What is the mechanical advantage of a hockey stick that is gripped at point D and hits the puck at point A?
Answers
Effort distance = D - Fulcrum = 0.5 m
Resistance distance = A - Fulcrum = 2.0 m
Then,
Mechanical advantage = 0.5/2 = 0.25
Hockey stick is an example of third class where mechanical advantage is less than one as the speed of the end of point A is critical.
Related Questions
An ion is created when __________ are added or removed.
Answers
What is the composition of Level C in a soil profile
A. Topsoil mixed with inorganic material.
B. Clay and slit mixed with sand
C. Decayed organic material.
D. Weathered rock fragments
Answers
The correct choice is
D. Weathered rock fragments
During most of a cell’s life cycle, DNA is found in a mass of loose strands called?
Answers
How is the ideal mechanical advantage of a wheel and axle calculated?
Answers
Ideal Mechanical Advantage of wheel and axle is calculated by
IMA = Wheel Radius / Axle Radius
By virtue, the higher the computed IMA the lower the force needed to be exerted, this is the purpose for using machine, lower input force but larger output. (The smalled the axle radius compared to the wheel radius is the better setup.)
Divide the radius of the wheel by the radius of the axle
Why does increasing the heat under a pan of boiling water not decrease the cooking time for hard-boiled eggs? (Select all that apply.)
increasing the heat under the pan will not raise the water temperature
increasing the heat under the pan will raise the temperature, but eggs are not affected by this
increasing the heat under the pan will only evaporate water faster increasing the heat under the pan will raise the pan temperature, but not affect the eggs increasing the heat under the pan will increase the boiling point of water and therefore not affect the eggs
Answers
water boils at 212F and stays at this temp until all the liquid water changes to vapor/gas phase.
Answer:
increasing the heat under the pan will not raise the water temperature
increasing the heat under the pan will only evaporate water faster
Explanation:
i got this question too, these are the right answers
Measuring the Orbital Speeds of Planets
Introduction
A Boeing 747 can fly 624 miles per hour. That’s pretty fast! Right now, Earth and other objects in the
solar system are orbiting the Sun, but how fast are these objects moving? In this assignment, you will
calculate the orbital speeds of objects in our solar system.
Part A: Planetary Periods
In the 1600s, Johannes Kepler discovered three laws that govern the motion of objects around the sun.
Kepler’s first law explains that objects travel in an elliptical, or oval-shaped, path around the sun.
Kepler’s second law explains that an object travels faster in its orbit when it is closer to the Sun and
slower in its orbit when it is farther away. In this activity, you will investigate Kepler’s third law: the
relationship between an object’s distance from the sun and the time it takes the object to complete an
orbit around the sun.
Access the Gizmo from within today's lesson. The exploration guide found within this simulation will
help you work through the Gizmo. Click on the Lesson Materials link, which appears on the top left
corner of the screen once you enter the simulation, to access the student exploration sheet. Use it as
you work through Activity C and answer all parts.
Part B: Calculating Orbital Speed
Every object moves at a different average speed in its orbit around the Sun. In this activity, you will use
data collected from Part A to calculate the average orbital speeds of each planet and of Pluto.
1. Recall that the path an object takes around the Sun is an ellipse, and not a circle. However, to
approximate the circumference, or length, of each orbit, you will treat the orbits as circles. Go
back to your notes in your student exploration sheet from Part A. Using the mean orbital radius
(R) that you recorded, calculate the circumference of each planet’s orbit and record it in the
table below. Use the following formula to calculate the circumference:
Circumference 2 = π r
2. Using the periods you recorded in your student exploration sheet and the circumference of orbit
that you just calculated, calculate the average orbital speed of each planet and record it in the
table below. Use the following formula to calculate speed:
Distance Circumference Average Orbital Speed Time Period = =
The units of your answer will be in AU/year.
3. To give you a better perspective of how fast these orbital speeds really are, convert the orbital
speeds you just calculated from AU/year to miles/hour. 1 AU/year = 10,604 miles/hour. Record
your answers in the table below.
Table
Object
Mean
orbital
radius (AU)
(copy from
#6 in part A)
Circumference of
Orbit (AU)
Period
(Earth
Years)
(copy
from #6
in part
A)
Orbital Speed
(AU/year)
Orbital Speed
(miles/hour)
Mercury
Venus
Earth
Mars
Jupiter
Saturn
Uranus
Neptune
Pluto
Drawing Conclusions
4. Which planet takes the longest amount of time to travel once around its orbit? Which planet
takes the shortest amount of time?
5. How does an increase in orbital radius affect average orbital speed?
Extension
perihelion
In astronomy, the term refers to the point in the orbit of an asteroid, comet, or planet at
which it is closest to the sun. Aphelion refers to the point at which the object is furthest away from the
sun. Research facts about the dwarf planet Ceres. Calculate the average orbital speed of Ceres in
miles/hour when it is closest to the sun and when it is farthest away.
Answers
Kepler's third law allows finding the answers for the orbital speed of the planets are:
The speed decreases as we move away from the Sun, the values are in the third column of the table. The fastest planet is Mercury and the slowest planet is Pluto.
Kepler measured and analyzed the astronomical data of him and his tutor Brake, finding mathematical relationships that describe the movement of the planet, they are called Kepler's laws
1. The orbits are ellipses
2. A vector from the sun to the planet travels equal areas in equal times
3. A relationship between the period and the semi-major axis of the orbit.
Kepler's third law is an application of Newton's second law to the motion of the planets around the sun.
Newton's second law establishes a relationship between force and the product of mass and acceleration of the object; in this case the force is the gravitational attractive force
F = m a
F = [tex]G \frac{M m}{r^2}[/tex]
Wher M y m are sum and planet mass, r is the distance ang G constnate universal gravitation
They indicate that we consider the orbits as circular, in this case the acceleration is centripetal
a = [tex]\frac{v^2}{r}[/tex]
Let's substitute
[tex]G \frac{M m}{r^2} = m \frac{ v^2}{r}[/tex]
[tex]v = \sqrt{ \frac{GM }{r} }[/tex] (1)
The modulus of velocity (speed) is constant so we can use the uniform motion ratio
v = [tex]\frac{\Delta x}{t}[/tex]
For a complete orbit, the distance traveled is the length of the circle and the time is called the period.
Δx = 2π r
we substitute
[tex]\frac{G M}{r} = \frac{4 \pi^2 r^2 }{T^2}[/tex]
T² = ( [tex]\frac{4\pi ^2 }{GM}[/tex]) r³
They ask to calculate the orbital velocity we can use the relation 1
v = [tex]\frac{\sqrt{GM }}{ \sqrt{r} }[/tex]
Let's find the value of the constant
[tex]\sqrt{GM}[/tex] = [tex]\sqrt{6.67 \ 10^{-11} \ 1.991 \ 10^{30}}[/tex]
[tex]\sqrt{GM} = 1.15 \ 10^{10}[/tex]
In the table we have the tabulated values for the radii of the orbits of the planets
planet radius orbit (m) velocity (m/s)
Mercury 5.79 10¹⁰ 4.779 10⁴
Venus 1.08 10¹¹ 3.499 10⁴
Land 1,496 10¹¹ 2,973 10⁴
Mars 2.28 10¹¹ 2.408 10⁴
Jupiter 7.78 10¹¹ 1.304 10⁴
Saturn 1.43 10¹² 9.62 10³
Uranus 2.87 10¹² 6.79 10³
Neptune 4.50 10¹² 5.42 10³
Pluto 5.91 10¹² 4.73 10³
We calculate the speed of some as an example and the others are in the third column of the table
Mercury
v = [tex]\frac{1.15 \ 10^{10}}{\sqrt{5.79 \ 10^{10}} }[/tex]
v = 4.779 10⁴ m / s
Venus
v = [tex]\frac{1.15 \ 10^{10}}{\sqrt{1.08 \ 10^{11}} }[/tex]
v = 3,499 10⁴ m / s
They ask to know the planet that has maximum and minimum orbital speed.
After reviewing the calculations, and observed the table, Mercury has the highest speed and Pluto is the one with the lowest orbital speed.
When examining the expression the velocity is inversely proportional to the square root of the radius of the orbit
The radius of the orbit of Ceres is r = 2.766 ua ( [tex]\frac{1.49 \ 10^{11} m}{1 ua}[/tex]) = 4.11 10¹¹ m
the orbital velocity of Ceres is
v = [tex]\frac{1.15 \ 10^{10}}{\sqrt{4.11 \ 10^{11}} }[/tex]
v = 1.79 10⁴ m / s
those that correspond to a speed between Mars and Jupiter
In conclusion using Kepler's third law we can find the answers for the orbital speed of the planets are:
The speed decreases as we move away from the Sun, the values are in the third column of the table. The fastest planet is Mercury and the slowest planet is Pluto.
Learn more here: brainly.com/question/9622816
Which of the following units would be the most appropriate for measuring the mass of a paper clip? A. grams B. milligrams C. centigrams D. kilograms
Answers
For this case we have that a paper clip is a very small object, to be taken in the hand we feel that its mass is very small, almost imperceptible.
For this reason we can discard option D and option A.
Being so small we can use the milligrams to measure its mass, it is the smallest scale.
Answer:
Option B
Answer: Grams
Explanation: In the metric system, masses are measured using grams as the base unit. Prefixes can then be added to the base unit when appropriate.
If you were trying to build a sound proof room, which of the following materials would you choose in order to absorb the most sound, based on the coefficient of absorption for each material
Answers
Answer: concrete
Explanation: because of the absorption
(from Penn Foster) ⭐⭐⭐⭐⭐
Material Coefficient of Absorption
Perforated acoustic ceiling material 60%
Heavy curtains (A) 50%
Carpeting (B) 20%
Wood (C) 5%
Plaster 3%
Clay tile (D) 3%
Concrete 2%
The answer is A. Heavy curtains ✅
PLZ HELP!!!
*best answer gets brainliest*
Answers
Have you ever seen the two different sides of a battery? One side is often labelled with a positive sign, and the other with a negative sign. Inside the battery are four cells where two processes take place. One process uses electrons, and the other creates electrons. When the electrons flow, it creates electricity.
Drums convert mechanical energy into sound energy.
When a musician bangs his/her drumstick on the drum, the motion makes a sound. This movement turned motion into sound.
25 POINTS
I need a DETAILED ANSWER explaining WHY you wrote it please!!
When you go to the movies, a strong light shines through the film and then through one or more lenses. The image you see on the screen is much larger than the one on the film.
What kind of image are you looking at on the movie screen?
Answers
good luck
Answer:
Explanation:
The real image is always inverted and can be obtained on a screen in this mode.
On the cinema screen, it now appears normal to our eyes.
Condensed light from the condenser goes through the film forming rays which are then passed through a series of lenses which spread them out and focus them on the screen.
The real image is what now shows on the screen.
Which of these describes the heat element of a toaster oven?
A. A resistor, which converts some electrical energy to thermal energy
B. A conductor surrounded by an insulator
C. A conductor, which carries electric currents
D. An insulator, which stops the flow of electricity.
Answers
Hope this helps
Koala bears can eat only certain kind of Australian eucalyptus leaves.koalas are considered
Answers
Answer: Koala bears are considered herbivores, or as in the scientific name, arboreal herbivorous marsupial, marsupial because it also carries it's babies around in a pouch. Koala bears are also native to Australia, which eucalyptus leaves are also native to.
Hope this helped you! ♥
Answer:
a specialized species
Explanation:
In which of the following technologies do satellites work together to aid in navigation?
radio telescope
optical telescope
interstellar space probe
Global Positioning System
Answers
Satellites in the Global Positioning System (GPS) work together to provide navigation assistance via radio signals.
Satellites work together to aid in navigation in the Global Positioning System (GPS). GPS satellites broadcast radio signals that are used by GPS receivers to calculate precise positions on the Earth's surface. This calculation involves measuring the time it takes for the signals to travel from the satellite to the receiver, which allows the device to compute its distance from multiple satellites and thus pinpoints its location accurately.
The space segment, which is comprised of the Earth-orbiting GPS satellites themselves.The control segment, which includes ground monitoring stations that maintain the satellites' orbits and check their clocks.The user segment, made up of the individual GPS receivers that people use to determine their position and time.Global Navigation Satellite Systems (GNSS) such as GPS, along with other international systems like Galileo, GLONASS, and BeiDou, provide critical Positioning, Navigation, and Timing (PNT) services, which are essential for various applications ranging from military operations to civilian uses like navigation and surveying.
How does changing the lengthy but not the height of an inclined plane affect the work done to lift a load? PLZ HELP ME NOW'
Answers
Answer: Work Done would remain same.
Let us assume that the velocity is constant while taking the load up the inclined plane. Then, the kinetic energy would remain the same. This is because kinetic energy is dependent on velocity [tex](K.E.=\frac{1}{2}mv^2)[/tex]. If that is constant, the kinetic energy would remain same. The potential energy is dependent on the height[tex](P.E.=mgh)[/tex]. If the height is changed, then potential energy varies. In the question, it is mentioned that without changing the height, the length of the inclined plane is changed. Therefore, the potential energy would be same as before.
We know, work done is equal to potential energy plus kinetic energy. Since there is no change in any of these, the required work done would not change.
The distance between one point on a compression and the corresponding point on the next compression in a sound wave is called a
Answers
In fact, the wavelength of a wave is defined as the distance between two consecutive same-shape points of the wave. In this case, we have the distance between two corresponding compression points of the wave, so this distance corresponds to the wavelength.
Cognitive changes that accompany depression include
Answers
That is correct. Cognitive changes that accompany depression can include: Concentration, Memory, Decision-Making, Slowed Cognitive Processing, Negative Cognitive Bias, Rumination, Reduced Attention to Detail, Forgetfulness, Information Processing, Executive Function Impairment.
Difficulties in Concentration: People with depression often struggle to concentrate or focus on tasks, making it challenging to stay attentive and productive.
Memory Problems: Depressed individuals may experience difficulties with memory, both short-term and long-term, leading to forgetfulness and trouble recalling important information.
Impaired Decision-Making: Depression can affect a person's ability to make decisions, leading to indecisiveness, second-guessing, and avoidance of making choices.
Slowed Cognitive Processing: Cognitive processing speed may be reduced in individuals with depression, resulting in delayed responses and slower information processing.
Negative Cognitive Bias: Depression can lead to a negative cognitive bias, causing individuals to interpret situations in a pessimistic and negative manner, reinforcing feelings of hopelessness.
Rumination: Depressed individuals may engage in rumination, which involves obsessively dwelling on negative thoughts and feelings without finding resolution, leading to a cycle of negative thinking.
Reduced Attention to Detail: Depression can lead to a decreased ability to pay attention to details, impacting work, studies, and daily activities.
Forgetfulness: Depressed individuals may experience forgetfulness, leading to difficulties in remembering appointments, tasks, and important events.
Difficulty Processing Information: Depression may affect a person's ability to process and comprehend new information, making it challenging to learn and adapt.
Executive Function Impairment: Executive functions, such as planning, organization, and problem-solving, may be impaired by depression, making it difficult to manage daily responsibilities.
It's essential to remember that not everyone with depression will experience all of these cognitive changes, and the severity of these symptoms can vary from person to person. Seeking professional help and treatment for depression is crucial to address both the emotional and cognitive aspects of the condition. Early intervention can lead to better management of depression and its cognitive effects.
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Complete question:- Cognitive changes that accompany depression include difficulties in concentration, memory problems, impaired decision-making, slowed cognitive processing, negative cognitive bias, rumination, reduced attention to detail, forgetfulness, difficulty processing information, and executive function impairment.
Please Help!
Complete each sentence or statement.
15. like charges____and opposite charges________.
16. A complete path through which charge can flow is an electric____.
17. To calculate power, multiply voltage measured in ____ by _____ measured in amps.
18. The magnetic field lines of a bar magnet begin near the magnet's_______.
19. A charged particle moving in a magnetic field will be deflected in a direction ______ to the magnetic field.
20. In a solenoid, there will be no magnetic field if there is no ______ in the wires of the coil.
21. Large power plants in the united states use ___________ generators.
Answers
16. circuit
17. volts, currents
18. north pole
19. across
20. current
21. AC
Hope this helps
Which of the following best illustrates a use of friction in the transportation industry? A. When a passenger jet burns fuel and shoots exhaust out its back end, the jet responds by moving forward. B. When a locomotive's brakes are applied to train tracks, the force between the brakes and the tracks causes the locomotive to slow down. C. When a ship is launched out to sea, the downward force of the ship onto the water is balanced by the water's upward force onto the ship. D. When a driver applies a force to a car's accelerator pedal, the car responds by traveling at a faster speed.
Answers
Please give me Brainliest!
Answer:
b
Explanation:
A duplicated chromosome is made of two identical structures is called?
Answers
To test the hypothesis that plants grow faster in green light, a student set up 3 of the same type of plants. She placed the first plant under a green light, the second plant under a regular light bulb, and the third plant under a red light. What is the dependent variable in this experiment?
Answers
You move a 2.5 kg book from a shelf that is 1.2 m above the ground to a shelf that is 2.6 m above the ground. What is the change in potential energy of a system containing the book and Earth?
Answers
[tex]U=mg \Delta h[/tex]
where
m is the mass of the object
g is the gravitational acceleration
[tex]\delta h[/tex] is the increase in altitude of the object
In our problem, [tex]m=2.5 kg[/tex] is the mass of the book, [tex]g=9.81 m/s^2[/tex] and
[tex]\Delta h=2.6 m -1.2 m=1.4 m[/tex] is the increase in altitude of the book, so its variation of potential energy is
[tex]U=mg\Delta h=(2.5 kg)(9.81 m/s^2)(1.4 m)=34.3 J[/tex]
The change in potential energy of the book, moved from 1.2 m to 2.6 m above the ground, is 34.3 J.
Change in Potential Energy of a Book
To find the change in potential energy of the system containing the book and Earth, we use the formula for gravitational potential energy: PE = mgh, where m is the mass, g is the acceleration due to gravity (approximated as 9.8 m/s²), and h is the height.
First, calculate the initial potential energy of the book when it is at 1.2 m:
PEinitial = mghinitial
PEinitial = (2.5 kg)(9.8 m/s²)(1.2 m) = 29.4 J
Next, calculate the final potential energy of the book when it is at 2.6 m:
PEfinal = mghfinal
PEfinal = (2.5 kg)(9.8 m/s²)(2.6 m) = 63.7 J
The change in potential energy (ΔPE) is the difference between the final and initial potential energy:
ΔPE = PEfinal - PEinitial
ΔPE = 63.7 J - 29.4 J = 34.3 J
Thus, the change in the potential energy of the system is 34.3 joules.
what is a homogenous mixture
Answers
A ball is thrown into the air
Answers
Ben walks 500 meters from his house to the corner store. He then walks back toward his house, but continues 200 meters past his house to talk to a neighbor. It takes Ben 17 minutes from the time he leaves his house until he stops to talk to his neighbor. What is Ben’s average velocity?
Answers
Answer:
0.196 m/s
Explanation:
Average displacement is defined as the total displacement covered to the total time taken.
Total displacement = 500 - 500 - 200 = - 200 m
Total time taken = 17 minutes = 17 x 60 = 1020 second
So, Average velocity = 200 / 1020 = 0.196 m/s (magnitude only)
Answer:
Talking Ben is lazy so he would have gotten to the corner store on a scooter because hes to fat of a dog and he probley felt lazy and tired after going the the store and he probley sat back on his big fat red chair and burped his head off.
Suppose you are investigating how the day ends hamsters affect how much they run on the hamster wheel. In order to control the experiment which of these should you do?
A. Change only the diet of each hampster.
B. Give all the hamsters the exact same diet.
C. Only allow some hampsters to run on the wheel.
D. Compare the behavior of hamsters and gerbils
Answers
Answer:
B
Explanation:
If you want to control the experiment, you want to make sure that no outside factor could potentially influence your results.
Hence, changing the diet of a hamster would significantly alter any results you may collect.
For example, if you allow hamster A to eat a nutritious diet, while not giving a proper diet to hamster B. Hamster A will perform better, and run further and for longer, because he has more energy.
The answer is B, because you want to make sure no hamster is at an advantage.
According to the electromagnetic spectrum, Gamma rays have the slowest wave length. Therefore, Gamma rays have _______frequency.
A). a random
B). the lowest
C). the highest
D). an undetermined
Answers
Answer:
A. the highest
What factors affect the frictional force between objects ?
Answers
Final answer:
The factors that affect the frictional force between objects include the roughness of the surfaces, adhesive forces between molecules, and the normal force pushing the objects together.
Explanation:
In physics, several factors affect the frictional force between objects. One factor is the roughness of the surfaces in contact. If the surfaces have more irregularities or peaks, more force is required to set the object in motion and maintain its motion. Another factor is the attractive forces between molecules making up the two objects. These adhesive forces depend on the substances the surfaces are made of, which explains why rubber-soled shoes slip less than those with leather soles. Finally, the normal force pushing the systems together also affects friction. Friction is proportional to the normal force.
you make the following measurements of an object 42kg and 22m what would the objects density be. show your work
Answers
density = 1.90909 kg/m³
Explanation:
The measurements given are:
42 kg which gives us the mass of the object
22 m³ (not 22 m) which gives us the volume of the object
Density can be calculated as follows:
density = mass / volume
density = 42 / 22
density = 1.90909 kg/m³
Hope this helps :)
Calculate the critical angle for light going from Glycerine to air.
Answers
When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
[tex]\theta_c = \arcsin ( \frac{n_2}{n_1} )[/tex]
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
[tex]\theta_c = \arcsin ( \frac{1.00}{1.473} )=42.8^{\circ}[/tex]
The critical angle for light going from glycerin to air is approximately [tex]\( 42.47^\circ \)[/tex]
To calculate the critical angle for light going from glycerin to air, we need to use Snell's Law, which states:
[tex]\[ n_1 \sin \theta_1 = n_2 \sin \theta_2 \][/tex]
Where:
[tex]\( n_1 \)[/tex] is the refractive index of glycerin.
[tex]\( n_2 \)[/tex] is the refractive index of air.
[tex]\( \theta_1 \)[/tex] is the angle of incidence.
[tex]\( \theta_2 \)[/tex] is the angle of refraction.
The critical angle [tex](\( \theta_c \))[/tex] is the angle of incidence in the denser medium (glycerin) for which the angle of refraction in the less dense medium (air) is [tex]90[/tex] degrees. At the critical angle:
[tex]\[ \sin \theta_c = \frac{n_2}{n_1} \][/tex]
The refractive index of air [tex](\( n_2 \))[/tex] is approximately [tex]1[/tex]. The refractive index of glycerin [tex](\( n_1 \))[/tex] is approximately [tex]1.47[/tex]
Using these values:
[tex]\[ \sin \theta_c = \frac{1}{1.47} \][/tex]
Now, calculate [tex]\( \sin \theta_c \)[/tex]
[tex]\[ \sin \theta_c = 0.6803 \][/tex]
To find the critical angle [tex]\( \theta_c \)[/tex], take the inverse sine ([tex]arcsine[/tex]) of [tex]0.6803[/tex]
[tex]\[ \theta_c = \arcsin(0.6803) \][/tex]
Using a calculator
[tex]\[ \theta_c = 42.47^\circ \][/tex]
Cell theory was discovered and advanced because of the development of which instrument?
A) telescope
B) gyroscope
C) light microscope
D) electron microscope
Answers
Light microscope is a cell theory was discovered and it advanced to development instrument.
Hope it helped.
-Charlie
Have a great day!
Answer:
C
Explanation:
Just did it