What is 4 1/3 times 18

The histogram that represents the data will be given below.

0-4, with a frequency of 6

5-9, with a frequency of 4

10-14, with a frequency of 3

15-19, with a frequency of 2

One of its most used graphs for displaying frequency tables is the histogram. The ordinal scale, as we all know, describes how frequently each individual value appears in the data collection.

The data below show the number of games won by a football team in each of the last 15 seasons.

3, 4, 8, 12, 7, 2, 1, 15, 16, 6, 10, 13, 4, 1, 5.

Arrange in ascending order. we have

1, 1, 2, 3, 4, 4, 5, 6, 7, 8, 10, 12, 13, 15, 16.

Then we have

Using intervals of width 5, we have

0-4, with a frequency of 6

5-9, with a frequency of 4

10-14, with a frequency of 3

15-19, with a frequency of 2

More about the histogram representation of the data link is given below.

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Answer:

the x value equals 6.

Step-by-step explanation:

When you are solving for x, divide the 42 by 7.

The weight of the RV in tonnes is approximately 2.26796 tonnes.

The weight of the RV can be converted from tons to tonnes using a conversion factor. One ton is equal to 0.90718474 tonnes. To find the weight of the RV in tonnes, we can multiply 2.5 tons by the conversion factor:

Weight in tonnes = 2.5 tons x 0.90718474 tonnes/ton = 2.26796 tonnes

Therefore, the weight of the RV in tonnes is approximately 2.26796 tonnes.

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Final answer:

The height of the ball after 1.4 seconds, using the function h(t) = 150 – 9t, is 137.4 feet above the ground.

Explanation:

To determine the height of the ball after 1.4 seconds using the function h(t) = 150 – 9t, we simply need to substitute the value of t with 1.4 seconds into the equation.

By plugging in the given values in the equation, the solution we get will be:

h(1.4) = 150 – 9(1.4) = 150 - 12.6 = 137.4 feet

Therefore, the height of the ball after 1.4 seconds will be 137.4 feet above the ground.

The first step in solving this problem is to compute for the original rate of Aphrodite.

144 leagues / 12 days = 12 leagues/day (original rate)

It was stated in the problem that she doubled her rate which she means she has a new rate of 24 leagues/day (12 x 2).

168 leagues / 24 leagues/day = 7

Therefore, it would take her 7 days to travel 168 leagues at her new speed.

Step 1    

Find the value of TS

we know that

if PQ is parallel to RS. then triangles TRS and TPQ are similar

so

[tex]\frac{TR}{TP} =\frac{TS}{QT}[/tex]

solve for TS

[tex]TS =\frac{TR*QT}{TP}[/tex]

we have

[tex]RP=2\ cm\\TP=18\ cm\\QT=27\ cm[/tex]

[tex]TR=TP+RP\\TR=18+2=20\ cm[/tex]

substitute

[tex]TS =\frac{20*27}{18}[/tex]  

[tex]TS =30\ cm[/tex]

Step 2

Find the value of SQ

we know that

[tex]SQ=TS-QT[/tex]

we have

[tex]TS =30\ cm[/tex]

[tex]QT=27\ cm[/tex]

substitute

[tex]SQ=30\ cm-27\ cm=3\ cm[/tex]

therefore

the answer is

the value of SQ is [tex]3\ cm[/tex]

Answer: C. 3cm

Step-by-step explanation:

Answer:

2nd Option is correct.

Step-by-step explanation:

We are given a set of cards containing numbers from 1 to 8 on each cards.

Randomly a card is drawn and noted.

This is repeated 1000 times.

To find: Number of time 4 will be drawn from the pack using theoretical probability.

We know that,

Theoretical Probability: Probability which is based on reasoning  and written as a ratio of the number of favorable outcomes to the total number of outcomes.

Probability of getting 4 from the pack = [tex]\frac{1}{8}[/tex]

Now, Number of the times 4 will be drawn from pack out of 1000 times

= [tex]\frac{1}{4}\times1000[/tex]

= 125

Therefore, 2nd Option is correct.

Rock layers that formed more recently contain fossils that resemble existing species more closely than do fossils found in older rock layers.

Fossils found in rock layers provide evidence for Earth's long history of changing lifeforms. Rock layers that formed more recently contain fossils that resemble existing species more closely than do fossils found in older rock layers. This is because the more recent layers contain organisms that are more similar to the species that exist today.

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Final answer:

The library may not be adding more fairy tales due to decreased demand, a desire to offer a diverse collection, and a strategic choice to provide a balanced collection.

Explanation:

It is possible that the library is not adding any more fairy tales due to a variety of reasons. One reason could be that the demand for fairy tales has decreased among library patrons. Another reason could be that the library wants to diversify its collection and offer a wider range of books to its readers.

Additionally, the library may be focusing on acquiring books from different genres or themes to cater to the interests of its diverse audience.

It is important to note that libraries regularly make decisions about which books to add to their collection based on factors such as popularity, relevance, and availability. The decision to not add any more fairy tales could simply be a strategic choice made by the library to provide a more balanced and comprehensive collection for its readers.

1. For T (-1,2),(7,8): 10

For E (3,-4), (-2,5): 10.3

For  A (-7,0), (-4,12): 12.4

For N (1,-5), (-9,-9): 10.8

2. For S (2,6), (3,10): (2.5, 8)

For F (15,-1),(9,-5): (12, -3)

For T (7,-2), (-10,-8): (-1.5, -5)

For E (-3,0), (-11,9): (-7, 4.5)

Here are the distances and midpoints, calculated step by step:

Distances:

T: (-1, 2), (7, 8)

Difference in x-coordinates: 7 - (-1) = 8

Difference in y-coordinates: 8 - 2 = 6

Distance using the Pythagorean theorem: √(8² + 6²) = √100 = 10

E: (3, -4), (-2, 5)

Difference in x-coordinates: -2 - 3 = -5

Difference in y-coordinates: 5 - (-4) = 9

Distance: √((-5)² + 9²) = √106 ≈ 10.3

A: (-7, 0), (-4, 12)

Difference in x-coordinates: -4 - (-7) = 3

Difference in y-coordinates: 12 - 0 = 12

Distance: √(3² + 12²) = √153 ≈ 12.4

N: (1, -5), (-9, -9)

Difference in x-coordinates: -9 - 1 = -10

Difference in y-coordinates: -9 - (-5) = -4

Distance: √((-10)² + (-4)²) = √116 ≈ 10.8

Midpoints:

S: (2, 6), (3, 10)

Midpoint: ((2 + 3)/2, (6 + 10)/2) = (2.5, 8)

F: (15, -1), (9, -5)

Midpoint: ((15 + 9)/2, (-1 - 5)/2) = (12, -3)

T: (7, -2), (-10, -8)

Midpoint: ((7 - 10)/2, (-2 - 8)/2) = (-1.5, -5)

E: (-3, 0), (-11, 9)

Midpoint: ((-3 - 11)/2, (0 + 9)/2) = (-7, 4.5)

Complete question:

Write the exercise letter in the box above the answer at the bottom of the page. Find the distance between the two given points. If necessary, round to the nearest tenth.

T (-1,2),(7,8)

E (3,-4), (-2,5)

A (-7,0), (-4,12)

N (1,-5), (-9,-9)

Find the midpoint between the two given points.

S (2,6), (3,10)

F (15,-1),(9,-5)

T (7,-2), (-10,-8)

E (-3,0), (-11,9)