ (r/R)³ − ¼ (r/R)⁴) / ε₀
E = 12Q (⅓ (r/R)³ − ¼ (r/R)⁴) / (4πr²ε₀)
When E is a maximum, dE/dr is 0.
First, simplify E:
E = 12Q (⅓ (r/R)³ − ¼ (r/R)⁴) / (4πr²ε₀)
E = Q (4 (r³/R³) − 3 (r⁴/R⁴)) / (4πr²ε₀)
E = Q (4 (r/R³) − 3 (r²/R⁴)) / (4πε₀)
Take derivative and set to 0:
dE/dr = Q (4/R³ − 6r/R⁴) / (4πε₀)
0 = Q (4/R³ − 6r/R⁴) / (4πε₀)
0 = 4/R³ − 6r/R⁴
0 = 4R − 6r
r = ⅔R
Evaluating E at r = ⅔R:
E = Q (4 (⅔R / R³) − 3 (⁴/₉R² / R⁴)) / (4πε₀)
E = Q (8 / (3R²) − 4 / (3R²)) / (4πε₀)
E = Q (4 / (3R²)) / (4πε₀)
E = Q (1 / (3R²)) / (πε₀)
E = Q / (3πε₀R²)
For question 1:
For the region [tex]r \geq R[/tex], an expression for the electric field can be calculated by using the Gauss law:
Use gauss law of electrostatics, the charge electric flux through the Gaussian surface is,
[tex]\int \vec{E} \cdot d\vec{A}=\frac{q_{enc}}{\varepsilon_{0} }\\\\E(4\pi r^2)=\frac{Q}{\varepsilon_0}\ \ \ \ \ \ \ \ \ \ \ \ \ (Since\ \ q_{enc}=Q )[/tex]
Here, Q is the enclosed charge and [tex]\varepsilon_0[/tex] , is the permeability.
[tex]E=\frac{1}{4\pi \varepsilon_0 } \frac{Q}{r^2}[/tex]
Therefore, the required electric field is [tex]\frac{Q}{4\pi\varepsilon_0 r^2 }[/tex]
For question 2:
For Gaussian sphere of radius [tex]r \leq R[/tex], the charge enclosed within a spherical shell is,
[tex]dq =\rho_0(1-\frac{r}{R}) 4\pi r^2 dr[/tex]
Hence, the total charge enclosed with in the radius r is as follows,
[tex]q_{enc}=\int^{r}_{0} \rho_{0} (1-\frac{r}{R}) 4\pi r^2 \ dr\\\\[/tex]
[tex]=4\pi \rho_0 |\frac{r^3}{3}-\frac{r^4}{4R}|^4_{0}\\\\=\frac{12 Q}{R^3}(\frac{r^3}{3}-\frac{r^3}{4R})\\\\=\frac{Qr^3}{R^3}(4-\frac{3r}{R})\\\\[/tex]
Use Gauss's law for the Gaussian sphere of radius r,
[tex]\int \vec{E}\cdot dA=\frac{q_{enc}}{\varepsilon_0}\\\\E(4\pi r^2)=\frac{Qr^3}{\varepsilon_0 R^3}(4-\frac{3r}{R})\\\\E=\frac{Qr}{4\pi \varepsilon_0 R^3}(4-\frac{3r}{R})\\\\[/tex]
Therefore, the required electric field at [tex]r\leq R[/tex] is [tex]\frac{Qr}{4\pi \varepsilon_0 R^3}(4-\frac{3r}{R})\\\\[/tex]
For question 3:
The change in electric filed with respect to distance is zero when the electric field has a maximum value.
[tex]\frac{dE}{dr}= 0\\\\\frac{d(\frac{Qr}{4\pi \varepsilon_0 R^3}(4-\frac{3r}{R}))}{dr}=0\\\\(\frac{Q}{4\pi \varepsilon_0 R^3})\frac{d(4r-\frac{3r^2}{R})}{dr}=0\\\\[/tex]
Here, [tex](\frac{Q}{4\pi \varepsilon_0 R^3})[/tex] is not equal to zero. Hence,
[tex]\frac{d(4r-\frac{3r^2}{R})}{dr}=0\\\\4-\frac{6r}{R}=0\\\\r=\frac{4R}{6}=\frac{2R}{3}[/tex]
Therefore, the required value of [tex]r \ \ is\ \ \frac{2R}{3}\\\\[/tex]
For question 4:
Maximum value of the electric filed is as follows
[tex]E= \frac{Q}{4\pi \varepsilon_0 R^3} (4-\frac{3r}{R})\\\\[/tex]
[tex]= \frac{Q(\frac{2R}{3})}{4\pi \varepsilon_0 R^3} (4- \frac{3(\frac{2R}{3})}{R})\\\\=\frac{Q}{3 \pi \varepsilon_0 R^2}[/tex]
Therefore, the required maximum value of the electric field is [tex]\frac{Q}{3 \pi \varepsilon_0 R^2}[/tex]
Learn more:
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A sailor pulls a 2,000 kilogram boat 25 meters along the dock with a rope attached to the boat that makes a 45 degree angle with the dock. How much work is done by the sailor if he exerts a force of 400 newtons while pulling the boat?
Answer: 7071.067 Joules
Explanation:
The Work [tex]W[/tex] done by a Force [tex]F[/tex] refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path [tex]d[/tex].
It should be noted that it is a scalar, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:
[tex]1J=(1N)(1m)=Nm[/tex]
Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
[tex]W=(F)(d)[/tex] (1)
When they are not parallel, both directions form an angle, let's call it [tex]\alpha[/tex]. In that case the expression to calculate the Work is:
[tex]W=Fdcos{\alpha}[/tex] (2)
In this case the force and the distance in the path form an angle [tex]\alpha=45\°[/tex], so we will use the second equation, where [tex]F=400N[/tex] and [tex]d=25 m[/tex]:
[tex]W=(400 N)(25 m) cos(45\°)[/tex] (3)
Then:
[tex]W=7071.067 Nm=7071.067 J[/tex]
The work done by the sailor to pull the boat 25 meters with a force of 400 newtons at a 45-degree angle to the dock is approximately 7,071 Joules.
The amount of work done by the sailor on the boat can be calculated by using the formula for work done by a force at an angle, which is W = F imes d imes ext{cos}( heta). In this case, the force (F) is 400 newtons, the distance (d) is 25 meters, and the angle ( heta) is 45 degrees.
First, we calculate the cosine of the angle, which in this case is ext{cos}(45^{ ext{o}}) = rac{ ext{ extsqrt{2}}}{2}.
Then, we multiply the force, distance, and cosine of the angle: W = 400 N imes 25 m imes rac{ ext{ extsqrt{2}}}{2}.
Therefore, the work done by the sailor is 400 imes 25 imes rac{ ext{ extsqrt{2}}}{2}, which equals 7,071 Joules approximately.
A bulldozer does 4,500 J of work to push a mound of soil to the top of a ramp that is 15 m high. The ramp is at an
angle of 35° to the ground. How much force did the bulldozer apply to the mound of soil? Round your answer to two
significant figures.
Its 520 N
Answer:
520 N
Explanation:
Work is the dot product of the force vector and displacement vector.
W = F · x
This means it is the product of the magnitudes of the vectors and the cosine of the angle between them.
W = F x cos θ
The displacement of the soil is 15 m up. The force is parallel to the ramp. So the angle between the vectors is 90° − 35° = 55°.
Plugging in the values and solving for F:
4500 J = F (15 m) (cos 55°)
F = 523 N
Rounded to two significant figures, the force is 520 N.
On a 100m straight track, Zak runs to the 80m mark in 15s. He then runs back to the 20m in 10s. He then runs to the 100m mark in 20s. Finally he runs to the 70m mark in 5s. The total distance travelled by Zak is ____ m and total displacement is ____ m.
Answer:
The total distance traveled by Zak is 250 m and total displacement is
70 m
Explanation:
Distance is a scalar quantity that represents how much ground an
object has covered during its motion
Displacement is a vector quantity that represents how far out of place
an object is, means the change in its position
Displacement = final position - initial position
The straight track is 100 m
Zak runs to the 80 m mark
That means he runs forward from zero to 80
Then his distance = 80 m
His displacement = + 80 m
He then runs back to the 20 m
That means that he runs back from 80 m to 20 m
Then his distance = 80 - 20 = 60 m
His displacement = 20 - 80 = -60 m
He then runs to the 100 m mark
That means he runs forward from 20 m to 100 m
Then his distance = 100 - 20 = 80 m
His displacement = 100 - 20 = + 80 m
Finally he runs to the 70 m mark
That means he runs back from 100 m to 70 m
Then his distance = 100 - 70 = 30 m
His displacement = 70 - 100 = - 30 m
His total distance is the sum of all distances he runs
The total distance = 80 + 60 + 80 + 30 = 250 m
His total displacements is the sum of all displacements he runs
The total displacement = (+80) + (-60) + (+80) + (-30) = + 70 m
The total distance traveled by Zak is 250 m and total displacement is
70 m
the kind of graph that would best show the
results of a survey of 144 people where 75 ride a bus, 45 drive cars,
15 carpool, and 9 walk to work.
Answer:
a bar graph would be the kind of graph that you should use for this problem because it would be easier to read and also do
Explanation
A Pie Chart is the best type of graph to represent the results of this survey, as it visually expresses each commuting mode as a portion of the total survey responses.
Explanation:The type of graph that would present this data most clearly is a Pie Chart. The Pie Chart would provide a visual representation of each commuting method as a proportion of the total survey responses. For instance, the section corresponding to bus riders would be rather large, as 75 out of 144 individuals, or approximately 52% of the participants, use the bus. In contrast, the segment for individuals who walk would be smaller, as 9 out of 144 or about 6% of respondents walk to work. As such, a Pie Chart offers a visual distribution of responses, making it easy to compare different categories.
Learn more about Pie Chart here:https://brainly.com/question/11433309
When the volleyball is below your shoulders you need to?
Answer:
You need to Bump the volleyball
hope it helps :)
4.) An apartment building is on fire and a guy is trapped on the fire escape ladder. There is a
dumpster that is 6.3m away and is filled full of trash, and he is 7m above it. If he jumps totally
in the horizontal direction, how fast does he have to jump in order to land in the dumpster?
Answer:
5.3 m/s
Explanation:
First, find the time it takes for him to fall 7m.
y = y₀ + v₀ t + ½ at²
0 = 7 + (0) t + ½ (-9.8) t²
0 = 7 − 4.9 t²
t ≈ 1.20 s
Now find the velocity he needs to travel 6.3m in that time.
x = x₀ + v₀ t + ½ at²
6.3 = 0 + v₀ (1.20) + ½ (0) (1.20)²
v₀ ≈ 5.27 m/s
Rounded to two significant figures, the man must run with a speed of 5.3 m/s.
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm/s at top of rise). Remember, acceleration is -9.80 m/s2.
d = _____ m
1.02
2.04
20.4
40.8
Answer:
20.4
Explanation:
Given:
y₀ = 0 m
v₀ = 20.0 m/s
v = 0 m/s
a = -9.80 m/s²
Find: y
v² = v₀² + 2a (y − y₀)
(0 m/s)² = (20.0 m/s)² + 2 (-9.80 m/s²) (y − 0 m)
y = 20.4 m
significant digits show the _____ of measurements and calculations.
1) accuracy
2) precision
The number of neutrons is equal to the atomic number
O A True
B. False
Answer:false
Explanation:
The total number of the neutrons in a atom is the difference of mass number of the atom and its atomic number.
The number of neutrons is not equal to the atomic number. Thus the given statement is false.
What is atom?Atom is the smallest unit of the matter consist the positive charged nucleus and the electrons which moves around it. The atom can not be divided further.
The atom of a matter is made by three elements-
1) Neutron-Neutron is the element of atom, which has zero charge.2) Proton-Proton is the element of atom, which has positive charge.3) Electron-Electron is the element of atom, which has negative charge.The relation between the atomic number and neutrons-
The total number of the neutrons in a atom is the difference of mass number of the atom and its atomic number.
Thus total number of the neutrons in a atom is,
[tex]N=M-n[/tex]
Here, [tex]M[/tex] is the mass number of the atom and [tex]n[/tex] is the atomic number of it.
Thus, the number of neutrons is not equal to the atomic number. Thus the given statement is false.
Learn more about the atomic number here;
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With which part of the brain is awareness typically associated?
Answer:cerebral cortex
Explanation:
Answer:
Cerebral Cortex
Explanation:
The cerebral cortex has a left and a right hemisphere. Each hemisphere can be divided into four lobes: the frontal lobe, temporal lobe, occipital lobe, and parietal lobe. The lobes are functional segments. They specialize in various areas of thought and memory, of planning and decision making, and of speech and sense perception.
A human hair is approximately 56 µm in diameter.
Express this diameter in meters.
Answer in units of m
Answer:
The diameter is 0.000056 m
Explanation:
Lets explain the relation between the meter and the micrometer
1 Meter is equal to 1000000 (one million) micrometers
1 micrometer = [tex]\frac{1}{1000000}=\frac{1}{10^{6}}=10^{-6}[/tex]
The symbol of the meter is m
The symbol of micrometer is μm
A human hair is approximately 56 µm in diameter
We need to express this diameter in meter
To do that we divide this number by 1,000,000 or multiply it by [tex]10^{-6}[/tex]
→ [tex]\frac{56}{1000000}=0.000056[/tex] 56 µm = 0.000056 m
→ OR
→ [tex]56*10^{-6}=0.000056[/tex]
→ 56 µm = 0.000056 m
The diameter is 0.000056 m
A 50 newton force is required to push a 10 kg box 30 meters across the floor. The box is then lifted up 6 meters and placed on a shelf. How much total work was done?
Answer:
2088 J
Explanation:
Work = net force × distance
When the box is being pushed across the floor, the force is 50 N, and the distance is 30 m.
W = (50 N) (30 m)
W = 1500 J
When the box is being lifted, the force is the weight of the box (10 kg × 9.8 m/s²), and the distance is 6 m.
W = (98 N) (6 m)
W = 588 J
So the total work done is:
W = 1500 J + 588 J
W = 2088 J
A force of 15 newtons is applied to both Object A with a mass of 25 kilograms and Object B with a mass of 50 kilograms. What is true about the
acceleration of Object A and Object B?
Answer:
Acceleration of Object A = 0.6 m/s²
Acceleration of Object B = 0.3 m/s²
Acceleration of Object A is double than the acceleration of Object B.
Explanation:
According to the Newton's 2nd law of motion, Acceleration of an object by a net force is directly proportional to the magnitude of that net force and in the direction of that net force and inversely proportional to the mass of the object
Mathematically
F ∝ a
F = ma
Given data:
F = 15 N
m₁ = 25 kg
m₂ = 50 kg
F = m₁a₁
a₁ = F/m₁
a₁ = 15/25
a₁ = 0.6 m/s²
F = m₂a₂
a₂ = F/m₂
a₂ = 15/50
a₂ = 0.3 m/s²
It can be seen that acceleration of Object A is double than the acceleration of Object B.
At summer camp, the swimming course runs the length (L) of a small lake. To determine the length of the course, the camp counselors measure the two "dry" legs of a right triangle. What is the length in meters of the swimming course in the figure below? A right triangle overlaps a lake. It has sides 25 and 40 meters. Hypotenuse labeled L goes through the lake.
Answer:
The length of the swimming course is 47.16 meters.
Explanation:
It is given that the right triangle overlaps the lake and hypotenuse L runs through the length of the lake. Thus length of the lake will be the length of this hypotenuse.
The instructors have conducted measurements of the right triangle and has found the legs to be 25 and 40 meters. The sum of squares of base and height of a right triangle gives the value of its hypotenuse according to Pythagoras theorem.
Thus [tex]h^2+b^2=H^2[/tex]
b - base
h - height.
[tex]40^2+25^2=1600+625=2225[/tex]
[tex]H=\sqrt{2225}=47.16 m[/tex]
How does the scattering of tiny particles in the air affect the colors of the sky at sunrise and sunset
It affects the colors of the sky at sunrise and sunset because only the longer-wavelengths colors are visible.
At the end of the 4th half-life, how much of a material will have decayed?
93.75% of a material decays at the end of [tex]4^{th}[/tex] half-life.
Explanation:
The time needed by a material to reduce its initial amount into half is called half-life. It is generally used term in nuclear physics. This is to explain how fast unstable atom undergoes, or how long can stable atoms present, and radioactive decay.
Decay % of material after each half-life to be calculated as follows,
After one half-life- 50% original, and 50% product decayed.
After two half-life- 25% original, and 75% product decayed.
After three half-lives- 12.5% of original, and 87.5% of decay product.
After four half-lives- 6.25% original, and 93.75% of decay product.
Answer:
15/16
Explanation:
What will happen to an object at rest if no unbalanced forces act on it,
according to Newton's First Law?
Explanation:
Newton's first law says that an object at rest stays at rest, and an object in motion stays in motion, until acted upon by an unbalanced force.
If there's no unbalanced force, then an object at rest will stay at rest.
A box is being pulled to the right. What is the direction of the gravitational force?
up
down
Oright
left
Answer:
The correct answer would be downwards
Hope this helps have a good day
Final answer:
The gravitational force on a box being pulled to the right is downward towards the Earth's center.
Explanation:
The direction of the gravitational force on a box being pulled to the right is downward towards the Earth's center. This is because gravitational force is a vector that points downwards, regardless of any horizontal movement or force applied to an object. The gravitational force can be calculated using the equation F = mg, where F is the gravitational force, m is the mass of the object, and g is the acceleration due to gravity, which is approximately 9.81 m/s² near the Earth's surface. Therefore, even when the box moves to the right, the gravitational force only acts downward.
A car is traveling at 10m/s before it increases its speed to 30m/s for 120m. How long does it take to do this ?
Answer:
60 seconds
Explanation:
Given:
v₀ = 10 m/s
v = 30 m/s
Δx = 120 m
Find: t
Δx = ½ (v + v₀)t
120 = ½ (30 + 10) t
t = 60
It takes 60 seconds.
Hey:) what is a monatomic molecule?
Answer:
"mono" and "atomic" means single atom this term is used in both physics and chemistry and it applied to the gasses as a monatomic gas
Answer and Explanation:
Good Day mate!
A monatomic molecule is that some of the elements do not have a tendency to form a molecule. Which means, the molecule of an element is made up of only one atom. Thus, there are called as Monatomic molecule.
Some common examples of monatomic molecules :
1. Helium (He)
2. Neon (Ne)
3. Argon (Ar)
4. Xenon (Xe)