A position-versus-time graph for motion with constant, nonzero acceleration forms a parabola, as the position increases at an increasing rate due to constant acceleration.
Explanation:The shape of the graph for motion with constant, nonzero acceleration on a position-versus-time graph is a parabola. Acceleration - the rate of change of velocity - is constant in this scenario, implying that velocity is increasing at a constant rate. As a result, position, which is the area under the velocity versus time graph, increases at an increasing rate. This is represented graphically by a parabolic curve.
For instance, consider a car starting from rest and accelerating at a consistent rate. At the beginning of motion, the car covers a relatively small distance, resulting in a low point on the graph. As time progresses and the car accelerates, the distance covered in each subsequent time interval increases, resulting in an upward curve on the position-versus-time graph. The steepness of the curve increases with time, forming a parabolic shape.
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Snow has been lying on a mountainside. Suddenly, it starts to move down the mountain. Which types of friction are observed in this avalanche? Where does each type occur?
The energy which is due to position is potential energy. So when the snow is lying on the mountain. It possess potential energy but when suddenly, it starts to move down the mountain, the potential energy is converted into the kinetic energy. Yet some force is exerting on the snow to stop the smooth flow of snow through mountains.
This example of frictional force may be due to presence of rough surface or stones. Generally, there are four types of friction as static, rolling, sliding and fluid friction. Though in this case when snow is lying it possess static friction, when flows then it possesses sliding and fluid friction both.
what is the average atomic mass of an element?
The average atomic mass of an element is the mass found on the periodic table under the element symbol. It is called the average atomic mass because it is actually a calculated sum of the masses of the element's isotopes (same element with different number of neutrons), each multiplied by their natural abundances.
The average atomic mess of an element is the sum of masses of its isotopes, each multiplied by its natural abundance .
a student attaches a rope to a 20.0 kg box of books. he pulls with force of 90.0 n at a angle of 30.0° with the horizontal. the coefficient of kinetic friction between the box and the sidewalk is 0.500. find the acceleration of the box
Answer:
acceleration = 0.12 m/s^2
Explanation:
Using Second Law of Motion,
F = m*a
F is net force (N) m is mass of the box (kg) a is acceleration of the box (m/s^2)μ = f/Fn
μ is coefficient of friction f is the friction force (N) Fn is the nomal force acting on the object (N)Fn = m*g – 90*sin(30)
Fn = (20)*(9.81) – 90*sin(30)
Fn = 151.2 N
f = μ*Fn
f = (0.5)*(151.2)
f = 75.6 N
F = 90cos(30) – 75.6
F = 2.34 N
a = F/m
a = 2.34/20
a = 0.12 m/s^2
name 15 measurement instrument use in physic and their uses
1. Meter Rule
Meter rule is used to measure the small length or distance between any two points.
2. Measuring Tape
It is also use to measure length and distance in meters and centimeters.
3. Vernier calipers.
It can be use to measure small diameter or radius of objects up-to 10th part of a millimeter.
4. Micrometer screw gauge.
It is also use to measure diameter or radius unto 100th part of a millimeter.
5.Beam balance
It is use to measure mass upto 10th part of a gram.
6. Physical balance
it is use to measure mass upto 100th part of a gram.
7.Electronic balance
It is use to measure mass upto 100th part of a gram.
8. Stop watch.
It is use to measure time upto 10th and 100th part of a second.
9.Measuring cylinder
It is use to measure volume of a small object.
10. Hydrometer
It is use to measure density of liquids.
11. Barometer.
It is use to measure the atmospheric pressure.
12. Thermometer
It is use to measure temperature.
13. Ammeter
It is used to measure amount of electric current in circuit.
14.Photometer.
It is use to measure intensity of light.
15. Protector,.
It can be use to measure angle.
16. Lactometer.
It can be use to measure specific gravity of milk.
which of the following best describes the way that scientists make observations
why is a person who lives in the city able to sleep through the sounds of traffic but awaken to the soft sound of bird singing
They grew up to that sound. They love the sound of that same traffic sound.
The items listed below are found in a science classroom.
1. Heart made of plastic with many of its parts labeled
2. Clay formed to look like Earth and other planets
3. A giant plastic plant cell with removable cell parts
4. Fill in the blank. These items are all examples of
Models
Experiments
Variables
Controls
These are all Examples of Models
Which of the following is the correct definition of mechanical energy?
A.
energy stored in chemical bonds of molecules
B.
energy of an object due to the random motion of its atoms and molecules
C.
energy an object has because of its motion or position
D.
energy produced from the splitting of atoms
Jamal wanted only to test the effect of the free fall and so he put his system in a vacuum to prevent air resistance. In free fall, will the crumpled or flat paper reach the ground first? The crumpled paper will reach the ground first. The flat paper will reach the ground first. Both papers will reach the ground at the same time. It is hard to tell which would reach the ground first without experimentation.
When a paper is crumpled and then released the air drag on the paper is less while when we put the flat paper and released it from rest we can see that there is large surface area due to which it will have more air drag and hence it will reach later
So we can say that air friction or air drag depends on the surface area of object
More will be the surface area more is the drag force of air and hence less is the effective acceleration due to gravity
So when we drop the two objects in vacuum it will not have any friction force
and hence they both will have same gravity downwards
So in that case the two objects will reach the ground in same time
so its answer will be
Both papers will reach the ground at the same time.
Answer:
the answer is they both hit at the same time
Explanation:
The density of the gold is 19.3g/cm3.
The density of the iron pyrite is 5.0 g/cm3.
If a night of iron pyrite and nugget of gold each have a mass of 50g ... what you can conclude about the volumen of each nugget ?
I don’t get it
If both nuggets have the same mass and different densities then it can be concluded that the volume with the highest density is smaller.
For, so to speak, density is a relation of how much mass is there in a given volume. So the more the mass and the smaller the volume, the greater the density.
To verify this, let us calculate the volumes of iron pyrite and gold pyrite.
For the iron pyrite nugget:
density = mass / volume
volume = mass / density
volume = 50/5
volume = 10cm3
For the gold nugget:
volume = mass / density
volume = 50 / 19.3
volume = 2.59cm3
Therefore it is found that the nugget with the highest density (gold) is the one with the lowest volume.
what force is needed to accelerate a mass of 36 kg at 8.6m/sec2
Solution is given in following attachment.
Newton’s _______ law states than an object at rest will remain at rest and an object in motion will stay in straight line motion unless acted upon by an unbalanced force
The answer is Newton's First law of motion.
Answer:
Newton's First law of motion.
Explanation:
Newton's First law of motion -
Newton' s first law of motion , also called the law of inertia .
According to this law , when an object is at rest or at stationary position , stays at that position and when the object is at motion , continues to be at the motion unless and until some force is acted on it .
Hence , the correct law for the given statement of the question , is Newton's First law of motion .
When you enter a toll road, your ticket is stamped 1:00 p.m. When you leave, after traveling 55 miles, your ticket is stamped 2:00 p.m. What was your average speed in miles per hour?
Answer:
55 miles per hour
Explanation:
Given
Distance d = 55 miles
t_o =1.00 pm
t_f = 2.00 pm
Solution
Duration of the trip
[tex]\Delta t = t_f - t_o\\\\\Delta t = 2.00 pm - 1.00 pm\\\\\Delta t = 1 hour[/tex]
Average velocity
[tex]v = \frac{d}{\Delta t} \\\\v = \frac{55}{1} \\\\v = 55 mph[/tex]
How is the enthalpy of vaporization related to intermolecular forces during a phase change?
A)
The temperature increase converts bonding forces into intermolecular forces during vaporization.
Eliminate
B)
The intermolecular energy of vaporization represents a greater change increasing the bonding forces.
C)
The kinetic energy of the ethanol molecules increases strength of the intermolecular forces increases.
D)
The liquid state is stabilized by the molecule's intermolecular forces resulting in a high enthalpy of vaporization.
Lol I just did this on USA Test Prep. The answer is D.
Option D - The liquid state is stabilized by the molecule's intermolecular forces resulting in a high enthalpy of vaporization → is the correct option.
We have enthalpy of vaporization.
We have to determine how is the enthalpy of vaporization related to intermolecular forces during a phase change.
What are intermolecular forces?Intramolecular forces are the forces that hold atoms together within a molecule.
According to the question -
The molecules inside liquid are held together by the intermolecular forces. A specific amount of heat energy is required to overcome these intermolecular forces in order to change the state from liquid to gas. This energy is called heat of vaporization. Hence, the intermolecular forces help liquid to stay in a steady state which will ultimately require more energy to separate the molecules.
Therefore, Option D is the correct Alternative.
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Tim puts his spare change in a jar each day when he comes home. When the jar is full he separates the coins and takes them to the bank. The coins would be classified as a _________. A) compound B) element C) mixture D) solution
The bunch of stuff in the jar is a mixture. The different kinds of pieces aren't bound to each other, and they can be easily separated.
James took two pea plants, placing one in a dark closet and the other on a sunny windowsill. Both are located in air-conditioned rooms. He then measured the growth of the pea plants after a week. Which of the following best describes the purpose of this experiment?
To determine the effect of air conditioning on plant growth
To determine the effect of lack of water on plant growth
To determine the effect of sunlight on plant growth
To determine the effect of enclosed spaces on plant growth
I should assume the answer would be C, to determine the affects of sunlight on plant growth. In the above paragraph, everything else in the experiment was the same, and the only variable was the amount of sunlight reaching each plant. Hope this helped!
This procedure will demonstrate the effect of sunlight on plant growth. If that wasn't the purpose that James had in mind, then he picked the wrong experiment.
Equation for 20 m/s and 26 m/s for final and initial velocity
26 m/s - 20 m/s = 6 m/s
A blow dart is fired horizontally from a height of 1.2 meters. If the dart hits a target that is .6m high and 12m away, what is the initial velocity of the dart?
Blow dart is projected from a height of 1.2 m
Dart will hit the target at height 0.6 m
so the vertical displacement of the dart will be 1.2 - 0.6 = 0.6 m
here we can say that in vertical direction kinematics is applied
[tex]y = v_i* t + \frac{1}{2}at^2[/tex]
[tex]0.6 = 0 + \frac{1}{2}*9.8*t^2[/tex]
[tex]t = 0.35 s[/tex]
now we can say that dart will hit the target after t = 0.35 s
so in the same time it will cover the distance 12 m in horizontal direction
so here in order to find the initial speed we can say
[tex]d = v * t[/tex]
[tex]12 = v* 0.35[/tex]
[tex]v = \frac{12}{0.35}[/tex]
[tex]v = 34.3 m/s[/tex]
so dart is projected with speed 34.3 m/s in horizontal direction
The blow dart is launched with an initial velocity of around 34.3 m/s. This is determined by calculating the time of flight using the height difference and gravitational acceleration, then determining the velocity using that flight time and the horizontal distance to the target.
Explanation:The subject of this question is physics, as it requires an understanding of kinematic equations for projectile motion to solve. First, let's figure out how long the dart is in the air. We're going to use the formula h = 0.5 * g * t^2, where h is the height difference (1.2m - 0.6m = 0.6m), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Solving for t, we have sqrt((2*h) / g) = sqrt((2*0.6) / 9.81) = approximately 0.35 seconds.
Now that we know how long the dart was in the air, we can find out its initial horizontal velocity. Since horizontal motion is the constant velocity in the absence of air resistance, the initial velocity is simply the total horizontal distance divided by the time. Therefore, the initial velocity, v, is d / t = 12m / 0.35s = approximately 34.3 m/s. So the dart was launched with an initial velocity of roughly 34.3 m/s.
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Which equation represents mass-energy equivalence? E = m2c E = mc2 E = (mc)2 E = mc
Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be
[tex]E = mc^2[/tex]
where
m = mass in kg
c = speed of light in m/s
this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle
So correct relation above will be
[tex]E = mc^2[/tex]
the answer is B i just took it
Suppose a skydiver (mass = 75kg) is falling toward the earth. When the skydiver is 100m above the earth, he is moving at 60m/s. At this point, calculate the skydiver’s:
• Gravitational Potential Energy
• Kinetic Energy
• Total Mechanical Energy (kinetic + potential)
gravitational potential energy is given as
[tex]PE = mgH[/tex]
here given that
m = 75 kg
g = 9.8
H = 100 m
now plug in all value above
[tex]PE = 75 * 9.8* 100[/tex]
[tex]PE = 73500 J[/tex]
now for kinetic energy we can use
[tex]K = \frac{1}{2}mv^2[/tex]
here we have
m = 75 kg
v = 60 m/s
now we have
[tex]K = \frac{1}{2}*75*60^2[/tex]
[tex]K = 135000 J[/tex]
now for mechanical energy we have
[tex]ME = KE + PE[/tex]
so now we will add above to energy to find mechanical energy
[tex]ME = 73500 + 135000 [/tex]
[tex]ME = 208500 J[/tex]
two vectors have a magnitude of 2.5km and 6.5 km . Predict the maximum and minimum magnitudes of their resultant vector
The maximum magnitude of their resultant vector is when the two vectors are parallel and in the same direction, so they lie on the same axis. In this case, the magnitude of their resultant vector is simply the sum of the two magnitudes:
[tex]R=2.5 km+6.5 km=9.0 km[/tex]
The minimum magnitude of their resultant vector is when the two vectors are parallel but in opposite direction. In this case, the magnitude of their resultant vectors is just the difference between the two magnitudes:
[tex]R=6.5 km-2.5 km=4.0 km[/tex]
Which Richter magnitude range can be recorded by instruments but isn't felt? A. less than 2.9 B. 3.0 – 4.9 C. 5.0 – 5.9 D. 6.0 and higher
A. anything less than 3.0 magnitude on a richters scale usually can't be felt by humans but instruments can pick it up.
Answer:
A. Less than 2.9
Explanation:
Richter scale is a measure of the intensity of the earthquakes designed and developed by Charles Richter in 1935. Its value ranges from 1.0 to 9.0 and greater. The earthquakes having a Richter magnitude of less than 2.9 are minor earthquakes which are slightly felt by a few humans but can be recorded on a seismograph. Earthquakes with magnitude above 2.9 can easily be felt by humans.
can someone answer this for meee?? w
We know that either team is winning which means that the cumulative forces (sum of each girl force) on both teams are equal.
This means,
[tex]250 + 250 + 250 + 250 = 260 + 260 + 260 + x[/tex]
being x the force of the fourth girl on the east team.
Solving to x, you get
[tex]x = (250 + 250 + 250 + 250) - (260+260+260)
x = 1000 - 780
x = 220[/tex]
The fourth girl on the east is pulling with a force of 220N.
The force applied by fourth girl in east team is 220 N.
Explanation.If neither side is wining, it means that force applied on both sides are equal.
Total force by team west = 250 N * 4 = 1000 N
Total force of 3 girls on east side = 260 N * 3 = 780 N
As we know the east team apply total force of 1000 N.
Force applied by the fourth girl in east team = 1000 N - 780 N = 220 N
When you are on a swing, and at the lowest point of your motion, is your apparent weight greater than, less than, or equal to your true weight? Explain
When you are on a swing, and at the lowest point of your motion, is your apparent weight greater than to your true weight.
What is apparent weight?In general, an object's apparent weight is equal to its mass multiplied by the vector difference between gravitational acceleration and the object's acceleration.
According to this definition, apparent weight is a vector that can act in any direction, not just vertically.
The weight of an object is how gravity pulls on it, but apparent weight is a measure of downward force. Weight, on the other hand, is a measure of the force exerted by gravity.
We can pretend you're in a uniform circular motion at the bottom of the swing trajectory, so the net force points toward the center of the circle.
As a result, the swing must exert a greater force on you than the earth does in the opposite direction. As a result, your apparent weight is greater than your true weight.
Thus, the true weight will be less than the apparent weight.
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Mike walks 200 km in 6 hours.he then walks another 100km in 4 hours .what is his average speed?
Average speed is defined as the ratio of total distance covered in total given time
[tex]speed = \frac{distance}{time}[/tex]
here we know that total distance that man moved is
[tex]d_1 = 200 km[/tex]
[tex]d_2 = 100 km[/tex]
so total distance is
[tex]d = d_1 + d_2[/tex]
[tex]d = 200 km + 100 km[/tex]
[tex]d = 300 km[/tex]
now here total time of the motion is
[tex]t_1 = 6 hours[/tex]
[tex]t_2 = 4 hours[/tex]
total time will be given as
[tex]t = t_1 + t_2 [/tex]
[tex]t = 6 + 4 = 10 hours[/tex]
now by above formula
[tex]v_{avg} = \frac{300}{10}[/tex]
[tex]v_{avg} = 30 km/h[/tex]
so his average speed is 30 km/h
An object is dropped from a 15 m ledge. What is the objects final velocity ?
Answer:
The object's final velocity is approximately \(17.15 \ m/s\) downward.
whats the velocity if a seagull drops a shell from rest at a height of 11m, how fast is the shell moving when it hits the rocks
Seagull is at height 11 m
it drops a shell from rest
so here we know that
acceleration of shell is due to free fall = -9.81 m/s^2
displacement = - 11 m
initial speed = 0
now we will use kinematics equation here in order to find the final speed
[tex]v_f^2 = vi^2 + 2as[/tex]
now plug in all values in it
[tex]v_f^2 = 0 + 2*(-9.81)*(-11)[/tex]
[tex]v_f^2 = 215.82[/tex]
[tex]v_f = 14.7 m/s[/tex]
so here the speed by which shell will strike with the rocks is 14.7 m/s
Final answer:
The velocity of a shell dropped from rest at a height of 11m when it hits the ground is approximately 14.69 m/s. This is calculated using the kinematic equation for uniformly accelerated motion, considering gravity as the acceleration.
Explanation:
The question refers to the velocity of a shell dropped by a seagull from a specific height until it hits the ground. To solve this, we can use the equations of motion under gravity. Specifically, we can use the following equation, which comes from the kinematic equations for uniformly accelerated motion:
v² = u² + 2as
v represents the final velocity
u is the initial velocity (which is 0 in this case, since the shell is dropped from rest)
a is the acceleration due to gravity (approximately 9.81 m/s² on Earth)
s is the distance the object has fallen, in this case, 11 meters
Plugging the numbers into the equation gives us:
v² = 0⁻ + 2*9.81*11
v² = 215.82
v = √(215.82)
v = 14.69 m/s (to two decimal places)
Therefore, the velocity of the shell when it hits the rocks will be approximately 14.69 m/s.
According to the law of conservation of matter, which chemical equation represents a possible chemical reaction? A. CaCO3 Fe2O3 B. 2Na + Cl2 2NaCl C. 4Fe + 3O2 C6H12O6 + 6O2 D. C6H12O6 + 6O2 CaO + CO2
The correct answer is:
B. 2Na + Cl2 --> 2NaCl
In fact, this is the only reaction among the choices where the number of atoms of each element is conserved. In fact, we see that on the left we have 2 atoms of sodium and 2 atoms of chlorine, and on the right we have two molecules of NaCl, which means that we still have 2 atoms of sodium (Na) and 2 atoms of chlorine (Cl).
A sound wave is created in an unknown substance with a frequency of 24kHz. Using extremely sensitive sensors, it is determined that the sound wave travels through a piece of this substance that is 3.5 m long in .919 millisecond. Determine the substance that this sound wave is traveling through.
velocity is of sound id defined as distance covered by sound per unit time
here given that
distance covered by sound = 3.5 m
time taken by the sound = 0.919 millisecond
So the velocity of sound will be given as
[tex]v = \frac{d}{t}[/tex]
[tex]v = \frac{3.5}{0.919* 10^{-3}}[/tex]
[tex]v = 3808.5 m/s[/tex]
so the speed of sound in the given medium is 3808.5 m/s
As we know that speed of sound in any substance is given as
[tex]v = \sqrt{\frac{E}{\rho}}[/tex]
As per the data available online the speed of sound in gold is 3250 m/s while speed of sound in glass is 4500 m/s
So here we can say the above speed is in between these two mediums whose elasticity and density ratio is more than gold but less than glass.
So this velocity of sound is nearly match with the data obtained for copper
So this speed is approx obtained in copper
a car accelerates from rest at 5 m/sec2 for 12 seconds what is the final velocity
Vi =0 ( as car starts from rest )
Acceleration= a = 5m/s²
t =12sec
Vf =Vi + at
Vf= 0 + (5m/s²) (12s)
Vf=60 m/s