Answers
we know that
An exterior angle is equal to the sum of the two non adjacent angles
so
In this problem
[tex](4n+6)\°=2n\°+60\°[/tex]
Solve for n
Group terms that contain the same variable, and move the constant to the opposite side of the equation
[tex](4n-2n)\°=(60-6)\°[/tex]
Combine like terms
[tex]2n\°=54\°[/tex]
[tex]n=27\°[/tex]
Find the measure of angle ABD
∠ABD=[tex](4n+6)\°[/tex]
Substitute the value of n
∠ABD=[tex](4*27+6)\°=114\°[/tex]
therefore
the answer is the option
[tex]114\°[/tex]
Answer:
the answer is 114
Step-by-step explanation:
hope i helped all of you guys and girls
Related Questions
Which of the following functions best represents the graph?
A. f(x) = x3 + x2 − 4x − 4
B. f(x) = x3 + x2 − x − 1
C. f(x) = x3 + 3x2 − 4x − 12
D. f(x) = x3 + 2x2 − 2x − 1
Answers
Answer:
B. f(x)=x³+x²-x-1
Step-by-step explanation:
The value of the graph f(x) shows that at x=1 and x=-1 must yield f(x)=0
which is true in case B.
A. f(1)=1+1-4-4= -6≠0
C. f(1)= 1+3-4-12=-12≠0
D. f(-1)= -1+2+2-1= 2≠0
Hence, option B is correct
i.e. f(x)= x³+x²-x-1
A 45 degree sector in a circle has an area of 13.75pi cm^2, what is the area of the circle? Enter your answer as a decimal.
Answers
[tex] \frac{360}{45} = 8 [/tex] sectors in total
Area of the circle = 8 * 13.75 = 110.0 cm^2
If p is a true statement and q is false then p V q is true
Answers
Answer:
Step-by-step explanation:
True
HELP!!!!! 8 POINTS!!!!!! Rachel decided to have bouncy balls as a party favor. She determines that her ratio of bouncy balls to guests is 9:3. Explain how to find the number of balls needed for 30 guests.
Answers
a(1)= -2
a(n)=a(n-1)-5
whats the 4th term in the sequence?
Answers
[tex]A_1=-2\\ A_2=A_1-5=-2-5=-7\\ A_3=A_1-2*5=-2-2*5=-12\\ A_4=A_1-3*5=-2-3*5=-17\\ [/tex]
Answer:
The fourth term in the sequence is -17
Step-by-step explanation:
To find the 4th term of the sequence, we will simply follow the steps below;
a(1) = -2
a(n) = a(n-1)-5
We will find the value of the sequence when n = 1, n= 2 n =3 n=4
The first one has been done for us, so we have the first term to be a(1) = -2
The next thing to do, is to find the second term, ie. when n=2
a(n) =a(n-1)-5
a(2) =a(2-1)-5
=a(1) - 5
but a(1) = -2
a(2) =a(1) - 5
=-2-5
=-7
a(2) = -7
next is to find the third term, ie. when n=3
a(n) =a(n-1)-5
a(3) =a(3-1)-5
=a(2) - 5
but a(2) = -7
a(3) =a(2) - 5
=-7-5
=-12
a(3) = -12
next is to find the fourth term, ie. when n=4
a(n) =a(n-1)-5
a(4) =a(4-1)-5
=a(3) - 5
but a(3) = -12
a(4) =a(3) - 5
=-12-5
=-17
a(4) = -17
Therefore, the fourth term in the sequence is -17
Two cities are 124 miles apart from each other. The cities are 4cm on a map, what is the Scale factor?
Answers
Distance on map = 4 cm
Scale factor = 4 cm : 124 miles
Divide through by 4
Scale factor = 4 cm/4 : 124 miles /4
= 1 cm : 31 miles
The scale factor is 1 cm : 31 miles
There are many penguins on a hill. 53 penguins waddled off the hill. Now 21 penguins remain on the hill. How many penguins were on the hill to start?
74 penguins
72 penguins
32 penguins
34 penguins
Answers
Answer:
74 Penguins
Step-by-step explanation:
1. 53+21
2. =74
Penguins are my favorite animal. What's yours?
Answer:
There were originally 74 penguins on the hill.
Step 1: Determine the Values we NeedFor starters, we need to define the variable that we will use to solve this equation. I will use x.
We know that our original amount is x, and we need to find it to solve the problem.
The Factsx stands for the original amount of penguins on the hill.53 penguins waddle off of the hill.21 penguins remain after the 53 penguins waddle off of the hill.To find x, we will set up an algebraic equation that allows us to find the value easily.
Step 2: Set up the Algebraic EquationNow, we will need to set up the equation with the facts we have determined.
We know that we need to set our equation equal to x to find our total. To do this, we know that our initial amount is x, and we remove 53 penguins from this total since they waddle off of the hill.
Since we "remove" from the total, this means that we will subtract 53 penguins from x, our initial amount. We are left with the 21 penguins that do not leave the hill, or otherwise, remain on the hill.
[tex]x - 53 = 21[/tex]
Step 3: Rearrange and Solve the EquationFinally, we are ready to solve the equation to find our initial amount of penguins.
To solve this equation, we must combine our like terms.
Because our numbers (constants) do not have any letters (variables) attached to them, we will combine them.
The main goal of an algebraic equation is to get the variable (in this case, x) by itself. To do this, we can perform reverse operations to get the constants together.
You'll notice that 21 does not have a sign associated with it, but 53 does, and it is a subtraction symbol.
The reverse operation of subtraction is addition. Therefore, to combine the two values, we can add both 53 and 21 to each other to find x.
[tex]x = 53 + 21[/tex]
Using any method of choice, add the two values together.
[tex]x = 53 + 21 = 74[/tex]
Then, to simplify, remove the operation and only leave the sum of the operation.
[tex]\boxed{x = 74}[/tex]
Therefore, the initial number of penguins—the number of penguins on the hill to start—is equivalent to 74 penguins.
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Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, one chip has the number 3, and the other chip has the number 5. Miguel must choose two chips, and if both chips have the same number, he wins $2. If the two chips he chooses have different numbers, he loses $1 (–$1). Let X = the amount of money Miguel will receive or owe. Fill out the missing values in the table. (Hint: The total possible outcomes are six because there are four chips and you are choosing two of them.) Xi 2 –1 P(xi) What is Miguel’s expected value from playing the game? answer= $2 Based on the expected value in the previous step, how much money should Miguel expect to win or lose each time he plays? answer= $2 What value should be assigned to choosing two chips with the number 1 to make the game fair? Explain your answer using a complete sentence and/or an equation. A game at the fair involves a wheel with seven sectors. Two of the sectors are red, two of the sectors are purple, two of the sectors are yellow, and one sector is blue. Landing on the blue sector will give 3 points, landing on a yellow sector will give 1 point, landing on a purple sector will give 0 points, and landing on a red sector will give –1 point. Let X = the points you have after one spin. Fill out the missing values in the table. Xi P(xi) If you take one spin, what is your expected value? What changes could you make to values assigned to outcomes to make the game fair? Prove that the game would be fair using expected values. The point guard of a basketball team has to make a decision about whether or not to shoot a three-point attempt or pass the ball to another player who will shoot a two-point shot. The point guard makes three-point shots 30 percent of the time, while his teammate makes the two-point shot 48 percent of the time. Xi 3 0 P(xi) 0.30 0.70 Xi 2 0 P(xi) 0.48 0.52 What is the expected value for each choice? Should he pass the ball or take the shot himself? Explain. Claire is considering investing in a new business. In the first year, there is a probability of 0.2 that the new business will lose $10,000, a probability of 0.4 that the new business will break even ($0 loss or gain), a probability of 0.3 that the new business will make $5,000 in profits, and a probability of 0.1 that the new business will make $8,000 in profits. Claire should invest in the company if she makes a profit. Should she invest? Explain using expected values. If Claire’s initial investment is $1,200 and the expected value for the new business stays constant, how many years will it take for her to earn back her initial investment?
Answers
2) We can calculate the expected value of the game with the following: E=[tex] \frac{1}{6}*2- \frac{5}{6} *1[/tex]. In general, the formula is [tex]E= \sum{p*V}[/tex] where E is the expected value, p the probability of each event and V the value of each event. This gives a result of E=2/6-5/6=3/6=0.5$ Hence, Miguel loses half a dollar ever y time he plays.
3) We can adjust the value v of the winning event and since we want to have a fair game, the expecation at the end must be 0 (he must neither win or lose on average). Thus, we need to solve the equation for v:
0=[tex] \frac{1}{6}v -\frac{5}{6} =0 [/tex]. Multiplying by 6 both parts, we get v-5=0 or that v=5$. Hence, we must give 5$ if 1-1 happens, not 2.
4) So, we have that the probability that you get a red or purple or yellow sector is 2/7. We have that the probability for the blue sector is only 1/7 since there are 7 vectors and only one is blue. Similarly, the 2nd row of the table needs to be filled with the product of probability and expectations. Hence, for the red sector we have 2/7*(-1)=-2/7, for the yellow sector we have 2/7*1=2/7, for the purple sector it is 2/7*0=0, for the blue sector 1/7*3=3/7. The average payoff is given by adding all these, hence it is 3/7.
5) We can approach the problem just like above and set up an equation the value of one sector as an unknown. But here, we can be smarter and notice that the average outcome is equal to the average outcome of the blue sector. Hence, we can get a fair game if we make the value of the blue sector 0. If this is the case, the sum of the other sectors is 0 too (-2/7+0+2/7) and the expected value is also zero.
6) We want to maximize the points that he is getting. If he shoots three points, he will get 3 points with a probability of 0.30. Hence the average payoff is 0.30*3=0.90. If he passes to his teammate, he will shoot for 2 points, with a success rate of 0.48. Hence, the average payoff is 0.48*2=0.96. We see that he should pass to his player since 0.06 more points are scored on average.
7) Let us use the expections formula we mentioned in 1. Substituting the possibilities and the values for all 4 events (each event is the different profit of the business at the end of the year).
E=0.2*(-10000)+0.4*0+0.3*5000+0.1*8000=-2000+0+1500+800=300$
This is the average payoff of the firm per year.
8) The firm goes even when the total profits equal the investment. Suppose we have that the firm has x years in business. Then x*300=1200 must be satisfied, since the investment is 1200$ and the payoff per year is 300$. We get that x=4. Hence, Claire will get her investment back in 4 years.
Answer:
To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.
The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)
We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.
Pleasee hurryyyy
Asap
Correct as will get brainliest
Answers
So: (1,27) and (5, -213):
Using rate of change formula:
-213 - 27 = -240
5 - 1 = 4
-240/4 = -60, so it works.
Given the whole number 3,257,098, in what place value is the 2? Ten thousands Millions Thousands Hundred thousands
Answers
----------
The answer is Hundred thousands. Ten thousands would be 5, millions would be 3, and thousands would be 7.
----------
Hope this helps and have a great day! :)
Final answer:
In the number 3,257,098, the digit 2 is in the hundred thousands place, which is the sixth position from the right or the second position from the left.
Explanation:
In the number 3,257,098, the digit 2 is in the hundred thousands place. When examining place values, we count the positions of the digits from right to left, starting with the ones position immediately to the left of the decimal point (imaginary for whole numbers). The digit to the immediate left is in the tens place, followed by hundreds, thousands, ten thousands, and so on. In this case:
9 is in the ones place,8 is in the tens place,0 is in the hundreds place,7 is in the thousands place,5 is in the ten thousands place,2 is in the hundred thousands place,3 is in the millions place.What is the sum of the first eight terms of the series?
(−600)+(−300)+(−150)+(−75)+(−37.5)+...
Round the answer to two decimal places.
−1200.50
−1195.31
−1190.63
−1181.25
Answers
7 cakes cost £5.60 , what would be the cost of:
10 cakes
5 cakes
12 cakes
Answers
so 10 cake costs 10×0.8=£8
5cake costs 5×0.8=£4
12 cake costs 12×0.8=£9.6
10 cakes: £0.8×10=£8
5 cakes: £0.8×5=£4
12 cakes: £0.8 ×12=£9.6
Tamara says that raising the number i to any integer power results in either -1 or 1 as the result, since i^2 = -1. Do you agreed or disagree with Tamera? Explain
Answers
Tamara's claim that raising the complex number i to any integer power results in either -1 or 1 is incorrect. The powers of i follow a cyclic pattern which includes i, -1, -i, and 1.
Explanation:I must disagree with Tamara's statement that raising the complex number i to any integer power results in either -1 or 1. The powers of i actually follow a recurring pattern: i^1 = i, i^2 = -1, i^3 = -i, i^4 = 1, and then the pattern repeats.
For i to the power of 1, the result is just i itself.For i to the power of 2 (i^2), the result is indeed -1.For i to the power of 3 (i^3), the result is -i.For i to the power of 4 (i^4), the result is back to positive 1.So, while -1 and 1 are indeed in the sequence of results, they're not the only possibilities. Specifically, -i and i are also possible results of raising i to an integer power.
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The firing of a Revolutionary War cannon is used to open the local Fourth of July festivities. The muzzle of the cannon barrel is 6 feet above ground level. The height of the cannon ball being fired from the Revolutionary War cannon as a function of elapsed time is modeled by the function h(t) = –16t2 + 75t + 6, where h(t) is the height of the cannon ball in feet, and t is the elapsed time since firing in seconds. Determine at approximately what elapsed time(s) the cannon ball will be at a height of 55 feet.
Answers
[tex]-16t^2 + 75t + 6=55\\-16t^2+75t-49=0. \text{ Computing the discriminant:}\\75^2-4(-16)(-49)=2489.\text{ So by quadratic formula we get the sol:}\\\dfrac{-75-\sqrt{2489}}{-32}=3.9\text{ seconds.}[/tex]
What is the sum of 2 numbers is 100 and their difference is 6?
Answers
x -y = 6
Adding these equations gives
2x = 106
x = 53
y = 53 -6 = 47
The numbers are 47 and 53.
The probability that a bakery has demand for 2 3 4 or 5 birthday cakes on any given day are 0.32, 0.24, 0.25 and 0.19 respectively. construct a probability distribution for this data
Answers
On the horizontal axis, put your 4 different categories of 2, 3, 4, or 5.
On the vertical axis, label it by the percents: 0.10, 0.20, 0.30, 0.40
Then, make a bar at the correct height for each category.
What is the length of JK, to the nearest tenth of a millimeter?
Answers
3 = side c
angle B = 62 degrees
JK is side b
Use the Law of Cosines to find the length of side b.
b^2 = a^2 + c^2 − 2ac cos(B)
b^2 = (5^2 + 3^2) − ( 2 x 5 x 3) cos(62°)
b^2 = (25 + 9) − 30 x 0.469
b^2 = 34 - 30 x 0.469
b^2 = 34 - 14.084
b^2 = 19.916
b = √19.916
b = 4.463
Rounded to the nearest tenth is 4.5 mm.
Hope this helps!
The length of JK to the nearest tenth is; 4.5 mm
What is the Length of a side of the triangle?From the given triangle, we see the following parameters;
JL = 3 mm
KL = 5 mm
angle JLK = 62 °
Use the Law of Cosines, we can find the length of JK as;
|JK| = √(3² + 5² − 2(3 * 5) cos62°)
|JK| = √(34 - 14.084)
|JK| = 19.916
|JK| = √19.916
|JK| = 4.463
Approximating to the nearest tenth; JK = 4.5 mm
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i need to know how to make the equations
Answers
https://brainly.com/question/9016540
find all the zeros for each function.
p(x)=2x^3-3x^2+3x-2
*show work*
Answers
A graph of p(x) shows it has one real zero, at x=1. Dividing that out (and dividing out the scale factor of 2) reveals the remaining factor to be
.. (x -1/4)^2 +15/16
When we set this to zero, we have
.. (x -1/4)^2 +15/16 = 0
.. (x -1/4)^2 = -15/16
.. x -1/4 = i√(15/16)
and the remaining roots are
.. x = 1/4 ±i√(15/16)
.. x = (1 ±i√15)/4
The zeros are x = 1, x = (1 ±i√15)/4.
_____
You could use synthetic or long division to find
.. p(x)/(x -1) = 2x^2 -x +2
and then use any of several methods to determine the zeros of this are
.. x = (1 ±i√15)/4
can someone help me find the y-intercept and explain how you got that answer?
Answers
recall point slope form of a line is
[tex]y - y1 = m(x - x1)[/tex]
we plug in a point (6,0) and a slope from our line and get
[tex] y - 0 = - 4(x - 6)[/tex]
simplify
[tex]y = - 4x + 24[/tex]
FINAL ANSWER
[tex]y \: int = 24[/tex]
What is the measure of angle x? Enter your answer in the box. x = º Three intersecting lines. Three of the six angles formed by the intersecting lines are labeled. Every other angle is labeled. Going clockwise, they are labeled 56 degrees, x, and 41 degrees.
Answers
83 i am quite certain hope this helps (why did echo delete my answer the first time could of gave me a reason why because that was rude!)
im pretty sure it is 83
hope this help you guys
A principal of $400 is invested in an account at 6% per year compounded annually. What is the total amount of money in the account after 5 years? A. $526.00 B. $531.37 C. $535.29 D. $520.00
Answers
[tex]e = b \times (1 + \frac{i}{100} ) {}^{n} [/tex]
In this formula:
e represents the outcome
b represents the money at the beginning
i represents the interest rate
n represents the number of years.
Filling in this formula, we get:
[tex]e = 400 \times (1 + \frac{6}{100}) {}^{5} [/tex]
[tex]e = 400 \times 1.06 {}^{5} [/tex]
[tex]e = 535.29[/tex]
Therefore the answer is C. $535.29
The total amount of money in the account after 5 years is $535.29.
To calculate the total amount of money in the account after 5 years, we can use the compound interest formula: [tex]A = P{(1 + r/n)}^{(nt)[/tex], where A is the total amount, P is the principal, r is the annual interest rate, n is the number of times compounded per year, and t is the number of years.
Given that the principal is $400, the annual interest rate is 6%, and the compounding is done annually, we have:
A = 400(1 + 0.06/1)^(1*5) = 400(1.06)^5 = 400 * 1.338225 = $535.29
Therefore, the total amount of money in the account after 5 years is $535.29.
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Brian deposited $4000 into an account with 5.4% interest, compounded monthly. Assuming that no withdrawals are made, how much will he have in the account after 6 years?
Answers
FV=p(1+r/100n)^nt
where:
FV=future value
p=principle
r=rate
n=terms
t=time
thus substituting our values in the formula we get:
FV=4000(1+5.4/1200)^(6×12)
FV=$5,526.57
Answer: $5,526.57
Factor the polynomial. 6x2 - 7x - 3 A) (6x - 1)(x + 3) B) (6x + 3)(x - 1) C) (2x - 3)(3x + 1) D) (3x - 3)(2x + 1)
Answers
= (3x + 1)(2x - 3)
answer
C) (2x - 3)(3x + 1)
hope it helps
Find the missing measure for a right circular cone given the following information. Find L.A. if r = 6 and h = 8 48 60 96
Answers
Final answer:
The Lateral Area (L.A.) of a right circular cone with a base radius of 6 and a height of 8 is 60π square units, calculated by finding the slant height using the Pythagorean theorem and then applying the formula for L.A.
Explanation:
The student is asked to find the Lateral Area (L.A.) of a right circular cone given the base radius (r) is 6 and the height (h) is 8. First, we need to find the slant height of the cone, which can be done using the Pythagorean theorem in a right triangle where one leg is the height of the cone, the other leg is the radius of the base, and the hypotenuse is the slant height (l). The formula is l = [tex]\sqrt{(r^2 + h^2)[/tex]. After calculating l, we use the formula for the Lateral Area: L.A. = π r l.
Calculating the slant height: l = [tex]\sqrt{(6^2 + 8^2)}[/tex] = [tex]\sqrt{(36 + 64)[/tex]= [tex]\sqrt{100[/tex]= 10.
Now, we calculate the Lateral Area: L.A. = π * 6 * 10 = 60π. Hence, the Lateral Area of the cone is 60π square units.
Which ordered pair (a, b) is a solution to the given system?
Answers
(3,1) means that a = 3 and b = 1
Plug in a = 3 and b = 1 into the first equation
2a - 5b = 1
2*3 - 5*1 = 1.... replace 'a' with 3, replace b with 1
6 - 5 = 1
1 = 1
we get a true equation, so we have confirmed the first equation
Do the same for the second equation
3a+5b = 14
3*3+5*1 = 14 .... replace 'a' with 3, replace b with 1
9+5 = 14
14 = 14
we get a true equation, so the second equation has been confirmed
Both equations are true when (a,b) = (3,1). So the answer (3,1) has been confirmed fully
Can someone check my answers?
1. Simplify the sum or difference.
sqrt 5 + 6 sqrt 5
A) 6 sqrt 5
B) 30
C) 6 sqrt 10
D) 7 sqrt 5
2. Simplify the sum or difference.
4 sqrt 2 - 7 sqrt 2
A) negative sqrt 6
B) -3 sqrt 2
C) -11 sqrt 2
D) 11 sqrt 2
3. Simplify the sum or difference.
3 sqrt 7 - sqrt 63
A) -2 sqrt 7
B) -6 sqrt 7
C) -4 sqrt 3
D) 0
4. Simplify the sum or difference.
-6 sqrt 10 + 5 sqrt 90
A) 9 sqrt 10
B) -9 sqrt 10
C) -39 sqrt 10
D) -10
5. Simplify the product.
sqrt 6 (sqrt 2 + sqrt 3)
A) sqrt 8 + 3
B) sqrt 30
C) 2 sqrt 3 + 3 sqrt 2
D) 4 sqrt 2 + 3
Answers
2. 4sqrt2 - 7sqrt2 = (4-7)sqrt5 = -3sqrt2 (answer is B)
3. 3sqrt7 - sqrt63 = 3sqrt7 - sqrt7 * sqrt9 = 3sqrt7 - 3sqrt7 = 0 (answer is D)
4. -6sqrt10 + 5sqrt90 = -6sqrt10 + 5*(sqrt10 * sqrt9) = -6sqrt10 + 5*(3sqrt10)
= -6sqrt10 + 15sqrt10 = 9sqrt10 (answer is A)
5. sqrt6*(sqrt 2 + sqrt 3) = sqrt12 + sqrt18 = 2sqrt3 + 3sqrt2 (answer is D)
1 - D
2 - B
3 - D
4 - A
5 - C
6 - A
7 - D
8 - B
9 - B
10 - C
i just took the "Operations with Radical Expressions practice" for WA connexus, these answers are 100 percent correct
A group of art students are painting a mural on a wall. The rectangular dimensions of (6x+7) by (8x+5) and they are planning the mural to be (x+4) by (2x+5). What is the area of the remaining wall after the mural has been painted?
Answers
Answer:
The area of remaining wall after the mural has been painted is [tex]46x^2+73x+15[/tex] square units.
Step-by-step explanation:
If the dimensions of a rectangle are l and w, then area of rectangle is
[tex]A=l\times w[/tex]
The dimensions of wall are (6x+7) and (8x+5). So, the area of wall is
[tex]A_1=(6x+7)\times (8x+5)[/tex]
[tex]A_1=6x(8x+5)+7(8x+5)[/tex]
[tex]A_1=48x^2+30x+56x+35[/tex]
[tex]A_1=48x^2+86x+35[/tex]
The dimensions of mural are (x+4) and (2x+5). So, the area of mural is
[tex]A_2=(x+4)\times (2x+5)[/tex]
[tex]A_2=x(2x+5)+4(2x+5)[/tex]
[tex]A_2=2x^2+5x+8x+20[/tex]
[tex]A_2=2x^2+13x+20[/tex]
The area of remaining wall after the mural has been painted is
[tex]A=A_1-A_2[/tex]
[tex]A=48x^2+86x+35-(2x^2+13x+20)[/tex]
[tex]A=48x^2+86x+35-2x^2-13x-20[/tex]
[tex]A=46x^2+73x+15[/tex]
Therefore area of remaining wall after the mural has been painted is [tex]46x^2+73x+15[/tex] square units.
Answer:
46x^2 + 73x + 15
Step-by-step explanation:
Quick question!
Which investment vehicles historically provide the lowest annual rates of return?
A)Government bonds and U.S. Treasury bills
B)Large company stocks and government bonds
C)Small company stocks and large company stocks
D) U.S. Treasury bills and small company stocks
Answers
C) Small company stocks and large company stocks
Note: Small company stocks generally have a higher rate of return than large company stocks. Small company stocks are a riskier investment because they are more volatile. Stock investments in general are riskier investments than treasury bills or bonds. In general, the possible rate of return increases as the risk of the investment increases.
What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be defined if you multiplied it by 2? Would it be defined if you subtracted some real number from it? Would it be defined if you squared it? Would it be defined if you cubed it?
Answers
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
Final answer:
In the complex number system, types of numbers that are undefined under a radical sign in the real number system, such as negative real numbers, become defined. For example, the square root of -1 is i, an imaginary unit. This allows operations like multiplication, subtraction, squaring, and cubing on complex numbers to be defined, illustrating the comprehensive nature of the complex number system.
Explanation:
The types of numbers that are undefined under a radical sign (specifically the square root) are negative real numbers in the context of the real number system. However, when we introduce the concept of complex numbers, every number, including negative ones, can have a defined square root. For example, the square root of -1 is defined as i, which is an imaginary unit.
When you handle the expression √-1 (which is i) in various operations:
If multiplied by 2, the result is still defined as 2i, which is a complex number.If a real number is subtracted from it, such as √-1 - 3, this is also defined and results in i - 3, another complex number.If squared (√-1)^2, it simplifies to -1, which is a defined real number.If cubed (√-1)^3, it results in -i, still defined within the complex number system.This illustrates that with the incorporation of complex numbers, operations on what would be undefined values in the real number system become fully defined. Additionally, the complex number system ensures that every polynomial equation has a root, fulfilling the Fundamental Theorem of Algebra. Complex numbers are a critical development in mathematics, allowing for the full spectrum of polynomials to be solvable and expanding our capability to model and solve a wide array of problems.