What is the answer and work too the equation 4x+9+3x=30

(b) 2x² - 3x + 4

using synthetic division or long division to obtain the quotient 2x² - 3x + 4

Answer:

The answer is D . The means are equal and the standard deviation of Plot 1 is larger than the standard deviation of Plot 2.  

Step-by-step explanation:

The histogram gives you information about the number of times a specific number appears on your sample. Then you can construct your sample looking at each histogram. For example in Plot 1 the value -2 appears two times. If you this,  you obtain the following samples:  

Plot 1: -2, -2, -1, -1, 0, 0, 1, 1, 2, 2

Plot 2: -2, -1, -1, 0, 0, 0, 0, 1, 1, 2

If you calculate the means by adding and dividing by the number of obs you find equal means  (0) because the data is centered around 0. ( no deviations to left or right).  

Now the   standard deviation (sd) can be infered in the histogram. The sd measures the distance around the mean of the data. When data is concentrated very close to the mean, the sd is lower as in Plot 2 (More points are 0 or around zero in Plot 2). In plot 1 your points are farther apart from the mean of zero so the sd is higher.  

What does the graph of eˣ look like?  It has an asymptote at y = 0, passes through (0, 1) and goes to ∞.

y = 4eˣ has a vertical stretch by a factor of 4 compared to the parent graph so the range is the same as it's parent graph.

Range: y > 0     Interval Notation: (0, ∞)

(3w²r)²(-2w⁵r²)³ =​ When a power is raised to a power the exponents have to be multiplied.

​(3²w⁽²*²⁾r²)(-2³w⁽⁵*³⁾r⁽²*³⁾) = We can take out the constants

= (3²)(-2³)(w⁴r²)(w¹⁵r⁶) = We can group the same variables​

​= -72(w⁴w¹⁵)(r²r⁶) = When multiplying two powers that have the same base, you have to add the exponents.

​= -72w⁽⁴⁺¹⁵⁾r⁽²⁺⁶⁾ = -72w¹⁹r⁸

​Answer : F) -72w¹⁹r⁸

​Hope this helps!​​​​

​[tex]\textit{\textbf{Spymore}}[/tex]​​​​​​​

These are called integer numbers.

We start with natural numbers (or whole numbers), i.e. the set

[tex] \mathbb{N} = \{0,1,2,3,4,\ldots\} [/tex]

When you add the opposite of each whole number, you have the set of integers:

[tex] \mathbb{Z} = \{0,\pm1,\pm2,\pm3,\ldots\} [/tex]

Answer:the not called whole numbers there called integers

Step-by-step explanation: whole numbers are 0 1 2 3 4 and so on integers are 0 -1 -2 -3 -4 and so on

Solution 1:

In the given statement :

"The settlers traveled west in covered wagons"

The Predicate is traveled west in covered wagons.

So option c. traveled west in covered wagons is the correct choice.

Solution 2:

In the given sentence:

"Soon, telegraph lines provided additional communication to the city."

The simple subject and verb are given by lines provided.

Answer : Option a: lines provided.

Answer:

The answer will be: [tex]15 + \frac{3}{57}[/tex]

Step-by-step explanation:

In Partial quotients method, first we will subtract an easy multiple of the divisor from the dividend. Then repeat the subtraction until the remainder is less than the divisor.  Finally, we need to add up all the multiples of the divisor to find the quotient of the division.

Here, dividend is 858 and divisor is 57.

[tex]57)\overline{858}[/tex]

  - 570            × 10

     288

    - 285            × 5

         3

So, the quotient of the division will be:  [tex](10+5)=15[/tex] and the remainder is:  3

We can write the answer as:  [tex]15 + \frac{3}{57}[/tex]

Answer:

[tex]6^1[/tex]

Step-by-step explanation:

[tex]Use\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\\dfrac{6^{-3}}{6^{-4}}=6^{-3-(-4)}=6^{-3+4}=6^1[/tex]

The digits 4 and 5 can replace the box in order to make the inequality true.

Any digits larger than 5 or less than 4 will not make it true.

Suppose we used 3.

735 is not greater than 734, and so the inequality would be false.

Now let's suppose we used 6.

764 is not less than 761.

A list of digits that can replace the given expressions 735<7 and 4<761 has been provided.

The provided question asks for a list of numbers that can replace the expressions 735<7 and 4<761. To find the numbers that can replace these expressions, we need to identify the digits in the list provided that satisfy the conditions. Let's go through each digit in the list and determine if they can replace the expressions:

Therefore, the list of digits that can replace 735<7 are: 664, 695, 696, 698, 707, 712, 713, 721, 723, 725, 761, 762, 763, 767, 775, 778, 805, 833, 889, 893, 899, 903, 909, 921, 923. The list of digits that can replace 4<761 are: 136, 140, 178, 190, 205, 215, 217, 218, 232, 234, 240, 255, 270, 275, 290, 301, 303, 315, 317, 318, 326, 333, 343, 349, 360, 369, 377, 388, 391, 392, 398, 400, 402, 405, 408, 422, 429, 450, 475, and 512.

https://brainly.com/question/33663282

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Final answer:

The price per pound of turkey is $7.98.

Explanation:

To find the price per pound, divide the total cost by the weight. In this case, Bryan paid $19.95 for 2.5 pounds of turkey. So, the price per pound is $19.95 divided by 2.5, which is $7.98 per pound.To calculate the price per pound of turkey that Bryan paid, we divide the total cost by the total weight. Bryan paid $19.95 for 2.5 pounds of turkey.

Divide the total cost by the total weight in pounds.

$19.95 ÷ 2.5 pounds = $7.98 per pound

Thus, the price per pound of turkey that Bryan paid is $7.98.

The 3 inside angles of a triangle need to equal 180 degrees.

You are given 28 for one.

The second on is adding 58 + 77 = 135 degrees.

X = 180 - 28 - 135 = 17 degrees

Suppose, we are given a function

[tex]f(x)=ax^2+bx+c[/tex]

Application of Zeros:

we know that

zeros are x-intercepts

We know that zeros are values of x for which f(x)=0

and it has very wide application

It is extremely useful in real world applications such as finance, astronomy, geology, architecture, or physics

For exp:

[tex]h(t)=-16t^2 + 96t + 112[/tex]

Zeros will help us to find time at which ball reaches to ground

so, we set h(t)=0

and then we can solve for t

value of t are zeros

Application of y-intercept:

we know that y-intercepts are values of y at which x=0

It's application can be population , finance and physics etc

For exp:

[tex]h(t)=-16t^2 + 96t + 112[/tex]

we can find initial height of object after plugging t=0

[tex]h(0)=-16(0)^2 + 96(0) + 112[/tex]

[tex]h(0)=112[/tex]

so, body dropped from 112 feet

Answer: The amount of snow the town get the rest of the week is given by

[tex]\frac{5}{24}[/tex]

Step-by-step explanation:

[tex]\text{ Total inches of snow town got in a week }=5\frac{1}{3}=\frac{16}{3}[/tex]

[tex]\text{ Amount of snow it is receiving on Monday}=2\frac{3}{4}=\frac{11}{4}\text{ inches }[/tex]

[tex]\text{Amount of snow it is receiving on Tuesday}=1\frac{1}{2}=\frac{3}{2}\text{ inches }[/tex]

[tex]\text{Amount of snow it is receiving on Wednesday}=\frac{7}{8}\text{ inches }[/tex]

[tex]\text{Amount it is receiving in remaining week is given by}[/tex]

[tex]\frac{16}{3}-(\frac{11}{4}+\frac{3}{2}+\frac{7}{8})\\\\=\frac{16}{3}-\frac{22+12+7}{8}\\\\=\frac{16}{3}-\frac{41}{8}\\\\=\frac{128-125}{8}\\\\=\frac{5}{24}\text{ inches }[/tex]

So, the amount of snow the town get the rest of the week is given by

[tex]\frac{5}{24}\text{ inches }[/tex]

Equation is x= 558 t2/496

x=4.5

I got the answer from another brainly user asking the same question. Someone else answered it. I just typed your question into the search bar and got it. Good luck <3

Answer:

Step-by-step explanation:

ANSWER

[tex]P(1<X<5)=0.51[/tex]

EXPLANATION.

The probability of selecting a number between 1 and 5 can be calculated by summing all probabilities between 1 and 5

[tex]P(1<X<5)=P(X=2)+P(X=3)+P(X=4)[/tex]

[tex]P(1<X<5)=0.07+0.22+0.22[/tex]

[tex]P(1<X<5)=0.51[/tex]

The given formula is A= bh/2

First multiply both sides by 2:

2A = bh

Now divide both sides by b:

h = 2A/b

the question in English

Mateo will reproduce a photo measuring 5 cm per side on a scale of 3/4

How much will the square side of the copy measure?

Will the size of the copy be larger or smaller than the original?

we know that

the scale factor is equal to [tex]\frac{3}{4}[/tex]

Let

x----------> the original length side

y--------> the copy length side

[tex]y=\frac{3}{4}*x[/tex]

we have that

[tex]x=5\ cm[/tex]

substitute the values

[tex]y=\frac{3}{4}*5=3.75\ cm[/tex]

therefore

the answer Part a) is

the length side of the copy measure is [tex]3.75\ cm[/tex]

Part b)

we know that

the size of the original photo is------> [tex]5*5=25\ cm^{2}[/tex]

the size of the copy is------> [tex]3.75*3.75=14.06\ cm^{2}[/tex]

so

[tex]14.06\ cm^{2} < 25\ cm^{2}[/tex]

therefore

the answer part b) is

The size of the copy be smaller than the original

Answer:

  4.  2

Step-by-step explanation:

The value of B in the expression is the numerator of the fraction in the exponent: 2.

[tex]27^{-\frac{2}{3}}=\dfrac{1}{\sqrt[3]{27^2}}[/tex]

_____

= 1/9

Answer:

- The error is: [tex](\frac{31}{4})(\frac{1}{3})[/tex]

- The correct solution is:  [tex]\frac{93}{4}=23^{\frac{1}{4}}[/tex] (Carla can make approximately 23 recipes with the clay).

Step-by-step explanation:

1. Carla must divide [tex]\frac{31}{4}[/tex] ÷ [tex]\frac{1}{3}[/tex] as following:

- Take the reciprocal of [tex]\frac{1}{3}[/tex].

- Multiply the numerators and the denominators.

Then:

[tex](\frac{31}{4})(\frac{1}{3})=\frac{(31)(3)}{(4)(1)}=\frac{93}{4}[/tex]

2. As a mixed number:

[tex]\frac{93}{4}=23^{\frac{1}{4}}[/tex]

3. Therefore, Carla can make approximately 23 recipes with the clay.

Carla can make 23 full modeling clay recipes with 7 3/4 cups of salt, with a quarter cup of salt remaining.

To find out how many recipes of modeling clay Carla can make with 7 3/4 cups of salt, we need to divide the total amount of salt she has by the amount required for one recipe. Since one recipe requires 1/3 cup of salt, we will perform the following division: 7 3/4 divided by 1/3.

To simplify this, first, convert 7 3/4 to an improper fraction, which is (7 × 4 + 3)/4, or 31/4. Now, dividing by a fraction is the same as multiplying by its reciprocal. Therefore, we multiply 31/4 by the reciprocal of 1/3, which is 3/1.

31/4 × 3/1 = 93/4, which simplifies to 23 1/4.

This means Carla can make 23 full recipes with a little salt left over.

It would be 6 km because 4 1/2 divided by 3 = 1.5x4=6

You originally had 30 canicas in your collection.

Let's denote the total number of canicas in your collection as C

According to the information provided:

1. Tales received 1/5 of the total:

  Tales received [tex]\( \frac{1}{5} \)[/tex] of C, which can be expressed as [tex]\( \frac{1}{5} \times C \).[/tex]

2. You received 1/3 of the rest:

  After giving Tales his share, there are [tex]\( \frac{4}{5} \)[/tex] of the canicas left. You received [tex]\( \frac{1}{3} \)[/tex] of this remaining amount. So, your share is [tex]\( \frac{1}{3} \times \frac{4}{5} \times C \)[/tex].

3. Pitagórica received the remaining 16 canicas:

  After Tales and you received your shares, Pitagórica received the remaining canicas, which is given as 16 canicas.

Now, we can set up an equation to represent this situation:

[tex]\[ \frac{1}{5} \times C + \frac{1}{3} \times \frac{4}{5} \times C + 16 = C \][/tex]

Now, let's solve for C:

[tex]\[ \frac{1}{5}C + \frac{4}{15}C + 16 = C \][/tex]

Combine the terms with C:

[tex]\[ \frac{3}{15}C + \frac{4}{15}C + 16 = C \][/tex]

Combine the terms on the left side:

[tex]\[ \frac{7}{15}C + 16 = C \][/tex]

Subtract [tex]\( \frac{7}{15}C \)[/tex] from both sides:

[tex]\[ 16 = \frac{8}{15}C \][/tex]

Now, solve for C:

[tex]\[ C = \frac{15}{8} \times 16 \][/tex]

[tex]\[ C = 30 \][/tex]

Therefore, you originally had 30 canicas in your collection.

Complete question:

He divided my collection of dogs among my three best friends. A Tales to him he gave 1/5 of the total, a Here to me 1/3 of the rest, and lastly to Pitagórica, he gave me the 16 canicles that I sobraron.

How many canicas do I have in my collection?

Answer:

148.8

Step-by-step explanation:

The original price of the necklace before the 20% increase was approximately £155 (£186 / 1.20).

To find the original price of the necklace before the 20% increase, we can use the formula:

Original Price = Final Price / (1 + Percent Increase)

Given that the final price is £186 and the increase is 20%, we substitute these values into the formula:

Original Price = £186 / (1 + 0.20)

Calculating inside the parentheses first:

1 + 0.20 = 1.20

Now, divide the final price by 1.20:

Original Price = £186 / 1.20 ≈ £155

So, the original price of the necklace before the increase was approximately £155.

[tex]x=2y^3+3\\\\\text{change x to y and y to x}\\\\y=2x^3+3\\-----------------------\\\text{if you did it}\\\\2y^3+3=x\ \ \ \ |-3\\\\2y^3=x-3\ \ \ \ |:2\\\\y^3=\dfrac{x-3}{2}\to\boxed{y=\sqrt[3]{\dfrac{x-3}{2}}}[/tex]

Answer:

1 : Grouping Symbol

2 : Operator

3 : Order of Operations

4 : Exponent

5 : Variable

6 : Term

7 : Coefficient

8 : Constant

9 : Numerical Expression

10 : Variable Expression

11 : Equation

12 : Inequality

13 :

14 : Open Sentence

Those are the ones I know. I hope this helps

Answer:

i agree with BreezyXXX

Step-by-step explanation: