kevin said that if you triple his age, the result will be 1 less than his mother's age
Which expressions describe the area of the shaded region? Select all that apply. A rectangle is divided into 12 columns and 6 rows, making 72 smaller rectangles. An area that includes 9 smaller rectangles and is the intersection of 3 of the 12 columns and 3 of the 6 rows is shaded. A. 3 12 × 3 6 312×36 B. 3 10 × 1 2 310×12 C. 1 4 × 1 2 14×12 D. 1 4 × 1 3 14×13 E. 4 12 × 3 6 412×36
The expressions describing the area of the shaded region is 1/2 × 1/4
What is an expression?Expressions in math are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.
Given that, a rectangle is divided into 12 columns and 6 rows, making 72 smaller rectangles.
We need to find the expressions for the area of the shaded region,
So, we have,
The height is 6 and the length is 12
The shaded part is 3 boxes by 3 boxes
Therefore, we can write =
3/6 × 3/12 = 1/2 × 1/4
Hence, the expressions describing the area of the shaded region is 1/2 × 1/4
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3 full and distinct reasons for 100%.
WYR
See teachers armed with guns in the classroom.
OR
See things like bullet-proof vests and other safety measures in the classroom.
OPEN
(3 reasons for full credit)
Giving 99 pionts!
Answer:
i will say bullet proof vest there are my reason
1. your teacher is suppose to keep you safe
2.bullet proof vest would keep you safe from gun shootings
3. school guards should check everyone's pockets before interning the school building
i hope this helps you -pandamathhelper
A researcher measured the heights of forty high-school students. The measurements are recorded here.
Heights (in inches)
58 59 60 60 60 61 61 61 61 62
62 62 62 62 62 63 63 63 64 65
67 67 68 68 68 68 69 69 70 70
70 71 71 71 71 71 72 73 74 76
If Alyssa's height is in the 45th percentile within the group, what is her height in inches?
Answer:
64
Step-by-step explanation:
i just know
What is the greatest common factor of 4k , 18k4, and 12
Answer:
2
Step-by-step explanation:
The greatest common factor of whole numbers is the largest number that is a factor of all numbers. That is, it is the largest number that can divide all numbers.
In this case, the largest number that divide all the numbers is 2, who can divide 4, 18 and 12.
So:
[tex](4k, 18k^{4} ,12)= 2(2k,9k^{4} , 6)[/tex]
Minnie and Tori combined ate nine pieces of the wedding cake Mindy ate 3 pieces of the wedding cake Tori have one fourth of the total kick write an expression to determine how many pieces of cake C there was in total
Wilt and bill, two basketball players, are having a free throw shooting contest. wilt is known to make 75% of his free throws, and bill is known to hit 85% of his free throws. each of them takes 50 shots. assuming that the shots are independent, what is the probability that bill hits a higher percentage of his shots than wilt?
The probability Bill hits a higher percentage than Wilt in free throws is approximately 0.0085, or 0.85%.
To find the probability that Bill hits a higher percentage of his shots than Wilt, we can use the concept of binomial distributions.
Step 1 :Let's denote:
- [tex]\( W \)[/tex] as the number of successful shots Wilt makes out of 50,
- [tex]\( B \)[/tex] as the number of successful shots Bill makes out of 50.
Since Wilt makes 75% of his free throws and Bill makes 85% of his free throws, we can calculate the expected number of successful shots for each:
- For Wilt: [tex]\( E(W) = 50 \times 0.75 = 37.5 \)[/tex]
- For Bill: [tex]\( E(B) = 50 \times 0.85 = 42.5 \)[/tex]
Now, we can use the normal approximation to the binomial distribution to calculate the probability that Bill hits a higher percentage of his shots than Wilt. We'll assume that both distributions are approximately normal due to the central limit theorem.
The standard deviation for each player's distribution can be calculated as:
- For Wilt: [tex]\( \sigma_W = \sqrt{n \times p_W \times (1-p_W)} = \sqrt{50 \times 0.75 \times 0.25} \)[/tex]
- For Bill: [tex]\( \sigma_B = \sqrt{n \times p_B \times (1-p_B)} = \sqrt{50 \times 0.85 \times 0.15} \)[/tex]
Step 2 :Now, we can calculate the probability using a normal distribution:
[tex]\[ P(B > W) = P\left(Z > \frac{{E(B) - E(W)}}{{\sqrt{\sigma_B^2 + \sigma_W^2}}}\right) \][/tex]
Where [tex]\( Z \)[/tex] is a standard normal random variable.
Calculating:
[tex]\[ P(B > W) = P\left(Z > \frac{{42.5 - 37.5}}{{\sqrt{50 \times 0.85 \times 0.15 + 50 \times 0.75 \times 0.25}}}\right) \][/tex]
[tex]\[ P(B > W) = P(Z > 2.3717) \][/tex]
Using a standard normal distribution table or calculator, we find that [tex]P(Z > 2.3717) \approx 0.0085 \).[/tex]
So, the probability that Bill hits a higher percentage of his shots than Wilt is approximately 0.0085, or 0.85%.
A class had 30 pupils at the beginning of this school term, but now has 5 more pupils. What is the percent of increase?
Which statements are true about the regular polygon? Check all that apply. The sum of the measures of the interior angles is 900°. Each interior angle measures 108°. All of the angles are congruent. The polygon is a regular hexagon. The sum of the measures of the interior angles is 180(5 – 2)°.
Answer: 2,3,5
Step-by-step explanation:
Consider the function f(x) = x2 + 12x + 11. x-intercepts: 0 = x2 + 12x + 11 0 = (x + 1)(x+ 11) y-intercept: f(0) = (0)2 + 12(0) + 11 What are the intercepts of the function? The x-intercepts are . The y-intercept is .
Answer:
the x-intercepts are (-1,0) and (-11,0), the y-intercept is (0,11).
A winter sport passed at Wood Middle school costs $15. A stydent without a pass must pay $1.75 for each event. How many events would a student have to attend to pass a better deal?
Answer:
9
Step-by-step explanation:
15 divided by 1.75 equals 9.
And in order to double check, we multiply 9 and 1.75 together which equals 15.75.
Find the supplementary angle of 116 degrees.
Part A: Solve -np 70 < 40 for n. Show your work. (4 points)
Part B: Solve 4w -7k 28 for k. Show your work. (6 points)
A ___________ is a line segment that connects the center of a circle to a point on that circle.
A) radius
B) chord
C) diameter
D) obtuse angle
How do you write the equation of Mary has 10 roses John has 2 less
Use the drop-down menus to choose steps in order to correctly solve
5m – 8 = 3m + 8 for m.
Answer:
m=8
Step-by-step explanation:
on imagine 2021
Find the sum of the arithmetic sequence. 5, 7, 9, 11, ..., 23
The answer is 140, you just add them up and it goes by 2.
the ratio of pens to pencils in Carlos case 4:5 he has 16 pens how many pencils do Carlos have
Click on the graph to choose the best match of the graphed quadratic equation. F(x) = x 2 + 4x
The required graph of the quadratic function is the parabola shown in the attachment.
Given that,
To determine the graph to the best match of the graphed quadratic equation. F(x) = x² + 4x.
A parabola is a cross-section cut out of the cone and represented by an equation.
What is a graph?
The graph is a demonstration of curves that gives the relationship between the x and y-axis.
Here,
The given equation represents the parabola with vertex at (-2, - 5).
and a graph of the parabola is attached below.
Thus, the required graph of the quadratic function is the parabola shown in the attachment.
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The circumference of a circle is 60π cm. What is the length of an arc of 140°? 11.7π cm 16.1π cm 23.3π cm 29.5π cm
Answer:
c = 23.3
Step-by-step explanation:
Answer:
[tex]23.3 \pi[/tex] cm
Step-by-step explanation:
Circumference of circle = [tex]2 \pi r[/tex]
The circumference of a circle is 60π cm.
So, [tex]2 \pi r=60 \pi[/tex]
[tex]2r=60[/tex]
[tex]r=30[/tex]
Formula of length of arc = [tex]2 \pi r \times \frac{\theta}{360}[/tex]
Length of arc = [tex]2 \pi \times 30 \times \frac{140}{360}[/tex]
Length of arc = [tex]23.3 \pi[/tex]
So, Option C is true
Hence Length of arc is [tex]23.3 \pi[/tex] cm
Assume that the probability of error-free transmission of a message over a communication channel is . if a message is not transmitted correctly, a retransmission is initiated. this procedure is repeated until a correct transmission occurs. such a channel is often called a feedback channel. assume that successive transmissions are independent.
a. what is the probability that no retransmissions are required? (note that the number of retransmissions is the number of transmissions minus one.)
Answer:
Let the probability of error-free transmission of a message over a communication channel is P.
Then the Probability of Retransmission is =1-P
Now the question is Probability when no retransmission is required
= Probability of error free transmission in first attempt
=P
Now , suppose after first failure error free transmission takes place.
Since events are independent.
∵P[error free transmission after a failure ]= P[1-P]
If after two attempts error free transmission takes place
then P[ error free transmission after two failures]= P [1-P]²
So, For after n failures
P[error free transmission after n failure]=P[tex][1-p]^n[/tex]
Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8. Simplify [Q - R] + [S - T].
Answer: [tex][Q - R] + [S - T]=10m+7n-14[/tex]
Step-by-step explanation:
Given : [tex]Q = 7m + 3n[/tex],
[tex]R = 11 -2m[/tex],
[tex]S = n + 5[/tex], and
[tex]T = -m - 3n + 8[/tex]
Now , [tex]Q-R= 7m + 3n-(11 - 2m)[/tex]
[tex]Q-R= 7m +3n-11+2m[/tex] [ ∵ (-)(+)=(-) and (-)(-)=(+)]
[Note : when -1 is outside the parenthesis it indicates that -1 should be multiplied with each of the terms present inside the parenthesis .]
[tex]Q-R= 9m +3n-11[/tex] [Combine like terms.]
[tex]S-T=n + 5-(-m - 3n + 8)[/tex]
[tex]S-T=n + 5+m+3n-8[/tex] [ ∵ (-)(+)=(-) and (-)(-)=(+)]
[tex]S-T=4n +m-3[/tex] [Combine like terms.]
Now, [tex][Q - R] + [S - T]=[9m +3n-11]+[4n +m-3][/tex]
[tex]=9m +3n-11+4n+m-3[/tex]
[tex]=10m+7n-14[/tex] [combine like terms]
Hence, [tex][Q - R] + [S - T]=10m+7n-14[/tex]
Sales of tablet computers at ted glickman's electronics store in washington,
d.c., over the past 10 weeks are shown in the table below: week 1 2 3 4 5 6 7 8 9 10 demand 19 23 28 38 25 29 37 20 26 30 a) the forecast for weeks 2 through 10 using exponential smoothing with alpha = 0.60 and a week 1 initial forecast of 19.0 are (round your responses to two decimal places):
Some species of hummingbirds appear to hover in mid-air by flapping their tiny wings 80 times per second. How many times per minute do hummingbirds flap their wings?
Final answer:
To calculate the number of times a hummingbird flaps its wings per minute, you multiply the number of flaps per second by 60. In this case, hummingbirds flap their wings approximately 4800 times per minute.
Explanation:
To calculate how many times a hummingbird flaps its wings per minute, you can start by determining how many times it flaps its wings per second. Given that some species of hummingbirds flap their wings 80 times per second, you can simply multiply this by 60 to find the number of times per minute:
80 flaps/second x 60 seconds/minute = 4800 flaps/minute
Therefore, hummingbirds flap their wings approximately 4800 times per minute.
What percent is 6 out of 7?
What is the value of x in the diagram below?
A 30
B 60
C 90
D 120
could you please explain how you get the answer thank you so much.
jimmy had 8 boxes with 3 cars in each box. if jimmy wanted to give each of his 4 friends an equal number of cars, how many cars would each friend get?
The current population of a city can be represented by p. the population is expected to increase by 6.5% next year. Write a expression in simplest form that represents the expected population next year
The expression in the simplest form that represents the expected population next year will be 1.065p.
What is an exponent?Let a be the initial value and x be the power of the exponent function and b be the increasing factor.
The exponent is given as
y = a(b)ˣ
The ongoing populace of a city can be addressed by p. the populace is supposed to increment by 6.5% one year from now.
The expression in the simplest form that represents the expected population next year will be given as,
⇒ p(1 + 0.065)
⇒ 1.065p
The expression in the simplest form that represents the expected population next year will be 1.065p.
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What is the remainder of x3 + 3x2 − 10x + k divided by (x + 4)?
Select each equation that has NO real solution!
To determine equations with no real solutions, assess for a negative discriminant or no x-intercepts in quadratic equations. Steps include identifying unknowns, choosing appropriate equations, simplifying terms, and checking for reasonableness.
Explanation:To select each equation that has NO real solution, we must assess the equations provided, looking for specific characteristics that indicate the absence of real solutions. One of the hallmarks of such equations is when they represent a quadratic equation with no x-intercepts or the discriminant (b^2 - 4ac) in the quadratic formula is negative, which means the roots are complex numbers.
When working on problems like these, it's crucial to go through several steps: Identify the unknown, identify the knowns, choose an equation, eliminate terms to simplify the algebra, and then check the answer to see if it is reasonable.
Let's use an example equation: x^2 + 4 = 0. To determine if this has real solutions, we can identify the unknown (x), the knowns (coefficients of x), solve the equation or calculate the discriminant (4^2 - 4*1*-4 = 16 +16 = 32, which is positive), and confirm whether the solutions are real or not. In this case, because the discriminant is positive, this equation does have real solutions, and therefore would not be included in a list of equations with no real solutions.
The equations 2x² - 4x + 5 = -3, x² - 12x + 60 = 12, and x² + 3x + 6 = 0 have no real solutions, based on their negative discriminants.
We need to determine the discriminant (b² - 4ac) of each equation to check for real solutions. A negative discriminant indicates no real solutions.
Equations Analysis
2x² + 2x = 2: Rewrite as 2x² + 2x - 2 = 0. Here, a = 2, b = 2, c = -2. The discriminant is 2² - 4(2)(-2) = 4 + 16 = 20 (positive, so there are real solutions).2x² - 4x + 5 = -3: Rewrite as 2x² - 4x + 8 = 0. Here, a = 2, b = -4, c = 8. The discriminant is (-4)² - 4(2)(8) = 16 - 64 = -48 (negative, so there are no real solutions).x² - 12x + 60 = 12: Rewrite as x² - 12x + 48 = 0. Here, a = 1, b = -12, c = 48. The discriminant is (-12)² - 4(1)(48) = 144 - 192 = -48 (negative, so there are no real solutions).x² - 4 = 0: This is already in quadratic form with a = 1, b = 0, c = -4. The discriminant is 0² - 4(1)(-4) = 16 (positive, so there are real solutions).x² + 3x + 6 = 0: Here, a = 1, b = 3, c = 6. The discriminant is 3² - 4(1)(6) = 9 - 24 = -15 (negative, so there are no real solutions).Equations with No Real Solutions
2x² - 4x + 5 = -3x² - 12x + 60 = 12x² + 3x + 6 = 0Complete Question - Select each equation that has no real solution.
2x² + 2x = 22x² - 4x + 5 = -3 x² - 12x + 60 = 12 x² - 4 = 0 x² + 3x + 6 = 0