Answer:
MgO
Explanation:
Mass of Mg = 60.3 g
Molar mass of Mg = 24.305 g/mol
Moles of Mg = 60.3 g/ 24.305 g/mol = 2.48 mol
Mass of O = 39.7g
Molar mass of O = 16 g/mol
Moles of O = 39.7g/ 16 g/mol = 2.48 mol
So the molar ration of Mg:O is 1:1
Therefore the empirical formula is MgO
Which of the following is the best definition of a chemical change?
Answer: A change in a substance where one or more new substances form
Explanation: Apex
What is the molality of a solution that contains 75.2 grams of AgClO4 in 885 grams of benzene? Question 5 options: 0.41 m 4.10 m 8.20 m 0.83 m
The molality of the solution is 0.41 molal and the correct option is option 1.
What is Molality?
Molality is also known as molal concentration. It is a measure of solute concentration in a solution. The solution is composed of two components; solute and solvent.
The number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent is known as molality.
Molality = number of moles of solute ÷ mass of solvent in kg
Given,
Mass of AgClO₄ = 75.2g
Mass of benzene = 885g
Molality = number of moles of solute ÷ mass of solvent in kg
moles of AgClO₄ = 75.2 / 207
= 0.363 moles
Molality = 0.363 / 0.885
= 0.41 molal
Therefore, the molality of the solution is 0.41 molal and the correct option is option 1.
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which of the following substances has a molar mass of 208g
When assigning electrons to orbitals, which would be the most likely 'address' for the next electron following the 5s2 electron? 5s3 5p1 4d1 5d1
Filling of electrons in an orbitals takes place by using following rules:
Aufbau rule: Filling of electrons takes place in an energy levels in the increasing order of energy that is the one having lowest energy will fill first.
Hunds rule: No second electron will be filled in an orbital until each orbital occupies a single electron.
Pauli exclusion principle: No two electrons can have same spin in an orbital.
So here also also the rules must be applied in filling electrons , by Aufbau rule, energy level that is having lower energy in this case after 5s it will be 4d¹, will fill first. So the answer is 4d¹.
What concentration of the barium ion, ba2+, must be exceeded to precipitate baf2 from a solution that is 1.00×10−2 m in the fluoride ion, f−? ksp for barium fluoride is 2.45×10−5 . express your answer with the appropriate units?
Answer is: concentration of the barium ion is 0.245 M.
Chemical reaction: BaF₂ → Ba²⁺ + 2F⁻.
[F⁻] = 1.00·10⁻² M.
Ksp = 2.45·10⁻⁵.
Ksp = [Ba²⁺] · [F⁻]².
[Ba²⁺] = Ksp ÷ [F⁻]².
[Ba²⁺] = 2.45·10⁻⁵ ÷ (1.00·10⁻² M)².
[Ba²⁺] = 0.245 M.
Answer: The concentration of barium ions that must exceed to precipitate the salt is 0.245 M
Explanation:
Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is represented as [tex]K_{sp}[/tex]
Barium fluoride is an ionic compound formed by the combination of 1 barium ion and 2 fluoride ions.
The equilibrium reaction for the ionization of barium fluoride follows the equation:
[tex]BaF_2(s)\rightleftharpoons Ba^{2+}(aq.)+2F^-(aq.)[/tex]
The solubility product for the above reaction is:
[tex]K_{sp}=[Ba^{2+}]\times [F^-]^2[/tex]
We are given:
[tex][F^-]=1.00\times 10^{-2}M\\\\K_{sp}=2.45\times 10^{-5}[/tex]
Putting values in above equation, we get:
[tex]2.45\times 10^{-5}=[Ba^{2+}]\times (1.00\times 10^{-2})^2[/tex]
[tex][Ba^{2+}]=\frac{2.45\times 10^{-5}}{(1.00\times 10^{-2})^2}=0.245M[/tex]
Hence, the concentration of barium ions that must exceed to precipitate the salt is 0.245 M
Which atomic model proposed that electrons move in specific orbits around the nucleus of an atom?
Dalton’s atomic model
Thomson’s atomic model
Rutherford’s atomic model
Bohr’s atomic model
quantum atomic model
Answer: The correct answer is Bohr's atomic model.
Explanation:
For the given options:
Dalton's atomic model: This model states that every matter is made up of smallest unit known as atom.
Thomson's atomic model: He proposed a model known as plum pudding model. He considered atom to be a pudding of positive charge in which negative particles are embedded such as plum.
Rutherford's atomic model: He gave an experiment known as gold foil experiment. In his model, he concluded that in an atom, there exist a small positive charge in the center.
Bohr's atomic model: This model states that electron revolve around the nucleus in discrete orbits in an atom.
Quantum atomic model: This model determines the location of electrons in an atom in a 3-D space.
Hence, the correct answer is Bohr's atomic model.
He hydroxide ion concentration in household ammonia is 3.2 × 10−3 m at 25 °c. what is the concentration of hydronium ions in the solution
Answer:- [tex][H_3O^+]=4.2*10^-^1^1[/tex]
Solution:- Ammonia is a weak base. So, to calculate the hydroxide ion concentration we make the ice table:
[tex]NH_3(aq)+H_2O(l)\rightleftharpoons NH_4^+(aq)+OH^-(aq)[/tex]
I 0.0032 0 0
C -X +X +X
E (0.0032-X) X X
[tex]K_b=\frac{[NH_4^+][OH^-]}{[NH_3]}[/tex]
Kb value for ammonia is [tex]1.8*10^-^5[/tex] . Let's plug in the values and solve for X.
[tex]1.8*10^-^5=\frac{X^2}{0.0032-X}[/tex]
Kb value is very low so we can neglect the X on the bottom.
[tex]1.8*10^-^5=\frac{X^2}{0.0032}[/tex]
On cross multiply:
[tex]X^2=1.8*10^-^5*0.0032[/tex]
[tex]X^2=5.76*10^-^8[/tex]
On taking square root:
[tex]X=2.4*10^-^4[/tex]
From ice table, [tex][OH^-]]=X[/tex]
So, [tex][OH^-]=2.4*10^-^4[/tex]
hydronium ion and hydroxide ion concentrations are related to each other by the formula:
[tex][H_3O^+][OH^-]=K_w[/tex]
where, Kw is the water dissociation constant and its value is [tex]1.0*10^-^1^4[/tex]
[tex][H_3O^+]=\frac{1.0*10^-^1^4}{2.4*10^-^4}[/tex]
[tex][H_3O^+]=4.2*10^-^1^1[/tex]
How do impulses travel from one neuron to another?
substract 10x +9 from 7x-10
This is a subtraction of expression. You should remember the rules in subtracting or adding expression. You can only add or subtract two terms if they are similar terms which mean they have the same variable with the same exponents.
(7x – 10) – (10x + 9)
You have to distribute the negative to the parenthesis.
7x – 10 – 10x – 9
7x – 10x – 10 – 9
-3x - 19
Identify the oxidizing agent in the reaction: 8h+(aq) + 6cl−(aq) + sn(s) + 4no3−(aq) → sncl62−(aq) + 4no2(g) + 4h2o(l)
The oxidizing agent in the reaction is the NO3- ions.
Explanation:In the given reaction,
8H+(aq) + 6Cl-(aq) + Sn(s) + 4NO3-(aq) → SnCl62-(aq) + 4NO2(g) + 4H2O(l)
The oxidizing agent is the species that gets reduced. In this reaction, the NO3- ions are reduced from a +5 oxidation state to a +4 oxidation state, so the NO3- ions are the oxidizing agent.
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In the given reaction, the nitrate ion (NO₃⁻) is the oxidizing agent as it gets reduced from an oxidation number of +5 to +4. The tin (Sn) is oxidized from 0 to +4.
The identification is based on changes in oxidation numbers during the reaction.
To identify the oxidizing agent in the given reaction:
8H⁺(aq) + 6Cl⁻ (aq) + Sn(s) + 4NO₃⁻(aq) → SnCl₆²⁻(aq) + 4NO₂(g) + 4H₂O(l)Assign oxidation numbers to each element in the reaction:
Sn (tin) in its elemental form has an oxidation number of 0.In SnCl₆²⁻ tin’s oxidation number is +4.In NO₃⁻ (nitrate ion), nitrogen has an oxidation number of +5.In NO₂ (nitrogen dioxide), nitrogen has an oxidation number of +4.Determine what is being oxidized and reduced:
sn is oxidized from 0 to +4, losing electrons.NO₃⁻ is reduced from +5 to +4, gaining electrons.Identify the oxidizing and reducing agents:
The species that gets reduced is the oxidizing agent.So, in this reaction, NO₃⁻ (nitrate ion) is the oxidizing agent.
Correct question is: Identify the oxidizing agent in the given reaction:
8H⁺(aq) + 6Cl⁻ (aq) + Sn(s) + 4NO₃⁻(aq) → SnCl₆²⁻(aq) + 4NO₂(g) + 4H₂O(l)
In which relationship stage are the individuals in the following scenario?
Heather and Mona became good friends about ten years ago. For the last year, though, things haven't been the same. They no longer make the effort to meet up for lunch or go shopping together. They try to remember to call on birthdays and holidays, but sometimes they forget.
terminating
differentiating
stagnating
circumscribing
avoiding
Differentiating is a process of loosing or separating. During this stage, variations between the relationship associates are highlighted and what was considered to be connections starts to crumble. The people avoid discussing the relationship because they believe they understand what the other will respond.
Write the name of the following compound MgSO4 • H20
Vitellium (Vi) has the following composition:
Vi–188: 187.9122 amu; 10.861%
Vi–191: 190.9047 amu; 12.428%
Vi–193: 192.8938 amu; 76.711%
Based on this data, what can you predict about the average atomic mass of vitellium?
A.)It will be equal to the arithmetic mean of the masses of the three isotopes.
B.)It will be closer to the mass of Vi–188.
C.)It will be closer to the mass of Vi–193.
D.)It will be equal to the mass of Vi–193.
And I am a PLATO user so I already know it's not A!
The equation below shows hydrogen reacting with oxygen to produce water. 2H2+O2>2H2O if 16mol of oxygen were reacted with excess hydrogen gas, how many moles of water would be produced?
Answer : The number of moles of water produced would be, 32 moles.
Explanation : Given,
Moles of [tex]O_2[/tex] = 16 mole
The given chemical reaction is:
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
From the balanced chemical reaction we conclude that,
As, 1 mole of [tex]O_2[/tex] gas react to give 2 moles of [tex]H_2O[/tex]
So, 16 mole of [tex]O_2[/tex] gas react to give [tex]16\times 2=32[/tex] moles of [tex]H_2O[/tex]
Thus, the number of moles of water produced would be, 32 moles.
Is oil used by other organisms on Earth? If yes, explain.
The balanced net ionic equation for the neutralization reaction involving equal molar amounts of hno3 and koh is ________.
Final answer:
The balanced net ionic equation for the neutralization reaction involving equal molar amounts of HNO3 and KOH is H+(aq) + OH−(aq) → H2O(l), illustrating the direct interaction between hydrogen and hydroxide ions to form water.
Explanation:
The balanced net ionic equation for the neutralization reaction involving equal molar amounts of HNO3 and KOH is represented by the equation:
H+(aq) + OH−(aq) → H2O(l)
This equation demonstrates that the hydrogen ion (H+) from nitric acid (HNO3) combines with the hydroxide ion (OH−) from potassium hydroxide (KOH) to form water (H2O). The potassium ion (K+) and the nitrate ion (NO3−) are spectator ions and do not participate in the reaction. Therefore, they are not included in the net ionic equation. Neutralization reactions like this involve the combination of an acid and a base to produce water as one of the products.
How many grams of sodium metal are needed to react completely with 25.8 liters of chlorine gas at 293 Kelvin and 1.30 atmospheres? Ideal gas law after stoichiometry I don't need the answer please don't give it just explain how to solve it.
At high pressures, real gases do not behave ideally. calculate the pressure exerted by 18.0 g h2 at 20.0°c in a 1.00 l container assuming in part 1 non-ideal behavior and in part 2 ideal behavior.
Radon (rn) is the heaviest and the only radioactive member of group 8a(18), the noble gases. it is a product of the disintegration of heavier radioactive nuclei found in minute concentrations in many common rocks used for building and construction. in recent years, health concerns about the cancers caused from inhaled residential radon have grown. if 1.00 × 1015 atoms of radium (ra) produce an average of 1.373 × 104 atoms of rn per second, how many liters of rn, measured at stp, are produced per day by 9.64 g of ra?
The amount of Rn produced per day by 9.64 g of Ra is 1.13 [tex]\rm \times\;10^-^8[/tex] L.
Moles of Radon (Ra) in 9.64 g of Ra are;
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of Ra = [tex]\rm \dfrac{9.64}{226}[/tex]
Moles of Ra = 0.0426
Number of atoms of Ra in 0.0426 moles of Ra are:
Number of atoms = moles [tex]\times[/tex] Avagadro number
= 0.426 [tex]\times\;6.203\;\times\;10^2^3[/tex]
number of atoms of Ra produced by 9.64 g of Ra are 2.56 [tex]\rm \times\;10^2^3[/tex]
the proportion of atoms : atom\sec will be:
[tex]\rm \dfrac{atoms\;of\;Ra}{atoms\;of\;Ra/sec}\;=\;\dfrac{atoms\;of\;Rn}{x}[/tex]
[tex]\rm \dfrac{1\;\times\;10^1^5}{1.373\;\times\;10^4}\;=\;\dfrac{2.56\;\times\;10^2^2}{x}[/tex]
Atoms of Rn produced per second are 3.53 [tex]\rn \times\;10^1^0[/tex] atoms/sec.
Moles of Rn produced = [tex]\rm \dfrac{atoms\;per\;sec}{avagadro\;number}[/tex]
Moles of Rn produced = [tex]\rm \dfrac{3.52\;\times\;10^1^0}{6.023\;\times\;10^2^3}[/tex] moles
Moles of Rn produced = 5.85 [tex]\rm \times\;10^-^1^4[/tex] mol/sec.
From the ideal gas equation,
PV = nRT
The volume of Rn produced = [tex]\rm \dfrac{nRT}{P}[/tex]
= [tex]\rm \dfrac{5.85\;\times\;10^-^1^4\;\times\;0.0821\;\times\;273.15}{1}[/tex]
= 1.31 [tex]\rm \times\;10^-^1^3[/tex] liter/sec.
The amount of Rn produced per day = amount produced per second [tex]\times[/tex] 3600
The amount of Rn produced per day = 1.31 [tex]\rm \times\;10^-^1^3[/tex] [tex]\times[/tex] 24 [tex]\times[/tex] 3600 L
The amount of Rn produced per day by 9.64 g of Ra is 1.13 [tex]\rm \times\;10^-^8[/tex] L.
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A mixture is two or more substances that are mixed together but not chemically combined. The substances in a mixture each keep their own properties and can be separated from the mixture.
Identify the substance in a mixture of sand, salt, sawdust, and iron filings that can easily be separated by dissolving the mixture in water.
A) sand
B) salt
C) sawdust
D) iron filings
Plz help!
Sam wants to demonstrate how water changes from a solid to a gas. He places ice in a pot on a stove. What variable is causing water to change state?
A) the heat from the stove
B) the container the ice is placed in
C) the temperature of the air surrounding the ice
D) the time that has lapsed since the ice was removed from the freezer
Answer: Option (A) is the correct answer.
Explanation:
When Sam placed ice in a pot on a stove then there will be transfer of heat from the stove to the pot and then from the pot to the ice.
As a result, solid state of ice changes into liquid state of water because of melting of ice.
Thus, we can conclude that the heat from the stove is the variable that is causing water to change state.
Calculate the freezing point of a solution containing 15 grams of kcl and 1650.0 grams of water. the molal-freezing-point-depression constant (kf) for water is 1.86 ∘c/m
Answer : The freezing point of a solution is [tex]-0.454^oC[/tex]
Explanation : Given,
Molal-freezing-point-depression constant [tex](K_f)[/tex] for water = [tex]1.86^oC/m[/tex]
Mass of KCl (solute) = 15 g
Mass of water (solvent) = 1650.0 g = 1.650 kg
Molar mass of KCl = 74.5 g/mole
Formula used :
[tex]\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of KCl}}{\text{Molar mass of KCl}\times \text{Mass of water in Kg}}[/tex]
where,
[tex]\Delta T_f[/tex] = change in freezing point
[tex]\Delta T_s[/tex] = freezing point of solution = ?
[tex]\Delta T^o[/tex] = freezing point of water = [tex]0^oC[/tex]
i = Van't Hoff factor = 2 (for KCl electrolyte)
[tex]K_f[/tex] = freezing point constant for water = [tex]1.86^oC/m[/tex]
m = molality
Now put all the given values in this formula, we get
[tex]0^oC-T_s=2\times (1.86^oC/m)\times \frac{15g}{74.5g/mol\times 1.650kg}[/tex]
[tex]T_s=-0.454^oC[/tex]
Therefore, the freezing point of a solution is [tex]-0.454^oC[/tex]
Answer:
The freezing point of the solution containing 15 grams of KCl and 1650 grams of water is [tex]\rm -0.454^\circ\;C[/tex].
Explanation:
The freezing point of the solution can be calculated by:
Molarity = [tex]\rm \frac{mass\;of\;KCl\;}{molar\;mass\;of\;KCl\;\times\;Mass\;of\;water}[/tex]
Molarity = [tex]\rm \frac{15}{74.5;\times\;1650}[/tex]
Molarity = 1.2 [tex]\rm \times\;10^-^4[/tex] M
[tex]\rm \Delta\;T\;=\;i\;\times\;K_f\;\times\;Molarity[/tex]
[tex]\rm T^\circ\;\times\;T_f\;=\;i\;\times\;K_f\;\times\;Molarity[/tex]
[tex]\rm T_f=\;2\;\times\;1.86\;\times\;1.2\;\times\;10^-^4[/tex]
[tex]\rm T_f[/tex] = [tex]\rm -0.454^\circ\;C[/tex]
The freezing point of the solution containing KCl is [tex]\rm -0.454^\circ\;C[/tex].
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When a collision occurs between two reactant particles that, between them, have the required minimum kinetic energy, or activation energy, a product does not always form. Which of the following reasons explains this?
a.low temperature
b.small surface area
c.unfavorable geometry
d.low concentration
c.unfavorable geometry
Answer: C. Unfavorable geometry
Explanation: When collision occurs between two reactants in order to make a reaction possible there are 3 factors which are responsible.
a) Orientation factor
b) Energy factor
c) rate of collision
Thus out of the given options, unfavorable geometry is the correct one as temperature and concentration as well as surface area will have very little effect on the reaction.
If the geometry of the reactant is not complementary then the reaction would not lead successfully.
How many orbitals are there in the third shell (n=3)? express your answer numerically as an integer?
There are three subshells (s, p, and d) and a total of nine orbitals in the third shell (n=3) of an atom.
The question asks about the number of subshells and orbitals in the third principal shell (n=3) of an atom. In the third shell, there are three subshells, which are designated as 3s, 3p, and 3d. The subshell with l=0 is called s and has 2(0)+1 = 1 orbital, the subshell with l=1 is called p and has 2(1)+1 = 3 orbitals, and the subshell with l=2 is called d and has 2(2)+1 = 5 orbitals.
Total number of orbitals for n=3 = 1 + 3 + 5 = nine orbitals. These orbitals can accommodate a maximum number of electrons using the formula 2n², which gives us 2(3)² = 18 electrons for the third shell.
Consider the following equilibrium:
4KO2(s) + 2H2O(g) 4KOH(s) + 3O2(g)
Which of the following is a correct equilibrium expression?
Keq=[KOH]4[O2]3[KO2]4[H2O]2
Keq=[H2O]2[O2]3
Keq=[KO2]4[H2O]2[KOH]4[O2]3
Keq=[O2]3[H2O]2
Answer:
[tex]Keq=\frac{[O_{2}]^{3} }{[H_{2}O]^{2} }[/tex]
Explanation:
The equilibrium constant (Keq) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. In Keq we include gases and aqueous species, but not solids nor pure liquids because their concentration remains almost constant over time.
Let's consider the following reaction.
4 KO₂(s) + 2 H₂O(g) ⇄ 4 KOH(s) + 3 O₂(g)
Then, the equilibrium constant is:
[tex]Keq=\frac{[O_{2}]^{3} }{[H_{2}O]^{2} }[/tex]
What is the relationship between environmental health and our own health
The relationship between environmental health and our own health is intrinsic and multifaceted. Environmental health encompasses the aspects of human health that are determined by physical, chemical, biological, social, and psychosocial factors in the environment. It also refers to the theory and practice of assessing, correcting, controlling, and preventing those factors in the environment that can potentially affect adversely the health of present and future generations.
Here are several key points that illustrate the relationship between environmental health and personal health:
1. Exposure to Pollutants: The quality of air, water, and soil can directly impact health. For example, exposure to air pollutants like particulate matter, ozone, nitrogen dioxide, and sulfur dioxide can lead to respiratory and cardiovascular diseases. Similarly, contaminated water and soil can lead to a variety of health issues, including gastrointestinal illnesses and heavy metal poisoning.
2. Chemical Safety: The use of pesticides, herbicides, and industrial chemicals can have toxic effects on humans. Exposure to these chemicals, whether through direct contact or through the food chain, can increase the risk of cancer, reproductive issues, and developmental problems.
3. Climate Change: Changes in climate can affect health in numerous ways, including an increase in heat-related illnesses, the spread of vector-borne diseases (such as malaria and Lyme disease), and the impact of extreme weather events on mental health.
4. Natural Resources: Access to clean water, nutritious food, and natural spaces for recreation and relaxation contributes to good health. Conversely, a lack of these resources can lead to malnutrition, dehydration, and increased stress levels.
5. Built Environment: The design of our communities, including housing, transportation, and recreational facilities, influences physical activity levels, exposure to noise and light pollution, and opportunities for social interaction, all of which affect health outcomes.
6. Occupational Health: Workplace environments can expose individuals to hazardous conditions, dangerous materials, and stressful situations, which can lead to occupational diseases and injuries.
7. Social Determinants of Health: Environmental health also includes social and economic factors, such as access to education, healthcare, and safe neighborhoods. These factors can have a profound impact on health disparities and life expectancy.
8. Mental Health: The environment can influence mental health through factors such as noise pollution, overcrowding, and lack of green spaces, which can contribute to stress, anxiety, and depression.
In summary, environmental health is a critical determinant of the health of individuals and populations. By understanding and addressing the environmental factors that affect health, we can work towards creating healthier living conditions and reducing the burden of disease. Public health initiatives that focus on improving environmental quality, such as reducing pollution, promoting sustainable practices, and ensuring access to clean water and nutritious food, are essential for enhancing the health and well-being of current and future generations.
The nucleus of the atom contains what subatomic particle(s)? Protons only Neutrons only Electrons only Protons and neutrons Protons and electrons
Answer:
c
Explanation:
What is true about the element Francium (Fr, atomic number 87)? choose 3
A. It has seven valence electrons
B. It is likely to form ionic bonds
C. It is a nonmetal
D. It is in period Seven
E. It is a metal
Answer :
(B) It is likely to form ionic bonds
(D) It is in period seven
(E) It is a metal
Explanation :
Francium is an element whose symbol is 'Fr' and atomic number is 87.
Group 1 alkali metals consists elements Lithium, Sodium, Potassium, Rubidium, Caesium and Francium. Periodic table also shown below.
Francium belongs to the group 1 (alkali metal) and it is in period seven.
It has one valence electron, the electronic configuration of Francium is [Rn} [tex]7s^{1}[/tex].
Alkali metals have tendency to form ionic compounds because they have +1 charge.
The correct statements about Francium (Fr, atomic number 87) are that it is likely to form ionic bonds, is in period seven, and is a metal.
Explanation:The element Francium (Fr, atomic number 87) has several characteristics based on its position in the periodic table. Firstly, as an element in Group 1, it has one valence electron which makes statement A incorrect. This single valence electron also means Francium is highly probable to form ionic bonds with nonmetals seeking to gain electrons, making statement B true. Francium is not a nonmetal, so statement C is false. Statement D is correct as Francium is located in period seven of the periodic table. Lastly, because Francium is in Group 1, it is indeed an alkali metal, making statement E true. Therefore, the correct statements about Francium are B, D, and E.
2no2(g)⇌n2o4(g) kp=6.7at298k a 2.35-l container contains 0.053 mol of no2 and 0.084 mol of n2o4at298k. is the reaction at equilibrium? if not, in what direction will the reaction proceed?
Q> K hence the reaction proceeds in the reverse direction.
First we must obtain the concentration of each of the species;
NO2 - 0.053 mol/2.35-l = 0.023 M
N2O4 - 0.084 mol/2.35-l = 0.036 M
Hence;
Q = [N204]/[NO2]^2
Q = [0.036]/[0.023]^2
Q = 68.05
Since Q > K, it follows that the reaction moves towards the left hand side.
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The reaction quotient Q was found to be 69.86, which is greater than the equilibrium constant Kp of 6.7. Therefore, the reaction will shift towards the formation of NO2 (g) to reach equilibrium.
Explanation:To determine whether the reaction is at equilibrium, we need to calculate the reaction quotient (Qp) and compare it with the given equilibrium constant (Kp). The reaction we are analyzing is:
2 NO2 (g) ⇌ N2O4 (g), with Kp = 6.7 at 298 K.
The reaction quotient Qp is defined similarly to Kp but for an initial or non-equilibrium state and is calculated using partial pressures. Since we are given the number of moles and the volume of the container, we can use the ideal gas law to find the partial pressures of NO2 and N2O4. However, the student question provides moles instead of partial pressures, so we will assume ideal gas behavior and calculate the reaction quotient (Q) with concentrations, which can be used in place of Qp for our rough estimation, knowing they are related in the circumstance of gasses at same temperature and pressure.
The molar concentrations are:
Now we calculate the reaction quotient Q using the given concentrations:
Q = [N2O4]1 / [NO2]2
= 0.0357 / (0.0226)2
= 0.0357 / 0.000511
= 69.86
Since Q (69.86) is greater than Kp (6.7), the reaction will proceed in the direction that reduces Q to equal Kp, which is towards the formation of NO2 from N2O4.
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When hydrogen is burned, it reacts with oxygen and produces _____. carbon dioxide water oil helium