What is the first error he made in computing the standard deviation?



A.Yuri failed to find the difference between each data point and the mean.

B.Yuri divided by n instead of n -1.

C.Yuri did not subtract 9 - 14 correctly.

D.Yuri failed to square -2 correctly.

What Is The First Error He Made In Computing The Standard Deviation?A.Yuri Failed To Find The Difference

Answers

Answer 1
b.yuri divided by n instead of n-1
Answer 2

Answer:

Step-by-step explanation:

Given is a sample with 4 items as

12,9,14,21

Mean = average of 4 = 14

s is the square root of sample variance

Sample variance is the sum of squares divided by n-1

But Yuri divided by 4 = n instead of 3 = n-1

That is the only mistake he did and all other steps are right.


Related Questions

Use the three steps to solve the problem. Betty has 10 more dimes than quarters. If she has $3.45, how many coins does she have?

Answers

Step 1-------> set variables.
Let
x-----------> number of dimes
y-----------> number of quarters 

Step 2:  set the equation and solve for the variable
we know that
0.10 x+0.25 y=3.45---------------> 10x+25y=345   equation (1)
x=y+10  equation (2)
substituting 2 in 1
10[y+10]+25y=345----> 10y+100+25y=345
35y=345-100-----------> y=245/35=7
x=y+10--------> x=7+10=17

Step 3:  plug in the value of x and y from last step into the variables.

y=7--------> number of quarters coins
x=17-------> number of dimes coins

She has (7+17)=24 coins in total



If we assume the quarters are x, then the dimes are 10+x
Thus, 0.25x + 0.1(10+x) = 3.45
         = 0.25x +1 +0.1 x = 3.45
        = 0.35 x = 3.45 -1
         = 0.35x = 2.45
                   x = 7
Therefore, the quarters are 7, while the dimes were 17,
Thus a total of 24 coins

A cross-country travels 20 kilometers before she realizes that she has to cover at least 75 kilometers in order to qualify for the next race. If the racer travels at a rate of 10 kilometers per hour, how many whole hours will it take her to reach the 75-kilometer mark?

Answers

It will be 7 hour and 30 min
so find how much the racer needs to cover more she covered 20 and needs to cover 75 75-20=55 she needs to cover 55 more so 10 km per hour 10 times x hours=55 miles divide both sides by 10 x hours=5.5 since you want whole hours, we round up so she at least gets there 6 hour, I think

A right triangle has an area of 33 mm 2 2 and a height of 11 mm. How long is the base of the triangle? Enter your answer in the box. mm

Answers

Area: Base*Height
Area: 33/11
Area: 3
The answer is 3 millimeters

1000p for an answer pleaseeeeee

Answers

x=17.3
but the 3 has a line above. which means repeated 
17 1/3 is the correct answer

Which statement best describes Marcos equation

Answers

The answer would be D. It is true, because the cosine function has a period of 2[tex] \pi [/tex]

Cosine function has period of 2[tex] \pi [/tex] because the function value will be same for variable that 2[tex] \pi [/tex] appart.  In the problem, cos [tex]- \pi /2[/tex] and cos [tex] 3 \pi /2 [/tex] difference would be 4[tex] \pi [/tex], which is 2 * [tex] 2 \pi [/tex]. That means they both should have same value.

Meg constructed triangle POQ and then used a compass and straightedge to accurately construct line segment OS, as shown in the figure below:


Which could be the measures of angle POS and angle POQ?

Measure of angle POS is 25 degrees, measure of angle POQ is 40 degrees
Measure of angle POS is 25 degrees, measure of angle POQ is 30 degrees
Measure of angle POS is 20 degrees, measure of angle POQ is 40 degrees
Measure of angle POS is 20 degrees, measure of angle POQ is 30 degrees

Answers

In order to understand this question, one needs to understand the construction first. After creating POQ, Meg picks a radius r and makes a circle around O. There are 2 points where the circle meets the triangle. Then, she meets another radius and she makes a circle of radius s around each of the points on the triangle. The two circles cross at one point, as can be seen in the figure. Let's name the first two points A and B and let's name the last point S. We have that for the triangles OAS, OBS we have OA=OB=r, BS=AS=s and that OS is common to both. Thus by the S-S-S triangle equality theorem, the triangles are equal. Hence for the angles AOS=BOS, namely POS=QOS. Since POQ=POS+QOS, we have that POS has to be half of POQ. The only consistent choice is the third one, POS=20 degrees and POQ=40 degrees.

The correct answer is:

Measure of angle POS is 20 degrees, measure of angle POQ is 40 degrees

Explanation:

OS is an angle bisector of ∠POQ.  This means it splits ∠POQ into two congruent pieces.  

This tells us that ∠POS+∠SOQ = ∠POS+∠POS = ∠POQ.

If m∠POS = 20, this means that m∠POQ = 20+20 = 40°.

PLEASE HELP
8.02

1. Find the center, vertices, and foci of the ellipse with equation x squared divided by one hundred plus y squared divided by sixty four = 1.

A) Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-8, 0), (8, 0)
B) Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -8), (0, 8)
C) Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-6, 0), (6, 0)
D) Center: (0, 0); Vertices: (0, -10), (0, 10); Foci: (0, -6), (0, 6)

2. Find the center, vertices, and foci of the ellipse with equation 2x2 + 6y2 = 12.

A) Center: (0, 0); Vertices: point negative square root of six comma zero and point square root of six comma zero ; Foci: (-2, 0), (2, 0)
B) Center: (0, 0); Vertices: (0, -6), (0, 6); Foci: Ordered pair zero comma negative four square root two and ordered pair zero comma four square root two ;
C) Center: (0, 0); Vertices: point zero comma negative square root of six and point zero comma square root of six ; Foci: (0, -2), (0, 2)
D) Center: (0, 0); Vertices: (-6, 0), (6, 0); Foci: Ordered pair negative four square root two comma zero and ordered pair four square root two comma zero

3. Graph the ellipse with equation x squared divided by twenty five plus y squared divided by four = 1.

A) A vertical ellipse is shown on the coordinate plane centered at, five, two, with vertices at, five, seven, and five, negative three and minor axis endpoints at three, two, and seven, two.
B) A horizontal ellipse is shown on the coordinate plane centered at five, two, with vertices at zero, two, and ten, two and minor axis endpoints at five, four and five, zero.
C) A vertical ellipse is shown on the coordinate plane centered at the origin with vertices at zero, five and zero, negative five and minor axis endpoints at, negative two, zero and two, zero.
D) A horizontal ellipse is shown on the coordinate plane centered at the origin with vertices at, negative five, zero and, five, zero and minor axis endpoints at, zero, two and zero, negative two.

4. Find an equation in standard form for the ellipse with the vertical major axis of length 6 and minor axis of length 4.

A) x squared divided by two plus y squared divided by three = 1
B) x squared divided by nine plus y squared divided by four = 1
C) x squared divided by three plus y squared divided by two = 1
D) x squared divided by four plus y squared divided by nine = 1

5. An elliptical riding path is to be built on a rectangular piece of property, as shown below.
A vertical ellipse is shown centered on the coordinate plane, surrounded by a rectangle of equal length and width.

The rectangular piece of property measures 8 mi by 6 mi. Find an equation for the ellipse if the path is to touch the center of the property line on all 4 sides.

Answers

Hello,
Please, see the detailed solution in the attached files.
Thanks.

PLEASE HELP ASAP!!!!!!!!

Answers

Answer:

  A.  y = -2x + 4

Step-by-step explanation:

You are given the values of slope (m) and y-intercept (b). The slope-intercept form of the equation for the line is ...

  y = mx + b

Putting m=-2 and b=4 into this form, you get ...

  y = -2x + 4

Anybody have the answer to this?

Answers

we have a right triangle
one leg is 2.4 in
the other leg is 7.4/2=3.7 in (radius)
the hypotenuse is 
c^2=a^2+b^2
c^2=5.76+13.69=19.45
c=sqrt 19.45=4.41 in

Wendy took a trip from one city to another, a distance of 580 mi. she traveled part of the way by bus, which arrived at the train station just in time for wendy to complete her journey by train. the bus averaged 40 mi/h, and the train averaged 80 mi/h. the entire trip took 9 1 2 h. how long did wendy spend on the train?

Answers

If he traveled x mi by bus, then the time taken using bus is x/40 hours
and therefore, she took (580-x) mi by train, thus the time taken with train was (580-x)/80 hours.
Hence, x/40 +(580-x)/80 = 9.5 hours
             80(x/40) +80 (580-x)/80 =  (9.5)80
                = 2x + 580-x = 760
                              x= 760-580
                              x = 180
Thus the train covered a distance of  (580-x) =580-180 = 400
Hence, Wendy took 400/80 = 5 hours on the train

What is the solution to the following system?

3x + 10y -12z = 40
x - 5y = 0
x- 4z = 0

--------------------------------------------------------------------

A.) (8, 40, 32)

B.) (10, 2, 3)

C.) (20, 4, 5)

D.) (40, 8, 10)

Answers

Selection C is appropritate.

Answer: C.) (20, 4, 5)

Step-by-step explanation:

The given system is

[tex]3x + 10y-12z = 40.....................(1)\\x-5y =0..........................(2)\\x- 4z=0............................(3)[/tex]

From (2), we have

[tex]x=5y\\\Rightarrow\ y=\frac{x}{5}[/tex]

From (3)

[tex]x=4z\\\Rightarrow\ z=\frac{x}{4}[/tex]

Substitute the values of y and z in equation (1), we get

[tex]3x+10(\frac{x}{5})-12(\frac{x}{4})=40\\\\\Rightarrow\ 3x+2x-3x=40\\\\\Rightarrow\ 20x=40\\\\\Rightarrow\ x=5[/tex]

Then [tex]y=\frac{20}{5}=4[/tex]

and  [tex]z=\frac{20}{4}=5[/tex]

Hence, the solution of the given system is (20,4,5)

Jennifer is calculating her gpa. if she uses "=(a1+a2+a3+a4)/4", this is an example of which type of entry?

Answers

The first thing we should know in this case is the meaning of the following acronyms:
 (GPA) = Grade Point Average.
 Effectively in a program like excel she can use:
 GPA = (a1 + a2 + a3 + a4) / 4
 Where,
 ai = represents each of the notes (i: 1,2,3,4)
 However, this is also an example of the following type of entry:
 GPA = AVERAGE (a1: a4)
 Answer:
 Entry:
 Formulas: are references of cells, names of cells or ranges, functions or operators that result in a value from other existing values.

"there are 362 first-grade students in park elementary school. if there are 34 more girls than boys, how many girls are there"

Answers

There are 198 girls
you subtract 34 from 362 which is 328
you then divide 328 by 2 which is 164
next you add 34 to 164 which gives you 198 which is the number of girls

What is the domain of the graphed function?
A) y ≥ 4
B) x ≥ -2
C) y ≥ -2
D) x ≤ -2

Answers

The domain is all of the x values. In this graph, the x values start at -2 and go to infinity. Therefore, the answer is B) x greater or equal to negative 2

what is the constant of variation for the quadratic variation of x |2|3|4|5|6| fx |28|63|112|175|252|

Answers

f(x) = k*x^2
You can find k using only the first point.
28 = k*2^2
7 = k

The constant of variation is 7.

Describe a situation in which there would be a positive association between two variables.

Answers

There is a positive association between
.. number of miles driven
.. number of gallons of gas used
In a graph, it would be like 0, 5 then to 5, 10

Cary is 5 5 years older than dan. in 5 years the sum of their ages will be 81. find the age of each man now.

Answers

C = Cary, D = Dan
C - 55 = D
(C + 5) + (D + 5) = 81
C = D + 55
(D + 55 + 5) + (D + 5) = 81
(D + 60) + (D + 5) = 81
2D = 16
D = 8
C = 8 + 55 = 63

Cary is 63 years old, and Dan is 8 years old
Let's call x the age of Cary and y the age of Dan.

y = x - 55
x + 5 + y + 5 = 81

Then,

x + 5 + x - 55 + 5 = 81
2x - 45 = 81
2x = 81 + 45
2x = 126
x = 126/2 = 63

Now, let's find y.

y = 63 - 55 = 8.

Therefore Cary is 63 years old and Dan is 8 years old.

Hope this helps !

Photon

The area of a rectangular room is 120 square feet. The width is 10 feet. What is the length?

Answers

The length is 12 square feet. We know the area, and we know the width. The way to find the length is take the area, and divide it by the width. So 120 divided by 10. The answer to that is 12, so 12 square feet is your answer.
~Deceptiøn

The length of the rectangular room is 12 feet.

To find the length of a rectangular room when the area and width are known, you can use the formula:

Area = Length x Width

Given that the area is 120 square feet and the width is 10 feet,

we can substitute these values into the formula:

120 = Length x 10

Length = 120 / 10

Length = 12

Therefore, the length of the rectangular room is 12 feet.

Learn more about area here:

https://brainly.com/question/29183710

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The surface area of a sphere is found using the formula SA=4πr^2, where r is the radius. If the surface area of a sphere is 64π square feet, what is the radius, in feet? A. 3 B. 18 C. 1 D. 4

Answers

The answer should be d
64pi=4pir^2
cancel the pi
64=4r^2
16=r^2
r=4
[tex]SA = 4 \pi r^{2}[/tex]
[tex]64 \pi = 4 \pi r^{2}[/tex]
[tex]16= r^{2}[/tex]
[tex]r^{2}=16[/tex]
 [tex]r=4 [/tex] (Answer D)

Cycle paths inc, makes bicycles,tricycles,and unicycles. last week they made 88 more bicycles than unicycles, and 5 times as many tricycles as unicycles. if they made 40 more bicycles than tricycles, how many unicycles did they make

Answers

Let's name variables:
 x = bicycles
 y = tricycles
 z = unicycles
 We write the following system of equations:
 x = 88 + z
 y = 5z
 x = 40 + y
 We solve the equation system for z:
 1) x = 40 + y
 2) y = 5z
 3) x = 88 + z
 Substituting x and y in equation 1:
 88 + z = 40 + 5z
 We cleared z:
 4z = 88-40
 z = 48/4
 z = 12
 Answer:
 They did make 12 unicycles

Rewrite as a conditional statement.
2. The sprinkler was turned on this morning resulting in the grass getting wet.

Answers

if the grass is wet, then the sprinkler system was turned on this morning.

Marge wants to build a sidewalk of uniform width around a rectangular swimming pool that is 80 feet long and 50 feet wide.she has 2000 square feet of concrete to create the sidewalk.what should be the width of the sidewalk

Answers

For this case, the first thing we are going to do is rewrite the expression of the pool area again.
 We have then:
 (80 + 2W) (50 + 2W) - 80 (50) = 2,000
 Rewriting we have:
 4000 + 160W + 100W + 4W ^ 2 - 4000 = 2000
 4W ^ 2 + 260W - 2000 = 0
 W1 = 6.949334595148748
 W2 = -71.94933459514874 (ignore)
 round:
 W = 6.95
 Answer:
 the width of the sidewalk should be:
 W = 6.95 feet

The hours of daylight,y, in Utica in days, x, from January 1, 2013 can be modeled by the equation y=3.06sin(0.017x-1.40) + 12.23. How many hours of daylight, to the nearest tenth,does this model predict for February 14, 2013?

(1) 9.4
(2) 10.4
(3)12.1
(4)12.2

Answers

Answer:

Option (4) 12.2

Step-by-step explanation:

Hours of daylight, y, in Utica in days, x, from January 1, 2013 can be modeled by the equation

y = 3.06 sin ( 0.017x - 1.40 ) + 12.23

We have to calculate the hours of daylight from the given equation for February 14, 2013.

From January 1, 2013 to February 14, 2013 number of days = 31 + 14 = 45 days.

Now we place x = 45 days in the equation

y = 3.06 sin (0.017 × 45 - 1.40) + 12.23

= 3.06 sin ( 0.765 - 1.40 ) + 12.23

= 3.06 sin ( - 0.635 ) + 12.23

= 3.06 ( - 0.0111) + 12.23

= -0.0339 + 12.23 = 12.196 = 12.20

Option (4) 12.2 is the correct answer.

The number of hours of daylight for the model for February 14 , 2013 is 12.2

Given data:

The function is represented as y=3.06sin(0.017x-1.40) + 12.23

To find the number of hours of daylight predicted by the model for February 14, 2013, substitute the corresponding value of x into the equation and evaluate it.

The total number of days , x = 31 days in January + 14 days in February

So, x = 45

Now, substitute x = 45 into the equation:

y = 3.06sin(0.017(45) - 1.40) + 12.23

Calculating the expression inside the sine function:

0.017(45) - 1.40 = -0.635

Substituting this value back into the equation:

y = 3.06sin(-0.635) + 12.23

The sine of -0.635 is approximately -0.593.

y = 3.06(-0.593) + 12.23

y ≈ 10.425

Rounding to the nearest tenth, the predicted number of hours of daylight for February 14, 2013, is 10.4.

To learn more about function rule click :

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-(-(-)(-)(-10x))=-5 solve for x

Answers

-(-(-)(-)(-10x)) = -5

We need to cancel out the negatives, so we need to simplify this.

To make things a bit easier for you, we can begin by counting out how many negatives we have. After counting, you should have a negative number count of 5. However, one of the negatives is apart of (-10x) so we'll have 4 negatives and then an extra negative in with 10x.

Remember that "-" could also be looked at as "-1."

So, if we break this down into smaller parts and substitute "-" into "-1," then this'll look like this :

-1 × -1 × -1 × -1 × (-10x) = -5

Remember that a negative times a negative is always a positive.

So, since there are four negatives, then you just multiply it all together.

This results in 1 × (-10x) = -5

Simplify.

-10x = -5

Now, you simply divide both sides by -10.

-10x ÷ -10 = -5 ÷ -10

Simplify.

x = 1/2

~Hope I helped!~


The Mid-Atlantic Ridge is a spreading crack between crack between continental plates and it moves apart at 2.5 cm per year. New York is 5567 km from London. In 1,000,000 years, how many far apart will New York be from London.

Answers

In 1,000,000 years, if the Mid-Atlantic Ridge continues to crack at a constant rate, New York and London will be 5592 km away from each other. I found this out by using the unit rate 2.5 cm per year to find out that in 1 million years it would be 2,500,000 cm. There are 100,000 cm in a kilometer. Therefore 2,500,000 cm is equivalent to 25 km. Add the 25 km to 5567 km to get 5592 km as the distance between the two cities.

Find the GCF of the following literal terms. m^7 n^4 p^3 and mn^12 p^5

m[]n[]p[]

Answers

That would be m n^4 p^3

Answer:

The GCF of following literal terms is [tex]m^1n^4p^3[/tex].

Step-by-step explanation:

The given literal terms are

[tex]m^7n^4p^3[/tex]

[tex]m^1n^{12}p^5[/tex]

The factored form of the given terms are

[tex]m^7n^4p^3=m\times m\times m\times m\times m\times m\times m\times n\times n\times n\times n\times p\times p\times p[/tex]

[tex]mn^{12}p^5=m\times n\times n\times n\times n\times n\times n\times n\times n\times n\times n\times n\times n\times p\times p\times p\times p\times p[/tex]

The common factors are m,n,n,n,n,p,p,p. So, the G.greatest common factors is

[tex]GCF=m\times n\times n\times n\times n\times p\times p\times p[/tex]

[tex]GCF=m^1n^4p^3[/tex]

Therefore the GCF of following literal terms is [tex]m^1n^4p^3[/tex].

PLEASE HELP! Two numbers have a sum of one and a product of -6 Use the quadratic equation -n squared plus n plus 6 equals 0 to determine the two numbers

Answers

since it says two numbers have a sum of one and a product of -6
so let one be x and one be y
you need to find the factors of -6 which is 1 and 6, and 2 and 3 
the negative doesn't matter to which one.

only 3 and -2 add up to 1 and have a product of -6
the quadratic equation is ax² + bx + c
                                 -n² + n + 6 = 0
( n + 3 ) ( n - 2 ) = 0 

I hope this helps!

A photographer is planning to enlarge a photograph by a scale factor of 1:5 . The original photograph has an area of 154 square inches.

What is the area of the new photograph?

_____in²

Answers

Your answer should have been 3850 in^2 

1^2/5^2 = 1/25

1/25 = 154/x
1x= 154 (25)
1x/1= 3850/1
x= 3850

A photographer is planning to enlarge a photograph by a scale factor of 1:5 . The original photograph has an area of 154 square inches.

Solution:

The photograph is being enlarged by a factor 5.

So, each dimension of the photograph is enlarged by 5

So, area is enlarged by [tex] 5^{2} [/tex]

Or, Area is enlarged by a factor=5*5=25

So, the Area of enlarged photograph=[tex] 5^{2} [/tex] *Area of original photograph

Area of enlarged photograph=25*Area of original photograph

Area of enlarged photograph=25*154

On multiplying 25 by 154 we get 3850

Area of enlarged photograph=3850[tex] inches^{2} [/tex]

Answer:

Area of new photograph=3850[tex] in^{2} [/tex]

Quadrilateral ABCD ​ is inscribed in this circle.



What is the measure of angle B?

Enter your answer in the box.

m∠B=
°

Answers

(6x+19)° + x° = 180°
7x° = 180°-19°
7x° = 161°
x = 23°

m∠B = 6(23) + 19
= 157°

Answer:

∠B=157°

Step-by-step explanation:

It is given that Quadrilateral ABCD ​is inscribed in the circle.

Also, we know that if the Quadrilateral ABCD ​ is inscribed in the circle, then the opposite angles of the quadrilateral are supplementary by the property of circles. Then,

∠B+∠D=180°

⇒[tex]x+6x+19=180[/tex]

⇒[tex]7x+19=180[/tex]

⇒[tex]7x=161[/tex]

⇒[tex]x=23^{{\circ}}[/tex]

Thus, the value of ∠B=6x+19=6(23)+19=138+19=157°.

What is the length of the base of a right triangle with an area of 15 m² and a height of 3 m?

Answers

You know the formula to find the area of a triangle is B*h/2. If the area is [tex] 15m^{2} [/tex]. Multiply 15 by 2...........which gives you 30 divide 30 by 3 which gives you 10.

Answer: 10

Answer:

10 m

Step-by-step explanation:

I did the test

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