Answer:
Step-by-step explanation:
Given is a sample with 4 items as
12,9,14,21
Mean = average of 4 = 14
s is the square root of sample variance
Sample variance is the sum of squares divided by n-1
But Yuri divided by 4 = n instead of 3 = n-1
That is the only mistake he did and all other steps are right.
Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?
A cross-country travels 20 kilometers before she realizes that she has to cover at least 75 kilometers in order to qualify for the next race. If the racer travels at a rate of 10 kilometers per hour, how many whole hours will it take her to reach the 75-kilometer mark?
A right triangle has an area of 33 mm 2 2 and a height of 11 mm. How long is the base of the triangle? Enter your answer in the box. mm
1000p for an answer pleaseeeeee
Which statement best describes Marcos equation
Meg constructed triangle POQ and then used a compass and straightedge to accurately construct line segment OS, as shown in the figure below:
Which could be the measures of angle POS and angle POQ?
Measure of angle POS is 25 degrees, measure of angle POQ is 40 degrees
Measure of angle POS is 25 degrees, measure of angle POQ is 30 degrees
Measure of angle POS is 20 degrees, measure of angle POQ is 40 degrees
Measure of angle POS is 20 degrees, measure of angle POQ is 30 degrees
The correct answer is:
Measure of angle POS is 20 degrees, measure of angle POQ is 40 degrees
Explanation:
OS is an angle bisector of ∠POQ. This means it splits ∠POQ into two congruent pieces.
This tells us that ∠POS+∠SOQ = ∠POS+∠POS = ∠POQ.
If m∠POS = 20, this means that m∠POQ = 20+20 = 40°.
PLEASE HELP
8.02
1. Find the center, vertices, and foci of the ellipse with equation x squared divided by one hundred plus y squared divided by sixty four = 1.
A) Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-8, 0), (8, 0)
B) Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -8), (0, 8)
C) Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-6, 0), (6, 0)
D) Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -6), (0, 6)
2. Find the center, vertices, and foci of the ellipse with equation 2x2 + 6y2 = 12.
A) Center: (0, 0); Vertices: point negative square root of six comma zero and point square root of six comma zero ; Foci: (-2, 0), (2, 0)
B) Center: (0, 0); Vertices: (0, -6), (0, 6); Foci: Ordered pair zero comma negative four square root two and ordered pair zero comma four square root two ;
C) Center: (0, 0); Vertices: point zero comma negative square root of six and point zero comma square root of six ; Foci: (0, -2), (0, 2)
D) Center: (0, 0); Vertices: (-6, 0), (6, 0); Foci: Ordered pair negative four square root two comma zero and ordered pair four square root two comma zero
3. Graph the ellipse with equation x squared divided by twenty five plus y squared divided by four = 1.
A) A vertical ellipse is shown on the coordinate plane centered at, five, two, with vertices at, five, seven, and five, negative three and minor axis endpoints at three, two, and seven, two.
B) A horizontal ellipse is shown on the coordinate plane centered at five, two, with vertices at zero, two, and ten, two and minor axis endpoints at five, four and five, zero.
C) A vertical ellipse is shown on the coordinate plane centered at the origin with vertices at zero, five and zero, negative five and minor axis endpoints at, negative two, zero and two, zero.
D) A horizontal ellipse is shown on the coordinate plane centered at the origin with vertices at, negative five, zero and, five, zero and minor axis endpoints at, zero, two and zero, negative two.
4. Find an equation in standard form for the ellipse with the vertical major axis of length 6 and minor axis of length 4.
A) x squared divided by two plus y squared divided by three = 1
B) x squared divided by nine plus y squared divided by four = 1
C) x squared divided by three plus y squared divided by two = 1
D) x squared divided by four plus y squared divided by nine = 1
5. An elliptical riding path is to be built on a rectangular piece of property, as shown below.
A vertical ellipse is shown centered on the coordinate plane, surrounded by a rectangle of equal length and width.
The rectangular piece of property measures 8 mi by 6 mi. Find an equation for the ellipse if the path is to touch the center of the property line on all 4 sides.
PLEASE HELP ASAP!!!!!!!!
Answer:
A. y = -2x + 4
Step-by-step explanation:
You are given the values of slope (m) and y-intercept (b). The slope-intercept form of the equation for the line is ...
y = mx + b
Putting m=-2 and b=4 into this form, you get ...
y = -2x + 4
Anybody have the answer to this?
Wendy took a trip from one city to another, a distance of 580 mi. she traveled part of the way by bus, which arrived at the train station just in time for wendy to complete her journey by train. the bus averaged 40 mi/h, and the train averaged 80 mi/h. the entire trip took 9 1 2 h. how long did wendy spend on the train?
What is the solution to the following system?
3x + 10y -12z = 40
x - 5y = 0
x- 4z = 0
--------------------------------------------------------------------
A.) (8, 40, 32)
B.) (10, 2, 3)
C.) (20, 4, 5)
D.) (40, 8, 10)
Answer: C.) (20, 4, 5)
Step-by-step explanation:
The given system is
[tex]3x + 10y-12z = 40.....................(1)\\x-5y =0..........................(2)\\x- 4z=0............................(3)[/tex]
From (2), we have
[tex]x=5y\\\Rightarrow\ y=\frac{x}{5}[/tex]
From (3)
[tex]x=4z\\\Rightarrow\ z=\frac{x}{4}[/tex]
Substitute the values of y and z in equation (1), we get
[tex]3x+10(\frac{x}{5})-12(\frac{x}{4})=40\\\\\Rightarrow\ 3x+2x-3x=40\\\\\Rightarrow\ 20x=40\\\\\Rightarrow\ x=5[/tex]
Then [tex]y=\frac{20}{5}=4[/tex]
and [tex]z=\frac{20}{4}=5[/tex]
Hence, the solution of the given system is (20,4,5)
Jennifer is calculating her gpa. if she uses "=(a1+a2+a3+a4)/4", this is an example of which type of entry?
"there are 362 first-grade students in park elementary school. if there are 34 more girls than boys, how many girls are there"
What is the domain of the graphed function?
A) y ≥ 4
B) x ≥ -2
C) y ≥ -2
D) x ≤ -2
what is the constant of variation for the quadratic variation of x |2|3|4|5|6| fx |28|63|112|175|252|
Describe a situation in which there would be a positive association between two variables.
Cary is 5 5 years older than dan. in 5 years the sum of their ages will be 81. find the age of each man now.
The area of a rectangular room is 120 square feet. The width is 10 feet. What is the length?
The length of the rectangular room is 12 feet.
To find the length of a rectangular room when the area and width are known, you can use the formula:
Area = Length x Width
Given that the area is 120 square feet and the width is 10 feet,
we can substitute these values into the formula:
120 = Length x 10
Length = 120 / 10
Length = 12
Therefore, the length of the rectangular room is 12 feet.
Learn more about area here:
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The surface area of a sphere is found using the formula SA=4πr^2, where r is the radius. If the surface area of a sphere is 64π square feet, what is the radius, in feet? A. 3 B. 18 C. 1 D. 4
Cycle paths inc, makes bicycles,tricycles,and unicycles. last week they made 88 more bicycles than unicycles, and 5 times as many tricycles as unicycles. if they made 40 more bicycles than tricycles, how many unicycles did they make
Rewrite as a conditional statement.
2. The sprinkler was turned on this morning resulting in the grass getting wet.
Marge wants to build a sidewalk of uniform width around a rectangular swimming pool that is 80 feet long and 50 feet wide.she has 2000 square feet of concrete to create the sidewalk.what should be the width of the sidewalk
The hours of daylight,y, in Utica in days, x, from January 1, 2013 can be modeled by the equation y=3.06sin(0.017x-1.40) + 12.23. How many hours of daylight, to the nearest tenth,does this model predict for February 14, 2013?
(1) 9.4
(2) 10.4
(3)12.1
(4)12.2
Answer:
Option (4) 12.2
Step-by-step explanation:
Hours of daylight, y, in Utica in days, x, from January 1, 2013 can be modeled by the equation
y = 3.06 sin ( 0.017x - 1.40 ) + 12.23
We have to calculate the hours of daylight from the given equation for February 14, 2013.
From January 1, 2013 to February 14, 2013 number of days = 31 + 14 = 45 days.
Now we place x = 45 days in the equation
y = 3.06 sin (0.017 × 45 - 1.40) + 12.23
= 3.06 sin ( 0.765 - 1.40 ) + 12.23
= 3.06 sin ( - 0.635 ) + 12.23
= 3.06 ( - 0.0111) + 12.23
= -0.0339 + 12.23 = 12.196 = 12.20
Option (4) 12.2 is the correct answer.
The number of hours of daylight for the model for February 14 , 2013 is 12.2
Given data:
The function is represented as y=3.06sin(0.017x-1.40) + 12.23
To find the number of hours of daylight predicted by the model for February 14, 2013, substitute the corresponding value of x into the equation and evaluate it.
The total number of days , x = 31 days in January + 14 days in February
So, x = 45
Now, substitute x = 45 into the equation:
y = 3.06sin(0.017(45) - 1.40) + 12.23
Calculating the expression inside the sine function:
0.017(45) - 1.40 = -0.635
Substituting this value back into the equation:
y = 3.06sin(-0.635) + 12.23
The sine of -0.635 is approximately -0.593.
y = 3.06(-0.593) + 12.23
y ≈ 10.425
Rounding to the nearest tenth, the predicted number of hours of daylight for February 14, 2013, is 10.4.
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-(-(-)(-)(-10x))=-5 solve for x
The Mid-Atlantic Ridge is a spreading crack between crack between continental plates and it moves apart at 2.5 cm per year. New York is 5567 km from London. In 1,000,000 years, how many far apart will New York be from London.
Find the GCF of the following literal terms. m^7 n^4 p^3 and mn^12 p^5
m[]n[]p[]
Answer:
The GCF of following literal terms is [tex]m^1n^4p^3[/tex].
Step-by-step explanation:
The given literal terms are
[tex]m^7n^4p^3[/tex]
[tex]m^1n^{12}p^5[/tex]
The factored form of the given terms are
[tex]m^7n^4p^3=m\times m\times m\times m\times m\times m\times m\times n\times n\times n\times n\times p\times p\times p[/tex]
[tex]mn^{12}p^5=m\times n\times n\times n\times n\times n\times n\times n\times n\times n\times n\times n\times n\times p\times p\times p\times p\times p[/tex]
The common factors are m,n,n,n,n,p,p,p. So, the G.greatest common factors is
[tex]GCF=m\times n\times n\times n\times n\times p\times p\times p[/tex]
[tex]GCF=m^1n^4p^3[/tex]
Therefore the GCF of following literal terms is [tex]m^1n^4p^3[/tex].
PLEASE HELP! Two numbers have a sum of one and a product of -6 Use the quadratic equation -n squared plus n plus 6 equals 0 to determine the two numbers
A photographer is planning to enlarge a photograph by a scale factor of 1:5 . The original photograph has an area of 154 square inches.
What is the area of the new photograph?
_____in²
A photographer is planning to enlarge a photograph by a scale factor of 1:5 . The original photograph has an area of 154 square inches.
Solution:
The photograph is being enlarged by a factor 5.
So, each dimension of the photograph is enlarged by 5
So, area is enlarged by [tex] 5^{2} [/tex]
Or, Area is enlarged by a factor=5*5=25
So, the Area of enlarged photograph=[tex] 5^{2} [/tex] *Area of original photograph
Area of enlarged photograph=25*Area of original photograph
Area of enlarged photograph=25*154
On multiplying 25 by 154 we get 3850
Area of enlarged photograph=3850[tex] inches^{2} [/tex]
Answer:
Area of new photograph=3850[tex] in^{2} [/tex]
Quadrilateral ABCD is inscribed in this circle.
What is the measure of angle B?
Enter your answer in the box.
m∠B=
°
Answer:
∠B=157°
Step-by-step explanation:
It is given that Quadrilateral ABCD is inscribed in the circle.
Also, we know that if the Quadrilateral ABCD is inscribed in the circle, then the opposite angles of the quadrilateral are supplementary by the property of circles. Then,
∠B+∠D=180°
⇒[tex]x+6x+19=180[/tex]
⇒[tex]7x+19=180[/tex]
⇒[tex]7x=161[/tex]
⇒[tex]x=23^{{\circ}}[/tex]
Thus, the value of ∠B=6x+19=6(23)+19=138+19=157°.
What is the length of the base of a right triangle with an area of 15 m² and a height of 3 m?
Answer:
10 m
Step-by-step explanation:
I did the test